The time that the cannon ball spends in the air is 17.7 seconds.
What time does the cannon ball spend in the air?The cannon ball in flight is a projectile.
Projectiles are objects that follow a parabolic path during their motion.
The time that the cannon ball spends in the air is calculated as follows:
The cannon ball is released with a horizontal velocity, u = 30 m/s
The cannon ball travels a horizontal distance, d = 533 m
When the cannonball was fired, it undergoes two types of motion:
a vertical downward motion at constant acceleration due to gravitya horizontal motion with initial velocity, u = 30 m/s and final velocity, v = 0 m/sThe time spent in the air or time of flight, t, is the same for both the horizontal and vertical motion of the cannonball.
Horizontal distance = velocity * timetime = Horizontal distance / velocityTime = 533 / 30
Times spent in the air = 17.7 seconds.
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1. How did you decide whether a substance was a pure substance or a mixture? An element or a compound? A heterogeneous mixture or homogenous mixture? Describe your thought process!
Following are the differences between substance and mixture
A material is said to be pure if it just contains that substance and cannot be broken down into any other components. It is possible to separate a mixture into two or more pure substances. Pure substances have distinct physical and chemical properties, whereas mixtures have various qualities depending on the pure substance amounts and placement within each mixture.
Pure substances might be molecules made up of two or more different elements, or they can be elements composed solely of one type of atom. Depending on how thoroughly the components are combined, mixtures can either be homogeneous or heterogeneous.
Following are the differences between element and compound
Compounds are chemical unions of two or more elements and can potentially be pure substances, whereas elements are invariably pure things. Real-world substances, such as elements and compounds, are rarely pure because they are frequently tainted during manufacturing, storage, or by their environment. In theory, pure denotes the absence of any discernible imperfections. The majority of the time, it is achievable to purify substances to that standard, albeit it frequently necessitates a lot of work.
Following are the differences between heterogeneous and homogeneous mixtures.
Mixtures can be physically separated since they contain multiple types of atoms and molecules. When a combination is homogenous, the particles are so small that the entire mixture appears to be formed of the same substance. When a mixture is heterogeneous, the qualities of the mixture vary depending on which section of the mixture is being analyzed. Typical homogeneous mixtures include solutions. For instance, a salt-water solution is a homogenous combination since it is possible to separate the water and salt using distillation to create pure water and crystalline salt.
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physics grade 11 experince physics book page 21 step by step explanation
answer:
explanation: I don't know the answer to be honest
Result A 90 kg astronaut, initially at rest, throws a 5 kg oxygen tank at 1 m/s away from himself. What is the new speed and direction of the astronaut?
A 90 kg astronaut, initially at rest, throws a 5 kg oxygen tank at 1 m/s away from himself. The new speed for astronauts is 0.055 meters per second, and they will go in the opposite direction of the thing they are chasing.
This is further explained below.
What is the law of conservation of momentum?Generally, For this, use the law of conservation of momentum
Total final momentum = Total final momentum
P_{a i}+P_{0 i}=P_{a f}+P_{o f}
m_{a v_{a i}}+m_0 v_{o i}=m_{a v_{a f}}+m_0 v_af
0+0=90 v_{a f}+5 *1
90 v_{a f}=-5 a
[tex]v_{a f}=-\frac{5}{90} \mathrm{~m} / \mathrm{sec} \\\\v_{a f}=-0.055 \mathrm{~m} / \mathrm{sec}[/tex]
In conclusion, The new speed of astronauts is 0.055m/second and astronauts will move in the opposite direction of the object.
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a ball is shot from a cannon straight up into the air. when it falls back to earth, a radar gun measures its velocity to be 118 m/sec downwards as it reaches the same place from which it was fired. what was the velocity of the bullet when it left the gun?
The velocity of the bullet when it left the gun is 118 m/s.
