Answers
Answer:
Approximately [tex]3.5\; \rm kN[/tex] in each of the two ropes.
Explanation:
Let [tex]F_1[/tex] and [tex]F_2[/tex] denote the tension in each of the two ropes.
Refer to the diagram attached. The tension force in each rope may be decomposed in two directions that are normal to one another.
The first direction is parallel to resultant force on the barge.
The component of [tex]F_1[/tex] in that direction would be [tex]\displaystyle F_1\cdot \cos(45^\circ) = \frac{F_1}{\sqrt{2}}[/tex].Similarly, the component of [tex]F_2[/tex] in that direction would be [tex]\displaystyle F_2\cdot \cos(45^\circ) = \frac{F_2}{\sqrt{2}}[/tex].These two components would be in the same direction. The resultant force in that direction would be the sum of these two components: [tex]\displaystyle \frac{F_1 + F_2}{\sqrt{2}}[/tex]. That force should be equal to [tex]5\; \rm kN[/tex].
The second direction is perpendicular to the resultant force on the barge.
The component of [tex]F_1[/tex] in that direction would be [tex]\displaystyle F_1\cdot \sin(45^\circ) = \frac{F_1}{\sqrt{2}}[/tex].Similarly, the component of [tex]F_2[/tex] in that direction would be [tex]\displaystyle F_2\cdot \sin(45^\circ) = \frac{F_2}{\sqrt{2}}[/tex].These two components would be in opposite directions. The resultant force in that direction would be the difference of these two components: [tex]\displaystyle \frac{F_1 - F_2}{\sqrt{2}}[/tex]. However, the net force on the barge is normal to this direction. Therefore, the resultant force should be equal to zero.
That gives a system of two equations and two unknowns:
[tex]\displaystyle \frac{F_1 + F_2}{\sqrt{2}} = 5\; \rm kN[/tex], and[tex]\displaystyle \frac{F_1 - F_2}{\sqrt{2}} = 0[/tex].The second equation suggests that [tex]F_1 = F_2[/tex]. Hence, replace the [tex]F_2[/tex] in the first equation with [tex]F_1[/tex] and solve for [tex]F_1\![/tex]:
[tex]F_1 = \displaystyle \frac{5\; \rm kN}{2\, \sqrt{2}} \approx 3.5\; \rm kN[/tex].
Because [tex]F_1 = F_2[/tex] (as seen in the second equation,) [tex]F_2 = F_1 \approx 3.5\; \rm kN[/tex].
In other words, the tension in each of the two ropes is approximately [tex]3.5\; \rm kN[/tex].
The tension in each of the rope is 3,535.5 N
The given expression:
the resultant force, R = 5 kN = 5000 N
the angle in between the forces, α = 45
To find:
the tension in each of the ropesThe tension in each of the ropes is calculated as follows;
The tension in vertical direction
[tex]F_y = F \times sin(\alpha)\\\\F_y = 5000 \times sin(45)\\\\F_y = 5000 \times 0.7071\\\\F_y = 3,535.5 \ N[/tex]
The tension in horizontal direction;
[tex]F_x = F \times cos(\alpha)\\\\F_x = 5000 \times cos(45)\\\\F_x = 5000 \times 0.7071\\\\F_x = 3,535.5 \ N[/tex]
Thus, the tension in each of the rope is 3,535.5 N
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Answer:
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I'm gonna give you more than 4 So u can choose.
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A person weighs 780N on earth. What is his mass on earth, mass on moon? What is his weight on the moon?
Answers
Answer:
79.6kg
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Explanation:
Given parameters:
Weight of the person on earth = 780N
Now, we are to find;
Mass on earth;
Mass on moon;
Weight on moon
Solution:
The mass on earth and on the moon are the same. Mass is the amount of matter in a substance.
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780 = mass x 9.8
mass = [tex]\frac{780}{9.8}[/tex] = 79.6kg
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Answers
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?
