Answer:
1.45 N
Explanation:
Newton's Second Law: F=ma
Convert 145 grams to kilograms
0.145kg*10m/s^2
1.45 N
What is leadership? Why is leadership important in the health sciences? First to answer brainliest
the action of leading a group of people or an organizaton, leadership is important during sciences because, if someone doesn’t know what to do you can lead them in the right way
Explanation:
Answer:
Within healthcare, skilled leaders motivate staff to work at their highest potential to benefit patients, their colleagues, and the organization as a whole.
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Imagine that you are comparing three different ways of having a ball move down through the same height. In which case does the ball reach the bottom with the highest speed?.
We can observe that the ball reaches the bottom with the highest speed when the ball is dropped.
What occurs when a ball is dropped?As you drop the ball, gravity pulls it downward and accelerates it.It squashes as soon as it collides with the earth at impact.The crushed ball pushes against the floor, which pushes back as the ball assumes its original shape.The power of the floor pressing against the ball causes it to rebound back into the air.When you drop a ball, where does the energy go?If you drop the basketball, gravity will pull it down and, as it does so, transform its potential energy into kinetic energy.The potential energy of the ball decreases as it gets closer to the earth.However, the ball also accelerates upward, increasing its kinetic energy.To learn more about dropping a ball visit:
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what is true about current that flows through resistors in parallel? all current flows through the lowest value resistor(s). all current flows through the highest value resistor(s). the current is determined by v
A resistor is a passive two-terminal electrical component used in circuits to implement electrical resistance. Resistor use in electronic circuits includes lowering current flow, adjusting signal levels, dividing voltages, influencing active devices, and terminating transmission lines.
The voltage drop across a resistor increases with resistor size and consumes more energy as a result. Voltage drop can be confirmed using Ohm's Law. Voltage in a DC circuit is equal to current times resistance.
V = I R.
Resistors are said to as being in parallel when two nodes share terminal connections. The lowest parallel resistor is larger than the comparable overall resistance.
The supply current is equal to the total of the currents flowing through all of the resistors when they are linked in parallel. The supply current is equal to the sum of the currents in a parallel circuit's branches. The potential difference across parallel connections of resistors is the same.
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Marina is trying to pay more attention to her health, and she has been monitoring her heart rate using a fitness tracker. Yesterday, she got into her first-choice college. When she checked her tracker, she noticed that her heart rate was higher for most of the afternoon. What BEST explains this?
A. Strong emotions can impact the heart rate. B. She probably exercised and forgot about it.
C. If she was sitting most of the afternoon, it would be high.
D. Heart rates are unpredictable and don't generally follow patterns.
A. "Strong emotions can impact the heart rate."
An elevated heart rate, or tachycardia, can occur for any reason.
Exercise-induced or stress-related heart rate increases are two possible causes (sinus tachycardia).
Sinus tachycardia is not seen as an illness but rather a symptom.
Another factor contributing to tachycardia is an unsteady heartbeat (arrhythmia).
Heart problems and stress
Adrenaline and cortisol are two of these hormones. They get your body ready to handle stress. To help move blood to the body's center, they make your heart beat more quickly and your blood arteries shrink. Your blood pressure and blood sugar levels are also elevated by the hormones.
Heart palpitations and anxiousness are common side effects. The autonomic nervous system's "fight or flight" reaction is triggered by anxiety (ANS). Your ANS engages when you feel concerned about a circumstance, raising your heart rate.
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Consider a 0. 5-kg meter stick with a 1. 0 kg mass attached at the 50 cm mark and a 3. 0 kg mass at the very end. Where on the meter stick is the center of mass located?.
The meter stick is the center of mass of the three mass system is at 83cm.
What is center of mass?The center of mass is a location determined in respect to an object or group of things. It represents the average location of the system, weighted by the mass of each component.
Briefing:The center of mass of the three mass system is at 83cm
The mass of the meter stick is:
M = 0.5kg.
Since the meter stick is uniform, the center of mass of the meter stick is at 50cm or 0.5m.
Let the distance of the meter stick's center of mass from 0cm be x1. Then x1 = 0.5m.
Now a mass m2 = 1kg is attached at 50cm mark.
So the distance of m2 from 0cm is x2 = 50cm = 0.5m.
Similarly a mass m3 = 3kg is attached at the every end or 100cm mark. So the distance of m3 from 0cm is x3 = 100cm = 1m.
