A bicycle tire is 28 inches in diameter how far does the bicycle move forward each time the wheel goes around use 22/7 as an approximately for π

A Bicycle Tire Is 28 Inches In Diameter How Far Does The Bicycle Move Forward Each Time The Wheel Goes

Answers

Answer 1

Answer:

88 inches

Step-by-step explanation:

Well the bike will travel the distance of the circumference of the tire.

Circumference is 2*pi*radius or pi*diameter since the diameter is twice the radius

I guess they want is to use 22/7 for pi, which is weird, but whatever.

C = pi*d

C = 22/7*28

This gets you [tex]C = \frac{616}{7}[/tex] or 88 inches


Related Questions

Suppose babies born after a gestation period of 32 to 35 weeks have a mean weight of 2500 grams and a standard deviation of 600 grams while babies born after a gestation period of 40 weeks have a mean weight of 2800 grams and a standard deviation of 415 grams. If a 34-week gestation period baby weighs 2875 grams and a 41-week gestation period baby weighs 3175 grams, find the corresponding z-scores. Which baby weighs more relative to the gestation period?
Find the corresponding z-scores. Which baby weighs relatively more? Select the correct choice below and fill in the answer boxes to complete your choice. (Round to two decimal places as needed.)

A. The baby born in week 34 weighs relatively more since its z-score ____, is smaller than the z-score of ____ for the baby born in week 41
B. The baby born in week 41 weighs relatively more since its z-score ____, is smaller than the z-score of ____ for the baby born in week 34
C. The baby born in week 34 weighs relatively more since its z-score ____, is larger than the z-score of for ____ the baby born in week 41 for the baby born in week 34
D. The baby born in week 41 weighs relatively more since its z-score ____, is larger than the z-score of ____ for the baby born in week 34

Answers

The corresponding z-scores for the given observations can be calculated using the formula:

[tex]\[z = \frac{{x - \mu}}{{\sigma}}\][/tex]

where [tex]\(x\)[/tex] is the observation, [tex]\(\mu\)[/tex] is the mean, and [tex]\(\sigma\)[/tex] is the standard deviation.

For the baby born in week 34 weighing 2875 grams:

[tex]\[z_{34} = \frac{{2875 - 2500}}{{600}} = 0.625\][/tex]

For the baby born in week 41 weighing 3175 grams:

[tex]\[z_{41} = \frac{{3175 - 2800}}{{415}} = 0.904\][/tex]

To determine which baby weighs more relative to the gestation period, we compare the z-scores.

A. The baby born in week 34 weighs relatively more since its z-score 0.625 is smaller than the z-score 0.904 for the baby born in week 41.

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Question Help
One taco supreme and two pan pizzas provide 3200 calories. Two taco supremes and one pan pizza
provide 3280 calories. Find the caloric content of each item.

Answers

Answer:

4324eqW

Step-by-step explanation:

3 + 5 =7

What should be done to both sides of the equation in order to solve y - 4.5 = 12.2?

Answers

Add 4.5

---

hope it helps

Answer: add 4.5 to both sides

Step-by-step explanation: this will allow the 4.5 to be removed from the y side and since you added it to one side you have to add it to the other side. This will give your y the value of 16.7.

Brainliest plz

Ajjwjjwjwjwjsbsbaa shah sash’s

Answers

Answer:

okay then

Step-by-step explanation:

Answer: gtyrehretr

Step-by-step explanation:

Translate into an equation: Twenty-six more than the product of a number and
17 is -42.

Answers

C) 17n + 26 = -42

“the product of a number and 17” = 17n

“twenty six more than” = + 26

And if the next question has you solve it:
17n + 26 = -42
Subtract 26 from both sides
17n = -68
Divide both sides by 17
n = -4

Please answer no links!!!!!!!!!!!

Answers

Answer:

2 (4, 14)3 (3, 5)
The answer for number 1 is 2- (4,14) and I believe the answer for 2 is (3,5) (I may be mistaken on that one since I didn’t graph it.

Suppose there is a family with four children. Assume that it is equally probable for a boy or a girl to be born. a. What is the probability of all girls? b. What is the probability of all girls given there is at west one girl? c. What is the probability of at least one boy and one girl?

