Oscillations will have been completed when the amplitude is 30% of its initial value 236
A = Ao e (bt / 2 m),
Putting each of the values into the equation as a replacement:
A/Ao = e (b t / 2 m)
When A / Ao = 0.60 and t = 50 s, we discover that b is equal to 0.60 when A / Ao = 0.60 and ln (0.60) = b t / 2 m.
B = (2m) ln (0.60) / t B = (.200) (.60) / 50 B =.00409
We discover the following for t when A/Ao = 0.30: 0.30 = e( b t / 2 m) ln (0.30) = (0.00409) t / 2. (0.200)
t = − (0.200) ln (0.30) / 0.00409 t = 118 s
The number of oscillations is thus:
oscillations = f * t=2s-1(118s) = 236
A quantity oscillates repeatedly or periodically when it moves between two or more states or around a central value, which is frequently an equilibrium point. Two typical illustrations of oscillation are an alternating current and a swinging pendulum. Oscillations can be used in physics to model complex interactions like those between atoms.
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A wheel is rotating freely at angular speed 800 rev/min on a shaft whose rotational inertia is negligible. A second wheel, initially at rest and with twice the rotational inertia of the first, is suddenly couple to the same left.
What fraction of the original rotational kinetic energy is lost?
The fraction of the original rotational kinetic energy lost due to the sudden coupling of the second wheel with twice the rotational inertia of the first is 100%.
When the two wheels are coupled, their rotational energies are combined and shared. Since the second wheel is initially at rest, its rotational energy is 0 and thus all the original rotational kinetic energy is lost.
The rotational kinetic energy of the first wheel is given by KE = 1/2Iω2, where I is the rotational inertia and ω is the angular velocity. Since the second wheel has twice the rotational inertia, the combined rotational kinetic energy is 1/2(I1 + 2I2)ω2. Since I2 is initially 0, the combined rotational kinetic energy is 1/2I1ω2, which is half of the original rotational kinetic energy. Therefore, 100% of the original rotational kinetic energy is lost.
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in the figure, a conducting metal bar of mass 0.5 kg sliding along conducting rails is connected to a battery of emf 18 v and resistor r
The bar's maximum magnitude of the velocity under these circumstances is 240 m/s.
What does a definition of mass mean?In physics, mass is a statistical expression of inertia, a basic characteristic of all matter. It essentially refers to a body of matter's resistance to changing its speed or location in response to the use of a force.
Briefing:The metal bar is experiencing the force.
F = iLB = ELB/R
The bar will increase in speed until the battery emf equals the induced emf.
Eind = vLB
current, and the force is eliminated.
Then the maximum velocity v = E/LB
v = 18/0.30*0.25
v = 240 m/s
Hence Option (5) is correct.
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The complete question is-
In the figure, a conducting metal bar of mass [tex]$0.5 \mathrm{~kg}$[/tex] sliding along conducting rails is connected to a battery of emf [tex]$18 \mathrm{~V}$[/tex] and resistor [tex]$R=200 \Omega$[/tex] to form a circuit. The rails are [tex]$30 \mathrm{~cm}$[/tex] apart and the entire arrangement is embedded in a uniform magnetic field [tex]$0.25 \mathrm{~T}$[/tex] directed into the page, as shown. Find the maximum velocity [tex]$v$[/tex] the bar attains under these conditions.
(1) [tex]$345 \mathrm{~m} / \mathrm{s}$[/tex]
(2) [tex]$68 \mathrm{~m} / \mathrm{s}$[/tex]
(3) [tex]$98 \mathrm{~m} / \mathrm{s}$[/tex]
(4) [tex]$135 \mathrm{~m} / \mathrm{s}$[/tex]
(5) [tex]$240 \mathrm{m} / \mathrm{s}$[/tex]
Unpolarized light of Intensity Io is incident on a pair of (ideal) polarizers, as shown below. The direction of polarization of the first polarizer is vertical. The second polarizer has unknown orientation.For each part below, determine whether it is possible for the light that reaches the observer to have the given value of intensity.If so: Determine the direction of polarization of the second polarizer. Show all work.If not: Explain by not.a. No light reaches the observerb. Light of intensity (2*Io)/3 reaches the observer.c. Light of intesity Io/2 reaches the observer.d. Light of intensity Io/4 reaches the observer.
The un polarization of light at each state was explained and second polarizer is I2=I1=Io/2 and first polarizer is I2=Io/4=Io/2 cos^(q).
What is polarization?
