Answer:
1. -0.863 kgm/s 2. -1.438 kgm/s
Explanation:
1. What is the change in momentum of the bullet if it embeds in the block?
Since the block does not move, the velocity of the bullet after hitting the block , v is zero. That is v = 0 m/s
Now, the momentum change of the bullet ΔP = m(v - u) where m = mass of block = 5.75 g = 5.75 × 10⁻³ kg, u = initial velocity of bullet = 1.50 × 10² m/s and v = final velocity of bullet after hitting the block = 0 m/s (since it embeds in the block and the block does not move).
So, ΔP = m(v - u)
= 5.75 × 10⁻³ kg(0 m/s - 1.50 × 10² m/s)
= 5.75 × 10⁻³ kg(- 1.50 × 10² m/s)
= -8.625 × 10⁻¹ kgm/s
= -0.8625 kgm/s
≅ -0.863 kgm/s
2. What is the change in momentum of the bullet if it bounces off the block in the opposite direction with a speed of 100 m/s?
If it bounces off the block in the opposite direction with a speed of 100 m/s, then its final velocity is v = -100 m/s.
So, our momentum change ΔP' = m(v - u) where m = mass of block = 5.75 g = 5.75 × 10⁻³ kg, u = initial velocity of bullet = 1.50 × 10² m/s and v = final velocity of bullet after hitting the block = -100 m/s = -1 × 10² m/s
So, ΔP = m(v - u)
= 5.75 × 10⁻³ kg(-1 × 10² m/s - 1.50 × 10² m/s)
= 5.75 × 10⁻³ kg(-2.50 × 10² m/s)
= -14.375 × 10⁻¹ kgm/s
= -1.4375 kgm/s
≅ -1.438 kgm/s
9. a. Determine the mass of a football which has a weight of 0.80 N on a planet where the gravitational field strength is 2 N/kg. (3 marks)
Answer:
m = 0.4 [kg]
Explanation:
Weight is considered as a force and this is equal to the product of mass by gravitational acceleration.
[tex]W=m*g\\[/tex]
where:
W = weight = 0.8 [N]
m = mass [kg]
g = gravity acceleration 2[N/kg]
Therefore:
[tex]m=W/g\\m = .8/2\\m = 0.4 [kg][/tex]
What distance is required for a train
to stop if its intial Velocity is 23 m/s
and its deceleration is 0.25m/s (Assume the train decelerates at a constant rate.)
Explanation:
what is time in this question
If the base runner leaves the base before the ball is caught in the outfield, what should the defence do?
Answer:
Well it depends
Explanation:
If the runner leaves the base before
the ball is caught the defence cannot do anything exept
catch the ball if they catch the ball while he is still running he has to get back to the base before they could tag him or the base if they tag him or the base before he can get back to his base he is out if they did not catch the ball the runner can run as long as he wants just cant get taged the defence has to get the ball in as fast as possible to get the runner out.
a b c or d for not heat
Answer:
a
Explanation:
How many protons will every atom of Carbon (C) have?
14
12
13
6
Answer:
6 protons
Explanation:
Following through when hitting a baseball
According to Einstein's famous formula, the relationship between mass and energy can be written E = M ∙ c2, where E = energy in joules, m = mass in kilograms and c = speed of light in meters per second. Sweden's annual energy use amounts to approximately 1.35 ∙ 10 up tp 18J. Suppose that all this energy could be created by converting matter into energy. If so, how much mass would be needed to cover the country's annual energy use?
The speed of light is 3 ∙ 10 up to 8 m / s
Answer:
the amount of mass needed is: 4.5 10^9 kg
Explanation:
Use the given equation:
E = m * c^2
with E = 1.35 * 10^(18) J
and c = 3 * 10^8 m/s
and solve for the mass as shown below:
m = 1.35 * 10^(18) / 3 * 10^8 ≈ 4.5 10^9 kg
A 5 kg ball of clay is moving with a speed of 25 m/s directly toward a 10 kg ball of clay which is at rest. The two clay balls collide and stick together. What is their velocity immediately after the collision?
