how do we determine the amount of dark matter in elliptical galaxies? how do we determine the amount of dark matter in elliptical galaxies? we measure the range of speeds of collections of stars at different distances from the galactic center and determine how much mass is interior to their orbits. we count the number of stars in the galaxy and determine its volume, so that we can calculate the galaxy's density. we measure how fast the galaxy rotates as a whole. we measure the orbital velocities of star-forming gas clouds around the outer portions of the galaxy. we search for dark lanes of dust and black holes within the galaxy.
To determine the amount of dark matter in elliptical galaxies, we have to: B. Measure the speeds of stars at different radii from the galactic center and determine how much mass is interior to the orbit.
How to measure dark matter in elliptical galaxies?Dark matter is a type of matter in the universe that does not interact with electromagnetic force. So, unlike ordinary matter, it does not absorb, reflect, or emit light. One of three ways to determine the amount of dark matter in elliptical galaxies is by measuring the galaxy's radius and the average of stars' movement (stars' speed) of that galaxy. We also need to calculate the ratio of mass-to-light from there. This method of measurement is called dynamical mass.
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Maryam used the graduated cylinder to measure the volume of an unknown liquid in the physics lab the volume she measured was 46.0 mL then the teacher asked her to mix it with 1.20 mL of water (what is the value of the mixture in (L) )
The total volume of the liquid in the graduated cylinder in liters is 0.0472 L.
What is the total volume of the mixture?The total volume of the mixture is the sum of the volume of all the liquid in the cylinder.
Mathematically, the formula for the total volume of the liquid in the graduated cylinder is calculated as follows;
V ( total ) = volume of the liquid + volume of the water
The given parameters include the following;
The volume of the liquid in the graduated cylinder = 46 mL
The volume of water in the graduated cylinder = 1.2 mL
The total volume of the liquid in the graduated cylinder is calculated as;
V (total) = 46 mL + 1.2 mL
V (total) = 47.2 mL
The total volume of the liquid in the graduated cylinder in liters is calculated as;
V (total in liters) = 47.2 mL / 1000 = 0.0472 L
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a stalled car is being pushed up a hill with increasing velocity by three people. the net force on the car must be
Three persons are pushing a stopped automobile up a hill at an increasing speed, hence the net force exerted on the car has to be zero.
Is what velocity, for example in the case?The speed at which anything goes along a certain path is referred to as its velocity. as fast as a car traveling north on a highway, even, or as fast as a rocket taking off. The velocity vector's absolute amount has always been equal to the motion's speed since it is a scalar.
Can velocity change direction?The pace at which an object's position varies over time is referred to as its velocity (displacement). Speed can only be beneficial, unlike velocity, which includes combined speed and direction, which may be neither favourable or negative.
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an induced current flows clockwise as the metal bar is pushed to the right. the magnetic field points
The magnetic field will point in anticlockwise direction
What is Fleming's right hand rule?Fleming's right hand rule states that If the thumb shows the direction of motion, index finger shows the direction of the magnetic field and middle finger are held mutually perpendicular, then middle finger gives the direction of induced emf/current in the wire.
Fleming's right hand rule is used to determine the direction of an induced current in a coil.
Since the magnetic field and the induced current move in opposite directions, then if the induced current flows clockwise, the magnetic field will move in anticlockwise direction
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Why do excavators have broad steel track chain instead of normal wheels?
Answer:
Increase the pressure , hence decreasing the force acting on the ground
Crates of masses 1 kg , 4 kg , and 6 kg are placed in a line on a frictionless table. They remain in contact as they are pushed by a 60 N force applied to the 1 kg block.
A) What is the magnitude of the force that the 4 kg block deals to the 6 kg block?
B) What is the magnitude of the force dealt by the 4 kg block on the 1 kg block?
Answer:
Approximately [tex]33\; {\rm m\cdot s^{-2}}[/tex].