Answers

a. The probability of all girls in a family with four children is 1/16 or 0.0625.

b. The probability of all girls given there is at least one girl is 1/15 or 0.0667.

c. The probability of having at least one boy and one girl in a family with four children is 15/16 or 0.9375.

a. To calculate the probability of all girls, we need to consider the possible outcomes of each child being a girl. Since each child has an independent probability of being a girl or a boy, the probability of all girls is (1/2) * (1/2) * (1/2) * (1/2) = 1/16 or 0.0625.

b. Given that there is at least one girl, we have three remaining children. The probability of all girls among the three remaining children is (1/2) * (1/2) * (1/2) = 1/8. Therefore, the probability of all girls given there is at least one girl is 1/8 divided by the probability of having at least one girl, which is 1 - (1/2)⁴ = 15/16, resulting in a probability of 1/15 or approximately 0.0667.

c. The probability of having at least one boy and one girl can be calculated by subtracting the probability of having all boys from the total probability space. The probability of having all boys is (1/2)⁴ = 1/16. Therefore, the probability of having at least one boy and one girl is 1 - 1/16 = 15/16 or approximately 0.9375. This probability accounts for all possible combinations of boys and girls in a family with four children, excluding the scenario of having all boys.

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A fair die is tossed twice and let X1 and X2 denote the scores obtained for the two tosses, respectively

Calculate E[X1] and show that var (X1) =
Determine and tabulate the probability distribution of Y = | X1 – X2 | and show that E[Y] =
The random variable Z is defined by Z = X1 – X2. Comment with reasons (quantities concerned need not be evaluated) if each of the following statements is true or false
E(Z2) = E(Y2)
Var(Z) = Var(Y)

Answers

1. When a fair die is tossed the expected value E[X1] = 3.5 and the variance var(X1) = 35/12.

When a fair die is tossed, each of the six possible outcomes has an equal probability of 1/6. Let X1 denote the score obtained in the first toss.

To calculate the expected value E[X1], we find the sum of all possible values of X1 multiplied by their respective probabilities:

E[X1] = (1 * 1/6) + (2 * 1/6) + (3 * 1/6) + (4 * 1/6) + (5 * 1/6) + (6 * 1/6) = 3.5

To calculate the variance var(X1), we use the formula:

var(X1) = E[X1^2] - (E[X1])^2

First, we find E[X1^2] by taking the sum of the squares of all possible values of X1 multiplied by their respective probabilities:

E[X1^2] = (1^2 * 1/6) + (2^2 * 1/6) + (3^2 * 1/6) + (4^2 * 1/6) + (5^2 * 1/6) + (6^2 * 1/6) = 91/6

Substituting the values into the formula, we calculate var(X1):

var(X1) = (91/6) - (3.5)^2 = 35/12

Therefore, E[X1] = 3.5 and var(X1) = 35/12.

2. The probability distribution of Y = |X1 - X2| is tabulated as follows:

Y |X1 - X2| P(Y)

0 0 1/6

1 1 2/6

2 2 2/6

3 3 1/6

To calculate E[Y], we find the sum of all possible values of Y multiplied by their respective probabilities:

E[Y] = (0 * 1/6) + (1 * 2/6) + (2 * 2/6) + (3 * 1/6) = 1

Therefore, E[Y] = 1.

3. The statements E(Z^2) = E(Y^2) and Var(Z) = Var(Y) are false.

E(Z^2) and E(Y^2) represent the expected values of the squares of the random variables Z and Y, respectively. Since Z = X1 - X2 and Y = |X1 - X2|, the squares of Z and Y have different probability distributions, leading to different expected values.

Similarly, Var(Z) and Var(Y) represent the variances of Z and Y, respectively. Since Z and Y have different probability distributions, their variances will generally not be equal.

Therefore, E(Z^2) ≠ E(Y^2) and Var(Z) ≠ Var(Y).

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can someone plz help me wit dis plz​

Answers

divide the area by the number in the triangle

Answer:

b = 6.1 ft

Step-by-step explanation:

The area (A) of a triangle is calculated as

A = [tex]\frac{1}{2}[/tex] bh ( b is the base and h the perpendicular height )

Here A = 10.98 and h = 3.6 , then

[tex]\frac{1}{2}[/tex] × b × 3.6 = 10.98

1.8b = 10.98 ( divide both sides by 1.8 )

b = 6.1

calculate the solubility (in g/l) of caso4(s) in 0.250 m na2so4(aq) at 25°c . the sp of caso4 is 4.93×10−5 .

