Answer:
[tex]V=2.8534m/s \approx 3m/s[/tex]
Explanation:
From the question we are told that
Acceleration [tex]a=0.460m/s[/tex]
Distance traveled [tex]S_1=8.5m[/tex]
Distance traveled [tex]S_2=15.6m[/tex]
Generally the velocity of the ball at the bottom of the first plane V is mathematically given by
[tex]v^2=2as[/tex]
[tex]v=\sqrt{2as}[/tex]
[tex]V=\sqrt{2*0.460*8.85}[/tex]
[tex]V=2.8534m/s \approx 3m/s[/tex]
An 8.00 kg mass moving east at 15.4 m/s on a frictionless horizontal surface collides with a 10.0 kg object that is initially at rest. After the collision, the 8.00 kg object moves south at 3.90 m/s. (a) What is the velocity of the 10.0 kg object after the collision
Answer:
9.3m/s
Explanation:
Based on the law of conservation of momentum
Sum of momentum before collision = sum of momentum after collision
m1u1 +m2u2 = m1v1+m2v2
m1 = 8kg
u1 = 15.4m/s
m2 = 10kg
u2 = 0m/s(at rest)
v1 = 3.9m/s
Required
v2.
Substitute
8(15.4)+10(0) = 8(3.9)+10v2
123.2=31.2+10v2
123.2-31.2 = 10v2
92 = 10v2
v2 = 92/10
v2 = 9.2m/s
Hence the velocity of the 10.0 kg object after the collision is 9.2m/s
Janice has just measured the density of an object. Which value is possible? (Density: D = )
Explanation:
Density is an intensive property of matter.
It is the mass per unit volume of a substance and it is expressed mathematically below:
Density = [tex]\frac{mass}{volume}[/tex]
Mass is the amount of matter present within a substance
Volume is the space a substance occupies
So, density is directly proportional to the mass of a body and inversely related to the volume it occupies.
The packing of a substance is very important for determining the density values .
Calculate the amount Electrical energy consumed by Electrical motor rated 1.5hp if operated for 7 hours?
Answer:
2.82 x 10⁷J
Explanation:
Given parameters:
Power rating of the motor = 1.5hp
Time taken = 7hrs
Unknown:
Amount of electrical energy consumed = ?
Solution:
To solve this problem, we need to convert first to standard unit.
1 hp = 746 Watts
1.5hp = 746 x 1.5 = 1119Watts
Also;
7hrs to Seconds;
1 hr = 3600s
7hr = 7 x 3600 = 25200s
So;
Electrical energy = Power x time = 1119 x 25200 = 2.82 x 10⁷J
Answer this question:
"Is lying Wrong?
explain it minimum 5 sentences.
Answer:
Lying is wrong. Lying to someone is wrong for many reasons, one of them being that it diminishes trust between people. Some people lie because they are trying to keep something hidden, which when the person finds out, breaks trust among them. Lying is normal, which is why most people would say it’s not wrong, but it is wrong, we just need to try and stop lying so much so we don’t break trust. There’s a saying “Honesty is the best policy” said by Sir Edwin Sandys and it means that you should be honest, because it is far more better than lying. The truth also will always come out. People who tell the truth are respected and trustworthy, whereas people who lie are disrespected and not trustworthy.
Explanation:
That was 7 sentences, and I hope this helps! =) Have a great day!!
* Psychology
Match the types of psychoactive drugs to their functions,
depressants
stimulants
amphetamines
hallucinogens
to excite neural activity and temporarily
elevate awareness
to increase dopamine activity and produce
schizophrenic-like paranoid symptoms
>
to inhibit the function of the central nervous
system and neural activity
to distort perceptions and effects on thinking
Answer:
See explanation below
Explanation:
Psychoactive drugs are drugs that affect the central nervous system. They alter cognitive function by changing mood and consciousness.
Examples;
Depressants: Inhibit the function of the central nervous system and neural activity.
Stimulants: Excite neural activity and temporarily elevate awareness.
Amphetamines: Increase dopamine activity and produce schizophrenic-like symptoms.
Hallucinogens: Distort perceptions and effects on thinking.
A drug is any substance that alters how the body functions.
What is a drug?A drug is any substance that alters how the body functions. There are different types of drugs that affect different parts of the body.
