(8.6) A space station in deep space is spun like a giant wheel to produce centrifugal force so the occupants experience artificial gravity of one g. How does a clock at the rim of the space station compare with one residing at the hub? What does this say about the behavior of a clock sitting on the surface of a planet with a surface gravity of one g?

Answers

Answer 1

The way that the clock at the rim of the space station compare with one residing at the hub is that Rim clock will always runs slower.

The behavior of a clock sitting on the surface of a planet with a surface gravity of one g is the same.

Is there a timepiece on the ISS?

For instance, timekeeping on the International Space Station (ISS) is slightly slower than that of reference clocks on Earth. This explains why astronauts on the International Space Station (ISS) mature more slowly, lagging by 0.007 seconds every six months.

Ground-based atomic clocks have served as the industry standard for timekeeping since the 1950s. These clocks use the extremely steady and accurate frequencies of light emitted by particular atoms to keep time.

Therefore, Satellite clocks run slower due to more velocity but faster due to reduced gravity. Clocks move more slowly at the ISS orbital height because velocity dominates. At GPS altitude, clocks move more quickly due to the influence of gravity.

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Related Questions

a boy throws a ball of mass of 0.25kg straight upward with initial velocity of 20 m/s when the ball returns its speed it 17m/s. how much work does air resistance do on the ball

Answers

1.125 joule work done does air resistance do on the ball

work done= kinetic energy= mΔv²/2

m=0.25kg

Δv=3 m/s

work done= mΔv²/2

work done=-0.25×9÷2

work done=-1.125 joule

When an item is moved across a distance by an external force, at least a portion of that force must be applied in the direction of the displacement. This is known as work done in physics. By multiplying the length of the path by the component of the force operating along the path, work may be calculated if the force is constant. The work W is equal to the force f times the distance h, or W = mgh, to mathematically describe this idea. The work is W = mas if the force is applied at an angle of to the displacement.

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a cat is moving at 2 m/s when it accelerates at 4 m/s for 2 seconds. his new velocity is

Answers

vf = vi + at = 2 m/s + (4 m/s²) (2 s) = 10 m/s

joanne drives her car at a speed of 20 m/s. when she applied her breaks, a frictional force of 2000 N brought her car to a complete stop in 10 seconds. what is the mass of her car

A) 1000 Kg
B) 1300 Kg
C) 20,000 Kg
D) 800 Kg​

Answers

Answer:

A) 1000 kg

Explanation:

vf = vi + at

0 = 20 + (a)(10)

a = -2.0 m/s^2

F = ma

2000 = (m)(2)

m = 1000 kg

A high diver reaches the highest point in his jump with his center of gravity 10 m above the water. Assuming that all his gravitational potential energy becomes kinetic energy during the dive, calculate his speed just before he enters the water.

Answers

According to the given statement = 14ms⁻¹ his speed just before he enters the water.

What is potential energy, exactly?

Potentially energy is a type of energy that depends on how various system elements interact with one another. A spring's potential energy rises when it is crushed or stretched. A steel ball has more potential energy when it is hoisted above the soil than how it was brought closer to it.

Briefing:

Since the decrease in kinetic energy equals the variation in g.p.e. out from peak of the dive to the time just before kate enters the water, we may say that.

mgh= 1/2mv²

This means that just before she enters the water, her speed is

v= √2gh

v= √2 *9.81 *10

v= √196

v= 14ms⁻¹.

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State the name given to reflected sound waves

Answers

Echo

Explanation:

It is termed as Echo. Echo is a reflection of sound that arrives at the listener with a delay after the direct sound.

Two 10¢ coins (dimes) carrying identical charges are lying 2.5 m apart on a table. If each of these coins experiences an electrostatic force of magnitude 2.0 N due to the other coin, how large is the charge on each coin?

I know the answer is 52 micro coulombs, but I keep getting 37.26...

Answers

Answer:

Charge q = 37.27 micro coulombs

Explanation:

Given:

q₁ = q₂ = q

r = 2.5 m

F = 2.0 N

________

q - ?

Coulomb's law:

F =k·q₁·q₂ / r² = k·q·q / r² = k·q² / r²

Charge:

q = √ (F·r² / k)

q = √ (2·2.5² / (9·10⁹) ≈ 37.27·10⁻⁹  C

or q = 37.27 micro coulombs

The correct answer is not 52, but !!! :))

Stars that have a mass greater than the _____ or _____ limit will not become white dwarfs.

Answers

Stars that have a mass greater than the 1.4 solar masses or the Chandrasekhar limit will not become white dwarfs.

What is Chandrasekhar limit?

The Chandrasekhar limit is the maximum mass that a stable white dwarf star can have. It was noted by E.C. Stoner and Willhelm Anderson in their works, and they gave it the name Subrahmanyan Chandrasekhar in honour of the Indian astronomer who made important, independent findings for enhancing calculation accuracy.

The limit was first disregarded by the scientific community since it would have supported the existence of black holes (technically unrealistic at this turn-off time). The white dwarf stars resist the gravitational collapse of the black hole due to the pressure of electron degeneration.

The Chandrasekhar limit is established at a mass where the gravitational field's self-attraction cannot be balanced by the pressure from electron decay.  The limit that has been established these days is 1.39 solar mass.

Hence, Stars that have a mass greater than the 1.39 solar masses or the Chandrasekhar limit will not become white dwarfs.

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Question 15 of 34
Which of the following would increase the mechanical advantage of a lever?
A. Moving the fulcrum closer to the output force
O B. Moving the fulcrum farther from the output force
C. Decreasing the input force without moving the fulcrum
D. Increasing the input force without moving the fulcrum

Answers

The option that  would increase the mechanical advantage of a lever is option A. Moving the fulcrum closer to the output force.

What influences a lever's mechanical advantage?

Mechanical advantage quantifies a lever's effectiveness (how easy it is to lift the load). - When compared to the distance between the load (resistance) and the fulcrum, the advantage relies on the distance between the effort and the latter (effort arm) (resistance arm).

Note that in Levers of Class 1:

The mechanical advantage will increase when the fulcrum is brought closer to the load.The mechanical advantage will increase when the effort is moved further from the fulcrum. You might need a longer lever for this.

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Write down in words the formula connecting acceleration, initial speed, final speed and time.

Answers

Formula connecting acceleration, initial speed, final speed and time.

v=u+at,

v2=u2+2as,

s=ut+1/2at2.

How many different acceleration formulas are there?

For motion on a straight line with constant acceleration, there are five common formulas. The formulas are provided in terms of the initial velocity (u), final velocity (v), displacement (x), acceleration (a), and time (t).

What is the relationship between distance and acceleration?

The following equation can be used to determine distance from acceleration: D = v*t + 1/2*a*t2. where an is the acceleration, t is the passage of time, and v is the velocity.

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Calculate weight if an object, given its mass

Answers

Answer:

Weight is a measure of the force of gravity pulling down on an object. It depends on the object's mass and the acceleration due to gravity

Explanation:

A 5 kg block is moved up a 30 degree incline by a force of 50 N, parallel to the incline. The coefficient of kinetic friction between the block and the incline is 0.25. What is the net work done on the block over this distance?

Answers

The net work done on the block over the given distance is 39.4d (joules)

What is the net work done on the block over this distance?