Polarized light waves are defined as those light waves that only travel in one plane. The polarization of light is the process by which unpolarized light waves are converted to polarized light waves.
What is un polarization ?
Unpolarized light is a form of electromagnetic radiation that vibrates in more than one plane. Unpolarized light is the kind that comes from the sun, a desk lamp, or a candle flame.
a) When the pass axis of the two polarizers are perpendicular to each other.
b) Not possible, because after first polarizer intensity becomes Io/2.
from malus law after second polarizer I2=I1 cos^2(q)
I2=2Io/3, cos^2(q)=4/3, q=cos^-1(1.15) Which does not exist.
c) When the pass axis of the second polarizer is parallel to first i.e q=0
I2=I1=Io/2.
d) I2=Io/4=Io/2 cos^(q)
cos^(q)=1/2, q=45 degree w.r.t pass axis of the first polarizer.
Therefore, the un polarization of light at each state was explained and second polarizer is I2=I1=Io/2 and first polarizer is I2=Io/4=Io/2 cos^(q).
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Linearity is an extremely useful property of equations in physics. If an equation is linear, it allows you to easily add together simple contributions from individual elements to get a solution for a more complex situation. One example of a simple linear equation in classical mechanics is F = ma. If you find the individual accelerations of a particular body due to various individual forces, you can then add those accelerations to find the acceleration due to all of the forces acting together. If Newton's second law were not linear, introductory physics would be a much more difficult and confusing subject!
The schrodinger's equation for [tex](A\phi_1+AU\Psi_1)+(B\phi_2+BU\Psi_2)[/tex] for the particular U and E can be expressed as [tex](A\phi_1+AU\Psi_1)+(B\phi_2+BU\Psi_2)=E(A\Psi_1+B\Psi_2)[/tex].
The solution to the equation is based on Fourier's Eigen Values method. This is the expression for any mathematical function as the sum of an infinite series of other periodic functions. The trick is to find the right functions with the right amplitudes so that when they are superimposed, they give the desired solution.
As a result, the solution to Schrondinger's equation, the system's wave function, was replaced by the wave functions of the individual series, natural harmonics of each other, resulting in an infinite series. Shrodinger discovered that replacement waves described individual states of the quantum system, and their amplitudes indicated the relative importance of that state to the entire system.
The schoringer 's equation is
[tex]-\frac{h^2}{2m}\frac{d\psi^2}{dx^2}+U(x) \psi=E\psi[/tex]
here, the E is the energy of the particle.
since the wave function [tex]\psi_1[/tex] is the solution of the schrodinger's equation,
[tex]-\frac{h^2}{2m}\frac{d\psi_1^2}{dx^2}+U(x) \psi=E\psi_1[/tex]
Since, the wave function [tex]\psi_2[/tex] is the solution of the schrodinger's equation,
[tex]-\frac{h^2}{2m}\frac{d\psi_2^2}{dx^2}+U(x) \psi=E\psi_2[/tex]
Then,
[tex](A\phi_1+AU\Psi_1)+(B\phi_2+BU\Psi_2)=(A(-\frac{h^2}{2m}\frac{d\Psi_1^2}{dx^2})+AU\Psi_1)+(B(-\frac{h^2}{2m}\frac{d\Psi^2}{dx^2})+BU\Psi_2)\\\\=A(-\frac{h^2}{2m}\frac{d\Psi_1^2}{dx^2}+U\Psi_1)+B(-\frac{h^2}{2m}\frac{d\Psi_1^2}{dx^2}+U\psi_2)\\\\=A(-\frac{h^2}{2m}\frac{d\Psi_1^2}{dx^2}+U(x)\Psi_1)+B(-\frac{h^2}{2m}\frac{d\Psi_1^2}{dx^2}+U(x)\psi_2)\\\\=A(E\Psi_1)+B(E\Psi_2)\\\\=E(A\Psi_1+B\Psi_2)[/tex]
Thus, the schrodinger's equation for particular U and E can be expressed as [tex]E(A\Psi_1+B\Psi_2)[/tex].
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Your question is incomplete, here is the complete question in the figure,
the beam contains the same number of red-light photons and blue-light photons, since the energy in the corresponding spectra is distributed equally. the beam contains a greater number of red-light photons, since they are less energetic relative to blue-light photons so that more red-light photons are needed to correspond to the total energy of blue-light photons. the beam contains a greater number of blue-light photons, since they are less energetic relative to red-light photons so that more blue-light photons are needed to correspond to the total energy of red-light photons.
