A 55.0-kg person steps on a scale which is on a horizontal floor. What is the normal force acting on the individual by the scale?

Based on the structure of the element shown, the element belongs to group 2A of the periodic table.

Families of elements in the periodic table refer to the elements that are found in the same vertical column in the periodic table.

The families of elements in the periodic table are also called groups.

Elements belonging to the same family in the periodic table have similarities in their properties, both physical and chemical.

The group or family to which an element belongs to depends on the number of electrons found in the valence shell of the element.

Elements in the same group have the same number of electrons in their valence shells. For example, elements in group 1A of the periodic table have one valence electron in their valence shell.

Considering the given element;

The element has three electron shells.

In the valence or outermost shell, there are 2 electrons in the atom of the element. This means that the element would belong to the family of elements that have two valence electrons, group 2A.

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The RC circuit, which is utilized in this experiment, is one of the most basic circuits that make use of a capacitor. When two conductors are linked to a charging device, the charge is passed from one conductor to the other.

When two conductors are connected to a charging device (such as a battery), the charge is transferred from one conductor to the other until the potential difference between the terminals of the charging device and the potential difference between the conductors are equal.

Capacitors are objects that have the capacity to hold electrical charge and energy. Capacitors have a wide range of uses, such as filters in DC power supplies and energy banks for pulsed lasers. Since capacitors only pass AC current and not DC current, they are used to block the DC component of a signal so that the AC component of the signal may be detected.

Plasma physics makes use of the energy-storage capabilities of capacitors. In plasma physics, short energy bursts with extremely high voltages and currents are frequently needed. A capacitor can be softly charged to the necessary voltage and then quickly discharged to yield the necessary energy.

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Syncopation in music is the off-beating of all or a portion of a tune or piece of music by combining different rhythms. Adding syncopation is NOT a way to change a rhythm.

Syncopation in music is the off-beating of all or a portion of a tune or piece of music by combining different rhythms. Syncopation can be defined more simply as "a disruption or interruption of the regular flow of rhythm" or "the placement of rhythmic stresses or accents where they wouldn't normally occur."

By challenging our perceptions of where the beat should be, syncopation adds excitement to the music. When every note falls on the anticipated beat, this groove-inducing technique departs from the straight feel. Syncopation also draws the listener's attention. Syncopation is NOT a method of altering rhythm.

Therefore, the correct answer is option A. Adding syncopation.

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Answer:

See below

Explanation:

INTAKE   -   compression   -    power    -   exhaust    for a 4 stroke engine

Answer:  intake

Explanation:

I took the quiz.

Answer:

F=ma

=60×1

=60N

Explanation:

straightforward formula

Considering the energy systems:

Energy is the ability to do work.

There are several forms of energy such as:

Generally, all matter possesses energy that can be used to do work.

The various forms of energy can be interconverted.

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When a car brakes hard and skids, the maximum deceleration is 3.1m/s^2. The coefficient of friction between the tires and the road is [tex]\mu=0.61[/tex].

This is further explained below.

Let us assume that the mass of the vehicle is m, and that the coefficient of friction between the tires and the road is mu.

We have determined this by using Newton's second rule of motion.

f=m a

[tex]\mu[/tex]m g=m a

[tex]&\mu=\frac{a}{g}[/tex]

[tex]&a=6 \mathrm{~m} / \mathrm{s}^2 \\\\&g=9.8 \mathrm{~m} / \mathrm{s}^2 \\[/tex]

Therefore

[tex]\mu=\frac{6}{9.8}[/tex]

[tex]\mu=0.61[/tex]

In conclusion,0.61 is the value of the coefficient of friction that exists between the tires and the vehicle.

[tex]\mu=0.61[/tex]

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Answer:

W = 5593.3 J

Explanation:

The work can be calculated as

W = Fdcosθ

Where F is the force, d is the distance and θ is the angle.

