A block of mass 3 kg slides down an inclined plane at an angle of p with a massless tether attached to a pulley with mass 1 kg and radius 0.5 m at the top of the incline. The acceleration of the block is a = [m1g(sinΘ - μcosΘ)]/(m1 + 1/2m2).
Formula of acceleration = a bar = (v - v0)/t = delta v / delta t
a bar = average acceleration
v = final velocity
v0 = starting velocity
t = elapsed time
After solving by the formula we get, a = [m1g(sinΘ - μcosΘ)]/(m1 + 1/2m2).
Acceleration refers to the rate at which an object's velocity with respect to time varies. Acceleration is a vector quantity (in that they have magnitude and direction). The direction of an object's acceleration is determined by the direction of the net force acting on it. According to Newton's Second Law, the amount of an object's acceleration is the combined result of two causes: According to the materials used to make the object, the magnitude of the net balance of all external forces acting on it is inversely proportional to its mass, but the magnitude of the net resulting force is directly proportional to the net force.
We are aware that the angle = 45°, the block's mass m1 is 3 kg, and the pulley's mass m2 is 1 kg.
Pulley radius is 0.5 meters, and its coefficient of friction is 0.4.
Four forces are at work on the mass-m1 block:
Weight is represented by m1g, normal response force by N, tension by T, and frictional force by f.
After solving we get acceleration = a = [m1g(sinΘ - μcosΘ)]/(m1 + 1/2m2)
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A series LCR circuit is connected to an ac voltage source. When L is removed from the circuit, the phase difference between current and voltage is π/3. If instead C is removed from the circuit, the phase difference is again π/3 between current and voltage. The power factor of the circuit is :
Azero
B0.5
C1.0
D-1.0
An ac voltage source is attached to an LCR series circuit. The phase difference between current and voltage is /3 when L is taken out of the circuit. The circuit has a power factor of one.
LCR series circuit, which stands for inductance-capacitance-resistance, can only function as one of the three components on its own. It is also employed to boost voltage and raise the voltage that travels through each component of the circuit individually. This voltage has the potential to be far higher than the external voltage that is applied to the electrical circuit.
IXc = sin (pi/4)
Xc = R
The phasor will look like this when C is eliminated.
Xl = Xc
The supplied circuit is therefore in resonance.
LCR circuit's power factor is 1 cos(o).
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A race car starts from rest and travels east along a straight and level track. For the first 5.0 s of the car's motion, the eastward component of the car's velocity is given by vx(t)=(0.970m/s3)t2.
a.What is the acceleration of the car when vx = 16.7 m/s? Express your answer with the appropriate units.
The acceleration of the car when Vₓ = 16.7 m/s is 8.05 m/s² .
In the question ,
it is given that ,
east ward component of the the car's velocity is Vₓ(t) = (0.970 m/s³)t²
To find the acceleration of the car, we differentiate velocity with respect to t ,
We get ,
aₓ = dVₓ/dt = d/dt (0.97 m/s³)t²
aₓ = (2 × 0.97 m/s³)t
aₓ = (1.94 m/s³)t ...equation(1)
given that Vₓ = 16.7 m/s .
So , 16.7 = (0.97 m/s³)t²
t² = 16.7/0.97
t = 4.15 sec .
Substituting, time t = 4.15 in the equation(1) , we get
aₓ = 1.94 × 4.15
= 8.05 m/s²
Therefore , the requires acceleration is 8.05 m/s² .
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Don is attempting to build muscle mass for his first body-building competition. According to the American College of Sports Medicine, he should be eating _______________ grams per kilogram of body weight of protein per day.
1.5 to 1.7
Don is attempting to build muscle mass for his first body-building competition. According to the American College of Sports Medicine, he should be eating 1.5 to 1.7 grams per kilogram of body weight of protein per day.
Muscle is a system of coordinated contractile tissues that is used to perform tasks more effectively. The physical appearance and cell location of the muscular systems in humans are used to classify them. Strained (or skeletal), cardiac, and smooth muscles are the three categories (or nonstriated). The majority of the muscular tissue in the body is striated muscle, which is mostly connected to the skeleton. The somatic nervous system directs the multinucleated fibers, which cause stresses on the skeleton like those produced by pulleys and levers to cause movement. Sinoatrial node, the pacemaker of the heart, controls the rhythmic contraction of cardiac muscle. Cardiovascular muscle is a particular striated muscle with several centrally positioned nuclei that is made up of elongated cells, however it is not controlled voluntarily. Blood lines the smooth muscle of the viscera.
