a body is moving with uniform acceleration, has initial velocity 45km/hr. and acceleration 20cm/s^2. find its velocity after 25 seconds​

Answer:

η = 0.7

Explanation:

The refractive index of the material can be calculated by using the following formula:

[tex]\eta = \frac{c}{v}\\[/tex]

where,

η = refractive index of the material = ?

c = speedof light in vaccuum = 3 x 10⁸ m/s

v = speed of light in this material = 4.3 x 10⁸ m/s

Therefore,

[tex]\eta = \frac{3\ x\ 10^8\ m/s}{4.3\ x\ 10^8\ m/s}[/tex]

η = 0.7

Answer: B

Explanation: I can tell the block weights more since the water went down

The magnitude of the induced electric field at a point near the center of the solenoid and 0.500 cm from the axis of the solenoid is 1.07 × 10⁻⁴ V/m,

The magnitude of the induced electric field at a point near the center of the solenoid and 1.00 cm from the axis of the solenoid is 4.284 × 10⁻⁴ V/m.

Total no. of turns on the solenoid = 900 turns/m

Radius of solenoid = 2.50 cm = 0.025m

Rate of increase in current = 48.0 A/s  

The magnetic field inside the solenoid,

B = μ₀nI

Where,

n = no. of turns per unit length

n = 900 turns/m

I = current flowing through the solenoid= 0 + 48t= 48t

T = 0s → I = 0

T = ∞ → I = 48

T = t

B = 4π × 10⁻⁷ × 900 × 48t

B = 1.363 T

The induced electric field at a point near the center of the solenoid.

(a) 0.500 cm from the axis of the solenoid

Area of the loop,

A = πr²

   = π(0.005)²

A = 7.85 × 10⁻⁵m²

Enclosed current,

I = nA × I

  = 900 × 7.85 × 10⁻⁵ × 48tI

  = 0.3396t

Magnetic flux,

Φ = BA = 1.363 × 7.85 × 10⁻⁵

Φ = 1.070 × 10⁻⁴ Wb

Induced electric field

E = - (dΦ/dt)

E = -d/dt (1.070 × 10⁻⁴)

E = - (-1.070 × 10⁻⁴)/dt

E = 1.07 × 10⁻⁴V/m(

b) 1.00 cm from the axis of the solenoid

Area of the loop,

A = πr² = π(0.01)²

A = 3.14 × 10⁻⁴m²

Enclosed current

I = nA × I

  = 900 × 3.14 × 10⁻⁴ × 48t

I = 1.36224t

Magnetic flux,

Φ = BA = 1.363 × 3.14 × 10⁻⁴

Φ = 4.284 × 10⁻⁴ Wb

Induced electric field,

E = - (dΦ/dt)

E = -d/dt (4.284 × 10⁻⁴)

E = - (-4.284 × 10⁻⁴)/dt

E = 4.284 × 10⁻⁴V/m

Hence,

the magnitude of the induced electric field at a point near the center of the solenoid and 0.500 cm from the axis of the solenoid is 1.07 × 10⁻⁴ V/m,

and

the magnitude of the induced electric field at a point near the center of the solenoid and 1.00 cm from the axis of the solenoid is 4.284 × 10⁻⁴ V/m.

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The ideal gas law can be used to solve the problem. The relationship between pressure, temperature, volume, and the number of moles of gas is given by the ideal gas law. PV = nRT is the formula for the ideal gas law,  Where:P = pressure in atm, V = volume in Litersn = a number of moles, R = gas constant, T = temperature in Kelvin.

The temperature at which 0.444 mol of CO gas occupies 11.8 L at 889 torr can be calculated as follows ;

First, we must convert the pressure from torr to atm: 889 torr × 1 atm/760 torr = 1.17 atm.

Using the ideal gas law formula: PV = nRT.

We can solve for T.T = PV/nR where, P = 1.17 atmV = 11.8 Ln = 0.444 molR = 0.08206 L•atm/mol•K.

Substitute the given values,T = (1.17 atm × 11.8 L)/(0.444 mol × 0.08206 L•atm/mol•K)T = 379 K.

Convert Kelvin to Celsius by subtracting 273.15 from the value,379 K - 273.15 = 105.85°C ≈ 106°C.

