5. What is the coefficient of the variable n?

- tan(50) → Choice A

Step-by-step explanation:

tan(-α) = - tan(α)

tan(-50) = - tan(50)

Further more :

tan (-50) = - tan (50) ≈ 0,27

Let's say c is the cost of the cantaloupe, and that p is how many pounds the cantaloupe weights.

In that case, $1.19 is the amount of money it will cost per pound of cantaloupe.

If the cantaloupe you buy is 3.5 pounds, it will cost you $4.165, but since money is only two decimal places, and since you can only round up when it's a 5 at the end, it becomes $4.17.

In other words, each pound of cantaluope you buy will cost you $1.19, and a cantaloupe that weighs 3.5 pounds will cost you $4.17.

Answer:

(258÷3) - 10 = 76.

Step-by-step explanation:

You need to use this equation to find this answer even though I already wrote the answer there for you.

The graphical relationship of the demand and price of brie are given in the two graphs

Reason:

The given parameters are;

The graphs gives the utility-maximizing combinations of bread and brie chosen by Hayden

The price of the loaf = $1.00

The prices of the brie are $4.00 and $6.00 per wheel

Given that as the price increases from $4.00 to $6.00, the quantity

demanded increases, we have;

When the price is $4.00, the quantity of brie demanded 23.84 brie wheels,

and the quantity of bread demanded is 15.9 bread loaves

When the price increases to $6.00, the quantity of brie demanded

decreases to 7.49 brie wheels, while the quantity of bread demanded

increases to 25.2 loaves

Therefore; we have;

At point A, the price is $4.00 and the quantity demanded is 23.84

At point B, the price is $6.00 and the quantity demanded is 7.49

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Answer:

54

Step-by-step explanation:

the ladder need to be 54 feet high

Answer:

x + 93 = 124

Step-by-step explanation:

4x = x + 93  {Vertically opposite angles are equal}

Subtract 'x' from both sides

4x - x = 93

3x = 93

Divide both sides by 3

x = 93/3

x = 31

x + 93 = 31+ 93 = 124

9514 1404 393

Answer:

  -2/a^3

Step-by-step explanation:

Anything (except 0) to the 0 power is 1, so b^0 = 1. This immediately simplifies the expression to -2a^-3. If you also want it with positive exponents, this will be ...

  -2/a^3

Answer:

Pencil on y: 5.5 then 3 down and 1 to the right. (You can trace a line with 2 points, but can continue the pattern: 3 down, 1 to the right)

Step-by-step explanation:

y- intercept = 1 - (3/2)(-3)

y-intercept = 1 + 9/2 = 11/2 = 5.5

y = 3/2x + 11/2

the answer would be c because the angles are equal to each other

Step-by-step explanation:

think it is 1.0000100011000 x10 rise the power negative 3

Answer:

b

Step-by-step explanation:

The sum of angles 7 and 8 is 180, so to find angle 8 you would subtract angle 7 from 180. So:

180 - 92 = 88  

The answer is B, 88 degrees.

Answer:

88° is your answer......

I believe the given limit is

[tex]\displaystyle \lim_{x\to\infty} \bigg(\sqrt[3]{3x^3+3x^2+x-1} - \sqrt[3]{3x^3-x^2+1}\bigg)[/tex]

Let

[tex]a = 3x^3+3x^2+x-1 \text{ and }b = 3x^3-x^2+1[/tex]

Now rewrite the expression as a difference of cubes:

[tex]a^{1/3}-b^{1/3} = \dfrac{\left(a^{1/3}-b^{1/3}\right)\left(a^{2/3}+a^{1/3}b^{1/3}+b^{2/3}\right)}{\left(a^{2/3}+a^{1/3}b^{1/3}+b^{2/3}\right)} \\\\ = \dfrac{a-b}{a^{2/3}+a^{1/3}b^{1/3}+b^{2/3}}[/tex]

Then

[tex]a-b = (3x^3+3x^2+x-1) - (3x^3-x^2+1) \\\\ = 4x^2+x-2[/tex]

