Answer:
Approximately [tex]6.59\times 10^{3}\; \rm m\cdot s^{-1}[/tex].
Explanation:
Look up the radius of the earth: approximately [tex]6.371 \times 10^{3}\; \rm km[/tex].
The radius of the orbit of this satellite is the of the radius of the earth (at ground level) plus the height of the satellite relative to ground level:
[tex]\begin{aligned}r &\approx 6.371 \times 10^{3}\; {\rm km} + 550\; {\rm km} \\ &= 6.921 \times 10^{3}\; \rm km\end{aligned}[/tex].
Convert the units of both distance and time to standard units:
Orbital radius:
[tex]\begin{aligned}r &\approx 6.921 \times 10^{3}\; {\rm km} \\ &= 6.921 \times 10^{3}\; {\rm km} \times \frac{10^{3}\; \rm m}{1\; \rm km} \\ &= 6.921 \times 10^{6}\; \rm m\end{aligned}[/tex].
Orbital period:
[tex]\begin{aligned}t &= 110\; \text{minute} \\ &= 110\; \text{minute} \times \frac{60\; \text{second}}{1\; \text{minute}} \\ &= 6.6 \times 10^{3}\; \text{second}\end{aligned}[/tex].
Calculate the circumference of this orbit:
[tex]\begin{aligned}& 2\, \pi\, r \\ \approx\; & 2 \, \pi \times 6.921 \times 10^{6}\; {\rm m} \\ \approx\; & 4.35 \times 10^{7}\; \rm m\end{aligned}[/tex].
Calculate the orbital speed (tangential) of this satellite:
[tex]\begin{aligned}v &= \frac{2\, \pi\, r}{t} \\ &\approx \frac{4.35 \times 10^{7}\; \rm m}{6.6 \times 10^{3}\; \rm s} \\ &\approx 6.6 \times 10^{3}\; \rm m \cdot s^{-1}\end{aligned}[/tex].
If the mass of a substance having its volume 80 cm is 68 g. Calculate the density of the substance
[tex]\text{Given that,}\\\\\text{Mass}~ m = 68 ~\text{g} = 68 \times 10^{-3}~ \text{kg}\\\\\text{Volume}~ V = 80 ~ \text{cm}^3 = 80 \times 10^{-6}~ \text{m}^3 = 8\times 10^{-5}~ \text{m}^3\\\\\\\text{Density} ~\rho = \dfrac mV = \dfrac{68\times 10^{-3}}{8 \times 10^{-5}} = 8.5 \times 10^2 = 850 ~ \text{kg}~\text{m}^{-3}[/tex]
NEED HELP ASAP PLEASE
The drop time can be calculated as follows t = sqrt((2y)/g) where y is the vertical height of the table and g is the acceleration due to gravity (9.80 m/)How did the calculated drop time compare to the average of your measured drop times? Find the percent error using the following equation measured drop time - calculated drop time % 100 calculated drop time What factors might cause the differences?
did you end up getting the answer- im struggling
Answer:
I would think human error could cause differences like not pressing the stop watch on time.
Explanation:
Samantha's teacher asks her to describe motion in one dimension. This type of motion is always
A motion in one dimension is a type of motion that is always along a straight line and has a constant acceleration.
Motion refers to a change in the location (position) of an object or physical body with respect to a reference point, especially due to the action of an external force.
In Science, the motion of an object or physical body is described in terms of the following parameters:
SpeedForceAccelerationDistanceTimeFurthermore, there are three (3) forms of motion based on dimension and these include:
1. Motion in one dimension
2. Motion in two dimension
3. Motion in three dimension
A motion in one dimension (one-dimensional motion) is also referred to as rectilinear or linear motion. Also, it is always along a straight line in any direction and characterized by constant acceleration.
Read more on motion here: https://brainly.com/question/17675825
How much power is used in question #2 if the power time was 100secs
I really need the Formula, substitute & solve , answer with units.
Answer:
I just put a random number for the work
Explanation:
I hope it is ok.
Help it’s multiple choice 11 through 15 please!
1. • Here, force of gravity on the block = 20 N.