Approximately [tex]55\; {\rm m\cdot s^{-2}}[/tex].
(Assume that the table is level, and that the [tex]60\; {\rm N}[/tex] force is horizontal.)
Explanation:
Consider all three blocks as one object of mass [tex]m = (1 + 4 + 6)\; {\rm kg} = 11\; {\rm kg}[/tex]. Among all the forces that are in action, the only unbalanced external force on this [tex]m = 11\; {\rm kg}[/tex] object will be the [tex]60\; {\rm N}[/tex] force. Hence, the resultant force of this combined object of mass [tex]m = 11\; {\rm kg}[/tex] will be [tex]F_{\text{net}} = 60\; {\rm N}[/tex].
Acceleration [tex]a[/tex] of this combined object will be:
[tex]\begin{aligned}a &= \frac{F_{\text{net}}}{m} \\ &= \frac{60\; {\rm N}}{11\; {\rm kg}} \\ &= \frac{60}{11}\; {\rm m\cdot s^{-2}}\end{aligned}[/tex].
Since the three crate blocks are moving together, each will have the same acceleration, [tex]a = (60/11)\; {\rm m\cdot s^{-2}}[/tex].
Resultant force on each of the crate blocks will be:
[tex]1\; {\rm kg}[/tex] crate: [tex]F_{\text{net}} = m\, a = (1\; {\rm kg})\, (60/11\; {\rm m\cdot s^{-2}}) = (60/11)\; {\rm N}[/tex].[tex]4\; {\rm kg}[/tex] crate: [tex]F_{\text{net}} = m\, a = (4\; {\rm kg})\, (60/11\; {\rm m\cdot s^{-2}}) = (240/11)\; {\rm N}[/tex].[tex]6\; {\rm kg}[/tex] crate: [tex]F_{\text{net}} = m\, a = (6\; {\rm kg})\, (60/11\; {\rm m\cdot s^{-2}}) = (360/11)\; {\rm N}[/tex].Assume that the [tex]60\; {\rm N}[/tex] external force on the [tex]1\; {\rm kg}[/tex] block points to the right.
When the crates are considered individually, external forces on the [tex]1\; {\rm kg}[/tex] crate will include:
the [tex]60\; {\rm N}[/tex] external force to the right, anda normal force the [tex]4\; {\rm kg}[/tex] block exerts on the [tex]1\; {\rm kg}[/tex] block (to the left.) Assume that this force is of magnitude [tex]x\; {\rm N}[/tex].(In the vertical direction, the weight of this block and the upward normal force from the table are balanced.)Since these two forces are in opposite directions, the resultant force on this [tex]1\; {\rm kg}[/tex] block will be [tex](60\; {\rm N} - x\; {\rm N})[/tex]. However, since the actual resultant force on this block (calculated from acceleration) is [tex](60 / 11)\; {\rm N}[/tex]:
[tex]\displaystyle 60\; {\rm N} - x\; {\rm N} = \frac{60}{11}\; {\rm N}[/tex].
Therefore, the force that the [tex]4\; {\rm kg}[/tex] block exerts on the [tex]1\; {\rm kg}[/tex] block will be
[tex]\displaystyle 60\; {\rm N} - \frac{60}{11}\; {\rm N} = \frac{600}{11}\; {\rm N} \approx 55\; {\rm N}[/tex].
When considered individually, the only unbalanced external force on the [tex]m = 6\; {\rm kg}[/tex] block is the normal force from the [tex]4\; {\rm kg}[/tex] block. Hence, this force will be equal to the resultant force on the [tex]m = 6\; {\rm kg}[/tex] block, [tex](360 / 11)\; {\rm N} \approx 33\; {\rm N}[/tex].
use newton's second law of motion to calculate the acceleration of a 7 kg mass if a force of 68.6 n acts on it?
The acceleration of the object is 9.8 m/s^2.
