a car starts from rest at a stop sign. it accelerates at 4.3 m/s2 for 6.4 s , coasts for 2.2 s , and then slows down at a rate of 3.5 m/s2 for the next stop sign.

Newton's law of inertia best describes why a golf ball stays on the tee until the golf club hits it.

Newton's law of inertia states that an object at rest will remain at rest unless acted upon by an external force. In the case of a golf ball on a tee, the golf ball is not moving because there is no external force acting upon it. Therefore, the golf ball will remain on the tee until the golf club is used to hit it, applying an external force and causing the golf ball to move.

Newton's laws of motion are three physical laws that, together, laid the foundation for classical mechanics. They describe the relationship between a body and the forces acting upon it, and its motion in response to those forces.

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To determine the order of a chemical reaction, you can plot the concentration of one of the reactants or products versus time and monitor the slope of the line. The slope of the line will be proportional to the rate of the reaction, and the exponent of concentration term in the rate law will be the order of the reaction.

If you have two plots of the decomposition of Br₂ as a function of time, you can choose order of the reaction by comparing the slopes of the lines. If slopes of lines are the same, then the reaction is first order. If slopes of lines are proportional to the concentrations of Br₂ to the power of 2, then the reaction is second order. If slopes of lines are proportional to the concentrations of Br₂ to the power of 3, then the reaction is third order.

To calculate rate constant, you will require to employ the rate law for the reaction. The general form of rate law is: rate = k[A]^m[B]^n...

To determine the rate constant, you will require to estimate the concentrations of the reactants and the rate of the reaction at different times and utilize the rate law to solve for "k". The rate of the reaction can be calculated by estimating the change in concentration of a reactant or product over a particular time interval.

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The statements that is true about the car and the truck is "The car's measurement is a scalar, and the truck's measurement is a vector"

third option is the correct answer.

Scalar quantities are those quantities that can be described by magnitude only.

These type of quantity has no direction, but can be effectively described by direction only.

Examples of scalar quantities include the following;

Vector quantities are those type of quantity which can be described by both quantity and direction.

Examples of vector quantities include the following:

Speedometer is a device used in measuring the speed of a car, hence the measurement of the car is scalar. The speed of the truck has direction (next lane), so it can be effectively regarded as vector quantity.

Thus, the speed of the truck has both magnitude and direction and can be called vector measurement.

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The distance from the top of the pendulum is 2.98 m.

Given,

         Mass of the pendulum rod,   M = 1.23 kg

         Length of the pendulum rod, L = 1.25 m

         Mass of the weight,               m = 1.99 kg

         Time period,                           T = 2 s

Let,

         The distance is d.

We know that the formula of the time period is given by

        [tex]T =[/tex] [tex]2\pi \sqrt{\frac{1}{(M+m)g} \frac{1}{3}ML^{2}+\frac{1}{(M+m)g}md^{2}}[/tex]

         4 = 4π² {1/3(1.23)(1.25)(1.25) + (1.99)d²}/{(1.23 + 1.99)9.8}

         94.668 = 6.034 + 10d²

         d = 2.98 m

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The velocity of the truck after the collision is 4.47 m/s.

We know that we can be able to use the principle of the conservation of momentum to be able to obtain the velocity of the truck. We know that from this principle, the momentum after collision would be the same as the momentum before collision.

Using this approach we can say that;

Momentum before collision = Momentum after collision

Then;

(3,242 *  11) + (1,413  * 0) = (3,242 * v) + ( 1,413 * 15)

35662 = 3242v + 21195

v = 35662  - 21195/3242

v = 4.47 m/s

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The velocity of the truck immediately after collision is 4.46m/s

?

Conservation of linear momentum states that in a closed system, if two bodies collides ,the momentum is always conserved. Or we can say conservation of linear momentum states that the momentum before collision is equal to the momentum after collision.

Momentum is expressed as : momentum = mass × velocity

The momentum before collision =

3242× 11 + 1413×0

= 35662+0 = 35662kgm/s

The momentum after collision

3242v + 1413× 15

= 3242v + 21195

from conservation of momentum

35662= 3242v+ 21195

3242v = 35662-21195

3242v = 14467

v = 14467/3242

v = 4.46m/s

therefore the velocity of the truck after collision is 4.46m/s

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In quantum mechanics, virtual particles are the hypothesized particles that combine to form quarks, graviton etc is a correct statement.

Quantum mechanics is the branch of science that examines the atomic and subatomic behavior of matter and light. It tries to explain and characterize the properties of molecules, atoms, and their constituent protons, neutrons, electrons, and other less well-known particles like quarks and gluons. These characteristics include electromagnetic radiation and how the particles interact with one another (i.e., light, X-rays, and gamma rays). It can be difficult to understand and accept the implications of the quantum theory because the behavior of matter and radiation at the atomic level frequently appears peculiar. Its theories frequently contradict intuitions derived from observations of the real world.

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If the disk is released from rest, Angular velocity (ω) of the disk is  [tex]245\frac{rad}{s}[/tex]

In physics, the angular velocity or rotational velocity (ω or Ω) is also known as the angular frequency vector, is the rate at which an object's angular position or orientation changes over time (i.e., the object's rotation speed is a pseudo-vector representation. or spin relative to a point or axis).

The magnitude of the pseudovector represents the angular velocity, i.e. the speed at which the object rotates or rotates, and its direction is perpendicular to the current plane of rotation or angular displacement. Angular velocity direction is conventionally given by the right-hand rule.

Calculation :

Given : M = 2kg, t = 3s, r = 80mm

solution :

[tex]0 + Mgrt = \frac{3}{2} Mr^{2}[/tex]ω

ω = [tex]\frac{2}{3} (\frac{g}{r} ) t[/tex]

ω =         [tex]245\frac{rad}{s}[/tex]

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(a) The ball hits the wall 5.3 meters above the release point.

(b) The horizontal component of its velocity is 17.5 m/s. (c) The vertical component of its velocity is 17.1 m/s.

(d) Yes, it has passed the highest point on its trajectory.

(a) Using the equation for range, we can solve for time:

R = V*t*cosθ =>25*t*cos65 = 12 t = 0.75 s

We can then solve for the height using the equation for vertical displacement:

h = V*t*sinθ - 0.5*g*t^2

h = 25*0.75*sin65 - 0.5*9.8*0.75^2 h

= 5.3 m

(b) We can solve for the horizontal component of the velocity using the equation for range:

R = V*t*cosθ 17.5

    = 25*t*cos65 t

   = 0.7 s V = 17.5 m/s

(c) We can solve for the vertical component of the velocity using the equation for vertical displacement:

h = V*t*sinθ - 0.5*g*t^2 17.1

= 25*0.75*sin65 - 0.5*9.8*0.75^2 V = 17.1 m/s

(d) Yes, the ball has passed the highest point on its trajectory because the ball is traveling downwards when it hits the wall.

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Answer:

The North Atlantic Gyre, the South Atlantic Gyre, the North Pacific Gyre, the South Pacific Gyre, and the Indian Ocean Gyre.

Explanation:

The 5 major gyres are:

1. the North Atlantic Gyre

2. the South Atlantic Gyre

3. the North Pacific Gyre

4. the South Pacific Gyre

5. the Indian Ocean Gyre

Hope this helps!

Velocity is zero, acceleration is non-zero is correct statement.

It is given that a ball is thrown upwards so a ball. So when ball is at maximum height, the condition will be that it's velocity will be zero.

So at maximum height velocity will become zero. No acceleration acting on it, acting on eight will be -G,

then G=-9.8 m/[tex]s^2[/tex]

So this extra acceleration due to gravity will always be same on the ball whether it is moving or it is at maximum height.

When the velocity will be zero only while our city is zero needed and the expiration is not equal to zero.

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The string vibrates in three segments at a frequency of 660 Hz while exerting a force of 166.27 N. The first normal mode of a cello string vibrates at a frequency of 220 Hz.

