A beaker is filled to the 500 ml mark with alcohol. What increase in volume (in ml) the beaker contain when the temperature changes from 5°C to 30°C? (Neglect the expansion of the beaker, evaporation of alcohol and absorption of water vapor by alcohol.) C°, Palcohol = 1.12 x 104/ °C

Answers

Answer 1

Answer:

1.4 mL

Explanation:

Given that:

volume of alcohol [tex]V_0[/tex] = 500

Temperature change ΔT = (30° - 5°)C

=25° C

[tex]\beta_{ alcohol }= 1.12 \times 10^{-4} / ^0C[/tex]

The increase in volume ΔV =  [tex]\alpha \times V_o \times \Delta T[/tex]

[tex]= 500 \times 1.12 \times 10^{-4} / ^0 C\times 25^0 C[/tex]

= 1.4 mL


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Explanation:

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True or false It is legal to pass in Florida when approaching within 100 feet of or traversing any railroad crossing grade croead

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That is a false statement.

Complete the sentence to identify a useful advance in the culinary arts.

The Egyptians invented

, which they used to store

for many years.

Answers

Answer:

silos to store grains

Explanation:

I got it from PLATO... hope this helps...

A broad range of subjects are included in the culinary arts. Food science and nutrition, ingredient quality, seasonality, flavors and textures, presentation and plate layout, and more are some of these. There are numerous specialties, sub-niches, and job titles that fall within this broad category.

What are the characteristics of culinary arts?

Additionally, to help students become more well-rounded cooks, a variety of cooking techniques, numerous recipes, new ingredients, and various flavor profiles are presented to them.

The term “culinary arts” is used to refer broadly to the processes involved in preparing, cooking, plating, presenting, and serving food. It relates to meals and the goods, not sweets or breads. That make up a meal, such as appetizers, side dishes, and main courses.

Therefore, Students who pursue a culinary education have the opportunity to study under several of the industry's best chefs.

Learn more about art here:

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how to update android 4.4.2 to 5.1 if there isnt any update available​

Answers

Answer:

You cant update it if there isin´t any update available lol

Explanation:

Well simply you can’t the problem is likely to be that the phone is to old !

When block C is in position xC = 0.8 m, its speed is 1.5 m/s to the right. Find the velocity of block A at this instant. Note that the rope runs around the pulley B and a pin attached to block C, as indicated.

Answers

Answer:

The answer is "2 m/s".

Explanation:

The triangle from of the right angle:

[tex]\to (x_c-0.8)+(1.5+y_4) +\sqrt{x_c^2 + 1.5^2}= constant[/tex]

Differentiating the above equation:

[tex]\to V_c +V_A+ \frac{X_cV_c}{\sqrt{x_c^2 +1}}=0\\\\\to 1-V_A+ \frac{0.8 \times 1.5}{\sqrt{ 0.8^2+1.5}}=0\\\\[/tex]

[tex]\to V_A= \frac{1.2}{\sqrt{ 0.64+1.5}}+1\\\\[/tex]

        [tex]= \frac{1.2}{ 1.46}+1\\\\= \frac{1.2+ 1.46}{ 1.46}\\\\ = \frac{2.66}{1.46}\\\\= 1.82 \ \frac{m}{s}\\\\= 2 \ \frac{m}{s}[/tex]

definition of ceramics

Answers

Answer:

Ceramics are generally made by taking mixtures of clay, earthen elements, powders, and water and shaping them into desired forms. Once the ceramic has been shaped, it is fired in a high temperature oven known as a kiln. Often, ceramics are covered in decorative, waterproof, paint-like substances known as glazes.

Explanation:

Answer:

made essentially from a nonmetallic mineral (such as clay) by firing at a high temperature.

Explanation:

what is 2+2 equal to

Answers

the answer is 4, lol.

Answer:

4

or

22

Explanation:

The hydrofoil boat has an A-36 steel propeller shaft that is 100 ft long. It is connected to an in-line diesel engine that delivers a maximum power of 2490 hp and causes the shaft to

Answers

The question is incomplete. The complete question is :

The hydrofoil boat has an A-36 steel propeller shaft that is 100 ft long. It is connected to an in-line diesel engine that delivers a maximum power of 2590 hp and causes the shaft to rotate at 1700 rpm . If the outer diameter of the shaft is 8 in. and the wall thickness is [tex]$\frac{3}{8}$[/tex]  in.

A) Determine the maximum shear stress developed in the shaft.

[tex]$\tau_{max}$[/tex] = ?

B) Also, what is the "wind up," or angle of twist in the shaft at full power?

[tex]$ \phi $[/tex] = ?

Solution :

Given :

Angular speed, ω = 1700 rpm

                              [tex]$ = 1700 \frac{\text{rev}}{\text{min}}\left(\frac{2 \pi \text{ rad}}{\text{rev}}\right) \frac{1 \text{ min}}{60 \ \text{s}}$[/tex]

                              [tex]$= 56.67 \pi \text{ rad/s}$[/tex]

Power [tex]$= 2590 \text{ hp} \left( \frac{550 \text{ ft. lb/s}}{1 \text{ hp}}\right)$[/tex]

          = 1424500 ft. lb/s

Torque, [tex]$T = \frac{P}{\omega}$[/tex]

                 [tex]$=\frac{1424500}{56.67 \pi}$[/tex]

                 = 8001.27 lb.ft

A). Therefore, maximum shear stress is given by :

Applying the torsion formula

[tex]$\tau_{max} = \frac{T_c}{J}$[/tex]

        [tex]$=\frac{8001.27 \times 12 \times 4}{\frac{\pi}{2}\left(4^2 - 3.625^4 \right)}$[/tex]

      = 2.93 ksi

B). Angle of twist :

     [tex]$\phi = \frac{TL}{JG}$[/tex]

         [tex]$=\frac{8001.27 \times 12 \times 100 \times 12}{\frac{\pi}{2}\left(4^4 - 3.625^4\right) \times 11 \times 10^3}$[/tex]

         = 0.08002 rad

         = 4.58°

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