Answer:
15
----
153
15=6+3+1
153=18×17÷2
Evaluate
4! - (11-2)!
8!
Answer:
Step-by-step explanation:
The expanded value of n! is (n) * (n - 1) * (n - 2) until we reach one.
Given:
4! - ((11-2)!) / 8!)
Rewrite:
[tex]\displaystyle 4! - \frac{(11-2)!}{8!}[/tex]
Subtract:
[tex]\displaystyle 4! - \frac{9!}{8!}[/tex]
Expand:
[tex]\displaystyle 4*3*2*1 - \frac{9*8*7*6*5*4*3*2*1}{8*7*6*5*4*3*2*1}[/tex]
Cancel out values that equal one in the fraction:
[tex]\displaystyle 4*3*2*1 - \frac{9}{1}[/tex]
Multiply:
[tex]\displaystyle 24 - \frac{9}{1}[/tex]
Simplify:
24 - 9
Subtract:
15
A bag contains hair ribbons for a spirit rally. The bag contains 8 black ribbons and 12 green ribbons. Lila selects a ribbon at random, then Jessica selects a ribbon at random from the remaining ribbons. What is the probability that both Lila and Jessica select a black ribbon? Express your answer as a fraction in simplest form.
Answer:
[tex]\boxed{\sf \dfrac{14}{95}}[/tex]
Explanation:
Black ribbons = 8 ribbons
Green ribbons = 12 ribbons
Total ribbons: 12 + 8 = 20 ribbons
[tex]\sf Probability = \dfrac{Favorable \ Outcomes}{Total \ Possible \ Outcomes}[/tex]
For Lila:
[tex]\sf Lila \ picks \ black \ : \ \dfrac{8}{20}[/tex]
Left black ribbons: 8 - 1 = 7 black ribbons
Left total ribbons: 20 -1 = 19 total ribbons
For Jessica:
[tex]\sf Jessica \ picks \ black \ : \ \dfrac{7}{19}[/tex]
Probability that they both pick black ribbons:
[tex]\sf \rightarrow \dfrac{8}{20} \ x \ \dfrac{7}{19}[/tex]
[tex]\sf \rightarrow \dfrac{14}{95}[/tex]
Here are the driving scores of 40 new drivers. make a relative frequency table for their scores:
48, 67, 62, 74, 42, 62, 60, 75, 91, 88, 48, 60, 51, 63, 57, 85, 69, 75, 97, 72,
71, 79, 84, 65, 63, 73, 46, 55, 62, 72, 80, 55, 55, 56, 83, 80, 64, 72, 83, 92
in creating the table, you will need to make some choices about how to bin the data: how many bins,
and how wide the bins should be. you may also need to make some decisions about what to do with numbers that fall in the boundary between two bins in writing up your answers be clear about how you are making these choices there is more than one reasonable way to do it so you need to be clear about which decisions you are making.
The relative frequency table is:
Class Frequency Relative frequency
40 - 50 4 0.1
50 - 60 6 0.15
60 - 70 11 0.18
70 - 80 9 0.23
80 - 90 7 0.18
90 - 100 3 0.08
What is the relative frequency table?The relative frequency measures how often a value appears relative to the sum of the total values. The class width is 10. The class width is the difference between the upper and lower boundary (e.g. 100 - 90).
Frequency is the number of times the numbers in the class interval appear in the data set. Relative frequency is the frequency of a class interval divided by the total frequency of the data set.
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Calculate the values
Answer:
a=108;b=36;c=72
Step-by-step explanation:
Answer:
a = 108°
b = 36°
c = 72°
Step-by-step explanation:
Note : the sum of the interior angles of a regular pentagon = 540°
Then
The measure of one interior angle of a reg pentagon =540/5 = 108°
Therefore a = 108°
c = 180 - 108 = 72°
SRT is a new isosceles triangle then :
[tex]b=\frac{180-108}{2} = \frac{72}{2} =36[/tex]
a produce company is packaging tomatoes into boxes containing 8 tomatoes each. how many boxes do they need to package 416 tomatoes?