What is acceleration?Acceleration is rate of change of velocity with time. Due to having both direction and magnitude, it is a vector quantity. Si unit of acceleration is meter/second² (m/s²).
Given parameters:
Mass of the object: m = 7 kg.
Force acting on it: F = 68.6 N.
Hence, according to Newton's 2nd law of motion:
Force = mass × acceleration
acceleration = force/mass
= 68.6 N/7kg
= 9.8 m/s^2.
Hence, acceleration of the object is 9.8 m/s^2.
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A skier starts from rest at the top of a hill that is inclined at 10.5° with the horizontal. The hillside is 200.0 m long, and the coefficient of friction between the snow and the skis is 0.075. At the bottom of the hill, the snow is level and the coefficient of friction is unchanged. How far does the skier move along the horizontal portion of the snow before coming to rest? Show all of your work.
Answer:
2000
Explanation:
ddoes rest : add the components
On a planet whose radius is 1.2×1010m, the acceleration due to gravity at the surface of the planet is 15m/s2. What is the mass of the planet?plese help me
Refer to the photo taken.
(ii) calculate the acceleration due to gravity on the moon, which has radius 1.74 * 106 m and mass 7.35 * 1022 kg.
The acceleration due to gravity on the moon ,which has the radius 1.74×10⁶ m and mass 7.35×10²² Kg is 1.63 m/s² .
The Acceleration due to gravity is defined as the acceleration of the freely falling bodies due to force of attraction of other body .
it is given that , the radius of the moon is(R) = 1.74×10⁶ m ;
the mass of the moon is(M) = 7.35×10²² Kg ;
we know that the gravitational constant is = 6.67×10⁻¹¹ Nm²/Kg² ;
the formula is :
g = GM/R²
g = (6.67×10⁻¹¹)(7.35×10²²)/(1.74×10⁶)²
g = 4.90×10¹²/3×10¹²
g = 1.63 m/s²
Therefore , the acceleration due to gravity on the moon is 1.63 m/s² .
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how much heat, in joules, does it take to raise the temperature of 225.0 g of water from 25.0°c to 100.0°c ?
The heat required to raise the temperature of 225.0 g of water from 25.0°c to 100.0°c is 70,537.5J
Heat = specific heat capacity of the substance × mass of the substance in grams × temperature difference
Let us rewrite the equation as
q=mcΔT
Where q is the heat required, m is the mass of the substance, c is the specific heat capacity of the substance and ΔT is the temperature difference.
m=225g
ΔT=100-25=72
c=4.18J/gC
Let us substitute the values.
q=225×75×4.18
q=70537.5J
What is specific heat capacity?
Specific heat capacity, or simply specific heat, refers to the heat capacity per unit mass of a pure substance. In other words, it is defined as the amount of heat needed to increase the temperature of 1kg of a material by 1K and is expressed in terms of J/kg·K or equivalently J/kg·°C.
How do you calculate the specific heat of water?
The specific heat capacity of water is 4.18 J/g/°C. We wish to determine the value of Q - the quantity of heat. To do so, we would use the equation Q = m•C•ΔT. The m and the C are known; the ΔT can be determined from the initial and final temperature.
Thus, the heat required is 70537.5J
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At which reference point should your vehicle appear to intersect with the curb when parallel parking?
The reference point at which vehicle appear to intersect the curb is 2.22km.
To ensure that every parallel park is successfully completed, it is crucial to employ a structured technique and to practice it until a level of proficiency is attained. However, contrary to popular belief, it need not be completed in a single seamless maneuver.
During the maneuver, it is acceptable to advance and make adjustments as long as you do so safely and keep an eye on your surroundings at all times.
Utilizing reference points, a structured technique is applied. Whatever method is used to parallel park, using reference points will help new drivers complete this maneuver.
You should slightly pass the car you plan to park behind. The front of this car is aligned with the center of your passenger-side front window in reference point.
