The concentration of reactant B after one half-life is equal to 1.512M.
What is the second-order reaction?A reaction is said to be a second-order reaction when the overall order of the reaction is equal to two. Suppose the reaction can be represented as follows:
A + A → P
The rate of second-order reactions can also be written as r = kA²
The term k'' is the rate constant for the second-order reaction and the unit of the reaction rate (r) is moles per liter per second (molL⁻¹s⁻¹) and the unit of the second-order rate constant is M⁻¹s⁻¹.
The half-life of the second-order reaction is:
[tex]t_{\frac{1}{2} } = \frac{1}{B_oK}[/tex]
where B₀ is the initial concentration of reactant B.
Given the rate constant of the 2nd order reaction, k = 1.45× 10⁻³M⁻¹s⁻¹
The half-life of the reaction, [tex]t_{\frac{1}{2} } = 228 sec[/tex]
B₀ = 1/ (1.45× 10⁻³) × 228
B₀ = 3.025M
The concentration of the reactant B after one half-life = B₀/2 = 1.512 M
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When an electron beam strikes a block of
copper, x-rays of frequency 2.74 × 10^19 Hz
are emitted. What is the wavelength of these
x-rays?
Answer in units of pm.
The wavelength (in pm) of the x-rays, given that it has a frequency of 2.74×10¹⁹ Hz is 10.9 pm
How do I determine the wavelength of the x-rays?We understood that the velocity, wavelength and frequency of a wave are related according to the following equation:
Velocity (v) = wavelength (λ) × frequency (f)
v = λf
With the above equation, we can determine the wavelength. Details below.
The wavelength of the x-rays can be obtained as follow:
Frequency of x-ray (f) = 2.74×10¹⁹ HzVelocity of x-ray (v) = 3×10⁸ m/sWavelength of x-ray (λ) = ?v = λf
3×10⁸ = λ × 2.74×10¹⁹
Divide both sides by 2.74×10¹⁹
λ = 3×10⁸ / 2.74×10¹⁹
λ = 1.09×10⁻¹¹ m
Multiply by 10¹² to express in picometer (pm)
λ = 1.09×10⁻¹¹ × 10¹²
λ = 10.9 pm
Thus, we can conclude that the wavelength is 10.9 pm
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Please select either A, B, C, or D at the end.
Molar ratio is widely used in stoichiometry and it represents the number of moles of a compound needed to react with another compound in order to produce a specific amount of product, as the reaction we have in the question:
2 H3PO4 + 3 FeBr2 -> 6 HBr + Fe3(PO4)2
If we have H3PO4 as the focus, we will have the following molar ratios:
2 H3PO4 = 3 FeBr2
2 H3PO4 = 6 HBr
2 H3PO4 = 1 Fe3(PO4)2
These are the specific amounts of reactants needed and products produced in order for the reaction to occur
Therefore the answer is letter B, since 2 H3PO4 = 2 H3PO4 is not a correct molar ratio
I NEED HELP ASAP!
Isotopes of certain ___ elements that spontaneously emit ___ and ___ from the ____.
Isotopes of certain _radioactive__ elements that spontaneously emit _radiation__ and _rays__ from the _nuclei___
What cause Isotopes to emit radiation ?Any of multiple species of the same chemical element with differing masses whose nuclei are unstable and spontaneously produce radiation in the form of alpha, beta, and gamma rays are known as radioactive isotopes, also known as radioisotopes, radionuclides, or radioactive nuclides.
Isotopes are identical elemental atoms with differing quantities of neutrons. Numerous elements have one or more radioactive isotopes. Due to the instability of their nuclei, they decay and release radiation.Many of the radioisotopes in the uranium, thorium, and actinium natural radiation decay series, as well as the naturally occurring radioisotopes potassium-40 and carbon-14, generate gamma radiation.Learn more about Isotopes here:
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How much energy would it take to heat a section of the cooper tubing that weighs about 650.0g, from 15.83C to 24.11C
Energy would it take to heat a section of the copper tubing that weighs about 650.0g, from 15.83°C to 24.11°C is 2.072 KJ.
The formula heat energy is given by :
q = mcΔT
given that :
m = 650.0 g
specific heat of copper c = 0.385 J/g °C
T1 = 15.83°C
T2 = 24.11°C
ΔT = T2 - T1 = 24.11°C - 15.83°C = 8.28 °C
putting all the values in the formula :
q = mcΔT
q = 650.0 g × 0.385 J/g °C × 8.28 °C
q = 2072.2 J = 2.072 KJ
Thus, Energy would it take to heat a section of the copper tubing that weighs about 650.0g, from 15.83°C to 24.11°C is 2.072 KJ.
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Which statement best describes the connection between environmental stress and maturation in girls? Question 3 options: Puberty occurs earlier in girls who have experienced chronic stress. Puberty occurs later in girls who have experienced chronic stress. The onset of puberty in girls is determined genetically, thus stress has no effect on the timing of puberty. The effects of stress on maturation in girls are unknown.
The connection between environmental stress and maturation in girls is that puberty occurs earlier in girls who have experienced chronic stress.
What is puberty?The term puberty refers to the time in the life a person in which secondary se--xual characteristics begin to occur. It is the time that a person begins to mature. This period could also be called the adolescence stage of person.
When a developing person is at this stage, there are several kinds of characteristics that show that the person have arrived at this stage of life. ow we know that there is a connection between the environmental stress and maturation in girls. This implies that as a result of environmental changes that some girl may seem to have an earlier or a later puberty. This can now explain the diversities in the times in which a girl does experience puberty as we know it now.
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Electrons are transferred from atoms of
sodium
to atoms of
phosphorus
. This transfer makes the sodium atoms
and the phosphorus atoms
. As a result, the sodium and phosphorus atoms strongly
each other.
Electrons are transferred from atoms of sodium to atoms of phosphorus this transfer makes the sodium atoms and the phosphorus atoms as a result, the sodium and phosphorus atoms strongly each other and it form sodium phosphide
Electron are smallest particles that make up an atom and they posses negative charge
Here given data is when electron are transferred from atom of sodium to the atom of phosphorous and this transfer made the sodium and phosphorous atom and because the form sodium phosphide because sodium is positive and phosphorous is negative and this positive negative are attracts and form sodium phosphide
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