75m X A car moves with a uniform velocity 21 ms-1 from position P and a truck moves from rest with uniform acceleration 2 ms-2 from position Q in the same time in the same direction.

i) Determine the distance travelled in 20 seconds.
ii) How many times the private car will meet? Analyze mathematically.​

75m X A Car Moves With A Uniform Velocity 21 Ms-1 From Position P And A Truck Moves From Rest With Uniform

Answers

Answer 1

Velocity after 20s for both

Car=21m/sTruck=2(20)=40m/s.

Distance traveled for car

20(21)=420m

Distance traveled by truck=

s=ut+1/2at²s=1/2(2)(20)²s=400m

#b

Distance from Q

for car

420-75=345m

For truck

400m

The truck will meet the car after 75/21≈4s

Then for 6s the car keeps meeting because after 7 s Truck will archive 22m/s velocity

Total meet ups=6+1=7times

Related Questions

Question 7 of 10
which type of insurance policy covers liability that exceeds the coverage of a
regular insurance policy?
o a. health insurance
o b. disability insurance

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Answer: it’s actually umbrella

Explanation: because

If the _ of the proteins changes, this is called a mutation

Answers

Answer:

If the DNA of the proteins changes, this is called a mutation.

Explanation: Hope it helps you :))))

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There are uniform cubes in a toy box, a child makes a pillar using these cubes on a rough plane which is inclined to the horizontal at angle theta. The cubes do not slide on each other. If tan theta = 1/8, the max no. of cubes that can be stacked is,
A. 4
B. 5
C. 8
D. 16

Please explain the methods of obtaining the ans . Will mark the brainliest for the best ans

Answers

The maximum number of cubes that can be stacked on the inclined plane without sliding is determined as 8.

Net force on the box

The net force on the box can be used to determine the maximum number of cubes that can be stacked without sliding.

The stack cubes must be at equilibrium.

∑Fx = 0

nW - μFₙ = 0

where;

n is number of the cubesFₙ is the normal force of the cubesW is the weight of the cubes acting parallel to the plane

n(mg)sinθ - μmgcosθ = 0

n(mg)sinθ  = μmgcosθ

nsinθ  = μcosθ

let the coefficient of friction = 1

nsinθ  = cosθ

n = cosθ/sinθ

n = 1/tanθ

n = (1)/(1/8)

n = 8

Thus, the maximum number of cubes that can be stacked on the inclined plane without sliding is determined as 8.

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When the defibrillator is in use, a potential difference of 4800 V is applied across the
person's chest.
A charge of 0.16 coulombs passes through the person's chest in 4.0 ms
Calculate the resistance of the person's chest.

Answers

If a defibrillator is in use with the given potential difference and charge in the given time, the resistance of the person's chest is 120 Ohms.

What is the resistance of the person's chest?

From Ohm’s law;

V = I × R

Where V is the voltage or potential difference, potential difference, I is the current and R is the resistance.

Given that;

Potential difference v = 4800VCharge Q = 0.16CTime elapsed t = 4.0ms = ( 4/1000 )s = 0.004sResistance R = ?

First, we calculate the current I.

Since current is the electric charge transferred per unit time.

I = Q/t

I = 0.16C / 0.004s

I = 40A

Now, the resistance of the person's chest will be;

V = I × R

R = V / I

R = 4800V / 40A

R = 120Ω

Therefore, If a defibrillator is in use with the given potential difference and charge in the given time, the resistance of the person's chest is 120 Ohms.

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HURRY A spring with a spring constant of 350 N/m pulls a door closed. How much work is done as the spring pulls the door at a constant velocity from an 85.0-cam stretch to a 5.0-cm stretch?

Answers

In stretching or compressing the spring by a distance of x (in meters), one performs 1/2 (350 N/m) x² of work on the spring, or equivalently the spring performs -1/2 (350 N/m) x² of work on the door. This work is negative since the restoring force of the spring opposes the force used to stretch or compress the spring.

Then when the spring is allowed to relax, it performs 1/2 (350 N/m) x² of work to return it to equilibrium position. The force from the spring acts in the direction of the door's motion, so the work done is positive once more.