Answer:
5.75
Step-by-step explanation:
If
1 box = 8 tomatoes
x boxes = 46 tomatoes
1 = 8
x = 46
You cross multiply giving you
8x = 46×1
8x = 46
8x/8 = 46/8
x = 5.75
estimate the perimeter and the area of the shaded figure to the nearest whole number
Answer:
See below ~
Step-by-step explanation:
Perimeter
2(6 + 8)2(14)28 unitsArea
2(4 x 2) + 2(8)4(8)32 square unitsa basket contains a supply of marbles of 4 different colors. marbles with the same color are assumed to be identical. in how many ways can you choose 6 marbles from the basket
For the basket with 4 different types of marbles, there are 4,096 combinations in which we can select 6 marbles (in order).
in how many ways can you choose 6 marbles from the basket?Here we need to identify the number of selections. We have 6 selections (assuming that order matters).
Marble 1:Marble 2:Marble 3:Marble 4:Marble 5:Marble 6:Now we need to find the number of options for each of these. We know that there are 4 different colors of marbles, then for each selection, we have 4 options:
Marble 1: 4 optionsMarble 2: 4 optionsMarble 3: 4 optionsMarble 4: 4 optionsMarble 5: 4 optionsMarble 6: 4 optionsThe total number of combinations is given by the product between the numbers of options, so we have:
C = 4*4*4*4*4*4 = 4,096 combinations.
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A pen was attached to a table by a small 10-inch chain. Jason lifted the pen, pulled the chain as far as it would reach, and then drew a circle as shown below.
The circumference of the circle that Jason drew is gotten as; 62.80 inches
How to find the circumference of a circle?Since Jason lifted the pen and pulled the chain as far as it would reach before drawing a circle, then it means that;
radius of circle; r = 10 inches
Formula for circumference is;
C = 2πr
Thus;
C = 2 * 3.14 * 10
C = 62.80 inches
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findin the measure of each angle (3x-13)° 5x -47
The measure of each angle is 43.25 and 46.75
How to determine the measure of each angle?The attached image represents the missing piece in the question.
From the image, we can see that:
3x - 13 + 5x - 47 = 90 ---- complementary angles
Evaluate the like terms
8x = 150
Divide by 8
x = 18.75
Substitute x = 18.75 in the given angles
3x-13 = 3 * 18,75 - 13 = 43.25
5x -47 = 5 * 18.75 - 47 = 46.75
Hence, the measure of each angle is 43.25 and 46.75
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(4a^3 - 36a^2 + 60a^2 + 72) \ (a - 6)
Answer:
4a^2+48a+288+(fraction)1800/a-6
Step-by-step explanation:
How many national roads connected to Bloemfontein?
Answer:
3
Step-by-step explanation:
The N1, N6 and N8 national highways meet in Bloemfontein,
Hope This Helped
The volume of this cube is 27 cubic meters. What is the value of m?
Hey ! there
Answer:
n is equal to 3 metersStep-by-step explanation:
In this question we are provided with a cube having volume 27 cubic meters . And we are asked to find the value of n that is basically its edge .
