6. rule (x,y) ---> is the image similar to the original pre-image?

6. Rule (x,y) ---> Is The Image Similar To The Original Pre-image?

Answers

Answer 1

Here, we want to check for the relationship between the image and its pre-image

The pre-image is (x,y)

The image is (3x,3y+5)

As we can see, the pre-image is not similar

This is because the transformation applied to the two values are not same

Thus, we have that;

No, the image is not similar to the pre-image as the translations applied to both coordinates are not same

The pre-image was transformed by dilating the x-coordinate of the pre-image by 3 units while the y-coordinate was transformed by dilating the y-coordinate of the pre-image by 3 and translating it upward by 5 units


Related Questions

Solve the equation 20 +7k = 8(k + 2).

Answers

Answer:

[tex]k=4[/tex].

Step-by-step explanation:

1. Write the expression.

[tex]20 +7k = 8(k + 2)[/tex]

2. Solve the parenthesis on the right hand side of the equation.

[tex]20 +7k = 8k+16[/tex]

3. Subtract 20 from both sides of the equation.

[tex]-20+20 +7k = 8k+16-20\\ \\7k = 8k-4[/tex]

4. Subtract 8k from both sides of the equation.

[tex]7k-8k = 8k-4-8k\\ \\-k = -4[/tex]

5. Multiply both sides by "-1".

[tex](-1)-k = -4(-1)\\ \\k=4[/tex]

6. Verify.

[tex]20 +7(4) = 8((4) + 2)\\ \\20 +28 = 8(6)\\ \\48=48[/tex]

7. Express the result.

[tex]k=4[/tex].

Answer:

k = 4

Step-by-step explanation:

a) Simplify both sides of the equation.

20 + 7k = 8(k + 2)

20 + 7k = (8)(k) + (8)(2)

20 + 7k = 8k + 16

7k + 20 = 8k + 16

b) Subtract 8k from both sides.

7k + 20 − 8k = 8k + 16 − 8k

−k + 20 = 16

c) Subtract 20 from both sides.

−k + 20 − 20 = 16 − 20

−k = −4

Divide both sides by -1.

-k/-1 = -4/-1

k = 4

17. What is the value of x in the rhombusbelow?AC(x+ 40)B3x⁰D

Answers

ANSWER

x = 35 degrees

EXPLANATION

Given tthat

[tex]\begin{gathered} \text{ m Follow the steps below to find the value of x

Recall, that the sum of m[tex]\text{ m < C + m Therefore, x is 35 degrees

The next model of a sports car will cost 11.5% less than the current model. The current model costs $59,000. How much will theprice decrease in dollars? What will be the price of the next model?

Answers

we are given that a car cost $ 59000 and the price will decrease by 11.56%, therefore, the amount it will decrease is equivalent to:

[tex]59000\times\frac{11.56}{100}=6820.4[/tex]

Therefore, the price will decrease by $6820.4. The total price will be then:

[tex]59000-6820.4=52179.6[/tex]

Therefore, the price will be $52179.6

Show all work to identify the asymptotes and state the end behavior of the function f(x) = 6x/ x - 36

Answers

Vertical asymptotes are when the denominator is 0 but the numerator isn't 0.

[tex]x-36=0 \implies x=36[/tex]

Since this value of x does not make the numerator equal to 0, the vertical asymptote is [tex]x=36[/tex].

Horizontal asymptotes are the limits as [tex]x \to \pm \infty[/tex].

[tex]\lim_{x \to \infty} \frac{6x}{x-36}=\lim_{x \to \infty}=\frac{6}{1-\frac{36}{x}}=6\\\\\lim_{x \to -\infty} \frac{6x}{x-36}=\lim_{x \to -\infty}=\frac{6}{1-\frac{36}{x}}=6\\\\[/tex]

So, the horizontal asymptote is [tex]y=6[/tex].

End behavior:

As [tex]x \to \infty, f(x) \to -\infty[/tex]As [tex]x \to -\infty, f(x) \to \infty[/tex].

