Answer:
BC>AB>AC
Step-by-step explanation:
The side length that sees the largest angle measure has the longest length
BC>AB>AC
4x² – 16x + 9 at x = 5.
Use the remainder theorem to evaluate f(x)
Answer:
29
Step-by-step explanation:
plug in 5 where x is.
so
4(5)^2-16(5)+9=
which equals 29
SEE IMAGE BELOW:)
Classify the triangle shown below.
ضع تصنيفا للمثلث الموضح أدناه.
11 cm
3 cm
13 cm
Answer:
Scuse me what the flip
Which system of inequalities does the graph represent?
Answer:system of linear equalities in one variable .
Step-by-step explanation:
Find the value of x to the nearest tenth
Answer:
a^2+b^2=c^2
6^2+6^2=72
square root of 72
=8.49(3sf)
c^2-b^2=a^2
=3
x=3
answer : 3
step by step:
this may seem hard but it is easy.
the first thing to do is to look at the bottom of the shape it shows a right triangle that is missing the hypotenuse lets see how to solve for that:
name the hypotenuse x
then write the equation
x^2= 6^2 + 6^2
x^2= 72
take both the square root of them
x = 8.5
next part is the rectangle and we see that it has been split into 2 right triangles which are the same but the cool part is that if we solve for one of the triangles we solve for the other we are going to do the same steps again notice now we are solving for the right angle that's not labeled if we solve that then that means we solve for the other triangle that is labelled x
first off we know that the hypotenuse is 9 and one angle is 8.5 so here is the equation:
x^2 = 9^2 - 8.5^2
x^2 = 8.75
take square root of both
x = 3
At the playground, the new sandbox was 10 meters wide and had an area of 60 square meters. How long is the sandbox?
Answer:
6 meters
Step-by-step explanation:
Area is length times width. If the width is 10 and the area is 60, then you would find 10 times ??? equals 60. Or 60 divided by 10. which is 6
Multiply the following using the vertical multiplication method: 3x^2-5x+1
x x^2+2x+4
9514 1404 393
Answer:
3x^4 +x^3 +3x^2 -18x +4
Step-by-step explanation:
The multiplication is done the same way as "long multiplication" with numbers. Each partial product is placed in the column corresponding to its "place value" (the degree of the variable). The only difference from numerical multiplication is that the sums of the partial products have no carry into any column with a different "place value".
400 is 100 times as much as
Help please!!! I don’t understand this question
Answer:
B) ASA - angle side angle
Hope it help
Find the circumference and area of a circle having a diameter of 7 1/2 ft. Use 3.14 for pi
Answer:
circumference= 32.56
area= 44.18
Step-by-step explanation:
for area: (A=pi×r^2) your diameter is 7.5 so you divide that by 2 to get your radius. and the radius is 3.75. then you are going to do 3.75^2 to get 14.1 then you are going to multiply 14.1 by pi to get 44.18
for circumference: (2×pi×r) you are going to take the same radius for the area and simply multiply that by pi (3.14) to get 11.78, then you are going to multiply 11.78×2 and that equals 23.56
Please answer step by step
[tex]27 {x}^{6} {y}^{9} [/tex]
Hope it helps you...
Find the circumference of the circle.
given the image below which segments are congruent
Answer:
-2+6=4
0+6=6
4+6=10
x+2=2. x=2-2. x=0
Step-by-step explanation:
hope this is helpful
how do you write .00057 1/2 in words
Answer:
Step-by-step explanation:
visit the following;
https://sciencing.com/write-fractions-words-4443134.html
4x(a-b)+3(b-a) factorise
Answer:
-(a-b) (3-4x). hope this helps
Suppose you have entered 115-mile biathlon that consists of a run and a bicycle race. During your run, your average velocity is 9 miles per hour, and during your bicycle race, your average velocity is 22 miles per hour. You finish the race in 7 hours. What is the distance of the run? What is the distance of the bicycle race?
Answer:
The distance of the run was 27 miles and the distance of the bicycle race was 88 miles.
Step-by-step explanation:
Since I have entered 115-mile biathlon that consists of a run and a bicycle race, and during my run, my average velocity is 9 miles per hour, and during my bicycle race, my average velocity is 22 miles per hour , and I finish the race in 7 hours, to determine what is the distance of the run and what is the distance of the bicycle race, the following calculations must be performed:
7 x 22 + 0 x 9 = 154
5 x 22 + 2 x 9 = 128
4 x 22 + 3 x 9 = 115
Therefore, the distance of the run was 27 miles and the distance of the bicycle race was 88 miles.