The limit is then equivalent to

[tex]\displaystyle \lim_{x\to\infty} \frac{4x^2+x-2}{a^{2/3}+(ab)^{1/3}+b^{2/3}}[/tex]

From each remaining cube root expression, remove the cubic terms:

[tex]a^{2/3} = \left(3x^3+3x^2+x-1\right)^{2/3} \\\\ = \left(x^3\right)^{2/3} \left(3+\dfrac3x+\dfrac1{x^2}-\dfrac1{x^3}\right)^{2/3} \\\\ = x^2 \left(3+\dfrac3x+\dfrac1{x^2}-\dfrac1{x^3}\right)^{2/3}[/tex]

[tex](ab)^{1/3} = \left((3x^3+3x^2+x-1)(3x^3-x^2+1)\right)^{1/3} \\\\ = \left(\left(x^3\right)^{1/3}\right)^2 \left(\left(3+\dfrac3x+\dfrac1{x^2}-\dfrac1x\right)\left(3-\dfrac1x+\dfrac1{x^3}\right)\right)^{1/3} \\\\ = x^2 \left(9+\dfrac6x-\dfrac1{x^3}+\dfrac4{x^4}+\dfrac1{x^5}-\dfrac1{x^6}\right)^{1/3}[/tex]

[tex]b^{2/3} = \left(3x^3-x^2+1\right)^{2/3} \\\\ = \left(x^3\right)^{2/3} \left(3-\dfrac1x+\dfrac1{x^3}\right)^{2/3} \\\\ = x^2 \left(3-\dfrac1x+\dfrac1{x^3}\right)^{2/3}[/tex]

Now that we see each term in the denominator has a factor of x ², we can eliminate it :

[tex]\displaystyle \lim_{x\to\infty} \frac{4x^2+x-2}{a^{2/3}+(ab)^{1/3}+b^{2/3}} \\\\ = \lim_{x\to\infty} \frac{4x^2+x-2}{x^2 \left(\left(3+\dfrac3x+\dfrac1{x^2}-\dfrac1{x^3}\right)^{2/3} + \left(9+\dfrac6x-\dfrac1{x^3}+\dfrac4{x^4}+\dfrac1{x^5}-\dfrac1{x^6}\right)^{1/3} + \left(3-\dfrac1x+\dfrac1{x^3}\right)^{2/3}\right)}[/tex]

[tex]=\displaystyle \lim_{x\to\infty} \frac{4+\dfrac1x-\dfrac2{x^2}}{\left(3+\dfrac3x+\dfrac1{x^2}-\dfrac1{x^3}\right)^{2/3} + \left(9+\dfrac6x-\dfrac1{x^3}+\dfrac4{x^4}+\dfrac1{x^5}-\dfrac1{x^6}\right)^{1/3} + \left(3-\dfrac1x+\dfrac1{x^3}\right)^{2/3}}[/tex]

As x goes to infinity, each of the 1/x ⁿ terms converge to 0, leaving us with the overall limit,

[tex]\displaystyle \frac{4+0-0}{(3+0+0-0)^{2/3} + (9+0-0+0+0-0)^{1/3} + (3-0+0)^{2/3}} \\\\ = \frac{4}{3^{2/3}+(3^2)^{1/3}+3^{2/3}} \\\\ = \frac{4}{3\cdot 3^{2/3}} = \boxed{\frac{4}{3^{5/3}}}[/tex]

Answer:

where is the graph?........

The cauliflower for one portion cost $6.75.

The first step is to convert pounds to ounces. The unit of conversion of pounds to ounces is 1 pound is equivalent to 16 ounces.

1 pound = 16 ounces

Therefore, 16 ounces of cauliflower costs $18.

