A compound with molecular formula C5H10Br2 displays the following 13C NMR along with the DEPT-90 and DEPT-135 13CNMR spectra. What is the structure for this compound?

Answers

Answer 1

Answer:

Explanation:

The correct structure for the compound C5H10Br2 is:

Br -- CH₂ -- CH₂ -- CH₂ -- CH₂ -- CH₂ -- Br

         1          2         3         4         5

The name of the required compound is 1,5-dibromopentane.

The DEPT spectroscopy is applied to differentiate between CH₃, CH₂, and CH groups.

Assuming the DEPT is up, this shows a positive peak which illustrates CH₃ group

Assuming the DEPT is down, this shows a negative peak which illustrates CH₂ or CH group

C-13 NMR with DEPT-135

The negative peak in DEPT at 26.77 ppm illustrates CH₂ or CHThe negative peak at 31.85 ppm illustrate CH₂ or CHThe negative peak at  33.24 ppm illustrate CH₂ or CH

The carbon analysis is:

Assign            ppm

1                     33.24

2                     31.85

3                     26.77

4                     31.85

5                    33.24


Related Questions

3.
What do we call materials
that let heat pass through
them easily?
Thermal conductors
Thermal insulators
Transparent

4.
Which of these is a good
thermal conductor?
Plastic
Wood
Steel

5.
Which of these is a good
thermal insulator?
Steel
Iron
Polystyrene

6.
To save on heating bills, do
you think the roof of a
building should be lined with...
a thermal conductor
a thermal insulator
nothing

7.
How does heat travel?
From cold things to hotter things
From hot things to colder things
Between things of the same temperature

Answers

Answer:

thermal conductors

steel

polystyrene

thermal insulator

between things of the same temp?

sorry to ask but if its ok with you, may i get brainly, i need to rank up all i need is two more, if not its fine. thank you and yours truly golden

A phosphate buffer is prepared with KH2PO4 at 0.02 M and K2HPO4 at 0.03 M. What is the concentration of phosphate buffer

Answers

Answer:

0.05M is the concentration of the phosphate buffer

Explanation:

A buffer is defined as the aqueous mixture of a weak acid (KH₂PO₄) and its conjugate base (K₂HPO₄). The concentration of this buffer is the sum of the concentrations of the weak acid and the conjugate base, that is:

Concentration of phosphate buffer = 0.02M + 0.03M

=

0.05M is the concentration of the phosphate buffer

An unknown object has a mass of 150 grams and a volume of 5 cm3. What is the density of this
object?

Answers

The answer is 30 cm3
I hope this help you !!

Answer:

1.2 cm

Explanation:

The reason how I got my answer is by dividing 150 by 125 and that gave me 1.2 cm.

Methyl salicylate is a common active ingredient in liniments such as ben-gay. It is also known as oil of wintergreen. It is made up of carbon, hydrogen, and oxygen atoms. When a sample of methyl salicylate weighing 5.287 g is burned in excess oxygen, 12.24 g of carbon dioxide and 2.505 g of water are formed. What is the simplist formula for oil of wintergreen

Answers

Answer: The empirical formula is [tex]C_3H_3O[/tex].

Explanation:

The chemical equation for the combustion of hydrocarbon having carbon, hydrogen and oxygen follows:

[tex]C_xH_yO_z+O_2\rightarrow CO_2+H_2O[/tex]

where, 'x', 'y' and 'z' are the subscripts of Carbon, hydrogen and oxygen respectively.

We are given:

Mass of [tex]CO_2[/tex] = 12.24 g

Mass of [tex]H_2O[/tex] = 2.505 g

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

For calculating the mass of carbon:

In 44g of carbon dioxide, 12 g of carbon is contained.

So, in 12.24 g of carbon dioxide, =[tex]\frac{12}{44}\times 12.24=3.338g[/tex] of carbon will be contained.

For calculating the mass of hydrogen:

In 18g of water, 2 g of hydrogen is contained.

So, in 2.505 g of water, =[tex]\frac{2}{18}\times 2.505=0.278g[/tex] of hydrogen will be contained.

Mass of oxygen in the compound = (5.287) - (3.338+0.278) = 1.671  g

Step 1 : convert given masses into moles.

