The frequency of the oscillation is determined to be 0.123 Hz.
The number of waves passing through a fixed point in unit time is said to be frequency.
Given that, Mass of the scrap steel = 100 kg
Spring constant k = 60 kN/m
The formula for time period is as follows,
T = 2π √(m/k)
And the relation between time period and frequency is, T = 1/f
f = 1 / [2π √(m/k)] = 1/ [ 2π √(100/60) = 1/ [ 2π * 1.29] = 1/8.105 = 0.123 Hz
Thus, the frequency of oscillation is 0.123 Hz.
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what is a hockey stick graph? name three metrics that would fit this description
A hockey stick graph is a graphical representation of data that has a steep increase or decrease at a certain point, resembling the shape of a hockey stick.
This type of graph is often used to show a sudden change in a metric over time. Three metrics that might fit this description are:
Population growth: The population of a city or country might increase slowly over time and then suddenly accelerate, forming a hockey stick shape on a graph.Sales revenue: A company's sales revenue might increase slowly at first and then suddenly spike up when a new product is introduced or a marketing campaign is launched.Internet usage: The use of the internet in a country or region might increase slowly over time and then suddenly accelerate as more people gain access to the internet.Other metrics that might fit this description include the adoption of a new technology, the spread of a disease, or the growth of a social media platform.
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choose one of the theorems you have encountered that is easier to prove with a coordinate proof than with another type of proof. explain. then write a coordinate proof.
The "generalised" points on the Cartesian Plane are used in the coordinate proof to support a geometric theorem. In order to use the midpoint or distance formulas, the procedure typically entails assigning variables to the coordinates of one or more points.
Example of coordinate proof
Show or deny the existence of a parallelogram in the quadrilateral formed by the points (2, 4, 1, 2, 5, 1, and 4). It's not required to plot the points, although it does assist to visualize. You can use it to determine whether or not it resembles a parallelogram.
There is no doubt that this is a parallelogram. Remember that a parallelogram is a quadrilateral with two sets of parallel sides to demonstrate that the shape is one. Therefore, confirming that the opposing sides are parallel is one technique to demonstrate that it is a parallelogram. Remember from algebra that if two lines have the same slope, they are parallel. On the image, identify the slope of each side.
Equal slopes can be found on the opposing sides. The opposing sides are thus parallel. The quadrilateral is a parallelogram as a result.
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a 1600kg car is traveling over a hill that has a radius of curvature of 25m. the car is slowing down as it goes over the hill. it slows down at a constant rate from a speed of 25ms to a speed of 10ms over a distance of 50m ending at the top of the hill. the net acceleration of the car at the top of the hill is most nearly
a. 5.3 m/s/s.
b. 9.3 m/s/s.
c. 4.0 m/s/s.
d. 26 m/s/s.
e. 6.6 m/s/s.
The net acceleration of the car at the top of the hill is most nearly is option A. . 5.3 m/s²
Acceleration is the rate of trade of the velocity of an object with appreciation to time. Accelerations are vector portions. The orientation of an object's acceleration is given by using the orientation of the internet pressure performing on that item.
Calculation:-
V² = U² - 2aS
a = U²- V² / 2S
= 25² - 10² / 2 × 50
= 625 -100/100
= 525/100
= 5.25 m/s² ≈ 5.3 m/s²
Acceleration is the price at which speed modifications with time, in terms of every velocity and course. A thing or an item shifting in a instantly line is increased if it quickens or slows down. motion on a circle is extended despite the truth that the price is constant due to the fact the direction is usually changing.
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A 1000 kg weather rocket is launched straight up. The rocket motor provides a constant acceleration for 16 s, then the motor stops. The rocket altitude 20 s after launch is 4600 m. You can ignore any effects of air resistance.
a. What was the rocket's acceleration during the first 16 s?
b. What is the rocket's speed as it passes through a cloud 5100 m above the ground?
Define the high quality route because the route pointing upward. Denote the rocket's acceleration throughout the primary 16s as a. In the primary 16s, we have the rocket's acceleration during the first 16 s is 1254.4 a.
