A 2-column table with 5 rows. Column 1 is labeled Number of chores, x with entries 2, 4, 6, 8, 10. Column 2 is labeled Days, y with entries 1, 2, 3, 4, 5. The table shows the number of days required to perform a given number of chores. The number of days varies directly with the number of chores. What is the constant of variation? 2 3 One-half One-third\

Let [tex]a,b,c[/tex] be the randomly selected lengths. Without loss of generality, suppose [tex]a

[tex]P(A + B \ge C) = P(A + B - C \ge 0)[/tex]

where [tex]A,B,C[/tex] are independent random variables with the same uniform distribution on [0, 1].

By their mutual independence, we have

[tex]P(A=a,B=b,C=c) = P(A=a) \times P(B=b) \times P(C=c)[/tex]

so that the joint density function is

[tex]P(A=a,B=b,C=c) = \begin{cases}1 & \text{if }(a,b,c)\in[0,1]^3 \\ 0 & \text{otherwise}\end{cases}[/tex]

where [tex][0,1]^3=[0,1]\times[0,1]\times[0,1][/tex] is the cube with vertices at (0, 0, 0) and (1, 1, 1).

Consider the plane

[tex]a + b - c = 0[/tex]

with [tex](a,b,c)\in\Bbb R^3[/tex]. This plane passes through (0, 0, 0), (1, 0, 1), and (0, 1, 1), and thus splits up the cube into one tetrahedral region above the plane and the rest of the cube under it. (see attached plot)

The point (0, 0, 1) (the vertex of the cube above the plane) does not belong the region [tex]a+b-c\ge0[/tex], since [tex]0+0-1=-1<0[/tex]. So the probability we want is the volume of the bottom "half" of the cube. We could integrate the joint density over this set, but integrating over the complement is simpler since it's a tetrahedron.

Then we have

[tex]\displaystyle P(A+B-C\ge0) = 1 - P(A+B-C < 0) \\\\ ~~~~~~~~ = 1 - \int_0^1\int_0^{1-a}\int_{a+b}^1 P(A=a,B=b,C=c) \, dc\,db\,da \\\\ ~~~~~~~~ = 1 - \int_0^1 \int_0^{1-a} (1 - a - b) \, db \, da \\\\ ~~~~~~~~ = 1 - \int_0^1 \frac{(1-a)^2}2\,da \\\\ ~~~~~~~~ = 1 - \frac16 = \boxed{\frac56}[/tex]

Answer:

{(-3, -2), (-4, 3), (-1, 0), (3, -7)}

Step-by-step explanation:

When you find the inverse of a function you swap the x and the y. So let's look at a couple examples and see what happens to the x and y values

Radical:

[tex]y=\sqrt{x}[/tex]

So let's just look at perfect squares so it's a bit easier to understand

(0, 0)

(4, 2)

(9, 3)

Now let's find the inverse:

[tex]x=\sqrt{y}[/tex]

Now to make this concept a bit easier to understand let's leave it in this form. Well the first notable thing, is that any operations applied to y will now apple to x, and any operations applied to x will apply to y (in this case the square root).

So if I input 9 as the y, the x will be 3

If I input 4 as y, the x will become 2

Some points are

(0, 0)

(2, 4)

(9, 3)

You'll notice the x and y values are swapped, well it's simply because you swap the x and y's place. this is also why the domain and range are swapped

So given the points {(-2, -3),  (3, -4), (0, -1), (-7, 3)} you simply swap the x and y to get:            {(-3, -2), (-4, 3), (-1, 0), (3, -7)}

Answer:

D

Step-by-step explanation:

[tex]\frac{1820728291}{14285714286}[/tex]

Answer: 42.308%

Step-by-step explanation:

1. R= {(2, 2), (3, 5), (4, 10), (4, 17)}

2. Domain = {1, 2, 3, 4}

3.  Range = {2, 3, 4, 5, 10, 17}

The domain of a function is the set of values that we are allowed to plug into our function.

The range of a function is the set of values that the function assumes.