The frequency of an event is its repetitions per unit of time. As a contrast to spatial frequency, it is also sometimes referred to as temporal frequency, and as a contrast to angular frequency, it is sometimes referred to as ordinary frequency. The hertz unit is used to measure frequency (Hz). f = 220Hz

L = 66cm = 0.6m for the wire's length

Wire mass = 1.8*10-3 kg, m/L = 1.8*10-3/0.66, and kg/m = 2.7*10-3

F = 4*2.7 *10^-3 *(0.6^2)*(220)^2 = 166.2N

The frequency at which n segments appear in a string is known:

fn = nf1

For, n = 3

f3 = 3f1

f3 = 3*220

f3 = 660Hz

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(a) According to the photoelectric effect, the intensity of light corresponds to the density of photons; if you have a more intense beam of light, you have more photons. Since the frequency is higher than the minimum frequency required to overcome the work function of the metal, more photons imply that more electrons will be ejected from the metal. Therefore, the current in the phototube will be higher.

(b) Current is defined as charge per unit of time. Electrons are charged, and we said in part (a) that the current would increase, so the number of electrons emitted from the metal surface will increase as well.

(c) The maximum kinetic energy will not change because the energy of the incident photons is constant at E = hf and the work function (the energy taken away by the metal) is a constant depending on the particular metal.

(d) Momentum and kinetic energy, you will note, are basically the same thing since

                 KE = [tex]mv^{2} \frac{1}{2m} = p^{2} /2m[/tex]

So we get the same answer as in part (c); namely, the maximum momentum will remain the same independent of the intensity.

(e) The definition of the de Broglie wavelength is

                               λ = h/p

so, since the maximum momentum Pₘₐₓ is constant, and h is Planck's constant, the minimum de Broglie wavelength is constant.

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When the string is properly tuned to 196 Hz, the wave speed on the string is 250 m/s then 75 cm long G string stretched when it's first tuned is 1.833 mm.

Simple harmonic motion (SHM) occurs when the restoring force (the force directed toward a stable equilibrium point) is proportional to the displacement from equilibrium.

Repetitive motion through a central equilibrium point, Symmetry of maximum displacement, Period of each cycle is constant, Force causing the motion is directed toward the equilibrium point (minus sign).

At the equilibrium point x = 0 so, a = 0 also. When the stretch is a maximum, a will be a maximum too. The velocity at the end points will be zero, and it is a maximum at the equilibrium point.

As we know,

v = sqrt(T/mu)

250 = sqrt(T/(1.3*10^-3))

So T = 81.25 N

Young's modulus for steel = 200 x 10^9 Pa

Y = (T/A)/(deltal/l) = T*l/(deltal*A)

So delta l = (T*l)/(Y*A) = 81.25*0.75/(200*10^9*pi*(0.23*10^-3)^2)

              = 1.833*10^-3 m

              = 1.833 mm

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a) Energy added = 3.113 × 107 J b)  coefficient of performance 3.70

A) COPhp= QH/Win

Hence QH = (COPhp)Win = 4.70×1.84 = 8.648 kW

Energy added = QH(60×60) = (8.648×103)(3600)

Energy added = 3.113 × 107 J

B)  coefficient of performance = (COP)hp - 1 = 4.70 - 1 = 3.70

Various efficiencies can be used to convert energy between different forms. Transducers are objects that change between these states. Examples of transducers include a battery, which converts chemical energy into electric energy, a dam, which transforms gravitational potential energy into the kinetic energy of moving water (and the turbine blades), and finally into electric energy via an electric generator (from heat to work)

Energy transformation examples include creating electric power from heat energy using a steam turbine or lifting something against gravity while using electrical energy to power a crane motor. When an object is lifted against gravity, mechanical work is done on it and gravitational potential energy is stored inside it. Gravity performs mechanical work on the thing if it falls to the ground.

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The force acting on the coil must also act parallel to the magnetic field if it is being accelerated parallel to the field.

A fundamental requirement that must be satisfied for current to be induced in a coil is that the magnetic field and force (acceleration) directions must be perpendicular to one another. As a result, current is induced in a path that is perpendicular to the directions in which the force acting on the coil and the magnetic field are moving. The coil would conduct this current either in a clockwise or anticlockwise direction. We may recast the change in fux as shown above because B is constant due to the constant magnetic Feld. Since A is a positive number, there will be a.

