The collision energy is used for the proving of the equation and the ratio of masses is 1:3.
By conservation of momentum,
m1v1 + 0 = m1v1f + m2v2f
=) v1 = v1f + (m2/m1)v2f -------------- 1
By conservation of kinetic energy
(1/2)m1v1^2 + 0 = (1/2)m1v1f1^2 + (1/2)m2v2f2^2
m1v1^2 + 0 = m1v1f1^2 + m2v2f2^2 ------------- 2
m1[v1f + (m2/m1)v2f]^2 = m1v1f^2 + m2v2f^2
m1v1f^2 + (m2^2/m1)v2f^2 + 2m2.v1f.v2f = m1v1f^2 + m2v2f^2
(m2^2/m1)v2f^2 + 2m2.v1f.v2f = m2v2f^2
(m2^2/m1)v2f^2 + 2m2.v1f = m2v2f
v2f[1-m2/m1] = 2v1f
v2f/v1f = (2m1/m2 - m2) ----------- 3
Hence proved.
B
v1f/v2f = 1/2 - (1/2)(m2-m1)
Now y = 2 / m1 and = v1f/v2f
x = 1/2 - 1/2y
2x = 1-y
y = 2x + 1 -------------- 4
C
Comparing y = mc + x
slope is m = -2
intercept c = 1
Putting v1f = - v2f means x = -1
from eq 4,
m2/m1 = y = -2 * -1 * +1 = 3
m2/m1 = 3.
Therefore, the collision energy is used for the proving of the equation and the ratio of masses is 1:3.
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A student wants to increase the temperature of an ideal gas in a cylinder that is initially at room temperature. The cylinder has a movable piston with negligible friction. Which of the following correctly indicates an action the student could take to increase the temperature of the gas and why the temperature increases? Pull the poston out and Then wit expand violently and increase in temperature Pull the piston out slowly. The as will have time to absorb encesy from the surroundings by heatinst as it expands. Push the piston in rapidly. The temperature of the gas will increase because no enery will be transferred to the surroundinis bw coolinu Push the piston in slowtv: The gas will have time to absorb energy from the surroundings by heating as it is compressed
In order to increase the temperature of an ideal gas in a cylinder that is initially at room temperature, the statement that correctly indicates the appropriate action is to push the piston in rapidly. The temperature of the gas will increase because no energy will be transferred to the surrounding by cooling. (Option C)
An ideal gas refers to a theoretical gas which is composed of many randomly moving point particles that are not subject to interparticle interactions. The concept is useful as it obeys the ideal gas law, which is a simplified equation of state, and is amenable to analysis under statistical mechanics. For an ideal gas, as the temperature increases, the average kinetic energy increases as does the velocity of the gas particles hitting the walls of the container. The force exerted by the particles per unit of area on the container is the pressure, so as the temperature increases the pressure must also increase. Hence, when the piston is compressed so quickly that there is no time to exchange heat to the surrounding, the temperature of the gas increases rapidly.
Note: The question is incomplete. The complete question probably is: A student wants to increase the temperature of an ideal gas in a cylinder that is initially at room temperature. The cylinder has a movable piston with negligible friction. Which of the following correctly indicates an action the student could take to increase the temperature of the gas and why does the temperature increases? A) Pull the piston out rapidly. The gas will expand violently and increase in temperature B) Pull the piston out slowly. The gas will have time to absorb energy from the surroundings by heating as it expands. C) Push the piston in rapidly. The temperature of the gas will increase because no energy will be transferred to the surrounding by cooling. D) Push the piston in slowly. The gas will have time to absorb energy from the surroundings by heating as it is compressed
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shows a particle of mass m at distance x along the axis of a very thin ring of mass m and radius r. calculate the gravitational potential energy of these two masses. Use what you know about the relationship between force and potential energy to find the magnitude of the gravitational force on when it is at position .
When a very thin ring is at position x>0 and at distance x along its axis, the gravitational force acting on it is 4GMm/4x2-L2.
With a gravitational pull that diminishes with distance as 1/r2, every body in the cosmos is attracted to every other body. The gravitational force of attraction a body experiences must be proportionate to its mass if two bodies of different masses accelerate at the same rate (i.e., a body twice as heavy experiences twice the gravitational force).
