The two cars will move with a velocity of 23m/s(optionB)
What is linear momentum?Linear momentum is the product of a system’s mass and its velocity. In equation form, linear momentum p is
p=mv.
Where m is the mass of the body and v is the velocity at which it moves.
The momentum of the first call = 2100× 25=52500kgm/s
The momentum of the second car = 1650×21= 34650kgm/s
The total momentum before collision = 52500+34650=87150kgm/s
momentum after collision= (2100+1650)v= 3750v
law of conservation of Linear momentum states that; momentum before collision = momentum after collision
Therefore 87150= 3750v
v = 87150/3750
v= 23m/s( nearest whole number)
Therefore the velocity of the two cars after collision is 23m/s.
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A cyclist who starts from rest will cycle with uniform acceleration. He moves 8m in 4th second. How far does he move in 5 seconds?
Answer: 200m in 5seconds.
Explanation: To find the distance traveled by the cyclist in 5 seconds, we need to use the equation for distance traveled with uniform acceleration:
d = d0 + v0t + 1/2a*t^2
where d is the distance traveled, d0 is the initial displacement (in this case, 0 since the cyclist starts from rest), v0 is the initial velocity (also 0 in this case), t is the time elapsed, and a is the acceleration.
We are given that the cyclist moves 8m in 4 seconds, so we can plug these values into the equation:
8m = 0 + 04s + 1/2a*4s^2
8m = 1/2a16s^2
a = 8m / (1/2 * 16s^2)
a = 16m/s^2
Now that we have the acceleration, we can use the equation to find the distance traveled in 5 seconds:
d = 0 + 05s + 1/216m/s^2*5s^2
d = 1/216m/s^225s^2
d = 200m
Therefore, the cyclist will move a distance of 200m in 5 seconds.
a 200 kg weather rocket is loaded with 100 kg of fuel and fired straight up. it accelerates upward at 30.0 m/s2 for 30.0 s, then runs out of fuel. ignore any air resistance effects.
a) What is the rocket's maximum altitude?b) How long is the rocket in the air?c) Draw a velocity vs. time graph for the rocket from lift-off until it hits the ground.
a). the rocket's maximum altitude is 54.8km .
b). the rocket in the air 227.6 s
Calculation :
Given data
The mass of the rocket is mr=200kgThe mass of the fuel is mf=100kgThe acceleration is ao=30m/s²The time period is t1=30sThe expression from the equation of motion can be given as,
v₁²−v²=2gs1......(1)
The velocity during the first phase can be calculated as,
v1=vo+at1
v1=0+(30×30)
v1=900m/s
(a)
The altitude attained during first phase can be calculated as,
s1=v²₁ / 2a
s1=900/(2×30)
s1=13500m
Substituting the values in equation 1 for distance travelled during second phase,
(900)²−0=2×(9.8)×s₂
s2=41326.5m
The maximum altitude attained by rocket can be calculated as,
s=s1+s2
s=13500+41326.5s
=54826.5m
s=54.8km
(b)
The total time period can be calculated by the expression,
t=ta+td......(2)
The time taken in second phase of the motion can be calculated as,
v=v1+gt2
0=900−(9.8)t2
t2=91.8s
The time of ascent can be calculated as,
ta=t1+t2
ta=30+91.8
ta=121.8s
The time of descent can be calculated as,
td=√(2s/g)
td=√(2×54832.5)/(9.8)
td=105.8 s
Substituting the values in equation 2,
t=121.8+105.8
t=227.6 s
Thus, the duration of rocket in the air was 227.6 s
(c)
Figure
From the figure,
At point A, fuel was out.
At point B, rocket attended maximum altitude.
At point C, rocket fell on ground.
Acceleration is the rate of change of an object's velocity with respect to time. Acceleration is a vector quantity (as long as it has magnitude and direction). The direction of an object's acceleration is given by the direction of the net force acting on that object. As described in Newton's second law the magnitude of an object's acceleration is the combined effect of two sources.
The mass of this object is inversely proportional to the mass of the object, depending on the material from which it is made.
The SI unit of acceleration is meters per second squared.
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How much force does it take to move a 35Kg box at an acceleration of 1.5 m/s2?
