The butcher should balance both the meat and 0.5 kg mass on one arm of the beam balance and 2 kg mass on the other arm of the beam balance.
What is a beam balance?A beam balance can be defined as an apparatus which comprises a lever with two (2) equal arms and a bowl (pan) that is suspended from each arm, so as to measure the mass of an object.
In this scenario, the butcher should balance both the meat and 0.5 kg mass on one arm of the beam balance and 2 kg mass on the other arm of the beam balance.
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Which of the following describes a velocity vs. time graph that looks like this?
HURRY PLEASE
Explanation:
the velocity has decreasing velocity. this is my answerWhich prathogen is often controlled by beneficial bacteria
Answer:
antibiotics
Explanation:
im not sure if this is right hope this helps lol
You are raising up a big bucket of water from a 25.9 m deep well. The combined mass of the water and the bucket is 13.9 kg. The bucket is attached to a heavy duty steel chain. The mass of the chain is 19.3 kg.
How much work do you perform during the lifting process?
8427 J is Incorrect.
If it takes 1.75 minutes for you to raise the bucket of water out of the well, then what was your average power?
80.25 W is Incorrect.
The total work done is 5980 Joules and the power expended is 57 Watts.
What is work done?
The work done is the work done in the gravitational field as the bucket is raised up Thus work required to remove the bucket Wb;
Wb = 13.9 kg * 25.9 m * 9.8 m/s^2 = 3530 Joules
Height of the center of mass of chain = 25.9 / 2 = 12.95 m
Work done by the chain Wc;
Wc = 12.95 * 19.3 * 9.8 = 2450 Joules
Total work = 3530 + 2450 = 5980 Joules
Power expended = W / t = 5980 J / 105 sec = 57 J/s = 57 Watts
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importance of states of matter
Answer:
STATES OF MATTER The three important states of the matter are (i) Solid state (ii) Liquid state (iii) Gaseous state, which can exist together at a particular temperature and pressure e.g. water has three states in equilibrium at 4.58 mm and 0.0098ºC.
Explanation:
A ball is thrown directly downward with an initial speed of 8.75 m/s, from a height of 29.4 m. After what time interval does it strike the ground?
After time 1.74 seconds ball will strike the ground.
A ball is thrown directly downward and information we have-
Initial velocity of ball (u) = 8.75m/s
distance/height (s) = 29.4m
Ball is thrown downward means there are gravitation force also worked and the acceleration of ball is-
acceleration (a) = g = 9.8 m/s²
When ball strike the ground then it's velocity should be 0 means-
Final velocity of ball (v) = 0 m/s²
For getting time period we can use 2nd equation of motion as-
s = ut + (1/2)at²
Now, 29.4 = (8.75 × t) + (1/2× 9.8 × t²)
29.4 = 8.75t + 4.9t²
Now we have a quadratic equation as -
4.9t² + 8.75t - 29.4 = 0
After solving it we get two values of t -
time = 1.74 and time = -3.5
But time can not be negative so we will reject the negative values.
so t = 1.74 seconds
So to conclude that after applying the second equation of motion the time taken by the ball to reach ground is 1.74 seconds.
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Q1) Write True or False for each statement:
Equal volumes of the two different substances have equal masses.
Answer:
True
Explanation:
it is true because blabla bla
A ball of mass m is dropped. What is the formula for the impulse exerted on the ball from the instant it is dropped to an arbitrary time τ later? Ignore air resistance.
The formula for the impulse exerted on the ball at any given instant is the change in the momentum of the ball.
Impulse exerted on the ballThe impulse exerted on the ball at any given instant is calculated as follows;
J = ΔP
J = Pf - Pi
where;
J is impulse exerted on the ballpf is final momentumpi is the initial momentumThus, the formula for the impulse exerted on the ball at any given instant is the change in the momentum of the ball.
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A rectangle has a length of (2.5 ± 0.2) m and a width of (1.5 ± 0.2) m. Calculate the area and the perimeter of the rectangle, and give the uncertainty in each value.