The cost of one ounce = 18 / 16 = $1.125

The cost of one portion of cauliflower is:

Cost of one ounce x number of ounces in one portion

$1.125 x $6 = $6.75

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[tex]\large\underline{\sf{Solution-}}[/tex]

#1

Solving by submitting method:

[tex]\sf \leadsto 5x - 4y = 9 \: \: - - - (i)[/tex]

[tex]\sf \leadsto x - 2y = -3 \: \: - - - (ii)[/tex]

By first equation,

[tex]\sf \leadsto 5x - 4y = 9[/tex]

[tex]\sf \leadsto 5x = 9 + 4y[/tex]

[tex]\sf\leadsto x = \frac{9+4y}{5}\\[/tex]

Now, we can find the original value of y from Eqⁿ (ii).

[tex]\sf \leadsto x - 2y = -3[/tex]

[tex]\sf \leadsto \bigg(\frac{9+4y}{5}\bigg) - 2y = -3\\[/tex]

[tex]\sf \leadsto \frac{9+4y-10y}{5} = -3\\[/tex]

[tex]\sf \leadsto \frac{9-6y}{5}= -3\\[/tex]

[tex]\sf \leadsto 9-6y = -3(5)[/tex]

[tex]\sf \leadsto 9 -6y = - 15[/tex]

[tex]\sf \leadsto -6y = - 15 - 9[/tex]

[tex]\sf \leadsto -6y = -6[/tex]

[tex]\sf \leadsto y = \frac{\cancel-6}{\cancel-6}\\ [/tex]

[tex]\sf \leadsto y = \dfrac{ 6}{ 6} \\[/tex]

[tex]\sf \leadsto y = 1[/tex]

Now, we can find the original value of x , from Eqⁿ (I)

[tex]\sf \leadsto 5x-4y = 9[/tex]

[tex]\sf \leadsto 5x - 4(1) = 9[/tex]

[tex]\sf \leadsto 5x - 1 = 9[/tex]

[tex]\sf \leadsto 5x = 9+1[/tex]

[tex]\sf \leadsto 5x = 10[/tex]

[tex]\sf \leadsto x = \frac{10}{5}\\[/tex]

[tex]\sf \leadsto x = 5[/tex]

Therefore, the values of x and y are 5 and 1 respectively.

#2

Solving by Eliminating method:

[tex]\sf \leadsto 4x + 6y = 12\:\:- - - (i)[/tex]

[tex]\sf \leadsto 6x+9y = 12 \:\: - - -(ii)[/tex]

Step 1: Multiply Eqⁿ (I) by 3 and Eqⁿ (ii) by 2 to make the coefficients of y equal. Then we get the equations.

[tex]\sf \leadsto 12x + 18y = 36\:\: - - - (iii) [/tex]

[tex]\sf \leadsto 12x + 18y = 24\:\:- - - (iv)[/tex]

Step 2: Subtract Eqⁿ (iii) from Eqⁿ (iv) , we get

[tex]\sf \leadsto (12x + 18y)-(12x + 18y) = 36-24[/tex]

[tex]\sf \leadsto 0 =12, Which is a false statement. [/tex]

Therefore, the pair of equations has no solution.

Hope this helps!!

Answer:

$7

Step-by-step explanation:

Wyatt will have $7 more in his account than Sophie.

Compound interest is the interest you earn on interest.

Given that, Sophie invested $170 in an account paying an interest rate of [tex]2\tfrac{3}{4}[/tex]% compounded continuously.

Wyatt invested $170 in an account paying an interest rate of [tex]3\tfrac{1}{8}[/tex]% compounded monthly.

We need to find how much more money would Wyatt have in his account than Sophie after 9 years,

For compounded continuously = [tex]Amount = Principal \times e^{rt[/tex]

Sophie =

[tex]Amount = 170 \times e^{0.0275 \times 9[/tex]

A = $217.74

Therefore, Sophie will have $217.74 in her account after 9 years.

For Wyatt,

So, using the formula of CI,

[tex]Amount = Principal(1+r/n)^{nt[/tex]

So,

[tex]= 170(1.0026)^{108[/tex]

A = $225

Therefore, Wyatt will have $225 in his account after 9 years.

The amount Wyatt have more than Sophie = 225-217.74 = $7.26 ≈ $7.

Hence Wyatt will have $7 more in his account than Sophie.