Answer: Fa = 52,5N
Explanation: The force that causes an object to move is called Force of application which is calculated by the formula Fa = m × a (Force of application = mass multiplied by the acceleration)
=> Fa = m × a
Fa = 35kg × 1.5m/s²
Fa = 52.5N
an 5-kg object sits on a frictionless incline that makes an angle 26 degrees with the horizontal. find the magnitude of the acceleration of the object.
An object weighing 5 kg is perched on a smooth incline that slopes at a 26-degree angle to the horizontal. The amplitude of the object's acceleration is given by F>mg sin26.
What is an explain acceleration?The rate where the direction of movement change over time is referred to as acceleration. Anything is said to be rushing when that goes faster or slower.
What three forms of acceleration are there?The three main types of propelled motions are regular accelerated, non-uniform velocity, and points of data. The motion in which an item moves in a single direction while increasing in velocity at regular intervals is referred to as uniform acceleration.
Briefing:F = ma
F - mg sin26 = ma
a = F - mg sin26/m
a = F/m - gsin26
which implies, F>mg sin26.
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a ? is a two-terminal device that passes current of one polarity and blocks current of the opposite polarity.
A diode is a two terminal device that passes and blocks the current.
What is a diode?A diode is a semiconductor gadget that essentially switches current in a single direction.
However, it substantially inhibits current flow in the opposite direction. It permits an easy flow of current in one direction.
Due to the fact that they convert alternating electricity into pulsing direct current, diodes are sometimes referred to as rectifiers. Type, voltage, and current capability are used to rate diodes.
The anode and cathode determine the polarity of diodes. The majority of diodes only permit current to flow when the anode is subjected to positive voltage.
A diode is forward-biased when it permits current flow. Reverse-biased diodes function as insulators.
The arrow of the diode symbol points away from the direction of electron flow. The symbol was created by engineers, whose current flowed in a positive direction.
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which of the following is true regarding the masses of antimatter particles? which of the following is true regarding the masses of antimatter particles? the mass of an antimatter particle is the negative value of that of its corresponding matter particle. the mass of an antimatter particle is always larger than that of its corresponding matter particle. the mass of an antimatter particle is the same as that of its corresponding matter particle. antimatter has no mass. the mass of an antimatter particle is always lower than that of its corresponding matter particle.
Regarding the masses of antimatter particles, the true statement is: A. The mass of an antimatter particle is the negative value of that of its corresponding matter particle.
Matter and AntimatterMatter is any substance made up of particles that takes up space by their volume and also have mass. Meanwhile, antimatter is a particle made up of antiparticles of the corresponding ordinary particles. One of the differences between matter and antimatter is the charge of their mass. An antimatter has the opposite electric charge of its corresponding matter. So, it is safe to say that the mass of an antimatter particle is the negative value of its corresponding particle.
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you perform 100 j of work on a refrigerator that extracts heat from a cold reservoir and dumps heat into a hot reservoir. the amount of heat dumped into the hot reservoir must be
a. equal to 100 J
b. less than 100 J
c. greater than 100 J
The amount of heat that is dropped in the hot reservoir is equal to 100 J. Option A
What is the first law of thermodynamics?According to the first law of thermodynamics, we know that energy can neither be created nor destroyed but can be converted from one form another.
We can see that as the heat is transferred from the we do some work so as to be able to extracts heat from a cold reservoir and dumps heat into a hot reservoir. Since heat can neither be created nor destroyed, the heat that is dumped must be equal to the amount of heat that is extracted.
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neutron stars are extremely dense objects formed from the remnants of supernova explosions. many rotate very rapidly. suppose the mass of a certain spherical neutron star is twice the mass of the sun and its radius is 5.0 km. determine the greatest possible angular speed it can have so that the matter at the surface of the star on its equator is just held in orbit by the gravitational force.
The greatest possible angular speed an object can have is 46072.3431 rad/s.
What exactly does gravity mean?Any two objects with mass are drawn together by the gravitational force. The gravitational force is known as. According to F=Gm₁m₂/r², the direction of force will always point in the direction of the opposing mass along the line connecting the two bodies. It is an alluring natural force.
The gravitational force will balance the centripetal force,
GmM/R² = mRω²
ω = √GM/R³
ω = √6.67 × 10⁻¹¹ × 2 × 1.989×10³⁰/5000³
ω = √2.653×10²⁰/5000³
ω = √2.653×10²⁰/1.25×10¹¹
ω = √2.122×10³¹
ω = 46072.3431 rad/s.