The gravitational force experienced by a minuscule unit mass placed at any point P in space is known as the gravitational field at that point.
Using the equation gravitational potential = GMm/r and further integrating on a short dx length at x from the rod's origin, we may determine this relationship.
U equals GMm/Lln2x-2/2x+2.
separating now with regard to dx, we obtain
F equals 4GMm/4x2L2.
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(II) A ski gondola is connected to the top of a hill by a steel
cable of length 800 m and diameter 1.7 cm As the gondola
comes to the end of its run, it bumps into the terminal and
sends a wave pulse along the cable. It is observed that it
took 17 s for the pulse to return. (a) What is the speed of the
pulse? (b) What is the tension in the cable?
FT=8278.857 N In the arteries of a man, the pulse wave moves at a rate of 4 to 10 meters per second.Its velocity is somewhat influenced by the blood flow through the artery under consideration
What is the pulse?Your pulse is how you can feel your heart rate. Every time your heart beats, it squeezes and propels blood through the network of arteries in your body. Your pulse is the pressure in your arteries going up briefly as your heart pushes out more blood to keep circulation going.
Does a pulse's speed alter?The amplitude, length, & pulse width of a pulse have no effect on its speed.The breadth or length of a pulse changing has no effect on the pulse speed.
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If a resistance of 500 £2 makes the ohmmeter pointer deflect to its scale, then the resistance which makes the pointer deflect to the scale of the ohmmeter is.
If a resistance of 500 ohms makes the ohmmeter pointer deflect to its scale, then the resistance that would cause the pointer to deflect to the scale of the ohmmeter would be equal to the range of the ohmmeter.
What is ohmmeter?Generally, The range of an ohmmeter refers to the range of resistances that it is designed to measure. If the ohmmeter has a range of 0 to 500 ohms, then a resistance of 500 ohms would cause the pointer to deflect to the scale of the ohmmeter.
If the ohmmeter has a range of 0 to 1,000 ohms, then a resistance of 500 ohms would not cause the pointer to deflect to the scale of the ohmmeter.
It is important to note that the range of an ohmmeter is typically marked on the front panel or in the user manual.
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Calculate the total Av required to transfer between two coplanar circular Earth orbits of radii r 1 parameters p = 13,457 km and e = 0.76. Ans.: 7.086 km/s 12,750 km and r2 = 31,890 km, respectively, using a transfer ellipse having parameters p=13.475 km and e=0.76
The total velocity required (Av) to transfer from one circular orbit to another is 7.086 km/s
The total velocity required (Av) to transfer from one circular orbit to another is given by Av = √(μ/p)(2/r1 - 1/r2), where μ is the standard gravitational parameter of the central body and p is the semi-latus rectum of the transfer ellipse.
Given the parameters for the two circular orbits, r1 = 12,750 km and r2 = 31,890 km, and for the transfer ellipse, p = 13,475 km and e = 0.76, we can calculate the total velocity required to transfer between the two orbits as follows:
Av = √(μ/p)(2/r1 - 1/r2)
Av = √(3.986E+13/13,475)(2/12,750 - 1/31,890)
Av = √(2.946E+10)(0.0690 - 0.0314)
Av = √(2.946E+10)(0.0375)
Av = 7.086 km/s
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the drawing shows two transverse waves traveling on strings. the linear density of each string is 0.065 kg/m. the tension is provided by a 26-n block that is hanging from the string. find the speed of the wave in part (a) and in part (b) of the drawing.
The wave's speeds in parts (a) and (b) of the drawing are 13.7 m/s and 9.691 m/s, respectively.
(Tension / Mass per Unit Length) / sqrt = velocity
A) tension: m = 2.3 * 9.8 = 22.54 N; mass per unit length: 0.12 kg/m
velocity is equal to sqrt(22.54/0.12) = sqrt(187.83) = 13.7 m/s b. 2.3 * 9.8 / 2 = 11.27 N tension
velocity or speed is equal to sqrt(11.27/0.12) = sqrt(93.916) = 9.691 metres per second.