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a uniform, 4.0 kg, square, solid wooden gate 1.5 m on each side hangs vertically from a frictionless pivot at the center of its upper edge. a 1.3 kg raven flying horizontally at 5.0 m/s flies into this door at its center and bounces back at 2.5 m/s in the opposite direction.
The angular speed of the gate just after it is struck by the unfortunate raven is 2.4375rad/s and during the collision, the angular momentum is conserved but not the linear momentum.
Given mass of square (m) =4kg
length of solid wooden gate (l) =1.5m
mass of raven (m1) = 1.3kg
speed of raven (v1) = 5m/s
speed of bouncing back (v2) = 2.5m/s
Impulse on gate (I) = 1/3ml^2 = 1/3x4x1.5x1.5 = 3kgm^2
(a) using conservation of angular momentum Li = Lf
1/2mv1L/2 = mv2L/2+Iω
m(v1+v2)L/2 = 3xω
1.3x(5+2.5)x1.5/2 = 3xω
ω = 2.4375rad/s
(b)As momentum is conserved there is no external torque
initial kinetic energy (KE) = 1/2mv1^2 = 1/2x1.3x5x5 = 16.25J
final kinetic energy (KEf) = 1/2mv2^2+Iω^2/2
KEf = 1x1.3x2x2/2+3x2.4375x2.4375/2 = 2.6+ 8.9 = 11.5J
As Kinetic energy is not conserved, the collision is inelastic.
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Complete question: a uniform, 4.0 kg, square, solid wooden gate 1.5 m on each side hangs vertically from a frictionless pivot at the center of its upper edge. a 1.3 kg raven flying horizontally at 5.0 m/s flies into this door at its center and bounces back at 2.5 m/s in the opposite direction. (a) What is the angular speed of the gate just after it is struck by the unfortunate raven? (b) During the collision, why is the angular momentum conserved but not the linear momentum?
identify the correlation you would expect to see between the weight of baggage someone carries and the speed at which he or she walks. explain.
Negative association; the pace of walking slows down as the amount of luggage grows.
Positive and negative correlation: what are they?Inverse correlation is another term for negative correlation. In statistics, an inverse correlation explains the association between two variables that vary in the opposite directions from one another, whereas a positive correlation shows the link between two variables that change together.
When two variables behave in synchrony, rising or falling in lockstep with one another, there is a positive correlation. When two variables move in opposition to one another—that is, when one rises, the other falls—this is known as a negative correlation.
A link between two variables that move in the opposing directions is known as a negative correlation.
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suppose that 256.0 j of heat is transferred by conduction from a heat reservoir at a temperature of 420.0 k
Answer:
ΔS= -1 J/K
Explanation:
Using this data
Heat Q= -256.0J
Temperature T=420.0 K
To find
Entropy change ΔS
Solution
We know that the entropy change of system is ΔS is given by
ΔS=Q/T
We have take heat value Q as negative because the heat is removed from heat reservoir
So
ΔS=(-256J/470K)
ΔS= -1 J/K
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A 2 m long wire carrying 2 A of current pointing to the right is placed in a magnetic field of 4 T directed away from you.
How big is the force acting on the wire?
A. 4 N
B. 8 N
C. 12 N
D. 16 N
Answer:16
Explanation:
as F=BIL so by placing value's B is magnetic field 4 and i is current 2A and l is length that js 2 m so answer is
Given: i=10A,B=0.15 T,θ=45
∘
and l=2 m
Force on a current carrying wire of finite length =
F
=l(
i
×
B
)
Hence, magnitude of force, F=Bilsinθ
=0.15×10×2×sin45
∘
=
2
3
N
figure 32-27 shows a closed surface. along the flat top face, which has a radius of 2.0 cm, a perpendicular magnetic field of magnitude 0.30 t is directed outward. along the flat bottom face, a magnetic flux of 0.70 mwb is directed outward. what are the (a) magnitude and (b) direction (inward or outward) of the magnetic flux through the curved part of the surface?
a) The magnitude of the magnetic flux through the curved part of the surface is 0.70 mWb.
b) The magnetic flux through the curved part of the surface is 12.56 cm².
The direction of the magnetic flux through the curved part of the surface is outward.
The magnetic flux through a surface is given by the equation:
Φ = B × A
where Φ is the magnetic flux, B is the strength of the magnetic field, and A is the area of the surface.
In this case, the strength of the magnetic field is given as 0.30 T, and the area of the curved surface is given as the surface area of a hemisphere with a radius of 2.0 cm, which is:
A = 2 × π × r² = 2 × 3.14 × (2.0 cm)² = 12.56 cm²
Plugging these values into the equation gives us a magnetic flux of:
Φ = (0.30 T) × (12.56 cm²) = 0.70 mWb
The direction of the magnetic flux is given as outward for both the top and bottom faces, so the direction of the magnetic flux through the curved part of the surface is also outward.