So, replacing F = 156N, d = 45.5 m and θ = 38, we get:

W = (156N)(45.5m)(cos38)

W = (156N)(45.5m)(0.788)

W = 5593.3 J

In states of matter, Solid has definite shape and volume, liquid has no shape but have definite volume, gas and plasma has no shape as well as no volume.

A solid has a definite shape and volume, liquid has a definite volume, but has no specific shape. A gas has no defined shape or has no volume. Plasma is similar to a gas but a gas is neutral whereas plasma has a charge. Solids and liquids have a definite volume. Gases and plasma have no definite volume. The force of attraction between the molecules of solid is maximum, less in liquid, least in gases and very less in plasma. Gas vibrate and move freely at very high speeds. liquid vibrate and slide past each other. Solid vibrate but do not move from place to place.

So we can conclude that solid has shape and volume, liquid has volume but no shape, gas and plasma has no shape and no volume.

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If a knife is dropped from 15.0 m high on a ship moving at 1.73 m / s

For an observer on the ship, it will appear as the knife is falling straight down. So, for an observer on the ship, the knife will not have a horizontal component.

u = 0

a = - 9.8 m / s²

s = - 15 m

v² = u² + 2 a s

v² = 0 + ( 2 * - 9.8 * - 15 )

v² = 294

v = ± 17.15 m / s

[tex]v_{y}[/tex] = - 17.15 m / s ( Since it is moving downwards )

For an stationary observer on the shore, it will appear as the knife moves a certain distance along with the ship in x direction along with its y displacement. So, for an observer on the shore, the knife will have both horizontal and vertical components.

[tex]v_{i}_{x}[/tex] = - 1.73 m / s

[tex]a_{x}[/tex] = 0

[tex]v_{x}[/tex] = - 1.73 m / s

R = √ [tex]v_{x}[/tex]² + [tex]v_{y}[/tex]²

R = √ ( - 1.73 )² + ( - 17.15 )²

R = √ 2.99 + 294.12

R = √ 297.11

R = 17.24 m / s

For an observer on the ship, the knife and the ship doesn't have any x component. So the position the knife lands is straight below the point it was dropped. For an observer on the shore, it seems that both the knife and ship have an equal amount of x-component. From the point of view also, the position the knife lands is straight below the point it was dropped.

Therefore,

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The gravitational force between the sun and the earth will become 16 times of the original force if distance between the Earth and Sun were decreased by a factor of 4.

The universal law of gravitational states that the force of attraction between two masses is directly proportional to product of their masses and inversely proportional to the square of the distance between them.

Given are the Earth and Sun and the distance between them is decreased by a factor of 4.

Assume that the mass of sun is m[S] and that of earth is m[E] and the distance between them be R. Then the gravitational force of attraction would be -

F [1] = Gm[S]m[E]/R²

If the distance is decreased by the factor of 4, then we can write -

F [2] = Gm[S]m[E]/(R/4)²

Now,

F[1]/F[2] = {Gm[S]m[E]/R²}/{Gm[S]m[E]/(R/4)²}

F[1]/F[2] = (R/4)²/R²

F[1]/F[2] = (R²/16)/R²

F[1] /F[2] = 1/16

F[2] = 16 F[1]

Therefore, the gravitational force between the sun and the earth will become 16 times of the original force if distance between the Earth and Sun were decreased by a factor of 4.

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Given data:

The mass of the first weight is

second

The mass of the third weight is

The mass of the fourth weight is

The force on the spring can be expressed as,

Here, g is the acceleration due to gravity which is considered as a constant value.

The force on the spring depends on the mass of each weight. Higher is the weight then more will be the force on each spring.

,

The mass relation for each weight can be given as:

The relationship between the forces acts on the spring can be given as,

Here, suffixes (1,2,3, and 4) numbers related to the first, second, third, and fourth weights.Thus, the relationship of the force on the spring is

Here, x is the stretch of the spring and k is the spring constant.

