A 200 ω resistor, a 0.850 h inductor, and a 5.75 μf capacitor are connected in series across a voltage source that has voltage amplitude 29.0 v and an angular frequency of 260 rad/s.

a. What is v at t= 22.0 ms ?
b. What is vR at t= 22.0 ms ?
c. What is vL at t= 22.0 ms ?
d. What is vC at t= 22.0 ms ?

Answers

Answer 1

The root mean square voltage Vrms of the circuit is 15.49 V.

The voltage of the resistor vR is 10.4 V.

The voltage of the inductor vL is 11.49 V.

The voltage of the capacitor vC is 0.035 V.

RMS voltage of the circuit is calculated as follows:

Vrms = -V₀ sin ωt = -29 * sin (260* 22* 10⁻³) = 29 * 0.534 = 15.49 V

XI = ωL = 260* 0.85 = 221 ohms

Xc = 1/ωc = 1/(260 * 5.75* 10⁻³) = 10³/1495 = 0.67 ohm

Z = √[R² +(XI - Xc)²] = √[200² + (221 - 0.67)²] = √[200² + 220.33²]

= √[ 40000 + 48545.30] = 297.56 ohm

Current flowing in the circuit is

Irms = Vrms/Z = 15.49 / 297.56 = 0.052 A

vR = Irms * R = 0.052 * 200 = 10.4 V

vL = Irms * L =  0.052 * 221 = 11.49 V

vC = Irms * C = 0.052 * 0.67 = 0.035 V

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It’s for sure United States (B)

Two waves, each with an amplitude of 0.5m are superimposed with constructive interference such that they are in phase. Describe the resultant amplitude

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Which of the following situations best represents a set of balanced forces?
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Answer:

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Answer:

Atoms are made up of various parts; the nucleus contains minute particles ... neutrons, and the atom's outer shell contains other particles called electrons. ... Physical Forms of Radiation; Radioactive Decay; Nuclear Fission; Ionizing Radiation ... of high-energy waves that can travel great distances at the speed of light and ...

Explanation:

The true statement of an alpha particle is it is an electron. The correct option is B.

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Decibels measure sound intensity- which would be D. Amplitude.

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Answers

Answer:

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Explanation:

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Answers

Answer:

R' = 4R

Hence, the resistance increases to four times its initial value as well.

Explanation:

The resistance of a conductor in terms of its physical dimensions can be given by the following formula:

[tex]R = \frac{\rho L}{A}\\[/tex]  _______ equation (1)

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ρ = resistivity of the material of the conductor

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Now, if the length of the conductor is increased to four times, keeping other values constant, then:

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....................

PLEASE HELP! A 0.423 kg object carries a +11.5 uc
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Answers

Answer:

2.15 m/s²

Explanation:

We'll begin by calculating the force of attraction between two charges. This can be obtained as follow:

Charge of 1st object (q₁) = +11.5 μC = +11.5×10¯⁶ C

Charge of 2nd object (q₂) = –7.55 μC = –7.55×10¯⁶ C

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Distance apart (r) = 0.925 m

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F = Kq₁q₂ / r²

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F = 0.781425 / 0.855625

F = 0.91 N

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2.15

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Answers

Answer:

Hello your question has some missing part attached below is the missing part

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Answers

Answer:

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Explanation:

From the question,

Applying,

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A boy who is riding his bicycle, moves with an initial velocity of 5 m/s. ten second later, he is moving at 15 m/s. what is his acceleration

Answers

[tex]\Large {{ \sf {Question :}}} [/tex]

A boy who is riding his bicycle, moves with an initial velocity of 5 m/s. Ten second later, he is moving at 15 m/s. What is his acceleration?

[tex]\Large {{ \sf {Given :}}} [/tex]

Initial Velocity (u) - 5 m/sFinal Velocity (v) - 15 m/sTime (t) - 10 sec

[tex]\Large {{ \sf {Formulae :}}} [/tex]

If the velocity of an object changes from an initial value u to the final value v in time t, the acceleration a is, [tex]a \: = \frac{v - u}{t} [/tex][tex]\Large {{ \sf {Step-by-step explanation :}}} [/tex]

[tex]a \: = \frac{v - u}{t} \\ or \: \: a = \frac{(15 - 5)}{10} m \: s^{ - 2} \\ or \: \: a \: = \frac{10}{10}m \: s^{ - 2} \\ or \: \: a = 1m \: s^{ - 2} [/tex]

[tex]\Large {{ \sf {Answer :}}} [/tex]

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Answers

Answer:

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Answer:

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