(a)Calculate the area and give its uncertainty. (Enter your answers in m2.)
(b)Calculate the perimeter of the rectangle and give its uncertainty. (Enter your answers in m.)
The area of the rectangle obtained is (3.75 ± 0.03) m². The perimeter of the rectangle obtained is (8 ± 0.64) m.
Given dimensions:
Length (L) = (2.5 ± 0.2) m
Width (W) = (1.5 ± 0.2) m
(a) Area of the rectangle (A) is given by:
A = L × W
A = (2.5 ) × (1.5 )
A = 3.75 m²
The relative uncertainty in area = ΔA / A
ΔA = (ΔL / L) × A + (ΔW / W) × A
ΔA = (0.2 / 2.5) × 3.75 + (0.2 / 1.5) × 3.75
ΔA = 0.03 m²
Therefore, the area of the rectangle is (3.75 ± 0.03) m².
(b) Perimeter of the rectangle (P) is given by:
P = 2 × (L + W)
P = 2 × (2.5 + 1.5)
P = 2 × 4
P = 8 m
Relative uncertainty in perimeter = ΔP / P
ΔP = (ΔL / L) × P + (ΔW / W) × P
ΔP = (0.2 / 2.5) × 8+ (0.2 / 1.5) × 8
ΔP = 0.64 m
Therefore, the perimeter of the rectangle is (8 ± 0.64) m.
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in order for work to be done wht must happen?
Answer asap please due soon
An object must move in the same direction as the force is applied for work to be accomplished. Option C is correct.
What is work done?Work done is defined as the product of applied force and the distance through which the body is displaced on which the force is applied.
Work may be zero, positive and negative. it depends on the direction of the body displaced. if the body is displaced in the same direction of the force it will be positive.
The work done is found as;
W= F × d
Where.
F is the force
d is the displacement
W is the work done
In order for work to be done, an object must move in the same direction, and the force is applied
Hence option C is correct.
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A yoyo with a mass of m = 150 g is released from rest as shown in the figure.
The inner radius of the yoyo is r = 2.14 cm, and the outer radius is R = 4.00 cm, and the moment of inertia about the axis perpendicular to the plane of the yoyo and passing through the center of mass is I[tex]_{cm}[/tex] = 1.01×10-4 kgm2.
1. Determine the linear acceleration of the yoyo.
2. Determine the angular acceleration of the yoyo.
3. What is the weight of the yoyo? (Hint: It's not 150 g)
4. What is the tension in the rope?
5. If a 1.27 m long section of the rope unwinds from the yoyo, then what will be the angular speed of the yoyo?
(1) The linear acceleration of the yoyo is 3.21 m/s².
(2) The angular acceleration of the yoyo is 80.25 rad/s²
(3) The weight of the yoyo is 1.47 N
(4) The tension in the rope is 1.47 N.
(5) The angular speed of the yoyo is 71.385 rad/s.
Linear acceleration of the yoyoThe linear acceleration of the yoyo is calculated by applying the principle of conservation of angular momentum.
∑τ = Iα
rT - Rf = Iα
where;
I is moment of inertiaα is angular accelerationT is tension in the roper is inner radiusR is outer radiusf is frictional forcerT - Rf = Iα ----- (1)
T - f = Ma -------- (2)
a = Rα
where;
a is the linear acceleration of the yoyoTorque equation for frictional force;
[tex]f = (\frac{r}{R} T) - (\frac{I}{R^2} )a[/tex]
solve (1) and (2)
[tex]a = \frac{TR(R - r)}{I + MR^2}[/tex]
since the yoyo is pulled in vertical direction, T = mg [tex]a = \frac{mgR(R - r)}{I + MR^2} \\\\a = \frac{(0.15\times 9.8 \times 0.04)(0.04 - 0.0214)}{1.01 \times 10^{-4} \ + \ (0.15 \times 0.04^2)} \\\\a = 3.21 \ m/s^2[/tex]
Angular acceleration of the yoyoα = a/R
α = 3.21/0.04
α = 80.25 rad/s²
Weight of the yoyoW = mg
W = 0.15 x 9.8 = 1.47 N
Tension in the ropeT = mg = 1.47 N
Angular speed of the yoyov² = u² + 2as
v² = 0 + 2(3.21)(1.27)
v² = 8.1534
v = √8.1534
v = 2.855 m/s
ω = v/R
ω = 2.855/0.04
ω = 71.385 rad/s
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find the x-component of this vector.