Answer:
8.3m/s
Explanation:
Given parameters:
mass of clay ball = 5kg
Speed of clay ball = 25m/s
mass of clay ball at rest = 10kg
speed of clay ball at rest = 0m/s
Unknown:
Velocity after collision = ?
Solution:
Since the balls stick together, this is an inelastic collision:
m1v1 + m2v2 = v(m1 + m2)
5(25) + 10(0) = v (5 + 10)
125 = 15v
v = 8.3m/s
A device that makes energy easier is a machine. true or false
Answer:
trueeeeeeeeeeeeeeeeee
dew forms when humid air cools overnight. if the temperature falls below freezing, blank will form instead
What part of a motor causes its electromagnet to turn in the same direction
consistently, transforming electrical energy into mechanical energy?
A. Commutator
B. Loop of wire
C. Permanent magnets
D. Battery
PLS HELP
Answer:
A. Commutator
Explanation:
Commutator is part of a motor causes its electromagnet to turn in the same direction consistently, transforming electrical energy into mechanical energy.
What is energy?Energy is the ability or capability to do tasks, such as the ability to move an item (of a certain mass) by exerting force. Energy can exist in many different forms, including electrical, mechanical, chemical, thermal, or nuclear, and it can change its form.
A commutator is a rotary electrical switch in certain types of electric motors and electrical generators.
Commutator is part of a motor causes its electromagnet to turn in the same direction consistently, transforming electrical energy into mechanical energy.
To learn more about energy refer to the link:
brainly.com/question/1932868
#SPJ5
PLEASE HELP ILL GIVE BRAIN
Answer:
1) 500m
2) 60s
3) 8,33 m/s
Answer:
[tex]500\:\mathrm{m}\\60\:\mathrm{s}\\8.\bar{3}\:\mathrm{m/s}}[/tex]
Explanation:
The total distance travelled is shown on the graph to be [tex]\fbox{$500\:\mathrm{m}$}[/tex].
The total is shown on the graph to be [tex]\fbox{$60\:\mathrm{s}$}[/tex].
Average speed is given by [tex]S=\frac{d}{t}[/tex], where [tex]d[/tex] is the total distance travelled and [tex]t[/tex] is time.
Therefore, the average speed is:
[tex]S=\frac{500}{60}=\fbox{$8.\bar{3}$\:\mathrm{m/s}}[/tex].
Compare between Convex lens and concave lens
Answer:
A convex lens or converging lens focuses the light rays to a specific point whereas a concave lens or diverging lens diverges the light rays. When these lenses are combined, they produce sharper images. Most of the eyeglass lenses use combinations of convex and concave lenses.
You slide a 15 kg box down a ramp with friction set to an angle of 38°. If the height of the ramp is 1.2 m, what's the frictional force on the box as it gets to the bottom of the ramp if the applied force down the ramp is 52 N?
Answer:
38.75N
Explanation:
According to Newton's second law
\sum Fx = ma
Fm-Ff = ma
Fm is the moving force
Fm = mgsin theta
Fm = 15(9.8)sin38
Fm = 90.5N
Ff is the frictional force
m is the mass = 15kg
a is two acceleration
Get the acceleration
a= F/m
a = 52/15
a ,= 3.45m/s²
Substitute the given values into the formula
90.5-Ff = 15(3.45)
90.5-Ff = 51.75
Ff = 90.5-51.75
Ff = 38.75N
Hence the frictional force on the box is 38.75N
An empty airplane with a mass of 200,000 kg must have a speed of 82 m/s to achieve takeoff. Once it is fully loaded, the airplane has a mass of 350,000 kg. It has 3200 m of runway. a) How much force is needed to get the full airplane safely in the air?
b) How much runway would the empty airplane use if its engines generated the same force?
Answer:
a) A force of 367718.75 newtons is needed to get the full airplane safely in the air.
b) The empty airplane would need a runway of 1828.571 meters.