Find the exact value by using ahalf-angle formula.[?] --cos 75°

Answers

Answer::

[tex]\cos 75\degree=\frac{\sqrt[]{2-\sqrt[]{3}}}{2}[/tex]

Explanation:

By the half-angle formula:

[tex]\cos \mleft(\frac{\theta}{2}\mright)=\pm\sqrt[]{\frac{1+\cos\theta}{2}}[/tex]

Let θ=150°, therefore:

[tex]\begin{gathered} \cos (\frac{150\degree}{2})=\sqrt[]{\frac{1+\cos150\degree}{2}} \\ \cos (150)\degree=-\cos (180\degree-150\degree)=-\cos 30\degree \\ \implies\cos (\frac{150\degree}{2})=\sqrt[]{\frac{1+\cos150\degree}{2}}=\sqrt[]{\frac{1-\cos30\degree}{2}} \end{gathered}[/tex]

Now, cos 30 = √3/2, thus:

[tex]\begin{gathered} =\sqrt[]{\frac{1-\frac{\sqrt[]{3}}{2}}{2}} \\ \text{Multiply both the denominator and numerator by 2} \\ =\sqrt[]{\frac{2-\sqrt[]{3}}{4}} \\ =\frac{\sqrt{2-\sqrt[]{3}}}{\sqrt{4}} \end{gathered}[/tex]

The exact value of cos 75° is:

[tex]\cos 75\degree=\frac{\sqrt[]{2-\sqrt[]{3}}}{2}[/tex]

1/2+3/4+1/8+3/16+1/32+3/64

Answers

Answer:

105/64 or 1 41/64

Step-by-step explanation:

Math

Make common denominator of 64

:]

What I need to know is that what is 3.5x2

Answers

Answer:

7

Step-by-step explanation:

Just add 3.5 twice which is the same as multiplying it by 2

Answer:

7

Step-by-step explanation:

hope it helps and have a nice!!! :)

brainiest is appreciated

You want to obtain a sample to estimate a population mean. Based on previous evidence, you believe the population standard deviation is approximately
σ
=
50.2
. You would like to be 90% confident that your estimate is within 1.5 of the true population mean. How large of a sample size is required?

Answers

Using the sample size relation with the standard normal distribution, the required sample size is 3032 samples.

What is Normal distribution ?

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Using the sample size relation with the standard normal distribution, the required sample size is 673 samples.

n = [(Z* × σ) / ME]²

ME = margin of error

Z* = Z critical at 90% = 1.645

Substituting the values into the equation :

n = [(Z* × σ) / ME]²

n = [(1.645 × 50.2) / 1.5]²

n = (82.6/ 1.5)²

n = 55.06

n ≈ 3032

Therefore, the Number of samples required is 3032 samples.

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Sam graduation picnic cost $13 for decoration plus an additional $5 for each attendee.at most how many attendees can there be if sam budgets a total of $33 for his graduation picnic?

Answers

Given:

The cost of graduation picnic = $13 for decoration plus an additional $5 for each attendee

Let the number of attendance = x

we need to find x when sam budgets a total of $33 for his graduation picnic

So,

[tex]13+5x=33[/tex]

solve for x, subtract 13 from both sides:

[tex]\begin{gathered} 13+5x-13=33-13 \\ 5x=20 \end{gathered}[/tex]

divide both sides by 5

[tex]\begin{gathered} \frac{5x}{5}=\frac{20}{5} \\ \\ x=4 \end{gathered}[/tex]

So, the answer is:

The number of attendees = 4

When a number is divided by $5,$ the result is $50$ less than if the number had been divided by $6$. What is the number?

Answers

Answer:

1500$

Step-by-step explanation:

Answer: -1500

Step-by-step explanation: yes it is

Abner and Xavier can make a loaf of bread from scratch in 3 hours. This includes
preparation and baking time. Prep time is 135 minutes. For how long does the bread
bake?
Check Your Understanding- Question 1 of 2
Fill in the blanks to identify the steps needed to solve the problem.
Start by converting the total time to minutes. The conversion factor from hours to
60 minutes
minutes is
1 hour
It takes
Attempt 2 of 2
810 minutes in total to make the bread.

Answers

Answer:

the bread bakes for 45 minutes (yum)

How many gallons of a 60% antifreeze solution must be mixed with 80 gallons of 20% antifreeze to get a mixture that is 50% antifreeze?