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I = 1.82 kg/m2 is the flywheel's moment of inertia. The highest amount of energy that can be stored by a flywheel-based energy storage system (a revolving disc) is 3.6 mj.

The torque required to achieve a desired angular acceleration is determined by the rigid body's moment of inertia, also referred to as the mass moment of inertia, angular mass, second moment of mass, or, more precisely, rotational inertia.

Given that, E = 3.6 MJ = 3.6*106J is the maximum energy that can be stored in the flywheel.

Flywheel angular velocity is w = 12000 revs per second, or 12094.39 rads per second.

the flywheel's moment of inertia must be determined. In rotational kinematics, the energy of a flywheel is given by I = 2E/W2.

I = 1.82 kg - m^2

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Generally, a partial pressure of oxygen of 0.45 atm is considered toxic but the duration of the exposure is also important. Option A.

High air pressure pushes our bodies harder and limits how much our tissues can expand. Low atmospheric pressure, on the other hand, causes the tissues of the body to swell more, putting more pressure on nerves and other parts of the body.

During the rainy season, most surface waters are enriched with oxygen because rains saturate them with oxygen. As mentioned earlier, higher partial pressure of oxygen in the alveoli causes the pulmonary arterioles to dilate, thereby increasing blood flow.

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The distance at which the center of gravity of hippo is located from the tail of hippo is equal to 1.58 m.

Center of gravity is referred to the point in any object at which the weight of the object is distributed evenly in all the directions. We need to find the position of Center of Gravity of the Hippo from the tail. We are given that Hippo carries 60% weight on its front feet that is

M(front) = 0.60 W

M(rear) = 0.40 W

Let d be the distance of center of gravity from tail and we write the equation as

0.60(1.8 + 0.5 - d) - 0.4(d - 0.5) = 0

=> 1.08 + 0.3 - 0.60d - 0.4d + 0.2 = 0

=> d = 1.58 m

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Complete Question:

A hippo's body is 4.0 m long with front and rear feet located as in (Figure 1). The hippo carries 60% of its weight on its front feet. How far from its tail is the hippo's center of gravity?

The statement that describes the results of the different weighing scales is as follows: Both accurate and precise (option C).

Accuracy is the exact conformity to truth, or to a rule or model i.e. degree of conformity of a measure to a true or standard value while precision is the ability of a measurement to be reproduced consistently.

Accuracy and precision are two measures of observational error. Accuracy is how close a given set of measurements are to their true value, while precision is how close the measurements are to each other.

According to this question, three different scales were used to weigh a bag of oranges. One scale says the bag weighs 2.1 lb, a second says it weighs 2.2 lb, and a third says it weighs 2.1 lb. The actual weight of the bag of oranges is 2.153 lb.

Based on the above observation, it can be said that the results are both accurate and precise because the measurements are both close to one another and to the true or standard value.

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The angular acceleration of the arm is 68.76 rad/s².

We know the formula for angular acceleration as,

α = (ω - ω₀)/t

It is given that the ball is accelerated from rest, so ω₀ = 0.

We know the formula for velocity as, v = r* ω

ω = v/r

Given that, Velocity v = 8.1 m/s

Time t = 0.38 s

Radius r = 31 cm = 0.31 m

So, α = 8.1/0.31 * 1/0.38 = 26.13 /0.38 = 68.76 rad/s²

Angular acceleration is calculated to be 68.76 rad/s².

The question is incomplete. We should find out the angular acceleration of the arm. The figure is attached in the attachment below.

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Answer: To solve this problem, we can use the principle of conservation of energy. Energy is a property of an object or system that is related to its ability to do work, and can take many different forms. In the case of a skateboarder being launched off a ramp, the energy of the system is made up of two forms: kinetic energy and potential energy.

Kinetic energy is the energy of motion, and is equal to one half of an object's mass times its velocity squared. In this case, the skateboarder has a kinetic energy of 0.5 * 50 kg * (10 m/s)^2 = 2500 J when it is launched off the ramp.