Therefore, the temperature at which 0.444 mol of CO gas occupies 11.8 L at 889 torr is approximately 106°C. Hence, the correct option is E)106 °C.

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Answer:

Ekaryote cells

an organism consisting of a cell or cells in which the genetic material is DNA in the form of chromosomes contained within a distinct nucleus. Eukaryotes include all living organisms other than the eubacteria and archaea.

prokaryote cells

microscopic single-celled organism which has neither a distinct nucleus with a membrane nor other specialized organelles, including the bacteria and cyanobacteria

Answer:

Force = 0.42 Newton

Explanation:

Given the following data;

Spring constant, k = 2.1

Extension, e = 0.2m

To find the force, we would use the formula below;

Force = spring constant * extension

Force = 2.1 * 0.2

Force = 0.42 Newton

Therefore, the input force is 9615.38N

T0 determine the input force needed  0.78 to raise a house corner from its foundation we need to use the formula for mechanical advantage.

Mechanical advantage = output force/ input force

Given the output force  to be 7500N and the mechanical advantage 0.78.

We can rearrange the the formula

IF = 7500/0.78

IF = 9615.38N

Therefore, the input force is 9615.38N

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Answer:

46.67 miles/s

Explanation:

...........

Explanation::i dont know the answer ,but pls then also mark me as brainlist

Answer:

When the N. Hemisphere is tilted away from the sun, the S. Hemisphere is tilted toward the sun

Explanation:

Unlike the idiot down there that just wanted point here you go

Answer:

8 g/cm³

Explanation:

density=mass/volume

volume=2*2*2=8 cm³

mass=64 g

density=64/8=8 g/cm³

The density of a 2 cm x 2 cm x 2 cm cube with a mass of 64 g is equal to 8 g/cm³.

Density can be defined as the material mass per unit of volume. The symbol commonly used to represent density ρ and the letter 'D' can also be used.

The mathematical equation of the density can be represented as written below:

Density = Mass /Volume

or,   ρ = m/V

The density of a material varies with pressure and temperature. There is a small variation for solids and liquids of any material but much larger for gases. Increasing the pressure of material decreases the volume and thus increases its density.

Given the volume of the cube =  2 cm x 2 cm x 2 cm

V = 8 cm³

The mass of the cube, m = 64 g

The density of the cube can be calculated from the above-mentioned formula:

Density = Mass of cube/volume

D = 64/8

D = 8 g/cm³

Therefore, the density of the cube is 8 g/cm³.

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In the subset number duplication example at the bottom of page 231, if the last record (2) was replaced with 1805, the Number Frequency Factor would remain the same.

The subset number duplication example is an example of the identification of the degree of duplication in a given group of data sets. It consists of records of numbers and their duplicates which are listed in order, the frequency with which each number is repeated, and the percentage of total numbers that each number represents.The given example contains a series of numerical values that represent the degree of duplication within a given group of data sets. By substituting the last record with the number 1805, the Number Frequency Factor would remain unchanged, as there is no instance of this number in the dataset. Hence, the number frequency factor would remain the same even after substituting the last record with 1805.

The units of the pre-outstanding variable An are indistinguishable from those of the rate consistent and will change contingent upon the request for the response. It has units of s1 for a reaction of first order. As a result, it is frequently referred to as the frequency factor.

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When the electroscope is grounded and a PVC pipe charged with fur is brought near it without touching, the leaves of the electroscope will diverge.

The electroscope is a device used to detect the presence of electric charge. It consists of a metal rod with two thin leaves attached to the bottom. When the electroscope is grounded, any excess charge on the leaves is neutralized and they collapse.

When a PVC pipe is charged with fur, it becomes negatively charged. As like charges repel each other, the negative charge on the PVC pipe repels the electrons in the leaves of the electroscope. Even though the pipe does not physically touch the electroscope, the electric field from the charged pipe causes the electrons in the leaves to move apart, resulting in their divergence. This happens because the electrons in the leaves experience a force of repulsion from the negative charge on the PVC pipe.

Once the charged pipe is withdrawn, the electric field weakens, and the leaves gradually come back together. The electroscope returns to its initial state with the leaves collapsed, indicating that the excess charge has been neutralized.

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The impulse exerted on the ball by the wall is -24i N s, the answer is option b.

The impulse exerted on the ball by the wall can be determined using the impulse-momentum theorem.

Impulse is equal to the change in momentum.