The stretch of the spring depends on the force of the spring.

The stretch of the spring relationship for the given weights can be given as:

Thus, the relationship of the stretch of the spring is

121 m far up the hill does he go.

Vo = 31.3 m/s

Angle [tex]\theta[/tex] = [tex]20^o[/tex]

Yo = 31.3*sin20

     = 28.57 m/s.

[tex]Y^2 = Yo^2 + 2g*h = 0.[/tex]

[tex]28.57^2 - 19.6h = 0 \\19.6h = 816.4\\ h = 41.6 m.[/tex]

[tex]d*sin20 = 41.6\\ d = 121 m. -- > up \ hill.[/tex]

Friction is a force that opposes the relative motion of solid surfaces, fluid layers and material elements that slide against each other.

There are four types of friction and they are classified as follows:

Applications of friction

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The period of the revolution as obtained from the question is 3.95 years.

We know that the solar system is composed of the sun and the planets. The sun is at the center of the solar system and the sun is surrounded by the planets which tend to form concentric circles.

From the Kepler's laws, we can see that the square of the  period is directly proportional to the cube of the radius of the planet;

Hence;

T^2 α r^3

T = period

r = distance

T = r^3/3

T = (2.5)^3/2

T = 3.95 years

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A skier has just begun descending a 20° slope, so the Acceleration of the skier will be -4.7 m/s².

Average velocity is a vector quantity. The change in position or displacement divided by the periods during which the displacement happens is known as average velocity. Depending on how the displacement is displaced, the average velocity may be positive or negative. Meters per second (m/s), the SI unit of average velocity, is used.

Average Velocity= [tex]Total\ Displacement/ Total\ Time[/tex]

According to the question,

Skier is on a 20° down slope.

Portion of weight parallel to and down slope.

f₁ = (sin20°)mg = 0.3 × mg

The friction force resists motion parallel to the slope, therefore its sign is opposite that of f1, and it is equal to the kinetic coefficient of friction times the weight's surface normal component.

f₂ = -μ(cos30°)mg = -0.9*0.8660 × mg

f₂ = -0.7794 × mg

The net force on the skier parallel to and down the slope

F = f₁ + f₂ = (0.3 -0.7794)mg

F = -0.4794 × mg

By Newton’s second law, net acceleration parallel to and down slope.

a = F/m = -0.4794 × g

For g = 9.807 m/s²,

a = -0.4794 × 9.807 = -4.7 m/s².

So, the acceleration of the skier will be -4.7 m/s².

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Answer:

Explanation what does a closed circuit need to work?

Closed Circuit: In a closed circuit, the connected source and load form a closed-loop path. We need a switch to make (ON) and break (OFF) the circuit for the electrical and electronic circuits to work (open circuit and closed circuit).

We can use the following equation to solve for V, voltage:

V = IR, where

I: current, and R: resistance

Let's plug in our known variables, current and resistance:

V = 4.5*100

Then solve for V:

V = 450V

The magnitude of the tension in the cable is determined as 49 N.

Force of tension is defined as the force transmitted through a rope, string or wire when pulled by forces acting from opposite sides.

The upward tension of the cable is equal to the downward weight of the beam.

Mathematically, the formula for calculating the tension in the cable is calculated as follows;

T  = W sinθ

where;

T = mg sinθ

Substitute the given parameters and solve for the tension,

T = (10 kg x 9.8 m/s²) x sin(30⁰)

T = 49 N

Thus, we can conclude that the tension in the cable as it bears the full weight of the beam is 49 N.

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The maximum horizontal range of the projectile is 91.8 m.

The maximum horizontal range of a projectile is the maximum horizontal distance travelled by the projectile.

Mathematically, the horizontal range of a projectile is given as;

R = u² sin(2θ) / g

where;

R = (30² x sin(2 x 45))/9.8

R = 91.8 m

Thus, we can conclude that the maximum horizontal distance travelled by the projectile occurs when the angle of projection is 45 degrees.