The greatest possible angular speed an object can have is 46072.3431 rad/s.
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When you have two like charges in a line – where is the electric field the greatest? Is there ever a point where the field will be zero?
The magnitude of the electric field will be greater where the lines of the charges are closest to each other.
An electric field is defined as an area that holds the electrically charged particles in its physical field and the electric field also exerts a force on all charged particles either attracting them or repelling them. If the force that is exerted on the charged particle varies from one point in the field to other then the electric field is said to be non-uniform.
In opposite charges, zero is not a possibility between two charges because the field vectors from both opposite charges will head toward the negative charge.
So we can conclude that the point where the field is zero does not exist.
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a car travels 80 km east in two hours. what is its average velocity? question 27 options: 160 km/hr east. 160 km/hr west. 40 km/hr east. 40 km/hr west.
80 kilometers east in two hours in a car. The car has a westward speed is 40 km/h.
What is a simple definition of velocity?The vector illustration expression of velocity is the movement in space-time of an object or particle. The recognized unit of velocity magnitude is the centimeter per second (m/s) (also known as speed).
What is velocity vs speed?Speed is the rate at which an object is moving across a path over time, whereas velocity is the speed or direction that an organism is moving. In other words, velocity is a scalar value, but velocity is a vectors.
Briefing:An object's velocity is a vector quantity. Both magnitudes and direction are present.
Arrows serve as directional indicators.
Car A is traveling west. Moving in an east-south direction is Car B. Vehicle C is traveling in a southerly direction. Vehicle E is traveling in a northerly direction.
Therefore, the Car is moving west at a speed of 40 km/h.
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The equation to find gravitational force is below. The value of
G is given as well. The mass of the Earth is 5.98 x 1024 kg and
the mass of a person sitting on the Earth is 70 kg. The
distance between the center of the Earth and the person is
6.38 x 106 m. Use the equation given to find force. Show ALL
of your WORK in the file you upload.
The gravitational force of the Earth is 686N.
How to calculate gravitational force?Gravitational force is a very long-range, but relatively weak fundamental force of attraction that acts between all particles that have mass; believed to be mediated by gravitons.
The equation to calculate gravitational force is as follows:
F = Gm₁m₂/r²
Where;
F is the Gravitational force between two objects measured in Newton (N)G is the Universal Gravitational Constant with a value of 6.674 × 10-¹¹ Nm²kg-²m₁ is the mass of one massive body measured in kg.m₂ is the mass of another massive body measured in kgr is the separation between them measured in kilometre (km)F = 6.674 × 10-¹¹ {5.98 × 10²⁴ × 70}/(6.38 × 10⁶)²
F = 6.674 × 10-¹¹ {4.186 × 10²⁶ ÷ 4.07 × 10¹³}
F = 6.674 × 10-¹¹ {1.03 × 10¹³}
F = 6.86 × 10²
F = 686N
Therefore, 686N is the gravitational force.
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a disk is suspended by a nail such that it pivots in a vertical plane about a point on the edge of the disk. if the disk's radius is 25 cm, what is the period of oscillation?
1.2s is the period of oscillation of a disk is suspended by a nail such that it pivots in a vertical plane about a point on the edge of the disk when the disk's radius is given 25 cm.
What do you mean by oscillation?The process in which any quantity or measure fluctuating repeatedly about its equilibrium value in time is what is termed as oscillation. The periodic change in a substance's measured value between two values or around its equilibrium value is another way to define oscillation. Period :The period, what is known as the length of each full oscillation, is constant. T = 2 Square root of L/g, where L is the pendulum's length and g is the acceleration brought on by gravity, is the formula for a pendulum's period.
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Use the data provided to calculate the amount of heat generated for each cylinder height. round your answers to the nearest tenth. 100 m: kj 200 m: kj 1000 m: kj
The amount of heat generated for each cylinder height is found out to be
100 m : 4.9 kJ
200 m : 9.8 kJ
1000 m : 49.1 kJ
In order to calculate this, you just have to calculate the PE of every cylinder and formula for PE is:
PE = g* h* m
where, m is mass
h is height
g is gravity
So, we just have to insert the values into the formula, to obtain results.
