Answer:
[tex]v_m \approx -4.38\; \rm m \cdot s^{-1}[/tex] (moving toward the incline.)
[tex]v_M \approx 4.02\; \rm m \cdot s^{-1}[/tex] (moving away from the incline.)
(Assumption: [tex]g = 9.81\; \rm m \cdot s^{-2}[/tex].)
Explanation:
If [tex]g = 9.81\; \rm m \cdot s^{-2}[/tex], the potential energy of the block of [tex]m = 2.20\; \rm kg[/tex] would be [tex]m \cdot g\cdot h = 2.20\; \rm kg \times 9.81\; \rm m \cdot s^{-2} \times 3.60\; \rm m \approx 77.695\; \rm J[/tex] when it was at the top of the incline.
If friction is negligible, all these energies would be converted to kinetic energy when this block reaches the bottom of the incline. There shouldn't be any energy loss along the horizontal surface, either. Therefore, the kinetic energy of this [tex]m = 2.20\; \rm kg\![/tex] block right before the collision would also be approximately [tex]77.695\; \rm J[/tex].
Calculate the velocity of that [tex]m = 2.20\; \rm kg[/tex] based on its kinetic energy:
[tex]\displaystyle v_m(\text{initial}) = \sqrt{\frac{2\times (\text{Kinetic Energy})}{m}} \approx \sqrt{\frac{2 \times 77.695\; \rm J}{2.20\; \rm kg}} \approx 8.4043\; \rm m \cdot s^{-1}}[/tex].
A collision is considered as an elastic collision if both momentum and kinetic energy are conserved.
Initial momentum of the two blocks:
[tex]p_m = m \cdot v_m(\text{initial}) \approx 2.20\; \rm kg \times 8.4043\; \rm m \cdot s^{-1} \approx 18.489\; \rm kg \cdot m \cdot s^{-1}[/tex].
[tex]p_M = M \cdot v_M(\text{initial}) \approx 2.20\; \rm kg \times 0\; \rm m \cdot s^{-1} \approx 0\; \rm kg \cdot m \cdot s^{-1}[/tex].
Sum of the momentum of each block right before the collision: approximately [tex]18.489\; \rm kg \cdot m \cdot s^{-1}[/tex].
Sum of the momentum of each block right after the collision: [tex](m\cdot v_m + m \cdot v_M)[/tex].
For momentum to conserve in this collision, [tex]v_m[/tex] and [tex]v_M[/tex] should ensure that [tex]m\cdot v_m + m \cdot v_M \approx 18.489\; \rm kg \cdot m \cdot s^{-1}[/tex].
Kinetic energy of the two blocks right before the collision: approximately [tex]77.695\; \rm J[/tex] and [tex]0\; \rm J[/tex]. Sum of these two values: approximately [tex]77.695\; \rm J\![/tex].
Sum of the energy of each block right after the collision:
[tex]\displaystyle \left(\frac{1}{2}\, m \cdot {v_m}^2 + \frac{1}{2}\, M \cdot {v_M}^2\right)[/tex].
Similarly, for kinetic energy to conserve in this collision, [tex]v_m[/tex] and [tex]v_M[/tex] should ensure that [tex]\displaystyle \frac{1}{2}\, m \cdot {v_m}^2 + \frac{1}{2}\, M \cdot {v_M}^2 \approx 77.695\; \rm J[/tex].
Combine to obtain two equations about [tex]v_m[/tex] and [tex]v_M[/tex] (given that [tex]m = 2.20\; \rm kg[/tex] whereas [tex]M = 7.00\; \rm kg[/tex].)
[tex]\left\lbrace\begin{aligned}& m\cdot v_m + m \cdot v_M \approx 18.489\; \rm kg \cdot m \cdot s^{-1} \\ & \frac{1}{2}\, m \cdot {v_m}^2 + \frac{1}{2}\, M \cdot {v_M}^2 \approx 77.695\; \rm J\end{aligned}\right.[/tex].