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mcdougal products is considering the purchase of new equipment to place in its factory. the equipment would cost $365,000, have a ten-year useful life and a salvage value at the end of its useful life of $65,000. the company estimates that annual revenues and expenses associated with the equipment would be as follows: the payback period of the new equipment is closest to:
The payback period of the new equipment is closest to 17.8%
Simple rate of return is equal to annual operating income minus the initial investment.
=$65000/365000
=17.8%
The payback period describes how long it will take to return the cost of an investment. The time it takes for an investment to break even can be summed up in this way. The payback period is important because people and businesses invest money primarily to be compensated. The payback period is the amount of time an investor would need to invest in a project before they would be able to repay their initial investment. The investment's break-even point is closely related to it.
Instead of using the units of a break-even analysis, Payback Period employs years to quantify investment opportunities and risk in a rapid and straightforward manner.
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acceleration of 14 m/s/s mass of object is decreased by a factor of 2.2 then the new accelration woul dbe
When the mass of the object is decreased by a factor of 2.2, the acceleration is increased by a factor of 2.2, new acceleration would be of 30.8 m/s/s.
The effect of reducing the mass of an object by a factor of 2.2 on its acceleration is determined by Newton's Second Law of Motion, which states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass.
In terms of calculations, the new acceleration can be calculated by multiplying the initial acceleration by the factor by which the mass is decreased. Therefore, the new acceleration of the object with a reduced mass of 2.2 times its original mass would be 2.2 times its initial acceleration of 14 m/s/s. This would result in a new acceleration of 30.8 m/s/s (14 x 2.2 = 30.8).
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On the basis of your knowledge of bonding in liquids and solids, which of the following substances has the highest melting temperature? Group of answer choices O CH4 O H2O O Cl2 O SO2 O NaBr
NaBr has the highest melting temperature on the basis of bonding in liquids and solids .
Option E is correct .
Network covalent solids, including silicon dioxide, graphite, and diamond, have the greatest melting points. A massive covalent structure is held together by a large number of strong bonds. There are certain metals with the next-highest melting points, particularly transitional metals.
Bonds between atoms in covalent compounds share electrons. They have distinctive physical characteristics, such as lower melting temperatures and electrical conductivity compared to ionic compounds, since they share electrons. Ionic compounds have high melting and boiling temperatures because it takes a lot of energy to break the bonds between the many ions in the ionic lattice.
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1 Wire 1 Wire 2 Long, straight, parallel wires 1 and 2 carry current I in opposite directions, as shown. Which of the following correctly describes the magnetic fields from the wires in the region between the wires and provide evidence to support this claim? A The magnetic fields are in opposite directions, because the currents are in opposite directions. B) The magnetic fields are in opposite directions, because the region is on opposite sides of the wires: to the right of wire 1 and to the left of wire 2. C The magnetic fields are in the same directions, because both wires are long and straight. D The magnetic fields are in the same directions, because the currents have the same magnitude. E The magnetic fields are in the same directions, because the currents are in opposite directions and are on opposite sides of the wires: to the right of wire 1 and to the left of wire 2. < >
Based on the information provided, the statement that correctly describes the magnetic fields from the wires in the region between the wires and provide evidence to support this claim is that the magnetic fields are in opposite directions, because the region is on opposite sides of the wires: to the right of wire 1 and to the left of wire 2. (Option B)
A magnetic field refers to a vector field that defines the magnetic influence on moving electric charges, electric currents, and magnetic materials. A moving charge in a magnetic field experiences a force perpendicular to its own velocity and to the magnetic field. A current traveling through a loop of wire creates a magnetic field along the axis of the loop. The direction is obtained from the right-hand rule. Hence, the direction of the field inside the loop can be found by curling the fingers of the right hand in the direction of the current through the loop; the thumb then points in the direction of the magnetic field.
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if the angle between the horizontal and the direction of the 5.0 meters per second veolocity decreases from 30 degrees to 20 defrees the horitonztoal distancr the ball travelks will
The magnitude of the horizontal component of the ball's initial velocity is 4.7 m/s .
In the question ,
it is given that ,
the velocity of the ball is ⇒ 5 m/s .
the angle between horizontal and the direction of 5 m/s decreases from 30 degrees to 20 degrees .
Now , θ = 20° .
We know that ,the trigonometric ratio , Cos θ is = (Adjacent side)/(Hypotenuse)
given velocity = 5 m/s .