An oscillation of a wave that is perpendicular to the direction of the wave's progress is known as a transverse wave in physics. An oscillating wave moves in the opposite direction from a longitudinal wave, which moves in the same direction. Examples of transverse waves include water waves.
An easy illustration is provided by the waves that may be produced on a horizontal piece of string by anchoring one end and moving the other end up and down.
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which statement about saturn's rings is not true? which statement about saturn's rings is not true? the rings must look much the same today as they did shortly after saturn formed. some features of the rings are shaped by small moons that actually orbit within the ring system. the rings are so thin that they essentially disappear from view when seen edge-on. the large gap known as the cassini division is shaped by an orbital resonance with the moon mimas, which orbits well outside the rings.
The rings must look much the same today as they did shortly after Saturn formed.
The Rings of Saturn:
The Saturnian ring system is the largest ring system in the Solar System. They are made up of innumerable tiny particles that circle Saturn and range in size from micrometers to meters. With a very small amount of stony material, the ring particles are virtually exclusively formed of water ice. Regarding how they form, there is still no agreement. Newer evidence from Cassini indicates that the rings developed relatively late, despite theoretical models suggesting they were likely to have formed early in the Solar System's history.
It is believed that the fragments of comets, asteroids, or shattered moons that broke apart before they reached Saturn and were blasted apart by the planet's strong gravity make up Saturn's rings. They are composed of countless quantities of tiny pieces of rock and ice that have been dusted with other substances.
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The average global temperature and sea levels are rising, accelerating at an unprecedented rate. Suggest three ways in which human beings will be affected by these phenomena.
There are many potential ways in which human beings could be affected by rising global temperatures and sea levels. Some potential impacts include:
Extreme weather events: As global temperatures rise, the Earth's climate is becoming more unpredictable and extreme. This could lead to an increase in the frequency and severity of extreme weather events, such as heatwaves, droughts, floods, and hurricanes. These events can have devastating impacts on human communities, including loss of life, damage to infrastructure, and economic disruption.Loss of habitat and biodiversity: Rising sea levels could lead to the loss of coastal habitats, such as wetlands and coral reefs. This could have serious consequences for the many species that rely on these habitats for their survival. In addition, the loss of these habitats could also have negative impacts on human communities that depend on them for food, shelter, and other resources.Displacement of people: As sea levels rise, many coastal communities could become uninhabitable. This could force people to migrate inland, potentially leading to conflicts over resources and territory. In addition, the loss of coastal habitats could also disrupt the livelihoods of many people who rely on these habitats for their income, such as fishermen and tourism operators.Overall, the impacts of rising global temperatures and sea levels are likely to be complex and far-reaching, potentially affecting many aspects of human life.
a 1271kg sample of water at 0c is cooled to -17c, and freezes in the process how much heat is liberated
The heat released in the whole process in which a sample of water is cooled and frozen is 4.64 * 10⁸ J.
The problem is to be divided into two steps. This process releases a certain quantity of heat,
Step 1) Solidification of the water at 0°C into ice.
Q = m* Lf
where,
m is the mass of the water
Lf stands for the latent heat of ice fusion
Substituting numbers, we find
Q₁ = (1271 kg)* (334 kJ/kg) = 424514 kJ = 4.2* 10⁸ J
step 2) The water became ice, now we need to cool it down to -36°C . This process releases a certain quantity of heat, which is
Q₂ = m* Cs* ΔT
where,
m is the mass of ice
Cs is the specific heat of ice
ΔT is the variation of temperature
By placing the numbers in the formula, we have,
Q₂ = (1271 kg)* (2050 J/kg K) (-17-0) = 44294350 J = - 0.44 * 10⁸ J
The negative sign means the heat is released by the system.
Thus, the overall process produces heat that is
Q = Q₁ + Q₂ = 4.2* 10⁸ J + 0.44 * 10⁸ J = 4.64 * 10⁸ J
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A new planet has been discovered ad given the name Planet X . The mass of Planet X estirated to be one-half that of Earth; and the radius of Planet X is estimated to be twice that of Earth The acceleration due to gravity on the surface of Planet X is gx: The acceleration due to gravity on the surface of Earth is 9E- Which of the following is correct expression? {9e 9x = #9e 9x = {91 9x = YE 29E
The mass of Planet X estirated to be one-half that of Earth; and the radius of Planet X is estimated to be twice that of Earth. The acceleration due to gravity on the surface of Planet X is gx: The correct formula is gx = (1/8)ge.
