(a) Calculate the tension in a vertical strand of spiderweb if a spider of mass 5.00 ✕ 10-5 kg hangs motionless on it.
N
(b) Calculate the tension in a horizontal strand of spiderweb if the same spider sits motionless in the middle of it much like the tightrope walker in Figure 4.13. The strand sags at an angle of 10.0° below the horizontal.
N
Compare this with the tension in the vertical strand (find their ratio).
(tension in horizontal strand / tension in vertical strand)

(a) Calculate The Tension In A Vertical Strand Of Spiderweb If A Spider Of Mass 5.00 10-5 Kg Hangs Motionless

Answers

Answer 1

a)The tension in the vertical strand will be 0.00049 N.

b))The tension in the horizontal strand will be 0.001284 N.

c)The ratio of tension in the horizontal strand to the tension in the vertical strand will be  2.62.

What is tension force?

The tension force is described as the force transferred through a rope, string, or wire as it is pulled by opposing forces.

Given data;

Mass of spiderweb = 5.00 ✕ 10⁻⁵ kg

The tension in a horizontal strand of a spiderweb, Tₓ

The tension in a  vertical strand of a spiderweb, Tₐ

The angle at which the strand sags, Θ = 10.0°

R is the ratio of  tension in the horizontal strand to the tension in the vertical strand

a)

From the FBD,

The tension  in the vertical strand is equal to the weight of the spider;

Tₐ = W

Tₐ = mg

Tₐ= 5 x 10⁻⁵ kg x 9.8 m / s²

Tₐ= 0.00049 N.

(b)

The super's total vertical forces are zero since it is not moving the value of the tension in the horizontal strand;

Tₓ = mg/( 2sinΘ)

Tₓ = 5 x 10⁻⁵ kg x 9.8 m /s² / ( 2 sin 11° )

Tₓ= 0.001284 N.

c)

R is the tension in the vertical strand divided by the tension in the horizontal strand.

R= Tₐ / Tₓ

R= 0.001284 N / 0.00049 N

R= 2.62

Hence, the tension in a vertical strand of a spiderweb, the tension in a horizontal strand of a spiderweb, and the ratio of tension in the horizontal strand to the tension in the vertical strand will be 0.00049 N, 0.001284 N, and 2.62 respectively.

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Related Questions

A 25 newton force applied on an object moves it 50 meters. The angle between the force and displacement is 40.0°. What is the value of work being done on the object?

Answers

Answer:

The value of work being done on the object is 958J.

Explanation:

Work done is equal to force multiply by distance, but when the angle is between the force and distance work done=Force (cos theta) × distance

Work done = Force(cos theta) × distance

Work done = 25N(cos 40.0°) × 50m

Work done = 25N(0.7660) × 50m

Work done = 19.15N × 50m

Work done = 957.5J = 958J

Therefore the value of work being done on the object is 958J.

The minimum takeoff speed for a certain airplane is 50 m/s. What minimum acceleration is required if the plane must leave a runway of length 2000 m? assume the plane starts from rest at one end of the runway.

Answers

Assuming constant acceleration, the requisite magnitude is [tex]a[/tex] such that

[tex]\left(50\dfrac{\rm m}{\rm s}\right)^2 - 0^2 = 2a (2000\,\mathrm m)[/tex]

Solve for [tex]a[/tex] :

[tex]a = \dfrac{\left(50\frac{\rm m}{\rm s}\right)^2}{4000\,\mathrm m} = \boxed{0.625 \dfrac{\rm m}{\mathrm s^2}}[/tex]

find the x-component of this vector.

Answers

The x-component for the vector given in the image is : [tex]B_{x}[/tex] = 18.3m

Meaning of a Vector

A Vector can be defined as a quantity that possesses both magnitude and direction thereby giving more details.

A vector is very important when it comes to dealing with forces.