Answers

Given

gallons which have 20% antifreeze solution = 80

Final concentration = 50% antifreeze solution

Find

Number of galloons with 60% antifreeze solution

Explanation

Let the number of gallons with 60% antifreeze solution = x

According to question

0.6x+0.2(80) = 0.50(x+80)

0.6x+16=0.5x+40

0.1x=24

x=240

Final Answer

Hence 240 gallons of 60% antifreeze solution will be required

Lukalu is rappelling off a cliff. The parametric equations that describe her horizontal and vertical position as a function of time are x ( t ) = 8 t and y ( t ) = − 16 t 2 + 100 and . How long does it take her to reach the ground? How far away from the cliff is she when she lands? Remember to show all of the steps that you use to solve the problem.

Answers

SOLUTION

Now the ground is assumed to be 0, so we have that

[tex]y(t)=0[/tex]

So, that means we have

[tex]\begin{gathered} y(t)=-16t^2+100 \\ 0=-16t^2+100 \\ 16t^2=100 \\ t^2=\frac{100}{16} \\ t=\sqrt{\frac{100}{16}} \\ t=\frac{10}{4} \\ t=2.5\text{ seconds } \end{gathered}[/tex]

Now, we have found t, which is how long it takes to get to the ground, you can plug it into x(t) to find the horizontal distance travelled, we have

[tex]\begin{gathered} x(t)=8t \\ x(2.5)=8\times2.5 \\ =20\text{ feet } \end{gathered}[/tex]

Hence it takes her 2.5 seconds to reach the ground

And she is 20 feet away from the cliff

Write the fraction as a percent.34/100

Answers

Answer:

34%

Explanation:

To write the fraction as a percent we need to divide 34 by 100 and then multiply by 100%, so

34/100 x 100 = 0.34 x 100% = 34%

Therefore, 34/100 as a percent is 34%

the angle t is an acute angle and sin t and cost t are given. Use identities to find tan t , csc t, sec t, and cot t. where necessary, rationalize demonstrations.sin t= 7/25, cos t= 24/25

Answers

Answer:

tan t = 7/24

csc t = 25/7

sec t = 25/24

cot t = 24/7

Explanation:

From the question, we're told that sin t = 7/25 and cos t = 24/25. Since we know the identities of sine and cosine to be as follows we can go ahead and determine tan t as shown below;

[tex]\begin{gathered} \sin t=\frac{opposite}{\text{hypotenuse}}=\frac{7}{25} \\ \cos t=\frac{adjacent}{\text{hypotenuse}}=\frac{24}{25} \\ \therefore\tan t=\frac{opposite}{\text{adjacent}}=\frac{7}{24} \end{gathered}[/tex]

Let's go ahead and find cosecant t (csc t);

[tex]\csc t=\frac{1}{\sin t}=\frac{1}{\frac{7}{25}}=1\times\frac{25}{7}=\frac{25}{7}[/tex]

For sec t, we'll have;

[tex]\sec t=\frac{1}{\cos t}=\frac{1}{\frac{24}{25}}=1\times\frac{25}{24}=\frac{25}{24}[/tex]

For cot t;

[tex]\cot t=\frac{1}{\tan t}=\frac{1}{\frac{7}{24}}=1\times\frac{24}{7}=\frac{24}{7}[/tex]

the graph of each function is shown. write the function in factored form . do not include complex numbers

Answers

We can see from the picture that the function f(x) has roots in x = -5 and x = 5. Using sintetic division with x = 5, we get:

then, we can write the function as:

[tex]f(x)=(x-5)(2x^3+11x^2+8x+15)[/tex]

since we know that another root is x = -5,we can use again the sintetic division on the right factor:

therefore, the function in factored form is:

[tex]f(x)=(x-5)(x+5)(2x^2+x+3)[/tex]

Let Events A and B be described as follows:• P(A) = buying popcorn• P(B) = watching a movieThe probability that you watch a movie this weekend is 48% The probability of watching amovie this weekend and buying popcorn is 38%. If the probability of buying popcorn is 42%,are watching a movie and buying popcorn independent?

