A car’s brakes decelerate it at a rate of -2.20 m/s2. If the car is originally travelling at 17 m/s and comes to a stop, then how far, in meters, will the car travel during that time?

Answers

Answer 1

Answer:

x = 65.68 [m]

Explanation:

To solve this problem we must use the following equation of kinematics.

[tex]v_{f}^{2}=v_{o}^{2}-2*a*x[/tex]

where:

Vf = final velocity = 0 (comes to stop)

Vo = initial velocity = 17 [m/s]

a = desaceleration = -2.2 [m/s²]

x = displacement [m]

Now replacing, we have:

[tex](0)^{2}=(17)^{2}-2*(2.2)*x\\4.4*x = 289\\x = 65.68 [m][/tex]

Answer 2
A :-) for this question , we should apply
2as = v^2 - u ^2
Given - u = 17 m/s
v = 0 m/s
a = -2.20 m/s^2
Solution -
2as = v^2 - u^2
2 x -2.20 x s = 0^2 - 17^2
s = 0^2 - 17^2 by 2 x -2.20
s = -( 17 x 17 ) by 2 x -2.20
( Cut minus ( - ) and ( - ) )
s = 17 x 17 by 2 x 2.20
s = 289 by 4.4
s = 65.6

.:. The car travelled 65.6 meters.

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Calculate the force applied (in newtons) if a pressure of 2000Pa is acting on an area of 3m2.

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P=F/A

Force= P * A = (2000 x 3) N = 6000N

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Answers

Answer:

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Explanation:

If they hope to see that energy is conserved, then energy must not be gained or lost during the experiment. That is, loss due to air resistance must be negligible.

Answer:

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Answer:

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Explanation:

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Answers

Answer:

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Explanation:

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11. Dance together
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Answers

Answer:

3 chocolate

explanation

Answer:9 and 6

Explanation:

2.
Mass of car = 200 kg and g = 10 m/s? or 10 N/kg (approx. value)
position of car
GPE (J) = mgh KE (J) =
GPE + KE
0.5mv2
(height)
60.000
top (30 m) before
ride starts so v=0
Halfway (15 m)
30,000
34 way down (7.5
4,000
m)
bottom(0 m)
0
3.

Answers

That’s a lot of work

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Answers

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Answer:

All fluids exert pressure like the air inside a tire. The particles of fluids are constantly moving in all directions at random. As the particles move, they keep bumping into each other and into anything else in their path. These collisions cause pressure, and the pressure is exerted equally in all directions.

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is -3 a solution to equation 3x -5 = 4+ 2x

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A 615.00 kg race car is uniformly traveling around a circular race track. It takes the race car 20.00 seconds to do one lap around the 80.00 m radius circular track. What is the frequency of the race car's circular motion?

Answers

Answer:

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Being Normal mean Submitting to the Conformed society that Barry B Benson wanted to rebel Against so that he didn't have to work the Same Job Everyday to which his father accepted himself into. once Barry had surpassed the Bee Law after speaking with Vanessa they got onto the plane to save all of the Flowers on earth and Save Mankind/Beekind, Barry gets accepted as a Pollen Jock. thus Reaching the end of the movie

A football is kicked with a speed of 18 m/s at an angle of 65° to the horizontal. How far does the football travel horizontally before it hits the ground?

Answers

The horizontal distance traveled by the football is determined as 25.33 m.

Horizontal distance traveled by the football

The horizontal distance traveled by the football is calculated as follows;

X = u²sin(2θ)/g

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u is the initial speedg is acceleration due to gravity

X = (18² x sin(2 x 65))/9.8

X = 25.33 m

Thus, the horizontal distance traveled by the football is determined as 25.33 m.

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Answers

Answer:

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Answers

Answer:

Is Mercury an answer on your thing?

Explanation:

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Answer:

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Answers

Answer:

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