• Therefore, the normal force will also be the same, i.e., 20 N [According to Newton's Third Law, on every action, there is an equal and opposite reaction]
• The coefficient
[tex] u_{k} = 0.4[/tex]
• Force of friction =
[tex]u_{k} \times \: normal \: \: \: force \\ = 0.4 \times 20N \\ = 8N[/tex]
• Hence, the force of sliding friction between the block and the ground is 8 N.
• So, it is option c. 8 N
2. The answer is option d. continue in the same direction with no change in speed.
We know, force = mass × acceleration. When force is 0, then acceleration will also be 0 since mass cannot be 0. So, there will be no change in speed.
3. It is option b. force that is required to give a one kilogram object the acceleration of 1 m/s^2.
Newton is the SI unit of force. As mentioned earlier, force = mass × acceleration. The SI unit of mass and acceleration is Kg and m/s^2 respectively.
So, 1 N = 1 Kg × 1 m/s^2.
4. It is d. not zero.
Acceleration is the change in speed. So, if the force is zero, then acceleration will not occur.
5. Force = 2 N
Acceleration of the object A = 2 m/s^2.
Acceleration of the object B = 1 m/s^2.
Therefore, mass of the object A = 2 N ÷ 2 m/s^2 = 1 Kg
And, mass of the object B = 2 N ÷ 1 m/s^2 = 2 Kg
So, the mass of object B is greater than that of object A.
Hence, the answer is option c. Object B has more mass.
Hope you could get an idea from here.
Doubt clarification - use comment section.
what depth would a submarine have to submerge so that it would not be swayed by surface waves wwith a wavelength of 30 meters
Answer:
Explanation:
ello
What is the boiling point of water?
Group of answer choices
373.15 degrees Fahrenheit
373.15 degrees Celsius
373.15 Kelvin
Answer:
373.15 Kelvin
Explanation:
Boiling Point of water
= 100 degree Celsius
= (100 + 273.15) Kelvin
= 373.15 Kelvin
according to newton's third law, of a sledgehammer hits a wall with a force of 1000 n, how much force does the wall hit the sledgehammer? a - 1000 n b 1000 n c 0 n d 500 n
The correct option is A: the force exerted on the wall by the sledgehammer is - 1000 N
Newton's third lawNewton's third law of motion states that for every action or force, there is an equal but oppositely directed force.
Application of the newton's third lawForce with which the sledgehammer hits the wall = 1000 N
From the Newton's third law, an equal but oppositely directed force is exerted on the sledgehammer by the wall.Thus, the force exerted by the sledgehammer on the wall = -1000 N
The negative sign indicates that the force acts in a direction opposite to that of the sledgehammer.Thus, the correct option is A: the force exerted on the wall by the sledgehammer is - 1000 N
Learn more about Newton's third law and force at: https://brainly.com/question/13874955
advantages of writing very large and very small numbers in the terms of power of ten
Answer:
Large numbers might create fuse, be confusing and if you miss even one of the zeros it is a very big deal in a situation when you are making a spaceship. Hope this answers your questions :) Merry Christmas. Have fun.
Explanation:
2
Explanation:
for saving space in large numbers
and small numbers for multiplying easily
A hockey player hits a rubber puck from one side of the rink to the other. It has a mass of .170 kg, and is hit at an initial speed of 6 m/s. If the rink is 61 meters long, how fast is the puck moving when it hits the far wall?
By using third law of equation of motion, the final velocity V of the rubber puck is 8.5 m/s
Given that a hockey player hits a rubber puck from one side of the rink to the other. The parameters given are:
mass m = 0.170 kg
initial speed u = 6 m/s.
Distance covered s = 61 m
To calculate how fast the puck is moving when it hits the far wall means we are to calculate final speed V
To do this, let us first calculate the kinetic energy at which the ball move.
K.E = 1/2m[tex]U^{2}[/tex]
K.E = 1/2 x 0.17 x [tex]6^{2}[/tex]
K.E = 3.06 J
The work done on the ball is equal to the kinetic energy. That is,
W = K.E
But work done = Force x distance
F x S = K.E
F x 61 = 3.06
F = 3.06/61
F = 0.05 N
From here, we can calculate the acceleration of the ball from Newton second law
F = ma
0.05 = 0.17a
a = 0.05/0.17
a = 0.3 m/[tex]s^{2}[/tex]
To calculate the final velocity, let us use third equation of motion.