Let,
The Earth's mass is m.
The Earth's radius is r.
Gravitational acceleration on Earth's surface is equal to ge.
Then,
The answer to the query is
Planet X's mass is equal to (1/2)m.
Planet X's radius is equal to 2r.
gx is the acceleration brought on by gravity on the surface of planet X.
We are aware that the calculation for the gravitational acceleration is
g = GM/R^2
Where,
g = Gravitational acceleration
The gravitational constant is G, which is 6.674*10(11) Nm2/kg2.
M is the planet's mass.
r = Planetary Radius
Currently, for Earth, we have
gₑ = Gm/r^2 ............ (1) (1)
And we have planet X.
gₓ = Gm/2(2r)^2
gₓ = Gm/8r^2 ......... (2) (2)
Equations (1) and (2) are contrasted to obtain
gₑr^2 = 8gₓr^2
gₓ = (1/8)gₑ
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Will a piece of paper produce the same kind of reflection as the mirror? Explain your answer.
Answer:
A piece of paper will not produce the same kind of reflection as a mirror. A mirror is a highly polished, smooth surface that is able to reflect light in a way that produces a clear and detailed image. A piece of paper, on the other hand, is a rough and porous surface that is not able to reflect light in the same way. When light hits a piece of paper, it is absorbed by the fibers and absorbed, scattered, and absorbed again in multiple directions, which produces a diffuse and distorted reflection. Therefore, a piece of paper will not produce the same kind of reflection as a mirror.
A train is approaching you at very high speed as you stand next to the tracks. Just as an observer on the train passes you, you both begin to play the same recorded version of a Beethoven symphony on identical MP3 players. (a) According to you, whose MP3 player finishes the symphony first? (b) What If? According to the observer on the train, whose MP3 player finishes the symphony first?
(c) Whose MP3 player actually finishes the symphony first?
(a) According to you, your player finishes the symphony first.
(b) According to the observer on the train, the observer's player finishes the symphony first.
Because of the variables in the given problem move relative to one another. The person standing next to the track is travelling at a much slower relative speed than the one seated on the train since the train is moving at a much higher speed. In this scenario, the clock that is located in the train will be operating at a slower rate in comparison to the frame of reference that is considered to be stationary.
So, according to you, your player finishes the symphony first. Ans according to the observer on the train, the observer's player finishes the symphony first.
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A football player pushes a 670-N blocking sled. The coefficient of static
friction
between sled and grass is 0.73, and the coefficient of kinetic friction
between sled and grass is 0.68.
a. How much force must the player exert to start the sled in motion?
b. How much force is required to keep the sled in motion?
c. Answer the same two questions with a 100-kg coach standing on the back
of the sled.
The force must the player exert to start the sled in motion and keep it in motion is 489.1 Newtons and 455.6 Newtons;
Given values,
Weight of blocking sled = 670 N
Coefficient of static friction between sled and grass = 0.73
Coefficient of kinetic friction between sled and grass = 0.68
a) Force required to start the sled in motion = Static friction acting on the sled
= coefficient of static friction * weight
= 0.73 * 670
= 489.1 N
b) Force to keep the sled in motion = kinetic friction acting on the sled
= coefficient of kinetic friction * weight
= 0.68 * 670
=455.6N
c) Now,
Total weight = weight of the sled + weight of the coach
where the weight of the coach = mass of the coach * acceleration due to gravity;
= 670 + 100*9.8
=1650
Force required to start the sled and the coach = Static friction acting on the sled and the coach
= 0.73 * 1650
= 1204.5N
Force req to keep the sled and the coach moving = Kinetic friction acting on the sled and the coach
= 0.68 * 1650
= 1122N
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Two isolated particles, A and B, lie along the x-axis. The particles have the same net charge +Q, but different masses with MA > MB. Is there a point along the x-axis where both the net electric field and net gravitational field of the particles are zero, and if so, in what region is the point? (A) Yes, in region I (B) Yes, in region II (C) Yes, in region III. (D) No, there is no point on the z-axis where both the fields are zero.
