A company is approached by a new warehouse management systems vendor to adopt a new system. The vendor claims that the warehouse management system reduces the average pick, pack, and ship time to below 3 minutes per order through bin location and routing optimization. You are given an opportunity visit an existing customer of the vendor. The customer allowed you to collect data for further analysis. You performed a time study and collected data about pick, pack ship duration of 25 shipments. Given, the data in the attached excel sheet
(Q1) perform a hypothesis testing by Use alpha=0.05 for hypothesis testing.
a. Stating your null and alternate hypotheses
b. Perform the proper hypothesis test and discuss your assessment of the vendor's claim.

Answers

Answer 1

Answer:

a

     The null hypothesis  is  [tex]H_o  :  \mu  = 180[/tex]

      The alternative hypothesis is  [tex]H_a :  \mu  <  180[/tex]

b

The decision rule is  fail to reject the null hypothesis

The conclusion

There no sufficient evidence to support the vendor claim  that the warehouse management system reduces the average pick, pack, and ship time to below 3 minutes(180 seconds) per order through bin location and routing optimization

Step-by-step explanation:

From the question we are told that

     The population mean is  [tex]\mu  =  3 \  minutes =  180 \  seconds [/tex]

     The sample  size is  n =  25

     The excel sheet is show on the first uploaded image

     The level of significance is  [tex]\alpha =  0.05[/tex]

     The null hypothesis  is  [tex]H_o  :  \mu  = 180[/tex]

      The alternative hypothesis is  [tex]H_a :  \mu  <  180[/tex]

Generally the sample mean is mathematically represented as

        [tex]\= x  =  \frac{156 + 136 + \cdots  + 181}{25}[/tex]

=>      [tex]\= x  = 173.2 [/tex]

Generally the standard deviation is mathematically represented as

      [tex]\sigma  =  \sqrt{\frac{\sum  (x_i - \= x )^2 }{n} }[/tex]

=>    [tex]\sigma  =  \sqrt{\frac{  (156 - 173.2 )^2 + (136 - 173.2 )^2  + \cdots + (181- 173.2 )^2  }{25} }[/tex]

=>    [tex]\sigma  =  24.261[/tex]

Generally the test statistics is mathematically represented as

      [tex]t =  \frac{\= x  -  \mu }{\frac{\sigma}{\sqrt{n} } }[/tex]

=>   [tex]t =  \frac{173.2 -  180 }{\frac{24.261}{\sqrt{25} } }[/tex]

=>   [tex] z = -1.40[/tex]    

Generally p-value is mathematically represented as

  [tex]p-value  =  P(Z <  z)[/tex]

=>  [tex]p-value  =  P(Z < -1.40)[/tex]

From the z-table  

   [tex]P(Z < -1.40) =  0.080757[/tex]

=>   [tex]p-value  = 0.080757 [/tex]

From the obtained value we that  [tex]p-value >  \alpha[/tex]

The decision rule is  fail to reject the null hypothesis

The conclusion

There no sufficient evidence to support the vendor claim  that the warehouse management system reduces the average pick, pack, and ship time to below 3 minutes(180 seconds) per order through bin location and routing optimization

   

A Company Is Approached By A New Warehouse Management Systems Vendor To Adopt A New System. The Vendor

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Answer:

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Answer:

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Step-by-step explanation:

Convert mixed numbers to fractions:

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90 * 4 / 7 * 7

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jana is a graphic designer. She created a poster for her friend’s movie on an 8.5 inches by 11 inches sheet of paper. Her friend’s movie has gotten a lot of publicity, and they want to put Jana’s poster on a billboard that is 12 feet wide and 16 feet high. How can they blow up the poster as much as possible while maintaining the ratio of the sides? a) Determine the length and width of the largest possible poster. b) What is the scale?

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Answer:

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Answers

Answer:

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Step-by-step explanation:

We can find how many of the 80 points were made with 2-point baskets by subtracting all the points gained through 3-point baskets. Since there are six 3-point baskets:

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9514 1404 393

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

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Answers

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Answers

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Step-by-step explanation:

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Answer:

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Answer:

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Answers

Complete question :

For a continuous random variable X, P(23 ≤ X ≤ 66) = 0.25 and P(X > 66) = 0.14. Calculate the following probabilities. (Leave no cells blank - be certain to enter "0" wherever required. Round your answers to 2 decimal places.)

a. P(X < 66)

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c. P(X = 66)

Answer:

P(X < 66) = 0.86

P(X < 23) = 0.61

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Step-by-step explanation:

Given that:

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P(X > 66) = 0.14 ;

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P(X < 0.66) = 0.86

P(23 ≤ X ≤ 66) = 0.25

P(X < 66) = 0.86

Hence,

P(X < 23) = 0.86 - 0.25 = 0.61

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Answers

Answer:

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Answers

Answer:

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Answers

Answer:

transitive property of equality

Step-by-step explanation:

I know cus i took the test also sorry it took so long dude

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45, 12, 48, 96, 61, 84, 29, 1,72,5,14
a.45
b.33
c.27
d.60
(apex)

Answers

Answer:

The interquartile range is 60 ⇒ D

Step-by-step explanation:

The interquartile range is the difference between the upper quartile and the lower quartile

Let us explain how to find the interquartile range

Arrange the number from smallest to greatestFind its median Q1 (the middle number in the set of numbers)Find the lower quartile Q1 which is the median of the set of the numbers before the median Find the upper quartile Q3  which is the median of the set of the numbers after the median Subtract Q1 from Q3 the answer is the interquartile range

Let us do these steps to find it

∵ The data set is {45, 12, 48, 96, 61, 84, 29, 1, 72, 5, 14}

→ Arrange them

∴ The data set is {1, 5, 12, 14, 29, 45, 48, 61, 72, 84, 96}

∵ They are 11 numbers

∴ The middle number is the 6th number (5 before it and 5 after it)

∵ The 6th number is 45

The median is 45

→ Find the lower set (before the median)

∴ The lower set is {1, 5, 12, 14, 29}

→ Find the lower quartile Q1

∵ The lower quartile is the middle number in this set

∵ There are 5 numbers

∴ The middle one is the 3rd

∵ The 3rd is 12

Q1 = 12

→ Find the upper set (after the median)

∴ The upper set is {48, 61, 72, 84, 96}

→ Find the upper quartile Q3

∵ The upper quartile is the middle number in this set

∵ There are 5 numbers

∴ The middle one is the 3rd

∵ The 3rd is 72

Q3 = 72

→ Subtract them to find the interquartile range

∵ The interquartile range = Q3 - Q1

∴ The interquartile range = 72 - 12

The interquartile range = 60

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