The energy of the photon increases with frequency. The number of photons in a beam of light is obvious. This indicates that extremely bright red light (lots of photons, with slightly lower energy).
Which type of light beam—red or violet—emits more electrons?The increased energy of a violet photon interacts with a single electron and gives it enough energy to escape the metal, making violet light more effective. The frequency of the light determines the electron's energy.
Why do red light sources produce more photons?Red light has a lower photon energy than blue light due to its shorter wavelength, lower frequency, and longer wavelength.
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Public Radio station KXPR-FM in Sacramento broadcasts at 88.9 MHz. The radio waves pass between two tall skyscrapers that are 15.0m apart along their closest walls.
A). At what horizontal angles, relative to the original direction of the waves, will a distant antenna not receive any signal from this station?
B).If the maximum intensity is 3.40W/m2 at the antenna, what is the intensity at �6.00? from the center of the central maximum at the distant antenna?
For radio-waves in Public Radio station KXPR-FM, the horizontal angles and intensity is-
(A) 1.4597 rad is the horizontal angles, relative to the original direction of the radio-waves.
(B) The intensity will be 1.576 W/m² for the given radio-waves.
Radio waves are a type of electromagnetic radiation. A radio wave has a much longer wavelength than visible light. Humans use radio waves extensively for communications. This radio tower has both rectangular and circular antennas to transmit and receive radio frequency energy.
A radio wave is generated by a transmitter and then detected by a receiver. An antenna allows a radio transmitter to send energy into space and a receiver to pick up energy from space.
Radio waves are used for wireless transmission of sound messages, or information, for communication, as well as for maritime and aircraft navigation. The information is imposed on the electromagnetic carrier wave as amplitude modulation.
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use ohm's law to determine the resistance of the conductors between the first and last receptacles based on the voltage dropped across the branch circuit conductors and the circuit current when loaded to 80% capacity. note: the branch circuit overcurrent protective device is rated at 15 amperes. (round the final answer to three decimal places.)
The resistance of the conductors between the first and last receptacles is 10 ohms.
To determine the resistance of the conductors using Ohm's law, you will need to know the voltage dropped across the conductors and the current flowing through them when the circuit is loaded to 80% capacity. Ohm's law states that the resistance of a conductor is equal to the voltage dropped across it divided by the current flowing through it. Therefore, the resistance of the conductors can be calculated using the following formula:
Resistance (R) = Voltage (V) / Current (I)
Assuming that the voltage dropped across the conductors is V and the current flowing through the conductors is I, the resistance of the conductors can be calculated as follows:
R = V / I
If the circuit is loaded to 80% capacity, the current flowing through the conductors will be 80% of the rated capacity of the overcurrent protective device, which is 15 amperes. Therefore, the current flowing through the conductors will be 0.8 * 15 amperes = 12 amperes.
If the voltage dropped across the conductors is V, the resistance of the conductors can be calculated as follows:
R = V / 12 amperes
To express the resistance in ohms, the units of amperes must be canceled out. Therefore, the resistance of the conductors can be expressed as follows:
R (ohms) = V (volts) / 12 (amperes)
If you know the values of V and I, you can substitute them into the formula above to calculate the resistance of the conductors.
For example, if the voltage dropped across the conductors is 120 volts and the current flowing through the conductors is 12 amperes, the resistance of the conductors would be:
R = 120 volts / 12 amperes = 10 ohms
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the luminosity of star a is 26 time bigger than luminosity of star b. star a is also known to be 3 times closer than star b
The luminosity of star a is 78 times bigger than star b.
The luminosity of star a is 78 times bigger than star b because the luminosity of star a is 26 times bigger than the luminosity of star b but star a is also 3 times closer than star b, so the difference in luminosity is amplified by a factor of 3. This means the luminosity of star a is 26 times 3, or 78 times bigger than star b.
The luminosity of a star is directly related to its distance from us. The closer a star is, the brighter it will appear. This is because the amount of light we receive from a star is inversely proportional to the square of its distance from us.
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the circuit of (figure 1) is a square 20 cm on a side. the magnetic field increases steadily from 0 t to 0.90 t in 10 ms. What is the current in the resistor during this time? Express your answer to two significant figures and include the appropriate units.
According to Faraday's law, the various magnetic flux via a closed loop induces an emf in it, given by E=−dϕdt so the current in the resistor during this time is 0.81818 A.