Now, the work done on the door …

• … to return it from 85.0 cm = 0.850 m to equilibrium is

1/2 (350 N/m) (0.850 m)² = 126.4375 J

• … to return it from 5.0 cm = 0.050 m to equilibrium is

1/2 (350 N/m) (0.050 m)² = 0.4375 J

• … to relax from 85.0 cm to 5.0 cm from equilibrium is

126.4375 J - 0.4375 J = 126 J

when we throw an arrow by streching the string of a bow , how does the energy change take place ?​

Answers

when we throw an arrow , we first stretch the string of the bow. while stretching the string of the bow, the work done by us in stretching the bowstring gets stored as potential energy in the bow. This potential energy of the bow is transformed into kinetic energy when the bowstring is released and this gives the momentum and Kinetic energy to the arrow.

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When an arrow is drawn back by a bow, the work done by us in stretching the bowstring gets stored at potential energy in the bow. This potential energy of bow is transformed into kinetic energy when the bowstring is released and this gives kinetic energy to the arrow.

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When vehicle wheels are about to lock, the ABS senses the impending lock up and prevents this from occurring. a) True b) False 2 Question 2 Electronic stability control reduces the risk of rollover crashes, such as are common with SUVs. a) True b) False 3 Question 3 _______________have the ability to control wheel lock on all four tires. a) Four-wheel anti-lock brakes b) Rear-wheel anti-lock brakes c) All anti-lock brakes d) None of the above 4 Question 4 _______________is a technology that works to help maintain vehicle control and steering capability in the event of a skid. a) Parking/emergency brake b) Service brakes c) Anti-lock Braking system d) None of the above 5 Question 5 ___________ reduce the impact forces of a crash exerted upon a vehicle's occupants by allowing parts of the front of the vehicle to crush at varying rates. a) Electronic Stability Control b) Anti-lock Braking Systems c) Crumple Zones d) Traction Control Systems 6 Question 6 The Traction Control System (TCS) is designed to help maintain traction on a vehicle in hazardous conditions or situations. a) True b) False 7 Question 7 A driver operating a vehicle with traction control should brake for the feature to activate. a) True b) False 8 Question 8 Air bags in trucks or other vehicles that do not have a rear seat will have an on/off switch that can be activated for children under age 12. a) True b) False 9 Question 9 All vehicles are equipped with Anti-lock Braking Systems. a) True b) False 10 Question 10 Airbags may deploy in the _______ of the passenger or driver, or from the ____of the vehicle.

Answers

The answers to the questions are:

True TrueFour-wheel anti-lock brakesAnti-lock braking systemCrumple zonesTrue FalseTruefalseFront, sides

What is ABS?

ABS is known as an Anti-lock braking systems (ABS) that act in the capacity of steering one in times in emergencies by bringing back traction to one's tires.

Note that it often helps to hinder  wheels from locking up and helping the driver to be able to steer to safety.

When vehicle wheels are about to lock, the ABS senses the impending lock up and prevents this from occurring is true as that is its function.

Note that Electronic stability helps to control helps to the risk of rollover crashes, such as are common with SUVs.

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The next closest star to Earth, Proxima Centuri, is 4.25 lightyears away. How far is that in meters?

Answers

Answer:

4.0208 x 10^16 meters

Explanation:

speed of light in m/s   *      # seconds in a year      * 4.25 years =

2.99792 x 10^8   *        3600*24*365.25  *     4.25 = 4.0208 x 10^16 m

What's the frequency of the wave below? ​

Answers

Answer:

2 Hz

Explanation:

the frequency of a wave is how many waves pass in one second. So, to find the frequency of this wave, we should look at how many wave cycles have occurred at 1 second.

2 full wave cycles are shown between 0.0 seconds and 1.0 seconds, making the frequency 2 Hz

The amount of energy required to raise the temperature of one gram of water by one celsius degree is called a

Answers

The amount of energy required to raise the temperature of one gram of water by one celsius degree is called a calorie.

How can you define calorie?

In physics, we can define it as a unit of measurement that defines the amount of energy to raise the temperature of 1 gram  of water by 1°C. Each material has its unique calorie, however by definition we use water as it is the lowest of all the elements.