Answers

The given values are: Ksp of CaSO4 = 4.93 × 10⁻⁵, Molarity of Na2SO4 = 0.250(m). Molar mass of CaSO4 = 136.14 g/mol. We can write the equation for the dissolution of CaSO4 in water as:CaSO4(s) ⇌ Ca²⁺(aq) + SO₄²⁻(aq). Let's consider that "x" grams of CaSO4 dissolves in "1 L" of 0.250 M Na2SO4. Since the CaSO4 dissolves according to the following equation:CaSO4(s) ⇌ Ca²⁺(aq) + SO₄²⁻(aq). The concentration of Ca²⁺ ions in the solution will be "x" moles / 1 L. The concentration of SO₄²⁻ ions in the solution will be "x" moles / 1 L. Since the concentration of Na2SO4 in the solution is 0.250 M or 0.250 moles / L, the concentration of SO₄²⁻ ions contributed by Na2SO4 will be (2 × 0.250) M or 0.500 M. In order to determine the value of "x" or the amount of CaSO4 that dissolves, we need to consider the equilibrium of the solution. The Ksp expression for the dissolution of CaSO4 can be written as: Ksp = [Ca²⁺][SO₄²⁻], Ksp = (x)(x) = x². As the dissociation is very small compared to the concentration of Na2SO4, we can consider "0.250" moles of Na2SO4 in "1 L" of the solution completely dissociated. Thus, the final concentrations of Ca²⁺ and SO₄²⁻ ions in the solution will be:[Ca²⁺] = x moles / L[SO₄²⁻] = (x + 0.500) moles /L. Therefore, we can write the expression for the ion product: IP = [Ca²⁺][SO₄²⁻]IP = (x)(x + 0.500)As the value of Ksp is equal to the IP, we can write the expression for Ksp as: Ksp = x² + 0.500xWe can substitute the value of Ksp as 4.93 × 10⁻⁵M:4.93 × 10⁻⁵ = x² + 0.500x. Solving for "x", we get the following quadratic equation: x² + 0.500x - 4.93 × 10⁻⁵ = 0. Solving for "x" using the quadratic formula: x = 0.00796 g/L. Therefore, the solubility of CaSO4(s) in 0.250 M Na2SO4 solution at 25°C is 0.00796 g/L.

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need help imm struggling ​

Answers

Answer:

1733.33

Step-by-step explanation:

The volume of a pyramid is (length*width*height) divided by 3

Answer:

1733.33

Step-by-step explanation:

v = (lwh)/3

v = (20 x 20 x 13)/3 = 5200/3 = 1733.33

Work out the size of angle x.
42°
Х
123°

Answers

Answer:

42+123+x=180

x=180-165

x=15 degrees

Step-by-step explanation:

Sails come in many shapes and sizes. The sail on the right is a triangle. Is it a right triangle? Explain your reasoning.

Answers

Answer:

not a right triangle

Step-by-step explanation:

you can use the pythagorean theorem to prove whether not this is a right triangle

if this triangle is a right triangle then the following equality should be true

a²+b²=c²

(9.75)²+(3.45)²=(10.24)²

(95.06)+(11.90)=(104.86)

106.96≠104.86

since the following equality is not true, this is not a right triangle.

P(x) = x2 + x +1
How many terms does this polynomial have?

Answers

Answer:

3

Step-by-step explanation:

Essie has two identical containers she fell one with milk and the other with water if the first container holds about 10 L of milk how much does the second container holds

Answers

Answer:

10 liters of water

Step-by-step explanation:

Given

[tex]A = 10L\ milk[/tex]

Required

How much the second holds

Since they are both identical, then both containers hold the same volume (even if the quantity they hold are different)

Hence:

[tex]B = 10L\ water[/tex]

Mia is working two summer jobs, making $11 per hour babysitting and making $20 per hour lifeguarding. In a given week, she can work a maximum of 15 total hours and must earn no less than $220. If x represents the number of hours babysitting and y represents the number of hours lifeguarding, write and solve a system of inequalities graphically and determine one possible solution.

Answers

Answer: 11x + 20y ≥ 220

x + y ≤ 15

Hope this helps

9514 1404 393

Answer:

x + y ≤ 1511x +20y ≥ 2203 hours babysitting and 11 hours lifeguarding

Step-by-step explanation:

The two inequalities represent the two relations described in the problem statement.

  x + y ≤ 15 . . . . . . . Mia works a maximum of 15 hours

  11x + 20y ≥ 220 . . . . Mia makes at least $220

These are graphed in the attachment. The solution area is the doubly-shaded area with vertices at (9, 6), (0, 11) and (0, 15). One possible solution is shown at (3, 11), which represents ...