Net electric field and Net gravitational field both can never be zero at any region. So, option d)No, there is no point on the z-axis where both the fields are zero, is the correct answer.
Since both particles have same charge then electric field and magnitude will be same for both particles because in electric field mass is not responsible. It means that electric field is independent from mass. Electric field is given by
E= [(μ[tex]_o[/tex] /4π)q²] /r²
where q is the charge of both particles and r is the distance between them.
Now, talking about about gravitational field, we get
=>Force between two masses is given by =(G[tex]M_A[/tex][tex]M_B[/tex])/r² where M is the mass of the particle and r is the distance between the particle. Since, mass is different, therefore it can be zero at some point.
Hence, option d is correct.
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two identical masses attached to identical springs with spring constant 33 n/m are coupled by a spring with spring constant l. the antisymmetric and symmetric normal modes have frequencies 15 hz and 12 hz.
If there is no friction and the mass's displacement out of its equilibrium position at x = 0 is "small," the motion of a mass linked to a spring is simple harmonic motion.
How does antisymmetric mode work?Mode of antisymmetry Four. .Both this and the modes mentioned above might have variants.
What are the usual frequency and mode?Free motion is described by its normal modes at specific frequencies.The term "natural" or "resonant frequencies" refers to these fixed frequencies of the a system's normal modes.Natural oscillations of a mass on a spring occur at the a single frequency.
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Find the unit vector in the direction of the vector 6i+8j
The unit vector in the direction of the vector 6i+8j is [tex]\frac{\sqrt{10}}{10} 3i-j[/tex]
Unit vectors are vectors whose magnitude is exactly 1 unit. These unit vectors are commonly used to indicate a direction, with a scalar coefficient providing the magnitude. It is also known as the Direction Vector.
A unit vector x in the direction of x is given by
[tex]x=\frac{x}{|x|}[/tex]
In this case, we have
[tex]|v|=\sqrt{6^{2}+2^{2} }[/tex]
=√40
=2√10
So a unit vector in the direction of v will be equal to as follows
[tex]v=\frac{1}{2\sqrt{10} } 6i-2j[/tex]
Taking 2 as a common from 6i - 2j, we get
[tex]v=\frac{1}{\sqrt{10} } 3i-j[/tex]
To rationalize the denominator, we will multiply √10 in the numerator as well as the denominator. After this, we will get
[tex]\frac{\sqrt{10}}{10} 3i-j[/tex]
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At an instant in time, the electric and magnetic fields of an electromagnetic wave are given by E = -9.13 times 10^3k V/m and B = -3.04 times 10^-11i T. Find the Poynting vector for this wave. (Express your answer in vector form.) S = W/m^2
the pointing vector for the given wave is [tex]219.26*10^{-9}j[/tex]
Electromagnetic waves, or EM waves, are waves produced by oscillations between electric and magnetic fields. In other words, EM waves consist of oscillating magnetic and electric fields.
The electric and magnetic fields of electromagnetic waves are perpendicular (right angles) to each other. They are also perpendicular to the EM wave direction.
S = (1/μ[tex]_{o}[/tex] )E*B ,
where
μ[tex]_{o}[/tex] is the vacuum permeability;
E is the electric field;
B is the magnetic flux density.
And,
1/μ[tex]_{o}[/tex] [tex]= 7.9*10^{5} units[/tex]
so,
[tex]S = 7.9*10^{5} (-9.13*10^{-3} ) *(-3.04*10^{-11} )[/tex] ∵ [tex](kxi = j)[/tex] [tex]S = 219.26*10^{-9} j[/tex]
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What type(s) of mirror form(s) distorted images?
There are several types of mirrors that can produce distorted images, including concave and convex mirrors. Concave mirrors are curved inward and produce a smaller, magnified image that is often distorted around the edges. Convex mirrors are curved outward and produce a larger, distorted image that appears farther away than it actually is. Both types of mirrors are used for a variety of purposes, including in telescopes, cameras, and other optical instruments.