The x-component for the vector given in the image is : [tex]B_{x}[/tex] = 18.3m
Meaning of a VectorA Vector can be defined as a quantity that possesses both magnitude and direction thereby giving more details.
A vector is very important when it comes to dealing with forces.
Analysis
[tex]B_{x}[/tex] = B cos(Θ)
Θ = 180° - 170° = 10°
[tex]B_{x}[/tex] = B cos(10°) = 18.3m
In conclusion, The x-component for this vector is : [tex]B_{x}[/tex] = 18.3m
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Melanie gets out of her car at the park. She walks 25 m to the trail entrance.
She jogs around the trail until she reaches a pond, where she stops briefly.
She then continues to follow the trail around the pond. Which reference point
should be used to describe her motion?
A. Her car
B. The trail entrance
C. The pond
D. The trail
The reference point that should be used to describe Melanie motion is the pond (option C).
What is reference point?Reference point is a particular point in space which is used as an endpoint to measure a distance from or chart a map from.
According to this question, Melanie gets out of her car at the park and walks 25 m to the trail entrance. She jogs around the trail until she reaches a pond, where she stops briefly.
However, she then continues to follow the trail around the pond. This suggests that the pond should serve as the reference point for Melanie's motion.
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Theory of uniform accelerated motion lab reports
The theory of uniform accelerated motion states that the movement of an element is constant in the same acceleration conditions.
What is the theory of uniform accelerated motion?The theory of uniform accelerated motion is a scientific statement regarding the acceleration of an object in steady conditions.
This theory (uniform accelerated motion) is fundamentally applied in physic and astrophysics.
In conclusion, the theory of uniform accelerated motion states that the movement of an element is constant in the same acceleration conditions.
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The form of energy that can move from place to place across the universe is
Answer:kinetic energy
Explanation:
calculate the pressure of water in a well if the depth of the water is 10m
Answer:
P= phg
so:- the height is 10m
density of water 1000 kg/m3
gravity is 9.8m/s2
P=1000 kg/m3*10m*9.8m/s2
=98000Pa
=98KPa
9. What's the process that a spark represents?
A. A body with a strong positive charge is placed near a body with a neutral charge and the electrons jump between the two bodies
B. A body with a strong positive charge is placed near a body with a strong negative charge and the electrons jump between the two
C. A body with a neutral charge is placed near a body with a strong negative charge and the electrons jump between the two bodies
D. A body with a strong positive charge is placed near a body with a strong positive charge and the electrons jump hatupon the. The answer
Answer:
Sparks often indicate the presence of a high voltage, or "potential field". The higher the voltage; the farther a spark can jump across a gap, and with enough energy supplied can lead to greater discharges such as a glow or an arc.
Explanation:
What buoyant force is exerted on a 6,000-mL toy balloon by the air surrounding the balloon? The density of air is 0.0009 g/mL
The buoyant force exerted on a 6,000-mL toy balloon by the air surrounding the balloon is 52.97N.
How to calculate buoyant force?The buoyancy needed for an object can be calculated using the formula;
B = ρ × V × g
where;
ρ and V are the object's density and volume respectivelyg is the acceleration due to gravity (9.81m/s²)B = 6000 × 0.0009 × 9.81
B = 52.97N
Therefore, the buoyant force exerted on a 6,000-mL toy balloon by the air surrounding the balloon is 52.97N.
