50 Points! Multiple choice algebra question. Photo attached. Thank you!

The requreid, as per the given percentage condition Mia tips the movers $80.

To find the amount of the tip, we need to calculate 16% of the total cost of the services, which is $500.

16% of $500 = 0.16 x $500 = $80

Therefore, Mia tips the movers $80.

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The median, mode and range for both dot plots are:

The median

This is the middle value

From the dot plots, we have the middle values to be

Group A = (7 + 8)/2 = 7.5

Group B = 5

So, we have

Median Group A = 7.5

Median Group B = 5

The mode

This is the number of books with the highest dots

From the dot plots, we have the modal values to be

Mode Group A = 7 and 8

Mode Group B = 4 and 5

The range

This is the difference between the smallest and highest number of books with the highest dots

From the dot plots, we have the range to be

Group A = 9 - 6 = 3

Group B = 10 - 3 = 7

So, we have

Range Group A = 3

Range Group B = 7

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As per the question of trigonometry the another equation that describes the given graph is

y = -cos5x. And after verifying the equation given in the question as well as the new equation we conclude that both equations are equal.

The sine and cosine function graphs' main characteristics are:  

a. We can use trigonometric identities to simplify the given equation in order to describe the graph using a different equation.

b. We can simplify the following equation and compare it with  [tex]y = -cos(5x)[/tex]to see if the two equations are equivalent.

We obtain this by applying the same trigonometric identity as before.

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The journal entry to record the sale of the equipment would be:Cash $105,800,Loss on Sale of Equipment $35,650,Equipment $212,000

Accumulated Depreciation $66,000

How to solve the question?

a. To calculate the book value of the equipment at December 31 of the fifth year, we need to determine the accumulated depreciation for the first five years. The annual depreciation expense is calculated as follows:

Depreciation Expense = (Cost - Residual Value) / Useful Life

Depreciation Expense = ($212,000 - $14,000) / 15

Depreciation Expense = $13,200 per year

The accumulated depreciation for five years is therefore:

Accumulated Depreciation = Depreciation Expense x Number of Years

Accumulated Depreciation = $13,200 x 5

Accumulated Depreciation = $66,000

The book value of the equipment at December 31 of the fifth year is calculated as follows:

Book Value = Cost - Accumulated Depreciation

Book Value = $212,000 - $66,000

Book Value = $146,000

b.

To record depreciation for the three months until the sale date, we need to calculate the depreciation expense for the sixth year. The annual depreciation expense remains the same at $13,200, but since the equipment was sold on April 1, we need to prorate the depreciation for the first three months of the year.

Depreciation Expense for the Sixth Year = Depreciation Expense x (Months Remaining / 12)

Depreciation Expense for the Sixth Year = $13,200 x (9 / 12)

Depreciation Expense for the Sixth Year = $9,900

The journal entry to record depreciation for the three months until the sale date would be:

Depreciation Expense $9,900

Accumulated Depreciation $9,900

To record the sale of the equipment, we need to compare the sale price to the book value of the equipment at the time of the sale.

The book value of the equipment at the time of the sale is calculated as follows:

Book Value = Cost - Accumulated Depreciation

Book Value = $212,000 - ($13,200 x 5.25)

Book Value = $141,450

Since the sale price of $105,800 is less than the book value of $141,450, we need to record a loss on the sale of the equipment. The journal entry to record the sale of the equipment would be:

Cash $105,800

Loss on Sale of Equipment $35,650

Equipment $212,000

Accumulated Depreciation $66,000

The cash received from the sale is debited, and the difference between the sale price and the book value is recorded as a loss on the sale of the equipment. The equipment and its accumulated depreciation are removed from the books.

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A function's codomain is a subset of its range. Although it is not a true subset, it is conceivable for the range to be equal to the codomain, in which case it is also a subset of the codomain.

A set that includes all or a portion of another set's elements is known as a subset. For instance, because every even integer is also an integer, the set of even integers is a subset of the set of integers. A subset that contains some, but not all, of the members of another set is said to be a proper subset. Because it contains some, but not all, of the positive integers, the set of positive integers less than 10 is a valid subset of the set of positive integers.

A function's codomain is a subset of its range. Although it is not a true subset, it is conceivable for the range to be equal to the codomain, in which case it is also a subset of the codomain.

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Given:

[tex]\vec F_{1} =27 \ N[/tex]

[tex]\vec F_{2} =24 \ N[/tex]

[tex]\vec a_{1} = 9 \ m/s^2[/tex]

Find:

[tex]\vec a_{2} = ?? \ m/s^2[/tex]

We know that [tex]\vec F= m \vec a[/tex]. Use [tex]\vec F_{1}[/tex] and [tex]\vec a_{1}[/tex] to find mass, m.