We shall now explain the following classifications of drugs;
depressants - to inhibit the function of the central nervousstimulants - elevate awarenesshallucinogens - to distort perceptions and effects on thinkingamphetamines - schizophrenic-like paranoid symptomsLearn more about drugs: https://brainly.com/question/6022349
What is Ex(P), the value of the x-component of the electric field produced by by the line of charge at point P which is located at (x,y) = (a,0), where a = 8.7 cm?
Answer:
The answer is below
Explanation:
We are going to use Gauss’ law to find the electric field equation. Since electric field is coming from an infinite line of charge, hence it is going out in a radial direction.
Therefore we use the area of the electric field which passes through, forming a Gaussian cylinder. We neglect the ends of the area.
Hence:
[tex]\int\limits {E} \, dA=\frac{Q_{enc}}{\epsilon_o}\\\\E(2\pi rL)= \frac{\lambda L}{\epsilon_o}\\\\E=\frac{\lambda}{2\pi r\epsilon_o} \\\\Given \ that:\\\\r=a=8.7\ cm=0.087\ m, \lambda=-2.3 \mu C/cm=-2.3*10^{-4}\ C/m,\epsilon_o=8.85*10^{-12}F/m.\\\\Hence:\\\\E=\frac{-2.3*10^{-4}}{2\pi *0.087*8.85*10^{-12}}=-4.75*10^7\ N/C[/tex]
The value of the x-component of the electric field is -475213.968 newtons per coulomb.
Procedure - Determination of the magnitude of an electric field at a given pointIn this question we shall apply Gauss' Law to determine the magnitude of the electric field ([tex]E_{x}[/tex]), in newtons per coulomb, rapidly and based on the assumptions of uniform charge distribution and cylindrical symmetry.
[tex]\frac{Q_{enc}}{\epsilon_{o}} = \oint\,\vec E\,\bullet d\vec A[/tex] (1)
Where:
[tex]Q_{enc}[/tex] - Enclosed charge, in coulombs.[tex]\epsilon_{o}[/tex] - Vacuum permitivity, in quartic second-square amperes per kilogram-cubic meter.[tex]\vec E[/tex] - Electric field vector, in newtons per coulomb.[tex]\vec A[/tex] - Area vector, in square meters.Based on all assumptions, we simplify (1) as follows:
[tex]\frac{\lambda\cdot l}{\epsilon_{o}} = E \cdot (2\pi\cdot r\cdot l)[/tex]
And the equation of the x-component of the electric field is:
[tex]E = \frac{\lambda}{2\pi\cdot \epsilon_{o}\cdot r}[/tex] (2)
Where [tex]\lambda[/tex] is the linear charge density, in coulomb per meter.
If we know that [tex]\lambda = -2.3\times 10^{-6}\,\frac{C}{m}[/tex] and [tex]a = 0.087\,m[/tex], then the electric field produced by the line of charge at point P is:
[tex]E = \frac{\left(-2.3\times 10^{-6}\,\frac{C}{m} \right)}{2\pi\cdot \left(8.854\times 10^{-12}\,\frac{s^{4}\cdot A^{2}}{kg\cdot m^{3}} \right)\cdot (0.087\,m)}[/tex]
[tex]E_{x} = -475213.968 \,\frac{N}{C}[/tex]
The value of the x-component of the electric field is -475213.968 newtons per coulomb. [tex]\blacksquare[/tex]
RemarkThe figure is missing, we present the corresponding image in the file attached below.
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A long copper bar of rectangular cross-section, whose width w is much greater than its thickness L, is maintained in contact with a heat sink at its lower surface, and the temperature throughout the bar is approximately equal to that of the sink, To. Suddenly, an electric current is passed through the bar and an airstream of temperature T is passed over the top surface, while the bottom surface continues to be maintained at To. Obtain the differential equation and the top surface boundary condition that could be solved to determine the temperature as a function of position and time in the bar.
A uniform electric field is present in the region between infinite parallel plane plates A and B and a uniform electric field is present in the region between infinite parallel plane plates B and C. When the plates are vertical, is directed to the right and to the left. The signs of the charges on plates A, B and C may be
Answer:
the signs on the plates are A + B- C +
Explanation:
The electric field for an infinite plate is perpendicular to it, this field is outgoing if the charge on the plate is positive and incoming if the charge on the plate is negative.