[tex]V^{2}[/tex] = [tex]U^{2}[/tex] + 2as
[tex]V^{2}[/tex] = [tex]6^{2}[/tex] + 2 x 0.3 x 61
[tex]V^{2}[/tex] = 36 + 36
[tex]V^{2}[/tex] = 72
V = [tex]\sqrt{72}[/tex]
V = 8.485 m/s
Therefore, the puck is moving at the rate of 8.5 m/s (approximately) when it hits the far wall.
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please help me !! i’ll mark brainliest if you’re right!
please help me! i’ll mark brainliest if you’re correct!
The answer is that the resultant force is the vector sum of the component forces. In your simple example, where the component forces (F1 and F2) are at right angles to one another, as illustrated below, then the resultant force (r) is given by:
[tex]r= \sqrt{(f_{1}) {}^{2} +( f_{2})^{2} + 2f_{1}f_{2}. cos \: Θ, } \\ where \\ \: Θ, = angle \: between \: f_{1} \: and \: f_{2} \\ r = \sqrt{(2) {}^{2} + (5) {}^{2} + 2 \times 2 \times 5 \times cos90 } \\ \sqrt{4 + 25} = \sqrt{29} = 5.385 \\ nearest \: hundred = 5.39[/tex]
Answer: 3N to the right
Explanation: 2N- 5N= 3N
assume that the hubble constant is 72 km/s/mpc. if a galaxy is 100mpc away, how fast is it moving away from us?
The galaxy is 7200 km/s moving away from us.
A Hubble is a large telescope in space.
The question can be solved using the formula below
⇒ Formula
v = Cd........................ Equation 1⇒ Where:
v = Speed of the galaxyC = Hubble constantd = Galaxy's distance⇒ Given:
C = 72 km/s/mpcd = 100 mpc⇒ Substitute these values into equation 1
v = 72(100)v = 7200 km/s.Hence, the galaxy is 7200 km/s moving away from us.
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What force is responsible for how magma flows and rocks stack up on top of one another?
Question 6 options:
Electroweak and Strong
Nuclear
Electromagnetic
Gravitational
Gravitational Force
Explanation:-
The magma flows through the gap between the rocks which are stacked up on top of one another.
The gravity attracts the magma to do that.
Also the rocks are stacked because of the gravitational force between them
Hence Option D is correct
Hope it helps
Answer:
pls mark me as brainliest
Explanation:
last one
how much force would be needed to push a box weighing 30 N up a ramp that ahas an ideal mechanical advantage of 3
Answer:
60n would be the needed force
The force needed to push a box weighing 30 N up a ramp that has an ideal mechanical advantage of 3 is equal to 10 N.
What is the mechanical advantage?The mechanical advantage can be described as the ratio of the input force to the output force. The mechanical advantage of any machine can be determined by the ratio of the forces involved to do the work.
The ratio of the resistance force to the effort is called the actual mechanical advantage which will be comparatively less. The efficiency of a machine is always determined by equating the ratio of its output to its input.
The efficiency of the machine is equal to the ratio of the actual mechanical advantage (M.A.) and theoretical mechanical advantage. Mechanical advantage can be defined as the force produced by a machine to the force applied to it.
Given the load = 30 N and the ideal mechanical advantage = 3
Mechanical advantage = Load/ Effort
Input force or effort = Load/ M.A.
Force = 30/3
Input Force = 10 N
Learn more about the Mechanical advantage, here:
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#SPJ2
A passenger of mass 90kg is involved in a minor car crash. The car approaches a solid barrier at 32m/s. It crashes into the barrer and stops in 0.2s. Determine the impulse that must be applied to the car to bring it to rest
Answer:
I hope this helps:)
Explanation:
good luck:)
What is the difference between folk dance and ballroom dance
Answer:
folk dancing is old music and ball room is young dancing
what is the velocity of a 50 kg dog with 3000 j of kinetic energy
Answer:
KE = 225000000 J
Explanation:
Answer:
10.954. from equation. KE=1/2m(v^2)
2KE=m(v^2) 6000=50(v^2) (v^2)=6000/50
(v^2)=120. square root for all v=10.954 m/s
Which statement describes ionic compounds?