[tex]\Longrightarrow \vec F_{1} = m \vec a_{1} \Longrightarrow 27= m(9) \Longrightarrow m= \frac{27}{9} \Longrightarrow m= \boxed{ 3 \ kg }[/tex]

We now know the mass of the moving object we can now find [tex]\vec a_{2}[/tex].

[tex]\Longrightarrow \vec F_{2} = m \vec a_{2} \Longrightarrow 24= (3) \vec a_{2} \Longrightarrow \vec a_{2}= \frac{24}{3} \Longrightarrow \vec a_{2}= \boxed{ 8 \ m/s^2 } \ \therefore \ Sol.[/tex]

The number of subsets that the set has are 128 subsets.

First, let's remove the duplicates from the set A. The distinct elements in set A are:

A = {a, r, i, t, m, e, c}

Now, we can find the number of subsets. For each element in the set, we have two choices: either it is included in the subset, or it is not. Therefore, there are 2^n subsets for a set with n distinct elements.

In our case, n = 7, so there are 2^7 = 128 subsets for the given set A.

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The correct option is C. mean, that is Mr. Greene should use the mean temperature, which is 77.86°F.

In mathematics, the mean value is a measure of central tendency of a set of numbers. It is also known as the arithmetic mean and is found by adding all the numbers in a set and dividing the sum by the total number of values. The mean is commonly used to represent the typical or average value of a set of data. It is a useful tool in statistics and other branches of mathematics for analyzing data and making predictions. The mean value can be affected by outliers or extreme values in a set of data, which can skew the results. However, in many cases, the mean provides a reliable and useful measure of central tendency.

Mr. Greene should use the mean temperature, which is 77.86°F, to summarize the temperatures for each day. The mean is a good measure of central tendency when the data set is approximately symmetric and has no significant outliers, which appears to be the case here. Additionally, using the mean will provide a single number that is representative of the entire data set. The interquartile range and mean absolute deviation are measures of spread and do not provide a summary of the temperatures for each day, and the maximum temperature is just one value and may not be representative of the entire data set.

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Answer:

a) The scale factor is [tex]\frac{4}{5}[/tex]

b) [tex]t=5\frac{3}{5}[/tex]

Step-by-step explanation:

The scale factor from shape A to shape B is the value that is multiplied by the side measures of shape A to arrive at the side measures of shape B.

In other words, 5 times a certain value is 4, 15 times a certain value is 12. and 7 times a certain value is t.

Let's start by calling our "certain value" k.

[tex]5k=4=\\k=\frac{4}{5}[/tex]

Let's check 15 to make sure k is 4/5, like so:

[tex]15(\frac{4}{5})=\\\frac{60}{5} =\\12[/tex]

Since 15 times 4/5 is twelve, our initial answer was correct.

So, the scale factor, or k, is 4/5.

Following this logic, we know that 7 multiplied by the scale factor is equal to t.

Let's set up an equation and solve for t:

[tex]7(\frac{4}{5} )=t=\\\frac{28}{5} =t=\\5\frac{3}{5} =t[/tex]

So, [tex]t=5\frac{3}{5}[/tex]

Answer:

C.

Step-by-step explanation:

because x value cannot be repeated in an ordered pair

Answer: 2

Step-by-step explanation:

Answer:

2 lines of symmetry.

The Addition Property of Equality allows us to add EF to both sides of the equation without changing its truth, giving us AB + EF = CD + EF.

We have,

The Addition Property of Equality states that if we add the same quantity to both sides of an equation, the equation remains true.

In the given equation,

AB = CD, we can add the same quantity, EF, to both sides of the equation to obtain:

AB + EF = CD + EF

This is because if two quantities are equal, and we add the same amount to both of them, the result is still equal.

Therefore,

The Addition Property of Equality allows us to add EF to both sides of the equation without changing its truth, giving us AB + EF = CD + EF.

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The measure of arc angle QT is determined as 142 ⁰.

The measure of m∠STR is determined as 23⁰.

The measure of angle subtended by the arc QT is calculated by applying the following formula.

Based on the angle of intersecting chord theorem, we will have the following equation.

m∠QST = ¹/₂( arc QT )

arc QT = 2 (m∠QST)

arc QT = 2 x 71⁰

arc QT = 142⁰

m∠STR = ¹/₂( arc SR )

m∠STR = ¹/₂ x 46⁰

m∠STR = 23⁰

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Answer:

The answer to (m+3)(m-3) is m^2-9.