1) s = 0.5 (a-g) 16^2 = 128(a-g) = 128 (a-9.8) = 128 a - 1254.4.When t = 16s, the rate is v1 = 16(a-g) considering the fact that a-g = (v1-0)/16. So withinside the subsequent 4s, we have2) 4200 - s = 0.5 (-g) 4^2 + 16(a-g) (4) = -8g + 64(a-g) = 64a -72g = 64a - 72(9.8) = 64a - 705.6.To resolve for the acceleration a, upload up 1) and 2),s + (4200-s) = 128a - 1254.4 + 64a - 705.6.Simplify,4200 = 192a - 1960.192a = 4200 + 1960 = 6160.a = 6160/192 = 32.08333 (m/s^2).The solution is 32.08333 m/s^2.Read more about Weight ;
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a car starts from rest at a stop sign. it accelerates at 4.3 m/s2 for 6.4 s , coasts for 2.2 s , and then slows down at a rate of 3.5 m/s2 for the next stop sign.
The sum stop signs of the car that accelerates at 4.3 m/s² for 6.4 s, coasts for 2.2 s, and then slows down at a rate of 3.5 m/s² = 216.118 m.
Velocity and accelerationVelocity is a vector quantity that shows how fast an object moves from one place to another. A vector quantity is a term that is intended for a quantity that has both value and direction, meaning that the determination of the value of that quantity is based on direction.
The equation is:
V = s/t
Acceleration is the rate of increase in speed in a certain time expressed in units of meters per second squared (m/s²).
The function of speed is to determine how fast an object goes at a certain distance and is measured based on a vector quantity. Conversely, acceleration serves to change the speed of an object that is moving.
The equation is:
α = v/t
The question is not complete, it should be:
How far apart are the stop signs?
We have,
Acceleration = 4.3 m/s²
t = 6.4 s
First, determine the distance (1)
It's start from rest, so v₀ = 0
s₁ = (v₀t)₁ + ½ (at)₁²
= 0 + ½ (4.3) (6.4)²
= 88.064 m
Next, the distance (2)
a₂ = 0 m/s²
s₂ = (v₀t)₂ + ½ (at)₂²
= 0 + 20.812
= 20.812 m
The last, the distance (3)
s₃ = (v₀t)₃ + ½ (at)₃²
= (27.52) (8.6) + ½ (-3.5) (8.6)²
= 107.242 m
So, the sum stop sign = 88.064 m + 20.812 m + 107.242 m
= 216.118 m
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g two point charges q1 = 2.30 nc and q2 = -6.10 nc are 0.100 m apart. point a is midway between them; point b is 0.0800 m from q1 and 0.0600 m from q2 (figure 1). take the electric potential to be zero at infinity.for related problemsolving tips and strategies, you may want to view a video tutor solution of potential and potential energy.
The electric field is -641.25 volt, potential energy is -1.76x 10⁻³ J.
What is electric field ?
The term "electric field" or "electrostatic field" refers to the area surrounding an electric charge where stress or an electric force occur. A significant amount of tension might be produced in the area if the charge is of a big magnitude. The letter E is used to denote the electric field. Newtons per coulomb, or volts per metre, is the SI unit for the electric field.
What is potential energy ?
Potential energy is energy that is preserved or stored in a material or an item. The item or substance's position, organization, or condition determines the amount of stored energy. Consider it as energy with the "potential" to accomplish work.
Va = kq1/r1 + Kq2/r2
Va = 9 x 10/0.05 (2.3 x 10⁻⁹ – 6x 10⁹)
Va = -666 volt
Vb = 9x10⁹ (2.3x10⁻⁹/.08 – 6x10⁻⁹/.06)
Vb = -641.25 volt
Work done by electric field from b to a
W e = q(Vb-Va)
W e = 3x10⁻⁹ (-641.25+666)
W e = 74.25x10⁻⁹ J
W e = qEd = 30x 10⁻⁹x 3.2x10⁴x.63
W e = 6.05x10⁻⁴ J
W e = -qEd cos 45
W e = -30x10⁻⁹x3.2x10⁴x2.6 cos 45
W e = -1.76x 10⁻³ J
Therefore, electric field is -641.25 volt, potential energy is -1.76x 10⁻³ J.
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Which of the following statements are true for an image formed by a plane mirror?The image always appears to be located the same distance behind the mirror as the object is located in front of the mirror.A. The image formed by a plane mirror is always a real image.B. The image is always larger than the object.C. The image formed by a plane mirror is always an upright image.D. The image formed by a plane mirror is always an inverted image.E. The image formed by a plane mirror is always a virtual image.
A mirror with a plane reflecting surface is known as a plane mirror. A plane mirror creates a virtual image of the same size as the thing that is behind the mirror.
The distance between the object and the mirror is the same for both the image and the object. Thus, the appropriate choice is (b). A planar mirror always creates a true-to-life image. The image always exceeds the thing in size. An upright picture is always produced by a flat mirror. An inverted picture is always produced by a plane mirror. Every time an object is in front of the mirror, the image appears to be behind it at the same distance.