Solve for [tex]v_m[/tex] and [tex]v_M[/tex] (ignore the root where [tex]v_M = 0[/tex].)
[tex]\left\lbrace\begin{aligned}& v_m \approx -4.38\; \rm m\cdot s^{-1} \\ & v_M \approx 4.02\; \rm m \cdot s^{-1}\end{aligned}\right.[/tex].
The collision flipped the sign of the velocity of the [tex]m = 2.20\; \rm kg[/tex] block. In other words, this block is moving backwards towards the incline after the collision.
A bugatti chiron travels 116 m/s for 10 seconds.how far did it travel
Answer:
V= 1,160 m
Explanation:
formula:
V= V* T
remplazamos:
V= 116m /s * 10s
V= 1,160 m
Answer:
V= 1,160 m
Explanation:
The diagram shows the forces acting on an object at an instant of time. Which of
the following statements about the forces is true? Select one answer.
Answer:
The correct option is;
The object is in horizontal equilibrium but NOT in vertical equilibrium
Explanation:
The given given forces in the force diagram are expressed in vector form as follows;
Topmost force = 2·i + 3·j
The horizontal force = 3·i
The force at the lower section = -5·i - 2·j
Adding the forces together to find the resultant force gives;
[tex]F_R[/tex] = 2·i + 3·j + 3·j + (-5·i - 2·j) = 5·i + 3·j - 5·i - 2·j = 0·i + j = j
[tex]F_R[/tex] = j
Therefore, the horizontal component of the forces are balanced as they cancel out and the object is said to be in horizontal equilibrium
However, the object has a net total resultant force component in the positive vertical direction, the object is not in vertical equilibrium.
is the force that opposes the motion and therefore, tries to stop
or slow down a moving body.
e fuole
Answer:
Friction is the force between an object in motion and the surface on which it moves. Friction is the external force that acts on objects and causes them to slow down when no other external force acts upon them. Inertia is the tendency of a body in motion to remain in motion.
Answer:
Explanation:
Friction is the drive between an object in motion and the surface on which it moves. Friction is the outside constrain that acts on objects and causes them to moderate down when no other outside drive acts upon them.
The average velocity of an object over 6.0 seconds interval is 2 m/s what is the total distance traveled and M by the object doing this time interval
Answer:
The answer is 12 mExplanation:
The distance covered by an object given it's velocity and time taken can be found by using the formula
distance = velocity × time
From the question we have
distance = 2 × 6
We have the final answer as
12 mHope this helps you
A roller coaster is stopped on a track. When the engineer presses a launch button on the coaster, the coaster moves forward. Explain this change in terms of balanced and unbalanced forces.
explain what happens when particles collide
Answer
they transfer energy
What is the net force on this box?
Answer:
I believe 0
Explanation:
this is due to the fact that the box will not move anywhere the forces are canceling themselves out.
Convert 14 minutes to seconds.
(What unit do we want)
1. Seconds
2. Minutes
Answer:
Seconds...
Explanation:
The south pole of one bar magnet is near the south pole of another bar magnet. What happens between the magnets?
A. They attract each other.
B. They twist toward each other.
C. They neither attract nor repel each other.
D. They repel each other.
PLEASE HELP!!!!!!!!!!
The south pole of one bar magnet brings near the south pole of another bar magnet, they repel each other. Therefore, option (D) is correct.
What are the magnets?A magnet can be defined as an object which is capable of producing a magnetic field and attracting unlike poles and repelling like poles. When a magnet dropped in iron filings, the iron filings cling to the end of the magnet as the attraction is maximum at the ends of the magnet.
Magnetic poles always exist in pairs whenever a magnet is suspended freely in the air, and always points in the north-south direction. The pole pointing towards the geographic north is called the North Pole and the pole pointing towards the geographic south is called the South Pole.
