a charged particle a exerts a force of 2.62 n to the right on charged particle b when the particles are 13.7 mm apart. particle b moves straight away from a to make the distance between them 17.7 mm. what vector force does particle b then exert on a?

The time taken for the object to reach its highest speed is 9 seconds.

The time of motion of an object is the time taken for the object to travel from its initial position to the final position.

The time taken for the object to reach its maximum or highest speed is calculated as follows;

v = u + gt

where;

The initial velocity of the object is zero, u = 0

v = u + gt

v = 0 + gt

v = gt

t = v/g

t = (88.2 m/s) / (9.8 m/s²)

t = 9 seconds

Thus, we can conclude that time from the initial position of the object to the final position of the object is 9 seconds.

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Kinetic energy is transformed into potential energy. The charges on the nuclei of lithium and thorium, which have Z=3 and Z=90, respectively, are 3e and 90e.

Potential energy is created by converting kinetic energy (we use the classical formula since v is significantly less than c). Lithium has a Z=3 and thorium has a Z=90, meaning that the charges on each of those nuclei are 3e and 90e, respectively. The "e" in the kinetic energy unit MeV is removed by manipulating the terms, and the other factor  of e is set to be 1.610 19 C.

We note that K= 1/4π0 can be written as 8.99*109V. m/C. Thus, from energy conversation, we have

Kinetic Energy=U = r=kq1q2/K=

(8.99x10^9 v.m/C)(3x1.6x10^-19)(90e)/3.00x10^6ev

which yields r= 1.3x10^-13 m (or about 130 fm).

​

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Zero the dynamic sensor is important because of its sensitivity, resolution, range, zero drift and repeatability.

Dynamic applications describe cyclical, quick measuring processes like those frequently seen in presses. In dynamic applications, it's crucial to tare the zero point at regular intervals to prevent the measuring signal from wandering.

The input for automated zero point adjustments is provided by the strain transducers. The PLC can be used to start the zero point adjustment. The signal is reset (pulled to zero) and the zero point adjustment is performed if the input is pulled to 3 V.

The sensor is in measuring mode if the input is open. Instead of using "Active-Low-Levels," the reset logic is also possible with "Active-High-Levels".

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The equation used to calculate required fastener torque as a function of desired preload and bolt size is τ = K D [tex]F_{i}[/tex].

τ = K D [tex]F_{i}[/tex]

[tex]F_{i}[/tex] = σ[tex]_{t}[/tex] * A[tex]_{t}[/tex]

σ[tex]_{t}[/tex] = 0.9 * σ[tex]_{y}[/tex]

τ = Torque

K = Torque co-efficient

D = Nominal bolt diameter

[tex]F_{i}[/tex] = Desired preload

σ[tex]_{t}[/tex] = Tensile stress

A[tex]_{t}[/tex] = Tensile stress area

σ[tex]_{y}[/tex] = Ultimate yield strength

Therefore, the equation used to calculate required fastener torque as a function of desired preload and bolt size is τ = K D [tex]F_{i}[/tex].

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The work calls for a 10k Omega resistance value and a 1 nF capacitance value. Being aware of those output gives us a clear advantage. To get the frequency of unity gain, we can utilize the transfer function (2.34)

The output waveform will consist of positive and negative spikes of size Vsat, which is roughly 13V for a 15V op-amp power source, for a square wave input, let's say 1V peak and 1 KHz.

The differentiated output will be zero whenever the input is held constant at 1V.

For a perfect square wave, the input slope is infinite when it transitions between the t 1V levels.

As a result, the output is clipped to around 13V for a 15V op-amp power source.

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The question was incomplete. Check below the full question.

differentiator utilizes an ideal op amp, a 30 kω resistor, and a 0.03 μf capacitor. what is the frequency 0f in hz at which its input and output sine‐wave signals have equal magnitude? what is the output signal for a 1 v peak‐to‐peak sine‐wave input with frequency equal to 10f₀ ?