Let's analyze the situation presented, we have two infinite plates A and B with the elective field directed to the right, therefore the charge of the plate must be
plate A positive charge
plate B Negative charge
We also have a third plate C and they indicate that the field between B and C is directed to the left, therefore
plate B negative charged
plate C positive charged
in short the signs on the plates are
A + B- C +
A parallel-plate capacitor with plate area 2.6 cm^2 and air-gap separation 0.25 mm is connected to a 30 V battery, and fully charged. The battery is then disconnected.
I Solved most of the parts of this q's but not this one:
The plates are now pulled to a separation of 0.55 mm. What is the charge on the capacitor now?
note:
I found 125.5pC and the answer unit is pC
Answer:
276.12 pC
Explanation:
We are given that
Area,A=[tex]2.6 cm^2=2.6\times 10^{-4}m^2[/tex]
Where [tex]1 cm^2=10^{-4} m^2[/tex]
[tex]d=0.25 mm=0.25\times 10^{-3} m[/tex]
[tex]1mm=10^{-3} m[/tex]
Potential difference, V=30 V
We have to find the charge on the capacitor when the plates are pulled to a separation of 0.55 mm.
We know that
Charge ,[tex]Q=\frac{\epsilon_0 A V}{d}[/tex]
Where [tex]\epsilon_0=8.85\times 10^{-12}[/tex]
Using the formula
[tex]Q=\frac{8.85\times 10^{-12}\times 2.6\times 10^{-4}\times 30}{0.25\times 10^{-3}}[/tex]
[tex]Q=2.7612\times 10^{-10} C[/tex]
[tex]Q=276.12p C[/tex]
[tex]1 pC=10^{-12} C[/tex]
When the plates are now pulled to a separation of 0.55 mm.Then, the charge on the plates remain same because the battery has been disconnected.
Therefore, charge on the capacitor=276.12 pC
Three charges, Q1, Q2, and Q3 are located in a straight line. The position of Q2 is 0.301 m to the right of Q1. Q3 is located 0.169 m to the right of Q2. The force on Q2 due to its interaction with Q3 is directed to the.....
1.Left if the two charges have opposite signs. t/f
2.Right if the two charges are negative. t/f
3.Left if the two charges are positive. t/f
4.Left if the two charges are negative. t/f
5. Right if the two charges have opposite signs. t/f
In the above problem, Q1= 1.90·10-6 C, Q2= -2.84·10-6 C, and Q3= 3.03·10-6 C.
1. Calculate the total force on Q2. Give with the plus sign for a force directed to the right.
2. Now the charges Q1= 1.90·10-6 C and Q2= -2.84·10-6 C are fixed at their positions, distance 0.301 m apart, and the charge Q3= 3.03·10-6 C is moved along the straight line. For what position of Q3 relative to Q1 is the net force on Q3 due to Q1 and Q2 zero? Use the plus sign for Q3 to the right of Q1.
Answer and Explanation: A charge exerts a force over another charge even if they are very far apart. This force is called Electrostatic Force.
If the two charges have the same sign, e.g. both aare positive, the force between them is opposite. If they have opposite sign, the force is towards each other. In other words, for electrostatic force, equal charges repel and different charges attract.
