A change of state is a(n)
process.
A. irreversible
B. reversible

Answer:

movement of charged particles through the wire .

Explanation:

When electricity is passed through the wire of electromagnet , moving electrons of the wire produces magnetic field . This magnetic field in increased due to high permeability of soft iron of the electromagnet . It is this magnetic field which creates magnetic force .

Answer:

Solution A: 0.00400M

Solution B: 0.00400M

Solution C: 4.00x10⁻⁵M

Explanation:

Solution A is diluting the 0.100M NaCl from 10mL to 250mL. That is:

250mL / 10mL = 25 times.

That means molar concentration of sln A is:

0.100M / 25 = 0.00400M

Solution B is obtained diluting 25mL to 100mL:

100mL / 25mL = 4 times

0.00400M / 4 times = 0.00100M

And solution C is obtained diluting the solution C from 20mL to 500mL:

500mL / 20mL = 25 times

Solution C:

0.00100M / 25 times = 4.00x10⁻⁵M

The formula for serial dilution can be used to obtain the molarity of solution A, B , C.

M1V1 = M2V2

M2 = 0.100 M ×  10 mL/250-mL

M2 = 0.004 M

M1V1 = M2V2

M2 = 0.004 M × 25 mL/100-mL

M2 = 0.001 M

M1V1 = M2V2

M2 = 0.001 M × 20 mL/500-mL

M2 = 0.00004 M

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Answer:

See explanation and image attached

Explanation:

"A formal charge (FC) is the charge assigned to an atom in a molecule, assuming that electrons in all chemical bonds are shared equally between atoms, regardless of relative electronegativity" (chemlibretext).

We can obtain the formal charge from the formula;

Formal Charge = [number of valence electrons on atom] – [non-bonded electrons + 1/2number of bonds].

A structure in which SO2 has a zero formal charge is attached to this answer.

Image credit: Chemtopper

Answer:

2.56 eV

Explanation:

Using the formula;

ΔE= -RH(1/n^2final - 1/n^2initial)

RH = -2.18 * 10-18 J

nfinal = 2

ninitial =1

Substituting values;

ΔE= -2.18 * 10-18 J(1/4^2 - 1/2^2)

ΔE= -2.18 * 10-18 J(0.0625 - 0.25)

ΔE= 4.09 * 10^-19 J

To convert to eV

4.09 * 10^-19 J/1.6 * 10^-19

=2.56 eV

Answer:

e. I, At

Explanation:

Hello!

In this case, since the periodic trends of a series of elements belonging to the same group towards physical and chemical properties tend to be the same when closer in period, we notice that Mg and Al, Br and Kr and As and Br are close but in period, not in the same group; therefore e. I, At, iodine and astatine, are going to tend to exhibit the greatest similarity in their physical  and chemical properties.

Best regards!

Answer: The comparison of the experimental amount of product to the calculated amount : Percentage yield

The calculated amount of product under ideal conditions : Theoretical yield

The amount of product experimentally produced : Experimental yield or actual yield

Explanation:

Theoretical yield is to determine how much of the product should be formed based on stoichiometry of the given reaction. It is the maximum amount of product that could be formed from the given amounts of reactants.

Experimental yield or actual yield is the amount of product that is actually formed when the reaction is carried out in the laboratory.

Percentage yield is the ratio of the experimental yield to the theoretical yield, expressed as a percentage.

Answer:

Option 4

Explanation:

Volume of any substance is the space occupied by it.

For cuboidal objects the volume is equal to the product of length, weight and height.

Hence, mathematically volume can be written as

[tex]V = L * W * H[/tex]

Thus, option 4 is correct

Answer:

Silver Lake Picnic Area, Or C

Explanation:

Answer:

The Forces that form each star would be your answer :)

Answer:

an attraction between a partially positive region in one molecule and a partially negative region in another molecule....dipole-dipole interaction

an attraction between two temporarily polarized molecules...dispersion forces

an attraction between a negatively charged particle and a partially positive region in a molecule....ion dipole interaction

an attraction between a partially positive hydrogen atom in a molecule and a partially negative and highly electronegative atom on another molecule....Hydrogen bonding

Explanation:

Some molecules have permanent dipole. As a result of this, the positive part of one molecule may attract the negative part of the other molecule leading to dipole-dipole interaction.