Here we have;
ϕ=∫B.dA is the magnetic flux via the loop.Answer and Explanation:Given:Length of the facet of square: a = 30 cm = 0.3 mMagnetic area withinside the place will increase from B = 0 T to B = 0.9 T in t = 11 msBattery emf: V = 9 VResistance: R = 20 ΩCurrent because of the battery is: I1 = VR = 920 = 0.45 A (clock clever direction)As the magnetic area withinside the place is various, flu via the loop is likewise various and is given by:dϕdt = dBdt×A = 0.9−00.011×0.32 = 7.3636 Tm2According to Faraday's law, brought on emf is: Vind = dϕdt = 7.3636 VInduced contemporary: I2 = VindR = 7.363620 = 0.36818 ADirection of the brought on contemporary might be clockwise as it might generate magnetic area into the aircraft of the web page and therefore lowering the flux via the place.Therefore, general contemporary withinside the circuit will be:I = I1 + I2 = 0.45 + 0.36818 = 0.81818 ARead more about current;
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a toroid has a 50.8 cm inner diameter and a 53.7 cm outer diameter. it carries a 24.7 a current in its 604 coils.(figure 1) (figure 2). Determine the range of values for B inside the toroid. There should be two values, B(min) and B(max), in mT.
The range of values for B inside the toroid is: B(min) = 1.37 mT and B(max) = 3.37 mT
The range of values for B inside the toroid can be determined using the formula B = μ0nI/l, where μ0 is the permeability of free space, n is the number of turns, I is the current, and l is the average length of the toroid. The average length of the toroid is equal to the average diameter, which is (50.8 cm + 53.7 cm)/2 = 52.25 cm. Therefore, B = μ0nI/l = (4π×10^-7 H/m)(604 turns)(24.7 A)/(52.25 cm) = 0.0022 H/m. Since 1 mT = 10^-3 T, the range of values for B inside the toroid is 1.37 mT (B(min)) and 3.37 mT (B(max)).
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At point A, 4.40 m from a small source of sound that is emitting uniformly in all directions, the intensity level is 53.0 dBPart AWhat is the intensity of the sound at A?Part BHow far from the source must you go so that the intensity is one-fourth of what it was at A?Part CHow far must you go so that the sound level is one-fourth of what it was at A ?Part DDoes intensity obey the inverse square law?Part EDoes intensity level obey the inverse square law?
No, intensity level does not follow inverse square law.
The Inverse Square Law Formula: What Does It Mean?The square of the distance between the source and the observer determines how intense the light is for the observer. This demonstrates that the intensity of light is proportional to a value multiplied by 1/d² as the distance to a light source increases.
Here,
intensity level = 53 dB
distance, d = 4.4 m
part A)
let the intensity is I
Intensity level = 10×log(l/1×10⁻¹²)
53 = 10 ×log(1/1×10⁻¹²)
solving for I
I = 1.995 ×10⁻⁷ W/m²
the intensity of sound at A is 1.995 ×10⁻⁷W/m²
part B)
for the sound intensity to be one fourth.
as sound intensity = 1/(4×π×d²)
hence, the distance must be made two times,
new distance = 4.4 ×2
new distance = 8.8 m
the distance from the source is 8.8 m
part C)
distance to move from point A = 8.8 - 4.4
distance to move from point A = 4.4 m
part D)
yes, the intensity follow the inverse square law
part E)
for the intensity level,
as I = 10 × log(P/(4×π×d²×10))
hence, intensity level does not follow inverse square law.
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Student 1 brings a negatively charged rod with an insulating handle near to but not touching an uncharged metal sphere and finds that the objects attract. She wants the sphere to be repelled by the rod. Student 2, who is uncharged, suggests that this can be accomplished if he touches the sphere. Which of the following indicates whether this will work, and if so, gives a procedure that will cause the repulsion? (A) Yes, Student 2 could touch the sphere while the rod is held near it, because that would make the sphere negatively charged. (B) Yes, Student 2 could touch the sphere while the rod is kept far away, because that would make the sphere negatively charged. (C) Yes, Student 2 could touch the sphere while the rod is kept far away, because that would make the sphere positively charged. (D) No, there is no way that having Student 2 touch the sphere will work.
No, there is no way that having Student 2 touch the sphere will work. There will be no repulsion by touching the sphere whether the rod is kept near or away. No way cause the sphere negatively charged.
Charging an uncharged body by bringing near to it a charged body is called charging by induction. In the given case negatively charged rod is brought near to uncharged sphere, then all positive charges on it realigns towards the end of the rod by attraction.
When it is touched while keeping the rod closer, all negative charges are grounded passing through body. Thus sphere has now only positively charges. When rod is removed, the positive charges distributes uniformly ands sphere becomes positively charged.