That is,

J = Δp

Since momentum is a vector,

p = mv

Substituting the values,

p(initial) = mv(initial) = 3.0 kg × (4i + 3j) m/s

p(initial) = 12i + 9j N s

p(final) = mv(final) = 3.0 kg × (-4i + 3j) m/s

p(final) = -12i + 9j N s

Change in momentum,

(Δp) = p(final) - p(initial)

      = (-12i + 9j) N s - (12i + 9j) N s

      = (-12 - 12)i + (9 - 9)j N s

      = -24i N s

Thus, the impulse exerted on the ball by the wall is -24i N s, which means that the answer is option b.

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The magnitude of the electric field just above the middle of the sheet is approximately 3.05 x 10⁶ N/C.

To find the electric field just above the middle of a large, flat, horizontal sheet of charge, we can use Gauss's law.

Gauss's law states that the electric field (E) due to a flat sheet of charge is directly proportional to the charge density (σ) and perpendicular to the sheet.

The charge density is given as 5.40 µC/m², which represents the charge per unit area of the sheet.

The electric field just above the middle of the sheet is the same as the electric field just below the sheet. This is because the sheet is infinitely large and uniformly charged, creating a symmetric electric field.

The formula to calculate the electric field just above the middle of the sheet is:

E = σ / (2ε₀)

Where σ is the charge density and ε₀ is the permittivity of free space, which is approximately 8.85 x 10⁻¹² C²/(N·m²).

Substituting the given values, we have:

E = (5.40 x 10⁻⁶ C/m²) / (2 x 8.85 x 10⁻¹² C²/(N·m²))

Simplifying, we get:

E = 3.05 x 10⁶ N/C

The direction of the electric field is perpendicular to the sheet and points away from it.

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The power of the eye when viewing an object 3.00 m away is 58.82 diopters (D).

What is power of the eye?

The power of the eye refers to its ability to refract light and focus it onto the retina, enabling clear vision at different distances. The power of the eye is measured in diopters (D).

In the case of the human eye, it is generally assumed to have an equivalent focal length of approximately 17 mm, which is equivalent to 0.017 m. This value represents the average refractive power of the eye.

To calculate the power of the eye when viewing an object 3.00 m away, we can use the following formula:

P = 1 / f

P = 1 / 0.017

P = 58.82 D

Therefore, the power of the eye when viewing an object 3.00 m away is approximately 58.82 diopters (D).

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Answer:

Cool.

Explanation:

What's the question..? :|

A 600-w TV receiver is turned on for 4 hours with nobody watching it. If electricity costs 10 cents/kWh, the amount of money wasted is cents. Therefore, the amount of money wasted in this case is 24 cents.

There are different steps to calculate the money wasted in this case. Here is the step-by-step solution to this problem:

First, we need to calculate the energy consumed in kWh:

Energy consumed = Power × Time Power = 600 W Time = 4 hours

Energy consumed = Power × Time Energy consumed = 600 W × 4 hours

Energy consumed = 2400 Wh.

To convert Wh into kWh, we need to divide the energy consumed by 1000:

Energy consumed = 2400 Wh = 2.4 kWh.

Now, we can calculate the amount of money wasted:

Cost of 1 kWh = 10 cents Cost of 2.4 kWh = 2.4 kWh × 10 cents/kWh

Cost of 2.4 kWh = 24 cents.  

A 600-w TV receiver is turned on for 4 hours with nobody watching it. If electricity costs 10 cents/kWh, the amount of money wasted is cents. The energy consumed by the TV receiver can be calculated by multiplying the power rating by the time it is used. In this case, the power rating is 600 W, and the time is 4 hours.

Therefore, the energy consumed is 600 W × 4 hours = 2400 Wh.

To convert the energy consumed into kWh, we need to divide it by 1000. So, 2400 Wh = 2.4 kWh. The cost of electricity is 10 cents per kWh.

Therefore, the cost of 2.4 kWh is 2.4 kWh × 10 cents/kWh = 24 cents.

This is the amount of money wasted by keeping the TV receiver turned on for 4 hours without anyone watching it. It is important to turn off electrical appliances when they are not in use to save electricity and reduce the electricity bill.

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The flux across the portion of the sphere is  a³/ 16.