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When the current in a long, straight air-filled solenoid is changing at the rate of 3000 A/S, the voltage across the solenoid is 0.600 V. The solenoid has 1200 turns and uniform cross-sectional area 35.0 mm? Assume that the magnetic field is uniform inside the solenoid and zero outside, so the inductance formula L MAN/ 2/1 for a solenoid with N turns, uniform cross-sectional area A, and length 1, applies Part A What is the magnitude B of the magnetic field in the interior of the solenoid when the current in the solenoid is 3.00 A? Express your answer with the approppriate units. μΑ ? B= Value Units Submit Request Answer
The magnitude of B in the interior of the solenoid is 5 * 10⁻⁷ A/m.
Given that,
Rate of change of current = 3000 A/s
EMF induced ε = 0.6 V
Number of turns N = 1200 turns
Cross-sectional area A = 35 mm² = 35 * 10⁻⁶ m²
Current i = 3 A
We know the relation, ε = L* dI/dt
Making L as subject, L = ε / ( dI/dt )
Substituting the values, we have
L = 0.6 / 3000 = 0.0002 H
We know the relation between N, i, B and L as
N* B = L *i
Making B as subject, we have
B = L *i/N = (0.0002 * 3)/1200 = 0.0000005 A/m = 5 * 10⁻⁷ A/m
Thus, magnetic field in the interior of the solenoid is 5 * 10⁻⁷ A/m.
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a 450 g air-track glider attached to a spring with spring constant 8.00 n/m is sitting at rest on a frictionless air track. a 450 g glider is pushed toward it from the far end of the track at a speed of 150 cm/s . it collides with and sticks to the 450 g glider. What are the amplitude and period of the subsequent oscillations?
The amplitude and period of the subsequent oscillations 112.5 m/s
First the law of conservation of momentum,
(m1 + m2)*vf = m1*(vi)1 + m2*(vi)2
m1 = 450g
vi1 = 0
m2 = 450g
vi2 = 150 cm/s
(450 + 150)*vf = 0 + 450* 150
600*vf = 67500
vf = 112.5 cm/s = 112.5 m/s
An indicator of a periodic variable's change over a single period is its amplitude. When measured against a standard value, a non-periodic signal's amplitude is its magnitude. Amplitude has several definitions, all of which (listed below) depend on how much the extreme values of the variable deviate from one another. The amplitude of a periodic function is occasionally referred to as the phase in older writings. Peak amplitude is frequently employed in audio system measurements, telecommunications tests, and other applications where the measurand is a signal that oscillates above and below a reference value but is not sinusoidal. The greatest absolute value of the signal is this if the reference is zero; the mean value of the reference.
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help me ! thank you!!!!!
The horizontal force the student exerts on the boat is equal to 120 N toward in front of the boat. Therefore, option (A) is correct.
What is force?Force acting on a body can be defined as the influence that changes the state of the object of motion or rest. The force's S.I. unit is Newton (N) and is a vector quantity.
Force acting on an object can change the direction as well as the speed of the moving object. The force can be determined from the mass (m) times acceleration (a) of an object.
F = ma
Given, the mass of the student, m = 60 Kg
The acceleration of the student, a = 2.0 m/s²
The force acting on the boat can be calculated as follows:
F = ma
F = 60 ×2.0
F = 120 N
Therefore, the horizontal force is 120 N toward the front of the boat.
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The diameter of the solar system is 10 light hours. A spaceship crosses the solar system in 15 hours, as measured on earth. How long, in hours, does the passage take according to passengers on the spaceship? Hint:c1 light hour per hour.Previous question
According to the spaceship's passengers, the journey took 11.2 hours.
How long would it take to travel to the solar system's outermost point?
In reality, most of interstellar space is located within our solar system. Voyager 1 will need around 300 years to get to the inner edge of the Oort Cloud, and perhaps another 30,000 years to travel past it. The star that is currently closest to our solar system is Alpha Centauri.
Calculation:The spacecraft will travel across in t = 15 hours.
Since this can be measured with a single clock at both locations, the time measured in S' frame is the correct time.
The velocity is :v = 10lh /15 h
v = 2/3 c
Because Δt° = Δς
Δς = Δt√1 - β²
Δς = (15h)√1 - (2/3)²
Δς = 11.2 h
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which of the following sets of conditions is true for an exothermic reaction that is spontaneous at all temperatures?