Analysis

[tex]B_{x}[/tex] = B cos(Θ)

Θ = 180° - 170° = 10°

[tex]B_{x}[/tex] = B cos(10°) = 18.3m

In conclusion, The x-component for this vector is : [tex]B_{x}[/tex] = 18.3m

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9. What's the process that a spark represents?
A. A body with a strong positive charge is placed near a body with a neutral charge and the electrons jump between the two bodies
B. A body with a strong positive charge is placed near a body with a strong negative charge and the electrons jump between the two
C. A body with a neutral charge is placed near a body with a strong negative charge and the electrons jump between the two bodies
D. A body with a strong positive charge is placed near a body with a strong positive charge and the electrons jump hatupon the. The answer

Answers

Answer:

Sparks often indicate the presence of a high voltage, or "potential field". The higher the voltage; the farther a spark can jump across a gap, and with enough energy supplied can lead to greater discharges such as a glow or an arc.

Explanation:

importance of states of matter​

Answers

Answer:

STATES OF MATTER The three important states of the matter are (i) Solid state (ii) Liquid state (iii) Gaseous state, which can exist together at a particular temperature and pressure e.g. water has three states in equilibrium at 4.58 mm and 0.0098ºC.

Explanation:

Two blocks are connected by a massless rope over a massless, frictionless pulley, as shown in the figure. The mass of block 2 is 2=11.3 kg , and the coefficient of kinetic friction between block 2 and the incline is =0.200 . The angle of the incline is 31.5° . If block 2 is moving up the incline at constant speed, what is the mass 1 of block 1?

Answers

The mass of block 1 is 1.30176 kg.

What is tension in physics?

A tension force in physics is a force developed in a rope, string, or cable when stretched under an applied force.

Tension is acted along the length of the rope/cable in a direction that is opposite to the force applied on it.

According to the question,

Mass of block 2= 11.3 kg

Kinetic friction μ=0.200

The component of the weight in the direction of the incline

W = m₂gsinθ

T = [tex]F_{f} - W[/tex]........(1)

When the force of friction

[tex]F_{f}[/tex] = μ[tex]_k[/tex]N

[tex]F_{f}[/tex] = μ[tex]_k[/tex](m₂gcosθ)

Here , Put the value in equation 1

T = m₂gcos 31.5° - μ[tex]_k[/tex]m₂gcos 31.5°

We know that ,

T - m₁g = 0

T = m₁g

So,

m₁g = m₂g (Sin 31.5° - 0.200 x cos 31.5°)

m₁ = 11.3 x (0.0840 - 0.2 x 0.996)

m₁ = 11.3 x (0.1152)

m₁ = 1.30176 kg

Hence, the mass of block 1 is 1.30176 kg.

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calculate the pressure of water in a well if the depth of the water is 10m​

Answers

Answer:

P= phg

so:- the height is 10m

density of water 1000 kg/m3

gravity is 9.8m/s2

P=1000 kg/m3*10m*9.8m/s2

=98000Pa

=98KPa

Melanie gets out of her car at the park. She walks 25 m to the trail entrance.
She jogs around the trail until she reaches a pond, where she stops briefly.
She then continues to follow the trail around the pond. Which reference point
should be used to describe her motion?
A. Her car
B. The trail entrance
C. The pond
D. The trail

Answers

The reference point that should be used to describe Melanie motion is the pond (option C).

What is reference point?

Reference point is a particular point in space which is used as an endpoint to measure a distance from or chart a map from.

According to this question, Melanie gets out of her car at the park and walks 25 m to the trail entrance. She jogs around the trail until she reaches a pond, where she stops briefly.

However, she then continues to follow the trail around the pond. This suggests that the pond should serve as the reference point for Melanie's motion.

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Refer to Chapter 10 in the textbook which discusses externalities. Specifically, reference section 10-2, which details public policies towards externalities.

Additionally, find an article using your subscription to the Wall Street Journal detailing one proposed solution to pollution.

In your post, summarize the selected article and discuss the following:

Explain which of the public policies detailed in section 10-2 of the textbook best describes the proposed solution in the selected article.
Which of the public policy approaches outlined in section 10-2 would work best to resolve this pollution problem and why?
You are required provide a link to the article and support your answer with relevant ideas, facts, and examples.