The net work done on the block over the given distance is calculated by applying the following equation as shown below:

W(net) = F(net) x d where;

F(net) is the net force on the blockd is the distance moved by the block

F(net) = F - μmgcosθ where;

μ is the coefficient of kinetic frictionm is the mass of the blockg is acceleration due to gravityθ is the angle of inclination of the plane

F(net) = 50 N - (0.25 x 5 x 9.8 x cos30)

NF(net) = 50 N - 10.6 NF(net) = 39.4 N

The net work done on the block over the given distance is calculated as: W = 39.4 N x dwhere;

d is the distance moved by the block = length of the incline

W = 39.4d (joules)

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When an earthquake occurs, potential energy in the Earth's crust is released and waves of energy move across the Earth. What are
these waves called?
OA. seismic waves
OB. crust waves
OC. rock waves
OD. solid waves

Answers

Answer:

seismic waves

Explanation:

I am not sure how to approach this question.

Answers

Answer:

35.2 AU

Explanation:

Kepler's Third Law states that the square of the orbital period of a planet is directly proportional to the cube of the semi-major axis of its orbit.

[tex]\boxed{T^2 \propto a^3 \implies T^2=ka^3}[/tex]

Kepler's Third Law

[tex]T^2=\dfrac{4 \pi^2}{GM}a^3[/tex]

where a is the semi-major axis of the ellipse.

If expressed in the following units:

T = Earth years.a = Astronomical units AU (a=1 AU for Earth).M = Solar masses.

then:

[tex]\implies\dfrac{4 \pi^2}{GM}=1[/tex]

Therefore Kepler's Third Law can be expressed as:

[tex]\boxed{T^2=a^3}[/tex]

Given:

T = 75.6 years

From inspection of the given diagram:

[tex]\implies 2a=x+0.57[/tex]

[tex]\implies a=\dfrac{x+0.57}{2}[/tex]

Substitute these values into the equation and solve for x:

[tex]\implies (75.6)^2=\left(\dfrac{x+0.57}{2}\right)^3[/tex]

[tex]\implies (75.6)^\frac{2}{3}=\dfrac{x+0.57}{2}[/tex]

[tex]\implies 2(75.6)^\frac{2}{3}=x+0.57[/tex]

[tex]\implies x=2(75.6)^\frac{2}{3}-0.57[/tex]

[tex]\implies x=35.1883819...[/tex]

[tex]\implies x=35.2\; \text{AU}[/tex]

Please help me with this looking to go over my work

Answers

0.99 joule must the work done by friction to stop the box.

m=87g

k=82N/m

x=11cm=0.11m

spring force=kx

spring force=82N/m×0.11m

spring force=9.02 N

work done= Fx

work done=9.02 N×=0.11m

work done=0.99 joule

When an item is moved across a distance by an external force, at least a portion of that force must be applied in the direction of the displacement. This is known as work done in physics. By multiplying the length of the path by the component of the force operating along the path, work may be calculated if the force is constant. The work W is equal to the force f times the distance h, or W = mgh, to mathematically describe this idea. The work is W = mas if the force is applied at an angle of to the displacement.

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A 70kg student, happy to see snow in early
November, rushes out to sled on a hill with a 10kg
sled. They start h=12m above a horizontal plane.
How fast are they moving by the time they reach
the bottom of the hill? (assume the coefficient of
friction is zero here) After a short distance the
reach a point where there are some dry leaves are
scattered producing an effective coefficient of
friction uk=0.4. How far do they travel through the leaves before they
come to rest?
Use the fundamental principle

Answers

(a) The speed of the student at the bottom of the hill is 15.34 m/s.

(b) The speed of the student at the presence of friction force is 11.88 m/s.

What is the speed of the student at the bottom of the hill?

The speed of the student at the bottom of the hill is calculated by applying the principle of conservation of energy as shown below.

Kinetic energy at the bottom hill = potential energy at maximum height

¹/₂mv² = mgh

where;

m is mass of the studentv is the speed of the speed of the student at bottom hillh is the height of the hill

v² = 2gh

v = √2gh

v = √(2 x 9.8 x 12)

v = 15.34 m/s

The speed of the student at the presence of friction force is calculated as;

Kinetic energy at the bottom hill + work done against friction  = potential energy at maximum height

¹/₂mv² + μmgh = mgh

¹/₂v² + μgh = gh

v²  +  2μgh = 2gh

v² = 2gh - 2μgh

v² = (2 x 9.8 x 12) - (2 x 0.4 x 9.8 x 12)

v² = 141.12

v = √141.12

v = 11.88 m/s

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An elevator lifts 2400 kg a distance of 55 m in 18.9 s. How much power does the
elevator demonstrate?