An exothermic reaction that is spontaneous at any temperature meets the following criteria. ∆H < 0 , ∆S > 0 , ∆G < 0
This is because G = H - T S, and since -T S is always negative, if H is negative and S is positive, then G will always be negative.
Exothermic reactions (H0) characterize combustion. Due to the additional rise in the amount of gaseous species (net gain of one mole of gas, S > 0), this specific reaction entails an increase in entropy. As a result, the reaction is spontaneous (G0) at all temperatures. The sign of G will always be negative when H is negative and S is positive, and the reaction will always be spontaneous at all temperatures.
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complete question: Which of the following sets of conditions is true for an exothermic reaction that is spontaneous at all temperatures?
(a)∆H < 0 , ∆S < 0 , ∆G < 0
(b)∆H > 0 , ∆S < 0 , ∆G < 0
(c)∆H < 0 , ∆S < 0 , ∆G > 0
(d)∆H > 0 , ∆S < 0 , ∆G < 0
(e)∆H < 0 , ∆S > 0 , ∆G < 0
calculate the work done by an 85.0-kg man who pushes a crate 4.00 m up along a ramp that makes an angle of with the horizontal (see below). he exerts a force of 500 n on the crate parallel to the ramp and moves at a constant speed. be certain to include the work he does on the crate and on his body to get up the ramp.
The work done by an 85.0-kg man who pushes a crate 4.00 m up along a ramp that makes an angle of with the horizontal 3.14 x 103 J.
We know that
F = w x d
given
d =4 m
mass of man = 85 kg
force exerted by man on block = 500 N
resolving mg will give mgsin\large \theta and mgcos\large \theta
Ftotal = Fm + 500
Ftotal = mgsin\large \theta + 500 = 85x 9.8 x sin20 + 500 = 284.902 + 500 = 784.902 N
W = Ftotal x d = 784.902 x 4 = 3139.61 = 3.14 x 103 J
In physics, work is energy transferred to or from an object by applying a force along a displacement. In its simplest form, if the constant force is aligned with the direction of travel, it equals the product of the force and the distance traveled.
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The position of an object at any time t is given by: s(t) = x4 + 21x3 + 17x2 + 4x + 33 1. Determine the velocity of the object at any time t. 2. Does the object ever stop changing its position?
Given [tex]s(t) = t^{4} + 21t^{3} + 17t^{2} + 4t +33[/tex]
The velocity of the object at time t is [tex]v(t) = 4t^{3} + 63t^{2} + 34t + 4[/tex]
We know that, velocity is change in position with respect to time.
Therefore, [tex]v(t) = \frac{d[s(t)]}{dt}[/tex]
And it is given that [tex]s(t) = t^{4} + 21t^{3} + 17t^{2} + 4t +33[/tex]
So, differentiating above equation with respect to time t, we get
[tex]\\v(t) = \frac{d[s(t)]}{dt}\\\\ v(t) = \frac{d[t^{4} + 21t^{3} + 17t^{2} + 4t +33]}{dt} \\\\v(t) = 4t^{3} + 63t^{2} + 34t + 4[/tex]
For the second part of the equation, we need to find out if acceleration ever becomes zero. If acceleration is zero, it means the will stop changing it's position.
Now, we know that acceleration is change in velocity with respect to time.
Therefore, [tex]a(t) = \frac{d[v(t)]}{dt}[/tex]
[tex]a(t) = \frac{d[4t^{3} + 63t^{2} + 34t + 4]}{dt} \\\\a(t) = 12t^{2} + 126t +34[/tex]
Since acceleration becomes zero at two values of time t, therefore we can say that it will stop changing position.
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Consider the arrangement of two fixed point charges, equal in magnitude, shown in the figure. Which of the following statements arc correct for the initial motion of a third charge if it is released from rest in the vicinity of the two charges shown? A positive charge at point d will accelerate up. A positive charge at point b will accelerate up. A negative charge at point c will accelerate up. A positive charge at point a will accelerate toward the lower-left. A negative charge at point c will accelerate toward the lower-right.
The option (B and C) are true others are false.
What is acceleration ?
Acceleration is the rate at which velocity changes, as well as how quickly velocity changes over time. instantaneous acceleration is an acceleration at a single moment instantaneous acceleration divided by time deceleration
What is motion ?
The movement of atomic or molecular building blocks in a certain direction is referred to as molecular motion. Temperature and heat both have an impact on molecular mobility. This is so because the measurement of temperature, which reflects molecular motion and average kinetic energy, is used to determine molecular motion.
A is false; a positive charge at point d will be attracted to the nearby negative more than it is repelled by the more distance positive.
