A cat with LONG HAIR (heterozygous) is a carrier of the short hair allele. Its mate has SHORT HAIR. Use a Punnett Square to determine the probability of their offspring having LONG HAIR.
Group of answer choices
25%
100%
0%
50%
75%
Answers
Answer:
50%
Explanation:
Hi there!
We are given the hair types of two cats
The first one has long hair, and it's heterozygous, meaning it has one dominant, and one recessive allele. We are given that it is a carrier of the short hair allele, meaning in its genotype, it has the short hair gene (that doesn't necessarily mean it's there in its phenotype). However, since it has long hair (genotype), that means that the long hair allele is dominant (the gene that will always show), and the short haired one is recessive (the gene that gets "covered up" by the dominant allele). Let's say the genotype of the long haired cat is Tt, where T is the long hair, and t is the short hair
The second cat has short hair, and as we have mentioned above, the allele for short hair is recessive, so the short haired cat has 2 copies of the short hair allele. Its genotype is tt
Please see below for the Punnett Square
Hope this helps! :)
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Das wot Googoo told me.
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Answer:
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Explanation:
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Answer:
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Explanation:
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Answer:
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Explanation:
Answer:
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Answers
Answer:
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Explanation:
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Answer:
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in garden peas, yellow seeds (y) are dominant to green seeds (y), and inflated pods (i) are dominant to constricted pods (i). suppose you have crossed yyii parents with yyii parents. draw the f1 punnett square and predict the expected f1 phenotype(s). list the genotype(s) of gametes produced by f1 individuals. draw the f2 punnett square. based on this punnett square, predict the expected phenotype(s) in the f2 generation and the expected frequency of each phenotype.
Answers
Complete question:
In garden peas, yellow seeds (Y) are dominant to green seeds (y), and inflated pods (I) are dominant to constricted pods (i).
Suppose you have crossed YYII parents with yyii parents.
Draw the F1 Punnett square and predict the expected F1 phenotype(s). List the genotype(s) of gametes produced by F1 individuals. Draw the F2 Punnett square. Based on this Punnett square, predict the expected phenotype(s) in the F2 generation and the expected frequency of each phenotype.Answer:
F1 phenotype ⇒ 100% plants heterozygous for both traits, expressing yellow seeds and inflated pods, YyIi. F1 gametes ⇒ YI, Yi, yI, yiF2 Phenotype ⇒ 9/16 are expected to be plants with yellow seeds and inflated pods, Y-I-3/16 are expected to be plants with yellow seeds and constricted pods, Y-ii3/16 are expected to be plants with green seeds and inflated pods, yyI-1/16 are expected to be plants with green seeds and constricted pods, yyiiExplanation:
Available data:
yellow seeds (Y) are dominant to green seeds (y) inflated pods (I) are dominant to constricted pods (i)1st Cross:
Parentals) YYII x yyii
Gametes) YI, YI, YI, YI yi, yi, yi, yi
Punnett square) YI YI YI YI
yi YyIi YyIi YyIi YyIi
yi YyIi YyIi YyIi YyIi
yi YyIi YyIi YyIi YyIi
yi YyIi YyIi YyIi YyIi
F1) 100% of the progeny is expected to be heterozygous for both traits, expressing yellow seeds and inflated pods, YyIi.
2nd Cross:
Parentals) YyIi x YyIi
Gametes) YI, Yi, yI, yi YI, Yi, yI, yi
Punnett square) YI Yi yI yi
YI YYII YYIi YyII YyIi
Yi YYIi YYii YyIi Yyii
yI YyII YyIi yyII yyIi
yi YyIi Yyii yyIi yyii
F2) Genotype
1/16 are expected to be YYII2/16 are expected to be YYIi1/16 are expected to be YYii2/16 are expected to be YyII4/16 are expected to be YyIi2/16 are expected to be Yyii1/16 are expected to be yyII2/16 are expected to be yyIi1/16 are expected to be yyiiPhenotype
9/16 are expected to be plants with yellow seeds and inflated pods, Y-I-3/16 are expected to be plants with yellow seeds and constricted pods, Y-ii3/16 are expected to be plants with green seeds and inflated pods, yyI-1/16 are expected to be plants with green seeds and constricted pods, yyiiHere we've got a condition, in which an inexperienced pea has traits that include the colour of the seed, and the nature of the pod, wherein the Yellow colour seed (Y) is dominant over the inexperienced colour seed (y), and the inflate pods (I) is dominant over the constricted pods (i).
