The magnitude of the horizontal force acting on the sprinter is 56 N, the sprinter's power output at 2.0 s is 125.44 W, at 4.0 s is 251.68 W, and at 6.0 s is 376.32 W.
a. To find the magnitude of the horizontal force acting on the sprinter, we can use the following kinematic equation:
[tex]d = 0.5 * a * t^2[/tex]
where d is the distance traveled (50m), t is the time taken (7.0s), and a is the acceleration of the sprinter.
Solving for a, we get:
[tex]a = 2 * d / t^2[/tex]
[tex]= 2 * 50m / (7.0s)^2[/tex]
[tex]= 1.12 m/s^2[/tex]
Next, we can use Newton's second law of motion, which states that the net force acting on an object is equal to its mass times its acceleration:
F_net = m * a
Substituting the values, we get:
[tex]F_net =[/tex][tex]50kg * 1.12 m/s^2[/tex]
= 56 N
Therefore, the magnitude of the horizontal force acting on the sprinter is 56 N.
b. The power output of the sprinter can be calculated using the following formula:
P = F * v
where P is the power, F is the force, and v is the velocity.
At 2.0 s:
The sprinter's velocity can be found using the following kinematic equation:
v = a * t
where a is the acceleration found earlier [tex](1.12 m/s^2)[/tex], and t is the time taken (2.0 s).
Substituting the values, we get:
[tex]v = 1.12 m/s^2 * 2.0 s= 2.24 m/s[/tex]
Using the formula for power, we get:
[tex]P = 56 N * 2.24 m/s= 125.44 W[/tex]
Therefore, the sprinter's power output at 2.0 s is 125.44 W.
At 4.0 s:
The sprinter's velocity can be found using the same kinematic equation as before:
v = a * t
Substituting the values, we get:
[tex]v = 1.12 m/s^2 * 4.0 s= 4.48 m/s[/tex]
Using the formula for power, we get:
[tex]P = 56 N * 4.48 m/s= 251.68 W[/tex]
Therefore, the sprinter's power output at 4.0 s is 251.68 W.
At 6.0 s:
The sprinter's velocity can be found using the same kinematic equation as before:
v = a * t
Substituting the values, we get:
[tex]v = 1.12 m/s^2 * 6.0 s= 6.72 m/s[/tex]
Using the formula for power, we get:
[tex]P = 56 N * 6.72 m/s= 376.32 W[/tex]
Therefore, the sprinter's power output at 6.0 s is 376.32 W.
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How are rising sea levels and rising ocean temperatures connected? (1 point)
O At higher temperatures, the density of water also increases.
O At higher temperatures, the ocean begins to fill quickly with algae.
O At higher temperatures, the ocean melts ice caps faster.
O At higher temperatures, water evaporates from the surface of the ocean faster.
As temperatures rise, the Earth's ice caps and glaciers begin to melt, which increases the volume of water in the ocean and causes sea levels to rise. The correct answer is option: 3.
This melting is caused by the increased heat energy absorbed by the Earth's atmosphere, which is largely the result of human activity and the burning of fossil fuels. Rising ocean temperatures can also contribute to the melting of ice caps, as warmer water can flow beneath them and cause them to melt from the bottom up. Additionally, warmer water can expand in volume, which also contributes to rising sea levels. Hence option: 3 is correct.
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--The complete Question is, How are rising sea levels and rising ocean temperatures connected? (1 point)
At higher temperatures, the density of water also increases.At higher temperatures, the ocean begins to fill quickly with algae.At higher temperatures, the ocean melts ice caps faster.At higher temperatures, water evaporates from the surface of the ocean faster. --a student wants to construct an inductor of a given inductance using copper wire and a plastic tube. if a sufficient supply of copper wire is available, the student will also need a
To construct an inductor of a given inductance using copper wire and a plastic tube, the student will also need a magnetic core.
An inductor is a passive electronic component that is used to store energy in a magnetic field. It consists of a coil of wire wound around a magnetic core, which is usually made of a ferromagnetic material such as iron or ferrite. The magnetic core enhances the magnetic field created by the coil and increases the inductance of the inductor.