The discharge-suppressing RCD snubber circuit is used for this boost converter. Assume the stray inductance for one switch is 50 nH, the design goal is to limit the voltage overshoot under 100 V at the maximum current. 1 + w a) What is the capacitance you would choose for the snubber? b) What is the total power loss of the full snubber circuit?
Select a capacitor that can resist the impossibly high peak currents produced by snubbers. Dipped mica capacitors should be your first port of call for capacitance levels up to 0.01 F. Look for the Type DPP radial-leaded polypropylene, film/foil capacitors for larger capacitance values.
How is decoupling capacitance calculated?C + I Δt ΔV . Plug the peak current, risetime, and maximum ripple voltage parameters into equation (1), then solve for C to determine the decoupling capacitance. It is safe to presume that the OMAP5910's typical maximum ripple voltage and risetime are 10 mV and 1 ns, respectively.
What does a compressor snubber do?A mechanical snubber is a tool used to shield components from excessive stress or sway brought on by seismic activity or other momentary forces. The snubber permits tension and compression movement under normal working circumstances.
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Immiscible liquids can be separated by using
Answer:
Decantation
Explanation:
Immiscible liquids are liquids that are not able to be mixed together to form a homogenous solution. They can often be separated by using techniques such as decantation, in which the liquids are poured carefully so that they form separate layers, or by using a separating funnel, which allows the liquids to be separated by exploiting their differences in densities. Other methods for separating immiscible liquids include filtration, centrifugation, and distillation.
an athlete getting ready to compete in the 100-meter dash will rely primarily on for quick energy up to 10 seconds.
Athletes training for the 100-meter dash will mostly rely on phosphocreatine for this event's rapid energy.
In skeletal muscle, the heart, and the brain, phosphocreatine, also known as creatine phosphate (CP) or (Pcr),PCr is a phosphorylated version of creatine that acts as a quickly mobilizable reservoir of high-energy phosphates to recycle adenosine triphosphate, the energy currency of the cell.During the initial five to eight seconds of a maximal muscular exertion, phosphocreatine can anaerobically donate a phosphate group to ADP to create ATP. On the other hand, extra ATP can be utilized during a time of less exertion to reverse the conversion of creatine to phosphocreatine.Numerous creatine kinases catalyze the reversible phosphorylation of creatine, which includes both the forward and backward reactions. It is used to detect tissue injury when creatine kinase (CK-MB, creatine kinase myocardial band) is present in blood plasma.
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A cyclist rode at an average speed of 20 mph for 15 miles. How long was the ride? Explain. Correct answers only please and tyyy.
Answer:
15/20 = 3/4. 3/4 hours = 45 minutes.
Explanation:
when the weight is moved downward, the pendulum slows down; when it is moved upward, the pendulum swings faster. if the rod has a mass of 1.23 kg and a length of 1.25 m and
The distance is 1.026 m, the mass be placed to give the pendulum a period of 2.00 seconds.
For complete question?You are at a furniture store and notice that a Grandfather clock has its time regulated by a physical pendulum that consists of a rod with a movable weight on it. When the weight is moved downward, the pendulum slows down; when it is moved upward, the pendulum swings faster. If the rod has a mass of 1.23 kg and a length of 1.25 m and the weight has a mass of [10] kg, where should the mass be placed to give the pendulum a period of 2.00 seconds?
How to solve?mass of rod, M = 1.23 kg
Length, L = 1.25 m
mass, m = 10 kg
Time period, T = 2 s
Let the distance is d.
The formula of the time period is given by,
T=2π√1/3ML²+md²/(M+m)g
2x2=4π2x1/3×1.23×1.25×1.25+10d²/(1.23+10)×9.8
11.16=0.64+10d²
d=1.026m
How is the pendulum determined?You can use the equation L = (T/ 2)2*g to determine the length of a basic pendulum. where g is the acceleration caused by gravity and T is the simple pendulum's period of time.
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A uniform30 cmruler of mass50 gis attached to a friction-less vertical wall by a nail through one end. A horizontal force F=0.545 Nis applied to the end of the rod. If the rod is tilted at 40∘ from the vertical, what is the angular acceleration of the rod (around the nail) at this instant? Please enter a numerical answer below. Accepted formats are numbers or "e" based scientific notation e.g.0.23,−2,1e6, 5.23e-8
The value of the angular acceleration of the rod is approximately equal to 0.0055 rad/s².
