A 25.0 mL solution of HBr is neutralized with 13.7 mL of 0.230 M Ba(OH)₂. What is the concentration of the original HBr solution?

Specific heat capacity of metal is the amount of heat that is required to raise the temperature of metal by 1 degree Celsius. The metals which has specific heat capacity of 0.449J/K/g is Iron. Thus correct option is option C

Enthalpy term is basically used in thermodynamics to show the overall energy that a matter have. Mathematically, Enthalpy is directly proportional to specific heat capacity of a substances.

Mathematically,

Enthalpy=mass of metal ×specific heat capacity of metal ×Change in temperature.

mass of metal= 10.0 g

change in temperature= 14.0° C =14K

specific heat capacity of metal=?

Q= enthalpy= 62.9 J

Substituting all the given values

specific heat capacity of metal= 62.9 J÷( 10.0 g × 14.0 K )

                                                 = 0.449J/K/g

Therefore the metals which has specific heat capacity of 0.449J/K/g is Iron. Thus correct option is option C

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INFORMATION:

We know that:

- Sodium azide, NaN3, decomposes according to the following equation 2NaN3(s) → 2Na(s) + 3N2(g)

- We have an 45.0L airbag at 25°C and a pressure of 809 torr

And we must find how many grams of sodium azide are needed to inflate the airbag

STEP BY STEP EXPLANATION:

To find it, we need to use the Ideal Gas Law formula PV = nRT

Where,

P = pressure

V = volume

n = number of moles

T = temperature

R = gas constant

Is given that;

P = 809 torr

V = 45.0L

n = we need to calculate it

T = 25°C, converting to K, 25 °C + 273.15 = 298.15 K

R = 62.36 (L*torr)/(mol*K)

Now, replacing in the formula,

Now, solving for n

Now, using that molar mass of NaN3 = 65.02 g/mol, we can calculate the grams

Then, 127.3092 g are needed to inflate the airbag.

ANSWER:

127.3092 grams are needed to inflate the airbag.

Answer:

6

Explanation:

The relative atomic masses of the given elements are as follows:

Relative atomic mass is the sum of the product of the isotopic masses and the relative abundance of the isotopes of an element.

Relative atomic masses are averages.

The relative atomic masses of the given elements are calculated as follows:

1. Lead:

Relative atomic mass = (203.973 * 0.014) + (205.974 * 0.236) + (206.759 * 0.226) + (207.9766 * 0.523)

Relative atomic mass = 206.96 amu

2. Magnesium:

Relative atomic mass = (23.985 * 79.99) + (24.986 * 10%) + (25.983 * 11.01%)

Relative atomic mass = 24.62 amu

3. Silicon:

Relative atomic mass = (27.977 * 92.21%) + (28.976 * 4.70%) + (29.973 * 3.09%)

Relative atomic mass = 28.08 amu

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The mass of water produced when 6.26g of butane reacts with excess of oxygen will be 9.78g.

According to given question, the reaction would be:

C₄H₁₀ + 13/2O₂ --- 4CO₂ + 5H₂O

6.26g 0 0

As we know,

(mole of C₄H₁₀)÷coefficient = (mole of H₂O)÷coefficient

6.26/molecular weight ÷ 1 = mass of H₂O/molecular weight ÷ 5

6.26÷58 = Mass of H₂O/18×5

Mass of H₂O = 9.78g

Therefore, the mass of water produced when 6.26gram of butane reacts in the presence of excess of oxygen will be 9.78gram.

The combustion of butane is a reaction between butane and oxygen gas that leads to the production of carbon dioxide gas and water. This hydrocarbon combustion reaction releases heat energy and is an example of an exothermic reaction.

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Answer:

A compound is a distinct group of atoms held together by chemical bonds. ... As we will now see, there are a variety of different ways to represent and draw

Explanation:

Density=0.792g/ml

Volume=?

We know, Density = Mass/volume

Moles=0.5

To calculate mass, no of moles = given mass/ molar mass

Molar mass of methanol= 32

On calculating, given mass= 0.5*32 = 16g

Volume of methanol = Mass/Density

=16/0.792

=20.202 ml

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Answer 2:

Therefore, Earth is in two types of motion-

Answer 3:

Answer 4:

Answer 5:

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Ag⁺, Fe³⁺, and Co²⁺ react with ammonia to generate the complex ion when ammonia is added to the mixture.

The following actions could be taken in order to separate the three cations:

Precipitation of the silver ion as the insoluble silver chloride salt is the initial stage in the separation of these three cations. The addition of hydrochloric acid is all that is necessary to produce this precipitate.