Answers

The work done by the elevator over the 55 meters is easily calculable: W = mgh = (2400)(9.8)(55) = 1293600Joules. The total time of the trip can be calculated from the velocity of the elevator: t = x/v=55/18.9 = 2.91. Thus the average power is given by: P =W/t=1293600/2.91=444536   Watts

A weightlifter curls a 25 kg bar, raising it each time a distance of 0.50 m. How many times must he repeat this exercise to burn off the energy in one slice of pizza? Assume 25% efficiency. Energy content of one slice of pizza is 1260 kJ .

Answers

42 times must he repeat this exercise to burn off the energy in one slice of pizza.

What is energy?

Energy is the ability or capability to do tasks, such as the ability to move an item (of a certain mass) by exerting force. Energy can exist in many different forms, including electrical, mechanical, chemical, thermal, or nuclear, and it can change its form.

Energy burn by the weightlifter = potential energy

Potential energy = mgh

Potential energy = 25.(9.8)(0.50)

Potential energy = 122.5 Joule.

Assume 25% of efficiency so energy burn = 122.5*25/100

energy burn = 30.625 joule

Number of times = 1260/30.625

Number of times = 42 times.

42 times must he repeat this exercise to burn off the energy in one slice of pizza.

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A star loses 6.022×10²³ mass per second. The total mass of the star is 12.044×10⁴⁶ in how much time will the star lose all its mass.

please helpp!!!!​

Answers

It would take the star 2 seconds to lose all it's mass.

I got this by dividing 12.044×10⁴⁶ by  6.022×10²³

which ways more a quarter pound hamburger on jupiter or a 12 ounce steak on venus

Answers

Answer: 12 ounce steak on venus

Explanation: venus = closer to the sun. The sun = more potential gravity, which would make it heavier than a quarter pound hamburger on jupiter.

5. Chad wants to investigate whether adding a solute to water affects its boiling point and freezing point. He set up an experiment and recorded the boiling and freezing point in degrees Celsius (°C), his results are in the data table.

EFFECT OF SOLUTE ON BOILING AND FREEZING POINTS

Test
A.Water
B.Water + 10 grams of salt
C.Water + 20 grams of salt
D.Water +30 grams of salt
E.Water + 40 grams of salt
Boiling Point (°C)
A.100.0
B.100.5
C.101.0
D.101.5
E.102.0
Freezing Point (°C)
A.0
B.-2
C.-4
D.-6
E.-8

Based on the data, which statement would be the best conclusion?
A. Adding salt to water decreases the boiling point.
B. Adding any solute to water increases the boiling point.
C. Adding salt to water increases the boiling point and decreases the freezing point.
D. Adding any solute to water increases the boiling point and decreases the freezing point.

Answers

Answer: C Adding salt to water increases the boiling point and decreases the freezing point

Explanation:

A spaceship is coasting in orbit around a planet.
A second spaceship sits motionless on the launch
pad. The two ships define frames that are accelerated with respect to each other, yet both might be
regarded as inertial frames. Explain.

Answers

As per Drag theory , one possible explanation is v=0 that means velocity of earth relative to ether is zero.

For t1=t2, as per equation

[tex]t1=2l/c [ 1 + v^{2} /c^{2} ]\\t2= 2l/c [ 1 + v^{2} /2c^{2} ][/tex]

Then there is no relative velocity between earth and ether. In other words the ether is dragged with the motion of earth with the same velocity as the earth. However if this explanation is acceptable for there should be no aberration of light. Even if the ether is considered to be dragged partially , the absence of fringes shift and value of aberration cannot be explained simultaneously.