We need to know about the uniform motion to solve this problem. The uniform motion is an object's motion under acceleration. It should follow the rule
vt = vo + a . t
vt² = vo² + 2a . s
s = vo . t + 1/2 . a . t²
where vt is final velocity, vo is initial velocity, a is acceleration, t is time and s is displacement.
From the question above, we know that
vt = 118 m/s
g = 9.8 m/s²
Find the time taken to maximum height where the initial velocity is zero
vt = vo + at
118 = 0 + g . t
118 = 9.8.t
t = 12.04 s
Find the velocity of bullet when it left the gun
vt = vo - gt
0 = vo - 9.8 . 12.04
vo = 118 m/s
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IT'S 30 POINTS!!!!!!!
1) What are the five different types of interactions between organisms?
2) What patterns do scientists observe between predator-prey relationships like the wolves and moose on Isle Royale?
3) Use the data from your graph to provide evidence for the effects of of resource availability on individuals and populations in an ecosystem.
4) Do the patterns of interactions between organisms, such as competition and predation, change when they occur in different ecosystems? Explain.
5) Predict the effects on a predator-prey relationship, such as the one between a frog and blue heron, in a wetland ecosystem in the midst of a drought.
Answer:
1. Competition and prediction
Commensalism
Parasitism
Mutualism
Amensalism
2. As the population of wolves has declined the population of the moose increase
3.
an object of mass m is lifted at constant velocity a vertical distance h in time t. the power supplied by the lifting force is (a) mght (b) mgh/t (c) mg/ht (d) mgt/h (e) zero
Option (b) mgh/t will be the power supplied by the lifting force.
What does Newton's first law of motion state?
According to Newton's first law of motion, if a body is at rest or moving in a straight line at a constant speed, it will continue to move at that speed or remain at rest until acted on by a force.
How are formulas of power and force interlinked?
F = mg is the formula for force where,
F = force required
m = mass of the object
g = gravitational constant
and P=Fd/t is the formula for power where,
P= power
F=force
d= distance
and t= time
Substituting the value F=mg, in P=Fd/t we get,
P=mgd/t or P=mgh/t
Hence, we can conclude,
F = mg is the equation that expresses the force required to raise an item at a constant speed. P = Fd/t = mgh/t is then used to calculate the power.
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a worker drags a crate across a factory floor by pulling on a rope tied to the crate. the worker exerts a force of 450 n on the rope, which is inclined at 38° to the horizontal, and the floor exerts a horizontal force of 125 n that opposes the motion.
The magnitude of the acceleration when the crate's mass is 310 kg is 0.74 m/s² and the acceleration when the crate's weight is 310 N is 7.3 m/s².
What is acceleration?
The rate at which an item changes its velocity both in magnitude and direction is known as acceleration, a vector quantity. If an object's velocity is changing, it is accelerating.
Although the full specification of force,
[tex]F_{nett} = ma[/tex] where, m = mass, a = acceleration
This situation involves both x and y axes, only the x-application is needed to find what this particular problem asks for.
We note that acceleration in y axis is 0 so, we can denote acceleration in x axis simply as a. We choose +x to the right and +y up.
Let's calculate the x component of the force working on the crate:
[tex]F_x = F cos38^0[/tex]
putting values from question, we get
Fx = 355 N
and the resistive force have magnitude (f) = 125 N
(a) As per the Newton's second law
Fx - f = ma
355 - 125 = 310 a
(acceleration) a = 0.74 m/s²
(b) In this case, By the equation:
mass = weight/gravitational acceleration
we get mass(m') = 310/9.8 = 31.6 kg
Now, by Newton's second law
Fx - f = m' a
355 - 125 = 31.6 a
(acceleration) a = 7.3 m/s²
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Complete question
A worker drags a crate across a factory floor by pulling on a rope tied to the crate. The worker exerts a force of magnitude 450 N on the rope, which is inclined at an upward angle 38° to the horizontal, and the floor exerts a horizontal force of magnitude 125 N that opposes the motion. Calculate the magnitude of the acceleration of the crate if (a) its mass is 310 kg and (b) its weight is 310 N.