Moles of C =[tex] \frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{3.338g}{12g/mole}=0.278moles[/tex]

Moles of H=[tex]\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{0.278g}{1g/mole}=0.278moles[/tex]

Moles of O=[tex]\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{1.671g}{16g/mole}=0.104moles[/tex]

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C =[tex]\frac{0.278}{0.104}=3[/tex]

For H =[tex]\frac{0.278}{0.104}=3[/tex]

For O =[tex]\frac{0.104}{0.104}=1[/tex]

The ratio of C : H : O = 3: 3: 1

Hence the empirical formula is [tex]C_3H_3O[/tex].

100 POINTS FOR BEST ANSWER! What is the difference between LDOF and SDOF

Answers

An SDOF system is one whose motion is governed by a single, second-order differential equation. Only two variables, position and velocity are needed to describe the trajectory of the system. Many structures can be idealized as single degree-of-freedom systems.

The LDAP Data Interchange Format is a standard plain text data interchange format for representing LDAP directory content and update requests. LDIF conveys directory content as a set of records, one record for each object.

which of these is an example of the climate of a region?
A. Dry
B. Foggy
C. Overcast
D. Sunny​

Answers

its dry i think

Explanation:

it might be dry

Aniline, consists of carbon, hydrogen, and nitrogen. Combustion of this yields CO2, H20, and N2 as products. If the combustion of 12.5 g of aniline yields 7.1 grams of H2O, and 1.48 grams of N2, what is its empirical formula? [HINT: write out a chemical equation, consider law of conservation of mass, and then think about what percent hydrogen is in water]

A. CHN
B. C2H4N8
C. C16H15N2
D. C20H15N31

Answers

The empirical formula : C. C₁₆H₁₅N₂

Further explanation

Given

12.5 g of aniline

7.1 grams of H2O

1.48 grams of N2

Required

The empirical formula

Solution

Reaction :

mass H in H₂O :

= 2.1/18 x 7.1 g

= 0.79

mass N = 1.48

mass C :

= 12.5 g-(mass H+mass N)

= 12.5 - (0.79+1.48)

= 10.23

Mol ratio C : H : N =

= 10.23/12 : 0.79/1 : 1.48/14

= 0.853 : 0.79 : 0.106

= 8 : 7.5 : 1

= 16 : 15 : 2

A 2.0% (w/v) solution of sodium hydrogen citrate, Na2C6H6O7, which also contains 2.5% (w/v) of dextrose, C6H12O6, is used as an anticoagulant for blood which is to be used for transfusions. What is the molarity of the sodium hydrogen citrate in the solution

Answers

Answer:

0.0847M is molarity of sodium hydrogen citrate in the solution

Explanation:

The 2.0%(w/v) solution of sodium hydrogen citrate contains 2g of the solute in 100mL of solution. To find the molarity of the solution we need to convert the mass of solute to moles using molar mass and the mL of solution to Liters because molarity is the ratio between moles of sodium hydrogen citrate and liters of solution.

Moles Na2C6H6O7:

Molar Mass:

2Na: 2*22.99g/mol: 45.98g/mol

6C: 6*12.01g/mol: 72.01g/mol

6H: 6*1.008g/mol: 6.048g/mol

7O: 7*16g/mol: 112g/mol

45.98g/mol + 72.01g/mol + 6.048g/mol + 112g/mol = 236.038g/mol

Moles of 2g:

2g * (1mol / 236.038g) = 8.473x10⁻³ moles

Liters solution:

100mL * (1L / 1000mL) = 0.100L

Molarity:

8.473x10⁻³ moles / 0.100L =

0.0847M is molarity of sodium hydrogen citrate in the solution

Answer:

0.085M

Explanation:

Molecular weight of sodium hydrogen citrate=236.09 g

236.09 g of Na2C6H6O7 in 1000ml= 1 M

2%= 2 g in 1 litre (1000ml)

20/236.09=0.0847 M=0.085 M

What mass of water in grams will fill a tank 126cm long, 47 cm wide, and 13 cm high

Answers

Answer:

Mass =  76986  g

Explanation:

Given data:

Dimensions of tank = 126 cm× 47 cm× 13 cm

Mass of water required to filled = ?

Solution:

First of all we will calculate the volume of tank which is equal to the volume of water required to fill it.