It has been verified by experiments that newton's frame of reference taking stars to be fixed , is an inertial one , while the other one i.e. reference frame fixed to earth  is not an inertial frame. Since the earth rotates about its axis as well as round the sun.

Even Galilean Transformation equations explain the structure of inertial frames.

For example - Length of a rod is invariant under Galilean transformations.

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An object is rotating about a fixed axis such that its rotational inertia about the fixed axis is 10 kg - m². The object has an angular velocity was a function of time t given by w(t) = at³ - w₂.
where a=2.0 and up- -4.0
The change in angular velocity for the object from t=1s to t=3s is most nearly

Answers

The change in angular velocity for the object from t=1s to t=3s is most nearly  24 rad/s².

What is the change in the angular velocity of the object?

The change in the angular velocity of the object is the angular acceleration of the object and the magnitude is calculated as follows;

α = Δω/Δt

where;

Δω is the change in the angular velocityΔt is change in time of motion

α = at³ - w₂

α = d(at³ - w₂)/dt

α = 3at²

The given parameters;

a = 2t = 3 s - 1 s = 2 s

α = 3(2)(2)²

α = 24 rad/s²

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A set of lights consists of 20 lamps connected in series to the 230 V mains electricity supply. 1. (a) When the lights are switched on and working correctly, the current through each lamp is 0.25 A. (i) What is the total current drawn from the mains supply?

Answers

The total current that is drawn from the mains supply is 5 A.

What is current?

The term current has to do with the flow of charges in a circuit. Now we have been told that A set of lights consists of 20 lamps connected in series to the 230 V mains electricity supply. It was also said in the question that when the lights are switched on and working correctly, the current through each lamp is 0.25 A.

Now we have the following information;

Current passing through each lamp = 0.25 A

Number of lamps = 20 lamps

Hence;

Total current = 0.25 A * 20

= 5 A

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Turner’s treadmill runs with a velocity of −1.2 m/s and speeds up at regular intervals during a half-hour workout. After 25 min, the treadmill has
a velocity of −6.5 m/s. What is the average acceleration of the treadmill
during this period?

Answers

0.212 m/s²  is the average acceleration of the treadmill.

during this period

initial velocity, u = -1.2 m/s

time= 25 min

final velocity, v=  −6.5 m/s

acceleration = (v-u)÷ t

acceleration =5.3/25

acceleration =0.212 m/s²

The rate at which an item changes its velocity is known as acceleration, a vector variable. If an object's velocity is changing, it is accelerating. A moving object can occasionally alter its velocity by the same amount every second. a moving object that changes its speed by 10 m/s per second. Since the velocity is changing by a fixed amount every second, this is known as a constant acceleration. It is important to distinguish between an item with a constant acceleration and one with a constant velocity. Be not deceived! An object is accelerating if its velocity is changing, whether by a fixed amount or a variable quantity. Additionally, a moving item with a constant speed is not accelerating.

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URGENT!! ILL GIVE
BRAINLIEST!!!! AND 100 POINTS!!!!!

Answers

Answer is C. A force is changing the motion of the bus

Answer:

The force of friction and air resistance slow down the movement of the bus.

c) A forse is changing the motion of the bus

How massive would a black hole have to be in order for it to evaporate due to Hawking radiation in
only one year? How big is that mass compared to
some object with which you are familiar? (On the
surface of the Earth, 1 kg ≈ 2.2 lb.)

Answers

It takes a black hole an astonishingly long time to convert all of its mass into energy via Hawking radiation. A googol, or 10100 years, would be required for a supermassive black hole to completely vanish.

How are black holes able to dissipate energy?

A black hole radiates, losing mass as it does so and beginning to release more radiation, which accelerates the evaporation of the black hole. It eventually contracts to a size close to the Planck mass, where its Schwarzschild radius and DeBroglie wavelength coincide.