So , Cos(20°) = Vₓ/(5) ....Vₓ is the horizontal component .
Simplifying further ,
we get ,
Vₓ = 4.7 m/s .
Therefore , The magnitude of horizontal component is 4.7 m/s .
The given question is incomplete , the complete question is
The ball being kicked by a foot and rising at an angle of 30 degrees from the horizontal. The ball has a velocity of 5.0 meters per second. (Neglect Friction) If the angle between the horizontal and the direction of the 5.0 meters per second decreases from 30 degrees to 20 degrees,
What is the magnitude of the horizontal component of the ball's initial velocity ?
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FILL IN THE BLANK. while sitting at a desk, lisa talks on her cell phone. under these conditions, talking on a cell phone is a form of activity
Subcutaneous tissue fat functions similarly to insulation in your home in numerous areas of your body. This fat absorbs shock to underlying structures and aids in protecting the deep body systems like muscles and organs from temperature changes.
Which of the following causes a decrease in metabolism?
Crash dieting, starvation, or fasting all cause the body to reduce its metabolism in an effort to conserve energy. BMR can fall by up to 15%, and if lean muscle mass is lost as well, BMR is further decreased.
Which tissue serves as insulating material, a cushion of protection, and a source of energy?
The bottom layer of skin on your body is called the hypodermis. It has a variety of purposes, such as defending your body from injury, insulating your body, storing energy, and attaching your skin to your muscles and bones.
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the sun can fuse hydrogen for over ten billion years, while a star twice as massive runs out of hydrogen in
The sun can fuse hydrogen for over ten billion years, while a star twice as massive runs out of hydrogen in two billion years.
Given that they have more fuel than stars with smaller masses, you may assume that big stars would endure longer. However, the cores of these monsters burn through fuel more quickly because they are much hotter and fuse elements at far faster rates.
For more than 10 billion years, a star like a sun can happily burn hydrogen into helium. But in under two billion years, a star twice as massive as the sun exhausts its supply of hydrogen. In just a few hundred million years, a star eight times as massive as the Sun will run out of fuel. Additionally, the speed of each phase in the fusion process increases over time.
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when nellie newton dangles by a pair of ropes, each at different angle from the vertical, the rope tension will be greater in the rope having the ___
larger in a rope with a smaller angle.
When nellie newton dangles by a pair of ropes, each at different angle from the vertical, the rope tension will be greater in the rope having the larger in a rope with a smaller angle.
The pulling force transmitted axially by a string, rope, chain, or other similar object, or by each end of a rod, truss member, or other similar three-dimensional object is referred to as tension. The action-reaction pair of forces acting at each end of said elements can also be referred to as tension. The polar opposite of compression might be tension.
The ends of a string or other object that transmits tension will apply forces in the direction of the string at the point of attachment to the objects to which it is connected.
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Mass of a particle is 5 times its rest mass, calculate its velocity.
Two hockey pucks of equal mass approach each
other. Puck 1 has an initial velocity of 20.0 m/s [S
45° E], and puck 2 has an initial velocity of 15 m/s
[S 45° W]. After the collision, the first puck is
moving with a velocity of 10.0 m/s [S 45° W].
(a) Determine the final velocity of the second
puck.
(b) Is this collision elastic, perfectly inelastic, or
(non-perfectly) inelastic? Explain your reasoning.
The final velocity of the second puck will be 20.61 m/s [S 30.95 E] and the collision will be non-perfectly inelastic.
We know that since there is no external force applied to the system of two pucks, So after the collision, Momentum will remain conserved,
Using Momentum conservation in x-direction:
Px(initial) = Px(final)
[tex]m1*u1x + m2*u2x = m1*v1x + m2*v2x[/tex]
[tex]m1 = m2 = m[/tex] (given)
u1 = Initial speed of m1
= 20.0 m/s at S 45 E
= 20.0 m/s at 45 deg below the positive x-axis
u2 = Initial speed of m2
= 15.0 m/s at S 45 W
= 15.0 m/s at 45 deg below the negative x-axis
v1 = final speed of m1
= 10.0 m/s at S 45 W
= 10.0 m/s at 45 deg below the negative x-axis
u1x = Initial velocity of m1 in x-direction
= [tex]20.0*cos 45[/tex]°
= 14.14 m/s
u2x = Initial velocity of m2 in x-direction
= [tex]-15.0*cos 45[/tex]°
= -10.61 m/s
v1x = Final velocity of m1 in x-direction
= [tex]-10.0*cos 45[/tex]°
= -7.07 m/s
v2x = Final velocity of m2 in x-direction = ?