Similar poles of a magnet repel while unlike poles attract each other. The magnetic force between the two magnets is higher when the distance between these magnets is lesser. There are three types of magnets which are Permanent magnets, Temporary magnets, and electromagnets.
Learn more about magnets, here:
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A 3kg ball moving at 8 m/s strikes a 2kg ball at rest,if the collision is elastic,what is the speed of the lighter ball if the heavier ball moves at 2m/s in the opposite direction
Answer:
Speed of lighter ball is 4 m/s.
Explanation:
Applying the principle of conservation of linear momentum,
momentum before collision = momentum after collision.
[tex]m_{1}[/tex][tex]u_{1}[/tex] + [tex]m_{2}[/tex] [tex]u_{2}[/tex] = [tex]m_{1}[/tex][tex]v_{1}[/tex] - [tex]m_{2}[/tex][tex]v_{2}[/tex]
[tex]m_{1}[/tex] = 3 kg, [tex]u_{1}[/tex] = 8 m/s, [tex]m_{2}[/tex] = 2 kg, [tex]u_{2}[/tex] = 0 m/s ( since it is at rest), [tex]v_{1}[/tex] = 2 m/s, [tex]v_{2}[/tex] = ?
(3 x 8) + (2 x 0) = (8 x 2) - (2 x [tex]v_{2}[/tex])
24 + 0 = 16 - 2[tex]v_{2}[/tex]
2[tex]v_{2}[/tex] = 16 - 24
2[tex]v_{2}[/tex] = -8
[tex]v_{2}[/tex] = [tex]\frac{-8}{2}[/tex]
= -4 m/s
This implies that the light ball moves at the speed of 4 m/s in the opposite direction of the heavier ball after collision.
Consider the line graph depicting the motion of two cars. What statement regarding the cars motion is accurate?
Answer:
Its C
Explanation:
I did it on usatestprep
what would be the velocity
when a dog of 10kg and it's kinetic energy is 20J
Answer:
2 m/s
Explanation:
Lead-202 has a half-life of 53,000 years. How long will it take for 15/16 of a sample of lead-202 to decay?
106,000 years
159,000 years
212,000 years
265,000 years
(Thank you very much :L)
Answer:
C. 212,000 years
Explanation:
believe me it's correct.....and you're welcome :)
The force of a plane's engine is moving the plane toward the right with 800N. Coming from the left you have
resistance forces of air with 60N and friction with 40N. What is the direction and net forces that is being applied
the plane?
Answer:es la F
Explanation:
A diver runs horizontally off the end of a diving board with an initial speed of 1.95 m/s. If the diving board is 2.00 m above the water, what is the diver's speed just before she enters the water
Answer:
V = 6.56 m/s
Explanation:
in order to find the speed of the diver before she enters we need to find the vertical component of its final velocity by using 3rd equation of motion:
2gh = Vy² - V₀y²
where,
g = 9.8 m/s²
h = height = 2 m
Vy = Vertical Component of Final Velocity = ?
V₀y = Vertical Component of Initial Velocity = 0 m/s
Therefore,
2(9.8 m/s²)(2 m) = Vy² - (0 m/s)²
Vy = √39.2 m²/s²
Vy = 6.26 m/s
Assuming negligible air friction, the x-component of the final velocity will be the same as the initial velocity:
Vₓ = V₀ₓ = 1.95 m/s
Hence, the final velocity will be:
V = √(Vₓ² + Vy²)
V = √[(1.95 m/s)² + (6.26 m/s)²]
V = 6.56 m/s
The planet Jupiter is about 300 times as massive as Earth, but an object on its surface would weigh only 2.5 times as much as it would on earth. Can you come up with an explanation?
Answer:
here you go
Explanation:
so it might seem that a body on the surface of Jupiter would weigh 300 times as much as on Earth. ... But the radius of Jupiter is about 10 times that of Earth, weakening gravity by a factor of 100, resulting in 3 times its Earth weight.