If the velocity of a moving car increases from nine m/s to 25 m/s in the span of five seconds, what is the average acceleration during this time period?
Responses
7.2 m/s²
0.31 m/s²
3.2 m/s²
5 m/s²
the winding cages in mine shafts are used to move workers in and out of the mines. these cages move much faster than any commercial elevators. in one south african mine, speeds of up to km/h are attained. the mine has a depth of m. suppose two cages start their downward journey at the same moment. the first cage quickly attains the maximum speed (an unrealistic situation), then proceeds to descend uniformly at that speed all the way to the bottom. the second cage starts at rest and then increases its speed with a constant acceleration of magnitude m/s2. how long will the trip take for each cage? which cage will reach the bottom of the mine shaft first?
Cage 2 will reach the bottom first. The time taken by cage one is 114.76 seconds and cage 2 is 0.32 seconds.
How to find which cage will reach first?
Given,
Mine depth Y = 2072 m
Cage speed 1 v = 65.0 km/h
Acceleration of Cage 2,
a = 4.00 102 m/s2
Solution:
We shall utilize the international system of measurements (SI) to interchange magnitudes using the unit system, which allows us to do so precisely and without the need for antiquities.
v = 65 km / h (1000m/1Km) (1hr/3600s)
= 18.06 m / s
The relationships between location, velocity, and acceleration can be discovered using kinematics.
Work each cage separately in this practice since there are two of them.
Cage 1
They suggest that it is moving at a constant speed, which we can determine using the laws of uniform motion.
v = d/t
v = d/v
t1 = 2072/18.06
t₁ = 114.76 s
Cage 2
Stop so that your starting velocity is zero.
y = v₀ t + ½ a t²
y = 0 + ½ a t²
[tex]t = \sqrt{2y/a} \\\\t2 = \sqrt{2*2072/4*10^{2} } \\[/tex]
t₂ = 0.32 s
On comparing the time taken by cage 1 and cage 2, we can say that cage 2 will reach the ground first.
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Krusty Krabs Breath Mints Mr. Krabs created a secret ingredient for a breath mint that he thinks will “cure” the bad breath people get from eating crabby patties at the Krusty Krab. He asked 100 customers with a history of bad breath to try his new breath mint. He had fifty customers (Group A) eat a breath mint after they finished eating a crabby patty. The other fifty (Group B) also received a breath mint after they finished the sandwich, however, it was just a regular breath mint and did not have the secret ingredient. Both groups were told that they were getting the breath mint that would cure their bad breath. Two hours after eating the crabby patties, thirty customers in Group A and ten customers in Group B reported having better breath than they normally had after eating crabby patties.
1. Which people are in the control group?
2. What is the independent variable?
3. What is the dependent variable?
4. What should Mr. Krabs’ conclusion be?
5. Why do you think 10 people in group B reported fresher breath?
1) The control group are the people that are in group B
2) The independent variable is the administration of the breath mint
3) The dependent variable is the breath of the participants
4) The conclusion of Mr Krab should be that the breath mint is effective in treating bad breath.
5) 10 people in group B reported fresher breath because they thought that they got the breath mint.
What is an experiment?The term experiment is used to describe the way tat we could be able to spot the relationship between the dependent and the independent variable. Let us note that the independent variable is the variable that we have to manipulate in the course of an experiment while the dependent variable is the variable that would change as we change the independent variable.
We can see that there was a sort of improvement of the breath of the customers which according to the hypothesis of the experiment would be attributable to the new formula of the breath mint.
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a 5.20-kg howler monkey is swinging due east on a vine. it overtakes and grabs onto a 6.20-kg monkey also moving east on a second vine. the first monkey is moving at 10.2 m/s at the instant it grabs the second, which is moving at 7.20 m/s.
The relative velocity of the two monkeys is 8.568m/s.it overtakes and grabs onto a 6.20-kg monkey also moving east on a second vine. the first monkey is moving at 10.2 m/s at the instant it grabs the second.