Potential energy is the energy of position, and is equal to an object's mass times the acceleration due to gravity times its height. In this case, the skateboarder has a potential energy of 50 kg * 9.8 m/s^2 * h, where h is the height above the ramp.

Since energy is conserved, the sum of the kinetic and potential energy of the system must be constant. Therefore, at the peak of the skateboarder's motion, his kinetic energy must be 0, and all of the energy of the system must be in the form of potential energy. This means that the maximum height that the skateboarder can reach is equal to the kinetic energy of the system divided by the acceleration due to gravity times the mass.

For a skateboarder with a mass of 50 kg, the maximum height that he can reach is 2500 J / (9.8 m/s^2 * 50 kg) = 5.1 m. For a skateboarder with a mass of 100 kg, the maximum height that he can reach is also 5.1 m. This is because the maximum height that an object can reach is only dependent on its initial kinetic energy, not its mass. However, if the skateboarder is moving at a higher initial velocity, such as 20 m/s, then the maximum height that he can reach will be higher. In this case, the maximum height will be 0.5 * 50 kg * (

Explanation:

The magnitude of the force that maintains circular motion while  acting on the puck is 14.7 N

F=ma

F=1.5 kg×9.8 m/s^2

F=14.7 N

When an object interacts with another object, it feels a push or a pull. Each object that two objects make contact with experiences a force. Once the encounter is over, the force between the two objects is gone. Forces are merely interactions; they do not exist independently. When two objects interact and appear to be in physical contact with one another, contact forces are generated. Several types of contact forces include frictional forces, tensional forces, normal forces, air resistance forces, and applied forces. Even when two interacting objects are far apart from one another, action-at-a-distance forces are still present.

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An air capacitor is made by using two flat plates, each with area a, separated by a distance d, then a metal slab having thickness a (less than d) and the same shape and size as the plates is inserted between them, a capacitor has dielectric material between two plates.

A capacitor is a device that stores electrical energy in an electric field by using the buildup of electric charges on two neighboring surfaces that are electrically insulated from one another. It is a passive electrical component with two terminals. A capacitor's effect is referred to as capacitance. A capacitor is an electrical component designed to increase capacitance, even though there is some capacitance between any two neighboring electrical wires in a circuit. In its early days, the capacitor was referred to as a "condenser," and you may still see it in a few compound names, such "condenser microphone." There are several sorts of practical capacitors that are often used, and they are available in a wide range of physical shapes and constructions. The majority of capacitors include two or more electrical conductors separated by an insulating substance, typically in the form of metallic plates or surfaces. An electrolyte, thin sheet, sintered metal bead, or foil can all function as conductors. The nonconducting dielectric increases the charge capacity of the capacitor.

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The largest vertical force applied to the cord without causing motion is  

P ≤ 16.68 N.

From the free body diagrams shown in the attachment, we can write

∑ Fy = 0; -98.1 + Nab = 0

Nab = 98.1 N

-98.1 - 68.67 + Na = 0

Na = 166.77 N

∑ Fx = 0; P - Fab = 0,  P = Fab = Fa

Fab - Fa = 0

Fab = Fa

1st assumption: Block B slides alone

Fab = μab Nab = 0.3* 98.1 = 29.43 N

Fa = 29.43 is not less than μa Na = 0.1 * 166.7 = 16.68 N

Fa = 29.43 > μa Na = 16.68 N

P = 29.43 N

2nd assumption: Block A and B moves together

Fa = μa Na = 0.1 * 166.7 = 16.68 N

Fab = 16.68 < μab Nab = 29.43 N

P = 16.68 N

Thus, we can conclude that, P ≤ 16.68 N.

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The speed of the rocket is 3.6 * 10⁸ m/s.

The rocket's speed relative to spaceship is

Speed of spaceship = v(s) = 0.05c

Speed  of rocket = v(r) = 0.5c

We have to find the speed of rocket measured by friend in the space if the spaceship is fired away from the rocket.