The plastic tube can be used to create a form for the coil of wire. The copper wire will be wound around the plastic tube to create the coil. However, without a magnetic core, the inductance of the coil will be very low, and it may not function as an inductor at all.
The choice of magnetic core material will depend on the specific application and the frequency range of the circuit. In some cases, air can be used as the core material, but in most cases, a magnetic material is required to achieve the desired level of inductance.
In summary, to construct an inductor of a given inductance using copper wire and a plastic tube, the student will need a magnetic core in addition to the copper wire and plastic tube.
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36. A block and tackle pulley must lift a box with 50 N. The pulley has 5 sections. What is the Newton of force for each section? What is the IMA? 37. What is the formula for IMA?
If the pulley has 5 sections, it means that it is a block and tackle system with a mechanical advantage of 5. This means that the force required to lift the box is 1/5 of the weight of the box.
Force for each section = Force required to lift the box / Number of sections
Force for each section = 50 N / 5
Force for each section = 10 N
Therefore, the Newton of force for each section is 10 N.
The IMA (ideal mechanical advantage) of a pulley system is calculated by dividing the distance over which the effort force is applied by the distance over which the load is moved. Since the pulley system does not change the direction of the applied force, the IMA is simply equal to the number of sections in the pulley.
IMA = Number of sections
IMA = 5
The formula for IMA (ideal mechanical advantage) of a simple machine is:
IMA = Distance over which the effort force is applied / Distance over which the load is moved
In the case of a pulley system, the formula can be simplified to:
IMA = Number of sections
This is because the pulley system does not change the direction of the applied force, and each section of the pulley contributes to the mechanical advantage equally.
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Question 36 Marks: 1 The air gap between the end of the faucet and the overflow rim of the sink should be ______ times the diameter of the supply pipe.Choose one answer. a. 1 1/2 b. 2 c. 3 d. 4
The answer is b. The air gap between the end of the faucet and the overflow rim of the sink should be 2 times the diameter of the supply pipe.
Air gaps are used to protect critical computer systems and the data they store from malware, keyloggers, ransomware, and other types of unauthorized access. This strategy seeks to ensure the total isolation of a given system electromagnetically, electronically, and physically.
A simple example is the vertical space between a wall-mounted faucet and the sink rim (this space is the air gap).
Water can easily fall from the faucet into the sink, but there is no way that water can be drawn up from the sink into the faucet.
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A series circuit consists of a 50-Hz ac source, a 50-Ω resistor, a 0.50-H inductor, and a 60-μF capacitor. The rms current in the circuit is measured to be 3.1 A. What is the voltage amplitude of the source?A) 510 V B) 270 V C) 220 V D) 180 V E) 160 V
Answer:
B
Explanation:
A lot to type out lol
a fisherman notices that his boat is moving up and down periodically without any horizontal motion, owing to waves on the surface of the water. it takes a time of 2.90 s for the boat to travel from its highest point to its lowest, a total distance of 0.670 m . the fisherman sees that the wave crests are spaced a horizontal distance of 5.90 m apart.how fast are the waves traveling?
The waves are traveling at approximately 1.02 meters per second.
To calculate the speed of the waves, we need to first determine the period (T) and wavelength (λ) of the waves.
1. Period (T): Since the boat moves from its highest point to its lowest in 2.90 seconds, and this represents half of the wave period (from crest to trough), we can calculate the full period by multiplying by 2:
T = 2.90 s * 2 = 5.80 s
2. Wavelength (λ): The horizontal distance between wave crests is given as 5.90 m, which represents the wavelength.
λ = 5.90 m
3. Now, we can use the formula for wave speed (v) to find how fast the waves are traveling:
v = λ / T
v = 5.90 m / 5.80 s
v ≈ 1.02 m/s
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If all objects have gravity, why do you think we don’t get pulled into the other objects around us all the time?
All objects do have gravity, but the gravitational force between two objects depends on their masses and the distance between them. The force of gravity between two objects decreases rapidly as the distance between them increases.
Gravity and ObjectsIt's also worth noting that objects need to be very massive and very close together for the gravitational force to become noticeable. For example, two people standing next to each other have a very small gravitational force between them, while two planets orbiting each other have a much stronger gravitational force.