The relative velocity of an object to another item is its speed in respect to that object. It is a measurement of the relative speed of two moving objects. Because it clarifies how objects move and interact with one another, relative velocity is significant in physics.
Given;
mass of first monkey = 5.2 kg
mass of second monkey = 6.2 kg
speed of first monkey = 10.2 m/s
speed of second monkey = 7.20 m/s
by conservation of momentum
initial momentum = final momentum
5.2 * 10.2 + 6.2 * 7.2 = (5.2 + 6.2) * v
v = 8.568 m/s
their common speed = 8.568 m/s
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How does inertia of a car affect its speed?
Answer:W hen the car suddenly stops due to either braking or crashing, inertia will force the passengers or any other objects to keep moving forward. And since the force of inertia increases with the speed, the motion can varied from a light erk to a more serious crash.
Explanation:
What is the area of a box which weighs 95N exerting a pressure of 43Pa?
The area of the ball that weighs 95 N and exerting a pressure of 43 Pa is 1.51 m².
What is area?Area can be defined as the region bounded by a plane shape.
To calculate the area of the ball, we use the formula below.
Formula:
P = F/A.......... Equation 1Where
P = PressureF = Force/WeightA = AreaMake A the subject of the equation
A = F/P.......... Equation 2Froim the question,
Given:
F = 95 NP = 43 PaSubstitute these values into equation 2
A = 95/63A = 1.51 m²Hence, the area of the ball that weighs 95 N and exerting a pressure of 43 Pa is 1.51 m².
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What is the kinetic energy of a 24 kilogram rock rolling down a hill at a velocity of 2 meters persecond?
The mass of the rock is, m = 24 kg
The velocity of the rock is, v = 2 m/s
The kinetic energy of the rock can be given by the formula
[tex]K\mathrm{}E\mathrm{}=\frac{1}{2}mv^2[/tex]Substituting the values, the kinetic energy will be
[tex]\begin{gathered} K\mathrm{}E.=\frac{1}{2}\times24\times(2)^2 \\ =48\text{ J} \end{gathered}[/tex]Calculate the current in the 3.0 Ω resistor in the figure above when the current in the 9.0 Ω resistor is 2.4A
The current in the 3.0 Ω resistor is mathematically given as
I_X=1.8A
This is further explained below.
What is current?The proportion of individual resistance to the overall resistance is the same as the current flowing through a branch to the current flowing through the whole system.
When the total current in a parallel circuit is already known, a shortcut approach for finding the branch currents in the circuit may be found via the use of a formula called the current divider formula.
In series circuits, the voltage drops across each resistor, but the current stays the same.
This is analogous to what happens in parallel circuits when the current splits between two branches.
The following diagram illustrates how the entire voltage is distributed across each resistor while maintaining the same amount of current throughout. Ohm's law states that V = I*R.
current dividers ruleis used when current is divided in parallel, such as it is in this case so we employ the current dividers rule as follows
Generally, the equation for current dividers rule is mathematically given as
[tex]I_X=\frac{R_T}{R_X+R_T} I_T[/tex]
where,
I_X = current
R_X = resistor
R_T = total resistance
I_T = sum of the current flowing into a network where R _X is connected in parallel with R_T
Therefore
[tex]I_X=\frac{9}{3+9} 2.4[/tex]
I_X=1.8A
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If a metal box weighs 570 pounds on land, and it displaces 320 pounds of water, how much does it weigh underwater
If the metal box displaces water if 320 lbs, its weight in underwater is 250 lbs.
What is Archimedes principle?Archimedes principle states that when an object is totally or partially immersed in a fluid, it experiences un upthrust which is equal to the weight of the fluid displaced.
If the metal box displaces some volume of the water, it implies that the density of the metal box is greater than that of the water.