Answers

Solution:

Given that;

[tex]\begin{gathered} P(A)=42\%=0.42 \\ P(B)=48\%=0.48 \\ P(A\cap B)=38\%=0.38 \end{gathered}[/tex]

To find out if watching a movie and buying a popcorn are independent, the formula is

[tex]\begin{gathered} P(A|B)=\frac{P(A\cap B)}{P(B)}=\frac{0.38}{0.48}=0.79166 \\ P(A|B)=0.79\text{ \lparen two decimal places\rparen} \end{gathered}[/tex]

From the deductions above;

Hence, the answer is

[tex]No,\text{ because }P(A|B)=0.79\text{ and the }P(A)=0.42\text{ are not equal}[/tex]

Graph this steph function on the coordinate grid please help I don’t understand!

Answers

Given:

[tex]f(x)=\begin{cases}{-5\text{ }if\text{ }-5

Required:

We need to graph the given step function.

Explanation:

From the given data we have, -5,-1, and 2 are the respective values of y.

[tex]-5

The draw annulus to denote the points do not lie on the line since there is a symbol '<'.

Final answer:

Ariel makes $35 a day. How much can she get for 1/7 of a day? Ariel will earn ____ for 1/7 of the day.

Answers

We can calculate how much she get for 1/7 of a day by multiplying the daily pay rate by 1/7:

[tex]E=\frac{1}{7}\cdot35=\frac{35}{7}=5[/tex]

Answer: Ariel will earn $5 for 1/7 of the day.

Find the domain and range of the function represented by the graph.
543
domain: -4 ≤ x ≤ 2.
O domain: -4 < x <2.
O domain: -4 ≤ x ≤ 4.
O domain: -4 <
2
range: -4 Sy≤4
range: -4 range: -4 Sy≤2
x < 4. range: -4

Answers

Answer:

c

Step-by-step explanation:

c

P(6,23), Q (13,28)
Distance=?
Midpoint=?

Answers

Answer:

Step-by-step explanation:

distance between the two points:

[tex]\sqrt{ (x_2-x_1)^{2} +(y_2-y_1)^2[/tex]

[tex]\sqrt[/tex](13-6)²+(28-23)²

√(7)²+(5)²

√49+25

√74

distance: 8.6cm

midpoint=

[tex](\frac{x_1+x_2}{2} , \frac{y_1+y_2}{2} )[/tex]

(6+3/2,23+28/2)

(19/2,51/2)

(9.5,25.5)

Given P = $8945, t= 5 yearsand r= 9% compounded monthly. Is the correct compound interest formula to calculate to the nearest cent to the value of a

Answers

For this question, we use the following formula for compounded interest:

[tex]P=a(1+0.09)^{5\cdot12}[/tex]

Solving for a we get:

[tex]\begin{gathered} a=\frac{8945}{(1+0.09)^{60}} \\ a=\frac{8945}{(1.09)^{60}} \\ a=50.81 \end{gathered}[/tex]

Graph each pair of lines and use their slopes to determineif they are parallel, perpendicular, or neither.EF and GH for E(-2, 3), F(6, 1), G(6,4), and H(2,5)JK and LM for J(4,3), K(5, -1), L(-2, 4), and M(3,-5)NP and QR for N(5, -3), P(0, 4), Q(-3, -2), and R(4, 3)ST and VW for S(0, 3), T(0, 7), V(2, 3), and W(5, 3)

Answers

To find the slope of a line that passes through two points, we can use the following formula:

[tex]\begin{gathered} m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}} \\ \text{ Where m is the slope and} \\ (x_1,y_1)\text{ and }(x_2,y_2)\text{ are two points which the line passes} \end{gathered}[/tex]

Then, we have:

First pair of lines

Line EF

[tex]\begin{gathered} (x_1,y_1)=E\mleft(-2,3\mright) \\ (x_2,y_2)=F\mleft(6,1\mright) \\ m=\frac{y_2-y_1}{x_2-x_1} \\ m=\frac{1-3}{6-(-2)} \\ m=\frac{1-3}{6+2} \\ m=\frac{-2}{8} \\ m=\frac{2\cdot-1}{2\cdot4} \\ m=-\frac{1}{4} \end{gathered}[/tex]