To find the angular acceleration of the rod, we need to first determine the torque acting on the rod around the nail. The torque is given by the formula:
torque = force * distance * sin(angle)
Where: 'force' is the applied force F, 'distance' is the distance between the point where the force is applied and the point around which the torque is calculated (in this case, the nail) and 'angle' is the angle between the force and the distance vector
Plugging in the values, we get:
torque = 0.545 N * 30 cm * sin(40°) = 4.14 N cm
We can then use the formula for torque to calculate the angular acceleration:
torque = moment of inertia * angular acceleration
The moment of inertia of a rod about an end is given by:
moment of inertia = mass * length² / 12
Plugging in the values, we get:
moment of inertia = 50 g * (30 cm)² / 12 = 750 g*cm^2
Solving for angular acceleration, we get:
angular acceleration = torque / moment of inertia = 4.14 N cm / 750 gcm² = 0.0055 rad/s².
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strong winds developing high heat outputs in active fire heads. a probable change in wind speed and direction. high winds aloft with the potential to surface. wind may spring back up in a different direction. the direction of fire spread
The direction of fire spread is influenced by the direction of the wind. Strong winds developing high heat outputs in active fire heads can have a dramatic and far reaching effect on the rate and direction of fire spread.
High winds aloft can cause a rapid increase in heat output, as the fire is driven and pushed by the wind towards fuel sources. This can cause the fire to spread quickly, often at a rate faster than the firefighting teams are able to keep up with.
Additionally, with the potential for the wind to surface, the fire can be pushed in unexpected directions. This can cause the fire to spread in unintended directions, making it difficult for firefighters to contain. The wind direction can also influence the rate of spread, as the fire will take a more direct route when pushed in the same direction as the wind.
The wind speed and direction can also change suddenly, causing the fire to spread in yet another unexpected direction. This can cause the fire to spread in multiple directions, making it even more difficult for firefighters to contain.
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The four-wheeler has a weight of 335 lb and a center of gravity at G1, whereas the rider has a weight of 150 lb and a center of gravity at G2. If the engine can develop enough torque to cause the rear wheels to slip, determine the largest coefficient of static friction between the rear wheels and the ground so that the vehicle will accelerate without tipping over. What is this maximum acceleration? In order to increase the acceleration, should the rider crouch down or sit up straight from the position shown? Explain. The front wheels are free to roll. Neglect the mass of the wheels in the calculation.
To increase the acceleration rider should crouch down which decrease the height of CG from Ground & hence increase acceleration since both are Inversely proportional.
At each whee By condition of equilibrium we can find Load
Rear load Wr= 224lb=224*4.45=996.8N
Front load Wf= 261lb=261*4.45=1161.1N
(2.30, 1.62) here the CG of entire mass will be located
CG location Can be found by
x=sum(Wi*xi) /sum(Wi)
Load transfer due to acceleration is given by
DW=m*a*(h/L)
Where h= height of CG= 1.62ft=0.486m
L= wheel base=5ft=1.5m
m= total mass in kg=(335+150) *0.45=212.25kg
For front wheel to be lifted,
dW=Wf
solving we get acceleration value as
a= 16.884m/s² of acceleration will be max for tipping of vehicle.
We known that,
Tractive force = ma
Gives us tractive force as T=212.25*16.88=3582.78N
This will be achieved when friction force at rear end at max tractive condition Tractive force = static friction force.
T= Friction force= (coefficient of friction) *N
Where N= Wf+Wr for tipping condition
Coefficient of friction= 3582.78/(Wf+Wr) =1.72
For tipping of vehicle we need a coefficient of friction greater than & equal to 1.72.
In coefficient of Friction equation I have taken entire weight as normal since during tipping load will be shifted to rear wheel.
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one study gave several suggestions for how much imagery an athlete should practice. which of these was not one of the suggestions?
The one that is not a suggestion is the number of repetitions should remain the same regardless of the sport's skill. The correct option is c.