Now the position of the three mass system from 0cm is given by,
[tex]$X_{C M}=\frac{M x_1+m_2 x_2+m_3 x_3}{M+m_2+m_3}$[/tex]
[tex]$X_{C M}=\frac{0.5 \times 0.5+1 \times 0.5+3 \times 1}{0.5+1+3}$[/tex]
[tex]$X_{C M}$[/tex] = 3.75/4.5 =0.83 = 83cm
So the center of mass of the three mass system is at 83cm.
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DeWayne meets a potential employer at a restaurant, who gives him a phone number. Because he doesn't have anything to write with, he repeats the number several times to himself as a way of remembering the phone number. He is not very likely to remember this phone number later in the evening because of this strategy. True False
Based on the fact that he didn't write the number down, the statement "He is not very likely to remember this phone number later in the evening because of this strategy. " is True
This is further explained below.
What is DeWayne's strategy?Generally, While DeWayne's strategy is eating at a restaurant, he meets a potential employer who provides him with his phone number.
Because he does not have anything with which to write, he must recite the telephone number to himself many times in order to commit it to memory.
In conclusion, It is quite improbable that he will remember this phone number later on in the evening if you use this strategy.
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A stone is thrown off a cliff with a horizontal speed of 15 m/s.
If the stone’s final vertical speed is 40 m/s, how tall was the cliff?
How long is the stone in the air for?
How far from the base of the cliff does the stone hit the ground?
What is the stone’s horizontal speed right before it hits the ground?
The height of the cliff is 81.63 m.
The time spent by the stone in air is 4.08 seconds.
The horizontal distance travelled by the stone is 61.2 m.
The stone’s horizontal speed right before it hits the ground is 15 m/s.
What is the height of the cliff?
The height of the cliff is calculated as follows;
v² = u² + 2gh
where;
v is the final vertical velocity of the stone = 40 m/su is the initial vertical velocity of the stone = 0h is the vertical height of the stoneg is acceleration due to gravityv² = 0 + 2gh
h = v²/2g
h = (40²) / (2 x 9.8)
h = 81.63 m
The time of motion of the stone is calculated as follows;
h = ut + ¹/₂gt²
where;
u is initial vertical velocity = 0t is time of motion of the stoneh = 0 + ¹/₂gt²
t = √(2h/g)
t = √(2 x 81.63 / 9.8)
t = 4.08 seconds
The horizontal distance travelled by the stone is calculated as follows;
X = Vₓt
where;
Vₓ is initial horizontal velocityX = (15) x (4.08)
X = 61.2 m
During the horizontal motion of a projectile, the horizontal speed is constant. That is the final horizontal speed is equal to initial horizontal speed.
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URGENT!! ILL GIVE
BRAINLIEST! AND 100 POINTS
Does the equation below follow the Law of Conservation of Matter?
Answer:
4th one
i wont let me write less than 20 letters so ignore this line
two iceboats, one of mass m and the other of mass 2m, are racing on a frictionless horizontal frozen pond. both iceboats start from rest at the starting line, and the wind applies the same constant force to both iceboats.
When both boats have the same kinetic energy and are traveling at the same speed, the iceboat reaches the finish line first.
Since the kinetic energy saved will be the same for both icebergs in this situation,
This: F *x
F is equal to force due to the wind.
where x is the same for the two icebergs as the distance to the goal. Consequently, even if the velocities may differ, the kinetic energy in the end will be the same.
The square speed of the heavier boat must be equal to the square speed of the lighter boat for the kinetic relation to hold true, and both boats will reach the finish line with the same kinetic energy.
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7. If a graph is showing a positive slope, and the graph itself is a straight line, what must be the x and y axis if the straight
line is showing a constant acceleration?
An object has positive acceleration if it is accelerating and travelling in the right direction.
What does it signify if a position time graph has a straight line with a positive slope? A straight line with a positive slope will appear on the Position vs. Time graph of an item travelling forward at a constant speed. It shows that the object's velocity is constant and that it is travelling ahead.The y-axis of this sort of graph denotes position in relation to the starting point, while the x-axis denotes time. An object's distance from its beginning position at any given moment since it began moving is displayed on a position-time graph.In a distance-time graph, the object's speed is equal to the slope or gradient of the line. The line becomes steeper as the thing goes more quickly (and the greater the gradient).The starting point of the item is indicated by the y-intercept. An object's y-intercept is zero if it begins at the measuring instrument. Its y-intercept is 3 meters if it begins at a distance of 3 meters. When two items are in the same position, you may tell by where two lines intersect.To Learn more About Positive acceleration, Refer:
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while running a marathon, a long-distance runner uses a stopwatch to time herself over a distance of 100 m. she finds that she runs this distance in 21 s. answer the following by considering ratios, without computing her velocity.