[tex]Reference=\frac{\pi }{\sqrt{2} }[/tex]
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a conducting wire is quadrupled in length and tripled in diameter. part a part complete does its resistance increase, decrease, or stay the same? does its resistance increase, decrease, or stay the same? increase decrease stay the same previous answers completed part b by what factor does its resistance change?
The resistance decreases when the conducting wire is quadrupled in length and tripled in diameter.
The electrical resistance of a circuit component or tool is defined as the ratio of the voltage applied to the electric present day which flows thru it: If the resistance is consistent over a widespread variety of voltage, then Ohm's regulation, I = V/R, may be used to predict the behavior of the fabric.
An less difficult way to explain resistance is to don't forget an example of someone in a crowded marketplace struggling to go from one keep to every other. This situation is in reality similar to an electron looking to make its way thru a wire.
If the temperature and different bodily variables stay constant, the resistance of a conductor is exactly proportional to its period.
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the length of the path traveled by light in a vacuum in 1/299,792,458th of a second
A vacuum is an area devoid of matter, also referred to as "free-space." Practically speaking, only partial vacuums are feasible.
What do you meant by vacuums?North Americans typically refer to this electrical device as a vacuum cleaner or just a vacuum, whereas Britons typically refer to it as a hoover.
Both terms can be inflected to become verbs such as vacuumed, vacuuming, hoovered, and hoovering. A vacuum is an area devoid of matter, also referred to as "free-space."
Practically speaking, only partial vacuums are feasible. A great bagless upright vacuum, a respectable cordless vacuum, and a simple (but effective!) robot vacuum are just a few of the several vacuums we suggest; they typically cost around $150. Since the middle of the 19th century, a British person has been referred to as a "Limey" (from lime or lemon) in slang.
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thermonuclear runaway on the surface of a white dwarf due to accretion of matter from a companion star is called
A nuclear runaway on the edge of a White Dwarf (WD), which is absorbing matter from a partner star in a tight binary system, causes a classical nova eruption.
Has a thermonuclear bomb been used?The nuclear bomb, which the United States dropped in Japan in the Second World War and killed thousands of individuals, is already very powerful, but experts claim that a hydrogen bomb, which has never been used battle by any country, has the potential to destroy city and kill considerably more people.
What distinguishes nuclear energy from thermonuclear energy?Since a thermonuclear weapon makes use of the energy generated when two light protons and neutrons fuse together to make a heavier nucleus, it fundamentally differs from an atomic bomb. In contrast, the energy produced when a heavy alpha particle divides, or fissions, becoming two lighter nuclei is used in an atomic bomb.
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A 275-kg load is lifted 23.0 m vertically with an acceleration a=0.200 g by a single cable. Determine (a) the tension in the cable, (b) the net work done on the load, (c) the work done by the cable on the load, (d) the work done by gravity on the load, and (e) the final speed of the load assuming it started from rest.
Let's calculate T = 275 (-23.0 - 0.200) and T = -6380 N using the formulas T - W = m a, T = W + ma, and T = m (g + a). B) Network is weight work less stress work. W = F d, T-W d, m a d, (275- 0.200) 23, W = 270.4 J
The tension the net work done on the load?The tension formula is expressed as. T=mg+ma. where T is tension and g is the gravitational acceleration (9.8 m/s2). The load's mass is M = 275 kg, and its acceleration is a = 0.12 g. Let T represent the cable's tension. The load accelerates upwardly as well as being raised vertically. Because of this, according to Newton's laws, T = M ( g + a ) = 275 1.12 9.8 = 3018.4 N
Calculate the work done by gravity on the load, the work done by the cable on the load, and other factors.According to sign convention, the task that the cable has done W = F. d, W = F d cos 180, W = -285 22.0, W = 2.79 103 J The work done by the weight is up and the weight points down, therefore the angle is 180o. W = T d cos 0 W = 2838.6 22.0 W = 6.22 104 J d)
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The force of impact at 20 mph is what times that at 10 mph speeds
The force of impact at 20 mph is two times that at 10 mph speeds.