Dispersion forces occur in all molecules and is as a result of temporary polarization of a molecule due to instantaneous dipole–induced dipole attractions.

If a charged particle is attracted by a dipole in a molecule, we call it ion-dipole interaction.

When hydrogen is bonded to a highly electronegative element, the positive end of the dipole is on hydrogen while the negative end of the dipole is on the electronegative element. Molecular associations often result from this permanent dipole and is called hydrogen bonding, e.g, HF.

Answer:

[tex]10\, {\rm Fe}\rm SO_4 + 2\, \rm K {Mn} O_4 + 8\, H_2SO_4\\ \to 5\, {Fe} (SO_4)_3 + K_2SO_4 + 2\, {Mn}SO_4 + 8\, H_2O[/tex].

Explanation:

Identify the elements with oxidation state changes:

Oxidation states of iron, [tex]\rm Fe[/tex]:

Oxidation state of manganese, [tex]\rm Mn[/tex]:

The change in the oxidation state of [tex]\rm Mn[/tex] is five times the opposite of the change to the oxidation state of [tex]\rm Fe[/tex]. If there are one mole of [tex]\rm Mn\![/tex] atoms in each mole of this reaction, there would be five times as many [tex]\rm Fe\![/tex] atoms per mole reaction. In other words:

[tex]\displaystyle 5\, \overset{+2}{\rm Fe}\rm SO_4 + 1\, \rm K \overset{+7}{Mn} O_4 + ?\, H_2SO_4\\ \to \frac{5}{2}\, \overset{+3}{Fe} (SO_4)_3 + ?\, K_2SO_4 + 1\, \overset{+2}{Mn}SO_4 + ?\, H_2O[/tex].

(Notice that each mole of this reaction would include five times as many [tex]\rm Fe[/tex] atoms as [tex]\rm Mn[/tex] atoms.)

Multiply the coefficients by [tex]2[/tex] to eliminate the fraction:

[tex]\displaystyle 10\, {\rm Fe}\rm SO_4 + 2\, \rm K {Mn} O_4 + ?\, H_2SO_4\\ \to 5\, {Fe} (SO_4)_3 + ?\, K_2SO_4 + 2\, {Mn}SO_4 + ?\, H_2O[/tex].

Find the unknown coefficients using the conservation of atoms.

Reactants:

Therefore, among the products:

[tex]\displaystyle 10\, {\rm Fe}\rm SO_4 + 2\, \rm K {Mn} O_4 + ?\, H_2SO_4\\ \to 5\, {Fe} (SO_4)_3 + {1}\, K_2SO_4 + 2\, {Mn}SO_4 + ?\, H_2O[/tex].

Products:

Reactants:

[tex]\displaystyle 10\, {\rm Fe}\rm SO_4 + 2\, \rm K {Mn} O_4 + 8\, H_2SO_4\\ \to 5\, {Fe} (SO_4)_3 + {1}\, K_2SO_4 + 2\, {Mn}SO_4 + ?\, H_2O[/tex].

Products:

Therefore, among the products:

[tex]\displaystyle 10\, {\rm Fe}\rm SO_4 + 2\, \rm K {Mn} O_4 + 8\, H_2SO_4\\ \to 5\, {Fe} (SO_4)_3 + {1}\, K_2SO_4 + 2\, {Mn}SO_4 + 8\, H_2O[/tex].

Answer:

8.1 × 10² g

Explanation:

Step 1: Write the balanced equation

2 C₅₇H₁₁₀O₆ + 163 O₂ ⇒ 114 CO₂ + 110 H₂O

Step 2: Convert 1.6 lb of C₅₇H₁₁₀O₆ to g

We will use the conversion factor 1 lb = 453.592 g.

1.6 lb × 453.592 g/1 lb = 7.3 × 10² g

Step 3: Calculate the moles corresponding to 7.3 × 10² g of C₅₇H₁₁₀O₆

The molar mass of C₅₇H₁₁₀O₆ is 890.83 g/mol.

7.3 × 10² g × 1 mol/890.83 g = 0.82 mol

Step 4: Calculate the moles of water produced from 0.82 moles of C₅₇H₁₁₀O₆

The molar ratio of C₅₇H₁₁₀O₆ to H₂O is 2:110. The moles of H₂O produced are 110/2 × 0.82 mol = 45 mol

Step 5: Calculate the mass corresponding to 45 moles of H₂O

The molar mass of H₂O is 18.02 g/mol.

45 mol × 18.02 g/mol = 8.1 × 10² g

What type of rock is limestone? Describe how a limestone rock is likely to change over a long period of time. Pls answer I will mark brainiest.

Answer:

they get animal cells

Explanation:

Answer:

Na3PO4 + KCl = NaCl + K3PO4

Explanation:

You have to know the Chemical Formula for Sodium phosphide, = Na3PO4 and Potassium chloride. which is = KCI

Answer:

1.62

Explanation:

From the given information:

number of moles of benzamide  [tex]=\dfrac{70.4 \ g}{121.14 \ g/mol}[/tex]

= 0.58 mole

The molality = [tex]\dfrac{mass \ of \ solute (i.e. \ benzamide )}{mass \ of \ solvent }[/tex]

[tex]= \dfrac{0.58 }{0.85 }[/tex]

= 0.6837

Using the formula:

[tex]\mathbf {dT = l \times k_f \times m}[/tex]

where;

dT = freezing point = 27

l = Van't Hoff factor = 1

kf = freezing constant of the solvent

∴

2.7 °C = 1 × kf ×  0.6837 m

kf = 2.7 °C/ 0.6837m

kf = 3.949 °C/m

number of moles of NH4Cl = [tex]\dfrac{70.4 \ g}{53.491 \ g /mol}[/tex]

= 1.316 mol

The molality = [tex]\dfrac{1.316 \ mol}{0.85 \ kg}[/tex]

= 1.5484

Thus;

the above kf value is used in determining the  Van't Hoff factor for  NH4Cl

i.e.

9.9 = l × 3.949 × 1.5484 m

[tex]l = \dfrac{9.9}{3.949 \times 1.5484 \ m}[/tex]

l = 1.62

Answer

software is a set of instruction given to a computer to perform specific function. MS office etc.

the tangible parts of a computer are known as hardware.

Explanation:

software pprforms the function while hardwares are the structural parts of a computer.

Nacl = (. 23+35. 5)

= 58.5g

.

1 mol of Nacl = 58.5g

X mol Of Nacl = 25g

X Mol of Na Cl =25 ÷ 58.5

X mol of Nacl = 0.4 mol

Answer:

Amount = 2250 g

Explanation:

Note: This question is incomplete and lacks each and every data to solve. However, I have found the similar question on the internet and will be solving this question for you. Cheers!

Data Missing:

Organic Compound O

Solubility = 0.225 g/ml

Temperature = 10°C

Calculate the greatest mass of O that can be dissolved in 10.0 L acetonitrile at 10°C temperature.

Solution:

As we know the volume of the acetonitrile = 10.0 L

but first, we need to convert this into mL

We know that,

1 L contains 1000 mL

So,

10 L will contain = 10 x 1000 mL

10 L = 10000 mL

We, can write, 10000 mL as:

1 x [tex]10^{4}[/tex] mL

Now, the formula to calculate the greatest amount of O that can be dissolved in 1 x [tex]10^{4}[/tex] mL acetonitrile at 10°C temperature is:

Amount  = Solubility x volume

Here,

Solubility = 0.225 g/ml

and

Volume = 1 x [tex]10^{4}[/tex] mL

Plugging in the values, we get:

Amount  = 0.225 g/ml x 1 x [tex]10^{4}[/tex] mL

Amount  = 0.225 x [tex]10^{4}[/tex] g

Amount = 2250 g

Answer:

Other species will slowly die, because the species that eat snails and crayfish will not have anything to eat, then the thing that eats them will not have anything. This process will go on and on. So long story short populations will decrease, then off.