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The radial acceleration of the ball of mass 1.2 kg that is suspended by two wires from a horizontal arm, which is attached to a vertical shaft is 4.9 m / s²

Since the wires form a right angled triangle with the horizontal arm,

tan θ = Opposite side / Adjacent side

tan θ = 0.6 / 0.8

θ = [tex]tan^{-1}[/tex] ( 0.75 )

θ = 36.9°

m = 1.2 kg

W = m g

W = 1.2 * 9.8

W = 11.76 N

T1 = T2 = T

∑ [tex]F_{y}[/tex] = 0

T1 + T2 sin θ - W = 0

T + T sin 36.9° - 11.76 = 0

T + 0.6 T = 11.76

T = 11.76 / 1.6

T = 7.35 N

[tex]F_{c}[/tex] = m v² / r

[tex]F_{c}[/tex] = Centripetal force

∑ [tex]F_{x}[/tex] = m v² / r

T cos 36.9° = m * [tex]a_{r}[/tex]

[tex]a_{r}[/tex] = 7.35 * 0.8 / 1.2

[tex]a_{r}[/tex] = 4.9 m / s²

Therefore, the radial acceleration of the ball = 4.9 m / s²

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At the given coefficient of friction of the ramp, the acceleration is 0.97 m/s².

The time taken for the block to travel down the ramp is 6.42 s.

The acceleration of the block is calculated as follows;

Apply Newton's second law of motion to determine the acceleration of the block.

μmgcos(θ) = ma

μgcos(θ) = a

where;

a = (0.1)(9.8) cos(10)

a = 0.97 m/s²

The time taken for the block to travel down the inclined plane is calculated as follows;

s = vt + ¹/₂at²

where;

20 = 0 + ¹/₂(0.97)t²

40 = 0.97t²

t² = 40/0.97

t² = 41.24

t = √41.24

t = 6.42 seconds

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The percentage error in a steel tape used for measurement on a cold day when the temperature is -5 ℃ is - 0.028

Coefficient of linear thermal expansion for steel, α = 1.1 * [tex]10^{-5}[/tex] / C

Let the length of the tape at 20 ℃ be L.

New length of the steel tape after cooling, L' = L ( 1 + α ΔT )

ΔL = L' - L

ΔL = L ( 1 + α ΔT ) - L

ΔL = L ( 1 + α ΔT - 1 )

ΔL = L α ΔT

ΔT = T - [tex]T_{0}[/tex]

T = Final temperature

[tex]T_{0}[/tex] = Initial temperature

ΔT = - 5 - 20

ΔT = - 25 ℃

ΔL = L * 1.1 * [tex]10^{-5}[/tex] * ( - 25 )

ΔL = - 27.5 * [tex]10^{-5}[/tex]  * L

Percentage error = ΔL / L * 100

Percentage error =  - 27.5 * [tex]10^{-5}[/tex]  * L / L * 100

Percentage error =  - 0.028

Therefore, the percentage error in the steel tape is - 0.028

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The speed of Indiana Jones if he jumps from a 9.0 m high cliff and lands at the edge of a ledge that is 1.75 m from the cliff is 1.29 m / s

From the equations of motion,

s = ut + 1 / 2 at²

In vertical motion,

s = 9 m

u = 0

a = 9.8 m / s²

9 = 0 + ( 1 / 2 * 9.8 * t² )

t² = 1.84

t = 1.36 s

In horizontal motion,

a = 0

s = 1.75 m

1.75 = ( u * 1.36 ) + 0

u = 1.75 / 1.36

u = 1.29 m / s

Therefore, Indiana jones is running at a speed of 1.29 m / s

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The surface charge density on the disk is 1.73 x 10⁻⁸ C/m².