What is effect of force?An object can change its size or shape, begin moving, stop moving, accelerate, or decelerate as a result of a force acting on it. When two things contact, they exert pressures on one another that are identical in size but directed in the opposite direction.
The combined effect of all the forces acting on an object is known as the "resultant force," and it is the same as if only one force were to be operating on the object in that direction. To alter an object's velocity, the resulting force is necessary.
The force required for increasing speed 20 mph of an object of mass m at an interval of time t be = m×20/t.
The force required for increasing speed 10mph of an object of mass m at an interval of time t be = m×10/t.
Hence, the force of impact at 20 mph is two times that at 10 mph speeds.
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A woman is driving at a velocity of 33.86 m/s at an angle of 23° What is the Y component of her velocity?
Answer:
The values are provided in question Velocity V = 12.72…
Explanation:
The velocity will equal v=12.72
What are some of the differences between a gravitational force and a magnetic force?
A gravitational force is always attractive in nature and a magnetic force is attractive in nature between two opposite poles and repulsive in nature between two same pole.
What are the differences between a gravity and a magnetism?Gravity and magnetism are not the same thing. These two ideas or expressions are entirely dissimilar from one another. Despite the fact that both are regarded as forces, they are two distinct forces with various traits and features.
First of all, gravity works between two objects regardless of their composition because it is a separate force. There will be gravitational forces between the items as long as they have mass. Any two things will be drawn toward one another by gravity or another gravitational force if they have mass.
Magnetism, on the other hand, mostly depends on the unique characteristics of the object. There are two directions for the magnetic force. It has the power to draw things together as well as away from one another. The orientation of the electrons inside the items also affects how magnetism behaves. With gravity and gravitational force, this is not the case.
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a 6 kg box is pushed with a force of 41 n at the moment it starts to accelerate from rest across the carpet. calculate the coefficient of static friction between the box and the carpet.
The coefficient of static friction between the carpet and the box is found to be 0.68.
The mass of the box is 6 kg and a force f of 41 newton is applied at the moment it starts to accelerate from rest across the carpet. If the net force is f and the force of friction between the carpet and the box is Fr.
We can write,
f = Fr
We know, force of friction is given by,
Fr = uN
N is the normal that is equal to weight of body,
u is the coefficient of static friction between the carpet and the box.
Putting values,
f = uN
41 = u(6×10)
u = 41/60
u = 0.68
So, the coefficient of static friction is found to be 0.68.
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this photo shows apparatus used in an experiment in which materials thought to have been present on the early earth were sparked with energy. what have we learned from this type of experiment?
These experiments have shown that the building blocks of life form easily and naturally under conditions that existed on early Earth.
Who proposed the idea of the nebular hypothesis?
The generally accepted model for the formation of the solar system is called the nebular hypothesis. It takes all the different kinds of information and merges them into one hypothesis that seems to match all the observations. The theory was proposed by French mathematician Pierre Simon Laplace more than 200 years ago.
What is astrobiology and what type of research does it involve?
Astrobiology is the study of life within the universe. Astrobiologists study how life forms and develops, and where life can be found. Astrobiology involves the search for life outside Earth, the study of planets and moons within our Solar System, and the search for habitable planets around other stars.
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When you drop a golf ball, why does it not bounce as high as the initial drop point
height? (hint: 2 reasons should be given)
There are two reasons why a golf ball does not bounce as high as the initial drop point height. First, when the golf ball hits the ground, it experiences a force of impact that causes it to deform slightly. This deformation dissipates some of the energy from the initial drop, reducing the height of the bounce.
Second, when the golf ball bounces, it experiences friction with the ground, which also dissipates some of the energy from the initial drop. This further reduces the height of the bounce. Together, these two factors explain why a golf ball does not bounce as high as its initial drop point height.