So,
1. If Q2 and Q3 have opposite signs, it is TRUE force in Q2 will go the left;
2. If the 2 are negative, they have the same sign, so it's FALSE force is to the right;
Sentences 3 and 4 are also TRUE due to the reasons described above;
5. If the charges have opposite signs, it means force is towards each other, or, to the right, so the sentence is TRUE;
1. Force is directly proportional to charges in Coulomb [C] and inversely proportional to distance squared in [m]:
[tex]F=\frac{k.q.Q}{r^{2}}[/tex]
where k is a constant that equals 9 x 10⁹ N.m²/C²
Calculating force between 1 and 2:
[tex]F_{12}=\frac{9.10^{9}(1.9.10^{-6})(2.84.10^{-6})}{(0.301)^{2}}[/tex]
[tex]F_{12}=536.02.10^{-3}[/tex] N
Force between 2 and 3:
[tex]F_{23}=\frac{9.10^{9}(2.84.10^{-6})(3.03.10^{-6})}{(0.169)^{2}}[/tex]
[tex]F_{23}=2711.63.10^{-3}[/tex] N
Total force is the net force. Since Q2 is negative and the others are positive, force of 2 related to 1 is to left and related to 3 is to the right. Therefore, total force is the difference between those two forces:
[tex]F_{T}=2711.63.10^{-3}-536.02.10^{-3}[/tex]
[tex]F_{T}=2175.61.10^{-3}[/tex] N
The total force on Q2 is 2175.61 x 10⁻³ N
2. For net force to be 0, [tex]F_{13}=F_{23}[/tex]. Suppose distance from 1 to 3 is x, then from 2 to 3 is [tex]x-0.301[/tex]
Calculating:
[tex]\frac{k(1.90.10^{-6})(3.03.10^{-6})}{x^{2}}=\frac{k(2.84.10^{-6})(3.03.10^{-6})}{(x-0.301)^{2}}[/tex]
[tex]\frac{5.757.10^{-12}}{x^{2}} =\frac{8.6052.10^{-12}}{x^{2}-0.602x+0.090601}[/tex]
[tex]\frac{5.757.10^{-12}}{8.6052.10^{-12}}=\frac{x^{2}}{x^{2}-0.602x+0.090601}[/tex]
[tex]x^{2}=0.67x^{2}-0.40x+0.061[/tex]
[tex]0.33x^{2}+0.40x-0.061=0[/tex]
roots = 0.14 or -1.35
Solving quadratic equation gives 2 roots, but one of the roots is negative. As distance is a measure that cannot be negative, the solution is x = 0.14.
The distance of Q3 relative to Q1 is 0.14 m
Unpolarized light of intensity 30 W/cm2 is incident on a linear polarizer set at the polarizing angle θ1 = 22 ∘. The emerging light then passes through a second polarizer that is set at the polarizing angle θ2 = 162 ∘. Note that both polarizing angles are measured from the vertical. What is the intensity of the light that emerges from the second polarizer?
Answer:
I₂ = 8.80 W/cm²
Explanation:
To solve this exercise we need to apply the Malus's law.
First, when the light gors through the first polarizer which is linear, intensity is always cut in half, therefore:
I₁ = I / 2 (1).
Applying this, we have:
I₁ = 30 / 2 = 15 W/cm²
Now, we can calculate the intensity of the light, after it passes through the second polarizer. The Law of Malus states that light intensity will be:
I₂ = I cos²Ф (2)
Where Ф, is the difference between the angle of the first polarizer and the second. In this way we have:
Ф = α - β
Ф = 162 - 22 = 140°
Now, applying Malus's law we have:
I₂ = 15 cos²140°
I₂ = 8.80 W/cm²Hope this helps
How many seconds are there in 27.5 days?
A 3 kg ball moving to the right at 4 m/sec collides with a 4 kg ball moving to the right at 2 m/sec. Find the final velocities of the balls in m/sec if the coefficient of restitution is 0.6.
A. 2.2, 3.4
B. 1, 2
C. 4, 5
D. 6, 8
Answer:
Option A
Explanation:
To solve this problem we need to apply the momentum conservation, and analyze the data.
For this problem, I will call the initial velocities as V₁ and V₂, while the final velocities will be V₃ and V₄.
According to the momentum principle, this states the following:
m₁V₁ + m₂V₂ = m₁V₃ + m₂V₄ (1)
From this equation we can write an expression in function of V₃ and V₄. We also know that coefficient of restitution is 0.6. Knowing this, we can write the expression that will help us to solve for the final velocities:
e = V₄ - V₃ / 2 (2)
With both expressions we can solve for the final velocities. Let's use (1) first and see what we can simplify first by replacing the given data:
(3*4) + (4*2) = 3V₃ + 4V₄
12 + 8 = 3V₃ + 4V₄
20 = 3V₃ + 4V₄ (3)
This is all we can do for now. Let's use (2) now:
0.6 = V₄ - V₃ / 2
1.2 = V₄ - V₃
V₄ = 1.2 + V₃ (4)
Now, we can replace (4) into (3), and then, solve for V₃:
20 = 3V₃ + 4(1.2 + V₃)
20 = 3V₃ + 4.8 + 4V₃
15.2 = 7V₃
V₃ = 15.2 / 7
V₃ = 2.17 m/sWe have the value of one final velocity, let's see the other one.
