A. 10g
B.33g
C.40g
D.42g

Answer:

b

Explanation:

Answer:

J = 357.5 kg*m/s

Explanation:

       [tex]p_{o} = m*v_{o} = 55 kg * (-3.0 m/s) (1)[/tex]

       [tex]p_{f} = m*v_{f} = 55 kg * (3.5 m/s) (2)[/tex]

      [tex]J = p_{f} - p_{o} = m* (v_{f} -v_{o}) = 55 kg* (3.5m/s- (-3.0m/s)) = 357.5 kg*m/s (3)[/tex]

Answer:

a) 6636 km

b) 0.0154

Explanation:

The height above the earth at its furthest point is 368 km

The height above the earth at its closest point is 164 km

Radius of the Earth is 6370 km

The distance of the satellite from the center of the earth to the furthest point is 6370 + 368 km = 6738 km

The distance of the satellite from the center of the earth to the closest point is 6370 + 164 = 6534 km

If we add together the sum of the distance of the satellite from the furthest and its closest distance, it is equal to the 2 major semi axis.

Basically,

2a = R + r

a = (R + r) / 2

a = (6738 + 6534) / 2

a = 13272 / 2

a = 6636 km

Eccentricity, e = (a - r) / a

Eccentricity, e = (6636 - 6534) / 6636

Eccentricity, e = 102 / 6636

Eccentricity, e = 0.0154

Explanation:

Assume that mass of Earth is M, radius of earth orbit is R, and rotational period of Earth is T.

The angular momentum of Earth is,

 [tex]L_{z} &=M R^{2} \omega \\ &=M R^{2}\left(\frac{2 \pi}{T}\right) \\ &=\frac{2 \pi M R^{2}}{T}[/tex]

The mass of mars is, mass of Earth

=0.11 M

The radius of mars orbit is, of radius of earth

=0.53 R

The rotational period of mars is, of period of Earth

=1.03 T

The angular momentum of mars is,

[tex]L_{m}=\frac{2 \pi(0.11 M)(0.53 R)^{2}}{1.03 T}[/tex]

The angular momentum of mars is,

[tex]L_{m}=\frac{2 \pi(0.11 M)(0.53 R)^{2}}{1.03 T}[/tex]

The ratio of angular momentum of mars to that of earth is,

[tex]\frac{L_{m}}{L_{E}}=\frac{\frac{2 \pi(0.11 M)(0.53 R)^{2}}{1.03 T}}{\frac{2 \pi M R^{2}}{T}} \\ \frac{L_{m}}{L_{E}}=0.03 \\ \frac{L_{m}}{L_{B}}=3.0 \times 10^{-2}[/tex]

Answer:

13/23 ydfffgggggggffttf

Answer:

Centripetal acceleration is defined as the property of the motion of an object, traversing a circular path. Any object that is moving in a circle and has an acceleration vector pointed towards the center of that circle is known as Centripetal acceleration. ... Centripetal means towards the center.

Answer:

while ice is made by water again it melts and becomes water. water is colourless and odourless and has no taste but ice is only cold and hard. water is used for drinking and other things. but is for freshness and it never flows

Explanation:

so ice reflect more energy compared to water

Answer:

Acceleration = Δv/Δt or change in velocity over change in time

Explanation:

Answer:

1) Linear motion

2) Rotational motion

3) Rotational Motion

4) Random Motion ( The ball can be rolling in any direction)

5) Linear motion

The types of motion in each activity include the following:

This involves an object or a body changing position over time. There are

different types of motion with different examples as can be seen above in

this scenario.

Read more about Motion here https://brainly.com/question/453639

Answer:

0.15 s

Explanation:

From the question given above, the following data were obtained:

Speed of sound (v) = 330 m/s

Distance (x) = 25 m

Time (t) =?

The time taken for the echo of the sound to the bat can be obtained as follow:

v = 2x / t

330 = 2 × 25 / t

330 = 50 / t

Cross multiply

330 × t = 50

Divide both side by 330

t = 50 / 330

t = 0.15 s

Thus, it will take 0.15 s for the echo of the sound to the bat

Answer:

true

Explanation:

i think its true beacuse water can cause electricity

pls let me know if corrct

if yes pls mark brainlest

Explanation:

c willl fall fast then a and b

Answer:

72 J

Explanation:

Use the Work formula

W= F x d

Given:

F - 48 N

d - 1.5 m

Solution:

W= F x d

W=  48 N x 1.5 m

W= 72 J

Answer:

Answer down below!

