Answer:
a) a = 34.375 m / s², b) v_f = 550 m / s
Explanation:
This problem is the launch of projectiles, they tell us to ignore the effect of the friction force.
a) Let's start with the final part of the movement, which is carried out from t= 16 s with constant speed
v_f = [tex]\frac{x-x_1}{t}[/tex]
we substitute the values
v_f = [tex]\frac{ 6600 -x_1}{4}[/tex]
The initial part of the movement is carried out with acceleration
v_f = v₀ + a t
x₁ = x₀ + v₀ t + ½ a t²
the rocket starts from rest v₀ = 0 with an initial height x₀ = 0
x₁ = ½ a t²
v_f = a t
we substitute the values
x₁ = 1/2 a 16²
x₁ = 128 a
v_f = 16 a
let's write our system of equations
v_f = [tex]\frac{6600 - x_1}{4}[/tex]
x₁ = 128 a
v_f = 16 a
we substitute in the first equation
16 a = [tex]\frac{6600 -128 a}{4}[/tex]
16 4 a = 6600 - 128 a
a (64 + 128) = 6600
a = 6600/192
a = 34.375 m / s²
b) let's find the time to reach this height
x = ½ to t²
t² = 2y / a
t² = 2 5100 / 34.375
t² = 296.72
t = 17.2 s
We can see that for this time the acceleration is zero, so the rocket is in the constant velocity part
v_f = 16 a
v_f = 16 34.375
v_f = 550 m / s
pls solve this:
if u solve this, I will surely mark u as brilliant
Answer: The frequency of a pendulum is [tex]0.2 s^{-1}[/tex].
Explanation:
Time period is defined as the time required to produce complete wave.
As we know that the frequency and time are inversely proportional to each other.
That means,
[tex]\nu =\frac{1}{T}[/tex]
Where,
[tex]\nu[/tex] is frequency of pendulum
T is time period
Given:
Time period = 5 seconds
Now putting all the given values in the above formula, we get the frequency of the pendulum.
[tex]\nu =\frac{1}{T}\\\\\nu =\frac{1}{5s}\\\\\nu =0.2s^{-1}[/tex]
Therefore, the frequency of a pendulum is [tex]0.2 s^{-1}[/tex].
. If the static and kinetic friction between the tire and the inclined plane are 0.2 (static) and 0.15 (kinetic), calculate the maximum inclination angle so that the tire rolls without slipping
Answer:
81.47°
Explanation:
The forward force on the tire is the horizontal component of its weight along the incline mgcosФ. The frictional force along the incline is μmgsinΦ where mgsinΦ is the vertical component of the tire's weight along the incline.
Since the tire rolls without slipping, then
mgcosФ = μmgsinΦ where μ = coefficient of kinetic friction = 0.15 (since the tire is in motion) and Φ is the angle of the incline.
So, mgcosФ = μmgsinΦ
mgcosФ/mgsinΦ = μ
μ = cosФ/sinΦ
μ = 1/tanФ
tanФ = 1/μ
Φ = tan⁻¹(1/μ)
substituting into the equation, we have
Φ = tan⁻¹(1/0.15)
Φ = tan⁻¹(6.667)
Φ = 81.47°
What is the essential concept of the photon theory of light?
Answer:
Cause it gives us internet
Which of the following is the best definition of a physical change?
A. A change in a substance where a new substance is formed
B. A change in a substance in which bonds are broken
C. A change in a substance with no new substances being formed
D. A change in a substance in which mass is conserved
Answer:
The answer is C. A change in a substance with no new substances being formed
Explanation:
I did the quiz.
The best definition of physical change is a change in a substance, with no new substances being formed. Hence, option C is correct.
What is a Physical Change?A chemical substance's form, not its chemical composition, can change due to physical changes. In most cases, compounds cannot be separated into chemical components or simpler compounds; instead, mixtures are separated into their constituent compounds through physical changes.
Whenever something changes physically but not chemically, we say that something has changed physically. This is in contrast to the idea of a chemical change, which occurs when a substance's composition changes or when one or more compounds join or fragment to generate new substances. In general, physical means can be employed to undo a physical alteration. For instance, by letting the water evaporate, salt that has been dissolved in it can be reclaimed.
Therefore, this concludes that option C is correct.
To know more about Physical change:
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Last stage of a medium mass star
White Dwarf Stage
This ring is called a planetary nebula. when the last of the helium atoms in the core are fused into carbon atoms, the medium size star begins to die. Gravity causes the last of the star's matter to collapse inward and compact. This is the white dwarf stage.Describe the Compton Effect
As you can see from the Group 1 stars, the cooler or hotter a star is, the brighter it will be. Group 2 and Group 3 stars do not follow this pattern. Hence, there must be something besides temperature that can affect how bright a star is. Describe your own hypothesis about these stars (Group 2 and Group 3). Why would their brightness not be strictly related to their temperature
Answer:
brightness that we observe from a star is related to the energy produced and the distance to the Earth
Explanation:
In stars, the color that we observe is directly related to the temperature of the star by the y of the Wien displacement.
