A 100 kg disc with radius 1.6 m is spinning horizontally at 25 rad/s. You place a 20 kg brick quickly and gently on the disc so that it sticks to the edge of the disc. Determine the final angular speed of the disc-brick system.

Answers

Answer 1

Answer:

20.83rad/s

Explanation:

Using the law of conservation of momentum

m1u1+m2u2 = (m1+m2)v

m1 and m2 are the mass of the disc and Brick respectively

u1 and u2 are the linear velocities respectively

v is their final velocity of the block-disc system

Given

m1 = 100kg

m2 = 20kg

u1 = wr =25×1.6

u1 = 40m/s

u2 = 0m/s (brick is stationary)

Substitute and the final linear velocity v

100(40)+20(0) = (100+20)v

4000 = 120v

v = 4000/120

v = 33.3m/s

From the formula;

v = wr

w = v/r

w= 33.3/1.6

w = 20.83rad/s.

Hence the final angular speed of the disc-brick system is 20.83rad/s


Related Questions

2.9030 has 4 significant digits.
TRUE OR FALSE

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Your answer should be True

I need helpppppppppppppppppppppppppppppppppppppppppppppp

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Answer:u

Laa             c

Explanation:

The diagram below represents an electromagnetic wave. Please Help

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Answer:

I'm pretty sure it's A

Explanation:

bc the crest is is the point on the wave

The table represents the speed of a car in a northern direction over several seconds. Column 1 would be on the x-axis, and Column 2 would be on the y-axis. Which best lists the titles of each column? Column 1 0 2. 4 6 8 10 Column 2 5 10 15 20 25 30 O Column 1 should be titled "Time," and Column 2 should be titled "Velocity." O Column 1 should be titled "Velocity," and Column 2 should be titled "Time." O Column 1 should be titled "Time," and Column 2 should be titled "Acceleration." O Column 1 should be titled "Acceleration," and Column 2 should be titled "Time."​

Answers

Answer is A hope this helps luv

Answer:

Column 1 should be titled “Time,” and Column 2 should be titled “Velocity.”

Explanation:

Why is friction like applied force but different from gravity?

Answers

Answer:

Friction is when a force is applied or done by weight dragging onto something.

Explanation:

Gravity is when an object is getting pulled toward the center of what is attracting it. And applied force is when someone/sommething is applying force.

unlike friction, gravity relies on a natural source. Gravity happens naturally, but friction happens when a force that opposes motion between any surfaces that are touching.

A shot-putter exerts an unbalanced force of 128 N on a shot giving it an acceleration of 19
m/s2. What is the mass of the shot?

Answers

Answer:

128 is the ans cuz N is also lnown as mass

Explanation:

128


4. State in words how acceleration is calculated.

Answers

You multiply force times friction

Acceleration can be calculated by dividing the change in velocity by the change in time. If we have a mass and force that makes the acceleration, the divide the force by mass to get the acceleration.

What is acceleration ?

Acceleration is a physical quantity which describes the rate of change in velocity. Like velocity, acceleration is a vector quantity having both magnitude and direction.

If both speed and direction are changing and  if we want to know the acceleration at any particular moment in time, calculating acceleration can be challenging.

However, since just speed is changing, it is quite simple to determine average acceleration over time. After then, acceleration is equal to the time change divided by the velocity change.

a = ΔV/Δt

Similarly if have the force which accelerates a body of mass m, then the acceleration is the ratio of that force to the mass.

a = F/m

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PLZ HELP!!!!!!! ILL GIVE U BRAINLIEST

Answers

Answer:

Claim: Heart Rate for Sarah and Matt (this would be the homeostasis AT REST and throughout the graph time)

Evidence: The Graph and the HR/S and its evidence towards the heart rate/beats every 15 seconds, due to the homeostasis being a specific time limit and due to the specific heart rate of Matt and Sarah ONLY.

Explanation: A/B Checkpoint throughout the homeostasis (this would be heart rate/trial throughout the time of the graph)

Conclusion: Matt was further away ONLY BECAUSE Sarah has a higher Heart Rate during the time on the graph, which can represent how long they did something to increase/decrease from and where the homeostasis would be located.

Answer:

Claim: Heart Rate for Sarah and Matt (this would be the homeostasis AT REST and throughout the graph time)

Evidence: The Graph and the HR/S and its evidence towards the heart rate/beats every 15 seconds, due to the homeostasis being a specific time limit and due to the specific heart rate of Matt and Sarah ONLY.

Explanation: A/B Checkpoint throughout the homeostasis (this would be heart rate/trial throughout the time of the graph)

Conclusion: Matt was further away ONLY BECAUSE Sarah has a higher Heart Rate during the time on the graph, which can represent how long they did something to increase/decrease from and where the homeostasis would be located.

15)
The Celsius temperature equal to 86° Fahrenheit is:
T(F) = 9/5T(C) + 32
T(C) = 5/9 ( T(F) - 32)

A)
16°C
B)
30°C
C)
212°C
D)
190°C

Answers

Answer:

letter b

Explanation:

30 degrees Celsius equals 86 degrees Fahrenheit add me plesse mark brainiest

A microwave oven operates at 2.00 GHz . What is the wavelength of the radiation produced by this appliance?

Answers

Answer:

Wavelength = 0.15 m

Explanation:

The frequency of a microwave oven is 2.00 GHz or [tex]2\times 10^9\ Hz[/tex].

We need to find the wavelength of the radiation produced by this appliance. We know that the relationship between the frequency and wavelength is given by :

[tex]c=f\lambda[/tex]

Where,

[tex]\lambda[/tex] is the wavelength

So,

[tex]\lambda=\dfrac{c}{f}\\\\\lambda=\dfrac{3\times 10^8}{2\times 10^9}\\\\=0.15\ m[/tex]

So, the wavelength of the radiation produced by this appliance is 0.15 m.

Social science is a branch of science that deals with the nature of
A. human society
B. the physical world
C. animal societies
D. the medical field

Answers

The answer is A. Human Society.

Answer:

A. human society

Explanation:

what is the acceleration of a cat who starts from rest and moves 11.5 m in 2.8 s?​

Answers

Answer:

The acceleration is 4

Explanation:

use the formula v= change in position/change in time for vecter quantity's which will be in word problems that say acceleration or velocity.

Which statement is true of the electric field at a distance from the source charge?
A it is independent of the source charge
B It is directly proportional to the source charge
C it is inversely proportional to the source charge
D it is directly proportional to the distance

Answers

Answer:

It is directly proportional to the source charge.

Explanation:

I found it pretty sure it's right hit me up on my insta

desiignerjoe173


A 0.6 kg basketball moving 7.2 m/s to the right collides with a 0.04 kg tennis
ball moving 22 m/s to the left. After the collision, the tennis ball is moving
32.7 m/s to the right. What is the velocity of the basketball after the collision?
Assume an elastic collision occurred.
A. 10.9 m/s to the right
B. 10.9 m/s to the left
C.3.6 m/s to the left
D. 3.6 m/s to the right

Answers

Answer:b

Explanation:

The final velocity of the basketball after it undergoes collision with the tennis ball is 6.49m/s.

What is Final velocity?

The final velocity is a vector quantity which measures the speed and direction of a moving object after it has reached its maximum acceleration and distance.

Given data,

mass of basket ball (m₁) = 0.6kg

mass of tennis ball (m₂) = 0.04kg

velocity of basket ball (v₁) = 7.2m/s

velocity of  tennis ball (v₂) = 22m/s

velocity of basket ball (v₃) =?

velocity of  tennis ball (v₄) = 32.7m/s

We already know that the expression for elastic collision is given as

m₁v₁ +m₂v₂ = m₁v₃ + m₂v₄

Substituting these values, we get

0.6 × 7.2 + 0.04 × 22 = 0.6 × x + 0.04 × 32.7

4.32 + 0.88 = 0.6x + 1.308

Solving for x we have,

3.892 = 0.6x

x = 3.892 /0.6

x=6.49m/s

Therefore, the velocity of the basketball after the collision is 6.49m/s.

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Can someone please help me

Answers

Answer:

grams= 4.8e-5

kilograms= 4.8e-8

centigrams= 0.0048

dekagrams= 4.8e-6

Explanation:

What is the acceleration along the ground of a 18 kg wagon when it is pulled with a force of 91 N at an angle of 35° Above the horizontal?