_2. Region surrounding the nucleus where electrons are found.
?
_3. Positively charged center of an atom.
?
4. Particles that differ in number between isotopes.
Answers
Answer:
Electron shell
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Neutrons
Explanation:
An atom is made up of three fundamental subatomic particles which are the protons, neutrons and electrons.
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A. 330 N
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Answers
Answer is 3,300N
Explanation
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Answer:
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If the speed of a roller coaster at the bottom of a hill is 20.0 m/s , what is the tallest hill the coaster can climb, assuming no friction losses ?
Answers
Answer:
20.4 meters
Explanation:
KE = 1/2 m v^2 = mgh = PE (convert all kinetic energy to potential energy, because at the highest point the coaster can climb, it will be stopped!)
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Given that the velocity of the roller coaster at the bottom of the hill is 20.0 m/s, potential energy is converted into kinetic energy.
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A small truck has a mass of 2085 kg. How much work is required to decrease the speed of the vehicle from 22.0 m/s to 13.0 m/s on a level road?
Answers
Answer:
Work required is 328387.5 Joules.
Explanation:
Given the following data;
Mass = 2085kg
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Final velocity, Vf =22m/s
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We know that from the workdone theorem, the workdone by an object or a body is directly proportional to the kinetic energy possessed by the object due to its motion.
Mathematically, it is given by the equation;
W = Kf - Ki
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W is the work required.
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Ki is the initial kinetic energy possessed by the object.
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Answers
Answer:
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Explanation:
Given parameters:
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Unknown:
Mass of the rock = ?
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According to newton's second law of motion;
Force = mass x acceleration
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Answers
Answer:
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Answers
Answer:
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Answer:
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Answer:
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Answers
Answer:
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If the speed is tripled, what happens to its centripetal force?
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Answers
Answer:
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Answers
Answer:
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Explanation:
A P E X
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Answers
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Answers
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Answers
Answer:
Higher
Lesser
Lesser
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Explanation:
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ryanzl6659
14 hours ago
Physics
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Read each scenario below. Then select the answer choices that complete the sentences,
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More
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i got all correct
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Answer:
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Explanation:
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Answers
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Answers
Answer:
A
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Answers
Answer:
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If the mass increases, it's harder to accelerate
Because force tends to rise with mass while mass tends to decrease with force, mass is sometimes referred to as the difficulty of accelerating an item. As a result, the greater mass's inverse effect balances out the larger force exerted on more massive objects.
Newton's second law agreement with difficulty of acceleration of an object-While acceleration tends to decrease as mass increases, it tends to increase as force increases. As a result, the bigger force acting on more massive objects is balanced off by the greater mass's inverse effect.As a result, all things fall in free fall at the same rate of acceleration regardless of mass. As the mass increases, accelerating becomes more difficult.Newton's second law of motion is applicable when there are unbalanced forces acting on an object.The second law states that an object's rate of acceleration depends on both its mass and the net force acting on it.An object's acceleration is directly proportional to the net force applied on it and inversely proportional to its mass.An object's acceleration increases as the amount of force exerted on it does.A decreasing acceleration is caused by a rise in an object's mass.The acceleration of an item caused by a net force is inversely proportional to the mass of the object and directly proportional to the magnitude of the net force in the same direction.To learn more about Newton's second law of motion click here-
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A crane lifts a 425 kg steel beam vertically upward a distance of 614.4 m
How much work does the crane do on the beam if the beam accelerates upward at 1.8 m/s2? Neglect frictional forces.
Answers
PHYSICS
*not sure about the answer but here we go*
Mass = 425 kg
distance = 614.4 m
acceleration = 1.8 m/s²
Answer :
Count Force first.
[tex]f \: = m \: \times a[/tex]
F = 425 × 1,8
F = 765 N ✅
Now let's count Work.
[tex]w \: = \: f \: \times s[/tex]
W = 765 × 614.4
W = 470016 J ✅