In no way sphere will be negatively charged for repulsion to occur.
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Calculate the velocity for a 20kg object with 2,00J of KE.
so this is the answer velocity =10√2
A uniform, rigid, thin board that is 2.4m long and weighs 200N is attached to a post by a pivot at point P and hangs over the edge of a building. A crate weighing 400N is attached to the right end of the board. The left end of the board, .8m from the pivot, is attached to a light vertical wire anchored at the other end to keep the board from rotating.
1. Draw and label vectors on a horizontal board to represent forces acting on the board (not components). Show each force vector originating at its point of application.
2. Calculate the magnitudes of the forces exerted on the board by the post and by the wire. If you need to draw anything other than what you have shown in part 1 to assist in your solution, use the space below. Do not add anything to the figure in part 1
3. The rotational inertia of the board alone about its center is (1/12)Ml2 , where M is the mass of the board and L is its length. Calculate the rotational inertia of the combined board-crate system about point P
4. Suppose that the wire breaks and the board begins to pivot about point P. Calculate each of the following
(a) The magnitude of the initial angular acceleration of the board-crate system.
(b) The magnitude of the initial linear acceleration of the left end of the board.
1. Diagram (Attached above)
2. By equilibrium of forces of vertical direction,
T + Wa +Wc = Rp
T + 200 + 400 = Rp
Rp - P = 600N ------------------(i)
Taking moment of forces about P (Clockwise positive),
Wb * 0.4m + Wc * (0.4 + 1.2m) – T * 0.8m = 0
200 * 0.4 + 400 * 1.6 – 0.8T = 0
0.8T = 80 + 640
T = 900N
Putting T in equation (i),
Rp - 900= 600
Rp = 1500N
So, Rp= 1500N, T = 900N, Wb = 200N, Wc = 400N
3. Moment of inertia about C.O.M. ‘O’ is Icom= 1/12 ML2
Moment of inertia about ‘P’ by parallel axis theorem
Ip = Icom + M * (OP)2
Ip= 1/12 ML2+ M * (0.4)2
For net MOI about P, mass of crate Mc at distance PC from P will also be taken in account.
Mc = 400 / 9.8 = 40.8Kg, PC = 1.6m
Mass of board M = 200/9.8 = 20.4 Kg
Length of board L = 2.4m
So, Net M.O.I. about P,
Ip net = Icom + M*(0.4)2 + Mc * (PC)2
Ip net= 1/12 * 20.4*(2.4)2 + 20.4*(0.4)2+ 40.8*(1.6)2
Ip net = 117.5 Kg m2
4.
a. As, the moment of inertia about point P, Ip net =117.5 Kg m2
Torque experienced when wire is cut
τ = Wb * 0.4 + Wb * (0.4 + 1.2)
τ = 200 * 0.4 + 400 *1.6
τ = 720 N-m
As τ = I α, where α is angular acceleration.
720 = 117.5 * α
α = 6.127 rad / s2
So, magnitude of initial angular acceleration is α = 6.127 rad / s2
b. Initial Acceleration (linear) of left most point A
aA = α * AP
aA= 6.127 * 0.8
aA= 4.9 m/s2
So, linear acceleration of point A is 4.9 m/s2
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degeneracy pressure results from the uncertainty principle. general relativity. special relativity. the exclusion principle.
The exclusion principle, is the degeneracy pressure, results from the uncertainty principle. Correct answer: letter C.
Since, the pressure that arises when the electrons in an atom occupy all the available quantum states, which makes it difficult for additional electrons to enter the atom.
What is the difference between the exclusion principle and the uncertainty principle?The exclusion principle and the uncertainty principle are two distinct principles.
The exclusion principle states that no two electrons in an atom can have the same set of quantum numbers, while the uncertainty principle states that the position and momentum of a particle cannot both be known with precision.
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The G string on a guitar is a 0.46 mm diameter steel string with a linear density of 1.3 g/m. When the string is properly tuned to 196 Hz, the wave speed on the string is 250 m/s. Tuning is done by turning the tuning screw, which slowly tightens - and stretchs - the string. By how many mm does a 75 cm long G string stretch when it's first tuned?
A 75 cm long G string stretch when it's first tuned is 1.833 mm.