A physical quantity which has only magnitude is called scalar quantity eg: speed and distance whereas physical quantities which have both magnitude and direction are called vector quantities eg: velocity and displacement.

The average speed of the girl for the entire trip is 8m/s

Firstly we have to find the total distance that the girl covered.

As formula says

Distance = speed * time

So according to the question;

Total Distance = 10×6 + 5×4

= 60+20

= 80

And the total time taken by the girl = 6+4

= 10

Therefore, by Putting the values in the formula:

Average speed = 80÷10

=8m/s

Hence, the average speed of the girl is 8m/s.

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The linear speed is √5 m/s and the angular speed is √5/0.06 rad/s.

We need to know about the conservation of energy to solve this problem. The energy can not be created or destroyed, the only way is to change to another form. It can be written as

Ei = Ef

where Ei is initial energy and Ef is the final energy

From the question above, we know that

R = 0.06 m

h = 0.5 m

The playground slide is converting the potential energy from height to kinetic energy. Hence,

Ei = Ef

PE = KE trans + KE rot

m . g  . h = 1/2 . m . v² + 1/2 I . ώ²

m . 10  . 0.5 = 1/2 . m . v² + 1/2 m.R² . ώ²

5 = 1/2(v² + R² . ώ²)

10 = (v² + R² . v²/R²)

2v² = 10

v = √5 m/s

v = ώ . R

√5 = ώ . 0.06

√5 = ώ . 0.06

ώ = √5/0.06 rad/s

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Answer:

the answer is A

Explanation:

I took the test

Answer:

A

Explanation:

1) Magnitude of the magnetic field equals (permeabilityoffrespace) (currentmagnitude)

2π(distance)

B = μ02πr

Developing the Formula

B = denotes the strength of the magnetic field in Tesla (T)

The permeability of open space (4107Tm/A) is shown by the symbol 0

Electric current strength is expressed as I in terms of amperes (A)

R stands for the meters-long distance (m)

2) the magnetic force per unit length of wire in a uniform field is  

F/l =IB sinθ .

force on a length  l

current  I

uniform magnetic field  B ,

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Answer: the force required to begin moving the book is 7.93 N.

Explanation:The concepts required to solve this problem is forces.

Initially, calculate the force required to begin moving the book by using the expression for the static frictional force. Later, calculate the force required to keep the book moving by using the expression for the kinetic friction.

Here,

is the coefficient of static friction and N is the normal force.

Here,

is the coefficient of kinetic friction and N is the normal force.

Step: 1

The expression for the force required to begin moving the book is,

The normal force acting on the book ,

Substitute mg for N in the equation

.

Substitute 0.442 for

, 1.83 kg for m,

for g in the above equation.

Therefore, the force required to begin moving the book is 7.93 N.

Explanation:

The external force is required to move the book on the surface of the desk is known as static frictional force.

The forces acting on the book along the y direction is,

By using Newton’s second law of motion the net forces acting along y direction is,

As the book is along the x direction means that there is no motion of the book along the y direction. Hence the acceleration of the book is equal to zero.

Now the normal force is equal to the weight of the book.

Hint:

Calculate the force required to keep the book moving by using the expression for the kinetic friction.

Step: 2

The force required to keep the book moving ,

The normal force acting on the book ,

Substitute mg for N in the equation

.

Substitute 0.240 for

, 1.83 kg for m,

for g in the above equation.

Therefore, the force required to keep the book moving is 4.30 N.

The kinetic frictional force acts on the object if the object is in motion.

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If a 1.83 kg book is placed on a flat desk, 10.089 N of force is required to start moving the book. If the book and desk experience static friction of 0.442 and kinetic friction of 0.240, respectively.

A force that acts between moving surfaces is referred to as kinetic friction. A force acting in opposition to the direction of a moving body on the surface is felt. The two materials' coefficient of kinetic friction will determine how much force is applied.

The book needs force to move

Ff = N * s Ff = (1.83 kg)(9.81 m/s2)(0.562)=10.089 N

The book needs force to continue.