V₄ = 1.2 + V₃
V₄ = 1.2 + 2.17
V₄ = 3.37 m/sThe closest values to these results are in option A, so this will be the correct option.
Hope this helps
2.
Which is the value of a vector quantity?
A 200V
B 100kg/m
C 20m/s, east
D 50J/(kg°C)
А
B
C
D
3.
The diagrams show three uniform beams P Q and Reach pivoted at its centre
Answer:
c
Explanation:
a vector quantity has both magnitude and direction
The value of 20m/s, east is a vector quantity is Hence, option (C) is correct.
What is vector quantity?A physical quantity that has both directions and magnitude is referred to as a vector quantity.
A lowercase letter with a "hat" circumflex, such as "û," is used to denote a vector with a magnitude equal to one. This type of vector is known as a unit vector.
Given values 200V, 100kg/m, 50J/(kg°C) are denoting magnitude of different physical quantity. Hence, they and scalar quantity ( Physical quantities with merely magnitude and no direction are referred to as scalar quantities. These physical quantities can be explained just by their numerical value without any further guidance.).
But The value of 20m/s, east has a magnitude of 20 m/s and a direction along east. Hence, 20m/s, east denotes a vector quantity is Hence, option (C) is correct.
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What is the SI unit of energy and Work?
Answer:
joule is the answer
Explanation:
I hope it helps you
Statement A: 2.567 km, to two significant figures. Statement B: 2.567 km, to three significant figures. Determine the correct relationship between the statements. View Available Hint(s) Determine the correct relationship between the statements. Statement A is greater than Statement B. Statement A is less than Statement B. Statement A is equal to Statement B.
Answer:
Statement A is greater than Statement B.
Explanation:
Statement A: 2.567 km, to two significant figures..
To 2 sig figures means only 2 whole numbers should be left after approximation. Thus, 2.567 to 2 significant figures is 2.6 km
Statement B: 2.567 km, to three significant figures. To 3 sig figures means only 3 whole numbers should be left after approximation. Thus, 2.567 to 3 significant figures is 2.57 km
Comparing both values, statement A is obviously greater than Statement B
What are the major properties of the sun?
PLEASE HELP!!
Answer:
Explanation:
Properties of the sun
Introduction to Stars A. The Sun 1. ...
Layers of the sun (Atmosphere) a. Photosphere: Layer that emits the radiation we see. ...
Layers of the sun (Interior) a. ...
Solar Wind: a. ...
The sun in X-Rays: a. ...
Luminosity: The measure of the energy put out by the sun. ...
Luminosity continued: c. ...
Luminosity continued: e.
The heat of the Sun's surface is so large that neither solid nor liquid can reside there. The heat is the physical property of the sun.
What is the sun?The Sun is a billion star at the core of our universe, a hot. It is an incandescent ball of hydrogen and helium.
The Sun is millions of kilometers away from the land, and life is not possible without its energy.
The major properties of the sun are as follows;
1. The mass of the sun is 1.98892 x 10³⁰ kg.
2 The density of the sun is 1.622 x 10⁵ kg/m³
3. The surface gravity of the sun is 27.94 g.
4. The diameter is 1,391,000 kilometers.
5. The volume of the Sun is 1.412 x 1018 km³
The heat of the Sun's surface is so hot that neither solid nor liquid can reside there instead, the component materials are mostly gaseous atoms with a few molecules. As a result, no permanent surface exists.
Hence heat, density, and mass are the major properties of the sun.
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Which is larger: 65 mph (miles per hour) or 120 kph (kilometers per hour)? As a percentage, how much faster is one than the other?
To Find :
Which is larger: 65 mph (miles per hour) or 120 kph (kilometers per hour).
Solution :
We know, 1 mph = 1.61 kph
So, 65 mph = 1.61 × 65 kph
65 mph = 104.65 kph
Since, 65 mph is 104.65 kph which is smaller than 120 kph.