Step-by-step explanation:

We will use distributive law to solve this question.

m(m-3)+3(m-3)

= m^2-3m+3m-9

= m^2-9 (since, 3m-3m=0)

As an alternative method, we can use the direct rule learned in algebra: (a+b)(a-b)=a^2-b^2.

so, here a=m and b=3.

(m+3)(m-3)

=m^2-3^2

=m^2-9

The distance traveled by the wheel when it turns 20 times is 150.7964 feet.

What is circumference?

The circumference of a wheel can be calculated as:

Circumference = 2 x π x radius

where π (pi) is a mathematical constant approximately equal to 3.14159.

The distance traveled by a wheel when it turns is equal to the circumference of the wheel multiplied by the number of times it turns.

Given that the radius of the wheel is 1.2 feet, the circumference of the wheel is:

Circumference = 2 x π x radius

Circumference = 2 x 3.14159 x 1.2

Circumference = 7.53982 feet (rounded to 5 decimal places)

Therefore, each time the wheel turns, it travels a distance of 7.53982 feet. To find the distance traveled when the wheel turns 20 times, we can multiply the distance traveled each time by the number of times the wheel turns:

Distance traveled = Circumference x Number of turns

Distance traveled = 7.53982 feet x 20

Distance traveled = 150.7964 feet (rounded to 4 decimal places)

Therefore, the distance traveled by the wheel when it turns 20 times is 150.7964 feet.

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By using the properties of logarithms, The logarithm "log₅(98)" can be written as log₅(2) + log₅(7) + log₅(7).

We use the "product' and "quotient" logarithmic identities to write log₅(98) in terms of log₅(2) and log₅(7):

⇒ logₐ(b × c) = logₐ(b) + logₐ(c)      ....(product rule)

⇒ logₐ(b/c) = logₐ(b) - logₐ(c)           ...(quotient rule)

First, we write the number "98" as the product of 2 and 7, which is :

⇒ log₅(98) = log₅(2 × 7 × 7),

Using the product rule, we can split this into three logarithms;

⇒ log₅(2 × 7 × 7) = log₅(2) + log₅(7) + log₅(7),

So, we have,

⇒ log₅(98) = log₅(2) + log₅(7) + log₅(7),

Therefore, log₅(98) is equal to log₅(2) + log₅(7) + log₅(7).

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The given question is incomplete, the complete question is

Use the properties of logarithms to write the logarithm in terms of log₅(2) and log₅(7).

The logarithm is log₅(98).

The eight letters in the word DECEIVED may be arranged in 4200 distinct ways, with two Ds grouped together and three Es not all together.

The following approach may be used to determine how many different ways there are for the eight letters in the word DECEIVED to be arranged such that two Ds are together and three Es are not altogether:

7! - 6! - 5! = 5040 - 720 - 120 = 4200

Therefore, there are 4200 different arrangements of the 8 letters in the word DECEIVED, in which two Ds are together and the three Es are not all together.

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Answer:

dependent

Step-by-step explanation:

its dependent because the names getting pulled depends on the names pulled first

The confidence interval can be expressed as a trilinear inequality: 82.9% < p < 95.7%.

The confidence interval in interval form is (0.1864, 0.3026).

The given confidence interval, 89.3% ± 6.4%, means that we are 89.3% confident that the true value of the population parameter lies within a range of 6.4% above and below the sample estimate.

To express this in the form of a trilinear inequality, first find the upper and lower bounds of the interval.

Upper bound = 89.3% + 6.4% = 95.7%

Lower bound = 89.3% - 6.4% = 82.9%

Therefore, the confidence interval 89.3% ± 6.4% can be expressed in the form of a trilinear inequality as:

82.9% < p < 95.7%

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Answer:

4. b/c

Step-by-step explanation:

In a right-angled triangle with sides of lengths a, b, and c, where c is the hypotenuse (the side opposite the right angle), the sine of the angle opposite side b (angle B) is given by:

Sin theta : Opposite/hypotenuse

sin(B) = b/c

Therefore, the answer is 4. b/c

The correct statement is option a) The height of the terrain can measure between 2 meters and 10 meters.

Let the base of the triangular piece of land be x meters. Then, the height of the triangular plot is (x+2) meters.

The area of a triangle is given by the formula: A = (1/2)bh, where b is the base and h is the height.