B is true
C is true
D is false; the dipole field at point a is directed up (it curves from the lower positive charge to the upper negative one, but is directly upward here) so the charge will initially accelerate up
E is false; similar to question D, the field is up at point c so the negative charge will accelerate initially straight down.
Therefore, the option (B and C) are true others are false.
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(11.2) Describe the expanding steady state model. Describe an observation that would test the predictions of the perfect cosmological principle. Is the steady state model in conflict with present observations of the universe?
Parallel rays of monochromatic light with wavelength 573 nm illuminate two identical slits and produce an interference pattern on a screen that is 75.0 cm from the slits. The centers of the slits are 0.640 mm apart and the width of each slit is 0.434 mm.If the intensity at the center of the central maximum is 4.90×10−4 W/m2 , what is the intensity at a point on the screen that is 0.710 mm from the center of the central maximum?
Express your answer to three significant figures and include the appropriate units.
From three significant figures, the intensity at a point on the screen 0.830mm from the center of the central maximum is I = 8.64 × 10⁻⁶ W/m².
And the appropriate units are [tex]Watts/meter^{2}[/tex].
Monochromatic Light:
Single-wavelength light sources are known as monochromatic lights, where mono stands for only one and chroma for color. Monochromatic lights are defined as visible light that falls within a specific range of wavelengths. It has a wavelength that falls within a constrained wavelength range.
Given,
The wavelength of light; λ = 573 nm = 573 × 10⁻⁹ m
Distance of interference from slits; R = 75 cm = .75 m
Distance between the centers of slit; d = 0.640 mm = 0.00064 m
Width of each slit; a = 0.434 mm = 0.000434 m
Intensity at the central maxima; [tex]I_{o}[/tex] = 4.9 × 10⁻⁴ W/m²
Distance of intensity from the center of the central maximum; y = 0.710 mm = 0.00071 m
Let us first find the angle θ from the formula;
tanθ = y/R
tan θ = 0.00083/0.75
tan θ = 0.001107
θ = tan⁻¹0.001107
θ = 0.06343
θ is very small so
∅ = 2πdsinθ/λ
∅ = 7.7964 rad
Similarly, for the distance between the centers of the slit;
β = 2πasinθ/λ
β = 5.761 rad
For a position on the screen that is 0.830 millimeters from the center of the central maximum, the intensity is calculated as follows:
[tex]I =I_{0}(cos^{2} \frac{\phi}{2} ) [\frac{sin\frac{\beta }{2} }{\frac{\beta }2}} ]^{2}[/tex]
[tex]I=5*10^{-4}(cos^{2}(\frac{7.7964}{2} ) )[\frac{sin\frac{5.287}{2} }{\frac{5.287}{2}} ] ^{2}[/tex]
I = 8.6 × 10⁻⁶ W/m²
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A hockey puck attached to a horizontal spring oscillates on a
frictionless, horizontal surface. The spring has force constant 4.50 N/m and the oscillation period is 1.20 s. (a) What is the mass of the puck? (b) During an oscillation, the acceleration of the puck has maximum magnitude 1.20 m/s^2. What is the amplitude of the oscillation?
Answers:
(a) 0.164 kg
(b) 0.0438 m = 4.38 cm
(a) The mass of the puck is 0.16 kg
(b) The amplitude of the oscillation is 4.3 cm.
What is the mass of the puck?The mass of the puck is calculated by applying the formula for the period of the oscillation.
T = 2π √ ( m /k )
T / 2π = √ ( m /k )
T² / 4π² = m/k
m = k ( T² / 4π² )
where;
k is the spring constantT is the period of oscillationm is mass of the puckThe mass of the puck is calculated as;
m = 4.5 ( 1.2² / 4π²)
m = 0.16 kg
The amplitude of the oscillation is calculated as follows;
a = ω²A
where;
ω is the angular frequencyA is the amplitude a is the maximum accelerationω = √ ( k /m )
ω² = k / m
from this equation "a = ω²A" make amplitude "A" the subject of the formula.
A = a / ω²
A = (a) / (k / m)
A = ( 1.2 ) / ( 4.5 / 0.16)
A = (1.2) / ( 0.03556)
A = 0.043 m = 4.3 cm
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Your camping buddy has an idea for a light to go inside your tent. He happens to have a powerful (and heavy!) horseshoe magnet that he bought at a surplus store. This magnet creates B = 0.15 T field between two pole tips 10 cm apart. His idea is to build a hand-cranked generator shown in Figure. He thinks you can make enough current to fully light a R = 1.0 ? lightbulb rated at 4.0W. That's not super bright, but it should be plenty of light for routine activities in the tent.