Normally, calorimetry is directly linked with the thermal capacity that an element has to contain heat.

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Drag the tiles to the correct boxes to complete the pairs.
Identify the type of potential energy described.

Answers

Plants have more food is the chemical energy.

Two north magnetic poles have been brought together is the magnetic energy.

A person has walked to the top of hill posses gravitational potential energy.

A balloon has gained negative charged after being rubbed with a wool cloth is the electric energy.

A spring has been compressed inside a toy.

What is energy?

Energy is the ability to do work.

There are different kind of energies like kinetic energy, potential energy, gravitational energy, heat energy, elastic energy, chemical energy, etc.

Thus, the statement are connected to the correct type of potential energies.

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Which best explains why the receiver of a signal must understand the code or language being used

Answers

The receiver of a signal must understand the code or language being used to avoid confusion and losses.

What is a Signal?

This is usually in the form of a sound or body movement and is involved in conveying messages to people.

The receiver must understand the code or language in order to prevent confusion or loss of lives and properties.

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Determine the force p required to (a) raise and (b) lower the 40-kg cylinder at a slow, steady speed. the coefficient of friction between the cord and its supporting surface is 0.30.

Answers

Answer:

T - M g - Ff = M a     describes the acceleration of the object

T = M g + Ff      if the object moves at constant speed  (a = zero)

Ff = μ M g = .3 * 40 * 9.8 = 118 N     the force of friction

Ff will be in a direction opposite to the motion

M g = 40 kg * 9.8 m/s = 392 N

a) T = M g + Ff   for an object moving upwards

T = 392 + 118 = 510 N

b) T = M g - Ff     for an object moving downwards

T = 392 - 118 = 274 N

The 85-lb force P is applied to the 200-lb crate, which is stationary before the force is applied. Determine the magnitude and direction of the friction force F exerted by the horizontal surface on the crate.

Answers

The direction of the friction force F exerted by the horizontal surface on the crate will be in the left direction.

How to depict the force?

From the information given, the 85-lb force P is applied to the 200-lb crate, which is stationary before the force is applied.

mg = 200 ×  0.2248 × 9.8 = 440.608

The static friction force will be:

= 0.5 × 440.608

= 220.304N

Therefore, the static friction is greater than the force applied. Therefore, there'll be a static friction acting on the box on the left direction.

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A woman launches a boat from one shore of a straight river and wants to land at the point directly on the opposite shore. If the speed of the boat is 10 mph and the river is flowing east at 5mph, in what direction should she head the boat in order to arrive at the desired landing point

Answers

Answer:

If she stands on the North side of a river flowing to the East at 5 mph,

she must head towards the SouthWest to arrive on the South side of the river directly across from her starting point and we have

x^2 + 5^2 = 10^2 where x is her speed directly across the river

x = (75)^1/2 = 8.66 mph towards the South

sin theta = 5 / 10 = 1/2

She must angle the boat at 30 deg from straight South

A plastic rod that has been charged negatively touches a neutral metal sphere. What kind of charged particle was transferred between the rod

Answers

Answer:

Negative particles will be transferred to the sphere,

Assuming the sphere is not grounded the sphere will be negatively charged when the plastic rod is withdrawn,

(The sphere can be positively charged by grounding the sphere and bringing the rod close to the sphere and then remove the grounding to the sphere)

Care must be taken in noting if and when the sphere is grounded.

What happens to the cost of goods when inflation increases?
OA. The cost of goods decreases.
B. The cost of goods increases.
OC. The cost of goods stays the same.
OD. The cost of goods varies.

Answers

Answer:

The answer is B

Explanation:

Generally speaking, a company selling goods during periods of inflation will see an increase in its cost of goods sold.

When inflation increases, the cost of goods increases. The correct option is B.

Generally speaking, inflation raises the price of products sold. The price of producing and purchasing those things rises together with the prices of goods and services owing to inflation.

This can be attributable to elements like escalating manufacturing costs, rising input costs, and shifting dynamics of supply and demand.

As a result, companies might need to modify their pricing plans to take inflation-related cost increases into account, the cost of goods typically increases when inflation occurs.

Thus, the correct option is B.

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what are the similarities and differences between how living and non-living things fly.