Density (volumetric mass density or specific mass) is the mass of matter per unit volume. The most commonly used symbol for density is ρ (lowercase Greek letter rho), but the Latin letter D can also be used. Mathematically, density is defined as mass divided by volume.
v = sqrt(T/mu)
250 = sqrt(T/(1.3x10^-3))
So T = 81.25 N
Young's modulus for steel = 200 x 10^9 Pa
Y = (T/A)/(deltal/l) = T*l/(deltal*A)
So deltal = (T*l)/(Y*A) = 81.25*0.75/(200x10^9*pi*(0.23x10^-3)^2) = 1.833 x 10^-3 m
R = 1.833 mm.
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When a country burns its forests, neighboring countries may suffer from air pollution as well. Why are air pollutants produced by forest fires in one country able to travel to neighboring countries?
Answer:
Air pollutants produced by forest fires in one country are able to travel to neighboring countries because of the way air moves and circulates around the globe. The Earth's atmosphere is made up of a mixture of gases, including oxygen and carbon dioxide, which are capable of moving and circulating through the air. When pollutants, such as those produced by forest fires, are released into the atmosphere, they can be carried by wind and other atmospheric phenomena, allowing them to travel over long distances and affect other regions and countries. This is why air pollution from forest fires in one country can affect neighboring countries.
I have got the answers to these question but I need to find the working out pls if you are able to answer at least one please do
calm :), thanks mods
A rectangular swimming pool has dimensions of 15 m x 30 m and is 3.5 m deep. When the pool is filled with fresh water, what is the force on the side of the pool due to the water?
The total force on the side of the pool due to the water is 2275 N/m^2 x (15 m x 3.5 m) = 1523125 N.
To find the force on the side of the pool due to the water, we first need to calculate the volume of the water in the pool. Since the pool has dimensions of 15 m x 30 m and is 3.5 m deep, its volume is 15 m x 30 m x 3.5 m = 1575 cubic meters. Next, we need to calculate the weight of the water in the pool. The weight of an object is equal to its mass multiplied by the acceleration due to gravity. The density of fresh water is about 1000 kg/m^3, so the mass of the water in the pool is 1575 m^3 x 1000 kg/m^3 = 1575000 kg. Since the acceleration due to gravity is approximately 9.8 m/s^2, the weight of the water in the pool is 1575000 kg x 9.8 m/s^2 = 15442500 N. Finally, we can calculate the force on the side of the pool due to the water. Since the force is distributed evenly over the surface of the side of the pool, the force on each square meter of the side of the pool is 15442500 N / (15 m x 3.5 m) = 2275 N/m^2. Therefore, the total force on the side of the pool due to the water is 2275 N/m^2 x (15 m x 3.5 m) = 1523125 N.
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To understand the standard formula for a sinusoidal traveling wave One formula for a wave with a y displacement (e.g., of a string) traveling in the x direction is y(x, t) A sin(kx-wt) All the questions in this problem refer to this formula and to the wave it describes. Part A Which of the following are independent variables? O x only O t only O A only O k only O w only O xand t O w and t
O A and k and w Submit
The displacement of the sinusoidal wave travelling withinside the x course is y(x,t)=Asin(kx-wt).
This is described as a propagation of disturbances from vicinity to vicinity in a ordinary and prepared way.
The unbiased variables are x and t• Parameters that decide the traits of the wave are amplitude A, propagation steady okay and angular frequency wThe section phi(x,t) of the wave is (kx-wt)The wavelength A of the wave λ = 2π/ okayThe duration T of the wave = 2pi / omega• The pace of propagation v of the wave = w/okayRead extra approximately Waves here
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an inclined ramp is set up on your table. from the top of the ramp, you release a disk, hoop, and solid sphere at the same time. all objects are well manufactured with exactly the same mass. they are completely uniform and roll without slipping. which object reaches the bottom of the ramp first, second and third? select from the following, which are listed in order of first, second, third.
By evaluating the moment of inertia of the bodies, we get that the Solid Sphere will reach first, followed by the disk and hoop respectively.
Torque is the product of the moment of inertia and angular acceleration.
If torque is constant, the angular acceleration will be less for a large moment of inertia.
So, the object will smaller moment of inertia (I), the acceleration will be more, and thus, it will reach the bottom of the ramp first.
The given objects are disk, hoop, and solid sphere.
The moment of inertia of the Hoop = [tex]MR^{2}[/tex]
The moment of inertia of the Disk = [tex]\frac{1}{2} MR^{2}[/tex]
The moment of inertia of a solid sphere = [tex]\frac{2}{5} MR^{2}[/tex]
So, the moment of inertia for the hoop is greater than the disk and solid sphere.
[tex]I_{s} < I_{d} < I_{h}[/tex]
Thus, Solid Sphere will reach first, followed by disk and hoop respectively.