For finding the value of n we need to know the volume of cube. So ,
[tex] \: \qquad \: \qquad \: \underline{ \boxed{ \frak{Volume_{(Cube)} = a {}^{3} }}}[/tex]
Where ,
a refers to edge of cubeSOLUTION : -
Substituting given volume that is 27 m³ and value of a as n in formula :
[tex] \quad \longrightarrow \qquad \: n {}^{3} = 27[/tex]
Applying cube root on both sides :
[tex] \quad \longrightarrow \qquad \: \sqrt[3]{n {}^{3} } = \sqrt[3]{27} [/tex]
We get ,
[tex] \quad \longrightarrow \qquad \:n= \sqrt[3]{27} [/tex]
We know that 3 × 3 × 3 is equal to 27 that means cube root of 27 is 3 . So ,
[tex] \quad \longrightarrow \qquad \: \blue{\underline{\boxed{\frak{ n = 3 \: m}}}} \quad \bigstar[/tex]
Henceforth , value of n is ❝ 3 meters ❞Verifying : -
Now we are checking our answer whether it is wrong or right by substituting value of n and equating it with given volume that is 27 cubic meters . So ,
a³ = 27 ( where a is equal to n )Substituting values :
( 3 )³ = 273 × 3 × 3 = 279 × 3 = 2727 = 27L.H.S = R.H.SHence, Verified .Therefore, our answer is correct .
#Keep LearningAnswer:
3
Step-by-step explanation:
Formula for volume of cube :
V = n³Here, V is given to be 27 m³.
Substitute the value of V in the formula.
Solving : Take the cubic root on each side.
27 m³ = n³n = ∛27 m³n = 3 meterswhat is the probability of drawing a king and a diamond from a standard deck of cards
Answer:
P(king or diamond) = P(king) + P(diamond) - P(king and diamond) P(king or diamond) = (4/52) + (13/52) - (1/52) P(king or diamond) = 16/52 Page 5 P(king or diamond) = 4/13.
How to find area of 1 ???
Answer: 1 What???
Step-by-step explanation:
Out of all 252 twelfth graders, how many rode in a car to school? 11 74 111 114
Out of all 252 twelfth graders, 114 rode in a car to school
How to determine the number of students?The proportion of students that rode in a car is given as:
p = 45.24%
So, the number of students that rode in a car is:
Students = 45.24% * 252
Evaluate the product
Students = 114.008
Approximate
Student = 114
Hence, 114 rode in a car to school
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There are 21 students in a classroom. the ratio of boys to girls is 2 boys to 5 girls. how many boys are in the classroom?
Answer:
6
Step-by-step explanation:
The ratio of boys to girls is 2:5
let the number of boys be 2x -------(i)
and number of girls be 5x
and the total number of students is 21
therefore we know that..
2x+5x = 21
on solving for x,
7x=21
x= 21/7
x=3
now, by putting the value of x in (i),
2x = 2×3 = 6
therefore, there are 6 boys in the classroom.
you find the no. of girls similarly.
hope it helps !!...
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This dot plot shows the number of runs scored by the Yellow
Jackets in their last 12 baseball games.
Please solve this for me
Characterize the slope of the line in the graph.
Helpppp
I'll give 50 pts
Answer:
Step-by-step explanation:
Answer:
i agree with the other anwser!!
Step-by-step explanation:
cant solve x+4y=0
3x+2y=20
Answer:
The answer to this question is -2.
Step-by-step explanation:
First, multiply one of the equations by something that can cancel out the other variable.
3x+2y=20
3(x+4y=0)
3x+2y=20
3x+12y=0
Now, subtract both equations.
-10y=20
Now, divide both sides by -10.
y=-2
Hope this helps!
6 Mateo and Katia each walked into a
video arcade with $9.50 in quarters. After
they played video games for an hour, Katia
had $1.75 more than Mateo. Which could
be the amounts of money they had then?
Answer:
(amounts could be:)
Katia: $3.50
Mateo: $1.75
Step-by-step explanation:
Remember that a quarter = $0.25, 4 quarters = $1.00
We know that they both have 38 quarters ($9.50)after an hour of playing games in the arcade, Katia has $1.75 more than Mateo
lets say that Katia has (random amount)$3.50(14 quarters) and Mateo has $1.75 less than that.