Given:

R = { ( 1 + x , 1 + x^2 ) ∶ x≤ 4, ∈ }

1) R= {(2, 2), (3, 5), (4, 10), (4, 17)}

2) Domain = {1, 2, 3, 4}

3) Range = {2, 3, 4, 5, 10, 17}

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Pn(Z>zp)=1−p%

Given a variable X following a normal distribution with mean μ and standard deviation σ, the area below the curve that corresponds to all values that are less than a that is, X<a

is the probability P(X<a). This probability is usually calculated by converting the variable X to a standard normal variable Z (forming z scores) defined by:

[tex]z=\frac{x-\mu}{\sigma}[/tex]

The variable Z follows the standard normal distribution with a mean of 0 and a standard deviation of 1.

The standard normal probabilities are typically found by using the standard normal tables or other computational means such as calculators or software.

Pn(Z>zp)=1−p%

Here Pn is the probability for the standard normal variable.

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The tangent or tanθ in a right-angle triangle is the ratio of its perpendicular to its base. The height of the mountain is 3110.5767 feet.

The tangent or tanθ in a right-angle triangle is the ratio of its perpendicular to its base. it is given as,

[tex]\rm Tangent(\theta) = \dfrac{Perpendicular}{Base}[/tex]

where,

θ is the angle,

Perpendicular is the side of the triangle opposite to the angle θ,

The base is the adjacent smaller side of the angle θ.

The height of the mountain from the first point,

[tex]\tan(29^o) = \dfrac{H}{x+1000}\\\\H = (1000+x) \times \tan(29^o)[/tex]

The height of the mountain from the second point,

[tex]\tan(34^o) = \dfrac{H}{x}\\\\H = x \times \tan(34^o)[/tex]

Equating the height,

H = H

(1000+x) × tan(29°) = x tan( 34°)

x = 4611.5767 feet

Now, the height of the mountain is,

H = x tan(34°)

H = 3110.54776 feet

Hence, the height of the mountain is 3110.5767 feet.

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[tex]\angle PYZ=116^{\circ}[/tex] (angles on a line add to 180 degrees)

[tex]\angle ZYQ=58^{\circ}[/tex] (angle bisector)

[tex]\angle XYQ=122^{\circ}[/tex] (angle addition postulate)

[tex]\angle QYP=58^{\circ}[/tex] (angle bisector)

Reflex [tex]\angle QYP=302^{\circ}[/tex] (an angle and its reflex angle add to 360 degrees)

Answer:

  z = 110°

Step-by-step explanation:

Angles z and the one marked 70° form an linear pair, hence are supplementary.

  z = 180° -70° = 110°

The angle made by two chords is half the sum of the arcs intercepted by those chords. Here, that means ...

  70° = 1/2(60° +x)   ⇒   x = 140° -60° = 80°

The arc w completes the circle of 360°, so we have ...

  w +x +79° +60° = 360°   ⇒   w = 360° -219° = 141°

Finally, z is the average of w and 79°:

  z = (w +79°)/2 = (141° +79°)/2 = 110° . . . as above

Answer:

Step-by-step explanation:

[tex]1+tan^2\theta=sec^2\theta\\tan^2\theta=sec^2\theta -1 \\tan^2\theta=(sec\theta-1)(sec\theta+1)\\\implies \frac{1}{sec\theta-1} =\frac{sec\theta+1}{tan^2\theta} \\\\and \quad \frac{1}{sec\theta+1} =\frac{sec\theta-1}{tan^2\theta} \\\\ \frac{1}{sec\theta-1} + \frac{1}{sec\theta+1} = \frac{sec\theta+1}{tan^2\theta} + \frac{sec\theta-1}{tan^2\theta}\\\\=\dfrac{2sec\theta}{tan^2\theta}\\\\=\dfrac{2cos^2\theta}{cos\theta.sin^2\theta}\\\\\\=2cos\theta.cosec^2\theta[/tex]

Isolate x:

2x + 7y = -1

2x = -1 -7y

x = -1/2 - 7/2y

Substitute the equation of x:

4x - 3y = -19

4(-1/2 - 7/2y) - 3y = -19

-2 - 14 - 3y = -19

-3y = -19 + 14 + 2

-3y = -3

 y = 1

Substitute to find x:

2x + 7y = -1

2x + 7(1) = -1

2x = -1 - 7

2x = -8

x = -4

(-4, 1)

Multiply one or both equations through an integer in order that one time period has the same and contrary coefficients within the equations. Add the equations to provide a single equation with one variable. clear up for the variable. alternative the variable back into one of the equations and resolve for the other variable.