So,
[tex]m*14.14 + m*(-10.61) = m*(-7.07) + m*v2x[/tex]
[tex]v2x = 14.14 - 10.61 + 7.07[/tex]
[tex]v2x= 10.6 m/s[/tex]
Now Using Momentum conservation in the y-direction:
Px(initial) = Px(final)
[tex]m1*u1y + m2*u2y = m1*v1y + m2*v2y[/tex]
u1y = Initial velocity of m1 in y-direction
= [tex]-20.0*sin 45[/tex]°
= -14.14 m/s
u2y = Initial velocity of m2 in y-direction
= [tex]-15.0*sin 45[/tex]°
= -10.61 m/s
v1y = Final velocity of m1 in y-direction
= [tex]-10.0*sin 45[/tex]°
= -7.07 m/s
v2y = Final velocity of m2 in y-direction = ?
So,
[tex]m*(-14.14) + m*(-10.61) = m*(-7.07) + m*v2y[/tex]
[tex]v2y = -14.14 - 10.61 + 7.07[/tex]
[tex]v2y= -17.68 m/s[/tex]
So we have
v2x = 10.6 m/s and v2y = -17.68 m/s
the final speed of puck 2 will be:
[tex]|v2| = sqrt (10.6^2 + (-17.68)^2)[/tex]
[tex]|v2| = 20.61 m/s[/tex]
the final direction of puck 2 will be:[tex]Direction = arctan (\frac{v2y}{v2x} ) = arctan (\frac{-17.68}{10.6})[/tex]
Direction = 59.05 deg below positive x-axis (Since v2x > 0 and v2y < 0, So puck 2 will be moving in 4th quadrant)
Direction = 90 - 59.05
= 30.95 deg
= S 30.95 E
b) Since both pucks did not stick together after the collision, So this is not a perfectly inelastic collision
Now Using energy conservation:
[tex]KE = KEf - KEi[/tex]
[tex]KE = (\frac{1}{2})*m*v1^2 + (\frac{1}{2})*m*v2^2 - (\frac{1}{2})*m*u1^2 - (\frac{1}{2})*m*u2^2[/tex]
[tex]KE = (\frac{1}{2})*m*[10.0^2 + 20.6^2 - 20.0^2 - 15.0^2][/tex]
[tex]KE = -50.32*m[/tex]
So some amount of energy was lost during the collision, which means the above collision is (non-perfectly) inelastic
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a) The magnitude of the final velocity of the second puck is 20.61 m/s in the direction 50.3° east-south.
b) This collision is (non-perfectly) inelastic.
What is law of conservation of momentum?According to the rule of conservation of momentum, absent an external force, the combined momentum of two or more bodies operating upon one another in an isolated system remains constant. As a result, momentum cannot be gained or lost.
Let the final velocity of the second puck = v i + V j
Now, applying law of conservation of momentum along x axis:
m × 20.0 × cos45° + m × 10.0 ×(- cos45°) = m × 10 × ( - cos45°) + mv
⇒ v =10.6 m/s.
Applying law of conservation of momentum along y axis:
m × 20.0 × (-sin45°) + m × 10.0 ×(- sin45°) = m × 10 × ( - sin45°) + mV
⇒ V = - 17.68 m/s.
Hence, the final velocity of the second puck = 10.6 i - 17.8 j m/s.
The magnitude of the final velocity of the second puck
= √{(10.6)² + (-17.8)²} m/s
= 20.61 m/s.
and the direction is = tan⁻¹(-17.8/10.6) = - 59.22°
b) The amount of loss in kinetic energy = 1/2 × m ( 20.0² + 15.0² - 10.0² - 20.61²) joule
= 50.36m joule.
Hence, as loss of kinetic energy happens, this collision is (non-perfectly) inelastic.
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Suppose that in cases B, C, and D in problem 1, each combination of springs were replaced by a single spring such that the motion of the block is the same as before the replacement. We will call the spring constant of this new spring the effective spring constant of the original combination. Quantitatively, the effective spring constant, keff , may be defined by the relationship Sigma Fvector block, spring = -Keff , where Sigma block, spring is the sum of all forces on the block by the springs, and is the position of the block with respect to the equilibrium position. Rank the four cases according to keff, from largest to smallest. Explain. Use your ranking above and the relationship T = 2pi root m/keff to rank the cases according to period of oscillation. Explain. Use your ranking from part a and the relationship E total = 1/2 keffA2 to rank the cases according to total energy. Explain.
After solving the equation the cases according to total energy C<A<B= D
What is spring constant ?
A measure of the spring's stiffness is its spring constant, or k. Various springs and materials have different effects. The spring becomes stiffer and more challenging to extend the bigger the spring constant.