For 100m cylinder, PE = g* h* m
PE = 9.8* 100* 5 = 4900 J = 4.9 kJ
For 200m cylinder,
PE = 9.8* 200* 1 = 9800 J = 9.8 kJ
For 1000m cylinder,
PE = 9.8* 1000* 1 = 49100 J = 49.1 kJ
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as a result of the expansion, how do the average distances between galaxies in the distant past compare to the average distance between them today?
As a result of the expansion, parallax method is the way to compare the average distances between galaxies in the distant past and average distance between them today
Radio telescopes are used by astronomers all over the world to study the naturally occurring radio waves that are emitted by stars, planets, galaxies, clouds of dust, and gas molecules. For the most part, we are all familiar with visible-light astronomy and the information it provides about these objects. What we see with our eyes is referred to as visible light or optical light.The parallax method can be used to determine how far away nearby stars are. Over a period of six months, the position of the star in the sky is measured twice (e.g. g. both in the spring and in the fall). In contrast to stars further away, this one will seem to have moved. The same effect can be produced by holding your arm out in front of you and looking at your thumb with your left eye first, then your right eye later. The thumb will appear to leap in front of the background. The distance to the star can be calculated with ease by measuring the angle the star has shifted and knowing the radius of Earth's orbit.[tex]\alpha =L/x\\\\x=\sqrt{1-\frac{a}{y} } \\\\\alpha =\frac{L}{\sqrt{1-\frac{a}{y} }}[/tex]To study more about visible-light astronomy -
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Why does the Earth have gravity?
Answer:
All its mass makes a combined gravitational pull on all the mass in your body.
Explanation:
Basically anything with mass has gravity
A 9.5 kilogram object is moving at 6.4 m/s on a horizontal, frictionless surface. What is the total work (in Joules) that must be done on the object to increase its speed to 10.7 m/s?
(Express your answer rounded to the nearest 10th)
The total work (in Joules) that must be done on the object to increase its speed to 10.7 m/s is 349J.
What is the total work (in Joules) that must be done on the object to increase its speed to 10.7 m/s?ΔK.E = W
ΔK.E = K.Ef - K.Ei
⇒ ΔK.E = 1/2m(Vf² - Vi²)
⇒ ΔK.E = 1/2×9.5(10.7² - 6.4²)
⇒ ΔK.E = 349J
Hence, the total work is 349J
How can you determine how much work has been done on an object?Work = Force Distance is the formula for calculating work. The joule (J), sometimes known as the Newton meter (N m), is the SI unit for work. When an object is moved across a distance of 1 m by 1 N of force, the work done is equal to 1 joule.
How do you figure out how much labor is done when kinetic energy changes?Between KE and W relationship: An object's change in kinetic energy equals the work performed on it by a net force: W = KEi - KEf. The work-energy theorem is the name given to this relationship.
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explain the advantages of simplifying combinational logic circuits and how they make designs more efficient and beneficial to society.
Advantages of simplifying combinational logic circuits:
1. Simplified uses fewer gates to provide the same logic properties as necessary.
2. A circuit with fewer gates is smaller and less expensive than an original.
3. Because there are fewer interconnections, the reliability of the circuit will increase.
4. The circuit's operating speed goes up.
5.There are no redundant gates because of the simplification.
How simplifying combinational logic circuits make designs more efficient and beneficial to society?
It is challenging to design a circuit if it is complex, so the circuit should be as basic as feasible before design. We may need to provide a less amount of power if there are more gates. Therefore, combinational logic circuit simplification is good for society.
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A rugby player is moving at an initial speed of 2 m/s and takes a distance of 20 m to accelerate to 6 m/s. Calculate the acceleration of the rugby player.
Answer should include detailed steps!
The final velocity of the rugby player is 15.62m/s.
Explain what an acceleration is.Acceleration is the rate of change in both speed and direction of velocity over time. When something moves faster or slower in a straight line, it is said to have been accelerated.
Meter per second per second (m/s2) is the unit of acceleration. Definition. The force known as the snewton is that which, when applied to a mass of one kilogram, results in an acceleration of one metre per second per second.
Given,
Initial velocity u = 2m/s
distance s = 20 m
acceleration a = 6 m/s
v² = u²+ 2as
v² = 2² + 2×6×20
v² = 4+240
v² = 244
v = √244
v = 15.62m/s.