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A particle with mass 3×10−2 kg
k
g
and charge +3 μC
μ
C
enters a region of space where there is a magnetic field of 1 T
T
that is perpendicular to the velocity of the particle. When the particle encounters the magnetic field, it experiences an acceleration of 12 m/s2
m
/
s
2
. What is the speed of the particle when it enters the magnetic-field region?
The speed of the particle when it enters the magnetic-field region is 120,000 m/s.
Speed of the particle
Magnetic force on the particle is given as;
F = qvB
where;
q is magnitude of the chargev is speed of the particleB is magnetic field strengthFrom Newton's second law, force on an object is given as;
F = ma
where;
m is mass of the particlea is accelerationma = qvB
v = ma/qB
v = (3 x 10⁻² x 12)/(3 x 10⁻⁶ x 1)
v = 120,000 m/s
Thus, the speed of the particle when it enters the magnetic-field region is 120,000 m/s.
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How do the Sun, Earth, and Moon systems interact
The sun is the mother star of the solar system, which only emits light to half of the planet, while the other part is always dark.
The sun emits light towards the earth, which dominates all life on earth. The movements of the Moon around the Earth and of the Earth around the Sun are complex. Movements of rotation around their own axes are superimposed on movements of orbital translation. The Earth and the Moon rotate around their own axes: This is rotation.
physical properties of matter help describe a substance which of the following is not a physical property of a soil sample?
A. the container in which the soul is held
B. the color of the soil
C. the volume of the soil
D. the texture of the soil
Answer asap this is an exam il give brainlist
Kim has her coffee cup on her car's dash when she takes a corner with radius 4 m and 20 km/h.
What is the minimum coefficient of static friction which would allow the coffee cup to stay there
without slipping?
The minimum coefficient of static friction is 0.807
What is static friction?Static friction is friction between two or more solid objects that are not moving relative to each other.
According to the question,
When an object turns on a curve path at a specific speed, two forces will be acting on the object which balance each other:
Centripetal force and friction force.
The friction coefficient between the object and the path is independent of the object's mass.
Given,
The radius of a corner is, r=4.16m
The turning speed of the car is, v
[tex]20km/h * (\frac{\frac{5}{18}m/s }{1km/h} )[/tex]
= 5.72 m/s
To avoid slipping a coffee cup on the car's dashboard, the centripetal force would balance the friction force.
So, Fc=Ff
[tex]\frac{mv^2}{r}[/tex]=μmg
μ=[tex]\frac{v^2}{rg}[/tex]
Here,
Fc represents the centripetal force.
Ff represents the friction force.
μ represents the coefficient of static friction.
g represents the gravitational acceleration whose value is 9.8m/s²
By Substituting the values in the above formula, we get:
μ =[tex]\frac{(5.72m/s)^2}{(4m)(9.8m/s^2)} \\[/tex] ≈ 0.807
Therefore,
The minimum coefficient of static friction is 0.807
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Two rocks of identical mass sit high above the river. One rock is 10 meters above the river, and the other is 20 meters above the river. Which rock has the greatest potential energy?
Answer:
Gravitational potential energy is greater for the rock [tex]20\; {\rm m}[/tex] above the river.
Explanation:
The gravitational field near the surface of the earth is approximately uniform. Let [tex]g[/tex] denote the strength of the gravitational field near the surface of the earth.
Let [tex]m[/tex] denote the mass of each rock. Assume that the gravitational potential energy of the two rocks is [tex]0[/tex] when the rocks are at the surface of the river.
When the rock is at a height of [tex]h[/tex] above the river, the gravitational potential energy ([tex]\text{GPE}[/tex]) of that rock would be [tex]\text{GPE} = m\, g\, h[/tex]. In other words, the [tex]\text{GPE}\![/tex] of the rock is proportional to its height relative to the ground.