$3.50 - $1.75 = $1.75
Katia has $3.50 and Mateo has $1.75.Ms. brown is planting a rectangular garden. the garden is 90
feet long and 50 feet wide. what is the area of her garden?
a 140 ft?
b 4,000 ft?
c 280 ft?
d 4,500 ft
Explain how the arc BX, central angle BCX, and inscribed BNX are connected. You can compare two or three at a time. B АХ C Z
Answer:
arc BX = central angle BCX
inscribed BNX = 1/2 of central angle BCX
inscribed BNX = 1/2 of arc BX
Step-by-step explanation:
arc BX = central angle BCX
inscribed BNX = 1/2 of central angle BCX
inscribed BNX = 1/2 of arc BX
what's the answer for 3 ( x + 2) = 11+3x-5
Answer:
question is not correct
Step-by-step explanation:
3(x+2)=11+3x+5
3x+6=11+3x+5, once 3x is subjected from both sides it becomes unsolvable
Answer: Infinite solution
Step-by-step explanation: 3x + 6 = 11 + 3x - 5
-3x
6 = 11 - 5
6 = 6
How to find LCM by factorization method
Answer:
1. Find the prime factorization of each number.
2. Write each number as a product of primes, matching primes vertically when possible.
3. Bring down the same numbers in each column and the remaining numbers in each column.
4. Multiply the factors to get the LCM.
for example the lcm of 24 and 36
= 24 = (2 × 2 × 2 × 3) = 2^3 × 3^1
and 36 = (2 × 2 × 3 × 3) = 2^2 × 3^2
LCM(24, 36) = 2^2 × 3 × 2 × = 72
i hope my answer was helpful and please mark me as brainliest
Solve the math:
Elsa is 2 years older than Bella. Emma is twice as old as Elsa. So, what will be the sum of their ages in 1 years time. And then also find out what was the summation of their ages before 5 years from now.
Answer:
Step-by-step explanation:
Let Emma's age be 2x years, then:
Elsa's age is x years, also:
Bella's age is x - 2 years.
In one years time the sum of their ages
= 2x + 1 + x + 1 + x - 2 + 1
= 4x + 1 where x = Elsa's age now.
5 years before now
Sum of their ages
= 2x -5 + x - 5 + x - 2 - 5
= 4x - 17 where x = Elsa's age now,
8. Given the following function, (a) find the vertex; (b) determine whether there is a maximum or a minimum value, and find the value; (c) find the range; and (d) find the intervals on which the function is increasing and the intervals on which the function is decreasing.
Answer:
Step-by-step explanation:
Parabola:
[tex]\sf f(x) =\dfrac{-1}{2}x^2+7x - 5\\\\a = \dfrac{-1}{2} \ ; b = 7 \ ; \ c = -5[/tex]
[tex]\sf x = \dfrac{-b}{2a}\\\\x =\dfrac{-7}{2*\dfrac{-1}{2}}\\\\ = \dfrac{-7}{-1}[/tex]
x = 7
Now, to find the y-value substitute this in the equation
[tex]\sf f(x) = \dfrac{-1}{2}*7^2+7*7-5\\\\ =\dfrac{-49}{2}+49-5\\\\ = \dfrac{-49}{2}+44\\\\ = \dfrac{-49}{2}+\dfrac{88}{2}\\\\= \dfrac{39}{2}[/tex]
[tex]\boxed{Vertex(7 ,\dfrac{39}{2})}[/tex]
b) The value of a is negative. So, the parabola is open down words and the maximum value is given by the y-coordinate of the Vertex.