Answers

An externality, sometimes called a spillover, occurs when an exchange between a buyer and seller has an impact on a third party who is not part of the exchange. Externalities can be positive or negative

What are Externalities?

Externalities refers to situations when the effect of production or consumption of goods and services imposes costs or benefits on others which are not reflected in the prices charged for the goods and services being provided.

Externalities Private markets offer an efficient way to put buyers and sellers together and determine what goods are produced, how they are produced, and who gets them. The principle that voluntary exchange benefits both buyers and sellers is a fundamental building block of the economic way of thinking. But what happens when a voluntary exchange affects a third party who is neither the buyer nor the seller?

Externalities can be negative or positive. If you hate country music, then having it waft into your house every night would be a negative externality. If you love country music, then what amounts to a series of free concerts would be a positive externality.

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Dean is skateboarding. He starts at a speed of 0.5 m/s and speeds up to 4.0 m/s
to go off a ramp over a time of 5.0 seconds. What is Dean's acceleration?

Answers

Answer:

[tex]\huge\boxed{\sf a = 0.7 \ m/s^2}[/tex]

Explanation:

Given Data:

Initial velocity = [tex]V_i[/tex] = 0.5 m/s

Final velocity = [tex]V_f[/tex] = 4 m/s

Time = t = 5 s

Required:

Acceleration = a = ?

Formula:

[tex]\displaystyle a =\frac{V_f-V_i}{t}[/tex]

Solution:

Put the givens in the formula.

[tex]\displaystyle a=\frac{4-0.5}{5} \\\\a = \frac{3.5}{5} \\\\a = 0.7 \ m/s^2\\\\\rule[225]{225}{2}[/tex]  

A yoyo with a mass of m = 150 g is released from rest as shown in the figure.

The inner radius of the yoyo is r = 2.14 cm, and the outer radius is R = 4.00 cm, and the moment of inertia about the axis perpendicular to the plane of the yoyo and passing through the center of mass is I[tex]_{cm}[/tex] = 1.01×10-4 kgm2.

1. Determine the linear acceleration of the yoyo.

2. Determine the angular acceleration of the yoyo.

3. What is the weight of the yoyo? (Hint: It's not 150 g)

4. What is the tension in the rope?

5. If a 1.27 m long section of the rope unwinds from the yoyo, then what will be the angular speed of the yoyo?

Answers

(1) The linear acceleration of the yoyo is 3.21 m/s².

(2) The angular acceleration of the yoyo is 80.25 rad/s²

(3) The  weight of the yoyo is 1.47 N

(4) The tension in the rope is 1.47 N.

(5) The angular speed of the yoyo is 71.385 rad/s.

Linear acceleration of the yoyo

The linear acceleration of the yoyo is calculated by applying the principle of conservation of angular momentum.

∑τ = Iα

rT - Rf = Iα

where;

I is moment of inertiaα is angular accelerationT is tension in the roper is inner radiusR is outer radiusf is frictional force

rT - Rf = Iα  ----- (1)

T - f = Ma  -------- (2)

a = Rα

where;

a is the linear acceleration of the yoyo

Torque equation for frictional force;

[tex]f = (\frac{r}{R} T) - (\frac{I}{R^2} )a[/tex]

solve (1) and (2)

[tex]a = \frac{TR(R - r)}{I + MR^2}[/tex]

since the yoyo is pulled in vertical direction, T = mg [tex]a = \frac{mgR(R - r)}{I + MR^2} \\\\a = \frac{(0.15\times 9.8 \times 0.04)(0.04 - 0.0214)}{1.01 \times 10^{-4} \ + \ (0.15 \times 0.04^2)} \\\\a = 3.21 \ m/s^2[/tex]

Angular acceleration of the yoyo

α = a/R

α = 3.21/0.04

α = 80.25 rad/s²

Weight of the yoyo

W = mg

W = 0.15 x 9.8 = 1.47 N

Tension in the rope

T = mg = 1.47 N

Angular speed of the yoyo

v² = u² + 2as

v² = 0 + 2(3.21)(1.27)

v² = 8.1534

v = √8.1534

v = 2.855 m/s

ω = v/R

ω = 2.855/0.04

ω = 71.385 rad/s

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What is it called when data are arranged in rows and columns?
O A. Interpolation
O B. Correlation
O C. Table
OD. Bar graph

Answers

Answer:

C. Table

What is a Database table?

