A basketball has a mass of 1 kg and is traveling 12 m/s.

What would happen to the velocity if the momentum of the basketball were cut in half?

Answer:

[tex]6\:\mathrm{m/s}[/tex] (The velocity would also be halved)

Step-by-step explanation:

The momentum of an object is given as [tex]p=mv[/tex] where [tex]m[/tex] is the mass of the object and [tex]v[/tex] is the velocity of the object.

Because mass is constant, if the momentum ([tex]p[/tex]) was cut in half, the velocity of the basketball would also be halved:

Let [tex]p_1[/tex] be the initial momentum and [tex]p_2[/tex] be the final momentum:

[tex]\frac{1}{2}p_1=p_2,\\\frac{1}{2}mv_1=mv_2, \\\fbox{$\frac{1}{2}v_1=v_2$}[/tex]

Therefore, the basketball's new velocity is [tex]\frac{1}{2}\cdot 12=\fbox{$6\:\mathrm{m/s}$}[/tex].

is 6,12,18,24,30 proportional

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