[tex]\sf \boxed{Maximum \ value= \dfrac{39}{2}}[/tex]
[tex]\sf c) Range = [\dfrac{39}{2}, -infinity)[/tex]
Answer:
(a) (7,39/2)
(b) Maximum, 39/2
(c) y ≤ 39/2
(d) Increase when x < 7 and decrease when x > 7
Step-by-step explanation:
Given the parabola:
[tex]\displaystyle \large{f(x)=-\dfrac{1}{2}x^2+7x-5}[/tex]
( A ) Find the vertex
In order to find the vertex, let’s use calculus for this one. Recall the power rules for differentiation:
Power Rules
[tex]\displaystyle \large{f(x)=x^n \to f'(x)=nx^{n-1}}\\\\\displaystyle \large{f(x)=kx^n \to f'(x)=knx^{n-1} \quad \tt{(k \ \ is \ \ constant)}}\\\\\displaystyle \large{f(x)=k \to f'(x)=0 \quad \tt{(k \ \ is \ \ constant)}}[/tex]
Derivative Definition
Derivative f'(x) is a slope itself or rate of changes.Derive the parabola:
[tex]\displaystyle \large{f'(x)=-\dfrac{1}{2}(2)x^{2-1} + 7(1)x^{1-1} -0}\\\\\displaystyle \large{f'(x)=-x+7}[/tex]
Since vertex has slope = 0 —> e.g f'(x) = 0:
[tex]\displaystyle \large{0=-x+7}\\\\\displaystyle \large{-x=-7}\\\\\displaystyle \large{x=7}[/tex]
Substitute x = 7 in f(x):
[tex]\displaystyle \large{f(7)=-\dfrac{1}{2}(7)^2+7(7)-5}\\\\\displaystyle \large{f(7)=-\dfrac{1}{2}(49)+49-5}\\\\\displaystyle \large{f(7)=-\dfrac{49}{2}+44}\\\\\displaystyle \large{f(7)=-\dfrac{49}{2}+\dfrac{88}{2}}\\\\\displaystyle \large{f(7)=\dfrac{39}{2}}[/tex]
Therefore, the vertex is at (7,39/2)
( B ) Determine if max or min then find the value
Since the parabola opens downward then there only exists maximum value. The maximum value is the y-value of vertex at x-value of vertex. Henceforth:
There is maximum value but no minimum value and the maximum value is 39/2 at x = 7.( C ) Find range
For parabola, range is minimum value </≤ y </≤ maximum value. We know that parabola has maximum value of 39/2 but no minimum value so we can just ignore it then we’d have:
y ≤ 39/2 is our range[Note: < and > are for open-dot meaning the value will not be included —> e.g x > 4 means 4 isn’t included in.]
( D ) Find the interval when function is increasing and when it’s decreasing
For parabola, the function will increase only if f'(x) or slope > 0 and will decrease only f'(x) < 0.
We know, from part A that the derivative is:
[tex]\displaystyle \large{f'(x)=-x+7}[/tex]
Therefore, when f'(x) > 0 —> e.g -x + 7 > 0:
[tex]\displaystyle \large{-x+7 > 0}\\\\\displaystyle \large{-x > -7}\\\\\displaystyle \large{x < 7}[/tex]
When f'(x) < 0 —> e.g -x + 7 < 0:
[tex]\displaystyle \large{-x+7 < 0}\\\\\displaystyle \large{-x < -7}\\\\\displaystyle \large{x > 7}[/tex]
Therefore, the function will increase when x < 7 and will decrease when x > 7.
Suppose 60% of a herd of cattle is infected with a particular disease. let p = the number of non diseased cattle in a sample of size 5. the distribution of y is
The distribution of y is [tex]P(y) = ^5C_y * (60\%)^y * (1 - 60\%)^{5-y}[/tex]
How to determine the distribution?The given parameters are:
Probability of success, p = 60%
Sample size, n = 5
The distribution of y is represented as:
[tex]P(y) = ^nC_y * p^y * (1 - p)^{n-y}[/tex]
So, we have:
[tex]P(y) = ^5C_y * (60\%)^y * (1 - 60\%)^{5-y}[/tex]
Hence, the distribution of y is [tex]P(y) = ^5C_y * (60\%)^y * (1 - 60\%)^{5-y}[/tex]
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Give the following number
in Base 5.
1310 = [?]5
Expand 13 as 10 + 3.
10 = 2×5, so
13 = 2×5 + 3×1
or
13 = 2×5¹ + 3×5⁰ = 23₅