The time is defined as Delta X, or 1600 meters, because the speed is 5.55 meters per second. 288 seconds have now elapsed.
In this activity, we'll discuss uniform motion with constant speed. Keep in mind that the velocity is the same as the delta X. This is the distance divided by the time component, Delta T. And what we have is a runner who completes a 100-meter run in 18 seconds.
As a result, our objective is to assume that they want to maintain the same speed as she did in the first 100 meters and in question A. We must ascertain the runner's time requirement as well. We have traveled 400 meters. So let's figure out the speed first. The runner's speed v.
The attacks are comparable to this. The body is 100 m without a T, there are no taxes, and tea is served in 18 seconds. We therefore equal 72. I apologize. Yes, to reach a speed of 5.56 m/s.
That's not to imply that the T is prime. What we are trying to determine is what is equivalent to Delta X Prime divided by V. This distance, 400 meters, is calculated by dividing it by the assumed speed of 5.56 meters per second, which is the same as before. So, 72 seconds passed. Any inquiries? I have to wait to see how long the runner needs. True on, say, one mile away. Recall that 1600 meters make up one mile.
Since the speed is 5.55 meters per second, the time is defined as Delta X, or 1600 meters. So, 288 seconds have passed. You finish their exercise, I see.
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Answer:t = 1603/(100/21)
= 337.89 sec
Explanation:
t1 = 21 sec, x1=100m
speed= x/t1 = 100/21
x2= 300 m.
t2= x2/(x1/t)
=300/(100/21)
=63 sec
1 mile = 1603 m
t = 1603/(100/21)
= 337.89 sec
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a ball is being twirled in a circle at the end of a string. the string provides the centripetal force needed to keep the ball moving in the circle at a constant speed. does the force exerted by the string on the ball do work on the ball in this situation? explain.
The force exerted by the string on the ball does not do work on the ball if a ball is twirled in a circle at the end of a string.
W = F d cos θ
F = Force
d = Displacement
θ = Angle between applied force and displacement
If the string provides centripetal force, the force is acting towards the end of string that is constant. The direction is always tangential to the circular motion.
θ = 90°
W = 0
The work done is maximum when the force vector and displacement act in the same direction. Because if they both act in same direction, θ = 0° and W = F d cos 0° = F * d
Therefore, the force exerted by the string on the ball does not do work on the ball in this situation.
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the star arcturus is a red giant that is easily visible in the night sky. based on models of stellar evolution, what is happening to arcturus as this stage of its life?
Answer: it’s increasing in size and hydrogen fusion reactions are occurring in a shell around the core
The size of Arcturus is expanding, and its core is undergoing hydrogen fusion processes.
What is meant by red giant ?After a star exhausts its hydrogen fuel for nuclear fusion and starts to die, a red giant develops.
Here,
The brightest star in the constellation Boötes (the herdsman), Arcturus is a red giant star in the Northern Hemisphere of the Earth's sky. One of the brightest stars that can be seen from Earth is Arcturus.
At the conclusion of its existence, Arcturus will become a white dwarf, according to astronomers.
However, Arcturus is cooler than the sun, therefore a large portion of the red giant star's energy is released as heat. Arcturus really emits 215 times more heat than the sun does when this is taken into consideration.
The star is nearing the end of its existence. Arcturus, a red giant that has stopped fusing hydrogen in its core like the sun does, is now thought to be fusing heavier elements like carbon, according to astronomers.
Hence,
The size of Arcturus is expanding, and its core is undergoing hydrogen fusion processes.
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Mary pushes a crate by applying force of 18 newtons. unable to push it alone, she gets help from her friend, anne. together they apply a force of 43 newtons, and the crate just starts moving. if the coefficient of static friction is 0.11, what is the value of the normal force? a. 2.0 × 102 newtons b. 2.6 × 102 newtons c. 3.9 × 102 newtons d. 4.0 × 102 newtons e. 4.3 × 102 newtons
The value of the normal force is 3.9x10^2
Using the formula for friction,
Ff = UsN
Where
Us is the coefficient of static friction.
N is the normal force.