λ_{max} T = 2,898 10³
the brightness that we observe from a star is related to the energy produced and the distance to the Earth
Instead of changing the the frequency you can change the tension to produce the next higher harmonic. What percentage of the tension would produce the next higher harmonic?
Answer:
[tex]\frac{T}{T_o} = ( 1 + \frac{1}{n} )^2[/tex]
Explanation:
This is a string resonance exercise, the wavelengths in a string held at the ends is
λ = 2L₀ / n
where n is an integer
the speed of the wave is
v = λ f
f = v /λ
the speed of the wave is given by the characteristics of the medium (string)
v = [tex]\sqrt{\frac{T}{\mu } }[/tex]
we substitute
f = [tex]\frac{n}{2L_o} \ \sqrt{\frac{T}{\mu } }[/tex]
to obtain the following harmonic we change n → n + 1
f’ = [tex]\frac{n+1}{2L_o} \ \sqrt{\frac{T_o}{\mu } }[/tex]
In this case, it tells us to change the tension to obtain the same frequency.
f ’= \frac{n}{2L_o} \ \sqrt{\frac{T}{\mu } }
how the two frequencies are equal
[tex]\frac{n+1}{2L_o} \sqrt{\frac{T_o}{ \mu } } = \frac{n}{2L_o} \sqrt{\frac{T}{\mu } }[/tex]
(n + 1) [tex]\sqrt{T_o}[/tex] = n [tex]\sqrt{T}[/tex]
[tex]\frac{T}{T_o} = ( \frac{n+1}{n} )^2[/tex]
[tex]\frac{T}{T_o} = ( 1 + \frac{1}{n} )^2[/tex]
this is the relationship of the voltages to obtain the following harmonic,
An oscillating LC circuit consisting of a 1.0 nF capacitor and a 3.0 mH coil has a maximum voltage of 3.0 V. What are (a) the maximum charge on the capacitor, (b) the maximum current through the circuit, and (c) the maximum energy stored in the magnetic field of the coil
Answer:
[tex]E=4.5*10^-^9J[/tex]
Explanation:
From the question we are told that:
Capacitor [tex]C=1.0nf[/tex]
Induction [tex]I=3.0mH[/tex]
Voltage [tex]V=3.0[/tex]
Generally the equation for Max charge on Capacitor is mathematically given by
[tex]Q_{max}=C*V[/tex]
[tex]Q_{max}=1*10^{-9}*3[/tex]
[tex]Q_{max}=3*10^{-9}C[/tex]
Generally the equation for Energy in magnetic field of the coil is mathematically given by
Since
Energy stored in capacitor = Energy in magnetic field of the coil
Therefore
[tex]E = (1/2)* C * V^2[/tex]
[tex]E= 0.5 * 1*10^{-9} *3^2[/tex]
[tex]E=4.5*10^-^9J[/tex]
You push on a box with a force of 300 N directly north. Another person pushes the box with a
force of 600 N directly east. What is the resultant force?
Answer:
[tex]resultant \\ \: F = \sqrt{ {300}^{2} + {600}^{2} } \\ = \sqrt{450000} \\ = 670.82 \: newtons[/tex]
Explain how you would have to change the experimental set-up (electric field strength, drift chamber length, and/or buf
Answer:
Please find the complete question in the attached file.
Explanation:
In this statement, the weak electromagnetic field that has been used when with the range of resistance to start measuring the mobility of even an ion with both the counter-charge utilization as well as the DC is the potential for using so that we can always obtain a desired electrical field and modify the drift chamber lengthy and gas pressures buffered.
PLEASE HELPPPPPPP!!!!!!!!!!
Answer:
F' = 800 N
Explanation:
The electrical force between charges is 400 N.
The electrical force between two charges is given by :
[tex]F=k\dfrac{q_1q_2}{r^2}[/tex]
If q₁' = 2q₁, new force becomes,
[tex]F'=k\dfrac{q_1'q_2'}{r^2}\\\\F'=k\dfrac{2q_1\times q_2}{r^2}\\\\F'=2\times F\\\\F'=2\times 400\\\\F'=800\ N[/tex]
So, the new force becomes 800 N.
What is the path of an electron moving perpendicular to a uniform magnetic field?
Explanation:
this is your answer I hope it is helpful please mark me brainly
Objects 1 and 2 attract each other with a electrostatic force
of 72.0 units. If the distance separating Objects 1 and 2 is
tripled, then the new electrostatic force will be _units.
Answer:
8 units
Explanation:
From the question given above, the following data were obtained:
Initial force (F₁) = 72 units
Initial distance apart (r₁) = r
Final distance apart (r₂) = tripled = 3r
Final force (F₂) =.?
The final force between the two objects can be obtained by using the following formula:
F₁r₁² = F₂r₂²
72 × r² = F₂ × (3r)²
72r² = F₂ × 9r²
Divide both side by 9r²
F₂ = 72r² / 9r²
F₂ = 8 units
Therefore, the final force between the two objects is 8 units
Question
1 point
An object of mass 8.0 kg is falling vertically through the air. The drag force acting on the object is 60N. What is the best estimate of the acceleration of
the object?
Answer:
here's the pdf for it
IB QuestionbankExplanation:
What is the speed of a car that traveled total of 75 km in 2 hours? *
Answer:
speed=distance covered/time taken
=75/2
=37.5 km/hr
Explanation:
average speed = distance move/ time taken
= 75km/2h
= 37.5km/h
Calculate the heat energy required to convert 4kg of ice at -25℃, to stem, at 100℃, given the specific heat capacity of water is 4200J/(kg℃), , the specific heat capacity of ice is 2100J/(kg℃), the specific latent heat of vaporization of water is 2300 000J/kg.
Answer:
1,840,000 J
Explanation:
The energy required for a particular change in state is given by the specific latent heat. Specific latent heat is the amount of energy required to change the state of 1 ... of ice into 1 kg of water at its melting point of 0°C. The same amount of energy ... stored or released as the temperature of a system changes can be calculated.
When using Fleming's Left Hand Rule to determine the direction of the force on an electron moving in a magnetic field, the velocity vector (V) is represented by the direction of your ___________.
thumb
index finger
middle finger
None of the above
Help pleaseeeeee!!! I really need it today :)
Answer:
i'd say 1kg-----5m-----5kg but im not to sure
Explanation:
Isotopes of the same element always have the same
(2 points)
O atomic mass number
O A-number
O Z-number
O neutrinos
Answer:
Z-number
Explanation:
The Z number is the number of protons in an atom, and this does not change when an isotope is created. I got it right on the test.
Question 5 of 10
Which of the following best describes a property of water?
O A. Dissolving very few substances
B. Remaining liquid over a narrow range of temperatures
C. Having low surface tension
D. Requiring a lot of energy to change temperature
Answer:
B
Explanation:
water do not have a solid shape and that makes it take to shape of a container etc
Answer:
D. Requiring a lot of energy to change temperature
Explanation:
because im right n ur wrong
What is the wavelength of a wave with a frequency of 262 Hz and a speed of
343 m/s
Answer:
time perion=1/frequency
so here time period =1/262
let wavelength be x
speed of sound=wave length/time period
342=x/1/262
342=262x
342/262=x
1.30=x
therefore wavelength=1.30 metre
Explanation:
one of the lady spartans was falling to the ground after dunking the winning basket. At the end of her fall, she was falling 4 m/s. If she was 60kg, how much potential energy did she have at the top of her jump?
Answer:
15 is the correct answer I.t.
The solid metallic sphere is replaced with a hollow insulating shell of radius a. A charge Q is spread uniformly over the hollow spherical shell. What is the electric field strength inside the hollow shell at r
Answer:
Zero
Explanation:
It is given that the charge is uniformly spread at the surface of hollow spherical shells.
There is no charge with in the hollo shell. hence, with zero charge the electric field intensity is also zero.
Thus,
Magnitude of the electric field strength inside the hollow shell at r is zero
Two identical particles each of mass M and charge Q are placed a certain distance apart. If they are in equilibrium
under mutual gravitational and electric force then calculate the order of Q/M in SI units.
Answer:
Q / m = 8.61 10⁻¹¹ C / kg
Explanation:
For this exercise we use the gravitational force of attraction
[tex]F_g = G \frac{m_1m_2}{r^2}[/tex]
the electric force
[tex]F_e = k \frac{q1q2}{r^2}[/tex]
indicate that the two forces are equal
G m₁ m₂ / r² = k q₁ q₂ / r²
they also say that the two masses are equal and the two charges are equal
G m² = k Q²
Q / m = [tex]\sqrt{\frac{G}{k} }[/tex]
we calculate
Q / m = [tex]\sqrt{\frac{6.67 \ 10^{-11} }{8.99 \ 10^9} }[/tex]
Q / m = [tex]\sqrt{ 0.7419 \ 10 ^{-20}}[/tex]
Q / m = 0.861 10⁻¹⁰
Q / m = 8.61 10⁻¹¹ C / kg
The number of proton is equal to the number of _____ in an atom
Answer:
THE NUMBER OF PROTON IS EQUAL TO THE NUMBER OF ATOMIC NUMBER(Z) IN AN ATOM
Explanation:
PLZ MARK ME BRAINLIEST
Answer:
Explanation:
The number of proton is equal to the number of electron in an atom.
Which of the following terms describes a process that absorbs 672 J from
the surroundings?
O A. Thermal conduction
B. Thermal insulation
C. Exothermic
D. Endothermic
Answer:
Endothermic
Explanation:
Took the test :^)
The endothermic process that absorbs 672 J from the surroundings.
What is endothermic process?In thermochemistry, an endothermic process is any process with an increase in the enthalpy H (or internal energy U) of the system.[1] In such a process, a closed system usually absorbs thermal energy from its surroundings, which is heat transfer into the system. It may be a chemical process, such as dissolving ammonium nitrate (NH4NO3) in water (H2O), or a physical process, such as the melting of ice cubes.
The term was coined by Marcellin Berthelot from the Greek roots endo-, derived from the word "endon" meaning "within", and the root "therm" , meaning "hot" or "warm" in the sense that a process depends on absorbing heat if it is to proceed. The opposite of an endothermic process is an exothermic process, one that releases or "gives out" energy, usually in the form of heat and sometimes as electrical energy. Thus in each term (endothermic and exothermic) the prefix refers to where heat (or electrical energy) goes as the process occurs.
So Endothermic reaction is where heat energy is high inside the substance and reduces the thermal energy outside the substance (outside the substance the temperature drops and the temperature increases inside the substance.)
Learn more about endothermic process
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For a galvanic cell to generate an electric current flowing from anode to cathode, what must be true
Complete question:
For a galvanic cell to generate an electric current flowing from anode to cathode, what must be true?
(a) Electrons flow from the anode to the cathode
(b) Electrons flow from the more negatively charged electrode to the more positively charged electrode
(c) Electrons flow from higher potential energy to lower potential energy
(d) All of the above are true.
Answer:
(d) All of the above are true.
Explanation:
A galvanic or Voltaic cell is a primary type of electrochemical cell that is used to generate electrical energy from the chemical reactions that take place in it.
It consists of a positive electrode (cathode) and a negative electrode (anode) for the movement of charges.
(a) Electrons flow from the anode to the cathode. TRUE
Anode is the negative electrode and for electron current, electrons flow from negative electrode to positive electrode.
(b) Electrons flow from the more negatively charged electrode to the more positively charged electrode. TRUE
Based on electron current flow.
(c) Electrons flow from higher potential energy to lower potential energy. TRUE
The driving force of the electron flow is the potential difference. Electrons must flow from higher potential to lower potential.
All the options are correct, so we select option "D"
An electric field has a positive test charge of 5.00 C placed in it. The force on the test charge is
6.000 N. The magnitude of the electric field at the location of the test charge is
o 30.0 NVC
0 1.20 N/C
0 120, NVC
O 3.00 N/C
01.02 N/C
Answer:
yes
Explanation:
this means the answer is yes
Jack drops a stone from rest off of the top of a bridge that is 21.0 m above the ground. After the stone falls 7.0 m, Jill throws a second stone straight down. Both rocks hit the water at the exact same time. What was the initial velocity of Jill's rock
Answer:
v = 19 m/s
Explanation:
Since both rocks hit the water at the same time, and we know the total height of the bridge, we can get the time that it takes to the first rock to travel this height, due it is said that it was dropped, using the following kinematic equation:[tex]\Delta h = \frac{1}{2} * g * t^{2} (1)[/tex]
Replacing by the givens (Δh =21 m and g = 9.8 m/s2), and solving for t we get:[tex]t = \sqrt{\frac{2*21m}{9.8m/s2}} = 2.1 s (2)[/tex]
Now we need the time traveled by the first rock when it fell 7 m, that when the second rock was thrown, because the difference between the total time and this one will be the flight time for the second rock.We can use the same equation (1) replacing Δh by 7 m, and solving for t, in (2) as follows:[tex]t = \sqrt{\frac{2*7m}{9.8m/s2}} = 1.2 s (3)[/tex]
So, the total flight time for the second rock it was just the difference between (2) and (3):[tex]t_{2} = t_{tot} - t_{1} = 2.1 s - 1.2 s = 0.9 s (4)[/tex]
Since we know the total distance traveled, and the time of flight, we can use the same kinematic equation than in (1) but now taking into account the initial speed for the second rock, as follows:[tex]\Delta h = v_{o}* t_{2} + \frac{1}{2}* g*t_{2} ^{2} (5)[/tex] Since we know the value of Δh = 21 m and t₂ =0.9s, replacing in (5) and solving for v₀, we get:[tex]v_{o} =\frac{(\Delta h -\frac{1}{2}*g*t^{2})}{t_{2} } = \frac{(21m-(\frac{1}{2}*9.8m/s2*(0.9s)^{2}) ) }{(0.9m)} = 19.0 m/s (6)[/tex]
which was the initial velocity of Jill's rock taking as positive the down ward direction.