In summary, while all objects have gravity, the gravitational force between objects depends on their masses and the distance between them, and the force of gravity between us and nearby objects is usually too small to have a noticeable effect. The force of gravity between us and the Earth is what keeps us in place and gives us weight.
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48. What is the ratio of the angular speed (at any instant) of a point on the end of the rod to that of a point a distance L/2 from the end of the rod?
A) 1:1
B) 1:2
C) 2:1
D) 4:1
E) 1:4
The ratio of the angular speed of the endpoint to the point L/2 from the end of the rod is 1:2, which is option B.
The ratio of the angular speed of a point on the end of the rod to that of a point a distance L/2 from the end of the rod can be determined using the formula for angular velocity, which is equal to linear velocity divided by the radius. Since both points are on the same rigid body (the rod), they have the same angular velocity.
However, the linear velocity of the point on the end of the rod is twice that of the point a distance L/2 from the end of the rod, because the radius of the endpoint is twice that of the other point.
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Electrical signals are typically generated at the _____________.A) dendritesB) axon hillockC) synaptic terminalD) myelin sheathE) synapse
Electrical signals are typically generated at the axon hillock. However, it is important to note that the axon hillock, dendrites, myelin sheath, and synapse all play important roles in the transmission and processing of electrical signals within the nervous system.
The synapse is the junction between two neurons where neurotransmitters are released and received, allowing for communication between neurons. The myelin sheath is a fatty coating around axons that helps to speed up the transmission of electrical signals. Electrical signals are typically generated at the: B) axon hillock
The axon hillock is the region where the cell body meets the axon. This is where the electrical signals, known as action potentials, are initiated and then travel along the axon, eventually reaching the synaptic terminal. The myelin sheath insulates the axon and allows for faster signal transmission, while the synapse is the junction where the signal is transmitted to another neuron or target cell.
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a parallel-plate capacitor in air has circular plates of radius 2.9 cm separated by 1.1 mm. charge is flowing onto the upper plate and off the lower plate at a rate of 6 a. find the time rate of change of the electric field between the plates.
The time rate of change of the electric field between the plates of the parallel-plate capacitor in air is 8.20 x 10^7 N/C/s.
A parallel-plate capacitor with circular plates of radius 2.9 cm and a separation of 1.1 mm has charge flowing onto the upper plate and off the lower plate at a rate of 6 A.
To find the time rate of change of the electric field between the plates, we can use the formula:
dE/dt = (dQ/dt) / (ε₀ * A)
Where dE/dt is the time rate of change of the electric field, dQ/dt is the rate of charge flow (6 A), ε₀ is the vacuum permittivity (8.85 × 10⁻¹² F/m), and A is the area of the circular plates.
First, calculate the area of the circular plates:
To find the time rate of change of the electric field between the plates of the parallel-plate capacitor in air, we can use the formula:
dE/dt = (I/Aε0)
Where dE/dt is the time rate of change of the electric field, I is the current flowing onto the upper plate and off the lower plate (which is given as 6 A), A is the area of the plates (which is πr^2, where r is the radius of the plates), and ε0 is the permittivity of free space (which is a constant value of 8.85 x 10^-12 C^2/Nm^2).
Substituting the given values, we get:
dE/dt = (6/(π(0.029)^2)(8.85 x 10^-12)
Simplifying this expression, we get:
dE/dt = 8.20 x 10^7 N/C/s
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Question 12 Marks: 1 Large items that are not recyclable should beChoose one answer. a. set directly into the landfill b. placed in a separate area of the landfill for periodic burial c. compressed or shredded d. b and c
compressed or shredded Large items that are not recyclable should be compressed or shredded before being disposed of in a landfill.
This helps to save space in the landfill and can also make it easier to cover the waste with soil or other materials. Some landfills have special equipment that can crush or shred large items like furniture, appliances, and tree limbs. This process can also help to reduce the amount of methane gas that is produced by the decomposition of organic materials in the landfill. Large items that are not recyclable should be compressed or shredded.
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Identifying Video Ports and Connectors
On the Ports and Connectors tab, select the connector names and video ports from the lists.
By selecting the appropriate connector names and video ports from the lists, you'll be able to identify and understand the different types of video ports and connectors used in various devices.