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the uncertainty principle states that the more we know about the location of a particle, the less we can know about its: momentum. charge. mass. spin.
The uncertainty principle states that the less we can know about a particle's momentum, the more we can know about its location. A particle's mass multiplied by its momentum determines its momentum.
The uncertainty principle also implies the impossibility of precisely measuring a system's energy in a finite length of time. Measurement of Position and Momentum at the Same Time Is Not Possible. Take an example where the location of an electron is measured to demonstrate Heisenberg's uncertainty principle. An extremely precise measurement of one observable results in a comparatively high degree of measurement uncertainty for the other. A particle's momentum and position can also be used to describe the uncertainty principle.
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the gravitational constant g was first measured accurately by henry cavendish in 1798. he used an exquisitely sensitive balance to measure the force between two lead spheres whose centers were 0.19 m apart. one of the spheres had a mass of 138 kg, while the mass of the other sphere was 0.93 kg.
The answer is
3.5*10^-8:1
Explanation:
F(gravitation) = G*M1M2/r^2
G = gravitational constant = 6.67*10^-11 Nm^2/kg^2
M1 = mass of the heavier sphere,
M2 = mass of the lighter sphere
r = their distance apart
Fg = 6.67*10^-11*188*0.93/(0.19)^2
Fg = 3.23*10^-7N
The ratio of the force of gravitation between them to the weight of the lighter sphere = 3.23*10^-7: (0.93*9.81) = 3.5*10^-8. : 1 by dividing both side by (0.93*9.81)
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which of the following describes your ability to identify the sound of a musical instrument you have heard before
psychology
Answer: Recognition.
Explanation:
I'm pretty sure this is right !
The gauge pressure in a helium gas cylinder is initially 27atm . After many balloons have been blown up, the gauge pressure has decreased to 5atm .
One atm less than the absolute pressure is present in the gauge pressure. It is the variance between the absolute pressure inside the tank and the pressure outside. Therefor, the ratio is 0.185.
It is positive for pressures above atmospheric pressure and negative for pressures below atmospheric pressure; gauge pressure is the pressure as compared to atmospheric pressure. Any fluid that is not contained has its pressure increased by the atmospheric pressure. The pressure that exists inside the Earth's atmosphere is known as atmospheric pressure, also spelled barometric pressure (after the barometer). 101,325 Pa is the definition of the standard atmosphere, which is represented by the sign atm (1,013.25 hPa).
5/27 = 0.185 atm is the pressure ratio.
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10 rooster head questions
Answer:
How does a rooster's head differ from that of a hen?What is the function of a rooster's crest on its head?Can a rooster's head and neck change color during mating season?How does a rooster use its head and beak during courtship displays?How does a rooster use its head to establish dominance in a flock?Can a rooster's head and beak be used as a weapon against predators?How does a rooster's head and beak help it to find food?How does a rooster's head and beak help it to eat and digest food?Can a rooster's head and beak be used for vocalizations, such as crowing?What are some common health issues that can affect a rooster's head and beak?Here are ten questions about the story entitled "cabeza de gallo":
Who are the main characters in the play?What is the central theme of the story?What kind of narrator tells the story?What was the rooster game about?Where is the place where most of the story takes place?Were the protagonist's predictions correct?What holiday was being celebrated?Which were knocked down as creatures struck in the abdomen?Who is the author of the work?What lesson or message does the story convey?¿What is a tale?A story is a narration, either oral or written, about a story that may have happened in real life, or is the product of the author's imagination.
The stories have the characteristic of having few characters, and are shorter than any common text.
¡Hope this helped!
In shape and component stars, elliptical galaxies are most like our own
A. galactic center
B. spiral arms
C. nuclear bulge
D. halo
E. companions, the Magellanic Clouds
d
The correct option is D : Halo , In comparison to spiral galaxies, elliptical galaxies seem smooth, ellipsoidal, or spherical and have far less structure. Galaxy clusters are generally home to elliptical galaxies.
There are stars, planets, interstellar dust, and gases in elliptical, spiral, and irregular galaxies alike. The same gravitational forces that create other galaxies also create these three different sorts of galaxies.
Old stars, a tiny amount of gas, and dust can be found in elliptical galaxies. In contrast to open clusters, stars in these galaxies coalesce into globular clusters. Individual stars, nebula, and clusters are visible in some irregular galaxies but are invisible in other irregular galaxies.