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Complete question is "A rugby player is moving at an initial speed of 2 m/s and takes a distance of 20 m to accelerate to 6 m/s. Calculate the final velocity of the rugby player."
A 2500-kg SUV travels around a circular track that has a radius of 85 m. The centripetal
force is 14236 N. What is the SUV's velocity? ()
Answer:
SUV's velocity is 22 m/s
Explanation:
[tex]F=\frac{mv^{2} }{r} \\\\v=\sqrt{\frac{Fr}{m} } \\\\v=\sqrt{\frac{14236 N * 85 m}{2500 kg} } \\\\v=22 \frac{m}{s}[/tex]
all frictional forces are considered to be negligible. what distance does the object fall 10 s after it is released from rest? responses 3 m
The distance can be calculated as 490m .
We are given that,
Time = t = 10s
Initial velocity = u = 0
Acceleration due to gravity= g = 9.8m/s²
Suppose v is the final velocity. Where "t" stands for time, "s" for distance, "u" for starting velocity, and "g" for the acceleration brought on by gravity. Currently applying the second Newtonian equation for motion,
s = ut + 1/2 gt²
Putting the values in above equation ,
s = 0 + 1/2 (9.8)(10)(10)
s = 1/2 × 980
s = 450m
In this case, the distance is 490 m.
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18. which factor does not significantly affect the amount of solar energy reaching the surface of earth?
Factor that does not significantly affect the amount of solar energy reaching the surface of earth is : distance between earth and sun.
What is the solar energy reaching the surface of earth?Solar radiation that reaches surface of the Earth without being diffused is called direct beam solar radiation. Sum of the diffused and direct solar radiation is called global solar radiation.
Rotation of earth also does not affect the amount of solar radiation received at the Earth's surface. Tilt, orientation, latitude, and climate can have great impacts on a solar system's performance.
Solar energy is generated by the nuclear reaction within the sun and this energy reaches the surface of the earth in the form of electromagnetic radiation.
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what is the near point in cm of a person whose eyes have an accommodated power of 54.8 d? (assume a lens-to-retina distance of 2.00 cm.)
The near point of a person whose eyes have an accommodated power of 54.8d (assuming a lens-to-retina distance of 2cm is 20.83cm.
What is accommodated (eyes)?It is the process by which certain muscles (called ciliary muscles) function to change the focal length of the eyes so that the image is clearly formed on the retina which is called accommodation of the eye.
How to calculate the near point based on the information given from the question?
Power = P = 54.8D
Distance between the lens and the retina, Di = 2cm = 0.02m
Distance between the object and eyes, Do (we are trying to answer this)
The formula that we will use :
1 / Do = P - 1 / Di
1 / Do = 54.8 - 1 / 0.02
1 / Do = 4.8
Do = 1 / 4.8
Do = 0.2083m = 20.83cm
Therefore, the near point of a person whose eyes have an accomodated power of 54.8D is 20.83cm.
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find the energy in joules of photons of radio waves that leave an fm station that has a 90.0-mhz broadcast frequency.
5.94 ×10-26 J of energy of photons of radio waves is required to leave an FM station having 90MHz broadcast frequency
A photon's energy E and frequency f are exactly related. This is expressed mathematically as
Equation
E=hf (1)
where h is the Planck constant.
Given that the frequency of the radio wave is f=90 MHz
=9.0×107 Hz
and knowing the fact that the numerical value of Planck's constant is h=6.6×10−34 m-m-kg/s
then the energy of the photon in J using Eq. (1) is:
E=6.6×10−34× 9×107
E=5.94 ×10-26 J
what is Frequancy?
The frequency of a repeated event is its number of instances per time unit. It differs from angular frequency and is sometimes referred to as frequency for clarification. The unit of frequency is hertz (Hz), or one occurrence per second. The duration is the inverse of frequency since it is the amount of time that passes between events.
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newton's second law in 1 dimension: a 40-kg crate is being lowered with a downward acceleration is 2.0 m/s2 by means of a rope. (a) what is the magnitude of the force exerted by the rope on the crate?
The magnitude of force exerted by the rope on the crate is 312 N.