Answer:

35mL of the 7.5% solution are required to meake the media

Explanation:

To prepare the culture media there are required 2.625g of sodium bicarbonate. We have a 7.5% solution of sodium bicarbonate (That is, 7.5g of sodium bicarbonate in 100mL of solution). Thus, to obtain 2.625g we need:

2.625g Sodium bicarbonate * (100mL / 7.5g) =

Answer:

11.73 Kg of CO₂

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

2C₈H₁₈ + 25O₂ —> 16CO₂ + 18H₂O

Next, we shall determine the mass of C₈H₁₈ that reacted and the mass of CO₂ produced from the balanced equation. This can be obtained as follow:

Molar mass of C₈H₁₈ = (12×8) + (18×1)

= 96 + 18

= 114 g/mol

Mass of C₈H₁₈ from the balanced equation = 2 × 114 = 228 g

Convert 228 g to kg.

1000 g = 1 Kg

Therefore,

228 g = 228 g × 1 Kg / 1000 g

228 g = 0.228 Kg

Molar mass of CO₂ = 12 + (16×2)

= 12 + 32

= 44 g/mol

Mass of CO₂ from the balanced equation = 16 × 44 = 704 g

Convert 704 g to Kg

1000 g = 1 Kg

Therefore,

704 g = 704 g × 1 Kg / 1000 g

704 g = 0.704 Kg

SUMMARY:

From the balanced equation above,

0.228 Kg of C₈H₁₈ reacted to produce 0.704 Kg of CO₂.

Finally, we shall determine the mass of carbon dioxide, CO₂, that will be produced by the reaction of 3.8 kg of octane, C₈H₁₈. This can be obtained as follow:

From the balanced equation above,

0.228 Kg of C₈H₁₈ reacted to produce 0.704 Kg of CO₂.

Therefore, 3.8 kg of C₈H₁₈ will react to produce = (3.8 × 0.704) / 0.228 = 11.73 Kg of CO₂

Thus, 11.73 Kg of CO₂ is added to the atmosphere per 3.8 kg of C₈H₁₈.

Answer:

0.432 drinks are toxic

Explanation:

The toxic dose of ethylene glycol is 0.1 mL per kg body weight (mL/kg). In grams (Density ethylene glycol = 1.11g/mL):

1.11g/mL * (0.1mL / kg) =  0.111g/kg

If the victim weighs 85kg, its letal dose is:

85kg * (0.111g/kg) = 9.435g of ethylene glycol

Using the concentration of ethylene glycol in the liquid:

9.435g of ethylene glycol * (550g liquid / 120g ethylene glycol) = 43.2g of liquid are toxic.

The drinks are:

43.2g of liquid * (1 drink / 100 g) =

1s², 2s², 2p⁶, 3s², 3p⁵

Given

Phosphorus element

Required

The electron configuration

Solution

The energy level is expressed in the form of electron configurations.  

Writing electron configurations starts from the lowest to the highest sub-shell energy level. There are 4 sub-shells in the shell of an atom, namely s, p, d and f.

Charging electrons in the sub shell uses the following sequence:  

1s², 2s², 2p⁶, 3s², 3p⁶, 4s², 3d¹⁰, 4p⁶, 5s², 4d¹⁰, 5p⁶, 6s², etc.  

Electron configurations are based on the number of electrons in the atomic number.

The atomic number of the phosphorus is 15, so the number of electrons is 15.

The configuration:

1s², 2s², 2p⁶, 3s², 3p⁵

Answer:

 (C) Mass of KCl(s), mass of H20, initial temperature of the water, and final temperature of the solution

Explanation:

molar enthalpy of solution of KCl(s) is heat evolved or absorbed when one mole of KCl is dissolved in water to make pure solution . The heat evolved or absorbed can be calculated by the following relation.

Q = msΔt where m is mass of solution or water , s is specific heat and Δt is change in temperature of water .