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#SPJ2

Goodluck

Step-by-step explanation:

Answer:

The decimal point should be moved 4 places to the right

Step-by-step explanation:

38.75x10000= 387500

Answer:

Q1. 3.14 × 0.8 = 2.512

Q2. 6.28 × 6.8 = 42.704

Q3. 25.5 × 9.3 = 237.15

Q4. 1.3 × 5.7 = 7.41

Q5. 7.41 × 3.7 = 27.417

Answer:22% or A!

Step-by-step explanation: 400 x 9 = 3600 he has ran 792 so far so its about 22.%  

Answer:

so we're dealing with negative numbers here so after learning negative numbers you have to add negative15 to -182 Wich is negative 197

y = -1/4x + 2

yeah

that's it

Answer:

1. 2x + 4= slope: 2 | y intercept: (0,4)

2. 2x + 4= slope: 2 | y intercept: (0,4)

3. -1/4x + 2= slope: -1/4 | y intercept: (0,2)

4. -1/4x + 2= slope: -1/4 | y intercept: (0,2)

Answer:

Bro it is simple,see when the 2 numbers are multiplying in 1st number decimal is before 2 digits and in 2nd number decimal is before 1 digit and in product decimal is before 3 digits so to place the decimal you need to + the digits afer decimal of numbers eg. in 0.43 there are 2 digits afer decimal and in 0.2 there is 1 digit after decimal and in answer there are 3 digits after decimal

Step-by-step explanation:

If you like my answer than please mark me brainliest thanks

Answer: SEE BELOW

Step-by-step explanation:

Decimals are multiplied as if they were whole numbers, and then the decimal point is placed in the product. To find out where the decimal point should be placed, count the number of decimal places after the decimal point in each factor.

0.43......... 2 decimal place(s) Add your decimal places = 3

0.2......... 1 decimal place(s)

0.086 Place decimal 3 decimal places in answer like so.

hope this helps you! Smile ; )

6- (-2) - 3(-5)

= 6- (-2) +15

= 6+ 2 +15

= 8+ 15

=23.

Thus, your answer is 23

Answer:

look at the photo..............

Answer:

Step-by-step explanation:

Just make an example

Answer:

-28

Step-by-step explanation:

Answer:

the answer is -28

Step-by-step explanation:

-8 x 7 / 1 x 2

= 56 / 2

Step-by-step explanation:

y = 5x - 2…Equation 1

3x - 5y = 4…Equation 2

Subtitute value of y to Equation 2 :

3x - 5(5x - 2) = 4

3x - 25x + 10 = 4

-22x + 10 = 4

10 - 4 = 22x

6 = 22x

6/22 = x

3/11 = x

Subtitute value of x to one of Equation :

for example Equation 2…

3x - 5y = 4

3(3/11) - 5y = 4

9/11 - 5y = 4

9/11 - 4 = 5y

(9 - 44)/11 = 5y

(-35)/11 = 5y

(-35)/11 × 1/5 = y

-7/11 = y

Using the uniform distribution, we have that:

a) The graph is sketched at the end of this answer.

b) 0.33 = 33% probability of generating a number between 0.01 and 0.34.

c) 0.05 = 5% probability of generating a number greater than 0.95.

An uniform distribution has two bounds, a and b.  

The probability of finding a value between c and d is:

[tex]P(c \leq X \leq d) = \frac{d - c}{b - a}[/tex]

The probability of finding a value above x is:

[tex]P(X > x) = \frac{b - x}{b - a}[/tex]

In this problem, uniformly distributed between 0 and 1, thus [tex]a = 0, b = 1[/tex].

Item b:

[tex]P(0.01 \leq X \leq 0.34) = \frac{0.34 - 0.01}{1 - 0} = 0.33[/tex]

0.33 = 33% probability of generating a number between 0.01 and 0.34.

Item c:

[tex]P(X > 0.95) = \frac{1 - 0.95}{1 - 0} = 0.05[/tex]

0.05 = 5% probability of generating a number greater than 0.95.

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