Ff = (1.83 kg) (9.81 m/s2) (0.305) = 5.47 N

The force that prevents a sliding object from moving is known as friction. Everything has kinetic friction, which prevents two or more objects from moving in unison. In contrast to how an object would like to slide, the force operates in that direction. When a car needs to stop by kinetic friction, we engage the brakes, and that's when friction is created. Again, friction is to blame when one wishes to stop abruptly while walking. however, when we are forced to stop in the middle of a puddle.

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All objects in free fall have the same acceleration because  acceleration due to gravity is always the same. So option B is correct.

Gravity can be referred to as the force by which a planet or other body draws objects toward its center.

Gravity is one of the universe's fundamental forces and dominates every moment of our conscious experience which helps keeps us close to the ground.

All objects in free fall have the same acceleration because  acceleration due to gravity is always the same.

Free fall is a special type of motion in which the only force acting upon an object is gravity which will make all objects with the same rate of acceleration, regardless of their mass.

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Answer

the answer is 6.25

Explanation:

Here, the mass of the stone (m) = 0.5 kg, velocity at which it is thrown (v) = 5 m/s, The kinetic energy of the stone (KE) =? We have, Kinetic energy of the stone (KE) = \ (\frac12mv^21) = \(\frac120.5\times5^2\) = 6.25 Joules Hence, the kinetic energy of the stone (KE) is 6.25 joules. Hope it will be helpful

Answer: The nebular theory states that our solar system formed from the gravitational collapse of a giant interstellar gas cloud—the solar nebula. – (Nebula is the Latin word for cloud.) Kant and Laplace proposed the nebular hypothesis over two centuries ago.

Explanation:

The distance covered by the train is 225m.

Given,

u = 36km/hr = 10ms^(-1)

a = 5ms^(-2) ,t = 5sec

According to Newton's first law of motion:

v = u + (a × t)

v = 10 + (5 × 5) = 35ms^(-1)

According to Newton's third law of motion:

(v)²- (u)² = 2as

(35)² - (10)² ÷ (2 × 2.5) = s

s = 225m

The final velocity of the train is derived using Newton's first law of motion. Where, u = initial velocity, a = acceleration,v = final velocity, and t = time. The equations of motion define the behavior of the physical schema in order of motion.

Then find the distance covered by the train implementing the third equation of motion with velocity v, starting velocity u, constant velocity a, and displacement.

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The acceleration of this car is zero. Because Acceleration is the change of velocity with respect to time and since car maintains a constant velocity, there is no acceleration.

The rate at which a velocity changes over time in both direction and speed. A point or object going straight ahead is accelerated when it accelerates or decelerates. Even if the speed is constant, motion on a circle accelerates because the direction is always shifting.

Acceleration is the rate at which speed changes, while speed is the ratio of the distance in a time period. The metric process utilizes meters per second (m/s) as the unit of speed and meters per second squared (m/s²) as the measure of acceleration. Velocity is a scalar quantity, whereas speed is indeed a scalar quantity.

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Answer:

1.45 N

Explanation:

Newton's Second Law: F=ma

Convert 145 grams to kilograms

0.145kg*10m/s^2

1.45 N

Answer:

298.8g

Hope this helps! :)

The change in momentum of the ball will be biggest in Case 1.

The change in momentum of the ball will be highest in the case 1, where the ball bounce back to it's half the initial height after the collision with the cement floor.

When the ball hits the cement floor, the time of contact between ball and the floor is the very very less. This is why the force imparted by the cement floor on the ball will be very high.

The impulse I imparted on the ball by floor is.

I = ∆F/∆t

As the force is very high and the time of contact is very less. The impulse will be very high. And as we know from the impulse momentum theorem. The impulse is equal to the change in momentum.

So the change in momentum will be biggest in case 1.

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Complete question - Identical balls are dropped from the same initial height and bounce back to half the initial height. In case 1 the ball bounces off a cement floor and in case 2 the ball bounces off a piece of stretchy rubber. In which case is the change in momentum of the ball between the instant just before the ball collides with the floor or rubber and the instant just after the ball leaves the floor or rubber the biggest?