Hence, among the two rocks, [tex]\text{GPE}[/tex] would be greater for the rock that is higher above the ground ([tex]20\; {\rm m}[/tex]) than the rock [tex]10\; {\rm m}[/tex] above the ground.
Refer to Chapter 10 in the textbook which discusses externalities. Specifically, reference section 10-2, which details public policies towards externalities.
Additionally, find an article using your subscription to the Wall Street Journal detailing one proposed solution to pollution.
In your post, summarize the selected article and discuss the following:
Explain which of the public policies detailed in section 10-2 of the textbook best describes the proposed solution in the selected article.
Which of the public policy approaches outlined in section 10-2 would work best to resolve this pollution problem and why?
You are required provide a link to the article and support your answer with relevant ideas, facts, and examples.
An externality, sometimes called a spillover, occurs when an exchange between a buyer and seller has an impact on a third party who is not part of the exchange. Externalities can be positive or negative
What are Externalities?Externalities refers to situations when the effect of production or consumption of goods and services imposes costs or benefits on others which are not reflected in the prices charged for the goods and services being provided.
Externalities Private markets offer an efficient way to put buyers and sellers together and determine what goods are produced, how they are produced, and who gets them. The principle that voluntary exchange benefits both buyers and sellers is a fundamental building block of the economic way of thinking. But what happens when a voluntary exchange affects a third party who is neither the buyer nor the seller?
Externalities can be negative or positive. If you hate country music, then having it waft into your house every night would be a negative externality. If you love country music, then what amounts to a series of free concerts would be a positive externality.
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●
Dean is skateboarding. He starts at a speed of 0.5 m/s and speeds up to 4.0 m/s
to go off a ramp over a time of 5.0 seconds. What is Dean's acceleration?
Answer:
[tex]\huge\boxed{\sf a = 0.7 \ m/s^2}[/tex]
Explanation:
Given Data:Initial velocity = [tex]V_i[/tex] = 0.5 m/s
Final velocity = [tex]V_f[/tex] = 4 m/s
Time = t = 5 s
Required:Acceleration = a = ?
Formula:[tex]\displaystyle a =\frac{V_f-V_i}{t}[/tex]
Solution:Put the givens in the formula.
[tex]\displaystyle a=\frac{4-0.5}{5} \\\\a = \frac{3.5}{5} \\\\a = 0.7 \ m/s^2\\\\\rule[225]{225}{2}[/tex]
In each case below, a charged rod, made of the dense rubber ebonite, comes close or is in contact with the top of an electroscope. The ball on top of the electroscope is directly connected to the two metal leaves suspended in the flask.
Which image represents a gaining of a charge on the leaves of the electroscope by conduction?
Answer:
(B) (the leaves will separate when subjected to a net charge)
The image that represents a gaining of a charge on the leaves of the electroscope by conduction is image B.
What is electroscope?An electroscope is a device that detects the presence of an electric charge or ionizing radiation by suspending a pair of thin gold leaves from an electrical conductor that leads to the outside of an insulating container.
When an electrical charge is brought close to or in contact with a conductor, the leaves in an electroscope spread apart.
This occurs because the same charge, whether positive or negative, is received by the leaves, causing their repulsion (spreading apart).
A negatively charged rod is brought in close proximity to an uncharged electroscope. As a result, the electroscope leaves become further apart.
Thus, image B is representing the given scenario.
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A 25 newton force applied on an object moves it 50 meters. The angle between the force and displacement is 40.0°. What is the value of work being done on the object?
Answer:
The value of work being done on the object is 958J.
Explanation:
Work done is equal to force multiply by distance, but when the angle is between the force and distance work done=Force (cos theta) × distance
Work done = Force(cos theta) × distance
Work done = 25N(cos 40.0°) × 50m
Work done = 25N(0.7660) × 50m
Work done = 19.15N × 50m
Work done = 957.5J = 958J
Therefore the value of work being done on the object is 958J.
The minimum takeoff speed for a certain airplane is 50 m/s. What minimum acceleration is required if the plane must leave a runway of length 2000 m? assume the plane starts from rest at one end of the runway.