To get the crate moving, enough force must be applied to overcome the static friction:
Fapplied = Ff
Since Fapplied = 43 Newtons:
43 = UsN
Us = 0.11, so all you have to do is isolate N by dividing both sides by 0.11
43/0.11 = N = 390.9 which is approximately 391 = 3.9x10^2
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Answer:
See image
Explanation:
Plato
Calculate the energy possessed by a bullet of mass 10 Kg moving at a velocity of 25m/s.
125 J the kinetic energy possessed by a bullet of mass 10 Kg moving at a velocity of 25m/s.
What are some examples of kinetic energy?Kinetic energy, which may be seen in the motion of an object, particle, or group of particles, is the electricity of motion. Any moving item uses kinetic energy, such as a person who walks, a baseball being thrown, a piece of food falling from a table, or a charged particle inside an electric field.
What makes kinetic energy so important?The capacity to perform work is unquestionably the most important characteristic of kinetic energy. Force acting on to an object while it is moving is referred to as work. Energy and work are convertible because of their tight relationship.
Briefing:The kinetic energy of a body is
K.E. = 1/2 mv²
K.E. = 1/2 ×10 ×25
K.E. = 125 J
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a receiver in a football game is standing still, having just caught a pass. before he can move, a tackler, running at a velocity of 4.4 m/s, grabs him. the tackler holds onto the receiver, and the two move off together with a velocity of 3 m/s. the mass of the tackler is 120 kg. assuming that momentum is conserved, find the mass of the receiver.
115 kilos are given to us as m r, so m r equals m t. T is stated as 115 kilos when T is 4.5 meters per second divided by the combined velocity, which is 2.6 meters per second. This now weighs 84.04 kilos. As a result, the receiver's mass, m r, is determined to be 84 kilograms.
We are provided the tackler's mass, m, which is 120 kilos. A tackle moves at a speed of 4.4 meters per second. The combined velocity of the tackler and the receiver, designated as b r, is now given as 0 meters per second.
Let's say it's indicated as 3 m/sec since, based on the principle of momentum conservation, we know that the system's initial and end linear moments should be equal. The initial momentum is now m r v, r plus m t v, t equals m r plus m t, which is the combined mass into v, and this term now goes to zero since we are as zero, which is the initial velocity of the receiver. This phrase ends at 0. Now that t = m r + m t into v, we obtain m t v.
Now, if we rearrange this, we obtain m r = m t v, t by v, and m t less. Sorry, minus m t, so m r equals m t v, t by v minus m t, and now enter all the given values into v. For example, 115 kilos are given to us as m r, so m r equals m t. T is stated as 115 kilos when T is 4.5 meters per second divided by the combined velocity, which is 2.6 meters per second. This now weighs 84.04 kilos. As a result, the receiver's mass, m r, is determined to be 84 kilograms.
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Which planet's orbit was Kepler first studying when he began to develop his laws of orbital motion? A Earth B Mars C Saturn D Jupiter
The planet orbit Kepler was studying when he developed the law of orbital motion is Mars.
What is law of orbital motion?
Kepler’s law of orbital motion are three laws and can be stated as follows;
All planets move about the Sun in elliptical orbits, having the Sun as one of the foci. A radius vector joining any planet to the Sun sweeps out equal areas in equal lengths of time. The squares of the sidereal periods of revolution of the planets are directly proportional to the cubes of their mean distances from the Sun.The first and second Kepler's law of orbital motion was proposed when Kepler discovered that the orbit of Mars was an ellipse.
Thus, the planet's orbit that Kepler was first studying when he began to develop his laws of orbital motion is Mars.
The correction that describes the planets orbit Kepler was studying is Mars.
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Which part(s) of the electromagnetic spectrum are able to be seen by the human eye? question 2 options: radio waves microwaves infrared waves visible light ultraviolet rays x-rays gamma rays
Visible light is known as the fragment which is the part of electromagnetic spectrum that can be seen by humans.
The wavelength and frequency of light that is visible are 400nm to 700nm and 400THz to 800THz respectively. As we know, living beings are blind to a number of wavelengths of light, but it can be detected by specific instruments. But we can perceive easily that our world is aligned around this light.
For example, the sun is natural visible light. Everything around us that we’re able to see is a reflection of sunlight falling off the objects. Colour of any object that we’re able to see is actually just a reflection of light and other than that, all other colours get absorbed.