What is the radius of an automobile tire that turns with a period of 0.091 s and has a linear
speed of 20.0 m/s? What kind of force is the centripetal force?
Answer:
1) The radius of the tire is approximately 0.28966 meters
2) The centripetal force is the force that keeps a body moving on a circular path
Explanation:
1) The linear speed of the automobile tire = 20.0 m/s
The period with which the tire turns = 0.091 s
The period = The time it takes to make a complete turn
Therefore;
The number of turns in 1 second = 1/0.091 ≈ 10.989 turns
The distance covered with 10.989 turns, assuming no friction = 10.989 × The circumference of the tire
∴ The distance covered with 10.989 turns, assuming no friction = 10.989 × 2 × π × Radius of the tire
From the speed of the car, 20.0 m/s, we have;
The distance covered in 1 second = 20.0 meters
Therefore;
10.989 × 2 × π × Radius of the tire = 20.0 meters
Radius of the tire = (20.0 meters)/(10.289 × 2 × π) ≈ 0.28966 meters
The radius of the tire ≈ 0.28966 meters
2) The centripetal force is the force required to maintain the curved motion of an object, and having a direction towards the center of the rotary motion.
The centripetal force is given by the formula, [tex]F = \dfrac{m \cdot v^2}{r}[/tex]
Where;
F = The centripetal force
m = The mass of the object
v = The linear velocity of the object
r = The radius of the rotational motion.
What is the average acceleration of a tennis ball that has an initial velocity of 6.0 m/s [E] and a final velocity of 7.3 m/s [W], if it is in contact with a tennis racket for 0.094 s?
Given :
The average acceleration of a tennis ball that has an initial velocity of 6.0 m/s.
and a final velocity of 7.3 m/s.
It is in contact with a tennis racket for 0.094 s
To Find :
The average acceleration of the tennis ball.
Solution :
We know, average acceleration is given by :
[tex]a_{avg}=\dfrac{Final \ velocity-Initial\ velocity}{Time\ Taken}\\\\a_{avg}=\dfrac{7.3-6.0}{0.094}\ m/s^2\\\\a_{avg}=13.83\ m/s^2[/tex]
Therefore, average velocity is given by 13.83 m/s².
Hence, this is the required solution.
A 12 kg object speeds up from an initial velocity of 10 m:s-1
north to a final velocity of 15 m.s-north. Calculate the
change in momentum.
Select one:
a. -60 kg.m/s
b. 60 kg.m/s
C. -80 kg.m/s
d. 300 kg.m/s
Momentum = m • v
Original momentum = m • 10 m/s north
Final momentum = m • 15 m/s north
Change = m • (15 - 10) m/s north
Change = m • +5 m/s north
Change = +60 kg-m/s north
What is the current in the 10.0 resistor?
Answer:
12.0V
12.0V
Explanation:
.
.
.
.
.
.
.
.
.
.
.
Answer:
2.00 A
Explanation:
Psychology:
_________ is focusing on something specific in the environment.
A.
Attention
B.
Stimuli
C.
Memory
D.
Rehearsal
The answer is A. Attention
Answer:
ans is a .attention
plsssssssssssss mark meeee brainlist
Explanation:
How are density and buoyancy related to each other?
Answer:
Buoyant force is directly proportional to the density of the fluid in which an object is immersed. Buoyancy is the tendency to rise or float in a fluid. The upward force exerted on objects submerged in fluids is called the buoyant force. where ρ is the density, V is the volume, and m is the mass of the displaced fluid.
Explanation:
Answer:
well It means the plant cells inside of a organism
The SI unit of average speed m.s. True or False. But is there difference between m/s and m.s.
Answer:
false
Explanation:
there is difference in m/s and m.s
29. Identify whether each of the following is a form of mechanical energy:
elastic potential energy, chemical potential energy, gravitational potential
energy.