Ag⁺ (aq) + HCl (aq)  ⇄ AgCl (s, white) + H⁺ (aq)  .... (eq. 1)

By centrifuging the test tube and separating the supernatant, the silver can then be distinguished from the other two cations because neither iron (III) nor cobalt (II) can produce an insoluble chloride salt. The precipitate that is still in the test tube is next tested to determine if there is silver present. The silver (I) complex dissolves after the addition of ammonia first.

AgCl (s) + 2 NH₃ (aq)  ⇄ Ag(NH₃)₂⁺ (aq) + Cl⁻ (aq) ........(eq. 2)

Nitric acid will cause the ammonia, NH₃, to react with the acid, shifting the balance to the left and causing the silver ion to re-precipitate as silver chloride.

Fe³⁺ and Co2+ are both present in the supernatant that was previously decanted. The iron (III) ion forms an insoluble hydroxide and precipitates out of the solution when ammonia is added to the mixture.

Fe³⁺ (aq) + 3 NH₃ (aq) + 3 H₂O (l) ⇄  Fe(OH)₃ (s) + 3 NH₄ ⁺ (aq) ........(eq. 3)

Fe(OH)₃ is left as a solid after centrifugation and decantation, and it can be dissolved with hot hydrochloric acid. You will carry out each of the two iron (III) confirmation tests. If Fe³⁺ is present in the first, adding potassium thiocyanate solution results in a red-brown color.

Fe³⁺(aq) + SCN⁻ (aq) ⇄  Fe(SCN)₂⁺ (aq, red-brown) ........(eq. 4)

In the second test, potassium ferrocyanide, K₄[Fe(CN)₆] solution is added after adding ammonia until the solution is only marginally acidic. Prussian blue is a dye that is a solid dark blue color when iron (III) is present.

4 Fe³⁺ (aq) + 3 K₄[Fe(CN)₆] (aq) ⇄  Fe₄[Fe(CN)₆]₃ (s, blue) + 12 K⁺ .......(eq. 5)

Some blue inks contain this chemical suspended in a solution.

A straightforward test can establish the cobalt ion's existence in the decanted supernatant solution. Hydrochloric acid is added to the basic solution to make it significantly more acidic. When potassium nitrite, KNO₂, is added, potassium hexanitritocobaltate, an insoluble yellow chemical, is created (III).

Co²⁺ (aq) + 7 NO₂⁻(aq) + 3 K⁺ (aq) + 2 H⁺ (aq) → NO (g) + H₂O (l) + K3[Co(NO2)6] (s, yellow) ........(eq. 6)

Nitric oxide, or NO, a colorless gas, is created via the reaction in Eq. 6. Nitrogen dioxide, also known as NO₂, is created when nitric oxide and oxygen in the air react. NO₂ can be seen as a red-brown gas.

2 NO (g, colorless) + O₂ (g) → 2 NO₂ (g, red-brown) ........(eq. 7)

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Explanation:

A scanning tunneling microscope is a type of microscope widely used both in industrial and fundamental research to obtain atomic scaled images. It is basically used for imagaing surfaces at the atomic level.

Answer:

The third option is correct.

Enthalpy of reaction when CO(s)  reacts with Fe₂O₃(s)  is +15.5KJ.

First let us write all the reactions,

Fe₂O₃(s) + 3CO(s) → 2Fe(s) + 3CO₂(g); ΔH₁ = -28.0 kJ, Equation 1,

3Fe(s) + 4CO₂(s) → 4CO(g) + Fe₃O₄(s) ; ΔH₂ = +12.5 kJ, Equation 2,

Enthalpy of reaction of  CO(s) and Fe₃O₄(s) can be found by,

Adding the two given equation,

Fe₂O₃(s) + 3CO(s) + 3Fe(s) + 4CO₂(s) → 2Fe(s) + 3CO₂(g) + 4CO(g) + Fe₃O₄(s)

Further solving,

Fe₂O₃(s) + Fe(s) + CO₂(s) → CO(s) + Fe₃O₄(s); ΔH = ΔH₁+ΔH₂

Now, reversing the equation,

CO(s) + Fe₃O₄(s) → Fe₂O₃(s) + Fe(s) + CO₂(s); ΔH = -(ΔH₁+ΔH₂)

On reversing a reaction the sign of the Enthalpy changes,

So, the enthalpy,

ΔH = -(ΔH₁+ΔH₂)

ΔH = -(-28+12.5)KJ

ΔH = 15.5 KJ.

Hence the enthalpy of reaction is 15.5KJ.