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5) A rocket accelerates straight up from the ground at 22m / (s ^ 2) After rising for 5.0 s a piece of the rocket breaks of and falls back to earth. How fast does the piece hit the ground?
The final velocity of the rocket when it hits the ground is 71 m/s.
What is the final speed of the rocket?The final speed of the rocket will help us to determine how fast it is falling when it hits the ground.
Apply the following kinematic equation to determine the final velocity of the rocket
v = u + gt
where;
v is the final velocity of the rocketu is the initial velocity of the rocketg is acceleration due to gravityt is time of motionv = 22 m/s + (9.8 m/s²) x (5 s)
v = 22 m/s + 49 m/s
v = 71 m/s
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difference between friction and collision
Friction frequently has no immediate relevance. Perpendicular interactions are collisions. One parallel force is friction.
Consider a billiard ball colliding with another ball on a pool table. Although the billiard ball may enter at an angle, the momentum transfer occurs perpendicular to the contact plane.
Does collision cause friction?The internal force (of the collision) is often larger than the exterior force (friction) on a system when there is a collision within that system.
Two objects meet in an elastic collision when no kinetic energy is wasted. The kinetic momentum and energy of the objects are preserved when they bounce back from one another. We are dealing with an impactor because inelastic collisions are thought to happen when the two items stay together after the impact.
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Is there static friction on anything that is not moving?
Or, is there static friction present ONLY when there is something trying to get something else to move, but it not moving?
The friction force is static since there is no relative motion between the shoe and the ground. The friction force, if any, is the static force of friction if there is no relative motion between the objects in contact (FS). An illustration would be a box that sits motionless on a ramp.
What is static friction?A force that holds an object at rest is called static friction. The following is a definition of static friction:
the resistance people feel when they try to move something that is stationary on a surface without actually moving their bodies or the surface they are trying to move it on.
It can be explained as the frictional force that perfectly balances the applied force throughout the body's stationary state.
The static frictional force is self-regulating, meaning that it will always be equal to and the opposite of the applied force.
Friction is the force that prevents an object from moving in the direction it is sliding along a surface, therefore it acts in the opposite direction. But a friction force can be felt even when an object is not moving.
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suppose that you are climbing a hill whose shape is given by , and that you are at the point in which direction should you proceed initially in order to reach the top of the hill fastest?
If you walk due south from (60,40,966), we will ascend at the rate of 0.8. The location of something in relation to another is referred to as its direction.
To create the resulting vector, two vectors facing the opposite direction are subtracted from one another. Here, the vector B runs counterclockwise to the vector A, and the resulting vector R is
Consider,
z=1000−0.005x2−0.01y2∇f(x,y)
=⟨fx,fy⟩fx
=∂/∂x(1000−0.005x2−0.01y2)
=−0.01xfx
=∂/∂y(1000−0.005x2−0.01y2)
=−0.02y
Therefore,
∇f(x,y)
=⟨−0.01x,−0.02y⟩
At (60,40),∇f(60,40)
=⟨−0.01(60),−0.02(40)
=⟨−0.6,−0.8⟩
If you walk due south, the unit vector in the direction is
u=−j or ⟨1,−1⟩
Du(60,80)
=∇f(60,40)⋅⟨1, −1⟩
=⟨−0.6,−0.8⟩.⟨1,−1⟩=0.8
Therefore, if you walk due south from (60,40,966), we will ascend at the rate of0.8
The complete question is- Suppose that you are climbing a hill whose shape is given by z=934−0.06x2−0.1y2, and that you are at the point (80,50,300) In which direction (unit vector) should you proceed initially in order to reach the top of the hill fastest?
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Which variable is the Dependent Variable in that situation?
How do you know it's the Dependent Variable?
Answer: The time it takes for the cart to roll down the ramp is dependent on the height of the ramp. This makes the time dependent on the height.
53-20 you normally drive on the freeway between san diego and irvine at an average speed of 105 km/h, and the trip takes 2 h and 20 min. on a friday afternoon, however, heavy traffic slows you down and you drive the same distance at an average speed of only 74.0 km/h .
Assuming that average speed are in kilo-metres per hour, the typical trip takes 2 hours and 20 minutes to complete.
Apply the following formula to this issue:
Total distance travelled minus total time taken equals average speed.
You must first determine the length of the trip travelled.
Total distance travelled minus total time taken equals average speed.
Therefore : d = average speed x time spent overall - rearranging
In other words, d = vt = 105 km/hr x 2.3333... hrs = 245 km
Find out how long the typical journey takes on Friday afternoon.
t = d/v - equation rearranged equals 245 km/67 km/h = 3.6567164.