How long does it take a black hole to be destroyed by Hawking radiation?

Sagittarius A* 1087 years for Ton 618, the biggest black hole ever detected, and Sagittarius A* 1087 years for Sagittarius A* to evaporate from Hawking radiation It would take more than 10100 years for it to evaporate away (weighing a staggering 66 billion solar masses).

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950 kg
3.
If the car has 30.400 J of kinetic
energy, how fast is it moving?

Answers

m
=
950

k
g
E
=
30
,
400

J
To determine the speed of the car, we use the term for kinetic energy:

E
=
1
2
m
v
2

and we re-arrange this equation to get the speed v:

v
=

2
E
m

and we substitute:

v
=

2
(
30
,
400

J
)
950

k
g

evaluating this, we obtain the speed:

v
=
8

m
/
s

The force on a particle of mass 2.0 kg varies with position according to F(x) =−3.0x^2 (x in meters, F(x) in newtons). The particle’s velocity at =2.0m is 5.0 m/s. Calculate the mechanical energy of the particle using (a) the origin as the reference point and (b) =4.0m as the reference point. (c) Find the particle’s velocity at =1.0m. Do this part of the problem for each reference point.

Answers

(a) The mechanical energy of the particle at the origin is 0 J.

(b) The mechanical energy of the particle at 4 m is 625 J.

(c)  The particle’s velocity at 1.0m is 17.32 m/s.

What is the mechanical energy of the particle?

The mechanical energy of the particle is the total energy of the particle due to its motion and position above the ground such as kinetic energy and potential energy.

E = P.E + K.E

E = mgh + ¹/₂mv²

where;

h is the height of the particle above the groundg is acceleration due to gravitym is the mass of the particlev is the speed of the particle

at the origin, the displacement of the particle is zero and the velocity of the particle is zero.

E = (2 x 9.8 x 0) +  ¹/₂(2)(0)²

E = 0 J

The acceleration of the particle is calculated as follows;

F = ma

a = F/m

where;

F is force = 300 Nm is mass of the particle = 2 kg

a = (300)/2

a = 150 m/s²

The velocity of the particle at distance 4 m is calculated as follows;

v² = u² + 2as

where;

v is the velocity at 4 mu is the velocity at 2 ma is the accelerations is the distance travelled from 2 m to 4 m = 2 m

v² = (5)² + 2(150)(2)

v² = 625

v = √625

v = 25 m/s

E = ¹/₂mv²

E = ¹/₂(2)(25²)

E = 625 J

The particle's velocity at 1 m is calculated as follows;

Apply the principle of conservation of energy;

Work done by force = kinetic energy of the particle

Fd = ¹/₂mv²

where;

d is the displacement of the particlev is the velocity

300 x 1 = ¹/₂(2)v²

300 = v²

v = √300

v = 17.32 m/s

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The tune-up specifications of a car call for the spark plugs to be tightened to a torque of 50 N⋅m. You plan to tighten the plugs by pulling on the end of a 30-cm-long wrench. Because of the cramped space under the hood, you'll need to pull at an angle of 105 ∘ with respect to the wrench shaft.
With what force must you pull?

Answers

The force needed to pull the wrench of 30 cm long is 643.95 N.

What is force?

Force can be defined as the product of mass and aceleration.

To calculate the force that must be pull, we use the formula below.

Formula:

F = T/Lcos∅.......... Equation 1

Where:

F = ForceT = TorqueL = Length of the wrench∅ = Angle

From the question,

Given:

T = 50 N.mL = 30 cm = 0.3 m∅ = 105°

Substitute these values into equation 1

F = 50/(0.3×cos105°)F = -643.95 N.

Note: The negative sign tells the direction of the force and can be ignored (Pull)

Hence, the force need to pull is 643.95 N.

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Monkey Joe and Money Jane are pulling a boat through water. Each exerts a force of 600N directed at a 30 angle relative to the forward motion of the boat. If the boat moves with constant velocity, find the resistive force Fr, exerted in the boat by the water.