Substituting the given values:

A = (1/2)x(x+2)

Simplifying:

A = (1/2)(x² + 2x)

Since the area is less than 40 m², write:

(1/2)(x² + 2x) < 40

Multiplying both sides by 2:

x² + 2x < 80

Rearranging and factorizing:

x² + 2x - 80 < 0

(x+10)(x-8) < 0

The roots of the quadratic equation are -10 and 8. Since the coefficient of x² is positive, the parabola opens upwards and is negative in between the roots. Therefore, the inequality is true when -10 < x < 8.

However, x cannot be negative, so the base of the triangular terrain is between 0 and 8 meters.

Substituting the values in the expression for the height, the height is between 2 and 10 meters.

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A quadratic equation with opposite solutions can be found by multiplying a variable by its negative value. Specifically, if we start with a quadratic equation of the form:

ax^2 + bx + c = 0

We can find an equation with opposite solutions by multiplying either a or c by -1. For example, if we multiply c by -1, we get:

ax^2 + bx - c = 0

This equation will have opposite solutions if the discriminant, b^2 - 4ac, is negative. This is because the solutions of a quadratic equation are given by the formula:

x = (-b ± sqrt(b^2 - 4ac)) / (2a)

Thus, if the discriminant is negative, then the square root term will be imaginary, which means that the solutions will be complex conjugates of each other.

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The calculated value of sec^-1(1.4) is 44.41 degrees

The inverse secant function, denoted as sec^-1(x), returns the angle whose secant is x.

In other words, if secθ = x, then sec^-1(x) = θ.

To find the value of sec^-1(1.4), we need to find the angle whose secant is 1.4.

However, we know that the range of the secant function is [-∞, -1] ∪ [1, ∞], which means that sec^-1(x) is only defined for values of x that fall within this range.

Uisng a graphint tool, we have

sec^-1(1.4) = 44.41

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Answer:

13

Step-by-step explanation:

By counting the amount of dots there is on the graph you would end up with 13 trees.

A diagram that represents the expression |-5| include the following: A. graph A.

In Mathematics and Geometry, a number line simply refers to a type of graph with a graduated straight line which comprises both positive and negative numbers that are placed at equal intervals along its length.

This ultimately implies that, a number line primarily increases in numerical value towards the right from zero (0) and decreases in numerical value towards the left from zero (0).

Since the absolute value of -5 or |-5|, an inequality that matches this graph is represented by the first diagram.

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Missing information:

The question is incomplete and the complete question is shown in the attached picture.

The distance from the center are equal,

x = 6

The value of x is solved using the relationship existing between chords and the bisectors.

It will be noted that the line from the center

In the figure, since the chords are equal and the line from the center are perpendicular bisectors then the line from the center are equal.

we can therefore say that x = 6

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Because it gives exactly one output value for each input value, a(x) is a function, hence the answer is yes. Since several input values might result in the same output value, it is not a one-to-one function.

A mathematical item called a function accepts an input and creates an output. It looks like an apparatus with an input and an output. A formula or a graph can both be used to express a function. For instance, the function f(x) = x² returns the square of an input x as output.

Because it gives exactly one output value for each input value, a(x) is a function, hence the answer is yes. Since several input values might result in the same output value, it is not a one-to-one function. A(x) is not one-to-one, for instance, because a(1) and a(3) are both equal to 1.

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The correct equation to use is "s - 2.3 = 6.8", where s represents the distance Sam ran.

Distance is a measurement of how far apart two objects or points are from each other. It is usually measured in units such as meters, kilometers, miles, or feet. Distance can refer to physical space between two points, or it can be used to describe the extent of an abstract concept, such as a difference in opinion or a cultural divide.

The Situation column should have two entries: "finding part of a total" and "difference".

The Operation column should have only one entry: "minus".

The right formula is "s - 2.3 = 6.8", where s stands for the distance Sam ran.

To solve for s, we can add 2.3 to both sides of the equation:

s - 2.3 + 2.3 = 6.8 + 2.3

s = 9.1

Therefore, Sam ran 9.1 kilometers.

So, the Situation entries are: "difference" and "finding part of a total".

The Operation entry is: "minus".

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The horizontal component of the force is approximately 80.34 N, and the vertical component of the force is approximately 74.62 N.

The force can be broken down into its horizontal and vertical components using trigonometry.

Horizontal component:

cos(42) = adjacent/hypotenuse

adjacent = cos(42) * 110 N

adjacent ≈ 80.34 N

Vertical component:

sin(42) = opposite/hypotenuse

opposite = sin(42) * 110 N

opposite ≈ 74.62 N

Therefore, the horizontal component of the force is approximately 80.34 N, and the vertical component of the force is approximately 74.62 N.

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