Case 1

Case 2

Same in both

Answer:

MA of a simple machine is 4. It means that load overcome is 4 times more than effort used in the machine. This machine can multiply force 4 times the effort used.

Deceleration is the slowing down of the body as it moves away from its starting place. Negative acceleration is a common term for deceleration.

The kinematic equation was used to get the truck's estimated speed right before braking as

v2 = u2 + 2*acceleration *displacement.

Consequently,

[2*(45.0 m)*(6 m/s)]

= √540 = 23.24 m/s

The velocity, or v, of an object is the rate at which its direction is changing as seen from a particular angle and as measured by a particular unit of time.

The rates at which an object's velocity with respect to time changes are known as accelerations and are stated as constants. Whenever a force is operating on an object, it will always accelerate in a direction that is parallel to that force.

The length of a displacement vector is the smallest distance between the starting and ending coordinates of a moving point P.

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The radius of its circular orbit is calculated to be 1/B √(2qV/m)

If the field is vacuum, then the magnetic field is dominant factor determining the motion. As the magnetic force is perpendicular to the direction of travel, a charged particle follows a curved path in a magnetic field. The particle then continues to follow curved path until it forms a complete circle. As the magnetic force is perpendicular to velocity, so that no work is done on the charged particle. The kinetic energy of the particle and speed remain constant. The direction of motion is usually affected but not the speed.

The speed of particle just before entering into magnetic field is v₀

qV = 1/2*m *v₀²

v₀= √(2qV/m)

Radius of the circular path is given by

 r= mv₀/qB

r=m/qB √(2qV/m)

=1/B √(2qV/m)

Radius of circular orbit = 1/B √(2qV/m)

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Applied voltage across the capacitor is , V​​​​​​o = 15 v

Capacitance , C = 6 × 10-6 F

Resistance in the circuit , R = 5 M.ohm = 5 × 106 ohm.

• Maximum charge in the capacitor is,

Q = CV​​​​​o = (6×10-6 F)×(15 v) = 90 × 10-6 c

20% of maximum charge Q is, q = 0.2 ×(90×10-6) c

q =18×10-6 c.

when charge is 20% of maximum charge , voltage across the capacitor is,

V = q/C

V = (18 × 10-6 c)/(6 × 10-6 F) = 3 v

• At that time , voltage of the battery is V​​​​​​o = 15 v

Voltage across the capacitor is , V = 3 v

Resistance in the circuit, R = 5 × 106 ohm

So, applying ohm's law :

Current in the circuit, I = (V​​​​​​o - V)/R

> I = (15 - 3)/(5×106) A

> I = 2.4 × 10-6 A = 2.4 \muA

The current in the circuit is  2.4  \muA .

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The distance covered by Sam within the first 13 seconds is 96.75 m.

Given that the mass m of Sam is 80 kg and the force F is 170 N. The coefficient of friction is 0.1.

The net force is given below

Fₙ = F - F₁

Where Fₙ is the net force and F₁ is the friction force.

Fₙ = 170 - μmg

Fₙ = 170 - 0.1 x 80 x 9.8

Fₙ = 91.6

Fₙ = ma

91.6 = 80 x a

a = 91.6 / 80

a = 1.145 m/s²

For the first 13 seconds.

So, the distance covered by Sam with this acceleration is given .

s = ut + 1/2 at²

u is the initial velocity which will be zero and t is the time interval.

So,

s = 1/2 at²

s = 1/2 x 1.145 x 13²

s = 96.75 m

Hence, the distance covered by Sam within the first 13 seconds is 96.75 m.

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Answer:

A

Explanation:

because both energy and temperature ️ increase both are related.

Answer: Density

Explanation:  

I remember learning it in 9th-grade physic class.

Answer:

18 m

Explanation:

Velocity = distance / time

v = d/t

d = vt

d = (6 m/s) (3  s)

d = 18 m

Hope that helps