Answers

Answer:

4.1 m/s²

Explanation:

Net force in the x direction equals the mass times the acceleration.

∑F = ma

91 cos 35° = (18 kg) a

a = 4.1 m/s²

Answer:

Explanation:

bbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbb

Are these bones axial, appendicular
or both?

Answers

Answer:

Axial and Appendicular Skeletons The axial skeleton forms the central axis of the body and consists of the skull, vertebral column, and thoracic cage. The appendicular skeleton consists of the pectoral and pelvic girdles, the limb bones, and the bones of the hands and feet. Figure 6.41.

Explanation:

Part D
Which two kinds of energy are associated with flames?

Answers

Answer:

Thermal energy and electrical energy

Explanation:

Answer:

Hello!!! Princess Sakura here ^^

Explanation:

The two kinds of energy are thermal and electrical.

Atoms tend to be stable and nonreactive if they have six valence electrons.
Select one:
O True
O False

Answers

Answer:

True

Explanation:

Which of the following would be useful to show the growth rate of plants at varying temperatures?


bar graph


circle graph


line graph


frequency table

Answers

Answer:

line graph

Explanation:

Ik im late but i hope this helps lol

Calculate the magnetic field at the center of a circular current loop of radius R divided by the magnetic field at a distance R away from a very long straight wire carrying the same current value I. (Note the loop and wire are not in electrical contact.)

Answers

Answer:

The magnetic field at the center of a circular current loop of radius R divided by the magnetic field at a distance R away from a very long straight wire carrying the same current value I is [tex]\pi[/tex] or 3.14

Explanation:

The magnetic field at center of a circular loop is given by

[tex]B = \frac{\mu _{o}I }{2R}[/tex]

Where B is the magnetic field

[tex]\mu _{o}[/tex] is the free space permeability constant ( [tex]\mu _{o}[/tex] = 4π × 10⁻⁷ N/A²)

[tex]I[/tex] is the current

and [tex]R[/tex] is the radius

For the magnetic field of a long straight wire, it is given by

[tex]B = \frac{\mu _{o}I }{2\pi R}[/tex]

Where B is the magnetic field

[tex]\mu _{o}[/tex] is the free space permeability constant ( [tex]\mu _{o}[/tex] = 4π × 10⁻⁷ N/A²)

[tex]I[/tex] is the current

and [tex]R[/tex] is the distance from the wire

Then, to calculate the magnetic field at the center of a circular current loop of radius R divided by the magnetic field at a distance R away from a very long straight wire carrying the same current value I, that will be

[tex]\frac{\mu _{o}I }{2R} \div \frac{\mu _{o}I }{2\pi R}[/tex]

= [tex]\frac{\mu _{o}I }{2R} \times \frac{2\pi R }{\mu _{o}I}[/tex]

= [tex]\pi[/tex]

(NOTE: [tex]\pi[/tex] = 3.14)

Hence, the magnetic field at the center of a circular current loop of radius R divided by the magnetic field at a distance R away from a very long straight wire carrying the same current value I is [tex]\pi[/tex] or 3.14.

A force of 50n is applied to an object at an angle of 50 degrees measured relative to the horizontal. Determine the horizontal and vertical components of the applied force?

Answers

Answer:

Fx = 32.14 [N]

Fy  = 38.3 [N]

Explanation:

To solve this problem we must decompose the force vector, for this we will use the angle of 50 degrees measured from the horizontal component.

F = 50 [N]

Fx = 50*cos(50) = 32.14 [N]

Fy = 50*sin(50) = 38.3 [N]

We can verify this result using the Pythagorean theorem.

[tex]F = \sqrt{(32.14)^{2}+ (38.3)^{2}} \\F = 50 [N][/tex]

What is the takeoff distance for an airplane on a runway at
300km/hr with acceleration of 1 m/s 2

Answers

Answer:

x = 3472 [m]

Explanation:

To solve this problem we must use the following expression of kinematics:

[tex]v_{f}^{2}= v_{i}^{2}+(2*a*x)\\[/tex]

where:

Vi = initial velocity = 0

Vf = final velocity = 300 [km/h]

a = acceleration = 1 [m/s^2]

x = takeoff distance [m]

Note: The initial velocity is equal to zero as avion starts its movement from rest.

Now we have to convert units of kilometers per hour to meters per second, the final velocity.

[tex]300 [\frac{km}{h}]*[\frac{1h}{3600s} ]*\frac{1000m}{1km} \\= 83.33 [\frac{m}{s} ][/tex]

(83.33)^2 = 0 + (2*1*x)

2*x = 6943.88

x = 3472 [m]

1) Which of the following is considered an effective treatment for someone with hearing loss based on nerve damage?

TAD
Cochlear implant
Hearing aid
OBI
No treatment available


2) Sylvester is dealing with hearing loss. The doctor informs him that his basilar membrane is damaged. What type of hearing loss is Sylvester experiencing?

Nerve deafness
Conduction hearing loss
Cochlear hearing loss
Conduction deafness
Sensory hearing loss

Answers

Answer:

For number 1 no treatment available , number 2 cochlear hearing loss

Explanation:

nerve damage is permanent

answer
prove that p = d g h

Answers

Answer:

Proving LHS=RHS

Explanation:

Given

p=dgh

Multiplying by 0 on both sides of the equations

p×0=dgh×0

0=0

:- Hence proved

When light waves hit ice, most of them bounce off and radiate back into space. Because of this, ice is best described as which kind of surface?

Answers

Answer:

Reflective surface

Explanation:

Ice is a reflective surface because most the of the light waves that hits on it bounces off.

When a surface is smooth and polish, it acts a reflector. When a surface is jagged and not smooth light does not readily reflect. Reflection is through the incident angle of the light waves.

Therefore, snow is a reflective surface.

electromagnetic waves and sound waves can have the same frequency. what is the wavelength of a 1.00kHz electromagnetic wave

Answers

Wavelength = 300 000 000 / 1000 = 300 000 m

What is the final velocity of a running back that is moving with an initial velocity of 2 m/s and accelerates at a rate of 4 m/s$$ in 5 seconds as he moves toward the defensive line?

Answers

Answer:

Final velocity = 22

Explanation:

22-2/5= 4

20/5=4

so add to so it is not 18/5

Then you get your answer.

Answer:

4. A sound wave moves towards a building at 5 m/s for 22 seconds.

Explanation:

1.What is the mass of an object that weighs 98 N?​

Answers

Answer:

10 kg

Explanation:

Answer: 10kg




10 kg newton

As part of a carnival game, a 5.00 kg target is freely hanging from a very long and very light wire. Contestants can use one of two 1.5 kg balls to try to hit the target and deflect it high enough to win a prize. Ball A will have an elastic collision and bounce back toward you while ball B will have a nearly perfectly inelastic collision, but rather than sticking to the target, the ball will just drop straight downward to the ground after the collision. You can throw each ball with a velocity of 12 m/s. You are the first to try the game and which ball should you throw? Calculate the expected height the target will reach after each is thrown.

Answers

Answer:

Height ball A will deflect the target is 2.65 m

Height ball A will deflectthe target is 2.2 m

Ball A, will deflect the target to greater height, thus i will throw ball A

Explanation:

Given;

mass of the target, m₁ = 5.00 kg

mass of the ball, m₂ = 1.5 kg

initial velocity of each throw, u = 12 m/s

Throwing ball A; apply the principle of conservation linear momentum for elastic collision;

m₁u₁ + m₂u₂ = v₁m₁ + v₂m₂

The initial velocity of the target, u₁ = 0

The ball bounced back at the same speed, v₂ = -12 m/s

the velocity of the target after collision, = v₁

0 + 1.5 x 12 = v₁(5) + (-12 x 1.5)

18 = 5v₁ - 18

18 + 18 = 5v₁

36 = 5v₁

v₁ = 36/5

v₁ = 7.2 m/s

The vertical height reached by the target is given by;

v₁² = u₁² + 2gh

v₁² = 0 + 2gh

v₁² = 2gh

h = v₁² / 2g

h = (7.2)² / (2 x 9.8)

h = 2.65 m

Throwing ball B; apply the principle of conservation energy for the inelastic collision;

the kinetic energy of the ball will be converted to the potential energy of the target.

¹/₂m₁u₂² = mgh

¹/₂(1.5)(12)² = (5 x 9.8)h

108 = 49h

h = 108 / 49

h = 2.2 m

Ball A will deflect  the target to greater height, thus i will throw ball A.

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