Line GH

[tex]\begin{gathered} (x_1,y_1)=G\mleft(6,4\mright) \\ (x_2,y_2)=H\mleft(2,5\mright) \\ m=\frac{y_2-y_1}{x_2-x_1} \\ m=\frac{5-4}{2-6} \\ m=\frac{1}{-4} \\ m=-\frac{1}{4} \end{gathered}[/tex]

Now, when graphing the two lines, we have:

If two lines have equal slopes, then the lines are parallel. As we can see, their slopes are equal, therefore the lines EF and GH are parallel.

Second pair of lines

Line JK

[tex]\begin{gathered} (x_1,y_1)=J\mleft(4,3\mright) \\ (x_2,y_2)=K\mleft(5,-1\mright) \\ m=\frac{y_2-y_1}{x_2-x_1} \\ m=\frac{-1-3}{5-4} \\ m=-\frac{4}{1} \\ m=-4 \end{gathered}[/tex]

Line LM

[tex]\begin{gathered} (x_1,y_1)=L\mleft(-2,4\mright) \\ (x_2,y_2)=M\mleft(3,-5\mright) \\ m=\frac{y_2-y_1}{x_2-x_1} \\ m=\frac{-5-4}{3-(-2)} \\ m=\frac{-9}{3+2} \\ m=\frac{-9}{5} \end{gathered}[/tex]

Now, when graphing the two lines, we have:

As we can see, the slopes of these lines are different, so they are not parallel. Let us see if their respective slopes have the relationship shown below:

[tex]\begin{gathered} m_1=-4 \\ m_2=-\frac{9}{5} \\ m_1=-\frac{1}{m_2} \\ -4\ne-\frac{1}{-\frac{9}{5}} \\ -4\ne-\frac{\frac{1}{1}}{\frac{-9}{5}} \\ -4\ne-\frac{1\cdot5}{1\cdot-9} \\ -4\ne-\frac{5}{-9} \\ -4\ne\frac{5}{9} \end{gathered}[/tex]

Since their respective slopes do not have the relationship shown below, then the lines are not perpendicular.

Third pair of lines

Line NP

[tex]\begin{gathered} (x_1,y_1)=N\mleft(5,-3\mright) \\ (x_2,y_2)=P\mleft(0,4\mright) \\ m=\frac{y_2-y_1}{x_2-x_1} \\ m=\frac{4-(-3)}{0-5} \\ m=\frac{4+3}{-5} \\ m=-\frac{7}{5} \end{gathered}[/tex]

Line QR

[tex]\begin{gathered} (x_1,y_1)=Q\mleft(-3,-2\mright) \\ (x_2,y_2)=R\mleft(4,3\mright) \\ m=\frac{y_2-y_1}{x_2-x_1} \\ m=\frac{3-(-2)}{4-(-3)} \\ m=\frac{3+2}{4+3} \\ m=\frac{5}{7} \end{gathered}[/tex]

Now, when graphing the two lines, we have:

Two lines are perpendicular if their slopes have the following relationship:

[tex]\begin{gathered} m_1=-\frac{1}{m_2} \\ \text{ Where }m_1\text{ is the slope of the first line and }m_2\text{ is the slope of the second line} \end{gathered}[/tex]

In this case, we have:

[tex]\begin{gathered} m_1=-\frac{7}{5} \\ m_2=\frac{5}{7} \\ -\frac{7}{5}_{}=-\frac{1}{\frac{5}{7}_{}} \\ -\frac{7}{5}_{}=-\frac{\frac{1}{1}}{\frac{5}{7}_{}} \\ -\frac{7}{5}_{}=-\frac{1\cdot7}{1\cdot5}_{} \\ -\frac{7}{5}_{}=-\frac{7}{5}_{} \end{gathered}[/tex]

Since the slopes of the lines NP and QR satisfy the previous relationship, then this pair of lines are perpendicular.