What is equilibrium ?
When all external forces (including moments) acting on an item are balanced, the object is said to be in equilibrium in a reference coordinate system. Thus, all external moments and forces acting on this item result in zero as a net effect.
Case A; k effective = K
Case B ; strings connected in parallel
K effective = 2A
Case c; strings connected in series
K effective = k/2
Case D ; strings connected in parallel
K effective = 2K
So, C,<A<B= D
T= 2π[tex]\sqrt{m/Keffective}[/tex]
T∝ [tex]\sqrt{1/K effective }[/tex]
Accordingly time period ranking is C>A>B= D
E total = 1/2 K effective a²
E total ∝ k effective
so ranking will be
C<A<B= D
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A jet of water squirts out horizontally from a hole near the bottom of the tank shown in the figure. If the hole has a diameter of 3.80 mm, what is the height h of the water level in the tank? cm L.00 mn Fu.guu m7
A jet of water squirts out horizontally from a hole near the bottom of the tank shown in the figure. If the hole has a diameter of 3.80 mm, the height h of the water level in the tank is 44.1 cm
The height of the water level can be calculate as follows:
According to kinematics, if the water's initial velocity when it exits the tank is, its horizontal range is given by
d = v√(2y/y)
where, y is the acceleration caused by gravity and is the vertical distance from the ground to the hole.
Torricelli's law provides the velocity of the fluid flowing out of the hole. the velocity of water coming out of the hole is
v=√(2gh)
where,h is the tank's top-to-bottom distance, as depicted in the picture.
The horizontal range equation is used to calculate the water's exit velocity from the hole:
d= v√(2y/g)
v= d x √(g/2y)
and since d= 0.600 m an y= 1 m
v= 0.600 x √(9.8/2(1))
v= 0.600 x 4.9
v= 2.94 m/s
Now, we can use Torricelli's theorem to find the height
v=√(2gh)
h = v²/2g
h = (2.94)² / 2 (9.8)
h = 0.441 m = 44.1 cm
Your question is incomplete because of missing picture but most probably your full question attached below
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"The glider is released at a distance 1.47m from the bottom of the track. Use the acceleration value you obtained in Part C to calculate the speed of the glider when it reaches the bottom of the track. "
(I found the acceleration to be 7.55 m/s-1, as shown in the above picture)
The speed of the glider when it reaches the bottom of the track is 4.71 m/s.
[tex]V^{2}[/tex] = μ² + 2as
μ = 0
ν = [tex]\sqrt{2as}[/tex] = √2 × 7.55 × 1.47 = 4.71 m/s
This glider can create lift equal to its weight and can soar into the air at any speed greater than 30 kts. If the aircraft is launched into the wind at, let's say, a surface wind speed of 10 kts, it just needs to travel 20 kts above the ground before taking off. A winch launch is one of the most popular ways of launch, accelerating a glider from zero to sixty miles per hour in less than two seconds using a very powerful winch and lengthy steel cables. Slowest - normally 25 to 60 km/h for recreational gliders (above 50 km/h necessitates use of a safety device), these steel lines (and the glider linked to them) represent a very serious risk to everyone on the grounds.
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two small speakers a and b are driven in step at 725 hz by the same audio oscillator. these speakers both start out 4.50 m from the listener, but speaker a is slowly moved away. (see (figure 1)).
Speakers both start out 4.50 m from the listener, but speaker a is slowly moved away.The first, constructive interference occurs when the path difference is lambda 0.47m.
A. Let us find the wavelength 1st
use:
v = f * lambda
344 = 725* lambda
lambda = 0.47 m
First destructive interference occurs when the path difference is lambda/2
path difference = d
d = lambda/2
d = 0.47/2
= 0.235 m
B. 2nd destructive interference occurs when the path difference is 3*lambda/2
path difference = d
d =3* lambda/2
d = 3* 0.47/2
= 0.705 m
C. first, constructive interference occurs when the path difference is lambda
path difference = d
d = lambda
d = 0.47 m
Wavelength is the distance between identical points in adjacent cycles of a waveform signal propagating in space or along a wire. In wireless systems, this length is usually expressed in meters, centimeters, or millimeters. Wavelength is the distance between two wave crests and the same for wave troughs.
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what is the maximum magnitude of p that can be applied before tipping would occur, assuming the block does not slip? express your answer to three significant figures with appropriate units. ptip
A probabilistic assessment of seismic hazards requires an estimate of the maximum moment intensity M of the largest earthquake that is likely to occur in a given region. The answer is in the image.