The weight of the metal box underwater is calculated as follows;
W = weight on land - weight of water displaced
W = 570 lbs - 320 lbs
W = 250 lbs
Thus, we can conclude that the weight of the metal box underwater is 250 lbs.
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As ____ is added to the ice cube from a flame, the thermal ______ will change to ______ energy, which causes the ice molecules to move faster. The faster moving molecules will vibrate against each other.
URGENT!! ILL GIVE
BRAINLIEST! AND 100 POINTS
Match each picture with the correct type of substance.
Answer:
l-element. ll-mixture
lll-compound
Explanation:
element-2 or more substance make a element
mixture-2 or more substant is combined
compound-all the same and compact
How much does the force of gravity change between two objects if their masses remain the same but their distance of separation doubles?
The force of gravity will become one fourth of the original force when the masses of the objects remain the same but their distance of separation doubles.
Force of gravity is an attraction force which holds the object towards the ground surface.
The gravitational force depends directly on the masses of two objects and indirectly on the square of the distance between them.
This means that the gravitational force increases with mass but decreases with increasing distance between objects.Mathematically, [tex]F = \frac{Gm1m2}{r^{2} }[/tex]Let
m₁ and m₂ be the two different masses
r₁ be the initial distance between the the two masses
r₂ be the distance when their separation doubles.
i.e. r₂ = 2r₁
So, according to the formula,
F₁ = [tex]\frac{Gm1m2}{r1^{2} }[/tex]
F₂ = [tex]\frac{Gm1m2}{r2^{2} }[/tex]
since masses are same:
[tex]\frac{F1}{F2} = \frac{r2^{2} }{r1^{2} }[/tex]
[tex]\frac{F1}{F2} = \frac{4r1}{r1}[/tex]
F₁ = 4F₂
F₂ = [tex]\frac{1}{4}[/tex]F₁
The resultant force is one fourth of the original force.
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a driver traveling at 72 km/h sees a chicken dash out onto the road and slams on the brakes. accelerating at -10 m/s2, the car stops just in time 35 m down the road. what was the driver's reaction time
The driver's reaction time during uniform motion is 1 second or 3 second.
We need to know about the uniform motion to solve this problem. The uniform motion is an object's motion under acceleration. It should follow the rule
vt = vo + a . t
vt² = vo² + 2a . s
s = vo . t + 1/2 . a . t²
where vt is final velocity, vo is initial velocity, a is acceleration, t is time and s is displacement.
From the question above, we know that
vo = 72 km/h = 20 m/s
vt = 0 m/s
a = -10 m/s²
sactual = 35 m
Find the instant distance without reacting
vt² = vo² + 2a . s
0² = 20² - 20s
s = 20 m
Find the reaction distance
sreact = sactual - s
sreact = 35 - 20
sreact = 15 m
Find the time reaction
sreact = vo . t + 1/2 . a . t²
15 = 20t - 5t²
t² - 4t +3 = 0
(t - 3)(t - 1) = 0
t = 3 s or t = 1 s
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(c) The man lifts his suitcase.
The increase in gravitational potential energy of the suitcase is 264 J.
The mass of the suitcase is 12 kg.
Calculate the vertical height the suitcase is raised.
(gravitational field strength, g = 10 N/kg)
Use the equation:
change in
gravitational
nslą juoy ritiw qlent of magsib s web Vem UOY
or
potential energy = mass x g x change in vertical height
gwoq ort
enqma bns elsluolso of beay ed nso ezerli word bns exist bluorie atnabuta arit atramenvasen terw ns19
12+10+
boritem emsa edt eau taum zaslo aloriw ariT
atripiew pniau boritem s 10 aqeta gniau bortiem & eau veriferijeriw ablaeb faum aslo od
22slo ertt ni inebuta rose to tugtuo 1ewoq eril etapilzevni etnobute to zaslo A
anoitaeu
(e)
(2)
height raised =
m
(Total for question = 4 marks)
Answer:
sleep well
bukas nalng yan kakapagod ehh
a woodpecker’s brain is specially protected from large accelerations by tendon-like attachments inside the skull. while pecking on a tree, the woodpecker’s head comes to a stop from an initial velocity of 0.600 m/s in a distance of only 2.00 mm. (a) find the acceleration in meters per second squared and in multiples of g, where g
The acceleration in meters per second squared and in multiples of g is
a = 9.18 g.