A) ionic compounds are positively charged
B) ionic compounds are neutral
C) ionic compounds are negatively charged
Answer:the answer is b
Explanation:
This is because in an ionic bond negative and positive bonds are present
Which of the following statements cannot be supported by Kepler's laws of planetary motion?
A planet's distance from the sun will not be the same in six months.
A planet's speed as it moves around the sun will not be the same in six months.
The rotational speed of the four smallest planets can be determined using the rotational speeds of the four largest planets and their orbital periods.
The average distance of Saturn can be calculated using the average distance of Neptune and the orbital period of both planets.
A current of 2.0 A flows through a flashlight bulb when it is connected
across the terminals of a 5 V battery. What is the energy dissipated by this
bulb during 1 hour of continuous working?*
Using Joules law
[tex]\\ \sf\Rrightarrow H=VIt[/tex]
[tex]\\ \sf\Rrightarrow H=5(2)(1)[/tex]
[tex]\\ \sf\Rrightarrow H=10Kwh[/tex]
I don't understand when to use the formule with the constant k, and when to use the formula without it.
In the exercise that i sent here, they use the formule with a constant but I don't get why.
Can someone help me out please?
Thanks.
Answer:
This appears to be the formula for the electrical force between 2 objects.
You need this constant to calculate the electrical force between 2 charged objects.
Note that k = (1 / 4 * π ∈0)
∈0 is called the permittivity constant and ∈0 = 8.85E-12 farad/m
k = ( 1 / (4 * 3.28 * 8.85E-12) = 8.99E9
This makes F reasonably easy to remember as
F = 9E9 Q1 * Q2 / R^2 Newtons for the electrical force between Q! and Q2 separated by R
A 5.00 kg crate is on a 21.0 degree hill. Using X-Y axes tilted down the plane, what are the X AND Y components of the NORMAL FORCE?
Answer:
y-component = 45.75N
x-component = 0N
Explanation:
Which type of border shows the division between Sonora and Chihuahua?
National border
State border
Physical boundary
Natural boundary
how does gravitational lensing tell us about the mass of a galaxy cluster?
Answer:
Newton's universal law of gravitation predicts how mass can distort light, so we can apply Newton's law to determine the mass of the cluster. ... The lensing allows us to determine the orbital speeds of galaxies in the cluster, so that we can determine the mass of the cluster from the orbital velocity law.
Explanation:
Two sections of genetic material from a fruit fly are shown in the diagram.
X
-Eye color
-Wing shape
What does the diagram reveal about the inherited traits of fruit flies?
А Inherited traits are controlled by tissues, which are found in organs.
B
Inherited traits are controlled by organs, which are found in tissues.
с
Inherited traits are controlled by genes, which are found in chromosomes.
OD
Inherited traits are controlled by chromosomes, which are found in genes.
the answer is c, inherited traits are controlled by genes, which are found in chromosomes
What does the Area under a Speed-time graph represent?
A. acceleration
B. average speed
C. deceleration
D. distance travelled
Answer:
d. distance travelled
Explanation:
answer
The gravitational force between two asteroids is 6.2 × 108 N. Asteroid Y has three times the mass of asteroid Z.
If the distance between the asteroids is 2100 kilometers, what is the mass of asteroid Y?
Answer:
1.1x10¹⁶ kg
Explanation:
Let m = mass of asteroid y.
Because asteroid y has three times the mass of asteroid z, the mass of asteroid z is m/3.
Given:
F = 6.2x10⁸ N
d = 2100 km = 2.1x10⁶ m
Note that
G = 6.67408x10⁻¹¹ m³/(kg-s²)
The gravitational force between the asteroids is
F = (G*m*(m/3))/d² = (Gm²)/(3d²)
or
m² = (3Fd²)/G
= [(3*(6.2x10⁸ N)*(2.1x10⁶ m)²]/(6.67408x10⁻¹¹ m³/(kg-s²))
= 1.229x10³² kg²
m = 1.1086x10¹⁶ kg = 1.1x10¹⁶ kg (approx)
how to find velocity of center of mass before and after the collision
Hey there! I'll try to provide you with my best answer.
Answer: In a collision, the velocity change is always computed by subtracting the initial velocity value from the final velocity value. If an object is moving in one direction before a collision and rebounds or somehow changes direction, then its velocity after the collision has the opposite direction as before.
how can I make a square fit in a triangle hole
cut the square and make it a triangle