Volume = length ×height ×width

Volume = 126 cm × 13 cm× 47 cm

Volume = 76986 cm³

Mass of water:

Mass = density × volume

density of water is 1 g/cm³

Mass = 1 g/cm³× 76986 cm³

Mass =  76986  g

Consider the following chemical equilibrium:
NH4SH(s) ⇌ H2SgNH3(g) Now write an equation below that shows how to calculate Kp from Kc for this reaction at an absolute temperature T. You can assume T is comfortably above room temperature. If you include any common physical constants in your equation be sure you use their standard symbols, found in the ALEKS Calculator.

Answers

Answer:

See explanation below

Explanation:

First, let's write the reaction:

NH₄SH(s)   <------> H₂S(g) + NH₃(g)

The reaction is already balanced so we don't need to do anything else.

Second, let's take into account the following. The Kc expression for this reaction, only compounds in gaseous state are the only ones that contribute to the equilibrium. Solid and liquid do not contribute to the Kc expression. This is because solid and liquid have a constant concentration near to 1, so, it won't do any difference.

Knowing this, the Kc expression for this reaction is:

Kc = [H₂S] [NH₃]

Now, to calculate Kp from Kc, there's an expression that helps a lot to do this. The expression is the following:

Kp = Kc (RT)ᵃⁿ    (1)

Where:

R: universal constant of gases

T: Temperature in K

ᵃⁿ = difference of the coefficients of the reaction.

This expression comes from the fact that Kp is an expression that instead of working with concentrations, it works with pressure.

If we use the ideal gas equation we have:

PV = nRT

Solving for P:

P = nRT/V        and C = n/V   so

P = CRT

If we now replace this, in the Kp expression of equilibrium we have:

Kp = pH₂S * pNH₃

Kp = ([H₂S]RT)¹ ([NH₃]RT)¹

Kp = (RT)¹⁺¹ ([H₂S] [NH₃])

Kp = (RT)²Kc

So finally the expression for Kp would be:

Kp = Kc (RT)²

Hope this helps

Which statement about Niels Bohr's atomic model is true?
O Higher orbits have lower energies.
O Each orbit has a specific energy level.
O Electrons can exist in any energy level.
O Orbits close to the nucleus have no energy.

Answers

Answer:

O Each orbit has a specific energy level.

Explanation:

Neils Bohr put forward his own model of the atom based on the quantum mechanics originally developed by Planck.

He assumed the Rutherford's model and suggested that the extranuclear part consists of electrons in specific spherical orbits around the nucleus.

The orbits/energy level are the permissible through which the electrons can move through.

His concept is based the concept that the electron can move round the nucleus in certain permissible orbitss

A tank of nitrogen has a volume of 14.0 L and a pressure of 1 atm. Find the volume of the nitrogen when its pressure is changed to 0.8 atm while the temperature is held constant .

Answers

Answer:

17.5 L

Explanation:

Step 1: Given data

Initial volume of the tank of nitrogen (V₁): 14.0 LInitial pressure of nitrogen (P₁): 1 atmFinal volume of the tank of nitrogen (V₂): ?Final pressure of nitrogen (P₂): 0.8 atm

Step 2: Calculate the final volume of the nitrogen

We have a gas that undergoes a change at a constant temperature. If we assume an ideal behavior, we can calculate the final volume of the nitrogen using  Boyle's law.

P₁ × V₁ = P₂ × V₂

V₂ = P₁ × V₁/P₂

V₂ = 1 atm × 14.0 L/0.8 atm = 17.5 L

What does not affect the strength of an electromagnet?

Answers

Answer:

Unlike a permanent magnet, an electromagnet can be turned on and off using electrical current. Many variables affect the strength of this electromagnet, and there are some variables that do not affect the strength. ... Making the nail longer will not make the magnet stronger, unless you also add more turns to the coil.

electromagnet can be turned on and off using electrical current. Many variables affect the strength of this electromagnet, and there are some variables that do not affect the strength

If a gold ring weighs 25 grams. How much energy in Joules would it take to get it to reach its melting point if the ring starts out at 75 degrees C? (melting point is 1064 C, Cp for gold is .129 J/g-C.