Conclusion: A system of equations is fixed of 1 or greater equations related to some of the variables. The solutions to systems of equations are the variable mappings such that every one component equations are satisfied—in other phrases, the locations at which all of these equations intersect.

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The missing term in the expression ___( 2a-1)  is 6b.

An expression is an algebraic statement that consists of variables, constants, and mathematical operators.

The expression 12ab-6b is equivalent to

6b( 2a-1)

(By taking the common factors out of the given expression.)

Therefore, the missing term in the expression is 6b.

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Answer:

[tex]\sf Total \ amount \ of \ walnuts \ and \ pecans \ needed = \dfrac{7}{12}[/tex]

Step-by-step explanation:

    [tex]\sf Amount \ of \ walnut \ needed = \dfrac{1}{4}[/tex]

    [tex]\sf Amount \ of \ pecans \ needed =\dfrac{2}{6} =\dfrac{1}{3}[/tex]

To find the total amount of walnut and pecans, we have to add the fractions.

LCM of 4 & 3 = 12

Equivalent fractions:

      [tex]\sf \dfrac{1}{4}=\dfrac{1*3}{4*3}=\dfrac{3}{12}\\\\\dfrac{1}{3}=\dfrac{1*4}{3*4}=\dfrac{4}{12}[/tex]

Now, add

   [tex]\sf \dfrac{3}{12}+\dfrac{4}{12}=\dfrac{3+4}{12}[/tex]

                  [tex]\sf = \dfrac{7}{12}[/tex]

The missing segment in the image below is 78 units.

An equation is an expression that shows the relationship between two or more variables and numbers.

The ratio or two corresponding sides of similar shapes are in the same proportion.

Let x represent the missing side, hence:

(x + 26)/26 = 48/12

x =78

The missing segment in the image below is 78 units.

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Answer:

X=3

Step-by-step explanation:

First you can distribute the 4 to 2x-1 making is 8x-4

8x-4+2x+2=28

Now add like terms

8x+2x-4+2=28, 10x-2=28

Add 2 to both sides

10x=30

Divide both sides by 10

x=3

Answer:

33x - 13 = 13x + 7

Step-by-step explanation:

If "G" is the midpoint of line FH, then both segments (lines FG and GH) must be the same length. Therefore, to find "x", you can set both segments equal to each other. After doing this, you can simplify and isolate to find "x".

FG = 33x - 13

GH = 13x + 7

FG = GH

33x - 13 = 13x + 7

[tex]\huge\text{Hey there!}[/tex]

[tex]\huge\textbf{Assuming that your equation should}\\\huge\textbf{look like that: }[/tex]

[tex]\mathbf{33x - 13 = 13x + 7}[/tex]

[tex]\huge\textbf{If so:}[/tex]

[tex]\mathbf{33x - 13 = 13x + 7}[/tex]

[tex]\huge\textbf{SUBTRACT 13x to BOTH SIDES}[/tex]

[tex]\mathbf{33x - 13 - 13x = 13x + 7 - 13x}[/tex]

[tex]\huge\textbf{SIMPLIFY IT!}[/tex]

[tex]\mathbf{20x - 13 = 7}[/tex]

[tex]\huge\textbf{ADD 13 to BOTH SIDES}[/tex]

[tex]\mathbf{20x - 13 + 12 = 7 + 13}[/tex]

[tex]\huge\textbf{SIMPLIFY IT!}[/tex]

[tex]\mathbf{20x = 20}[/tex]

[tex]\huge\textbf{DIVIDE 20 to BOTH SIDES}[/tex]

[tex]\mathbf{\dfrac{20x}{20} = \dfrac{20}{20}}[/tex]

[tex]\huge\textbf{SIMPLIFY IT!}[/tex]

[tex]\mathbf{x = \dfrac{20}{{20}}}[/tex]

[tex]\mathbf{x = 1}[/tex]

[tex]\huge\text{Answer: \boxed{\mathsf{33x - 13 = 13x + 7}}}\huge\checkmark[/tex]

[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

The statement about the system of of equations that are true are as follows:

The system of equation can be solved as follows;

2x - 7y = - 13

2x + 11y = 1

18y = 14

y = 14 / 18

y = 7 / 9

2x  = 1 - 11(7 / 9)

2x = 1 - 77 / 9

2x = 9 - 77 / 9

2x = -68 / 9

cross multiply

18x = -68

x = -68 / 18

x = -34 / 9

Hence, the statement about the system of of equations that are true are as follows:

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Answer:

Y intercept: (0,2) Slope: 1/3

Step-by-step explanation:

X is horizontal. Y is vertical the slope touches at (0,2).