Therefore, 120 kph is faster than 65 mph by ( 120 - 104.65 ) = 15.35 kph.
what is the total distance traveled by a bike rider who rides for three hours at 40 km/hr and then two more hours at 50 km/hr?
Answer:
220 km
Explanation:
3 hours at 40 km/hr
40 km = 1 hour
40 km times 3 = 120 km
2 hours at 50 km/hr
50 km = 1 hour
50 times 2 = 100 km
Total distance
120 km + 100 km = 220 km
What do you think would happen to the force of attraction of two interacting charges if their distance apart is halved?
Answer:
The new force becomes 4 times the initial force.
Explanation:
The force of attraction or repulsion is given by the relation as follows :
[tex]F=k\dfrac{q_1q_2}{d^2}[/tex]
Where
d is the distance between the interacting charges
F is inversely proportional to the distance between charges.
If the distance is halved, d'=(d/2), new force is given by :
[tex]F'=k\dfrac{q_1q_2}{d'^2}\\\\=k\dfrac{q_1q_2}{(\dfrac{d}{2})^2}\\\\=k\dfrac{q_1q_2}{\dfrac{d^2}{4}}\\\\=4\times \dfrac{kq_1q_2}{d^2}\\\\F'=4F[/tex]
So, the new force becomes 4 times the initial force.
Four cylindrical wires of different sizes are made of the same material. Which of the following combinations of length and cross-sectional area of one of the wires will result in the smallest resistance?
a. Length Area
3L 3a
b. Length Area
3L 6a
c. Length Area
6L 3a
d. Length Area
6L 6a
Answer:
Explanation:
For resistance of a wire , the formula is as follows .
R = ρ L/S
where ρ is specific resistance , L is length and S is cross sectional area of wire .
for first wire resistance
R₁ = ρ 3L/3a = ρ L/a
for second wire , resistance
R₂ = ρ 3L/6a
= .5 ρ L/a
For 3 rd wire resistance
R₃ = ρ 6L/3a
= 2ρ L/a
For fourth wire , resistance
R₄ = ρ 6L/6a
= ρ L/a
So the smallest resistance is of second wire .
Its resistance is .5 ρ L/a
Choose the element that has a smaller atomic radius :scandium or selenium
The engineer of a passenger train traveling at 25.0m/s sights a freight train whose caboose is 200m ahead on the same track. The freight train is traveling at 15.0m/s in the same direction as the passenger train. The engineer of the passenger train immediately applies the brakes, causing a constant accelaration of -0.100m/s2, while the freight train continues with constant speed. Take x=0 at the location of the front of the passenger train when the engineer applies the brake.
a) Will the cows nearby witness a collision?
b) If so, where does it take place
c) On a single graph, sketch the positions of the frong of the passenger train and the back of the freight train.
Answer:
a) if the two trains are going to collide
b) x = 538 m
Explanation:
To solve this exercise we use the kinematics relations in one dimension.
We set a reference system at the starting point of the passenger train
Freight train, we use index 1 for this train
x₁ = x₀ + v₁ t
passenger train
x₂ = v₂ t - ½ a₂ t²
as we are using the same system to measure the position of the two trains, at the meeting point the position must be the same
x₁ = x₂
we substitute
x₀ + v₁ t = v₂ t - ½ a₂ t²
½ a₂ t² + t (v₁ -v₂) + x₀ = 0
we subjugate the values
½ 0.1 t² + t (15-25) + 200 = 0
0.05 t² - 10 t + 200 = 0
t² - 200 t + 4000 = 0
we solve the second degree system
t = [200 ±[tex]\sqrt{200^2 - 4 \ 4000}[/tex] ]/ 2
t = [200 ± 154.9] / 2
t₁ = 177.45 s
t₂ = 22.55 s
therefore for the smallest time the two trains must meet t₂ = 22.55 s
merchandise train
x = 200+ 15 22.55
x = 538 m
passenger train
x = 25 22.55 -1/2 0.100 22.55²
x = 538 m
we see that the trains meet for this distance
a) if the two trains are going to collide
b) x = 538 m
c) see attachment for schematic graphics
Post-Impressionist Georges Seurat is famous for a painting technique known as pointillism. His paintings are made up of different-colored dots, and each dot is roughly 2 mm in diameter. When viewed from far enough away, the dots blend together and only large-scale images are seen. Assuming that the human pupil is about 2.9 mm in diameter, determine an approximate minimum distance you need to stand from one of Seurat's paintings to see the dots blended together. (Assume two dots touch, such that their center-to-center distance is equal to one diameter. Also assume light with a wavelength of 563 nm.)