A organized collection of records is called a database table. The main key that uniquely identifies each row in the table. Since no two rows may have the same instantaneous value thanks to a unique key, it is simple to choose a row by its main key. A table can also contain several columns, each of which can hold a distinct kind of data. The information stored is verified using the column name and data type.  

The table name is the linguistic component of a database table. It can represent expressions or variable items, and it must be typed exactly. Square brackets denote a need for the item, whereas curly braces denote an optional element. An alternate choice is indicated by a vertical bar. A main key is a single field, and a secondary key might be a combination of many fields. This kind of information is crucial.

Any field in the data table can be referenced by the secondary key. A database's data field may be a string, a number, a date, or a time. A table's first field should always be the main key, followed by any foreign keys. Actual data should never be present in a primary key. Since the immediate key value is derived from external sources, it is crucial to use it properly. Otherwise, data input mistakes may occur.

The information kept in the database table is referred to as a secondary key. This kind is a primary key, which implies it is a secondary key. A primary key can be used as an alternate key to distinguish between different records in a table and to uniquely identify a record inside a database. Multiple fields that can be either main or alternative make up a composite key.

Depending on the type of data being stored and its intended use, a database table may have a single row or several. The main key determines the number of rows, which might be 50 or more. A secondary key can be used to establish connections between various tables and to distinguish between various data types in a database. A data table also includes a secondary key, which is essential for data retrieval and is separate from the primary key.

You can have local or global database tables. The two types of tables differ in terms of names, availability, and visibility. A global table is accessible to all users and may be utilized by any other user, while a local table is only visible to the present user. It is distinct from a typical table and requires more effort to build than a straightforward one does. Its main function is to maintain a database and store data.

Rows in a database table can be of any size. A table's rows can include any number of columns. A database table's rows can be arranged in any way. The number of rows on a data page might range from one to thousands. Each row may consist of a clustered index, a row, or both. A list of columns may also be present in a row. A clustered index can only contain information in a particular sequence.

A table can be set up in  two different ways. The information-containing row of data is its main key. The data column that contains the values for a row is known as a secondary key. A database that employs rows is the third form of table. Multiple primary keys are possible for a data row, and a secondary key is a secondary key that refers to a row column. A database will have a foreign key if it is formed with a single primary key.

There is no limit to the amount of rows and columns in a database table. Up to 1,024 rows are allowed in a typical user-defined table. The server's storage capacity determines how many rows can fit in a database table. A table can have characteristics added to it in addition to the column and row. A restriction can stop a row from having empty fields. The connection between two tables can be established via an important control.

Table
a bar graph is when data is arranged in bars, interpolation is data in the form of diagonal lines like on a x and y graph, and correlation is data in the form of dots in somewhat the shape of a interpolation

Which of the following describes a velocity vs. time graph that looks like this?

HURRY PLEASE

Answers

Explanation:

the velocity has decreasing velocity. this is my answer

Q1) Write True or False for each statement:

Equal volumes of the two different substances have equal masses.

Answers

Answer:

True

Explanation:

it is true because blabla bla

in order for work to be done wht must happen?
Answer asap please due soon

Answers

An object must move in the same direction as the force is applied for work to be accomplished. Option C is correct.

What is work done?

Work done is defined as the product of applied force and the distance through which the body is displaced on which the force is applied.

Work may be zero, positive and negative. it depends on the direction of the body displaced. if the body is displaced in the same direction of the force it will be positive.

The work done is found as;

W= F × d

Where.

F is the force

d is the displacement

W is the work done

In order for work to be done, an object must move in the same direction, and the force is applied

Hence option C is correct.

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In each case below, a charged rod, made of the dense rubber ebonite, comes close or is in contact with the top of an electroscope. The ball on top of the electroscope is directly connected to the two metal leaves suspended in the flask.