Explanation:

Answer:

τ = RC = 2.17 s

Explanation:

       [tex]V_{C} =V_{o} * e^{-t/RC} (1)[/tex]

       [tex]V_{C} = 1.00 V\\V_{o} = 100V\\t = 10.0 s[/tex]

      [tex]\frac{1.00V}{100 V} = e^{-10s/RC} (2)[/tex]

       [tex]R*C= \frac{-10s}{ln 0.01} = 2.17s (3)[/tex]

Answer:the answer is galaxy

Explanation:

Explanation:

Its D. The warm air from the land moves towards the water

Answer:

The work done by non-conservative forces on the car from the top of the first hill to the top of the second hill is 6574.75 joules.

Explanation:

By Principle of Energy Conservation and Work-Energy Theorem we present the equations that describe the situation of the roller coaster car on each top of the hill. Let consider that bottom has a height of zero meters.

From top of the first hill to the bottom

[tex]m\cdot g \cdot h_{1} = \frac{1}{2}\cdot m\cdot v_{1}^{2} +W_{1, loss}[/tex] (1)

From the bottom to the top of the second hill

[tex]\frac{1}{2}\cdot m\cdot v_{1}^{2} = m\cdot g \cdot h_{2} + \frac{1}{2}\cdot m \cdot v_{2}^{2}+W_{2,loss}[/tex] (2)

Where:

[tex]m[/tex] - Mass of the roller coaster car, in kilograms.

[tex]v_{1}[/tex] - Speed of the roller coaster car at the bottom between the two hills, in meters per second.

[tex]g[/tex] - Gravitational acceleration, in meters per square second.

[tex]h_{1}[/tex] - Height of the first top of the hill with respect to the bottom, in meters.

[tex]W_{1, loss}[/tex] - Work done by non-conservative forces on the car between the top of the first hill and the bottom, in joules.

[tex]v_{2}[/tex] - Speed of the roller coaster car at the top of the second hill, in meters per seconds.

[tex]h_{2}[/tex] - Height of the second top of the hill with respect to the bottom, in meters.

[tex]W_{2, loss}[/tex] - Work done by non-conservative forces on the car bewteen the bottom between the two hills and the top of the second hill, in joules.

By using (1) and (2), we reduce the system of equation into a sole expression:

[tex]m\cdot g\cdot h_{1} = m\cdot g\cdot h_{2} + \frac{1}{2}\cdot m \cdot v_{2}^{2} + W_{loss}[/tex] (3)

Where [tex]W_{loss}[/tex] is the work done by non-conservative forces on the car from the top of the first hill to the top of the second hill, in joules.

If we know that [tex]m = 175\,kg[/tex], [tex]g = 9.807\,\frac{m}{s^{2}}[/tex], [tex]h_{1} = 18\,m[/tex], [tex]h_{2} = 8\,m[/tex] and [tex]v_{2} = 11\,\frac{m}{s}[/tex], then the work done by non-conservative force is:

[tex]W_{loss} = m\cdot\left[ g\cdot \left(h_{1}-h_{2}\right)-\frac{1}{2}\cdot v_{2}^{2} \right][/tex]

[tex]W_{loss} = 6574.75\,J[/tex]

The work done by non-conservative forces on the car from the top of the first hill to the top of the second hill is 6574.75 joules.

Answer:

A

Explanation:

The angular momentum of a system of particles around a point in a fixed inertial reference frame is conserved if there is no net external torque around that point:

d

→

L

d

t

=

0

or

→

L

=

→

l

1

+

→

l

2

+

⋯

+

→

l

N

=

constant

.

Note that the total angular momentum

→

L

is conserved. Any of the individual angular momenta can change as long as their sum remains constant. This law is analogous to linear momentum being conserved when the external force on a system is zero.

Answer: Because of the amount of energy

Explanation: Heat is an energy, and small amounts of it does not effect large areas, whereas a very large blast of heat energy can greatly effect the air

Answer:

B I believe, because the axe is wedged into the log

Answer:

B

Explanation:

I think just rhis is the answer

The breeze/wind moves from the land to the sea. This statement is NOT correct about sea breezes.