Answer:
84 cm
Explanation:
The resolving power of the eye = 1.22 λ / D where λ is wavelength of light and D is diameter of the eye .
Putting the values in the formula
The resolving power of the eye = 1.22 λ / 2.9 x 10⁻³
Let the minimum distance you need to stand from one of Seurat's paintings to see the dots blended together be D .
d = distance between two dots = diameter of dot = 2 x 10⁻³ m .
Given ,
λ D / d = 1.22 λ / 2.9 x 10⁻³
D /2 x 10⁻³ = 1.22 / 2.9 x 10⁻³
D = 2 x 1.22 / 2.9 m
= .84 m
= 84 cm .
minimum distance you need to stand from one of Seurat's paintings to see the dots blended together is 84 cm .
What is a response of an organism when the temperature drops? A. Panting, which exchanges cold air for warm air in the body raising the temperature Sweating, which pulls moisture to the surface to trap heat close to the skin Salivating, which lets go of extra liquid in the body releasing energy as heat Shivering, where muscles contract and expand quickly and the body temperature rises
Shivering is a response of an organism when the temperature drops. In shivering, muscles contract and expand quickly and the body temperature rises.
What is Shivering ?Warm-blooded animals shiver (also known as shudder) as a physiological reaction to cold and acute fear. To preserve homeostasis, the shivering reaction is activated when the body's core temperature lowers.
Small skeletal muscle movements start, producing warmth as the muscles use up their energy. Another sign of a fever is shivering because the person may feel cold.
The hypothalamic set point for temperature rises during a fever. Up until the new set point is reached, the patient experiences cold until the increased set point raises body temperature (pyrexia).
Rigors are the medical term for extremely cold symptoms accompanied by ferocious shivering. Rigors happen as a result of the patient's body shivering in an effort to physiologically raise body temperature to the new set point.
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In what way did the cloud model resemble the Bohr model
Answer:
While Bohr's atomic model hypothesizes that electrons move in particular energy levels around the nucleus, the electron cloud model suggests that electrons move in an unpredictable pattern but are more likely to be in certain regions than others.
Explanation:
Scientists believe that the boundary stratum between the Cretaceous and Paleogene was caused by an asteroid. What evidence is most consistent with this theory?
Answer:
Because there was fewer fossils
Explanation:
Answer:
Actually the answer is "The stratum contains iridium.".
Explanation:
A 0.5kg football thrown by Tony Romo with a velocity of 15 m/s is caught by a stationary receiver and brought to rest in 0.02 seconds. a) what impulse is delivered to the ball? b) how much force must be exerted in order to stop the ball?
The answers are -7.5kg m/s and F = -375N, but I don't know how they got them. Steps please! Thank you!!
Answer:
a.-7.5 kg m/s
b.-375 N
Explanation:
We are given that
Mass of football, m=0.5 kg
Initial velocity ,u=15m/s
Final speed ,v=0
Time, t=0.02 s
a. We have to find the impulse delivered to the ball.
We know that
Impulse=Change in momentum
I=m(v-u)
Using the formula
[tex]I=0.5(0-15)=-7.5 kg m/s[/tex]
Hence, the impulse delivered to the ball=-7.5 kg m/s
(b)
We know that
Force,[tex]F=\frac{|mpulse}{time}[/tex]
Using the formula
[tex]F=\frac{-7.5}{0.02}=-375 N[/tex]
Name two types of mechanical weathering in NewBedford
Answer:
Explanation:
Mechanical weathering types
Mechanical weathering is the breaking down of rocks into smaller pieces without changing the composition of the minerals in the rock. This can be divided into four basic types – abrasion, pressure release, thermal expansion and contraction, and crystal growth.
If the speed of an object does NOT change, the object is traveling at a
constant speed
increasing speed
decreasing speed
Answer:
If the speed does not change at all, the object would be moving at a constant speed.