Answers

Flying animals utilize their wings to create both lift and propulsion by moving them in relation to the body.

What are living and nonliving things?

They both consist of fundamentally simple building blocks. They are composed of substance or mass. Atmospheric and molecular building blocks make up the world.

The differences between how living and non-living things fly;

1. Moving both living and non-living objects consumes energy. Flying animals utilize their wings to create both lift and propulsion by moving them in relation to the body.

In contrast to most air vehicles where the components that generate lift wings and thrust engines or propellers are distinct and the wings stay stationary.

Animal aviators like birds as well as natural parachuters like patagial as well as human inventions like aircraft as well as rockets that can power spacecraft and spaceplanes are just a few examples of the many things that can fly.

Hence there are similarities and differences between how living and non-living things fly.

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A car started its journey at point A. After 30 seconds, the car had reached point B. The car stops at point B for 10 seconds. Then, the car turned around and arrived at point A after 15 seconds. The car stopped at point A for 20 seconds. The car then went on his way and get to the point C after 10 seconds. Find the velocity from 30 to 40s

Answers

Since the displacement is equal to zero, the velocity from 30 to 40s will also be zero.

Velocity

Velocity is the distance travelled by a body in a specific direction per time taken. It is measured in meter per second. That is, m/s

Given that a car started its journey at point A. After 30 seconds, the car had reached point B. The car stops at point B for 10 seconds. Then, the car turned around and arrived at point A after 15 seconds. The car stopped at point A for 20 seconds. The car then went on his way and get to the point C after 10 seconds.

To find the velocity from 30 to 40s, we must realize that velocity can also be defined as;

Velocity = displacement / time

The displacement from point A to B and back to A is equal to zero.

Therefore, The velocity from 30 to 40s is also zero.

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11) The total conversion of 2.50 kilogram of the
Sun's mass into energy yields
(1) 9.31 x 102 MeV
(2) 8.38 x 10¹⁹ MeV
(3) 1.41 x 1030 MeV
(4) 2.25 x 10¹7 MeV

Answers

1.41 × 10³⁰ MeV

As we know, E=mc², where E is energy, m is mass and c is the speed of light(i.e. 3×10⁸ m/s).

Given mass = 2.5 kgs

E = (2.5)×(3×10⁸)² J = 22.5×10¹⁶ J

As our answer is in joules so we have to convert it into mega electron volt(MeV)

1 J = 6.242 × 10¹² MeV

⇒ 22.5×10¹⁶ J = 22.5×10¹⁶ × (6.242 × 10¹²) MeV

1.41 × 10³⁰ MeV

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It’s number (3) 1.41

Read the scenario below and answer the question that follows.

Jean has been increasingly hyperactive, staying up all night, and finishing her work assignments in record time during the past few weeks. She feels it is a big improvement from how she felt before, when she was worried about losing her job, had trouble concentrating, and felt extremely irritable.

Jean is most likely suffering from __________ disorder.
A.
major depressive
B.
bipolar
C.
phobic
D.
generalized anxiety

Answers

the answer you are looking for is D most of those are signs of anxiety

8. A round tube weighs 30 kg. If the tube is stood on end, it pushes down on the floor with a pressure of 20 N/m². How many square inches is the end of the tube​

Answers

Answer:

22785 square inches

Explanation:

As the mass of the tube is 30kg, therefore it is exerting a force of 30g N(30g = 30 × 9.8 = 294)So the force is 294 N.Pressure is 20 N/m², as given.As we know Pressure is equal to the force exerted per unit area (P=F/A).Therefore, A=F/P

        A = 294 ÷ 20 = 14.7 m²

As 1 m² = 1550 square inches. Therefore, 14.7 m² = 14.7 × 1550 square inches = 22785 square inches

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Explain how horizontal motion can be uniform while vertical motion is accelerated.
How will projectile motion be affected when drag due to air resistance is taken into
consideration?

Answers

In projectile motion horizontal motion has zero acceleration and when there is no air resistance acting on the object the motion will be uniform. Motion in the vertical direction is accelerated downwards to to the acceleration due to gravity

Why is a Magnetar extremely magnetic?