To find the flux across the portion of the sphere in the first octant, we need to use a parametrization of the surface. The sphere can be parametrized as:

r(θ, φ) = (a sin φ cos θ, a sin φ sin θ, a cos φ)

where 0 ≤ θ ≤ π/2 and 0 ≤ φ ≤ π/2.

The normal vector to the surface is:

n = r_θ × r_φ

where r_θ and r_φ are the partial derivatives of r with respect to θ and φ, respectively.

We have:

r_θ = (-a sin φ sin θ, a sin φ cos θ, 0)

r_φ = (a cos φ cos θ, a cos φ sin θ, -a sin φ)

So:

n = (-a² sin² φ cos θ, -a² sin² φ sin θ, -a² sin φ cos φ)

The flux of F across S is given by:

∫∫S F ⋅ n dS

where F is the vector field and dS is the surface area element. In this case,

F = (0, 0, z)

dS = |r_θ × r_φ| dθ dφ

So we have:

∫∫S F ⋅ n dS = ∫∫D F(r(θ, φ)) ⋅ (r_θ × r_φ) dθ dφ

= ∫0(0[tex]^{\pi } /2[/tex] )∫0[tex]^{\pi } /2[/tex] (a cos φ) (-a² sin² φ cos θ i - a² sin² φ sin θ j - a² sin φ cos φ k) ⋅ (-a² sin φ i - a² sin φ j - a² cos φ k) dθ dφ

= ∫0^(π/2) ∫0[tex]^{\pi } /2[/tex] a³ sin³ φ cos²φ dθ dφ

= (a³ / 4) ∫0[tex]^{\pi } /2[/tex] (sin 4φ / 4) dφ

= (a³ / 16) [1 - 0]

= a³/ 16

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The graph that correctly gives the variation of the electric field as a function of r is the third graph.

The electric field inside a conducting shell is zero. This is because the charges on the shell distribute themselves so that the electric field is zero everywhere inside the shell.

The electric field outside a conducting shell is radial and directed away from the center of the shell. The magnitude of the electric field is inversely proportional to the square of the distance from the center of the shell.

Therefore, the graph of the electric field as a function of r is a horizontal line at zero for r < a, a vertical line at r = a, and a decreasing curve for r > a.

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Isotope B (A = 208, Z = 82) is likely to be stable because it has a relatively large mass number (A) and a relatively high atomic number (Z), which indicates a balanced ratio of neutrons to protons in the nucleus.

Stable isotopes generally have a close to 1:1 ratio of neutrons to protons. Isotope A (A = 24, Z = 12) and isotope C (A = 222, Z = 86) have lower atomic numbers and may not have a balanced neutron-to-proton ratio, making them less likely to be stable.

However, it is important to note that stability is also influenced by the specific arrangement of nucleons and nuclear forces, so further analysis would be required to determine stability definitively.

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Answer:

9.0 N

Explanation:

The location of the mass of the wheel on the wheel = Evenly distributed

The acceleration of the solid wheel, α = 3.25 rad/s²

The applied force on the wheel = 4.5 N

The location mass of the replacement wheel = All on (around) the rim

The moment of inertia of the new wheel, I = m·r² (From an online source)

We have;

The moment of inertia for a solid wheel = 1/2·m·r²

The torque, τ = Moment of inertia, I × Acceleration, α

For the solid wheel, we have;

τ  = 1/2·m·r² × 3.25 rad/s²

τ = r × F = r × m × a

For the replacement wheel, we have;

τ  = m·r² × 3.25 rad/s² = 2 × 1/2·m·r² × 3.25 rad/s²

∴ τ = 2 × r × F

Given that the radius remains the same, the force applied on the replacement wheel needs to be doubled

The force that should be exerted on the strap to give the same angular velocity, F' = 2 × F

The required force, F' = 2 × 4.5 N = 9.0 N.

Answer:

V = 411.43 V

Explanation:

The two forces as a result of each of the 2 charges are;

F1 = kq1•q/r

F2 = kq2.q/r

Where r = r/2 since we are dealing with potential difference at a point midway between the charges.

q1 = 5 nC = 5 × 10^(-9) C

q2 = 3 nC = 3 × 10^(-9) C

k = 9 × 10^(9) N.m²/C²

r = 35 cm = 0.35m

r/2 = 0.35/2

Thus;

F1 = (9 × 10^(9) × 5 × 10^(-9) × q)/(0.35/2)²

F1 = 1469.39q

F2 = (9 × 10^(9) × 3 × 10^(-9) × q)/(0.35/2)²

F2 = 881.63q

Net force acting midway is;

F_net = F1 + F2

F_net = 1469.39q + 881.63q

F_net = 2351.02q

Now, we know that formula for electric potential is;

V = kq/r

Thus ;

V = Fr/q derived from the earlier equation for force we used.