18 hours equals 3 hours, 39 minutes (rounded to nearest whole minute)
You must now determine how much longer the Friday trip takes.
Duration: (3 hours and 39 minutes) - (2 hours and 20 minutes)
= 1 hour and 19 minutes
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The data below were collected by scientists testing the force of gravity between two objects.
Distance Mass 1 Mass 2 Force
(kg) (kg)
(m)
(N)
0.10
100
150
0.00010
0.10
150
150
0.00015
0.10
100
300
0.00020
0.10
200
200
0.00027
0.10
200
300 0.00040
4
What do the data in the table support?
OA. The force of gravity between two objects is determined by the object with less mass.
OB. The force of gravity depends on the masses of the objects interacting.
OC. The force of gravity between two objects is determined by the object with more mass.
The force of gravity only depends on the distance between the objects interacting.
OD.
The force of gravity depends on the messes of the object's interaction.
A data table is a document consisting of columns rows and cells that contain specific values. They store information that users can later retrieve and update as needed. Data table titles, column headings, and row headings help users more clearly understand the information in the table.
Data tables display information in a grid-like format of rows and columns. They organize information in ways that are easy to scan and allow users to search for patterns and extract insights from data. A data table can contain Interactive components. The table can be read from left to right or top to bottom. When reading the table across the lines, read the information from left to right.
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a carnot engine has an efficiency of 22.0%. it operates between constant-temperature reservoirs differing in temperature by 75.0 degrees celsius. what is the temperature of the (a) lower temperature and (b) higher temperature reservoir?
The temperature of the lower-temperature reservoir in the Carnot engine is 266 K, while the temperature of the higher-temperature reservoir is 341 K.
This is basically a two unknowns problem. If we mark the temperature of the higher-temperature reservoir as H (for hot) and the temperature of the lower-temperature reservoir as C (for cold), we know the following:
H - C = 75.0 °C = 75 K,
and the efficiency of Carnot engine is calculated in the following manner:
0.22 = 1 - C/H ⇒ C/H = 1 - 0.22 = 0.78 ⇒ C = 0.78H
Now we use that in the first equation:
H - 0.78H = 75.0 K = 0.22H ⇒ H = 75.0 K / 0.22 = 341 K
C = 0.78H = 0.78 * 341 K = 266 K
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Please help will give brainiest.
Answer:
Potential Energy.
Explanation:
Kinetic Energy is when an object is moving and it's the speed when it's released but Potential Energy is when the object is stand still/at rest, like the arrow, as the archer holds the arrow back.
fred moves past alice at a constant speed c and alice notes that fred's clock is running at a rate eight-elevenths that of her clock. what is fred's speed (in terms of c) relative to alice?
Fred's speed as relative to alice is V = 0.6873c.
Speed is defined as the distance covered in a unit of time. It is the rate of a moving object. The scalar quantity, or speed, is the size of the velocity vector. There is no direction to speed. When an object moves more slowly, it is thought to be traveling at a lower speed; when it moves more quickly, it is thought to be traveling at a higher speed.
Explanation
The formula below mentions the traditional way to determine an object's constant velocity while it is traveling straight.
r = d / t
where r stands for rate or speed (sometimes denoted as v, for velocity)
The distance traveled is d.
The motion's execution time is measured in t.
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a rock is thrown off a cliff with a initial velocity of 5 m/s in the horizontal direction. if the rock takes 5 seconds to hit the ground, how far does the rock go horizontally? How high is the cliff?
The rock will travel 25m horizontally with an initial velocity of 5m/s.
The height of the cliff is 125 meters.
Let 'x' be the horizontal distance travelled by the rock when thrown from the cliff.
Vₕ = horizontal velocity of the rock
T = total time of flight of the rock
Therefore, we know x = Vₕ × T
x = 5 × 5
x = 25
So, the horizontal distance travelled by the rock is 25 meters.
Now to find the height of the cliff, we can use one of the equations of motion,
H = uT+ ½gt²
Therefore equating all the given values in the above equation;
H = 0 + ½gt² (since u=0, initial vertical speed)
H = ½×10×(5)²
H = 5 × 25
H = 125m
So, the height of the cliff is 125 meters.
Learn more about projectile motion in a horizontal direction here:
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Which element does NOT have similar chemical properties to neon (Ne)
A. F
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