Acceleration is the rate of change of velocity with respect to time.
"comes to a stop" means
final v = 0 m/s
⇒v=0m/s.
"from an initial velocity of"
u = 0.600 m/s
"in a distance of 2.00 mm"
x = 2.00 × (10)⁻³m
So, we need an equation that involves
a, v, u, and x,
the equation is —
v²=(u)²-2×a×s
0= (0.600)² – 2×a× 2.00 ×(10)⁻³
In solving this, we get a;
a=90 m/s² —> eq. 1
Now, find the acceleration in meters per second squared and in multiples of g.
And, we know that g=9.8 m/s²2. —> eq.2
Divide eq.1 by eq.2
We get,
= 9.18 ⇒ a = 9.18 g.
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at a certain point on a heated metal plate, the greatest rate of temperature increase, 6 degrees celsius per meter, is toward the northeast. if an object at this point moves directly north, at what rate is the temperature increasing?
tempreture
√12 is degrees Celsius per meter.
What is tempreture?
tempreture is the degree of hotness or coldness of any kind of objects.
Sol-
The highest rate of tempreture increase is given as 6degrees as per the question
Imagine this high rate as a diagonal vector pointing in the northeast direction.
This vector has an x component (horizontal, or east) and a y component (vertical, or north).
The highest rate (maximum) is found as the magnitude of these two components.
It is the square root of (x^2)+(y^2).
6= √((x^2)+(y^2))
-> Take the square of both sides to remove the square root on the right side of the equation.
36 = (x^2)+(y^2)
-->The x^2 and y^2 values each must equal 8 in order to get: 12
(x^2) = 12
x = √12
(y^2) = 12
y = √12
If the object moves directly north, it is therefore moving only in the y-direction.
Thus, it is increasing tempreture at a rate of √12 degrees Celsius per meter.
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The graph shows carrying capacity in two different areas for two populations of salmon
which statement below is most likely true about these areas
The statement that is most likely true about these area A is it has more food resources than area B.
In the given graph, it is clear that carrying capacity of area A is larger than that of area B. Larger the carrying capacity, larger will be its quantity of food resources.
Carrying capacity is the maximum population size that a habitat can support as per its available resources such as food, space etc. It can also be called as a species' average population size in a particular habitat.
The given question is incomplete. The complete question is in the link mentioned below.
Therefore, the statement that is most likely true about these area A is it has more food resources than area B.
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What is one way to describe elements?
Elements have atoms and protons which makes them the building blocks of matters.
What are elements?
The nature of elements make them impossible to broken down into simpler kinds of matter.
Elements can be grouped into:
Metals: example of this category of element includes lead, iron, and gold, they form positive ions.Nonmetals: examples include oxygen, nitrogen. These elements doesn't have the properties of metals.In summary, elements have atomic number, structures, densities, and unique properties.
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What is the minimum wave amplitude amin such that the ant will become momentarily weightless at some point as the wave passes underneath it? assume that the mass of the ant is too small to have any effect on the wave propagation.
The minimum amplitude of the wave is equal to [tex]\frac{g \mu}{T_{\mathrm{s}}}\left(\frac{\lambda}{2 \pi}\right)^2[/tex]
What are the many kinds of wave propagation?A type of radio propagation known as a surface wave is known as ground wave propagation. Low and medium frequency versions of these waves travel across the surface of the earth. Mostly, these are employed for transmission between the earth's surface and the ionosphere. The quantity of individual waves makes up these.
The expression for the velocity of the wave is as follows:
[tex]v=\sqrt{\frac{T_s}{\mu}}[/tex]
Here,
Ts is the tension and
μ is the mass per unit length.