The surface charge density of the glass is 9.36 x 10⁻⁵ C/m²

The magnitude of the charge is calculated as follows;

V = kQ/r

where;

kQ = Vr

Q = Vr/k

Q = (1800 x 0.68 x 10⁻³) / (9 x 10⁹)

Q = 1.36 x 10⁻¹⁰ C

The surface charge density of the disk is calculated as follows;

σ = Q/A

σ = Q/(4πr²)

where;

σ = Q/(4πr²)

σ = (1.36 x 10⁻¹⁰ )/(4π x 0.025²)

σ = 1.73 x 10⁻⁸ C/m²

The surface charge density of the glass is calculated as follows;

σ = Q/A

σ = Q/(4πr²)

where;

σ = Q/(4πr²)

σ = (1.36 x 10⁻¹⁰ )/(4π x 0.00034²)

σ = 9.36 x 10⁻⁵ C/m²

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The energy needed to raise the temperature of 1 kg of lead from 40 °C to 60°C will be 2600 Joules.

We can calculate the energy of a substance by using the given formula:

Q = mc∆T

where;

Q = quantity of heat absorbed or released

m = mass of the substance

c = specific heat capacity

∆T = change in temperature(°C)

Now, according to the given question, 1 kg of lead has to be raised from 40°C to 60°C and we also have the specific heat capacity(c) of lead that is 130J/kg°C.

We can calculate the energy by putting the given values in the above equation:

Q = mc∆T

= 1 × 130 × (60-40)

= 20 × 130

Q = 2600J

Therefore, the amount of energy required to raise the temperature of 1 kg of lead from 40°C to 60°C is 2600J.

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Question 5

Given:

Ball 1 has negative charge.

Ball 2 is repelled by ball 1.

Ball 2 repels ball 3.

Ball 3 attracts ball 4.

To find the electric charge on ball 4.

Explanation:

Like charges repel each other.

Example - Positive and positive charge repel each other.

Also, negative and negative charge repel each other.

Unlike charges attract each other.

Positive and negative charge attract each other.

In the first diagram, ball 1 and ball 2 repel each other which means ball 2 has negative charge.

In the second diagram, ball 2 and ball 3 repel each other which means ball 3 has negative charge.

Now, in the diagram 3, ball 3 and ball 4 attract each other which means ball 4 has positive charge.

Thus, ball 4 has positive charge.

Answer:

Explanation:

tg α = V₂ / V₁ = 3 / 5 = 0.6

α ≈ 31°

Answer: w=1.84 rad/s

Explanation:  

During the experiment, the angular velocity will be allowed to vary. If the mass of the rotating object is 5 kg and the radius of rotation is 0.2 m, what will be the angular velocity, ω, when the force sensor reads 3.4 N?

first we set 3.4N = to the equation [tex]5kg(w)^{2}* .20[/tex]

solving for w [tex]w^2=17/5[/tex]

[tex]w=(\sqrt{85})/5 \\[/tex]

[tex]w=1.84391[/tex]

w=1.84 rad/s

The average acceleration of the MX missile is 87.5 m/s^2. The average acceleration in multiples of g is 8.9g.

The rate at which the velocity changes is known to as average acceleration. To determine the average acceleration of an object, we divide the change in velocity by the amount of time that has passed. The formula of acceleration is,

a = (v_f - v_i)/t

Where a = acceleration, v_f = final velocity, v_i = initial velocity and t = time.

Here, the initial velocity is zero, final velocity is 3.5 km/s and time is 40.0 seconds. The acceleration will be

a = (3.50*1000 - 0)/40.0

a = 3500/40

a = 87.5 m/s^2

The value of acceleration due to gravity (g) is 9.8 m/s^2. The acceleration of the MS missile in multiples of g is,

a = 87.5/9.8

a = 8.9g

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Given:

The speed of Mario's kart is

To find:

How far does he drive in 1.7 minutes?

Explanation:

The speed is,

The distance Mario drives is,

Hence, the required distance is 1.90 km.