Assuming constant acceleration, the requisite magnitude is [tex]a[/tex] such that
[tex]\left(50\dfrac{\rm m}{\rm s}\right)^2 - 0^2 = 2a (2000\,\mathrm m)[/tex]
Solve for [tex]a[/tex] :
[tex]a = \dfrac{\left(50\frac{\rm m}{\rm s}\right)^2}{4000\,\mathrm m} = \boxed{0.625 \dfrac{\rm m}{\mathrm s^2}}[/tex]
A person of mass 100kg runs up a staircase with a vertical height of 10m. If the trips takes 5 seconds to complete, calculate the person's power ( acceleration due to gravity =10m/s²)
Answer:
Power = 2000J/s
Explanation:
Power= Total Work done/Time
Given
mass = 100kg
distance(height) = 10m
time = 5s
acceleration due to gravity = 10m/s²
Work done = force × distance
Finding Force
Force = mass × acceleration due to gravity
Force = 100kg × 10m/s²
Force = 1,000N
Finding work done
Work done = Force × distance
Work done = 1,000N × 10m
Work done = 10,000J
Finding Power
Power = work done/time
Power = 10,000J/5s
Power = 2,000J/s
Therefore Power is 2,000J/s
A record of travel along a straight path is as follows:
1. Start from rest with constant acceleration of 2.10 m/s2 for 14.0 s.
2. Maintain a constant velocity for the next 1.90 min.
3. Apply a constant negative acceleration of −9.06 m/s2 for 3.25 s.
m/s
a) What was the total displacement for the trip?
b) What were the average speeds for legs 1, 2, and 3 of the trip, as well as for the complete trip?
The total displacement for the trip is 5510 m
During part 1, the distance travelled is
(1/2) a t^2
= (1/2)(2.77)(225)
= 311.6 m
The final speed gotten is (2.77)(15)
= 41.55 m/s.
The average speed for that interval is half of that or 20.8 m/s
During part 2, the distance traveled is
41.55 m/s*2.05 min*60 sec/min
= 5110 m/s
During part 3, the speed drops from 41.55 m/s to
41.55 - (9.47)(4.39)
= 0
The average speed during this interval is
41.55/2 - 20.78 m/s
The distance travelled is 20.78*4.39
= 91.2 m/s
Total distance travelled = 312 + 5110 + 91 = 5513 m
The average speeds for legs 1,2,and 3 of the trip as well as for the complete trip are:
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A rod of length 58.0 cm and mass 1.10 kg is suspended by two strings which are 35.0 cm long, one at each end of the rod.
The string on side B is cut. Find the magnitude of the initial acceleration of end B.
The string on side B is retied and now has only half the length of the string on side A.
Find the magnitude of the initial acceleration of the end B when the string is cut.
a) mg[tex]\frac{1}{2}[/tex] = [tex]ml^\frac{2}{3}[/tex] * ω
b)ω = [tex]\frac{3g}{2l}[/tex]
c)14.7 the magnitude of the initial acceleration of the end B when the string is cut.
What is Acceleration?Acceleration is the rate of change of the velocity of an object with respect to time.
Given
A rod of length 56.0 cm and mass 1.40 kg is suspended by two strings which are 42.0 cm long, one at each end of the rod.
When the string is cut rod rotates about other end.
Let's take momentum equation about that end:
mg*[tex]\frac{1}{2}[/tex] = Iω [I = [tex]ml^\frac{2}{3}[/tex]]
a) mg[tex]\frac{1}{2}[/tex] = [tex]ml^\frac{2}{3}[/tex] * ω
Angular acceleration:
b)ω = [tex]\frac{3g}{2l}[/tex]
c)Acceleration of end B:
a = lω= [tex]\frac{3g}{2}[/tex] =[tex]\frac{3*9.8}{2}[/tex]
a = 14.7 [g=9.8]
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