From Newton's second law of motion, we know the expression of force as,
F = m * a
where, m is mass
a is acceleration
Given that, mass of the crate is 40 kg
Acceleration is 2 m/s²
The net force that the rope is applying to the card while it is sliding downward is given by,
F = m(g - a)
Substituting the values,
F = 40(9.8 - 2)
F = 312 N
Thus, the net force exerted by the rope on the crate is 312 N.
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Give an example of a sport wherre shoes with a low coefficient of friction would be advantageous.
The example of a sport where shoes with a low coefficient of friction would be advantageous are hockey, football and cricket.
What do sportsmen perform in sports that have little friction?The athlete can move more quickly down the slope when there is no friction. Because there is little surface area in contact with the ice, friction is decreased. A force that is often up to eight times greater than gravity is applied to the ice as the competitors speed around a curved path.
What role does the coefficient of friction play in athletics?In a sled-towing activity, an athlete's sprint time should presumably get longer as the coefficient of friction of the running surface rises because more of the athlete's muscular force is lost to sled friction.
In football, what kind of friction is used?Football Collision
When the football is rolling or sliding during a play, frictional forces are working against it. The reason behind this is that as these balls roll across the ground, surface friction creates an opposing force that significantly slows the ball down.
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an aluminum flagpole is 39.4 m high. by how much does its length increase as the temperature increases by 15
The length of the aluminum flagpole will increase by 0.00881 m as the temperature increases by 15.
The length of an aluminum flagpole may not change with temperature. While thermal expansion can cause materials to change in size when heated or cooled, aluminium, as a metal, is not significantly affected by temperature changes. As such, the length of an aluminium flagpole is unlikely to be significantly affected by changes in temperature.
Calculate the Coefficient of Linear Expansion for Aluminum
The coefficient of Linear Expansion for aluminum is about 0.000023 per degree Celsius
Calculate the change in length
Change in length = (Coefficient of Linear Expansion x Original Length x Change in Temperature)
Change in length = (0.000023 x 39.4 m x 15) = 0.00881 m
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two bodies A and B are moving with a velocity of 6m/s and 8m/s along the horizontal and the vertical directions respectively.what is the relative velocity of body A respect to body B.
objects such as the great nebula in andromeda were once called extragalactic nebulae. it is now realized that they are actually
Objects such as the Great Nebula in Andromeda were once called extragalactic nebulae. It is now realized that they are actually.
What is extragalactic system?Extragalactic systems are systems containing objects that lie outside the Milky Way. The branch of astronomy that deals with this massive region of space is called Extragalactic Astronomy. In other words, it is the polar opposite of Galactic Astronomy.
Are there extragalactic planets?Astronomers believe they've spotted the first extragalactic exoplanet beyond our own galaxy. Residing some 28 million light-years away near the heart of the Whirlpool Galaxy (M51), the binary system M51-ULS-1 consists of either a neutron star or a black hole that's tangoing with a more standard companion star.
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A plane is flying to Minnesota with a velocity of 265.62 km/h, N. The plane encounters a crosswind with a velocity of 56.07 km/h, W. What is the magnitude of the resultant velocity of the plane? (Answer in km/h)
Answer:
First, write the velocities in component f…
Explanation:
As per as calculations
Which statements are explained by Newton’s law of universal gravitation?{|
{|}Heavier objects fall faster than lighter objects.
{|}The strength of Earth’s gravity decreases as an object gets farther from Earth.
{|}The strength of gravity depends on an object’s mass.
{|}Mass and weight are the same quantities.
In the given explanations, Newton’s law of universal gravitation can be explained by the statement, "Heavier objects fall faster than lighter objects". Thus, Option A is the correct answer.
What is Universal Law?Gravity is a natural phenomenon that causes all massive objects to attract each other. The magnitude or force of this interaction depends on the masses and distance of the bodies. This causes objects to fall toward Earth, for example, and keep satellites and celestial bodies in their orbits, such as the Earth's orbit around the Sun. Gravity also causes the tidal phenomenon.
In physics, gravity can be approximated by Isaac Newton's laws of gravity. Although the accuracy of the law is sufficient, for example, when calculating the orbits of spacecraft, gravity is best described by Albert Einstein’s general theory of gravity, in which it is considered the curvature of space-time.
Newton's law of universal gravitation states that a particle attracts every other particle in the universe with a force which is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers.
Hence, Option A is the correct answer.
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