Which image represents a gaining of a charge on the leaves of the electroscope by conduction?

Answers

Answer:

(B)  (the leaves will separate when subjected to a net charge)

The image that represents a gaining of a charge on the leaves of the electroscope by conduction is image B.

What is electroscope?

An electroscope is a device that detects the presence of an electric charge or ionizing radiation by suspending a pair of thin gold leaves from an electrical conductor that leads to the outside of an insulating container.

When an electrical charge is brought close to or in contact with a conductor, the leaves in an electroscope spread apart.

This occurs because the same charge, whether positive or negative, is received by the leaves, causing their repulsion (spreading apart).

A negatively charged rod is brought in close proximity to an uncharged electroscope. As a result, the electroscope leaves become further apart.

Thus, image B is representing the given scenario.

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How do the Sun, Earth, and Moon systems interact

Answers

The sun is the mother star of the solar system, which only emits light to half of the planet, while the other part is always dark.

The sun emits light towards the earth, which dominates all life on earth. The movements of the Moon around the Earth and of the Earth around the Sun are complex. Movements of rotation around their own axes are superimposed on movements of orbital translation. The Earth and the Moon rotate around their own axes: This is rotation.

A record of travel along a straight path is as follows:
1. Start from rest with constant acceleration of 2.10 m/s2 for 14.0 s.
2. Maintain a constant velocity for the next 1.90 min.
3. Apply a constant negative acceleration of −9.06 m/s2 for 3.25 s.
m/s
a) What was the total displacement for the trip?
b) What were the average speeds for legs 1, 2, and 3 of the trip, as well as for the complete trip?

Answers

The total displacement for the trip is 5510 m


Calculation and Parameters

During part 1, the distance travelled is

(1/2) a t^2

= (1/2)(2.77)(225)

= 311.6 m

The final speed gotten is (2.77)(15)

= 41.55 m/s.

The average speed for that interval is half of that or 20.8 m/s

During part 2, the distance traveled is

41.55 m/s*2.05 min*60 sec/min

= 5110 m/s

During part 3, the speed drops from 41.55 m/s to

41.55 - (9.47)(4.39)

= 0

The average speed during this interval is

41.55/2 - 20.78 m/s

The distance travelled is 20.78*4.39

= 91.2 m/s

Total distance travelled = 312 + 5110 + 91 = 5513 m

The average speeds for legs 1,2,and 3 of the trip as well as for the complete trip are:

20.8 m/s, 41.6 m/s, 20.8 m/s, 38.7 m/s

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The form of energy that can move from place to place across the universe is

Answers

Answer:kinetic energy

Explanation:

Answer: kinetic energy

A rod of length 58.0 cm and mass 1.10 kg is suspended by two strings which are 35.0 cm long, one at each end of the rod.
The string on side B is cut. Find the magnitude of the initial acceleration of end B.
The string on side B is retied and now has only half the length of the string on side A.
Find the magnitude of the initial acceleration of the end B when the string is cut.

Answers

a) mg[tex]\frac{1}{2}[/tex] = [tex]ml^\frac{2}{3}[/tex] * ω

b)ω = [tex]\frac{3g}{2l}[/tex]

c)14.7  the magnitude of the initial acceleration of the end B when the string is cut.

What is Acceleration?

Acceleration is the rate of change of the velocity of an object with respect to time.

Given

A rod of length 56.0 cm and mass 1.40 kg is suspended by two strings which are 42.0 cm long, one at each end of the rod.

When the string is cut rod rotates about other end.

Let's take momentum equation about that end:

mg*[tex]\frac{1}{2}[/tex] = Iω [I = [tex]ml^\frac{2}{3}[/tex]]

a) mg[tex]\frac{1}{2}[/tex] = [tex]ml^\frac{2}{3}[/tex] * ω

Angular acceleration:

b)ω = [tex]\frac{3g}{2l}[/tex]

c)Acceleration of end B:

a = lω= [tex]\frac{3g}{2}[/tex] =[tex]\frac{3*9.8}{2}[/tex]

a = 14.7 [g=9.8]

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A ball of mass m is dropped. What is the formula for the impulse exerted on the ball from the instant it is dropped to an arbitrary time τ later? Ignore air resistance.

Answers

The formula for the impulse exerted on the ball at any given instant is the change in the momentum of the ball.

Impulse exerted on the ball

The impulse exerted on the ball at any given instant is calculated as follows;

J = ΔP

J = Pf - Pi

where;

J is impulse exerted on the ballpf is final momentumpi is the initial momentum

Thus, the formula for the impulse exerted on the ball at any given instant is the change in the momentum of the ball.

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A particle with mass 3×10−2 kg
k
g
and charge +3 μC
μ
C
enters a region of space where there is a magnetic field of 1 T
T
that is perpendicular to the velocity of the particle. When the particle encounters the magnetic field, it experiences an acceleration of 12 m/s2
m
/
s
2
. What is the speed of the particle when it enters the magnetic-field region?

Answers

The speed of the particle when it enters the magnetic-field region is 120,000 m/s.

Speed of the particle

Magnetic force on the particle is given as;

F = qvB

where;

q is magnitude of the chargev is speed of the particleB is magnetic field strength

From Newton's second law, force on an object is given as;

F = ma

where;

m is mass of the particlea is acceleration

ma = qvB

v = ma/qB

v = (3 x 10⁻² x 12)/(3 x 10⁻⁶ x 1)

v = 120,000 m/s

Thus, the speed of the particle when it enters the magnetic-field region is 120,000 m/s.

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perpetual motion machines have fascinated people especially inventors for hundreds of years before the laws of thermodynamics became known. Ideally once energy is added to start a perpetual motion machine in motion, the machine would continue to operate indefinitely. Using a law of thermodynamics, explain why such a machine cannot be produced

HELP HELP HELP

Answers

Given the fact that energy conversion is not entirely efficient, it is impossible to produce a perpetual motion machine.

What is a perpetual motion machine?

The perpetual motion machine in one that is able to work continuously without stopping. This would mean that the efficiency of this machine must that the machine is 100% efficient which violates the second law of thermodynamics.

Thus, given the fact that energy conversion is not entirely efficient and energy looses cause machines not function effectively, it is impossible to produce a perpetual motion machine.

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Two rocks of identical mass sit high above the river. One rock is 10 meters above the river, and the other is 20 meters above the river. Which rock has the greatest potential energy?

Answers

Answer:

Gravitational potential energy is greater for the rock [tex]20\; {\rm m}[/tex] above the river.

Explanation:

The gravitational field near the surface of the earth is approximately uniform. Let [tex]g[/tex] denote the strength of the gravitational field near the surface of the earth.

Let [tex]m[/tex] denote the mass of each rock. Assume that the gravitational potential energy of the two rocks is [tex]0[/tex] when the rocks are at the surface of the river.

When the rock is at a height of [tex]h[/tex] above the river, the gravitational potential energy ([tex]\text{GPE}[/tex]) of that rock would be [tex]\text{GPE} = m\, g\, h[/tex]. In other words, the [tex]\text{GPE}\![/tex] of the rock is proportional to its height relative to the ground.

Hence, among the two rocks, [tex]\text{GPE}[/tex] would be greater for the rock that is higher above the ground ([tex]20\; {\rm m}[/tex]) than the rock [tex]10\; {\rm m}[/tex] above the ground.

physical properties of matter help describe a substance which of the following is not a physical property of a soil sample?
A. the container in which the soul is held
B. the color of the soil
C. the volume of the soil
D. the texture of the soil
Answer asap this is an exam il give brainlist

Answers

A the container the soil is held in is not a feature of the soil itself

Which prathogen is often controlled by beneficial bacteria

Answers

Intestinal flora aid in digestion. Some bacteria can be used for drug synthesis; for instance Humulin is synthesized by escherichia coli.

Answer:

antibiotics

Explanation:

im not sure if this is right hope this helps lol

A ball is thrown directly downward with an initial speed of 8.75 m/s, from a height of 29.4 m. After what time interval does it strike the ground?