  3 hours babysitting

  11 hours lifeguarding . . . . . . . . total 14 hours for $253


What is the solution to the equation below?
4x+8 = 2(x - 4)
A x = -5
B x = 6
Cx = -8
D x = -4

Answers

Answer:

C

Step-by-step explanation:

4x +8 = 2x -8

4x = 2x - 16

2x = -16

x = -8

Donna bought 5 bags of dog treats for $13.10. What is the cost per bag of dog treats?
A. $18.10
B.$3.28
C.$2.62
D.$0.38

Answers

It is answer C because 13.10 divided by 5 is 2.62 Pls mark brainliest

CAN SOMEONE HELP ME PLEASE

Answers

Answer: 9 x 6 x 6

Step-by-step explanation: 9 x 6=54  54 x 6 = 324 ft

Tim is making 30 sundaes with mint, chocolate, and vanilla ice cream.
1/5
of the sundaes are mint ice cream and
1/2
of the remaining sundaes are chocolate. The rest will be vanilla. How many sundaes will be vanilla?

Answers

12 sundaes will be vanilla can i please have brainliest

Answer:

12

Step-by-step explanation:

1/5 mint = 6

30 - 6 = 24

Half of 24 is 12

12 is chocolate

so 12 must be vanilla

a bag contains 15 red marbles, 15 white beads, 20 green beads, and 25 blue beads. What is the probability of randomly drawing a blue bead?

Answers

Answer:

1/3 or 33%

Step-by-step explanation:

15 + 15 + 20 +25 is equal to 75

25/75 is 1/3

Answer:

1 by 3

Step-by-step explanation:

15 + 15 + 20 + 25 = 75

so,

again,

25 divided by 75 is equal to 1 by 3

Jasmine has $50 and saves $4.38 every month. Radha has $0 and saves $5.38 every month. Jasmine's savings after x months can be represented by the function f (x) = 4.38 x + 50. Radha's savings after x months can be represented by the function g (x) = 5.38 x. Round your answer to the nearest hundredth.

After how many months will they both have the same amount in savings? Find the values of x for which f (x) = g (x).

After ____ months, Jasmine and Radha will have the same amount in savings.​

Answers

After 50 months, jasmine and Radha will have the same amount in savings

the school choir has 110 members there are 20 more girls than boys there are how many boys the choir

Answers

Answer:

65 girls and 45 boys

Step-by-step explanation:

Assuming the sample was taken from a normal population, test at ů. = 0.05 and state the decision. Họ: H = 13 HA: U < 13 ř= 10 S= 0.7 n = 9

Answers

the test statistic (t = -12.857) is smaller than the critical value (-1.860), we have enough evidence to reject the null hypothesis.

To test the hypothesis regarding the population mean, we can perform a one-sample t-test.

Given:

- Null hypothesis (H₀): μ = 13

- Alternative hypothesis (Hₐ): μ < 13

- Sample mean ([tex]\bar{X}[/tex]) = 10

- Sample standard deviation (s) = 0.7

- Sample size (n) = 9

- Significance level (α) = 0.05

To conduct the t-test, we can calculate the test statistic and compare it with the critical value from the t-distribution.

The test statistic (t-score) is calculated as:

t = ([tex]\bar{X}[/tex] - μ) / (s / √n)

Plugging in the values:

t = (10 - 13) / (0.7 / √9)

t = -3 / (0.7 / 3)

t = -3 / 0.233

t ≈ -12.857

To determine the critical value, we need to find the appropriate degrees of freedom (df) for a one-sample t-test. In this case, df = n - 1 = 9 - 1 = 8.

Using a significance level of α = 0.05 and looking up the critical value for df = 8 in the t-distribution table, we find the critical value to be approximately -1.860.

Since the test statistic (t = -12.857) is smaller than the critical value (-1.860), we have enough evidence to reject the null hypothesis.

Decision: Based on the test results, at α = 0.05, we reject the null hypothesis (H₀: μ = 13). There is sufficient evidence to support the alternative hypothesis (Hₐ: μ < 13), suggesting that the population mean is less than 13.

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Given question is incomplete, the complete question is below

Assuming the sample was taken from a normal population, test at α = 0.05 and state the decision. Họ: μ = 13 HA: μ < 13 [tex]\bar{X}[/tex]= 10 s= 0.7 n = 9

I need a little more help. Sorry for the spam questions.

Answers

perimeter is 28 and area is 32

A pump fills a pool at a constant rate. At the end of 1 minute it has filled 6 gallons of water. Which table represents the relationship between the number of minutes and the number of gallons of water in the pool?​

Answers

Answer:

I would need to see the different tables to answer this question.