Explanation:
elastic potential energy, chemical potential energy, and gravitational potential energy are all forms of mechanical energy.
Mechanical energy includes elastic potential energy, chemical potential energy, and gravitational potential energy.
What is Mechanical energy?Mechanical energy is the energy that an object has as a result of its motion or position. Because it is stretched out in that position, a pulled bow has mechanical energy (elastic potential energy). Chemical potential energy is the energy that a substance has stored in its chemical bonds. A barbell hoisted high above a weightlifter's head has mechanical energy because of its vertical position above the ground (gravitational potential energy).The sum of kinetic and potential energy in an object used to perform a specific task is known as mechanical energy. In other words, it describes the energy of an object as a result of its motion, position, or both.
To learn more about mechanical energy, refer
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Does water pressure depend on the total amount of water present?
(Will pick brainliest)
Answer:
No, because pressure is determined by force and the area over which that force acts.
Explanation:
kinetic energetic plus potential energy is called
Examine the diagram of the cell cycle.
Which label identifies the step labeled W?
Anaphase: chromosomes thicken
Metaphase: chromosomes thicken
Anaphase: chromosomes are pulled apart
Metaphase: chromosomes are pulled apart
Answer:
Anaphase: chromosomes are pulled apart
Explanation:
Anaphase is a very rapid phase of meiosis and mitosis where sister chromatids (during mitosis or meiosis II) or homologous chromosomes (during meiosis I) separate and migrate to opposite poles of the cell. In the image, the diagram represents mitosis (thus separation of sister chromatids).
During this phase, following a specific signal, the sister chromatids separate abruptly. They are then "pulled" by the "microtubules" towards the pole to which they are attached. Chromatids migrate rapidly at a rate of about 1 μm / min. Anaphase is usually divided into two distinct phases.
Answer:
The answer is C
Explanation:
What allows us to categorize rocks into the three rock types: Igneous, Sedimentary, and Metamorphic?
Whether or not the rock melts
Involvement of sediment
Process of formation
O Magma or weathering.
Answer:process of formation
Explanation:
A projectile is fired with an initial speed of 37.0 m/s at an angle of 43.7 ∘ above the horizontal on a long flat firing range. What is the maximum height.
Answer:
The maximum height reached by the projectile is 33.34 m
Explanation:
Given;
initial velocity of the projectile, u = 37 m/s
angle of projection, θ = 43.7°
The maximum height reached by the projectile = ?
Apply the following kinematic equation, to determine the maximum height reached by the projectile.
Maximum height (H) is given as;
[tex]H = \frac{u^2 sin^2\theta}{2g}\\\\ H = \frac{(37)^2 (sin 43.7)^2}{2*9.8}\\\\H = 33.34 \ m[/tex]
Therefore, the maximum height reached by the projectile is 33.34 m
A submarine is built to dive to a depth of 90 m where the pressure in the water is about 1 MPa. The engineers want to build a window in the submarine, but the window can only take a force of 10 kN safely. What is the largest surface area window that can be used?
Answer:
The largest surface area window that can be used is [tex]A=0.01\ m^2[/tex]
Explanation:
Pressure
The pressure is defined as force per unit area. The SI unit for pressure is the Pascal (Pa), defined as Newton per square meter.
If a force F acts on a surface area A, the pressure is calculated as:
[tex]\displaystyle P=\frac{F}{A}[/tex]
The pressure at a depth of 90 m is P=1 Mpa= 1,000,000 Pa and the submarine's window can only take a force of F=10 kN=10,000 N.
We need to calculate the largest surface area of the window. We can solve the equation for A:
[tex]\displaystyle A=\frac{F}{P}[/tex]
Substituting:
[tex]\displaystyle A=\frac{10,000}{1,000,000}[/tex]
[tex]A=0.01\ m^2[/tex]
The largest surface area window that can be used is [tex]\mathbf{A=0.01\ m^2}[/tex]