Where F is F_net.

V = 2351.02q × r/q

V = 2351.02r

Recall that we are dealing with midpoint and r = r/2

Thus;

V = 2351.02 × 0.35/2

V = 411.43 V

C) fault-block mountain

Answer

A spherical bob creates more control for the simple pendulum experiment. An irregular bob like a large piece of paper for instance, will create too much air resistance for a basic classical experiment to yield predictable results within the academic lab.

Two reasons why it is better to obtain the moment of inertia through a linear fit rather than by solving for I using specific points (ωmax and θ0) are:

Increased Precision: A linear fit allows for the consideration of a larger set of data points, which can provide a more accurate determination of the moment of inertia. By analyzing the relationship between θ and ω over a range of values, the linear fit captures the overall trend and minimizes the potential errors associated with individual data points. This leads to a more precise estimation of the moment of inertia compared to relying on only one or two specific points. Account for Nonlinearities: In some cases, the relationship between θ and ω may not follow a simple linear pattern. If nonlinearity exists, using a linear fit provides a more flexible approach to capture the overall trend. By fitting a line to the data, even if the relationship is not strictly linear, we can still obtain a reasonable approximation of the moment of inertia by considering the best-fit line that represents the general behavior of the system. This method accounts for potential nonlinearities and provides a more reliable estimate of the moment of inertia compared to a limited number of specific points.

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We can utilize Einstein's mass-energy equivalence equation, E = mc², where E represents the energy. The work done on the particle is equal to the change in energy.

When the particle is at rest, its energy is solely its rest energy, which is given by E = mc². As the particle is accelerated to a speed of 0.902 c, its total energy increases. The change in energy (ΔE) is the difference between the final energy and the initial rest energy.

The final energy of the particle when it reaches a speed of 0.902 c is given by E = γmc², where γ is the Lorentz factor. The Lorentz factor is defined as γ = 1/√(1 - (v/c)²), where v is the velocity of the particle.

By substituting the given values into the Lorentz factor equation, we can calculate the Lorentz factor for the particle. With the Lorentz factor known, we can determine the final energy of the particle.

The work done on the particle is equal to the change in energy, so the work can be calculated as ΔE = (γ - 1)mc². By substituting the values into the equation and expressing the answer as a multiple of mc², we can determine the work required to accelerate the particle to the given speed.

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Answer:

A

Explanation:

The wavelength is the spatial time of an occasional wave, the distance over which the wave's shape rehashes.

Hope this helped!!

Answer:

wavelength

Explanation:

A pot containing 630 g of water is placed on the stove and is slowly heated from 21°C to 81°C, then the change in entropy of the water is 7200 J/K.

To calculate the change in entropy (ΔS) of water, we can use the formula:

ΔS = mcΔT / T

Where:

m is the mass of the water,

c is the specific heat capacity of water,

ΔT is the change in temperature, and

T is the initial temperature.

First, we need to find the specific heat capacity of water. The specific heat capacity of water is approximately 4.18 J/g°C.

Mass of water (m) = 630 g

Change in temperature (ΔT) = (81°C - 21°C) = 60°C

Initial temperature (T) = 21°C

Substituting these values into the formula, we get:

ΔS = (630 g) * (4.18 J/g°C) * (60°C) / (21°C)

Simplifying the equation:

ΔS = (630 g) * (4.18 J/g°C) * (60°C) / (21°C)

  = 630 * 4.18 * 60 / 21

  = 7200 J/K

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Answer:

P=F/A where F is the weight of the water and A is the area on which it is resting. The weight of the water is mg. The mass of the water is dv where d is the density and v is the volume. Finally, the volume of the water in a vessel is equal to the area of the base of the vessel times the height of the vessel. (v=Ah)

Plugging everything in we get:

P = dAhg/A

So

P=dhg

So we have shown that liquid pressure is directly  proportional to height of liquid in a vessel.​