Explanation:
a) This problem can be solved by using the Work-Energy Theorem, which states that work needed by the airplane to get minimum speed is equal to its change in translational kinetic energy, both measured in joules. The resulting formula is presented below:
[tex]F\cdot \Delta s = \frac{1}{2}\cdot m \cdot (v_{f}^{2}-v_{o}^{2})[/tex] (1)
Where:
[tex]F[/tex] - Minimum net force, measured in newtons.
[tex]\Delta s[/tex] - Runway length, measured in meters.
[tex]m[/tex] - Mass of the airplane, measured in kilograms.
[tex]v_{o}[/tex], [tex]v_{f}[/tex] - Initial and final speeds of the airplane, measured in meters per second.
If we know that [tex]m = 350000\,kg[/tex], [tex]v_{o} = 0\,\frac{m}{s}[/tex], [tex]v_{f} = 82\,\frac{m}{s}[/tex] and [tex]\Delta s = 3200\,m[/tex], then the minimum net force needed by the airplane to get itself safely in the air:
[tex]F = \frac{m\cdot (v_{f}^{2}-v_{o}^{2})}{2\cdot \Delta s}[/tex]
[tex]F = \frac{(350000\,kg)\cdot \left[\left(82\,\frac{m}{s} \right)^{2}-\left(0\,\frac{m}{s} \right)^{2}\right]}{2\cdot (3200\,m)}[/tex]
[tex]F = 367718.75\,N[/tex]
A force of 367718.75 newtons is needed to get the full airplane safely in the air.
b) If we know that [tex]m = 200000\,kg[/tex], [tex]v_{o} = 0\,\frac{m}{s}[/tex], [tex]v_{f} = 82\,\frac{m}{s}[/tex] and [tex]F = 367718.75\,N[/tex], then the length of the runway is:
[tex]\Delta s = \frac{m\cdot (v_{f}^{2}-v_{o}^{2})}{2\cdot F}[/tex]
[tex]\Delta s = \frac{(200000\,kg)\cdot \left[\left(82\,\frac{m}{s} \right)^{2}-\left(0\,\frac{m}{s} \right)^{2}\right]}{2\cdot (367718.75\,N)}[/tex]
[tex]\Delta s = 1828.571\,m[/tex]
The empty airplane would need a runway of 1828.571 meters.
which wave carries the highest energy?
Answer:
Gamma rays
Explanation:
Variation in which characteristic would best help bison surviv a harsh winter?
A car starts from rest and accelerates at a constant rate of 3.5 m/s2. What is the car’s velocity after the car has traveled 800 m?
Answer:
Attached is the answer
Explanation:
The car’s velocity after the car has traveled 800 m is 74.83 m/sec.
What is velocity?When an item is moving, its velocity is the rate at which its direction is changing as seen from a certain point of view and as measured by a specific unit of time.
Using equation of motion, initial velocity u = 0 and acceleration a = 3.5 unit and distance travelled is 800 m.
v² = u² + 2as
v² = 0 + 2*3.5*800
v² = 5600
v = 74.83 m/sec
The car’s velocity after the car has traveled 800 m is 74.83 m/sec.
To learn more about velocity refer to the link
brainly.com/question/18084516
#SPJ2
PLZ PLZ PLZ PLZ PLZ PLZ PLZ HELPPPPPPPPPPPPPPPPP
Answer:
endoplasmic reticulum
Please help me this is worth allot
Microwaves are sent through a material causing the molecules in the material to twist and vibrate, causing the material to heat up. What is this twisting and vibration of the molecules creating heat an example of?(1 point)
a macroscopic change creating a macroscopic output
a microscopic change creating a macroscopic output
a macroscopic change creating a microscopic output
a microscopic change creating a microscopic output
Answer: The answer is C
Explanation:
4- Protein foods?? pls answer these i really need these
The #1 answer would be meats and eggs. But, as a veggan, I present you with meatless protien-rich food!
1 - Pea protein (used in Beyond Meat, which tastes just like meat btw!)