The slope goes up by one and right by three cause it connects to the line

for the second one all you would have to do is increase the slope first number like 4/3

Answer:

t ≥ 192

Step-by-step explanation:

To isolate t in the inequality 6.50t ≥1248, divide by 6.50 on both sides. There you are left with t ≥ 192 which means the cheerleading team must sell 192 t-shirts or more to make their profit goal. Graph this using a closed circle at 192 moving upwards. (You didn't include a picture of the given graphs in your problem)

Answer:

30°

Step-by-step explanation:

x + 90 = 2 × 60 ( angle at center = 2 × angle at circumference.)

x +90 = 120

x = 120-90

x = 30°

Using the rule of dilation, 5/4, the length of C'A' is: A. 10 units.

Dilation is a form of transformation that creates a new image that is similar to the original one.

The images formed are similar images shown in the diagram given, therefore, using the rule of dilation, Dy = 5/4, we would have:

CA × 5/4 = C'A'

Plug in the given value

8 × 5/4 = C'A'

10 = C'A'

C'A' = 10 units

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Answer:

a. What is the measure of ∠CAT?   Answer:  70°

b. What is the measure of ∠BAR?  Answer:  50°

c. What is the measure of ∠RAT?  Answer:   110°

d. What is the measure of ∠CAB? Answer:   130°

e. What is the measure of ∠BAT? Answer:    60°

Step-by-step explanation:

I just looked at the degrees of the protractor.

Hope this helps!

If not, I am sorry.

Answer:

your slow

Step-by-step explanation:

Step-by-step explanation:

good study habits will help! study before you plan on sleeping and designate times to do your work

The expressions that gives the number of online math classes is as follows:

y = x - 15

The number of math classes offered online in the summer is 15 less than the number of math classes offered face-to face in the summer.

Let

the number  of math classes offered face-to face = x

the  number of math classes offered online  = y

Therefore, the expression that gives the number of online math classes is as follows:

y = x - 15

x = y + 15

Hence,

y = x - 15

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ye answer's here  

Yes, the bathroom have enough water and shampoo for 35 long haired and 40 short haired members.

Inequality can be define as the relation of equation contains the symbol of ( ≤, ≥, <, >) instead of equal sign in an equation.

For 35 long haired and 40 short haired member.
Put this values in the given equation.

For water 70L+60S < 5600
  70 x 35 + 60 x 40
2450+2400
4850 <5600
inequality holds

For shampoo 0.02L+0.01S ≤ 1.50
0.02 x 35 + 0.01 x 40
0.7 + 0.4
1.1 < 1.50
inequality holds

Thus, the bathroom have enough water and shampoo for 35 long haired and 40 short haired members.

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Answer:

Step-by-step explanation:

Answer:

was there a list to choose from

Step-by-step explanation:

19, 26, 33, 40, 47

Answer:

159.3

Step-by-step explanation:

456 - 121.3 = 334.7

333.7 - 175.4 = 159.3

Hope this helped

Answer:

152

Step-by-step explanation:

You actually don't need to find the thirds number. Just by taking 456 and dividing it by three, you will get your answer and the average of the three numbers.

If the sample size is n=40 ,mean of 20 and a standard deviation then the sampling distribution is normally distributed.

Given sample size is 40, sample mean is 20, sample standard deviation is 5.

We have to find whether the distribution is normally distributed or not.

Normal distribution is an arrangement of a data set in which most values cluster in the middle of the range and the rest taper off simultaneously towards either extreme. It may be one tailed or two tailed also.

Yes the given distribution whose sample size is 40, sample mean of 20 and sample standard deviation of 5 is normally distributed as the sample size is greater than 30.

Signs of normal distribution are:

Hence the sampling distribution is normally distributed.

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