Crank 1.0 ?/4.0 w bulb
A. Find an expression for the induced current as a function of time if you turn the crank at frequency f. Assume that the semicircle has a radius of r = 5.0 cm and it is at its highest point at t = 0 s. Express your answer in terms of some or all of the variables B, R, r, f, t, and the constant ?.
B. With what frequency will you have to turn the crank for the maximum current to fully light the bulb?
C. Is this feasible? (Yes or no)
The equation for the induced current as a function of time when the crank is turned at frequency f is I = 2*pi*r2*B*Force(sin (2*pi*force*t))/R. You will need to turn the crank at a frequency of 540.54 Hz.
To completely illuminate the bulb requires the maximum current. Furthermore, this frequency is not practical. The current that results from electromagnetic induction is known as the induced current. The production of electric power relies heavily on electromagnetic induction. Several methods exist for producing this change, including altering the magnetic field's strength,
B, r, R, f, and t are words that describe induced current.
I = E/R = r2*B*2pi*force*sin(2*pi*force*t)/R
Max current Imax = 3.70*10-3 = Imax/3.70*10-3 P = I2/R
Imax = ((4)1/2)/2 AMP F = (2.3.70*10-3) = 540.54Hz
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three identical rocks are launched with identical speeds from the top of a platform of height 0 h . the rocks are launched in the directions indicated above. question which of the following correctly relates the magnitude vy of the vertical component of the velocity of each rock immediately before it hits the ground?
The magnitude of the vertical velocity under gravity changes by approximately 9.81 m/s each second, The option that correctly relates the magnitude, , of the vertical velocity is the option: (vy1=vy1)≥vy3.
The speed of rocks = u
The height the rocks are thrown = h₀
Rock 1; Direction = horizontal above the 45°
Rock 2; Direction =horizontal below45°
Rock 3; Direction = 0° or in the horizontal direction
The vertical component of Rock 1= -u·sin(45°)
Vertical component of Rock 2 = u·sin(45°)
Vertical component of Rock 3 = u·sin(0°) = 0
The velocity of the rock
v² = u² - 2·g·h₀
v= ±√u2-2.g.h0
v= ±√u2-2.g.h0
Therefore, the vertical velocity the rocks, Rock 1 and Rock 2, thrown with magnitude of velocity,|vy|=|u.sin45°| is the same during the vertical motion of the ball at the same height, but change only in sign
at given height h°, vy1=vy2
therefore , before the rocks hit the ground , vy1=vy2
the initial vertical velocity of rocks3, vy3=0,therefore:
∴ vy3=±√v+2.g.h°≤√u²+2.g.h°= (vy1= vy1
there fore , the correct option , we have:
vy1=vy1≥vy3
three identical rocks are launched with identical speeds from the top of a platform of height 0 h . the rocks are launched in the directions indicated above. question which of the following correctly relates the magnitude vy of the vertical component of the velocity of each rock immediately before it hits the ground?
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current attempt in progress the term thermal radiation pertains to radiation emitted over the entire spectrum of electromagnetic radiation. at very long wavelengths. at intermediate wavelengths. at very short wavelengths. etextbook and media save for laterattempts: 0 of 2 usedsubmit answer
Thermal radiation is electromagnetic radiation emitted from all matter that is at a non-zero temperature in the wavelength range from 0.1 μm to 100 μm.
Thermal radiation is electromagnetic radiation emitted from a material this is because of the warmth of the material, the characteristics of which depend upon its temperature. An example of thermal radiation is the infrared radiation emitted with the aid of a commonplace family radiator or electric heater.
Thermal radiation is electromagnetic radiation generated by means of the thermal movement of debris in the matter. Thermal radiation is generated when warmth from the movement of costs in the fabric is transformed into electromagnetic radiation. All count number with a temperature extra than absolute zero emits thermal radiation.
The heating electricity is emitted by using the radiator. Solar radiation. The mild electricity radiated with the aid of incandescent lamps. The emission of gamma rays.
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Water evaporating off a hot and a room-temperature surface?
Look at the pictures above and write a brief description of what is happening in each one on the molecular level.
Answer: Hot and room temperature surface.