Answers

Answer:

3.2 × 10³ J

Explanation:

Step 1: Given data

Mass of the gold ring (m): 25 gSpecific heat capacity of gold (Cp): 0.129 J/g.°CInitial temperature: 75 °CFinal temperature: 1064 °C

Step 2: Calculate the temperature change (ΔT)

ΔT = 1064 °C - 75 °C = 989 °C

Step 3: Calculate the energy required (Q)

We will use the following expression.

Q = Cp × m × ΔT

Q = 0.129 J/g.°C × 25 g × 989 °C

Q = 3.2 × 10³ J

how far does light travel in 3.0 days

Answers

Answer:

[tex]d=7.77\times 10^{13}\ m[/tex]

Explanation:

We know that the speed of light is equal to [tex]3\times 10^8\ m/s[/tex]

We need to find how far the light travel in 3 days.

Speed of an object is equal to distance covered divided by time taken.

Also, 1 day = 86400 s

3 days = 259200 s

So,

[tex]d=vt[/tex]

[tex]d=3\times 10^8\times 259200\\\\d=7.77\times 10^{13}\ m[/tex]

So, the light will travel [tex]7.77\times 10^{13}\ m[/tex] in 3 days.

Nitrogen dioxide (NO2) is a toxic gas produced by cars and factories. If a car produces one mole of NO2 during a 10 mile drive, how many grams of nitrogen dioxide are produced?

Answers

Answer:

Explanation:

molecular weight of NO₂ is 14 + 2 x 16 = 46

So one mole of nitrogen dioxide will have mass of 46 grams .

How many grams of Mo2(S04)3 are in 5.35X10 22 molecules of Mo2 (SO4)3?​

Answers

Answer:

42.658

Explanation:

1) Avogadro's number is: N(A)=6.02*10²³

2) M of (Mo₂(SO₄)₃)=96*2+96*3=480 (gr/mol);

3) if N(A) ~ 1 mol of (Mo₂(SO₄)₃), tnen 5.35*10²² ~

(5.35*10²²)/(6.02*10²³)≈0.0888 mol of (Mo₂(SO₄)₃);

4) m(Mo₂(SO₄)₃)=M(Mo₂(SO₄)₃)*0.0888;

m((Mo₂(SO₄)₃)=480*0.0888=42.658 (gr)

This diagram is attempting to compare the sizes of the four inner planets. What is wrong with this diagram?

Answers

Answer:

points

Explanation:

Answer:

Where is the diagram?

Explanation:

..........................

In general, weathering tends to occur more rapidly in warm climates than in cool climates. How does this trend explain the effect of temperature on erosion rates?

Answers

Answer:

See explanation

Explanation:

Weathering refers to the breakdown of rocks to form soil. There are several agents of weathering.

In warmer regions, there are more vegetation and microorganisms and they increase the rate of biological weathering.

Since weathering leads to the formation of soil and the rate of weathering is greater in warmer climates, it also follows that as temperature increases and more soil is formed, erosion will happen faster at this higher temperature owing to the presence of more soil compared to colder climates.

There is a huge and direct effect of temperature on the rates of erosion.

The highest rate of weathering occurs in warm and wet climate because in warm and wet climatic regions, more rainfall occurs which increase the rate of weathering. Rainfall and temperature can affect the rate in which rock weathering occurs.

High temperatures and greater rainfall increase the rate of chemical weathering. Rocks in tropical regions exposed to abundant rainfall so we can conclude that hot temperatures weather much faster than similar rocks residing in cold, dry regions.

Learn more: https://brainly.com/question/20929061

Temperature can weather rocks because A heat can cause minerals to oxidize B. most rocks do not absorb heat evenly C. water contracts when it freezes D. rocks usually melt in the hot sun​

Answers

Answer:

b

Explanation:

it is not c because water expands when it freezes.

explain why different objects appear to be different colors.

Answers

Answer:

Different objects appear to be different colors, because we see color by light bouncing off an object and reflecting or transmitting into our eye. The amount of light that reflects or transmits into our eye depend on the color that we will see.

Joaquin tells his science class that galaxies consist of gas, dust, and many planets. What is the most important component of galaxios Joaquin is missing in his description?
astero de
comets
constellations
Stars

Answers

Answer:

the answer is asteroids!