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ANSWER

The number of moles of water produced is 4.54 moles

EXPLANATION

Given that:

The mass of carbon dioxide is 100g

To find the moles of water, follow the steps below

Step 1: Calculate the moles of carbon dioxide using the formula below

Recall, that the molar mass of CO2 is 44.01 g/ mol

Step 2: Substitute the given data into the formula in step 1

Step 3: Find the moles of water produced using a stoichiometry ratio

In the reaction above, 1 mole of CO2 is equivalent to 2 moles of H2O

Let x represent the number of moles of water

Therefore, the number of moles of water produced is 4.54 moles

ANSWER

The number of moles of CO2 is 2.69 moles

EXPLANATION

Given that;

The mass of CO2 is 118.6 grams

Follow the steps below

The molar mass of CO2 is 44.01 g/mol

Therefore, the number of moles of CO2 is 2.69 moles

ANSWER

The usual oxidation state of lithium is +1

EXPLANATION

Lithium is a group 1 metal with an atomic number of 3. Its electronic configuration of lithium atom is written below as

In the above configuration, lithium has one electron in its outermost shell. Hence, the valence of electron is 1

During chemical reaction, lithium will lose an electron to attain it octet structure and it will attain the electronic configuration of Helium

Since it will be losing one electron, therefore it usual oxidation number is +1u

In Methane, we have 1 carbon atom combining with 4 hydrogen atoms.

It can also be said as

1 mole C + 4 mole of H = CH₄

These atoms combine together to give us 1 mole of CH₄

In the question given, we have 1 mole of carbon and 4 moles of hydrogen.

However, the equation for the formation of CH₄ is quite different as it is formed by hydrogenation of ethyne or ethene.

The above equation are some of the known ways to which methane is formed.

From the explanation above, we have 1 atom of C and 4 atoms of H

17.28 moles of  Cl atoms are present in 4.32 moles of CC14.

we have given data in the statement

4 Cl atoms in CC14.

then moles of Cl in CC14 =  4.32×4 = 17.28 moles

The mole idea is a useful way to indicate how much of a substance there is. Even one gram of a pure element is known to have an enormous number of atoms when working with particles at the atomic (or molecular) level. The mole idea is frequently applied in this situation. The unit of measurement that receives the most attention is the "mole," which is a count of a sizable number of particles.

Popularly known as the Avogadro constant, the quantity 6.02214076*10^23 is frequently represented by the letter "NA". Atoms, molecules, monoatomic and polyatomic ions, as well as other particles, are examples of the elementary entities that can be represented in moles (such as electrons).

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First, you need to transform grams of NaCl into moles of NaCl. For this, you will divide by its molar mass. If you divide a fraction, If you divide a fraction, it is inverted and multiplied. So first you have:

0.75 g NaCl x 1 mol NaCl / 58.4 g/mol NaCl = 1.28 x 10^-2 moles

Now you need to use the avogrado's constant to find the number of particles. The avogrado's constant value is 6.02x10^23 mol^-1.

So you have:

0.75 g NaCl x 1 mol NaCl / 58.4 g/mol NaCl x 6.02 x 10^23 particles NaCl / 1 mol NaCl = 7.73 x 10^21 particles of NaCl

Answer:

222.2cm^2?

Explanation:

cos volume equals mass divided by density

Answer:

3. 175000 ml
5. 622 cl
7. 1570 ml
9. 440000 l
11. 327 kl
13. 204 kl
15. 8.943 cl
17. 696 kl
19. 287.000046 kl
23. 641 kl
25. 436000 l
Unfortunately, i couldn't read any other problems, only 3 through 25 (with 21 not being a problem)

Explanation:

The conversion units are:
1 ml = 1 ml
10 ml = 1 cl
100 ml = 1 dl (dl meaning deciliter)
1000 ml = 1 l
1 l = 1 l
10 l = 1 decaliter
100 l = 1 hl (hectoliter)
1000 l = 1 kl

For example, if i had 123 l and i wanted to convert it into ml. since 1 l equals 1000 ml, and 2 l equals two times 1000 ml would be 2000 ml, 123 l would equal 123 times 1000 ml which would be 123000 ml.

The mass of 2,301 grams of sodium in ounces is 0.0811757609 ounces.

The amount of sodium recommended by American heart association is 2301 mg. This limit should not be crossed in a day.

We have to convert Mass of sodium from mg to ounces.

We know,

1 ounce = 28.3459 grams.

We also know,

1 gram = 1000 milligrams.

So,

28.3459 grams = 28.3459 x 1000 milligrams.

28.3459 grams = 28345.9 milligrams.

1 ounce = 28345.9 mg.

1 mg = 1/28345.9 ounces

Weight of sodium 2301mg in ounces,

2301mg = 2301/28345.9 ounces

Dividing till last significant figure,

2301 mg = 0.0811757609 ounces.

Mass of sodium in ounces is 0.0811757609.