Explanation: from the picture the hot temperature surface has easy and loose intermolecular activity, there are more spaces between the molecules to escape. So, it is for the water molecules to evaporate faster which is directly propositional to the temperature. Simply when a water is boiled at 100 degrees that when the heat helps the molecules to evaporate fast through the steam. But when it is in the room temperature the molecules are slightly tightly packed to each other, that is the reason why molecules can't evaporate as fast as compared to the hot temperature. It mostly depends on the intermolecular bond and kinetic energy that helps the molecules to escape into the atmosphere.
Two balls of clay known masses hang from the ceiling on masslessstrings of equal length. They barely touch when both hang atrest. One ball is pulled back until its string is45o, the released. It swings down, collides withthe second ball, and they stick together. To determine theangle to which the balls wing to the opposite side, you need toinvoke:
A. Conservation of momentum
B. Conservation of mechanicalenergy
C. Both conservation of momentum andconservation of mechanical energy
D. Either, but not both.
E. These principles alone are not sufficientto find the angle
To determine theangle to which the balls wing to the opposite side, C. Both conservation of momentum and conservation of mechanical energy (option c).
Conservation of energy and momentum is one of the most important and useful principles in physics. Conservation of momentum states that if no external forces are acting on a system of bodies, the total momentum is always the same (conserved). Furthermore, if we can give a potential to all forces, whether external or internal, the total energy is also constant. This is the law of conservation of energy.
1.Conservation of energy to calculate the velocity of the first ball of clay by the time it descends:
mgh=1/2mu2
[calculate h by using h=L(1-cos45)]
2.Conservation of momentum to find out the final velocity of the balls of clay using:
m1u1+m2u2=(m1+m2)v
3.Conservation of energy to calculate the max height the balls of clay will go by using:
1/2(m1+m2)v2=mgh
Once you have h,
h=L(1-cosθ), solve for θ
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interference occurs with not only light waves but also all frequencies of electromagnetic waves and all other types of waves, such as sound and water waves. suppose that your physics professor sets up two sound speakers in the front of your classroom and uses an electronic oscillator to produce sound waves of a single frequency. when she turns the oscillator on (take this to be its original setting), you and many students hear a loud tone while other students hear nothing. (the speed of sound in air is 340 m/s.)
Answer: Some of the students who originally heard a loud tone again hear a loud tone, but others in that group now hear nothing.
Explanation: When two sources emits identical soundwaves then there is interference of waves.
In region of constructive interference (When the peaks line up with peaks and troughs line up with troughs then resultant wave has twice the amplitude of the original waves) the sound wave will be twice as loud.
In destructive interference (When peaks line up to troughs then results in cancellation of waves, hence resultant have zero amplitude) there is no sound.
Please refer to the image:
Hence, the students who were sitting in the region of constructive interference heard loud tone while the students who were sitting in the region of destructive interference heard nothing.
identify the correct statement from the following. classical physics is valid for matter speeds larger than the speed of light classical physics is valid for object size smaller than microscopic objects classical physics is valid under weak gravitational fields all of these options none of these options
Classical Physics is normally concerned with matter and energy on the normal scale of observation, while modern physics is caring with the behavior of matter and energy under extreme conditions or on a very large or very small scale.
For example, atomic and nuclear physics studies matter on the tiny scale at which chemical elements can be identified. The physics of elementary particles is on an even smaller scale since it is concerned with the most basic units of matter.
Classical Physics is also known as high-energy physics because of the extremely high energies required to produce many types of particles in particle accelerators.
On this scale, regular, commonsense notions of space, time, matter, and energy are no longer valid.
Computational modeling is essential for quantum and relativistic physics.
Classic physics is considered the limit of quantum mechanics for a large number of particles.
On the other side, classic mechanics is derived from relativistic mechanics. Like, in most of the formulations from special relativity, a correction factor (v/c)**2 appears, where v is the velocity of the object and c is the speed of light.
For velocities much minute than that of light, one can neglect the terms with c2 and higher that appear.
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shown from above in (figure 1) is one corner of a rectangular box filled with water. a laser beam starts 10 cm from side a of the container and enters the water at position x. you can ignore the thin walls of the container.
The minimum length required is 17.91 m when a laser beam starts 10 cm from side a of the container and enters the water at position x.
The output laser consists of a number of very closely spaced, discrete frequency components (very narrow spectral lines) covering a moderately broad spectral range. The discrete components are called laser modes and the spectral range they occupy is approximately the fluorescent line width of atomic transition giving rise to the laser output.
Laser oscillations occur, when the wave within the cavity replicate itself after two reflections so that the electric fields add in phase. In other words, the mirrors form a resonant cavity and standing wave patterns are setup.