Who is an athlete?An athlete is someone who practices for and participates in sporting activities, either professionally or just for enjoyment. Examples of athletes include those who bowl for a team, run in neighborhood 5K races or take home an Olympic gold medal.
The biggest advantages of imagery are seen in tasks with mostly cognitive components for increasing the learning and performance of motor abilities.
Therefore, the correct option is c, The number of repetitions should remain the same regardless of the sport skill.
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The question is incomplete. Your most probably complete question is given below:
There should be three to four sessions per week.
Sessions should be around 15 minutes in length.
The number of repetitions should remain the same regardless of the sport skill.
If concentration wanes, break imagery sessions into shorter blocks.
Imagery practice should be systematic.
How does a plastic stopper in a flask help reduce heat loss?
A plastic stopper in a flask can help reduce heat loss in several ways. Some of the main mechanisms by which a plastic stopper can help to reduce heat loss include:
Insulation: A plastic stopper can provide a layer of insulation between the hot liquid inside the flask and the surrounding air. This can help to slow the transfer of heat from the liquid to the air, and can keep the liquid hot for a longer period of time.Airtight seal: A plastic stopper can also create an airtight seal when it is inserted into the neck of the flask. This can help to prevent air from entering the flask, which can reduce heat loss through convection. When air is able to enter the flask, it can circulate around the hot liquid and carry heat away from it. By preventing air from entering the flask, a plastic stopper can help to keep the liquid hot for a longer period of time.Thermal conductivity: In addition, the specific material used for the plastic stopper can also affect its ability to reduce heat loss. Some plastics are better insulators than others, and have a lower thermal conductivity. This means that they can slow the transfer of heat more effectively, and can help to keep the liquid hot for a longer period of time.Overall, a plastic stopper in a flask can help to reduce heat loss by providing insulation, creating an airtight seal, and slowing the transfer of heat through its thermal conductivity. These mechanisms can help to keep the liquid hot for a longer period of time. ;)
water flows through the pipe contraction shown. for the given 0.2-m difference in the manometer level, determine the flowrate as a function of the diameter of the small pipe, d.
The flow rate as a function of diameter is Q^2 = 2.24 × 10^-4×D^4 / 10^-4 - D^4 when 0.2 m difference in the manometer level.
Given: The pipe's diameter at point 1 isD1=0.1 m D1=0.1 m
D2=D at point 2 dia. of pipe
And the pipe's flow rate is Q.
Velocity at point 1, where V1=Q/D12/4.
V1= Q/π×(0.1) (0.1)
^2/ 4
Speed at point 2; V2=Q/D2
^2/ 4
As atmospheric pressure causes pipes 1 and 2 to both open, both are 0; 1 and Bernoulli equation application at point 2
P1/pg+v12/2g+ h1= P2/pg+ v22/2g+ H2, where v12 / 2g+ h1= v2 / 2g+ H2.
Put the velocity and height values in the equation above.
Q^ 2/( π/4)^2×(1/D^4-l/(0.1)^4)= 2×g×(h1-h2) (h1-h2)
Q^2 = 2.24 × 10^-4×D^4 / 10^-4 - D^4
This represents the flow rate as a function of diameter.
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if an object is at a pole, it blank accelerating.target 1 of 6 we can truly write blank, such that the apparent weight is exactly mg .target 2 of 6 at the blank, the object is moving in a very large circular path as the earth rotates.target 3 of 6 this means that technically blank.target 4 of 6 that is, the weight force toward the center of the circular path must be slightly blank so it can provide a centripetal force.target 5 of 6 thus n
The answer related to Equator of following are : 1) is not, 2) n – mg = may = 0, 3) equator, 4) n – mg = may < 0, 5) larger, 6) equator
What is Equator?
The equator, an invisible circle that spans the centre of the planet and runs parallel to it at its widest point, is located halfway between the North and South Poles. The areas of Earth where the equator crosses are among the warmest because they are closest to the sun.
The equator exists in other places besides just Earth. There is an equator on each planet and star in the sky. An invisible line that lies evenly between the two poles of each rotating planet or star, including the sun in our solar system, is referred to as the equator.
The majority of the equator travels across the ocean, as seen in the image below.
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