So data required is mass of water or solution , initial and final temperature of solution , specific heat of water is known .

Now to know molar heat , we require mass of solute or KCl dissolved to know heat heat absorbed or evolved by dissolution of one mole of solute .

The correct option is option C.

To determine the molar enthalpy of the solution of [tex]Kcl(s)[/tex] is pure [tex]H_2O(l)[/tex]

We need to know that the,

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Answer:

The rate of disappearance of C₂H₆O = 2.46 mol/min

Explanation:

The equation of the reaction is given below:

2 K₂Cr₂O₇ + 8 H₂SO₄ + 3 C₂H₆O → 2 Cr₂(SO₄)₃ + 2 K₂SO₄ + 11 H₂O

From the equation of the reaction, 3 moles of C₂H₆O is used when 2 moles of Cr₂(SO₄)₃ are produced, therefore, the mole ratio of C₂H₆O to Cr₂(SO₄)₃ is 3:2.

The rate of appearance of Cr₂(SO₄)₃ in that particular moment is given 1.64 mol/min. This would than means that C₂H₆O must be used up at a rate which is approximately equal to their mole ratios. Thus,  the rate of of the disappearance of C₂H₆O can be calculated from the mole ratio of Cr₂(SO₄)₃ and C₂H₆O.

Rate of disappearance of C₂H₆O = 1.64 mol/min of  Cr₂(SO₄)₃  * 3 moles of C₂H₆O / 2 moles of Cr₂(SO₄)₃

Rate of disappearance of C₂H₆O = 2.46 mol/min of C₂H₆O

Therefore, the rate of disappearance of C₂H₆O = 2.46 mol/min

There are 4.5165  × 10²³ molecules are there in 0.75 mol NH₃.

A molecule is a set of or more atoms held together by means of attractive forces referred to as chemical bonds; depending on the context, the term may additionally or won't encompass ions that satisfy this criterion.

1 mole of NH₃ = 6.022 × 10²³

0.75 mole =  6.022 × 10²³ × 0.75 molecule

                  = 4.5165  × 10²³ molecules.

A molecule is defined as the smallest unit of a compound that consists of the chemical properties of the compound. Molecules are made of agencies of atoms. Describing the shape of an atom, an atom is also subdivided into smaller devices. Protons, electrons, and neutrons are sub-debris of an atom. The smallest particle of a substance has all of the bodily and chemical homes of that substance. Molecules are made up of 1 or extra atoms.

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#SPJ1

mass of PbI₂ = 27.6606 g

Given

Pb(NO₃)₂ + NaI → PbI₂ + NaNO₃

28.0 grams of Pb(NO₃)₂ react with 18.0 grams of NaI

Required

mass of PbI₂

Solution

Balanced equation

Pb(NO₃)₂ + 2NaI → PbI₂ + 2NaNO₃

The principle of a balanced reaction is the number of atoms in the reactants = the number of atoms in the product

mol Pb(NO₃)₂ :

= 28 : 331,2 g/mol

= 0.0845

mol NaI :

= 18 : 149,89 g/mol

= 0.12

Limiting reactant : mol : coefficient

Pb(NO₃)₂ : 0.0845 : 1 = 0.0845

NaI : 0.12 : 2 = 0.06

NaI limiting reactant (smaller ratio)

mol PbI₂ based on NaI

= 1/2 x 0.12 = 0.06

Mass PbI₂ :

= 0.06 x 461,01 g/mol

= 27.6606 g

Answer:

___________

Poem with Compound Words

------------------------------------------

whenever there's a full moon,

I cannot overlook,

some alterations in my ways,

and changes in my look.

my werewolf hair grows everywhere,

my werewolf teeth get long,

my eyesight gets much keener and

I'm muscular and strong.

I get to roam around outside,

the moonlight makes me howl,

these otherworldly sound effects

mean I am on the prawl.

I see the moon is round and full,

I'm moonstruck by the sight,

I've made some telltale changes-so, you'd best stay in tonight.

Explanation:

I HOPE IT HELPS YOUR ENGLISH SUBJECT ;) ★

Answer:

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