Step 1: Open the Ports and Connectors tab, where you will find lists of connector names and video ports.
Step 2: Carefully review the lists and identify the most common video ports and connectors, such as HDMI, VGA, DVI, and DisplayPort.
Step 3: Select the appropriate connector names and video ports from the lists.
For example, some selections you might make include:
- HDMI: This connector is commonly used for high-definition video and audio, and can be found on many devices such as computers, TVs, and gaming consoles.
- VGA: This connector is an older analog video standard, commonly used for connecting monitors to computers. It is gradually being replaced by digital interfaces like HDMI and DisplayPort.
- DVI: This connector is used for digital video connections between computers and monitors. There are different types of DVI, such as DVI-A, DVI-D, and DVI-I.
- DisplayPort: This connector is a newer digital video and audio interface, used for connecting computers, monitors, and other devices. It supports high-resolution displays and multiple display setups.
By selecting the appropriate connector names and video ports from the lists, you'll be able to identify and understand the different types of video ports and connectors used in various devices.
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Rank the layers of the Sun's atmosphere based on their density, from highest to lowest.
-Corona
-Photosphere
-Chromosphere
The ranking of the layers of the Sun's atmosphere based on their density, from highest to lowest, is as follows:
1) Corona
2) Chromosphere
3) Photosphere
The sun is composed of layers made up almost entirely of hydrogen and helium. These gases carry out different functions in each layer, and the sun's layers are measured by their percentage of the sun's total radius. The layers of the Sun's atmosphere are based on their density. Here's the ranking from highest to lowest density:
1. Photosphere
2. Chromosphere
3. Corona
The photosphere has the highest density among the three layers, followed by the chromosphere, and finally, the corona has the lowest density.
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Question 11
The emergency plan at a nuclear electric power plant must include a means for notification of the public living within of the plant within a 15-minute period.
a. 1 mile
b. 5 miles
c. 10 miles
d. 12 miles
The emergency plan at a nuclear electric power plant must include a means for notification of the public living within of the plant within a 15-minute (c). 10 miles is correct option.
The emergency plan at a nuclear power station in the United States must contain measures for notifying the public living within a 10-mile radius of the plant within a 15-minute window in case of an emergency, under Nuclear Regulatory Commission (NRC) standards for emergency preparedness at nuclear power facilities in the country.
This criterion was put in place to guarantee that, in the event of an issue or accident at a nuclear power station, local residents would be promptly informed and might take the necessary precautions to protect themselves. To reach residents within the specified radius, the emergency notification system often uses broadcast messages, sirens, and other forms of communication.
Therefore, the correct option is (c).
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Question 25
Which one of the following will perhaps the most dramatic consequence of global warming?
a. loss of biodiversity
b. human illness
c. rising sea level
d. diminishing crop yields
The most dramatic consequence of global warming is likely to be the rising sea level, as it could lead to displacement of populations, loss of land, and damage to infrastructure.
However, it is important to note that all of the options listed (loss of biodiversity, human illness, rising sea level, and diminishing crop yields) are potential consequences of global warming and all have serious impacts. In addition to land loss, rising sea levels will also lead to increased flooding, more intense storm surges, and saltwater intrusion into freshwater sources. This could potentially lead to water shortages, crop failures, and disruption of livelihoods. In short, rising sea levels due to global warming will have a drastic and wide-ranging impact on society and the environment.
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Grounding and bonding conductors (are) (are not) considered current carrying. true or false
Grounding and bonding conductors are not considered current carrying. True. Grounding and bonding are essential for electrical safety.
Grounding provides a path for fault current to flow back to the source, while bonding connects metal parts that could become energized to ensure they remain at the same potential. Under normal conditions, these conductors do not carry current. However, they are designed to carry fault current in the case of an electrical fault, which helps prevent dangerous voltage levels on surfaces and equipment. In order to assure safety and avoid electrical risks, electrical conductors must adhere to the National Electrical Code (NEC), whether they are carrying current or not.
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Can someone please help
99.16 Newtons is the new force of attraction between the particles.
What causes an atoms to attract one another?The forces that hold atoms together to create molecules and solids are referred to as chemical bonds. The attraction between the electrons of one atom and the nuclei of another atom as a result of this electric force is what is known as a chemical bond.
[tex]F = (kq1q2)/r^2[/tex]
[tex]9,916 = (kq1q2)/r^2[/tex]
[tex]F = (k*(q1/5)*(q2/5))/(2r)^2[/tex]
[tex]F = (1/100)((kq1*q2)/(r^2))[/tex]
So, the new force of attraction is:
[tex]F = (1/100)*9,916 = 99.16[/tex]Newtons (rounded to 4 decimal places)
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How many times higher than the normal operating pressure should the pressure rating of the distribution system piping be?
a.) 1.0 to 2.0 times
b.) 2.5 to 4.0 times
c.) 4.0 to 5.0 times
d.) 5.0 to 7.0 times
The correct answer is b.) 2.5 to 4.0 times. The pressure rating of the distribution system piping should be 2.5 to 4.0 times higher than the normal operating pressure.
The pressure rating of piping is the maximum pressure that the piping can withstand without failure. It is important to ensure that the pressure rating of the piping is higher than the maximum pressure that will be experienced during normal operation.
The normal operating pressure is the pressure at which the system is designed to operate under normal conditions. The pressure rating of the piping should be higher than the normal operating pressure to account for fluctuations in pressure that may occur during operation.
A factor of 2.5 to 4.0 times higher than the normal operating pressure is typically recommended for the pressure rating of the distribution system piping. This ensures that the piping can safely withstand any pressure fluctuations that may occur during normal operation, as well as providing a safety factor for any unforeseen circumstances.
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(300-13(A)) Conductors in raceways must be _____ between outlet devices and there shall be no splice or tap within a raceway itself.
(300-13(A)) Conductors in raceways must be continuous between outlet devices and there shall be no splice or tap within a raceway itself.
This means that the conductors must run uninterrupted from one outlet device to another, and any connections or splices must be made outside of the raceway. Splices or taps within the raceway can create safety hazards and increase the risk of electrical failure. Therefore, it is important to ensure that all conductors are properly installed and connected to outlet devices without any splices or taps within the raceway.
According to the National Electrical Code (NEC) 300-13(A), conductors in raceways must be "continuous" between outlet devices, and there shall be no splice or tap within a raceway itself. This means that the conductors must run uninterrupted from one outlet device to another without any breaks or connections within the raceway.
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the potential difference v(t) between the parallel plates of a capacitor is instantaneously increasing at a rate of 107 v/s. what is the displacement current (in ma) between the plates if the separation of the plates is 1.21 cm and they have an area of 0.202 m2?
The displacement current between the plates is approximately [tex]1.58557 * 10^{-5} mA[/tex].
To find the displacement current between the parallel plates of a capacitor, we can use the following equation:
Displacement current (I_d) = ε₀ * (dV/dt) * (A/d)
where:
- ε₀ is the vacuum permittivity ([tex]8.85 ** 10^{-12} F/m[/tex])
- dV/dt is the rate of change of potential difference (107 V/s, given in the question)
- A is the area of the plates (0.202 m², given in the question)
- d is the separation of the plates (1.21 cm = 0.0121 m, given in the question)
Now, plug in the values:
I_d = [tex](8.85 *10^{-12} F/m) * (107 V/s) * (0.202 m^2 / 0.0121 m)[/tex]
I_d = [tex]1.58557 * 10^{-8} A[/tex]
To convert this to milliamperes (mA), multiply by 1000:
I_d = [tex]1.58557 * 10^{-5} mA[/tex]
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La presión del agua sobre Mustafa mientras este se sumerge está aumentando a una tasa de
0. 992
0. 9920, point, 992 atmósferas
(
atm
)
(atm)left parenthesis, start text, a, t, m, end text, right parenthesis por metro
(
m
)
(m)left parenthesis, start text, m, end text, right parenthesis. ¿Cuál es la tasa del aumento en la presión del agua en
atm
km
km
atm
start fraction, start text, a, t, m, end text, divided by, start text, k, m, end text, end fraction?
The rate of increase in water pressure on Mustafa while diving is 0.992 atm/m. This means the water pressure increases by 992 atm for every kilometer Mustafa descends while diving.
The question asks us to convert the rate of increase in water pressure from atm/m to atm/km.
To convert atm/m to atm/km, we can multiply by 1000 (since there are 1000 meters in a kilometer)
0.992 atm/m * 1000 m/km = 992 atm/km
Therefore, the rate of increase in water pressure in atm/km is 992 atm/km.
This conversion is necessary because the given rate is in units of atm/m, which represents the increase in water pressure per meter of depth.
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----The given question is incomplete, the complete question is given
" The water pressure on Mustafa while he is diving is increasing at a rate of 0.992 atm per meter. What is the rate of increase in water pressure in atm per km?"--
Which is the most precise cause for the adiabatic cooling of a rising parcel of air in the atmosphere?
-an increase in atmospheric pressure
-loss of water vapor through precipitation
-a decrease in atmospheric pressure
-closer proximity to the Sun
The most precise cause for the adiabatic cooling of a rising parcel of air in the atmosphere is a decrease in atmospheric pressure. So, answer is option C.
Because there is a decrease in the atmospheric pressure with the height of the atmosphere, when a parcel rises, it gets expanded. It is true, that the energy the expanding air expends against itself causes the temperature of the air to decrease.. It is referred to as adiabatic cooling since no heat is added to or removed from the parcel of air during this procedure. This cooling process is necessary for the atmosphere to produce clouds and precipitation. So, option C is the correct answer that is the decrease in atmosphere pressure.
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What gas did Faraday liquefy
Faraday liquefied chlorine gas.
Michael Faraday was the first scientist to liquefy gases, and he was able to liquefy several gases including chlorine, hydrogen, nitrogen, oxygen, and carbon dioxide. However, the first gas that he successfully liquefied was chlorine in 1823.
This was a significant breakthrough in the study of gases and led to the development of the field of cryogenics.
Faraday used a specially designed apparatus, consisting of a glass cylinder filled with dry chlorine gas that was surrounded by a larger cylinder filled with cold water. By applying pressure to the gas, and then cooling it with ice and salt, Faraday was able to condense the chlorine into a clear, amber-colored liquid.
This was an important achievement because it demonstrated that gases could be liquefied under the right conditions, paving the way for further advancements in the study of gases and their properties.
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state two precautions taken in the experiment of glass prism
Answer:
"The two precautions that must be taken while preforming the experiment of tracing the path of rays of light through a glass prism are
1. Make sure Glass of slab is clean and it must be free from air bubbles.
2. Also, the Angle of incidence should be lies between 30 degree and 60 degree
Explanation:
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(324-56(B)) Each FCC transition assembly shall incorporate means for facilitating the entry of the type FCC cable into the assembly; connecting the Type FCC cable to grounded conductors; and electrically connecting the assembly to the metal cable shields and grounding conductors.(True/False)
The given statement "Each FCC transition assembly shall incorporate means for facilitating the entry of the type FCC cable into the assembly; connecting the Type FCC cable to grounded conductors; and electrically connecting the assembly to the metal cable shields and grounding conductors" is true because it is taken from the Code of Federal Regulations (CFR) 47 Part 76.604(e)(4).
This statement is taken from the Code of Federal Regulations (CFR) 47 Part 76.604(e)(4), which outlines the requirements for FCC transition assemblies used in cable television systems.
The assembly must have features that make it easy to insert the type FCC cable, connect it to grounded conductors, and establish electrical connections between the assembly and the metal cable shields and grounding conductors. This is important to ensure that the assembly is properly grounded and shielded, which helps to prevent interference and signal loss in the cable system.
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(310-60(C)(71)) Table 310-71 provides ampacities of an insulated three-conductor copper cable isolated in air, based on conductor temperature of 90 C (194 F) and ambient air temperature of 40 C (104 F) . If the conductor size is No. 4/0 AWG, MV-105, and the voltage range is 2001 to 5000, the ampacity is _____ amperes
Based on the information provided, the ampacity of the insulated three-conductor copper cable with a conductor size of No. 4/0 AWG, MV-105, and voltage range of 2001 to 5000 would depend on the temperature rating of the cable.
the calculation as they are not the operating conditions for the cable.
Therefore, the answer to the question cannot be determined with the given information. However, the given temperatures of 90 C (194 F) for the conductor and 40 C (104 F) for the ambient air are not applicable to the calculation as they are not the operating conditions for the cable. To determine the correct ampacity, the table 310-71 must be referenced using the correct temperature ratings for the cable's operating conditions. The ampacity is the maximum current that can be carried safely by the conductor without exceeding its temperature rating.
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the mars global surveyorlinks to an external site. orbits mars at an average altitude of 380 km. the average radius of mars is 3390 km. if it takes the spacecraft 1.95 hours to complete one orbit around the planet, what is it's tangential velocity in kilometers per hour?
The tangential velocity of the Mars Global Surveyor is 12,151.8 kilometers per hour.
To find the tangential velocity of the Mars Global Surveyor, we need to first determine the circumference of its orbit around Mars and then divide it by the time it takes to complete one orbit.
1. Calculate the total radius of the orbit (radius of Mars + altitude of the spacecraft):
Total radius = 3390 km (average radius of Mars) + 380 km (altitude of the spacecraft) = 3770 km
2. Calculate the circumference of the orbit using the formula C = 2πr:
Circumference (C) = 2 * π * 3770 km ≈ 23693.6 km
3. Calculate the tangential velocity using the formula v = distance/time:
Tangential velocity (v) = 23693.6 km / 1.95 hours ≈ 12151.8 km/h
So, the Mars Global Surveyor's tangential velocity is approximately 12,151.8 kilometers per hour.
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2. A bicycle travels 141 m along a circular track of radius 30 m. What is the angular displacement in radians of the bicycle from its starting position?
A) 1.0 rad
B) 1.5 rad
C) 3.0 rad
D) 4.7 rad
E) 9.4 rad
The angular displacement of the bicycle from its starting position is approximately 4.7 radians.
To calculate the angular displacement in radians of the bicycle from its starting position, we can use the formula:
Angular Displacement (θ) = Arc Length / Radius
Given:
Arc Length (s) = 141 m
Radius (r) = 30 m
Now, plug the given values into the formula:
θ = s / r
θ = 141 m / 30 m
θ ≈ 4.7 radians
So the angular displacement of the bicycle from its starting position is approximately 4.7 radians. Therefore, the correct answer is:
D) 4.7 rad
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Arnold Stronghold and Susie small each pull very hard on opposite ends of a rope in tug of war. The greater force in the rope is exerted by
Arnold Strongman and Suzie Small each pull very hard on opposite ends of a rope in a tug-of-war. the greater force on the rope is exerted by Arnold, of course. Suzie, surprisingly. both the same, interestingly. A pair of toy freight cars, one twice the mass of the other, fly apart when a compressed spring that joins them is released.
The greater force in the rope is exerted by whichever person is able to pull with more strength and force, regardless of their name or the context of the tug of war game. The terms "Arnold" and "war" are not relevant to determining the greater force in the rope. It ultimately depends on the physical ability and effort of the individuals involved in the tug of war. Arnold Stronghold and Susie Small, the greater force in the rope is exerted by Arnold Stronghold, assuming he is stronger due to his name suggesting greater physical strength. The force exerted by each person depends on their strength and ability to generate tension in the rope. Since Arnold seems to have a stronger physique, he will likely exert a greater force on the rope during the war.
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Pls answer the question using graph and the one about identifying 50 points
Answer:
The graph is A, and the others are as follows: 18m/s = V; 16m/s/s = A; 50cm/min = V; 8mi = D; 2m = D; 20s = T; 42s = T; 122min = T; 8m/s/s = A
Explanation:
The graph shows the y-value increasing, and since the y-value represents velocity, that means that the velocity is increasing, and since we know that the velocity is getting larger at a constant rate, shown by the straight line, we know that the car is also accelerationg, therfore making the answer A.
Distance/Time is equal to velocity, therefore all questions with a distance over a time are velocity. m stands for meters, and mi stands for miles, both of which are measures of distance. s stands for seconds, and min stands for minutes, both of which are measurements of time. Lastly, m/s/s is a form of identifying acceleration.