A skydiver dives from an airplane. air resistance is measured each second following the skydiver’s jump.
Time after jump | Weight | Air Resistance
1 sec | 500 N | 200 N
2 sec | 500 N | 300 N
3 sec | 500 N | 400 N
4 sec | 500 N | 500 N
Which statement best identifies her speed at each second?
a. The skydriver has the slowest speed at 2 seconds
b. The skydriver has the fastest speed at 4 seconds
c. The skydriver has the slowest speed at 1 second
d. The skydriver has the fastest speed at # seconds
The statement that best identifies her speed at each second is as follows: the sky driver has the fastest speed at 4 seconds (option B).
What is air resistance?Air resistance is the action of friction that slows something moving through air.
Air resistance is dependent on velocity, area, and shape of the object going through the air. Altitude, temperature, and humidity change air density and, consequently, its resistance.
The higher the speed and the bigger the area, the higher the resistance. As speed increases so too does the frequency of the collision of air molecules with the object. This results in an increase in air resistance.
Therefore, as the sky driver with a weight of 500N increases in air resistance, the speed also increases.
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What is the magnitude of force A,B
The magnitude of force A is -50N and for the B is 200N
What is magnitude?Magnitude is a measure of the size or intensity of something. It is usually the size of a physical quantity, such as a force, or an earthquake. It can also be used to refer to the degree of importance or intensity of an emotion, feeling or event. Magnitude is often expressed as a numerical value on a logarithmic scale. This scale is used to compare different physical quantities or events, such as the intensity of an earthquake or the power of a solar flare. Magnitude can also be used to describe the size, brightness or importance of an object, such as a star or a planet.
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Three examples of physical changes are……?
Answer:Cutting, bending, dissolving, freezing, boiling, and melting
Explanation:
Im not sure but if your teacher asked you why are you interested in dawn (sunrise) what would you say?
Answer:
Because it's beautiful and very interesting. It shows the start of a new day. Why not be interested in it?
Explanation:
Why might a wine glass survive a fall onto a carpeted floor but not onto a concrete floor?.
An 893-kg (1974 lb) dragster, starting from rest, attains a speed of 25.8 m/s (57.8 mph) in 0.59 s.
(a) Find the average acceleration of the dragster during this time interval.
(b) What is the magnitude of the average net force on the dragster during this time?
(c) Assume that the driver has a mass of 68 kg. What horizontal force does the seat exert on the driver?
Hello,
I hope you and your family are doing well!
(a) To find the average acceleration of the dragster, we can use the equation:
average acceleration = (final velocity - initial velocity)/time interval
Plugging in the values from the problem, we get:
average acceleration = (25.8 m/s - 0 m/s)/0.59 s = 43.7 m/s^2
(b) The net force on an object is equal to its mass times its acceleration, so the net force on the dragster during this time interval is:
net force = 893 kg * 43.7 m/s^2 = 38,971 N
(c) To find the horizontal force the seat exerts on the driver, we can use the equation:
force = mass * acceleration
The acceleration of the driver is the same as the acceleration of the dragster, which we found to be 43.7 m/s^2. Plugging this value into the equation, we get:
force = 68 kg * 43.7 m/s^2 = 2970 N
So the seat exerts a force of 2970 N on the driver.
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Sport question:
Move used in many sports where the ball carrier keeps one foot planted on the ground but is allowed to rotate on that foot
Answer:
That move is called a pivot foot.
Explanation:
Marissa does 11.1 J of work to lower her window shade in her bedroom in 7 seconds. How powerful is Marissa?
Marissa does 11.1J of work in 7 seconds.
We know that, the expression of power,
P= W/t
Here, W is the work done and t is the time.
Substitute the required values to determine the value of the power of Marissa.
work done= 11.1 J
time taken = 7 seconds
Power = 11.1 / 7
Power = 1.58 W
Hence, Marissa is 1.58 W is powerful
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