We need to calculate the rocket's speed relative to Earth

Using formula of relative speed

v = v(s) - v(r) / 1 - {v(r) - v(s) / c²}

Put the value into the formula

v = 0.05 - 0.5 / 1 - { 0.5 - 0.05 / c²}

v = c * 1.2

v = 3.6 * 10⁸ m/s

Therefore, the speed of the rocket is 3.6 * 10⁸ m/s.

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The mass of the robot on mars will be 39.4 Kg. The mass of an object is constant hence, the mass of the robot in earth also be 39.4 Kg. But it weight in earth changes to 386 N.

Gravitational force is the force by which an object attracts other objects into its centre of mass. Earth exerts a gravitational force to every objects on its surface and that's why everything stay on the ground and experience a weight.

The weight of a body in a gravitational field is the product of its mass and acceleration due to gravity g. The g value in mars is 3.8 m/s². The weight of the robot in mars is 150 N

mass of robot = 150 N/3.8 m/s² = 39.4 Kg.

Mass of an object is constant everywhere and the mass of robot in earth be 39.4 Kg.

The g value of earth is 9.8  m/s². Thus, weight of the robot in earth  = 34.9 × 9.8  m/s²  = 386 N.

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What is resistance?

Resistance refers to the quantity that AN object impedes or resists in an electrical current. current refers to the flow of electrons. a better thanks to make a case for resistance is to think about an example of an individual in a very jam-pawncked market troubled to travel from one look to another.

Resistance may be a live of the opposition to current flow in an electrical circuit. Resistance is measured in ohms, symbolized by the Greek letter omega (Ω). Ohms are named once Georg Simon Ohm  a German man of science who studied the connection between voltage, current and resistance.

Equivalent resistance

R= 4 * 12 / 4+12

Req = 3 ohm

From ohm's law

V = IR

V = 2 * 3 = 6V

I4ohm = V/R4

= 6/4 = 1.5 ampere

Hence, final answer is  current through 4ohm is 1.5 ampere

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Tension in the back muscle for this scenario is 3095.4 N and the compressive reaction force is 3048 N, and the ratio is 5.53.

Two forces are acting on the compartment, Gravity acting downward, Tension T in cable acting upward.

Force is an influence which could change the movement of an object. A pressure can reason an object with mass to change its pace (e.g. moving from a kingdom of relaxation), i.e., to boost up. pressure can also be described intuitively as a push or a pull. A pressure has both importance and course, making it a vector quantity. it's far measured within the SI unit of newton (N). it's far a wellknown mechanical quantity. pressure is represented with the aid of the symbol F (previously P).

A) In equilibrium net torque about the hip = 0

   T*sintheta*x - Fgup*L/2 - Fgob*L = 0

   T*sin10*0.33 - 40*9.8*0.5/2 - 16.2*9.8*0.5 = 0

   Tension(T) = 3095.4 N

B) Fv = FRx = T*costheta

   Fv = 3095.4*cos10

     = 3048 N

C) Fv/(wub + wobj) = 3048/((40+16.2)*9.8) = 5.53

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When a white dwarf gains enough mass to surpass the Chandra-Sekhar limit, type 1a supernovae are produced.

The importance of the Chandrasekhar limit in Type-1a supernovae has been recognised in astrophysics. The Chandrasekhar limit is thought to be crossed by a white dwarf, causing a catastrophic collapse, which is assumed to be the cause of these supernovae. It is believed that Type Ia supernovae (SNIa) are produced when a carbon-oxygen white dwarf in a binary system reaches the Chandrasehkar limit, either as a result of accretion from a donor or mergers. One of the two stars must be a white dwarf in order to cause a type Ia supernova.

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The amount of damping force that allow shortest possible time is called​ critical damping of the system.

Critical damping is the threshold between overdamping and underdamping  at which the oscillator returns to the position of equilibrium quickly as possible.

Critical damping is frequently desired because such a system returns to and maintains equilibrium quickly. Furthermore, a constant force applied to a critically damped system moves the system to a new equilibrium position as quickly as possible without overshooting or oscillating around the new position.

Critical damping thus provides the rapid approach to zero amplitude for a damped oscillator.

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