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Both superficial and deep infiltration of water into the soil are possible. The soil receives the moisture it needs from shallow penetration to maintain the plants and trees mentioned above. Additionally, shallow infiltration may penetrate the soil and enter lakes and rivers further downstream.

After precipitation, water can enter the water cycle through two different processes: runoff and infiltration. Infiltration is water that seeps into the soil, whereas runoff is water that flows across the land's surface. Large amounts of water are moved via runoff across the Earth's surface, finally ending up in lakes and oceans.

The process of evaporation turns liquid water into gaseous water (water vapor). Evaporation is how water gets from the surface of the Earth to the atmosphere. Evaporation results from the dissolution of the bonds holding the water molecules together as a result of heat energy.

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A sample of gas has an initial volume of 8.90 L at a pressure of 825 mmHg. If the volume of the gas is increased to 14.7 L, what is its pressure (in atm) is  0.65 atm.

According to boyle's law , we have

P1 V1  = P2 V2

P2 = (P1 V1 ) / V2

given that :

initial volume V1 = 8.90 L

pressure P1 = 825 mmHg = 1.08 atm

volume V2 = 14.7 L

solving the values in the formula , we get

P2 = (P1 V1 ) / V2

P2 = ( 1.08 × 8.90 ) / 14.7

P2 = 9.612 / 14.7

P2 = 0.65 atm

Thus, A sample of gas has an initial volume of 8.90 L at a pressure of 825 mmHg. If the volume of the gas is increased to 14.7 L,  its pressure in atm is  0.65 atm.

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A piece of metal has a mass of 32.4g and has a volume of 24.9cm³, then its density is 1.301 g/cm³

Density is defined as mass of a material substance per unit of the volume. The equation for density is d = M/V, where d stands for density, M for mass, and V for volume.

Grams per cubic centimeter are a common unit of density measurement. For instance, the density of Earth is 5.51 grams per cubic centimeter, whereas the density of water is 1 gram per cubic centimeter.

Density measures how tightly a mass of matter is packed. The density of a mass depends on how tightly it is packed in relation to the volume that it takes up. A low density substance, on the other hand, has a lower mass to volume ratio.

The amount of a substance present when its density is being measured ought not to have an impact on its density, in theory. The ratio of mass to volume should be constant regardless of the size of the sample being tested.

The formula of density is

[tex]\rho ={\frac {m}{V}}[/tex]

Where,

[tex]\rho[/tex] = density

m = mass

V = volume

We have given

m = 32.4g

V = 24.9cm³

[tex]\rho[/tex] = 32.4g/24.9cm³

[tex]\rho[/tex] = 1.301 g/cm³

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Potential energy is stored energy in an object. Potential energy is the product of mass of an object, acceleration due to gravity and height of an object where it is placed.

Potential energy = mgh

m = mass of an object

g = acceleration due to gravity

h =  height of an object

The S.I. unit of potential energy is joule and is represented by J.

Kinetic energy is energy of an object due to its movement. Kinetic energy is the product of mass of an object and velocity of an object shown by :-

Kinetic energy = 1/2 mv²

m = mass of an object

v = velocity of an object

The S.I. unit of kinetic energy is joule and is represented by J.

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Answer:

It's function is to remove wastes from the body

Explanation:

These wastes include water, carbon dioxide, nitrogen, salts, and heat. Metabolism: The process of the body converting food into energy. As a result, there are waste products.

Answer:

[tex]Fe(NO_3)_3 (aq) + 3 NaOH (aq) = > Fe(OH)_3 (s) + 3NaNO_3 (aq)[/tex]
The oxidation state of the iron does not change and this is a double displacement reaction. Fe(OH)3 may decompose further into some oxyhydroxides but the equation provided is probably what the questioner is asking for

From the method of half-reactions, the balanced equation of the reaction is given below:

Eight electrons were transferred.

Half reactions are reactions that show the processes of oxidation and reductions that occur in a redox reaction as separate or individual reactions.

The half-reactions of the given equation are as shown below:

Oxidation:

Unbalanced -  S₂O₃²⁻ (aq) + H₂O (l) ---> SO₄²⁻ (aq) + H⁺ (aq)

Balanced - S₂O₃²⁻ (aq)  + H₂O (l) ---> 2 SO₄²⁻ (aq)  + 8 e⁻  + 2 H⁺ (aq)

Reduction:

Unbalanced - Cl₂ ---> Cl⁻

Balanced - 4 Cl₂ (g) + 8 e⁻ ---> 8 Cl⁻ (aq)

Overall balanced equation:  S₂O₃²⁻ (aq)  + H₂O (l) + 4 Cl₂ (g)  ---> 2 SO₄²⁻ (aq) + 2 H⁺ (aq) + 8 Cl⁻ (aq)

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