2 - Soy protein such as tofu
3 - Nuts
4 - Beans! oml so many beans have MORE protien than meat!! ikr!?!?
may I have Brainliest pls =)
A 30 kg dog runs at a speed of 15
What is the dog's kinetic energy?
aluminum has a density of 270 kg/m3. what volume of aluminum would have a mass of 49.9 kg?
(unit = m^3)
0.184[tex]m^{3}[/tex] is the answer for Acellus students!
A force is exerted on a box an an equal and opposite force is exerted by the box. what explains this?
Answer: What is the force that opposes motion between two surfaces in contact with each ... How is the relationship among mass, force and acceleration explained? ... When a force is exerted on a box, an equal and opposite force is exerted by the box.
A cell of e.m.f 1.5 v and internal resistance 2.5 ohm is connected in series with an ammeter of resistance 0.5 ohm and a resistor of resistance 7.0 ohm. Calculate the current in the circuit.
Answer:
The current in the circuit is 0.15 Ampere
Explanation:
The given parameters of the cell are;
The electromotive force (e.m.f.) of the cell, E = 1.5 V
The resistance of the cell, r = 2.5 ohm
The resistance of the ammeter = 0.5 ohm
The resistance of the resistor = 7.0 ohm
The formula for the e.m.f., E of a cell is given as follows;
e.m.f. E = I·(R + r)
Where;
I = The current in the circuit
R = The sum of the resistances in the circuit = 7.0 Ω + 0.5 Ω + 2.5 Ω = 10 Ω
Therefore, we have;
[tex]The \ current \ in \ the \ circuit, \ I = \dfrac{E}{R + r}[/tex]
Substituting the known values, gives;
[tex]I = \dfrac{1.5 \ V}{7 \ \Omega + 0.5 \ \Omega + 2.5 \ \Omega} = \dfrac{1.5 \ V}{10 \ \Omega} = 0.15 \ A[/tex]
The current in the circuit, I = 0.15 Ampere.
The difference between temperature and thermal energy is that___________.
Answer:
Heat vs temperature - Energy Education The core difference is that heat deals with thermal energy, whereas temperature is more concerned with molecular kinetic energy. Heat is the transfer of thermal energy, whereas temperature is a property the object exhibits.
A 5.0\, \text {kg}5.0kg5, point, 0, start text, k, g, end text box is at rest on a table. The static friction coefficient \mu_sμ
s
mu, start subscript, s, end subscript between the box and table is 0.500.500, point, 50, and the kinetic friction coefficient \mu_kμ
k
mu, start subscript, k, end subscript is 0.300.300, point, 30. Then, a 20\,\text N20N20, start text, N, end text horizontal force is applied to the box.
What is the best estimate of the magnitude of the box’s acceleration?
Answer:
25 N
Explanation:
When a force is applied to an object, for it to move it has to overcome the frictional force. The frictional force is perpendicular to the surface on which it acts. For an object at rest, it is acted upon by static friction, this friction must be overcome before the object can move, while a moving object is resisted by kinetic friction that prevents it from moving.
Since the box is at rest, it is acted upon by a static friction.
mass = 5 kg, acceleration due to gravity = 10 m/s², static friction coefficient = 0.5
Weight of the box = mass * acceleration due to gravity = 5 * 10 = 50 N
The applied horizontal force (F) is:
[tex]F=\mu_s*weight=0.5*50\\\\F=25\ N[/tex]
Answer:
0 m/s^2
Explanation:
khan academy
A person runs 15.0 km north then turns around and runs 10.0 Km south. what is his dstance
Answer:
25km
Explanation:
The person runs 15km Northward
Turns around and runs 10km southward
The distance is the length of path covered by the person running.
This is given as:
Distance = Distance North + Distance South
Distance = 15km + 10km = 25km
Answer:
25km
Explanation:
cant explain but ik
An object moving at a constant velocity accelerates at a constant rate of 2.5 m/s2 for a distance of 30 m. At the end of the acceleration the object has a velocity of 90 m/s. What was its velocity before accelerating?
Answer:
The initial velocity is 89.16m/s
Attached is the solution
Explanation: