Answer:
4.44 m/s^2
Explanation:
A 15-kg wagon is pulled to the right across a surface by a tension of 100 newtons at an angle of 30 degrees above the horizontal. A frictional force of 20 newtons to the left acts simultaneously.The acceleration of the wagon 4.44 m/s².
What is acceleration?The rate at which an item changes its velocity is known as acceleration, a vector quantity. If an object's velocity is changing, it is acceleration.
Given in the question a 15 kg wagon is pulled to the right across a surface by a tension of 100 newtons at an angle of 30 degrees above the horizontal. A frictional force of 20 newtons to the left acts simultaneously, then the acceleration is 4.44 m/s².
The acceleration of the wagon 4.44 m/s².
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What happens to most of the light waves that strike a clear pane of glass? O A. absorption B. diffraction O C. reflection O D. transmission
slight reflect but most goes through because glass is transparent
Most of the light waves that strike a clear pane of glass reflects. Details about reflection can be found below.
What is reflection?Refection in physics is the property of a propagated wave being thrown back from a surface such as a mirror.
Mirror is an example of an object that could be hit by an incumbent wave, however, most of the light waves that hit the mirror surface gets reflected back.
Therefore, most of the light waves that strike a clear pane of glass reflects.
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which of the following is not a mechanical form of energy?
a. Nuclear
b. Kinetic
c. Spring potential
d. Gravitational potential
Answer:
The answer is Spring Potential
Explanation:
Because all the others are a mechanical form of energy
Four students were loading boxes of food collected during a food drive. The force that each student exerted while lifting and the distance each box was lifted are listed in the table.
A 3-column table with 4 rows. The first column labeled student has entries Chet, Mika, Sara, Bill. The second column labeled Force (Newtons) has entries 50, 40, 30, 60. The third column labeled Distance (meters) has entries 1.0, 2.0, 1.5, 0.5.
Which lists the students in order from the greatest amount of work done to the least? (Work: W = Fd)
Answer:
The correct answer is B. Mika, Chet, Sara, Bill
Explanation:
Look at the picture
hope this helps :)
The list, that the students in order from the greatest amount of work done to the least, is: Mika, Chet, Sara, Bill.
What is work?We can state that Work is the product of the component of the force acting in the displacement's direction and its magnitude.
The joule (J), a unit of work used in the International System of Units (SI), is defined as the amount of work required to move an item one meter in the direction of a force of one newton.
Work done by Mika = 50 × 1.0 Joule = 50 Joule
Work done by Chet = 40 × 2.0 Joule = 80 Joule
Work done by Sara = 30 × 1.5 Joule = 45 Joule
Work done by Bill = 60 × 0.5 Joule = 30 Joule
So, The list, that the students in order from the greatest amount of work done to the least, is: Mika, Chet, Sara, Bill.
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a projectile is shot upward from the surface of the earth with an initial velocity of 384 ft/s. What is its velocity after 5 seconds
Answer:
335 ft/s
Explanation:
In this question, we have a very important factor missing. The equation of the projectile. So, in simplifying the question I'm going to assume an equation which you can correct thereafter
s(t) = -4.9t² + v(0)t + s0
From the question, we're told that v(0) = 384 ft/s, so if we apply that, we have
s(t) = -4.9t² + 384t + s0, where s0 = 0
On differentiating the equation, we have
s(t) = v(t) = -4.9(2t) + 384(1)
v(t) = -9.8t + 384
Now, at time t = 5 seconds, the velocity v =
v(t) = -9.8(5) + 384
v(t) = -49 + 384
v(t) = 335 ft/s
Therefore, the velocity of the projectile after 5 seconds is 335 ft/s. Please leave a like if it helped you.
Compute the density in g/cm? of a piece of metal that has a mass of 0.450 kg and a volume of 52 cm3
Answer:
Ro = 8.65 [g/cm³]
Explanation:
We must remember that density is defined as the ratio of mass to volume.
[tex]Ro=m/V[/tex]
where:
m = mass = 0.450 [kg] = 450 [g]
V = volumen = 52 [cm³]
Ro = density [g/cm³]
Now replacing:
[tex]Ro = 450/52\\Ro = 8.65 [g/cm^{3} ][/tex]
if humans have some animal blood sails why do we walk on 2 feet
write the difference between convert and
Concave minores
A block slides along a frictionless surface and onto a slab with a rough surface. The slab has mass of 4 kg and the block has mass of 2 kg. What is the friction force on the small block at t = 1 second?
Answer: the friction force on the small block at t equals 1 second is 2N
Explanation:
Given the data in the question;
from the slope in the graph provided, we will get the acceleration of the slab
At t = 1 seconds
Slope = acceleration = ( 1 - 0) / ( 2 - 0 ) = 1/2 = 0.5 m/s²
Force = ma = 4 × 0.5 = 2 N
so by Newton's third law
Force on block will be same which is 2N
Therefore the friction force on the small block at t equals 1 second is 2N
The work done on the machine is called
Answer:
Hey Queen Messy here!
Work input
Explanation:
The work you do on a machine is called the work input. The force you apply to the machine to do the work is the input force. The work done by the machine on another object is called the work output. The force the machine applies to do this work is the output force.
Help!!
The effects of an increasing BAC are not linked to the passage of time.
A. True
B. False
The statement 'the effects of an increasing BAC are not linked to the passage of time' is False.
What does BAC mean?The abbreviation BAC indicates 'blood alcohol concentration' and it is a measure that allows us to know the amount of alcoholic content.
This value (blood alcohol concentration) is well known to decrease over time.In conclusion, the statement 'the effects of an increasing BAC are not linked to the passage of time' is False.
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A student is creating an electromagnet for an investigation. Which feature of the electromagnet will least influence the magnetic force?
A
the material of the core
B
the brand of the battery
С
the number of wire coils
D
the che of the power source
What average net force is required to stop a 3.5 kg bowling ball initially travelling at a speed of 1.5 m/s over a distance of 0.4 m?
First the aceleration:
Vf² = Vo² - 2ad
a = (Vf² - Vo²) / 2d
a = (0 m/s)² - (1,5 m/s)²) / 2 * 0,4 m
a = -2,25 m²/s² / 0,8 m
a = -2,81 m/s²
Now, for the net force, use 2nd law of Newton:
F = ma
F = 3,5 kg * (-2,81 m/s²)
F = -9,835 N
The force for stop the bowling ball is -9,835 Newtons.
Approximating Earth's atmosphere as a layer of gas 6.8 km thick, with uniform density 1.3 kg/m3 , calculate the total mass of the atmosphere.
Answer:
The total mass of the atmosphere is 4.508 x 10⁹ kg
Explanation:
Given;
thickness of gas layer, h = 6.8 km
density of Earth's atmosphere, ρ = 1.3 kg/m³
the surface area of Earth is given as 5.10 x 10⁸ km²
Volume of the atmosphere is calculated as;
V = Ah
where;
A is the surface area of Earth
h is the thickness of gas layer
V = (5.10 x 10⁸ km²)(6.8 km)
V = 3.468 x 10⁹ km³
The total mass of the atmosphere is calculated as;
mass = density x volume
m = ρV
m = (1.3 kg/m³)(3.468 x 10⁹ km³)
m = 4.508 x 10⁹ kg
Therefore, the total mass of the atmosphere is 4.508 x 10⁹ kg.
Say a funny joke and whoever makes me laugh the hardest gets brainliest or however u spell it haha
Answer:
i cant make funny joke
Explanation:
but i can be alive.
wait no, im failing at that currently.
Which of these is another name for Newton's
first law?
A. the law of action-reaction
B. the law of force and acceleration
C. the law of gravity
D. the law of inertia
What type of telescope did Galileo use to observe Jupiter?
reflector telescope
refractor telescope
radio telescope
latter telescope
Answer:
a refractor telescope
Explanation:
Answer:
a. refractor telescope
A man weighs himself twice in an elevator. When the elevator is at rest, he weighs 824 N; when the elevator starts moving upward, he weighs 932 N. Most nearly how fast is the elevator accelerating, assuming constant acceleration?
a. 0.64 m/s
b. 1.1 m/s^2
c. 1.3 m/s
d. 9.8 m/s^2
Answer: c. 1.3 m/s^2
Explanation:
When he is at rest, is weight can be calculated as:
W = g*m
where:
m = mass of the man
g = gravitational acceleration = 9.8m/s^2
We know that at rest his weight is W = 824N, then we have:
824N = m*9.8m/s^2
824N/(9.8m/s^2) = m = 84.1 kg
Now, when the elevators moves up with an acceleration a, the acceleration that the man inside fells down is g + a.
Then the new weight is calculated as:
W = m*(g + a)
and we know that in this case:
W = 932N
g = 9.8m/s^2
m = 84.1 kg
Then we can find the value of a if we solve:
932N = 84.1kg*(9.8m/s^2 + a)
932N/84.1kg = 11.1 m/s^2 = 9.8m/s^2 + a
11.1 m/s^2 - 9.8m/s^2 = a = 1.3 m/s^2
The correct option is C
arrangement in which a light ball hangs from a thread and oscillates freely
Answer:
pendulum
hope it helps! please mark me brainliest..
Thank you! have a good day ahead
Help! Help!
___ are a primary way to discourage drinking and driving.
A. High prices for alcohol
B. Scare tactics
C. Laws
Answer:
Laws
Explanation:
Laws are a primary way discourage drinking and driving
A primary way to discourage drinking and driving is Law.
What is drinking and driving?The person who takes in alcohol and then drives on the road. This is strictly prohibited.
Laws against the 'drinking and driving' will make people get scared of getting charged or sentenced to jail for some years. Lot of accidents have caused when there were no laws against the action.
Thus, Laws are a primary way to discourage drinking and driving.
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The weight of a 0.5 kg object on the surface of Planet X is 20 N. If the radius of the planet is 4 X 106 m, what is its mass?
Answer:
The mass of the Planet X is 9.595 x 10²⁴ kg.
Explanation:
mass of the object, m = 0.5 kg
radius of the Planet X, r = 4 x 10⁶ m
weight of the object, W = F = 20 N
let the mass of the Planet X = mₓ
Apply Newton's gravitational law;
[tex]F = \frac{Gmm_x}{r^2} \\\\m_x = \frac{Fr^2}{Gm} \\\\m_x = \frac{(20)(4\times 10^6)^2}{6.67 \times 10^{-11} \ \times \ 0.5} \\\\m_x = 9.595 \times 10^{24} \ kg[/tex]
Therefore, the mass of the Planet X is 9.595 x 10²⁴ kg.
The electron has the positron as its antiparticle.
A True
B False
please hellp!!!!!!!!!!!!!!!!!!!!?
Answer:
the second to last by the north pole
Explanation:
what is true about ocean water that is more dense?
1. It is generally warmer water.
2. It sinks to the bottom.
3. It has a lower salinity than less dense water.
4. It rises to the surface.
Answer:
Ocean water is more dense because of the salt in it. ... Temperature has a greater effect on the density of water than salinity does. So a layer of water with higher salinity can actual float on top of water with lower salinity if the layer with higher salinity is quite a bit warmer than the lower salinity layer.
rawr goes the dinosaur rawrrrrrrr >:c
Answer:
rawrrrrrrrrrrrrrrrrrr
lol Thank you
Answer:AAAAAAHHHHH scary :c
Explanation:
A boy climbs 12.0m up an apple tree. He picks an apple and throws it horizontally with a velocity of 3.0 m/s. How far forward does the ball go before it hits the ground
Answer:
4.692m
Explanation:
The distance that this boy climbed = 12.0m
The velocity = 3.0m/s
We are to find how far forward this apple goes before it hits the ground.
We have y = 1/2gt²
X = v*t
T = 1.564 seconds
X = 3x1.564
X = 4.692m
Therefore the ball goes a distance of 4.692m forward before it then hits the ground.
Two skaters, each of mass 51.2 kg, approach each other along parallel paths separated by 2.92 m. They have equal and op- posite velocities of 1.38 m/s. The first skater carries a long light pole 2.92 m long, and the second skater grabs the end of it as he passes; see Fig. 10-30. Assume frictionless ice. (a) Describe quantitatively the motion of the skaters after they are connected by the pole. (b) By pulling on the pole, the skaters reduce their separation to 0.940 m. Find their angular speed then.
Answer:
a) w = 0.4726 rad / s, b) w_{f} = 4.56 rad / s
Explanation:
a) the two skaters have an angular momentum, for which we will form a system formed by the two of them, in this case when they collide the forces are internal and the moment is conserved.
Initial instant. When the skaters approach, just before touching
L₀ = r p = r m v
in this case the result is the same if we take the reference system at the midpoint or on one of the skaters. We place the reference system on one of the skaters
Final moment. After being joined by the pole
[tex]L_{f}[/tex] = I w
as the forces are internal, the ngualr moment is conserved
L₀ = L_{f}
r m v = I w
suppose we approximate the skaters as particles
I = m r²
we substitute
r m v = m r² w
w = v /r
we calculate
w = 1.38 /2.92
w = 0.4726 rad / s
What happens is that when the two skaters lower the pole, their velocity acts as a torque, creating a rotational movement with angular velocity w.
b) When the skaters who are at r₀ = 2.92 m approach [tex]r_{f}[/tex] = 0.940 m as the system is isolated, the angular momentum is conserved
initial instant. r₀ = 2.92
L₀ = I w
final instant r_{f} = 0.940 m
L_{f} = I_{f} w_{f}
L₀ = L_{f}
I w = I_{f} w_{f}
let's approximate skaters as particles
I = m r²
we substitute
m r² w = m r_{f}² wf
[tex]w_{f}[/tex] = [tex]\frac{r^{2} }{r_{f}^{2} } w[/tex]
we calculate
w_{f} = [tex]\frac{2.92^{2} }{ 0.940^{2} }[/tex] 0.4726
w_{f} = 4.56 rad / s
we see that the angular velocity increases
Define friction. Prove that tangent of angle of friction is equal to coefficient
of friction.
Answer:
Friction is the force that opposes movement between moving objects.
The angle at which one object starts to slip on the other is directly related to the coefficient. When the two objects are horizontal there is no frictional force. So, the coefficient of static friction is equal to the tangent of the angle at which the objects slide. A similar method can be used to measure μk.
Explanation:
Answer:
brainliest plsssssss
Explanation:
The resistance that one surface or object encounters when moving over another
Sample Volume Mass
A 100 ml 100 g
B 80 ml 100 g
C 110 ml 100 g
D 120 ml 100 g
^table
The table shows the volumes of different samples of liquid. Which sample has the greatest DENSITY?
A)
Sample A
B)
Sample B
C)
Sample C
D)
Sample D
Answer:
sample B
Explanation:
The samples given all have the same mass which is 100g but their volume differs significantly.
Density is the mass per unit volume of a substance. The mass is the amount of matter contained in a substance. Volume is the space a body occupies.
Density = [tex]\frac{Mass}{Volume}[/tex]
Density is inversely proportional to volume. The higher the volume the lesser the density provided the mass is constant.
So, the sample with the least volume will have the greatest density value.
This sample is sample B
Answer:
the answer is b
Explanation:
A 0.323 kg ball is moving 13.9 m/s when it runs into a spring. If the spring compresses 0.350 m in bringing the ball to a stop, what is the spring constant?
Answer:
Explanation:
F = -k*x
k = F/x = (0.323*9.8)/(0.35)
k = 9.04
The kinetic energy of the spring is equal to its elastic potential energy. From this we can determine the force constant k. The force, constant of the ball here is 509.4 N/m.
What is spring constant ?The applied force f on an elastic material like a spring is directly proportional to the displacement x of the material.
Thus, f = -k x
here, the proportionality constant k is called spring constant or force constant. It can be defined as the force required to stretch or compress an elastic material by 1 m.
The elastic potential energy = 1/2 kx²
it is equal to the kinetic energy of the material if its move to form a wave like a spring.
Here, mass of the ball = 0.323 kg
velocity = 13.9 m/s
displacement = 0.350 m
then 1/2 mv² = 1/2 kx²
then k = mv²/x²
k = 0.323 kg × (13.9 m/s)²/ (0.35)² = 509.4 N/m
Therefore, the spring constant of the ball will be 509.4 N/m.
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A student drops a ball off the top of building and records that the ball takes 3.82s to reach the ground. Determine all unknowns and answer the following questions. Neglect drag.
What was the ball's speed just before striking the ground?
m/s
From what height was the ball dropped?
m
Explanation:
Given parameters:
Time of drop = 3.82s
Unknown:
Final velocity of the ball = ?
Height of fall = ?
Solution:
To solve this problem, we apply the appropriate motion equation.
To find the final velocity;
v = u + gt
v is the unknown final velocity
u is the initial velocity = 0m/s
g is the acceleration due to gravity = 9.8m/s²
t is the time
v = 0 + 9.8 x 3.82 = 37.4m/s
Height of drop;
H = ut + [tex]\frac{1}{2}[/tex]gt²
So;
H = (0 x 3.82) + ( [tex]\frac{1}{2}[/tex] x 9.8 x 3.82²) = 71.5m