Maximum magnitude, an important parameter in calculating seismic hazards, is also a controversial parameter. The choice of value can have a large impact on the final outcome of the results, but it is most likely the magnitude of an earthquake that has not yet occurred in the area under study.
The term size is defined as the number of flocks. For example, the magnitude can be used to describe the speed comparison between a car and a bicycle. It can also be used to describe how far an object has moved or how much an object has in relation to size.
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A physics professor demonstrates the Doppler effect by tying a 450
Hz sound generator to a 1.0
−
m
-long rope and whirling it around her head in a horizontal circle at 100
rpm .
A. What is the difference between the highest frequency heard by a student in the classroom and the initial frequency of the sound generator? Express your answer with the appropriate units.
B. What is the difference between the lowest frequency heard by a student in the classroom and the initial frequency of the sound generator? Express your answer with the appropriate units.
The difference between the highest frequency heard by a student in the classroom and the initial frequency of the sound generator is =582.5 Hz and 619.2 Hz
briefly:-F(s) = 600 Hz, the generator's frequency
The rope's length is r = 1 m.
rotating frequency, w = 100 rpm
First, we determine the generator's speed, v (g)
v(g) = r.w
However, it should be remembered that we must convert the whirling speed from rpm to rad/s.
100 rpm is 100*2/60 rad/s.
100 rpm = 200π/60
100 rpm = 620.4 / 60
10.47 rad/s for 100 rpm.
Now, we employ this to determine the generator's speed.
v(g) = r.w
v(g) = 1 * 10.47
v(g) = 10.47 m/s
The frequency is estimated when approaching the generator as
F(a) = F(s) / [(v(g)/v) - 1)]
F(a) = 600 / [1 - (10.47/343)]
F(a) = 600 / 0.969
F(a) = 619.2 Hz
On the other hand, the frequency of the retreating generator is
F(r)=F(s)/[1 + (v(g)/v)]
F(r) = 600 / [1 + (10.47/343)]
F(r) = 600 / 1.030
F(r) = 582.5 Hz
The highest and lowest frequencies are therefore 619.2 Hz and 582.5 Hz, respectively.
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To avoid last-minute moves, you should be looking down the road to where your vehicle will be in about:
(a) 5 to 10 seconds.
(b) 10 to 15 seconds.
(c) 15 to 20 seconds.
Scrutinize the route 10-15 seconds in advance of your car to spot risks and prevent last-minute maneuvers. It's risky to stare at the car or the road just in front of yours all the time.
What controls the velocity of a vehicle?The ignition switch, brake pedal, or steering wheel are the three inputs on a car that can alter its speed. If either rate or location changes, velocity also does. The idea of acceleration describes how quickly the velocity varies.
What is an illustration of velocity?Velocity can be defined as the rate at which someone moves in a specific direction. as the pace of a car driving north on such a highway or the pace at which a rocket takes off. The location of the automobile is not shown by the speedometer. As a result, this instrument can only determine a vehicle's speed, not its velocity.
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a small em-wave source (i.e. a small collection of charges which is vibrating in simple harmonic motion having a known frequency) radiates an electromagnetic wave into the vacuum of space itself. of course, the electromagnetic wave consists of blocks of magnetic and electric fields which are leaving the vibrating source; these blocks of electric and magnetic fields leave the source in all possible directions (i.e. nothing has been done by the designers of the source to form the wave into a tight beam). as the wave moves away from the source, determine what happens to each of the following: a) the frequency of the electromagnetic wave o increases o decreases O remains constant (b) the intensity of the electromagnetic wave increases o decreases O remains constant Give your reasoning as briefly as possible
As the wave moves away from the source, the frequency of the wave (c) remains constant whereas the intensity of the wave (b) decreases.
Frequency stays same because frequency of EM wave does not depend on the distance from the source because waves cannot just disappear in free space.
So, frequency remains constant.
The intensity (I) of a wave is defined as the rate at which it transfers energy divided by the area over which the energy is spread. In other words, intensity is the rate of energy flow per unit area.
Intensity of EM wave is inversely proportional to the square of distance from source, as
I = P/A
So, intensity of wave decreases.
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Giraffe bending to drink. In a giraffe with its head 2.0m above its heart, and its heart 2.0m above its feet, the (hydrostatic) gauge pressure in the blood at its heart is 250torr.Assume that the giraffe stands upright and the blood density is . In torr (or mm Hg), find the (gauge) blood pressure (a) at the brain (the pressure is enough to perfuse the brain with blood, to keep the giraffe from fainting) and (b) at the feet (the pressure must be countered by tight-fitting skin acting like a pressure stocking). (c) If the giraffe were to lower its head to drink from a pond without splaying its legs and moving slowly, what would be the increase in the blood pressure in the brain? (Such action would probably be lethal.)