Given f(x)= 5 (6) x for rexeh 1 o elsewhere for a continuous veidon variable z. (a) Compute p(2.4 x <3). (6) Compite Elx)

Answers

a.  the value of P(2.4 < x < 3) is 8.1.

b. the value of E(X) is 10.

Given function is f(x) = 5(6)x for x≥1 and elsewhere for a continuous random variable z.  

a. Compute P(2.4 < x < 3)

For continuous random variable, P(a < x < b) = ∫f(x)dx, where f(x) is the probability density function (PDF).

Here, f(x) = 5(6)x for x≥1 and elsewhere

So, P(2.4 < x < 3) = ∫f(x)dx = ∫2.4^35(6)xdx= 5 ∫2.4^36xdx= 5 [(3^2 - 2.4^2)/2] = 5 [(9 - 5.76)/2] = 5 [1.62] = 8.1

Hence, the value of P(2.4 < x < 3) is 8.1.

b. Compute E(X)Expected value of X is given by E(X) = ∫xf(x)dxFor continuous random variable, E(X) = ∫xf(x)dx, where f(x) is the probability density function (PDF).Here, f(x) = 5(6)x for x≥1 and elsewhereSo, E(X) = ∫xf(x)dx = ∫1∞5(6)x.xdx+ ∫-∞0 0dx= 5 ∫1∞6x^2dx+ 0 = 5 [(6) (x^3)/3]1∞= 5 [(6) (1^3)/3] = 10

Hence, the value of E(X) is 10.

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Given f(x)= 5 (6) x for rexeh 1 o elsewhere for a continuous veidon variable z. We are required to compute p(2.4 < x <3) and E(x).

Compute p(2.4 < x <3)For the given function, f(x) = 5 (6) x for 1 ≤ x ≤ 3 and 0 elsewhere.

So, the total area under the curve will be equal to 5 (6) 2 = 60.

And the required probability is given by the area under the curve from 2.4 to 3.  [Illustration is provided below]

Hence, p(2.4 < x <3) = 3.6

(b)Compute E(x)Expected value of x, E(x) is given by E(x) = ∫xf(x) dx,

which is equal to the area under the curve multiplied by the distance over which the function is spread.

Let's calculate the area under the curve, which is equal to 60, as we have calculated earlier.

Now, we calculate the distance over which the function is spread.

Distance = 3 - 1 = 2 unitsHence, E(x) = 60/2 = 30.

Answer:Therefore, p(2.4 < x <3) = 3.6 and E(x) = 30.

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2. A cow gives 24litre milk each day. If the milkman sells 75% of the milk, how many
liters of milk is left with him?​

Answers

Answer: 6 liters

Step-by-step explanation:

24 liters

He sells 75%

24 x 0.75 = 18 liters

24 - 18 = 6

He still has 6 liters left

Oatmeal is packaged in a right circular cylindrical container that has a radius of 7 centimeters and a height of 16 centimeters.



What is the surface area of this container in terms of pi?

a. 176
b. 254
c. 322
d. 440

Answers

Answer:

c. 322

Step-by-step explanation:

Surface area of cylinder = 2πr² + 2πrh.

SA in terms of π = π(2r² + 2rh) →

π(2(7)² + 2(7)(16)) →

π(2(49) + 2(112)) → π(98 + 224) → π(322)

8. Which equation is true for all x- and y- values in the table below?

x y
1 7
2 14
3 21
4 28
(1 point)
y = x + 7
y = x – 7
y = x over seven
y = 7x

Answers

Answer:

y = 7x

Step-by-step explanation:

you mutiply 7 times 1=7

you just continue to do that

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Use the double exponential smoothing procedure to find forecasts for the next two time periods.Use = 0.7 and = 0.3. The current stock price of IBM is $70. A put option on IBM with an exercise price of $66 sells for $7 and expires in 6 month(s). If the risk-free rate is 1.3% per year, what is the price of a call option on IBM with the same exercise price and expiration date (keep two decimal places)? Question 8 Betty DeRose, Inc. operates two departments, the handling department and the packaging department. During April, the handling department reported the following information: work in process, April 1 units started during April work in process, April 30 units 27,000 51,000 32,000 work in process, April 1 costs added during April total costs % complete DM 60% DM $ 67,330 $277,070 $344,400 75% The cost of beginning work in process and the costs added during April were as follows: % complete conversion 25% Conversion $141,120 $257,520 $398,640 45% Total cost $208,450 $534,590 $743,040 Calculate the cost of goods completed and transferred out during April using the FIFO process costing method. how many grams of dextrose are in 300 ml of a 5 5w solution? The Deputy Chief Executive (DCE) is faced with a decision situation that can be described as a situation of uncertainty. Which Decision-making model will be used in this decision situation? DO "O supply 4. Short-run equilibrium and long-run aggregate supply The following graph shows several aggregate demand and aggregate supply curves for an economy whose potential output is $5 trilion. Suppose L = 3, and consider the demand function x(p, w) defined byX1(P, w)=(P2 P1+P2 +P3)(w P)X2(p,w)=( P3P+ P2+ P3)(w P2)X3(p, w) = (p1p1+p2+p3) (wp3)Does this demand function satisfy homogeneity of degree zero and Walras' law when = 1? What about when (0,1)? what is the meaning of folks b) Nusantara Spa needs to borrow approximately RM150,000 for a 6 months. The bank offers the company a choice of the following three (3) types of loan. i) Loan with simple interest rate of 7 percent with compensating balance of 15 percent of the amount loaned. (3 marks) ii) A discounted loan at a stated interest of 6.5 percent and 20 percent compensating balance. (3 marks) iii) A revolving line of credit of RM250,000 for a 1 percent commitment fee payable on advance on the unused funds and a 12 percent stated interest rate. (3 marks) iv) Justify which alternative should the company choose. (1 mark) Quinlan-Cohen, Inc., publishers of movie and song trivia books, made the following errors in adjusting the accounts at year-end (December 31):Did not accrue $2,000 owed to the company by another company renting part of the building as a storage facility.Did not record $15,200 depreciation on the equipment costing $109,000.Failed to adjust the Unearned Fee Revenue account to reflect that $1,300 was earned by the end of the year.Recorded a full year of accrued interest expense on a $22,800, 10 percent note payable that has been outstanding only since November 1.Failed to adjust Prepaid Insurance to reflect that $700 of insurance coverage had been used. Exon Company purchased equipment for $240,000 on January 1, 2018. The equipment has an estimated residual value of $20,000 and an estimated useful life of 10 years. The company depreciates the equipment using the double declining balance method. On January 1, 2021, the company determines that the total useful life is 8 years and the estimated residual value is $3,000. Required: 1. The equipment's book value at January 1, 2021 is $ ... . Round your final answer to the nearest dollar. 2. The annual depreciation expense for 2021 is $ ... . Round your final answer to the nearest dollar. assuming the temperature of the air in her lungs is constant, to what volume must her lungs expand when she reaches the surface of the water? Media for marketing (Turkey)a. Agency assistanceb. Coverage of various media Write a C++ program to choose one of the following two options for your summer vacation. Your options are:HawaiiBahamasCancunYour program should select one of the above options using ifelifelse statements and Menu.Once an option is selected, your program should select one of the following two options using.ifelse ifelse ifelse statement and Menu for airline company.US AirDeltaUnited How is income recognized in cash basis accounting?How are dividends taxed?Your friend John files his own tax returns. He received a computer as a dividend from a closely held corporation. He says that he does not need to report the computer as dividend income because the dividend was not paid in cash. Is he right? if a population's growth rate decreases as the population size approaches carrying capacity, the population's growth follows a(n) ________ model. Machine breakdown and repair in a twelve machine factory having three repair mechanics would develop which type of queuing system line structure concerning machine breakdowns?A) Machine breakdown and repair in a twelve machine factory having three repair mechanics would develop which type of queuing system line structure concerning machine breakdowns?B) Machine breakdown and repair in a twelve machine factory having three repair mechanics would develop which type of queuing system line structure concerning machine breakdowns?C) Multichannel, single phaseD) Multichannel, multiphaseE) None of the above oberon, inc. has a $20 million (face value) 10-year bond issue selling for 97 percent of par that pays an annual coupon of 8.25 percent. what would be oberons before-tax component cost of debt? which of the following statements is false concerning the board member and her hidden agenda?a. She was a rogue board member in every sense of the word with a personal agenda that only became clear at a later point in time.b. Her personality overpowered some board members and caused dissension among the others. c. She had strategically placed the past board member, who turned out to have an ongoing personal relationship with her, internally to sabotage the current operations of the organization and discredit the CEO. d. She then planned to promote herself into the CEO position, thus replacing the job from which she was about to retire.