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An automobile radiator may be viewed as a cross-flow heat exchanger with both fluids unmixed. Water, which has a flow rate of 0.05 kg/s, enters the radiator at 400 K and is to leave at 330 K. The water is cooled by air that enters at 0.75 kg/s and 300 K.
a) If the overall heat transfer coefficient is 200 W/ m2 .K, what is the required heat transfer surface area?
b) Repeat part (a), except assume that the air flow is mixed.
c) Suppose that the heat exchange area of the radiator is 1.0 m2 , and that U and the inlet temperatures are the same as in part (a) (both outlet temperatures are unknown). If the mass flow rates are also the same as in part (a), what is the water outlet temperature? Assume that the air flow is mixed.
Area required to achieve a prescribed outlet temperature is 1.51m².
What is Temperature?
The term "temperature" describes how hot or cold a body is. It is, specifically, a method of calculating the kinetic energy of the particles that make up an item. When particles travel more quickly, the temperature rises, and vice versa.
Nearly every aspect of daily life as well as every scientific field, from physics to geology, depend heavily on temperature
Assumptions: (1) Negligible heat loss to surroundings and kinetic and
potential energy changes, (2) Constant properties.
Analysis: The required heat transfer rate is
q = (m c)h (T h,i - T h,o)
= 0.05 kg/s (4209J / kg.K) 70K = 14,732 W
Using the ε-NTU method,
Cmin = Ch
= 210.45 W / K
Cmax = Cc
=755.25W / K
Hence, Cmin/Cmx(Th,i - Th,o)
= 210.45W / K(100K)
= 21,045W
and
ε=q/qmax
= 14,732W / 21,045W = 0.700
NTU≅1.5, hence
A=NTU(cmin / U)
= 1.5 x 210.45W / K(200W) / m² .K)
= 1.58m²
1. the air outlet is..
Tc,o = Tc,i + q / Cc
= 300K + (14,732W / 755.25W / K)
= 319.5K
2. using the LMTD approach ΔTlm
= 51.2 K,, R=0.279 and
P=0.7
hence F≅0.95 and
A = q/FUΔTlm = (14,732W) / [0.95(200W / m².K) 51.2K]
= 1.51m²
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dentica bcams of light arc incident on thrcc diffcrent pairs of (idcal) polarizers. Thc double arrow drawn on cach polarizer represents its direction of polarization. Case Unpolarized light Case B Unpolarized light Case C Unpolarized light Suppose that the incident light in each case were unpolarized. Rank the three cases (A-C) according to the intensity of the light transmitted past the sccond polarizer; from largest to smallest: If, for any casc, no light is transmitted past the second polarizer; state 50 explicitly. Explain your easoning Now suppose that Ihe incident light in each case were polarized in the vertical direction. Rank the three cases A-C) according to the intensity of the light transmitted past the second polarizer; from largest to smallest If; for any case; no light is transmitted past the second polarizer; state explicitly. Explain your reasoning:
Unpolarized light has light waves that are oriented in all directions while polarized light has all the light waves oscillating in one direction. An example for unpolarized is the Sun, or any other simple type of light.
Whereas if unpolarized light is originally updates, the diffraction pattern will be slightly horizontally polarized, according to the stated assertion.
The light that strikes the object as incident light from the source but also reflects off it is alluded to as refract. It makes no difference what the flashlight is or what you are photographing. When light strikes anything, it will always be transformed and reflected.
A portion of the light is dispersed around a different wavelength; this is called Raman scattering.
Therefore, a portion of the light is dispersed when unpolarized light hits a sample. Rayleigh scattering is the process wherein most of the dispersed light shares the same frequency as the incoming light.
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An object attached to one end of a string moves in a circle at constant speed. Which of the following is correct?
the object is accelerating as it moves
the object's velocity is the same as its speed
the object does not require a force to keep its state of circular motion
if the string breaks, the object will keep its circular motion
If the string breaks, the object will move Radially away from the center of the cicl
The object is accelerating as it moves in a circle at constant speed. This is because acceleration is a measure of how an object's velocity changes over time, and the velocity of an object moving in a circle is constantly changing direction.
The object's velocity is not the same as its speed. Speed is a scalar quantity that refers to the distance an object travels per unit of time, while velocity is a vector quantity that refers to the speed and direction of an object's motion. The velocity of an object moving in a circle will vary as the object moves around the circle, even if its speed remains constant.
An object moving in a circle does require a force to keep its state of circular motion. This force is known as the centripetal force, and it is directed towards the center of the circle. The centripetal force is necessary to keep the object moving in a circular path, rather than following a straight-line path.
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