(a) The gauge pressure at the brain of the giraffe is 94 torr.
(b) The gauge pressure at the feet of the giraffe is 4.1×10² torr.
(c) The increase in the blood pressure in the brain as the giraffe lowers its head to the level of its feet is 3.1×10² torr.
We know that,
The blood column between the feet and the brain is where the hydrostatic blood pressure gauge is located.
(a) The gauge pressure at the brain of the giraffe is
P(brain) = P(heart) − ρgh
P(brain) = 250 torr − (1.06×10³ kg/m³)(98 m/s²)(2.0 m) (1 torr/133.33 Pa)
P(brain) = 94 torr.
Hence, The gauge pressure at the brain of the giraffe is 94 torr.
(b) The gauge pressure at the feet of the giraffe is
P(feet) = P(heart) + ρgh
P(feet) = 250 torr + (1.06×10³ kg/m³)(9.8 m/s²)(2.0 m) (1 torr/133.33 Pa)
P(feet) ≈ 4.1×10² torr.
Hence, The gauge pressure at the feet of the giraffe is 4.1×10² torr.
(c) The increase in the blood pressure in the brain as the giraffe lowers its head to the level of its feet is
△P = P(feet) − P(brain)
△P = 406 torr − 94 torr
△P = 312 torr ≈ 3.1×10² torr
Hence, The increase in the blood pressure in the brain as the giraffe lowers its head to the level of its feet is 3.1×10² torr.
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A boy is initially seated on the top of a hemispherical ice mound of radius R=13.8m. He begins to slide down the ice, with a negligible initial speed (Fig. 8-47). Approximate the ice as being frictionless. At what height does the boy lose contact with the ice?
The height of the boy above the bottom of the mound is 9.20m.
What is radius ?
The radius of a circle is the distance a circle's center from any point along its perimeter. Usually, "R" or "r" is used to indicate it.
What is speed ?
Speed is the rate of change in location of an item, expressed in metres per second. For instance, the speed of an item is one metre per second if it starts at the origin and goes three metres in three seconds. Speed is easily calculated by dividing a distance by a time.
Let FN be the normal force of the ice on him and m is his mass. The net inward force is mgcosθ−F N , and, according to Newton's second law, this must be equal to mv 2 /R, where v is the speed of the boy. At the point where the boy leaves the ice F N =0, so gcosθ=v 2 /R.. We wish to find his speed. If the gravitational potential energy is taken to be zero when he is at the top of the ice mound, then his potential energy at the time shown is
U=−mgR(1−cosθ).
He starts from rest and his kinetic energy at the time shown is 21 mv 2 . . Thus conservation of energy g 0= 21 mv 2 −mgR(1−cosθ)orv=2gR(1−cosθ).
We substitute this expression into the equation developed from the second law to obtain gcosθ=2g(1−cosθ). This gives cosθ=2/3.
The height of the boy above the bottom of the mound is
h=Rcosθ= 32R= 32(13.8m)=9.20m
Therefore, the height of the boy above the bottom of the mound is 9.20m.
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start with the smallest problem and progress to the most complex", is another of the rules of the Cartesian method, what rule is it?
Using theory on the Cartesian method, starting with the smallest problem and progressing to the most complex, refers to the rule known as synthesis.
¿What is the Cartesian method?This has been a method developed by René Descartes with which he sought to find what was the truth.
The method established by René Descartes contains four fundamental rules or principles that are:
Rule (Evidence)AnalysisSynthesisVerificationAmong all these rules, the synthesis is the one that indicates that you should start with the smallest problem and progress to the most complex.
1. Abus moves 2moveront and om east, 5 North and 3m South fay 5 second. calculate on) Total distance b) Tofal displosment c Averge speed d Average Velocity.
(a) The total distance of the bus is 10 m.
(b) The total displacement of the bus is 2.83 m.
(c) The average speed of the bus is 2 m/s.
(d) The average velocity of the bus is 0.57 m/s.
What is the total distance travelled by the bus?The total distance of the bus is the sum of all the distance covered by the bus and it is calculated as follows;
distance = 2 m + 5 m + 3 m = 10 m
The total displacement of the bus is calculated as follows;
resultant horizontal displacement = 2 m east
resultant vertical displacement = 5 m - 3 m = 2 m North
Total displacement = √ ( 2² + 2² )
Total displacement = 2.83 m
The average speed is calculated as;
average speed = 10 m / 5 s = 2 m/s
The average velocity is calculated as;
average velocity = 2.83 m / 5 s = 0.57 m/s
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