Answers

Answer:

1039 N

Explanation:

The 'x' components of their pulling forces = the force of friction:

2 x 600 cos 30 = 1039 N

Other Questions
Yasmin is writing a story about her first day of high school. Which sentence would most likely help her to develop multiple plot lines in the narrative?. which of the following is often associated with an increasing employment rate of women in living wage occupations? a.) less access to education b.) higher standard of living for families c.) fewer resources for children d.) increased population growth Rcriture (10 min, 5 points)Rcrivez ce passage au pass compos en proc-dant toutes les transformations ncessaires. Private markets fail to account for externalities becauseA. externalities don't occur in private marketsB. sellers include costs associated with externalities in the price of their product.C. decision makers in the market fail to take account of the external effects of their behaviorD. the government can easily correct any adverse effect on the market that externalities may cause A container releases fuel at a rate of 5 gallons per second. If y represents the amount of fuel remaining in the container and represents the number of seconds that have passed since the fuel starteddispensing, then x and y satisfy a linear relationship.If the tank begins with 103 gallons, how many gallons will remain after 2 seconds? if an organism found itself in a suddenly colder environment, and if the body temperature dropped, what changes at the molecular level could be instituted to maintain membrane fluidity? acrostic poem definition of iridescent as a general rule of thumb, which principle holds that all decisions should be made assuming that the decision would be applied to everyone else in similar circumstances? Why do male turkeys gobble? A climber of mass 100 kg (including the equipment she is carrying) ascends from sea level to the top of a mountain 5500 m high. Calculate the change in her gravitational potential energy you are a medical doctor and have a patient in their 50s. the patient is concerned about osteoporosis. what would you suggest as a preventative treatment? a woman with bipolar disorder, manic episode, has been spending thousands of dollars on clothing and makeup. she has been partying in bars every night and rarely sleeps or eats. the nurse in the outpatient clinic, knowing that this client rarely eats, recognizes that her eating problems most likely result from what? -18t=-3(t+5) distributive property I only have 10 points. What is the equation of the line shown in this graph? Which five sections in this excerpt from The Importance of Being Earnest by Oscar Wilde show that Lady Bracknell places utmost importance onwealth and appearances?LADY BRACKNELL (Sitting down again.): A moment, Mr. Worthing. A hundred and thirty thousand pounds! And in the Funds! Miss Cardew seems tome a most attractive young lady, now that I look at her.Few girls of the present day have any really solid qualities, any of the qualities that last, andimprove with time. We live, I regret to say, in an age of surfaces. (To Cecily.) Come over here, dear. (Cecily goes across.) Pretty child! your dress issadly simple and your hair seems almost as Nature might have left it. But we can soon alter all that. A thoroughly experienced French maidproduces a really marvellous result in a very brief space of time.OWTI husband did not know herI remember recommending one to young Lady Lancing, and after three months herJACK And after six months nobody knew her.LADY BRACKNELL(Glares at Jack for a few moments.Then bends, with a practised smile, to Cecily.): Kindly turn round, sweet child. (Cecily turnscompletely round.) No, the side view is what I want. (Cecily presents her profile.)your profileYes, quite as I expected. There are distinct social possibilities inThe two weak points in our age are its want of principle and its want of protile. The chin a little higher, dear. Style largely depends onthe way the chin is worn Theyworn very high, just at present. Algernon! What are the 4 nucleotides DNA? brea is a business owner who is in charge of ensuring that her business earns enough money to pay the rent, pay the employees, and purchase new manufacturing machines when the old ones wear out. which of these resources best describes brea? is it reasonable to use this line of best fit to make the above prediction? select the correct answer below: The extent to which goals are challenging, attainable, and require effort is known as goal ___________. A strategy in which a player cooperates until the other player defects and then defects until the other player cooperates again.