Answers

Answer:

The dominant theory of the strong fields of magnetars is that it results from a magnetohydrodynamic dynamo process in the turbulent, extremely dense conducting fluid that exists before the neutron star settles into its equilibrium configuration.

How strong is a magnetar magnetic field?

It can generate the most intense magnetic field observed in the Universe. The field strength of a magnetar is one thousand trillion times stronger than Earth's and is so intense that it heats the surface to 18 million degrees Fahrenheit. We only know of about 10 magnetars in the Milky Way galaxy.

A scientist claims that a certain type of fabric is better able to repel water than another. Which option describes an experiment that will produce evidence that will support or refute her claim?
A. Test groups of each kind of fabric by exposing them to the same amount of water for the same amount of time.
B. Test groups of each kind of fabric by exposing them to the same amount of water for different amounts of time?
C. Test a group of one kind of fabric by spraying water on it, and a group of the other fabric by submerging it.
D. Test a group of one fabric by spraying it with distilled water, and a group of the other fabric by spraying it with salt water.

Answers

The best way would be to test groups of each kind of fabric by exposing them to the same amount of water for the same amount of time. The correct option is A.

Scientific experiments

In conducting scientific experiments to compare test subjects such as the fabrics mentioned in the illustration, the test subjects must be subjected to the same conditions.

The outcome of the experiment will no longer be scientifically valid if the test subjects are not exposed to the same condition.

Thus, the two fabrics must be exposed to the same amount of water for the same amount of time in order to come to a valid conclusion about which is a better water repeller among the two.

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Does paint and cardboard have joints in it

Answers

Noooo it doesn’t because it’s not apart of the body

Suppose a 2662 kg giant seal is placed on a scale and produces a 20.0 cm compres- sion. If the seal and spring system are set into simple harmonic motion, what is the period of the oscillations

Answers

Answer:

  0.8976 seconds

Explanation:

The period of oscillation for the simple harmonic motion can be found using the formula ...

  T = 2π√(d/g)

where d is the displacement of the spring due to the attached weight, and g is the acceleration due to gravity.

__

For d = 0.20 meters, the period is ...

  T = 2π√(0.20/9.8) ≈ 0.8976 . . . . seconds

_____

Additional comment

The formula for the oscillator period is usually seen as ...

  T = 2π√(m/k)

where m is the mass in the system and k is the spring constant. The value of the spring constant is calculated from ...

  k = mg/d

Using that in the formula, we find it simplifies to ...

  [tex]T=2\pi\sqrt{\dfrac{m}{k}}=2\pi\sqrt{\dfrac{m}{\left(\dfrac{mg}{d}\right)}}=2\pi\sqrt{\dfrac{d}{g}}[/tex]

The water in this pot is in the process of changing from a liquid to a gas. Thermal energy is still being added to the water as it vaporizes, but its temperature and the motion of its particles are not increasing. What do you think is happening to the extra energy?

Answers

The extra energy allows the molecules to convert states of molecules.

What is heating?

When the temperature is increased , the body or particle is said to be heating.

The water in this pot is in the process of changing from a liquid to a gas. Thermal energy is still being added to the water as it vaporizes, but its temperature and the motion of its particles are not increasing.

When the liquid is converted to gas, the temperature reaches the boiling point of water. After boiling, the heat added up will only make the particles to convert its phase and go away in then atmosphere.

Thus, extra energy added helps molecules of water to change its state from liquid to solid.

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1. Find the force if the mass is 6 kg and the acceleration is 12 m/s/s ​

Answers

Answer:

The answer to the question is 72N

The formular for calculating force is;

Force = Mass× acceleration due to gravity

therefore 6kg×12m/s/s = 72N

If a 0.08 kg cell phone falls off a table at 15 m/s, then what is its kinetic energy right before it hits the ground?

Answers

The kinetic energy of the phone right before it hits the ground is 9J.

Kinetic energy of the phone

The kinetic energy of the phone right before it hits the ground is calculated as follows;

K.E = ¹/₂mv²

where;

m is mass of the phonev is velocity of the phone

K.E = ¹/₂(0.08)(15)²

K.E = 9 J

Thus, the kinetic energy of the phone right before it hits the ground is 9J.

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