Local wind patterns known as sea breezes flow from the sea to land during the day. When there is no strong large-scale wind system and it is very hot or very cold during the day or at night, sea breezes and land breezes alternate along the coasts of large lakes or oceans.

Because the sea breeze's surface flow ends over land, an area of low-level air convergence is created. Locally, this convergence frequently causes air to rise, which promotes the formation of clouds. Showers over land in the afternoon may result from such clouds.

Hence, the sea  breeze/wind moves from the land to the sea. This statement is NOT correct about sea breezes.

Learn more about sea breeze here:

https://brainly.com/question/13015619

#SPJ6

Answer:

5.4 m/s

Explanation:

Given that

Mass of the safe, m1 = 1000 kg

Distance to lower the safe, d = 3 m

Mass of furniture, m2 = 500 kg.

Speed of the safe, v = ?

To get the final speed by the time that the safe hits the truck, we first find its acceleration.

The total mass of the system is M = 1000 + 500 kg = 1500 kg

One of the forces acting on the system is that of gravity, and it acts on the safe friction acting on the furniture. Using the formula, we have

= m1*g - mu*m2g

= 1000 * 9.81 - 0.5 * 500 * 9.81

= 7357.5 N

From this calculated weight, we find the acceleration.

Acceleration, a = F/m

Acceleration, a = 7357.5 / 1500

Acceleration, a = 4.905 m/s²

From the question, we know that the Initial speed = 0 m/s

So, employing the use of one of the equations of motion, we have

v² - u² = 2aS

v² - 0 = 2 * 4.905 * 3

v² = 29.43

v = √29.43

v = 5.4 m/s

Answer:

B

Explanation:

Where it shows on the map is B

One of the major effects of heat transfer is temperature change: heating increases the temperature while cooling decreases it. We assume that there is no phase change and that no work is done on or by the system. Experiments show that the transferred heat depends on three factors—the change in temperature, the mass of the system, and the substance and phase of the substance.

Figure a shows a copper-colored cylinder of mass m and temperature change delta T. The heat Q, shown as a wavy rightward horizontal arrow, is transferred to the cylinder from the left. To the right of this image is a similar image, except that the heat transferred Q prime is twice the heat Q. The temperature change of this second cylinder, which is also labeled m, is two delta T. This cylinder is surrounded by small black wavy lines radiating outward. Figure b shows the same two cylinders as in Figure a. The left cylinder is labeled m and delta T and has a wavy heat arrow pointing at it from the left that is labeled Q. The right cylinder is labeled two m and delta T and has a wavy heat arrow pointing to it from the left labeled Q prime equals two Q. Figure c shows the same copper cylinder of mass m and with temperature change delta T, with heat Q being transferred to it. To the right of this cylinder, Q prime equals ten point eight times Q is being transferred to another cylinder filled with water whose mass and change in temperature are the same as that of the copper cylinder.

Answer:

500 m/s

Explanation:

From the question,

V = √(T/m')................. Equation 1

Where V = Speed with which the wave travels on the string, T = Tension of the string, m' = Mass per unit length of the string.

Given: T = 1200 N, m' = 4.80×10⁻³ kg/m

Substitute these values into equation 1

V = √(1200/4.80×10⁻³)

V = √(250000)

V = 500 m/s

Hence the speed of the wave in the string is 500 m/s

Answer:

They're going to come home as soon as the movie is over.

Answer:

B: They're going to come home as soon as the movie is over.

Explanation:

Answer:

his distance is too small (r = 0.01 mm), therefore the cut can be at any distance

Explanation:

For this exercise let's use the ampere law.

Let's use a cylinder as the circulating surface

          ∫ B. ds = μ₀ I

in this case the field is circular and ds is circular therefore the angle between them is zero and cos 0 = 1

          B 2π r =  μ₀ I

          r =  [tex]\frac{\mu_o I}{2\pi B}[/tex]

The field needed to demagnetize the card is B = 1000 gauss = 0.1 T

          r = [tex]\frac{4\pi 10^{-7} 5.0 }{2\pi \ 0.1}[/tex]

           r = 2 10⁻⁷  5.0/0.1

          r = 1  10⁻⁵ m

this distance is too small (r = 0.01 mm), therefore the cut can be at any distance