In most high power applications for material processing or medical surgery, the laser is used as a mean for transferring the energy to the target. Thus there is no importance for the longitudinal laser modes.
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colligative properties are those that depend on the identity and not the concentration of the solute those that depend on the concentration and not on the identity of the solute those that depend on the identity and the concentration of the solute those that do not depend on the amount or identity of the solute
Colligative properties are those of solutions that are influenced by the volume of a nonvolatile solute dissolved in a solution but not by the nature of the solute. The correct option to this question is both b and c
When solute molecules are dissolved in a certain solvent, solutions are created as homogenous mixtures. These solutions have special characteristics that could be referred to as collaborative qualities. These include melting point depression, osmotic pressure, rising boiling point, and reducing vapor pressure.
These solute molecules have an impact on vapor pressure, freezing point, and boiling points.
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Complete question :colligative
property depends on _____.
a. the identity of the solute
b. the concentration of the solution
c. the number of solute particles dissolved in the solution
d. both a and b
e. both b and c
The vapor pressure of liquid ethanol, C2H5OH, is 100. mm Hg at 308 K.
A sample of C2H5OH is placed in a closed, evacuated 529 mL container at a temperature of 308 K. It is found that all of the C2H5OH is in the vapor phase and that the pressure is 67.0 mm Hg. If the volume of the container is reduced to 344 mL at constant temperature, which of the following statements are correct?
Choose all that apply.
a. The pressure in the container will be 103 mm Hg.
b. Some of the vapor initially present will condense.
c. Liquid ethanol will be present.
d. Only ethanol vapor will be present.
e. No condensation will occur.
B
The statements that apply are;
The pressure in the container will be 103 mm Hg. Some of the vapor initially present will condense.Liquid ethanol will be present.What is the new pressure?We know that the pressure can be taken as the force with which the molecules of the substance are able to hit the walls of the container in this case, we need to obtain the pressure of the ethanol vapor when the volume has been reduced.
Using
P1 = initial pressure
P2 = final pressure
V 1 = initial volume
V2 = final volume
By the use of the Boyle's law we have;
P1V1 = P2V2
P2 = P1V1 /V2
P2 = 67.0 * 529/344
P2 = 103 mmHg
Thus, as the volume is reduced there would be an increase in the pressure and some of the ethanol would condense and we would have liquid ethanol in the system.
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A kettle is rated as 2.3kW. A mass of 750g of water at 20oC is poured into the kettle.When the kettle is switched on, it takes 2.0 minutes for the H2O to start boiling. In a further 7.0 minutes, half of the mass of H2O is boiled away. Estimate for this water: The specific heat capacity, the specific latent heat of vaporization.
The specific heat capacity of water, Cw is 4.6 J/g/K
The specific latent heat of vaporization of water, Cv is 2576 J/K
What is the amount of energy used by the kettle?Electrical energy is defined as the product of electrical power in watts and time in seconds.
Mathematically;
Electrical energy = power * time
The amount of energy used by the kettle to boil the water is calculated below:
Energy used = 2.3 kW * 1000 W/kW * 2 * 60 s/min
Energy used = 276000 J
The specific heat capacity of water, Cw is determined as follows:
Energy = mass * Cw * temperature change
Cw = Energy / mass * temperature change
Cw = 276000 / 750 * (100°C - 20°C)
Cw = 4.6 J/g/K
The amount of energy used by the kettle to evaporate half the mass of the water is calculated below:
Energy = 2.3 kW * 1000 W/kW * 7 * 60 s/min
Energy used = 966000 J
The specific latent heat of vaporization of water, Cv is determined as follows:
Energy = mass * Cv
Cv = Energy / mass
Cv = 966000 / (750 * 0.5)
Cv = 2576 J/K
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a metal with a work function of 1.2 ev is illuminated by visible light with the full range of wavelengths, which we take to be 400 nm to 700 nm. What is the maximum kinetic energy, in electron volts, of the photoelectrons?
The maximum kinetic energy, in electron volts of the photoelectrons, is K.Emax = 1.8ev.
Solution:
E = Wo + K.Emax
= 3.10ev = 1.3ev + K.Emax
= K.Emax = 1.8ev
Kinetic energy is the energy that an object has when it moves. If you want to accelerate an object you have to apply a force. To add strength, we need our work. When the work is done, the energy is transferred to the object and it moves at a new constant speed.
Kinetic energy is the kinetic energy observable as the motion of a body particle or group of particles. All moving objects use kinetic energy. A person walking throwing a baseball crumbs falling from a table and charged particles in an electric field are examples of kinetic energy.
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