When we make a pass among true-breeding mother and father having yellow colour seed, and inflated pods with true-breeding determine have inexperienced colour seed and constricted pods, then withinside the F1 technology we get -
The genotype of a true-breeding determines having a yellow colour seed, and inflated pOds=YY||.The genotype of a true-breeding determined to have inexperienced colour seed and constricted pods = yyii.A pass among YYII (Yellow, inflated) x yyii (Green, constricted).Gametes are made out of a mother and father having genotype YY|I=YI.Gametes are made out of a mother and father having genotype i = Yi.1st cross :
Parental YYII x yyii
Gametwes YI,YI,YI,YI yi,yi,yi,yi
Punnet square YI YI YI YI
yi YyIi YyIi YyIi YyIi
yi YyIi YyIi YyIi YyIi
yi YyIi YyIi YyIi YyIi
yi YyIi YyIi YyIi YyIi
100% pure progeny is obtained.
2nd cross :
Parents : YyIi x YyIi
Gametes: YI, Yi, yI, yi YI, Yi, yI, yi
F2) Genotype ratios :
1/16 are anticipated to be YYII 2/16 are anticipated to be YYli1/16 are anticipated to be YYii2/16 are anticipated to be Yyll 4/16 are anticipated to be Yyli2/16 are anticipated to be Yyii 1/16 are anticipated to be yyll2/16 are anticipated to be yyli 1/16 are anticipated to be yyiiPhenotype ratio :
9/16 are anticipated to be vegetation with yellow seeds and inflated pods, Y-I3/16 are anticipated to be vegetation with yellow seeds and constricted pods, Y-ii.3/16 are anticipated to be vegetation with inexperienced seeds and inflated pods, yyli1/16 are anticipated to be vegetation with inexperienced seeds and constricted pods, yyii.What is dominant ?Dominant is over the receive and thus it is the dominant character. Its include and genotypes for example red colour of flowers are dominant over white.
Thus it is clear that the above explanations are true.
To learn more about the dominant refer to the link ;
https://brainly.com/question/8368376
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Answers
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Answers
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Explanation:
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to consolidate the study of history into
smaller textbooks
to streamline communication related to the
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to avoid confusion and miscommunication
when discussing parts of the body
to get people more interested in joining the
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Answers
Answer:
B. To streamline communication related to the health sciences
C. To avoid confusion and miscommunication when discussing parts of the body
Explanation:
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Answers
Answer:
A
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Answers
Answer:
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Answer:
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Answers
This should help you
(Really hope it does an plss mark me as brainliest)
Answer:
your answer would be G
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delivering oxygen and nutrients to organs and cells and carrying their waste products away.
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Answers
Answer:
b
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Answers
Answer:
22 autsomes and an X or y chromosome
Explanation:
Humans have 46 chromosomes. 23 from the mother and 23 from the father. The father has x and y chromosome. While the mother has two x chromosomes. 22 chromosomes each are given from both parents And the other chromosome (the 23rd) are the chromosomes for sex genes. Autosomes are all chromosomes that are not sex chromosomes. Therefore 22 autosomes are given from each parent. With reference to this questions 22 autsomes and one x or y chromosome will be given from the father.
what is a chromosome made of
Answers
Answer:
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Explanation:
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Explanation:
Which nucleotide bonds with
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A. Thymine
B. Uracil
C. Adenine
D. Guanine
Answers
Answer:
B
Explanation:
In DNA cytosine bonds with thymine meanwhile in RNA uracil bonds with thymine instead.
Answer:
D. Guanine
Explanation: