Answer:
i. 3600 rpm ii. 377 rad/s
Explanation:
(a) What is the mechanical synchronous speed in rad/sec and in rpm
i. The mechanical synchronous speed in rpm
The mechanical synchronous speed in rpm, N = 120f/P where f = frequency = 60 Hz and P = number of poles = 2
So, N = 120f/P = 120 × 60 Hz/2 = 60 × 60 = 3600 rpm
ii. The mechanical synchronous speed in rad/s
We now convert N to rad/s by multiplying by 2π/60
So, the mechanical synchronous speed in rad/s , N' = 3600 rpm × 2π/60 = 60 × 2π = 120π rad/s = 377 rad/s
On a TXV system, the temperature sensing bulb is located at the
A condenser outlet
B evaporator outlet
C condenser inlet
D evaporator inlet
Answer:
Explanation:
B evaporator outlet: on the suction line between the evaporator and the compressor
A process fluid having a specific heat of 3500 J/kg-K and flowing at 2 kg/s is to be cooled from 80 C to 50 C with chilled water, which is supplied at a temperature of 15 C and a flow rate of 2.5 kg/s. Assuming an overall heat transfer coefficient of 2000 W/m2-K, calculate the required heat transfer areas for the following exchanger configurations: (a) parallel flow (15 pts), and (b) counterflow (15 pts).
Answer:
to claim your answer $2 Approach www.gotit-pro.com
Explanation:
The St. Francis Dam was original designed at a height of 175 ft. However, during the construction phase, the height of the dam was increased by 10 ft to 185 ft to provide the additional reservoir storage capacity. What would be the increase in the overturning moment (lb-ft/ft) about the toe (point O) of the dam caused by the water pressure due to height increase
This question is incomplete, the missing diagram is uploaded along this answer below;
Answer:
the increase in the overturning moment is 10.1 × 10⁶ lb.ft/ft
Option c) 10.1 × 10⁶ lb.ft/ft id the correct answer
Explanation:
Given the data in the question and illustrated in the image below;
Hydrostatic force on Dam ( per unit length )
P = [tex]\frac{1}{2}[/tex] rH.H = [tex]\frac{1}{2}[/tex]rH² lb/ft
Now, Overturning moment;
M = R × P = H/3 × [tex]\frac{1}{2}[/tex]rH² = [tex]\frac{1}{6}[/tex]rH³ lb.ft/ft
so when H = 175 ft
M₁ = [tex]\frac{1}{6}[/tex]r × ( 175 )³ = [tex]\frac{1}{6}[/tex] × 62.4 × ( 175 )³
M₁ = 55737500
Also, When H = 185 ft
M₂ = [tex]\frac{1}{6}[/tex]r × ( 185 )³ = [tex]\frac{1}{6}[/tex] × 62.4 × ( 185 )³
M₂ = 65848900
∴ Increase in overturning moment will be;
⇒ M₂ - M₁ = 65848900 - 55737500
⇒ 10111400 ≈ 10.1 × 10⁶ lb.ft/ft
Therefore, the increase in the overturning moment is 10.1 × 10⁶ lb.ft/ft
Option c) 10.1 × 10⁶ lb.ft/ft id the correct answer
Techm digital definition comprises of
Answer:
Below is the response to the given question:
Explanation:
The relevant services supplied through TechMahindra Digital Services Provider are among the different options given in n inquiry. This is a digital company that has offered its customers an end-to-end solution that digitalizes all the requirements for client operations. It offers digital solutions, services cloud-based, digital marketing strategies, and then all client needs.
Three district robots are being used today
The website of a bank that an organization does business with has been reported as untrusted by the organization's web browser. Its security analyst has been assigned to investigate. The analyst discovers the bank recently merged with another local Bank in Combined Names. Additionally, the user's bookmark automatically redirects to the website of the newly-named bank. Which of the following is the most likely cause of this issue?
a) The company's web browser is not up to date
b) The website certificate still has the old bank’s name
c) The website was created to recently to be trusted
d) the website certificate has expired
Answer:
B. The website's certificate still has the old bank's name
Explanation:
MRK ME BRAINLIEST PLZZZZZZZ
The company PureNSafe is designing a portable, solar-powered disinfection system for Army use only. The system is simply an inlet pipe, a pump, a mixing chamber and an outlet pipe. The water is continuously pumped into the chamber where it is irradiated with UV light before it exits through the the appropriate tube into a collection vessel. The disinfection rate constant rate of disinfection with UV light is 7.80 s.1 and the amount of bacteria has to be reduced by 99.9%. be reduced by 99.9%. Since the Army requires an object that can be carried in a backpack, it requires that the chamber of the apparatus must not hold a capacity greater than 2 L. How much water will the system be able to produce during 10 hours of sunshine?
Solution :
The treatment system will operate as the well mixed chamber.
Disinfection rate constant for the UV light, k is 7.80 /s. Number of bacteria in water need to be reduced by 99.9%
Percent reduction of bacteria should be [tex]$(1-10^{0.99}) \times 100 =89.7\%$[/tex]
Volume of the unit chamber is fixed at 2L
Assume the inlet concentration, [tex]$C_0$[/tex] as 1000
The outlet concentration of bacteria, C should be [tex]$1000-\left(1000 \times \frac{89.7}{100}\right)$[/tex]
= 103
The well mixed chamber will then follow a completely mixed flow reactor model.
Compute the time required :
[tex]$t=\frac{1}{k}\left(\frac{C_0}{C}-1\right)$[/tex]
[tex]$t=\frac{1}{7.8}\left(\frac{1000}{103}-1\right)$[/tex]
= 1.115 s
Flow through the system is [tex]$\frac{2 \ L}{1.115 \ s}$[/tex] = 1.79 L/s
The amount of water treated during the 10 hours of sunlight is 1.79 x 10 x 60 x 60 = 64440 L
are trains cool because if they are then my dad didn't beat me
Answer:
I think trains are pretty awesome. There's a train in japan that levitates slightly and runs on magnetism. Pretty amazing. It's super fast too
Limestone scrubbing is used to remove SO2 in a flue gas desulfurization (FGD) system. Relevant reactions are given below. A limestone mix is used that consists of 94% CaCO3 and 6% inert material. The actual feed rate of the limestone mix is 36,000 lb/hr. The SO2 in the flue gas is 20,314 lb/hr and the FGD efficiency is 97%. If the resulting sludge has 58% solids, determine the total sludge production rate (lb/hr). Round your answer to the nearest whole number.
Answer:
hello some data related to your question is missing attached below is the missing data
answer : 63700 Ib/hr
Explanation:
Given data :
Limestone mix : consists of 94% CaCO3 and 6% inert material
Actual feed rate = 36,000 Ib/hr
SO2 in flue gas = 20,314 Ib/hr
FGD efficiency = 97%
resulting sludge contains 58% solids
Calculate the Total sludge production rate
First : determine SO2 removed in sludge
= 0.97 * 20314
= 19704.58 Ib/hr
next : moles of SO2 removed
= 19704.58 / 64 Ib/ Ib mol
= 307.88 Ib mol / hr
also moles of CaSO3 produced = 307.88 Ib mol / hr
mass of CaSO3 = 307.88 * 120 = 36946.09 Ib/hr
Therefore Total sludge production rate
= 36946.09 / 0.58
= 63700.15 Ib/hr
5. According to the FMCSRs, you are qualified to operate a CMV if you:
A. are at least 15-years old.
B. have passed an IQ test.
C. have only one current CDL.
D. are currently disqualified from operating a motor vehicle.
Answer:
currently states that a person is qualified to drive a commercial motor vehicle if he/she “can read and speak the English language sufficiently to converse with the general public, to understand highway traffic signs and signals
So I think B
it is the tool used to measure the amount of electric current
Answer:
Ammeter
Explanation:
Instrument for measuring either direct or alternating electric current, in amperes. Ammeters vary in their operating principles and accuracies
Answer:
ammeter is used to measure electric current.
Air entrainment is used in concrete to: __________.
1. Strengthen the concrete
2. Increase the resistance of the concrete to freeze thaw damage
3. Create a better surface appearance
4. Make the concrete easier to handle during placement
5. Help evaporate excess water from the curing concrete
The answer is number 2) Increase the resistance of the concrete to freeze-thaw damage.
Air entrainment is used in concrete to Increase the resistance of the concrete to freeze thaw damage.
What is air entrainment?Microscopic air bubbles embedded in the concrete's surface reduce internal pressure by creating little spaces for water to expand into during freeze-thaw cycles.
Without these pockets, water has nowhere to escape, which causes concrete to crack and/or scale, severely reducing the lifespan of a structure. An air entraining additive, or AEA, is used to add air to the concrete mix.
To fit the requirements of the task at hand, a mix's air content can be changed. When pouring concrete in locations that experience freeze-thaw conditions, using air-entrained concrete is advantageous.
Therefore, Air entrainment is used in concrete to Increase the resistance of the concrete to freeze thaw damage.
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The following dataset contains eight items representing colored points on the x-y plane:
х y color
1 1 red
1 3 green
2 5 blue
3 5 green
4 1 blue
4 4 red
5 3 blue
5 4 green
Using this data as the training set, run the k-nearest-neighbors classification algorithm (k=1) using square distance and choose the color for a new item with x = 3 and y = 3.
Solution :
According to the question, the following datasheet contains eight items representing the colored points o the x-y plane.
We have to use this data as training set to run the k-nearest classification algorithm to decide most likely color for a new item with x = 3 and y = 3.
The distance between the points is actual distance on x-y plane, called as Eucledian distance.
We will make a data table, by calculating distance from (3, 3) of each point. By using formula :
Distance, [tex]$d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$[/tex]
x y Color Distance from point (3, 3)
1 1 Red [tex]$\sqrt{(3-1)^2+(3-1)^2} = 2.82$[/tex]
1 3 Green [tex]$\sqrt{(3-1)^2+(3-3)^2} = 2$[/tex]
2 5 Blue [tex]$\sqrt{(3-2)^2+(3-5)^2} = 2.23$[/tex]
3 5 Green [tex]$\sqrt{(3-3)^2+(3-5)^2} = 2$[/tex]
4 1 Blue [tex]$\sqrt{(3-4)^2+(3-1)^2} = 2.23$[/tex]
4 4 Red [tex]$\sqrt{(3-4)^2+(3-4)^2} = 1.41$[/tex]
5 3 Blue [tex]$\sqrt{(3-5)^2+(3-3)^2} = 2$[/tex]
5 4 Green [tex]$\sqrt{(3-5)^2+(3-4)^2} = 2.23$[/tex]
Now, we will do sorting of colors with distance in ascending order.
We get, [ Red, Green, Green, Blue, Blue, Blue, Green, Red]
Now if we run the algorithm with k = 1, then we pick only 1 color having the shortest distance that will be assigned to the given point.
Therefore the color is RED.
If we run the algorithm with k = 4, we will pick up [tex]$4 \text{ colors}$[/tex] with shortest distance which are [tex]$\text{red, green, green, blue}$[/tex]. Since, now we know, Green has the greatest frequency among 4, hence the answer is Green.
a transformer is built with 200 primary turns and 50 secondary turns. Whats the transformers turn rate? A) 1:4 B) 2:1 C) 1:2 D) 4:1
Answer:
[tex]4:1[/tex]
Explanation:
[tex]N_p[/tex] = Number of turns of primary coil = 200
[tex]N_s[/tex] = Number of turns of secondary coil = 50
The transformer turn ratio is given by
[tex]\dfrac{N_p}{N_s}=\dfrac{200}{50}[/tex]
[tex]\Rightarrow \dfrac{N_p}{N_s}=\dfrac{4}{1}[/tex]
[tex]\Rightarrow \dfrac{N_p}{N_s}=4:1[/tex]
The transformer turn ratio is [tex]4:1[/tex].
Oleg is using a multimeter to test the circuit branch you just installed. After turning off the current to the circuit at the service panel , hell first attach one pole to the ______________ at the end of the run? A) WHITE WIRE B) BOX C) BLACK WIRES) GROUND WIRE
Answer:
Option D, Ground Wire
Explanation:
Oleg is a mustimeter or multi tester or a basic voltage tester which is used to test the ground. The main purpose of the tester is to ensure that the outlet is connected to the ground of the circuit, thereby ensuring its proper functioning.
Hence, option D is correct
In this worksheet, we will use the drag equations to calculate drag force. Assume the following:
1 liter bottle with radius = 40 mm.
The drag coefficient is 0.299 for the 150 mm long nose cone.
Velocity is 30 m/s.
Answer:
Explanation:
plz provide the density
w/ density, the drag force can be calculated:
drag force = drag coefficient * cross-section area * .5 * density * Velocity^2
where drag coefficient is given as 0.299,
cross-section area = 3.14*0.04^2
Velocity given as 30
Answer:
Explanation:
Drag force is given by the equation: 1/2 * drag coefficient * density * area * velocity^2.
So drag force = 1/2 * 0.299 * density * 3.14 * (40/1000)^2 * 30^2
in this image if the ground were removed from the neutral wire what would the voltage to ground be?
Answer:
240
Explanation:
Which of the following can effect LRO?
Answer:
The lunar radiation environment, allowing scientists to determine potential impacts to astronauts and other life. It also will test models on the effects of radiation and measure radiation absorption by a type of plastic that is like human tissue. The results could aid in the development of protective technologies to help keep future lunar crew members safe. CRaTER was built and developed by Boston University and the Massachusetts Institute of Technology in Boston.
A flow of 2.6 MGD leaves a primary clarifier with a BOD of 131 mg/L. Determine the aeration period (hydraulic detention time) of an activated sludge tank that has a BOD loading of 35 lbsper 1000 ft3per day. Determine the sludge age of the facility given the following data: VSS concentration is 2100 mg/L, and the mass rate of wasted sludge is equal to 44 percent of the BOD loading.
Answer:
8.5 days
Explanation:
Given data :
Flow ( Q ) = 2.6 MGD = 11819.834 m^3/day
BOD = 131 mg/L
BOD loading rate = 35 Ibs/1000 ft^3 per day = 0.5606 kg/m^3/day
Calculate the sludge age of the facility
Given the BOD applied to the aeration tank = 11819.834 m^3/day * 131mg/l
= 1548.398 kg/day
first calculate the volume of the aeration tank
V = BOD applied / BOD loading rate
V = 1548.398 / 0.5606 = 2762.03 m^3
Hydraulic Detention time = V / Q
= 2762.03 / 11819.834 = 0.2336 day = 5.6 hour
next : determine the mass rate of the waste
= 44% * 0.5606 kg/m^3/day
= 0.2466 kg/m^2/day
finally determine the sludge age
= V * Xt / ∅w * R
= ( 2762.03 m^3 * 2100 * 10^-3 ) / ( 0.2466 * 2762.03 kg/day )
= 8.5 days
Compare and contrast the three USDA quality grades available to consumers and describe how the grades affect labeling.
Answer:
USDA has developed strict measures of quality for products such as grains, rice, corn, and beans. Quality grading is based on the standards developed for each product. Quality grades provide a common language among buyers and sellers, which in turn assures consistent quality for consumers.
Explanation:
Calculate the velocity of a motor cyclist who travelled a distance of 200 min
10 seconds.
Answer: The velocity of a motor cyclist who travelled a distance of 200 m in 10 seconds is 20 m/sec.
Explanation:
Given: Distance = 200 m
Time = 10 seconds
Formula used to calculate velocity is as follows.
[tex]Velocity = \frac{Distance}{Time}[/tex]
Substitute the value into above formula as follows.
[tex]Velocity = \frac{Distance}{Time}\\= \frac{200 m}{10 sec}\\= 20 m/sec[/tex]
Thus, we can conclude that the velocity of a motor cyclist who travelled a distance of 200 m in 10 seconds is 20 m/sec.
Student A says that wires on a screw-type terminal connection should be installed as shown in Figure A - 5 . Student 8 says that wire nut connections are a type of soldere connection. Which of the following statements is correct?
Answer:
Student A
Explanation:
There is no reason to solder a wire nut connection because the nut already makes a mechanical connection.
A short reinforced concrete column is subjected to a 750 kips axial compressive load. The Moduli of elasticity of plain concrete and steel are 5.5 and 30 million psi, respectively. The cross-sectional area of the steel is 1.8% of the reinforced concrete. Considering the column is made of composite material and subjected to a load parallel to the steel rebars, calculate the following:
a. the modulus of elasticity of the reinforced concrete.
b. the load carried by each of the steel and plain concrete.
c. the minimum required cross-sectional area of the column, given that the allowable compressive stress of the plain concrete is 5,500 psi and that the allowable compressive stress of plain concrete will be reached before that of steel.
Answer:
a) 5.94* 10^6 psi
b) Pc = 683.06 kips ( load carried by concrete )
Ps = 0.098 * 683 .06 = 66.94 kips ( load carried by steel )
c) 126.47 In^2
Explanation:
A)
Er = Ec * Ac + Es *As ------- ( 1 )
where : As ( cross sectional area of steel )= 1.8% = 0.018
Ac = 1 - 0.018 = 0.982
back to equation 1
modulus of elasticity = ( 5.5 * 10^6 * 0.982 ) + ( 30 * 10^6 * 0.018 )
= 5.94* 10^6 psi
B)
Ps = 0.098 Pc
Given that : Ps + Pc = 750 kips
0.098 Pc + pc = 750 kips
therefore ; Pc = 750 kips / 1.098
Pc = 683.06 kips ( load carried by concrete )
Ps = 0.098 * 683 .06 = 66.94 kips ( load carried by steel )
c) Determine the minimum required cross-sectional area of the column (Ag)
given that allowable compressive force ( Pac ) = 5500 psi
Ac = 0.982 * Ag
Pc = Pac * Ac
683.06 = 5500 * 0.982 * Ag
∴ Ag = 126.47 In^2
A two-position mode controller is used to control the water level in a tank by opening or closing a valve which in the open position allows water at the rate of 0.4 m3 / s to enter the tank. The tank has a cross-sectional area of 12 m2 and water leaves it at the constant rate of 0.2 m3 / s. The valve opens when the water level reaches 4.0 m and closes at 4.4 m. What will be the times taken for (a) the valve opening to closing, (b) the valve closing to opening
Answer:
The right solution is:
(a) 24 sec
(b) 24 sec
Explanation:
The given values are:
Water inlet's flow rate,
= 0.4 m³/s
Water outlet's flow rate,
= 0.2 m³/s
(a)
The volume of water filled will be:
= [tex]Area(height)[/tex]
= [tex]12(4.4-4)[/tex]
= [tex]12\times 0.4[/tex]
= [tex]4.8 \ m^3[/tex]
Opening to closing time taken will be:
= [tex]\frac{4.8}{0.2}[/tex]
= [tex]24 \ sec[/tex]
(b)
Inlet's flow rate,
= 0
Outlet's flow rate will be:
= 0.2 m³/s
Closing to opening time taken will be:
= [tex]\frac{4.8}{0.2}[/tex]
= [tex]24 \ sec[/tex]
a. The time taken for the valve opening to closing is 24 seconds.
b. The time taken for the valve closing to opening is 24 seconds.
Calculation of the time taken:a.
First we need to determine the volume of the water
= Area * height
= 12*(4.4-4)
= 12*0.4
= 4.8
Now the time taken should be
= 4.8/0.2
= 24 seconds.
b. The time taken should be
= 4.8/0.2
= 2.4 seconds
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Engineers study the properties of fluids, including viscosity and compressibility, to test the efficiency of systems under given conditions. True or False?
Answer:
True.
Explanation:
The compressibility of a fluid can be defined as a measure of the change in volume (density) with respect to the amount of pressure applied to the fluid. Thus, as the pressure of a compressible fluid increases, both its viscosity and density increases.
Some examples of compressible fluids are vapors, gases, air etc.
Additionally, the compressibility of fluids plays a significant role in the field of science such as in aerodynamics, fluid mechanics, thermodynamics etc.
Viscosity can be defined as a quantity expressing the magnitude of internal friction that restricts the ease of flow between parallel layers at some distance apart having unit speed relative to each other.
These properties of fluids, including viscosity and compressibility are usually being studied by engineers such as civil engineers, in order to test the efficiency of systems under given conditions.
Answer:
true
Explanation:
edge
Which type of electrical system tool checks power in
12-volt circuits in a vehicle to see if current is flowing?
A test light
B timing light
C oscilloscope
D scan tool
The resistance of a copper wire 200 m long is 21 Q. If its thickness (diameter) is 0.44 mm, its specific resistance is around_______________?
Answer:
Its specific resistance will be around 0.015
a poorly tighten terminal is often the cause of a/an ? a) open circuit b) circuit breaker interrupt c)short circuit d) ground fault
Answer: b) circuit breaker interrupt
Explanation:
Wires connect to outlets through terminals and these terminals need to be tight to ensure that electricity flows with the minimum amount of resistance.
If the terminal is poorly tightened, what happens is that resistance will build up as the appliance is being used and this resistance will make the terminal hotter.
The heat will continue to rise until the circuit breaker trips to interrupt the circuit and protect the appliance.
what does kichfoff's currebt law
Answer:
Kirchhoff's current law (1st Law) states that the current flowing into a node (or a junction) must be equal to the current flowing out of it
Explanation:
Which do you think would cause the most destruction to the organisms in a food web: taking away the carnivores, taking away the herbivores, taking away the producers or taking away the decomposers? Use evidence from your Food Web diagram above to support your claim.
Answer:
Explanation:
I do not have access to your diagram but based on what I know, a food web cannot sustain itself without decomposers. They are the main guys who break down dead animals, plants into organic or inorganic nutrients which are needed by the primary producers to grow. So if decomposers are not there then producers cannot produce and thus herbivores cannot live and carnovers die out as well. Hope this makes sense.
Check out: https://www.nationalgeographic.org/encyclopedia/decomposers/
A food web cannot sustain itself without decomposers. They are the main components who break down dead animals, plants into organic or inorganic nutrients which are needed by the primary producers to grow.
What are decomposers?Decomposers are living organisms like fungi and bacteria. These decomposers are heterotrophic which means they must take the nutrients and it cannot make its own food. Decomposers play an eminent role in an ecosystem because of their process of nutrition.
They break down the dead plants and the animals. These break down the waste of the organisms. They are very eminent for all the ecosystem. If these were not in the ecosystem, the plants cannot get essential nutrients, dead matter and waste would deposit. So the nutrients in them gets recycled back so that they can be used again.
When fish dies, there is nothing which is ingested and the bladder air starts to release, which causes the fish to sink to the bottom. After few days, the internal organs of the dead fish gets decomposed, after which a gas is formed.
Therefore, A food web cannot sustain itself without decomposers.
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