Explanation:

Answer:

astroid

Explanation:

becaus

A certain substance X condenses at a temperature of 123.3°C . But if a 650. g sample of X's prepared with 24.6 g of urea ((NH2)2 CO) dissolved in it, the sample is found to have a condensation point of 124.3°C instead. Calculate the molal boiling point elevation constant Kb of X.

Answers

Answer:

1.6 °C.kg/mol

Explanation:

Step 1: Calculate the molality of urea

We will use the following expression.

m = mass(urea) / molar mass(urea) × kg solvent

m = 24.6 g / 60.06 g/mol × 0.650 kg

m = 0.630 mol/kg

Step 2: Calculate the boiling point elevation of X

The boiling point elevation is a colligative property that can be calculated using the following expression.

ΔTb = 124.3 °C - 123.3 °C = 1.0 °C

Step 3: Calculate the boiling point elevation constant

We will use the following expression.

ΔTb = Kb × m

Kb = ΔTb/m

Kb = 1.0 °C/(0.630 mol/kg) = 1.6 °C.kg/mol

A particle that travels around the nucleus of an atom in orbitals is called a(n)

Answers

Answer: electrons

Explanation:

Answer: It is called an electron because it is attracted to the positively charged particales called protons in the center of the atom.

Explanation:

Iron and vanadium both have the BCC crystal structure and V forms a substitutional solid solution in Fe for concentrations up to approximately 20 wt.% V at room temperature. Determine the concentration in weight percent of V that must be added to iron to yield a unit cell edge length of 0.289 nm.

Answers

Answer:

Explanation:

To find the concentration; let's first compute the average density and the average atomic weight.

For the average density [tex]\rho_{avg}[/tex]; we have:

[tex]\rho_{avg} = \dfrac{100}{ \dfrac{C_{Fe} }{\rho_{Fe}} + \dfrac{C_v}{\rho_v} }[/tex]

The average atomic weight is:

[tex]A_{avg} = \dfrac{100}{ \dfrac{C_{Fe} }{A_{Fe}} + \dfrac{C_v}{A_v} }[/tex]

So; in terms of vanadium, the Concentration of iron is:

[tex]C_{Fe} = 100 - C_v[/tex]

From a unit cell volume [tex]V_c[/tex]

[tex]V_c = \dfrac{n A_{avc}}{\rho_{avc} N_A}[/tex]

where;

[tex]N_A[/tex] = number of Avogadro constant.

SO; replacing [tex]V_c[/tex] with [tex]a^3[/tex] ; [tex]\rho_{avg}[/tex] with [tex]\dfrac{100}{ \dfrac{C_{Fe} }{\rho_{Fe}} + \dfrac{C_v}{\rho_v} }[/tex] ; [tex]A_{avg}[/tex] with [tex]\dfrac{100}{ \dfrac{C_{Fe} }{A_{Fe}} + \dfrac{C_v}{A_v} }[/tex] and

[tex]C_{Fe}[/tex] with [tex]100-C_v[/tex]

Then:

[tex]a^3 = \dfrac { n \Big (\dfrac{100}{[(100-C_v)/A_{Fe} ] + [C_v/A_v]} \Big) } {N_A\Big (\dfrac{100}{[(100-C_v)/\rho_{Fe} ] + [C_v/\rho_v]} \Big) }[/tex]

[tex]a^3 = \dfrac { n \Big (\dfrac{100 \times A_{Fe} \times A_v}{[(100-C_v)A_{v} ] + [C_v/A_Fe]} \Big) } {N_A \Big (\dfrac{100 \times \rho_{Fe} \times \rho_v }{[(100-C_v)/\rho_{v} ] + [C_v \rho_{Fe}]} \Big) }[/tex]

[tex]a^3 = \dfrac { n \Big (\dfrac{100 \times A_{Fe} \times A_v}{[(100A_{v}-C_vA_{v}) ] + [C_vA_Fe]} \Big) } {N_A \Big (\dfrac{100 \times \rho_{Fe} \times \rho_v }{[(100\rho_{v} - C_v \rho_{v}) ] + [C_v \rho_{Fe}]} \Big) }[/tex]

Replacing the values; we have:

[tex](0.289 \times 10^{-7} \ cm)^3 = \dfrac{2 \ atoms/unit \ cell}{6.023 \times 10^{23}} \dfrac{ \dfrac{100 (50.94 \g/mol) (55.84(g/mol)} { 100(50.94 \ g/mol) - C_v(50.94 \ g/mol) + C_v (55.84 \ g/mol) } }{ \dfrac{100 (7.84 \ g/cm^3) (6.0 \ g/cm^3 } { 100(6.0 \ g/cm^3) - C_v(6.0 \ g/cm^3) + C_v (7.84 \ g/cm^3) } }[/tex]

[tex]2.41 \times 10^{-23} = \dfrac{2}{6.023 \times 10^{23} } \dfrac{ \dfrac{100 *50*55.84}{100*50.94 -50.94 C_v +55.84 C_v} }{\dfrac{100 * 7.84 *6}{600-6C_v +7.84 C_v} }[/tex]

[tex]2.41 \times 10^{-23} (\dfrac{4704}{600+1.84 C_v})=3.2 \times 10^{-24} ( \dfrac{284448.96}{5094 +4.9 C_v})[/tex]

[tex]\mathbf{C_v = 9.1 \ wt\%}[/tex]

identify which element is oxidized and which element is reduced.
PLZ HELPP...​

Answers

In the first three equations, Magnesium, sodium and aluminum are oxidized because they loose electrons. Sulfur, oxygen and chlorine are reduced because they gain electrons. In the last equation, magnesium is reduced because it gains hydrogen, and hydrogen is oxidized because it loses electrons.

Draw the structure(s) of the major organic product(s) of the following reaction. 1. lithium diisopropylamide / hexane 2. 1 eq. CH3I You do not have to consider stereochemistry. Omit products derived from the acidic or basic reagent itself, e.g. HN(i-Pr)2 derived from N(i-Pr)2-. If no reaction occurs, draw the organic starting material. If substantial starting material is present at the end of the reaction, include it in the products. Draw one structure per sketcher. Add additional sketchers using the drop-down menu in the bottom right corner. Separate structures with signs from the drop-down menu.

Answers

Answer:

See explanation below

Explanation:

You are not providing the starting material, however, I manage to find a similar question to this, so I'm gonna use it as a basis to help you answer yours.

Now let's analyze what is happening in the reaction so we can predict the final product.

We have a ketone here, reacting at first with LDA. This is a very strong base that is commonly used in reactions with ketones and aldehydes to promove a condensation. To do this, as LDA is a strong base it will occur firts an acid base reaction, substracting the most acidic hydrogen in the molecule (Which in this case, is the Beta hydrogen of the carbonile). This will cause an enolate formation.

Then, this enolate will react with the CH3I and form a new product. The final result would be a ketone with a methyl group now attached. In the picture 2, you have the mechanism and final product.

Hope this helps

How do molecules bond?
plz answer I will give brainliest

Answers

Answer:

Atoms with a positive charge will be attracted to negatively charged atoms to form a molecule. This bonding between atoms is the key to how molecules interact with each other. ... Other molecules interact with water, combining with the atoms to create new soluble liquids.

2. According to the U.S. government, 4.9 billion barrels of crude oil flowed into the Gulf of Mexico following the explosion that destroyed the Deepwater Horizon drilling rig in April 2010. Express this volume of crude oil in liters and in cubic kilometers​

Answers

In September 2014, a U.S. District Court judge ruled that BP was primarily responsible for the oil spill because of its gross negligence and reckless conduct. In July 2015, BP agreed to pay $18.7 billion in fines, the largest corporate settlement in United States history.

15 grams of hydrogen and 7.5 grams of oxygen were placed in a beaker. An explosion happened
inside the baker that produced water. The beaker was never opened. How many grams of water
were produced

Answers

Answer:

25.33 grams of water are produced.