Fourth pair of lines

Line ST

[tex]\begin{gathered} (x_1,y_1)=S\mleft(0,3\mright) \\ (x_2,y_2)=T\mleft(0,7\mright) \\ m=\frac{y_2-y_1}{x_2-x_1} \\ m=\frac{7-3_{}}{0-0} \\ m=\frac{4}{0} \\ \text{Undefined slope} \end{gathered}[/tex]

The line ST has an indefinite slope because it is not possible to divide by zero. Lines that have an indefinite slope are vertical.

Line VW

[tex]\begin{gathered} (x_1,y_1)=V\mleft(2,3\mright) \\ (x_2,y_2)=W\mleft(5,3\mright) \\ m=\frac{y_2-y_1}{x_2-x_1} \\ m=\frac{3-3_{}}{5-2} \\ m=\frac{0}{3} \\ m=0 \end{gathered}[/tex]

Line VW has a slope of 0. Lines that have a slope of 0 are horizontal.

Now, when graphing the two lines, we have:

As we can see in the graph, the ST and VW lines are perpendicular.

√54²-43.8² +2(7)
What is the height of the space Lilly needs? Round to the nearest hundredth.
18.52
24.20
45.58
235.06

Answers

√54²-43.8² +2(7)

54-1918.44+14

-1850.44

The first three terms of a sequence are
given. Round to the nearest thousandth
(if necessary).
4, 8, 12,..
Find the 40th term

Answers

Answer:

Step-by-step explanation:

Recall the formula for an arithmetic sequence: [tex]a_{n} =a_{1} +d(n-1)[/tex]

Where d is the common difference and a_1 is the first term of the sequence.

You are given :

a_1=4

a_2=8

a_3=12

Next is to find the common difference d.

To find the common difference, take the next term and subtract it from the current term.

a_2-a_1=8-4=4

Let try the next term start at a_2

a_3-a_2=12-8 =4

Do you see the pattern?

The patter is going up by 4 each time. So the common difference is 4 i.e d=4

Now we just need to plug into the generalize formula above and get

[tex]a_{n}=4+4(n-1)[/tex]

The question asked for the 40th term. Plug 40 into the formula and you will get:

[tex]a_{40}=4+4(40-1)=160[/tex]

I hope this helps!

I need help with this practice problem I’m having trouble

Answers

Part N 1

[tex]2^{(6\log _22)}=12[/tex]

Apply property of log

[tex]\log _22=1[/tex]

so

[tex]\begin{gathered} 2^{(6\cdot1)}=12 \\ 2^6=12\text{ -}\longrightarrow\text{ is not true} \end{gathered}[/tex]

the answer is false

Part N 2

we have

[tex]\frac{1}{4}\ln e^8=\sqrt[4]{8}[/tex]

applying property of log

[tex]\frac{1}{4}\ln e^8=\frac{8}{4}\ln e=2\ln e=2[/tex]

so

[tex]2=\sqrt[4]{8}\text{ ---}\longrightarrow\text{ is not true}[/tex]

the answer is false

Part N 3

we have

[tex]10^{(\log 1000-2)}=10[/tex]

log1000=3

so

log1000-2=3-2=1

10^1=10 -----> is true

the answer is true

Choose all equivalent expression ( s). (4) ^ (3z ^ 2); (4) ^ (- 3x ^ 2); (1/4) ^ (3z ^ 2); (pi/4) ^ (3x)

Answers

Among the given options, no one is an equivalent expression.

What is an equivalent expression?

Expressions are said to be equivalent if they do the same thing even when they have distinct appearances. When we enter the same value(s) for the variable, two algebraic expressions that are equivalent have the same value (s).

In the given options no one satisfies the property of an equivalent expression.

Therefore, among the given options, no one is an equivalent expression.

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A wind-up toy car can travel 5 yards in about 3 minutes. If the car travels at a constant speed, then how many minutes will it takes to travel 40 meters? State your answer to the nearest minute.( 1 yard = 0.92 meters)

A) 20
B) 22
C) 24
D) 26

Answers

Answer: D

Step-by-step explanation:

0.92 metres =   1 yard

 40 metres  = 43.5 yard [tex](\frac{40 * 1}{0.92})[/tex]

  5 yards   :  3 minutes

43.5 yards :  26.1 minutes [tex](\frac{43.5*3}{5})[/tex]

26.1 mins ≈ 26 mins

Create a graph system of linear equations that model this situation.