The expression for the wave vector is as follows:
[tex]k=\frac{2 \pi}{\lambda}[/tex]
λ is the wavelength of the wave.
The expression for the angular frequency is as follows:
ω = v k
Here, v is the velocity of the wave.
The expression for the minimum amplitude is as follows:
[tex]A=\frac{g}{\omega^2}[/tex]
Here, g is the acceleration due to gravity.
putting the values of v and k in w
[tex]\begin{aligned}&\omega=v k \\&\omega=\left(\sqrt{\frac{T_s}{\mu}}\right)\left(\frac{2 \pi}{\lambda}\right)\end{aligned}[/tex]
[tex]\begin{aligned}A=& \frac{g}{\omega^2} \\A=& \frac{g}{\left(\left(\sqrt{\frac{T_s}{\mu}}\right)\left(\frac{2 \pi}{\lambda}\right)\right)^2} \\&=\frac{g}{\frac{T_s}{\mu}\left(\frac{2 \pi}{\lambda}\right)^2} \\&=\frac{g \mu}{T_s}\left(\frac{\lambda}{2 \pi}\right)^2\end{aligned}[/tex]
The minimum amplitude of the wave is equal to [tex]\frac{g \mu}{T_{\mathrm{s}}}\left(\frac{\lambda}{2 \pi}\right)^2[/tex]
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The average kinetic energy of an object is its _____.
A.temperature
B.potential energy
C.kinetic energy
D.thermal energy
Answer:
Answer is a
Explanation:
a baseball player hits a baseball into the air with an initial vertical velocity of 65 feet per second. the player hits the ball from a height of 3 feet. after how many seconds will the ball hit the ground?
Answer:
Time to reach zero speed t1 = 65 ft/sec / 32 ft/sec^2 = 2.03 sec
H = 65 * 2.03 - 32/2 ^ 2.03^2 = 66 ft above launch point
h = distance ball falls = 66 + 3 = 69 ft
h = 1/2 g t2^2 time to fall 69 ft
t = (2 * 69 / 32)^1/2 = 2.08 sec
Total time = t1 + t2 = 2.03 + 2.08 = 4.11 sec
an eclipsing binary has been analyzed and it has been determined that the ratio of the mass of star a to the mass of star b is 6 and the total mass of the two stars is 26 solar masses. what are the masses of star a and star b?
If the ratio of the mass of star A to the mass of star B is 6 then, mass of star A is 22.3 solar masses and the mass of star B is 3.7 solar masses.
What is star?
The brilliant plasma spheroid that constitutes an astronomical object known as a star is held together by gravity. The star that is closest to Earth is the Sun. Even while other stars are also visible at night with the unaided eye, they appear as stationary points of light due to their immense distances from Earth.
A:B = 6:1
We can write it as
A/B = 6
A=6B
and we also given in the question as:
A+B = 26
putting the above value of A
6B+B = 26
B = 26/7
B = 3.7 solar masses
Subtracting it from total mass:
A = 26-B = 26-3.7
A = 22.3 solar masses
Therefore, mass of star A is 22.3 solar masses and mass of star B is 3.7 solar masses.
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solve problem 9-33 (page 388) in hibbeler 8th edition. determine the slope and displacement at point b. ei is constant. use the method of virtual work. 15
The slope and displacement at point b. ei is constant. By using the method of virtual work we get Triangle B=6637.5 / EI.
The study of forces and movement in a mechanical system results in virtual work when the concept of least action is applied. A force's work on a particle as it moves along a displacement varies depending on the displacement. One will minimise the action among all virtual displacements, or potential displacements, that a particle might take. As a result, the particle follows this displacement in accordance with the principle of least action. The term "virtual work" refers to the labour performed by a force on a particle along a fictitious displacement.
virtual work and the associated calculus of variations were initially created to examine systems of rigid bodies, but they were later developed for the study of mechanics.
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