Answers

After time 1.74 seconds ball will strike the ground.

A ball is thrown directly downward and information we have-

Initial velocity of ball (u) = 8.75m/s

distance/height (s) = 29.4m

Ball is thrown downward means there are gravitation force also worked and the acceleration of ball is-

acceleration (a) = g = 9.8 m/s²

When ball strike the ground then it's velocity should be 0 means-

Final velocity of ball (v) = 0 m/s²

For getting time period we can use 2nd equation of motion as-

s = ut + (1/2)at²

Now, 29.4 = (8.75 × t) + (1/2× 9.8 × t²)

29.4 = 8.75t + 4.9t²

Now we have a quadratic equation as -

4.9t² + 8.75t - 29.4 = 0

After solving it we get two values of t -

time = 1.74 and time = -3.5

But time can not be negative so we will reject the negative values.

so t = 1.74 seconds

So to conclude that after applying the second equation of motion the time taken by the ball to reach ground is 1.74 seconds.

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A rectangle has a length of (2.5 ± 0.2) m and a width of (1.5 ± 0.2) m. Calculate the area and the perimeter of the rectangle, and give the uncertainty in each value.

(a)Calculate the area and give its uncertainty. (Enter your answers in m2.)

(b)Calculate the perimeter of the rectangle and give its uncertainty. (Enter your answers in m.)

Answers

You can just add the uncertainties

The area of the rectangle obtained is (3.75 ± 0.03) m².  The perimeter of the rectangle obtained is (8 ± 0.64) m.

Given dimensions:

Length (L) = (2.5 ± 0.2) m

Width (W) = (1.5 ± 0.2) m

(a) Area of the rectangle (A) is given by:

A = L × W

A = (2.5 ) × (1.5 )

A = 3.75 m²

The relative uncertainty in area = ΔA / A

ΔA = (ΔL / L) × A + (ΔW / W) × A

ΔA = (0.2 / 2.5) × 3.75 + (0.2 / 1.5) × 3.75

ΔA = 0.03 m²

Therefore, the area of the rectangle is (3.75 ± 0.03) m².

(b) Perimeter of the rectangle (P) is given by:

P = 2 × (L + W)

P = 2 × (2.5 + 1.5)

P = 2 × 4

P = 8 m

Relative uncertainty in perimeter = ΔP / P

ΔP = (ΔL / L) × P + (ΔW / W) × P

ΔP = (0.2 / 2.5) × 8+ (0.2 / 1.5) × 8

ΔP = 0.64 m

Therefore, the perimeter of the rectangle is (8 ± 0.64) m.

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A person of mass 100kg runs up a staircase with a vertical height of 10m. If the trips takes 5 seconds to complete, calculate the person's power ( acceleration due to gravity =10m/s²)

Answers

Answer:

Power = 2000J/s

Explanation:

Power= Total Work done/Time

Given

mass = 100kg

distance(height) = 10m

time = 5s

acceleration due to gravity = 10m/

Work done = force × distance

Finding Force

Force = mass × acceleration due to gravity

Force = 100kg × 10m/

Force = 1,000N

Finding work done

Work done = Force × distance

Work done = 1,000N × 10m

Work done = 10,000J

Finding Power

Power = work done/time

Power = 10,000J/5s

Power = 2,000J/s

Therefore Power is 2,000J/s

What buoyant force is exerted on a 6,000-mL toy balloon by the air surrounding the balloon? The density of air is 0.0009 g/mL

Answers

The buoyant force exerted on a 6,000-mL toy balloon by the air surrounding the balloon is 52.97N.

How to calculate buoyant force?

The buoyancy needed for an object can be calculated using the formula;

B = ρ × V × g

where;

ρ and V are the object's density and volume respectivelyg is the acceleration due to gravity (9.81m/s²)

B = 6000 × 0.0009 × 9.81

B = 52.97N

Therefore, the buoyant force exerted on a 6,000-mL toy balloon by the air surrounding the balloon is 52.97N.

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