Answers

x represents the number of packages of coffee sold

y represents the number of packages of pastry sold

We were the cost of a package of coffee is $6 and the cost of a package of pastry is $4. If the total amount made from selling x packages of coffee and y packages of pastry is $72, then the equation representing this scenario is

6x + 4y = 72

Also, we were told that she sold 2 more packages of coffee than pastries. This means that

x = y + 2

Thus, the system of linear equations is

6x + 4y = 72

x = y + 2

We would plot these equations on the graph. The graph is shown below

The red line represents x = y + 2

The bu line represents x = y + 2


5 A salesman sold $1,500 worth of
merchandise and received $75 in
commission for the sale.What percent of the sale was commission

Answers

Answer:20%

Step-by-step explanation:

1500/75=20(%)

Other Questions
your business advisor, a consulting company, does not use reversing entries. on march 31, 2024, the bookkeeper journalized and posted an adjusting entry for $300 to salaries payabl What is the length of cd ? Please help Name the reciprocals of each equation Equations in picture For the line y = 1 - 3x, create a table to show the values of x and y where x is from -2 to 2. A company is constructing an open-top, square-based, rectangular metal tank that will have a volume of 48.5 (ft) with superscript (3). What dimensions yield the minimum surface area? Round to the nearest tenth, if necessary. What is an important river for cultural and religious diffusion in India? What resulted in the building of a network of roads, an increase in trade and travel and the spread of common language on the Italic peninsula?A. the appointment of Cincinnatus as directorB. the gradual unification of the Italian peninsula under Roman ruleC. the inscription of law on the Twelve TableD. the reverence given to Romulus and Remus as Rome's founders In Thoreau's view, what kind of lives do most people lead? what is the economic benefit of having uniformity between states with regard to contracts for the sale of goods, and what motivates state legislatures to adopt statutes proposed by independent bodies like the nccusl? Margaret drove to a business appointment at 70 mph. Her average speed on the return trip was 60 mph. The return took hr longer because of heavy traffic. How far did she travel to the appointment ? Carlos does a chin-up in gym class and raises himself 0.8 m. If Carlos has a mass of 62 kg how much work does he accomplish? How can Leslie balance her presentation slide so it is easier to read? air is contained in a rigid tank with a volume of 2 m3, initially at 10 bar and 300 k. heat is transferred to the tank until its temperature reaches 400 k. during this process a pressure-relief valve allows air to escape and maintain the pressure constant at 10 bar. neglecting kinetic and potential energy variation eects, and using ideal gas equations with constant specific heat at 300 k, determine, (a) the mass of air that escapes the tank (in kg), and (b) the amount of heat transferred to the tank. Please help!!!!Ill give you the Brainiest A triangle has height 4ft and area 32 ft. What is the length of its base? Give a polynomial of degree 3 that has zeros of 18, 10i, and 10i, and has a value of 3434 when x=1. Write the polynomial in standard form axn+bxn1+. which one of the following is not a type of qualitative forecasting? which one of the following is not a type of qualitative forecasting? historical analogy customer survey nave method jury of executive opinion Ill give brainleast Environmental Accidents Portfolio Directions:You have just learned about several human-caused environmental accidents, including the 1986 nuclear plant meltdown in Chernobyl and the 1989 oil spill in the Gulf of Alaska. Use the Internet to research one human-caused environmental accident that is not mentioned in this lesson. Write an essay of 400-500 words that addresses the following Identify when and where the accident occurred Describe how the accident occurred. Describe.how the accident affected the environment. 'Explain how environmentalists responded to the accident. Explain whether or not the environment is still affected by the accident today Source citation (3 pts - all or none) Length (1 pt - all or none) Grammar (1 pt - all or none) D. Explain what the total fertility rate and the infant mortality rate imply about the roles ofwomen in the countries listed in the table. Write an argumentative essay in which you state and defend a claim about whether it is ethical to target uninformed consumers.If anyone does it can you make it at least 2 paragraphs PLEASE How does president carters diction help establish his perspective about the necessity of citizens and government working together toward common goals?.