Explanation:

15 g H / 1.00784* = 14.8833 moles H

7.5 g O / 15.999** = 0.468779 moles O

Ratio of Hydrogen to Oxygen in Water: 2 : 1

Oxygen: 0.468779 moles

Hydrogen (calculated based on oxygen): 0.468779 * 2 = 0.937558 moles

Water: 0.468779 + 0.937558 = 1.406337 moles

Grams of water produced:

1.406337 mol * (water molar mass)

= 1.406337 mol * [2(1.00784) + 1(15.999)]

= 1.406337 mol * (18.01468***)

= 25.3347110272 g water

Notes:

*molar mass of hydrogen

**molar mass of oxygen

***molar mass of water is actually 18.01528, so the calculation of 18.01468 is close enough

-------------------------------- Summary --------------------------------

Convert hydrogen and oxygen to moles.

Determine number of moles of water using: 2 mole hydrogen + 1 mole oxygen = 1 mole water

Convert water moles to grams.

Other Questions
please help please helppppppppppppppppppp How many significant figures are in 3.20x10^2 g? Which type of writing would most likely require the use of a traditional, topic-based outline as opposed to a chronological outline?A. Instructions for repairing a leaking kitchen faucetB. Driving directions for a car tour of the national parksO C. A research essay about the chemical elements found on MarsO D. A manual that explains how to use a spectrometer -An internatinal call costs $9.35 for 32 minutes. What is the cost per minute? What is the easiest way to do the distributive property find the linear relationships Solve the literal equation for the given variable. Show your work. A = 1/2 h ( b 1 + b 2 ) for h 3 4/5 3 1/2 divide reduce to the lowest term Solve the system of linear equations.3x = 6 3 +y= -6 Royce Co. acquired 60% of Park Co. for $420,000 on December 31, 2019 when Park's book value was $560,000. The Royce stock was not actively traded. On the date of acquisition, Park had equipment (with a ten-year life) that was undervalued in the financial records by $140,000. One year later, the following selected figures were reported by the two companies.Additionally, no dividends have been paid. Rovce Co. Park Co. Book Value Book Value Fair Value Current assets 868,000 420,000 448,000 Equipment 364,000 280,000 400,000Buildings 574,000 210,000 210,000 Liabilities (546,000) (168,000) (168,000) Revenues (1,260,000) (560,000)Expenses 700,000 420,000Investment income Not Given 1. What is consolidated net income for 2011 atributable to Royce's controlling interest? 2. What is the noncontrolling interest's share of the subsidiary's net income for the year ended December 31 2011 and what is the ending balance of the noncontrolling interest in the subsidiary at December 31, 2011? 1.What country sweeps the gold medal in Arnis in the 2019 South East Asian Games? A. Indonesia B. Malaysia C. Philippines D. Thailand Why did President Jackson believe nullification crisis wouldthreaten the stability of the nation? What is the value of x in the proportion? What is the probability you will get one tail? Toss a coin three times Holstein cattle are normally black and white. A su- perb black and white bull, Charlie, was purchased by a farmer for $100,000. All the progeny sired by Charlie were normal in appearance. However, cer- tain pairs of his progeny, when interbred, produced red and white progeny at a frequency of about 25 percent. Charlie was soon removed from the stud lists of the Holstein breeders. Use symbols to ex- plain precisely why. Prompt:"There are many problems that exist in our world today, and mankind tends tospend a great deal of time and money trying to fix environmental and societalissues. However, Leo Tolstoy said, "Everyone thinks of changing the world, but noone thinks of changing himself."" Would focusing on self-improvement do moreto change the world for the better than attempting to change the world?Pre-Writing:Use the box below to create your plan. You should also go through the prompt and number thetask listed in the prompt and circle action words and verbs.Writing the Essay:Answer the prompt in the box below. The following question is based on your reading of Heart of Darkness by Joseph Conrad.What does Marlow need to repair his wrecked steamer?a.Steel platesc.Toolsb.A new boilerd.RivetsPlease select the best answer from the choices provided FOR 20 points Show your work neatly for each problem.1. Michelle and Cameron are selling popcorn for a school fundraiser. Michelle sold 10 tins of cheesepopcorn and 8 tins of caramel popcorn for a total of $446. Cameron sold 22 tins of cheese popcorn and11 tins of caramel popcorn for a total of $803. Write a system of equations to determine the cost one tinof cheese popcorn and one tin of caramel popcorn. Show all your work. Please help me with these math problems! I have had so much going on lately and haven't had time to do them Will give lots of points and make brainliest please help A car travels for a time of 2.4 hours at a speed of 65Km/hr. How far has it traveled?