Ms.Peralta's friend Mike is a construction worker. Mike gets paid $15 an hour. After working 9 hours he gets paid 1.25 times his hourly rate. Below you can find Mike's hours for last Friday. - Mike worked for 5 hours - took an 1 hr and 15 minute break for lunch (does not count toward his work hours) - worked for an additional 7.5 hours How much money did Mike make last Friday?
Answer:
Mike made $ 200.63 last Friday.
Step-by-step explanation:
Since Ms. Peralta's friend Mike is a construction worker who gets paid $ 15 an hour, and after working 9 hours he gets paid 1.25 times his hourly rate, and last Friday Mike worked for 5 hours - took an 1 hr and 15 minute break for lunch (does not count toward his work hours) - and worked for an additional 7.5 hours, to determine how much money did Mike make last Friday the following calculation must be performed:
5 + 7.5 = 12.5
12.5 - 9 = 3.5
9 x 15 + (3.5 x (15 x 1.25)) = X
135 + 3.5 x 18.75 = X
135 + 65.625 = X
200.63 = X
Therefore, Mike made $ 200.63 last Friday.
Which expression is equivalent to x(97-12)?
– 12
Answer:
85x−12
Step-by-step explanation:
why is the solution to the following equation? x+(-21)=8
Answer:
x = 29
Step-by-step explanation:
[tex]x+(-21)=8[/tex]
[tex]29+(-21)=8[/tex]
[tex]29-21=8[/tex]
[tex]x=29[/tex]
The pie chart is best because pie charts are a good way to portray percentage based data. B. The Pareto chart is best because it allows you to see which sources account for most of the electricity. C. The pie chart is best because pie charts should always be used when comparing percentages. D. The Pareto chart is best because the bars make it easy to visually compare the different percentages. E. Neither type of chart is a good way to portray the data.
Answer:
The pie chart is best because pie charts are a good way to portray percentage based data.
Step-by-step explanation:
Pie charts are used for graphical representation of data. The data can be shown in percentages or numbers. It is easy for the user to understand the data in the pie chart because it clearly represents the data in circular graphical form.
Is this correct? I just started learning negative numbers.
Answer:
It's on the negative side, so make sure you put -2.25. But yes, it's right.
You used (formula in screenshot) when calculating variance and standard deviation. An alternative formula for the standard deviation that is sometimes convenient for hand calculations is shown below. You can find the sample variance by dividing the sum of squares by n-1, and the sample standard deviation by finding the square root of the sample variance. Complete parts (a) and (b) below.
Answer:
[tex]Varianve = 3.842[/tex]
[tex]SD = 1.960[/tex]
Step-by-step explanation:
Given
See attachment for data
First, calculate [tex]\sum x^2[/tex]
[tex]\sum x^2 = 18^2 + 17^2 +20^2 + 19^2 + 20^2 + 16^2 + 16^2 + 15^2 + 18^2+14^2 +19^2 + 19^2+18^2+17^2 + 16^2+20^2+16^2+18^2+14^2+20^2[/tex]
[tex]\sum x^2 = 6198[/tex]
Calculate [tex]\sum x[/tex]
[tex]\sum x = 18 + 17 +20 + 19 + 20 + 16 + 16 + 15 + 18+14 +19 + 19+18+17 + 16+20+16+18+14+20[/tex]
[tex]\sum x = 350[/tex]
So, we have:
[tex]SS_x = \sum x^2 -\frac{(\sum x)^2}{n}[/tex]
[tex]SS_x = 6198 -\frac{350^2}{20}[/tex]
[tex]SS_x = 6198 -\frac{122500}{20}[/tex]
[tex]SS_x = 6198 -6125[/tex]
[tex]SS_x = 73[/tex]
Solving (a): The variance
[tex]Varianve = \frac{SS_x}{n-1}[/tex]
[tex]Varianve = \frac{73}{20-1}[/tex]
[tex]Varianve = \frac{73}{19}[/tex]
[tex]Varianve = 3.842[/tex]
Solving (b): The standard deviation
[tex]SD = \sqrt{Variance}[/tex]
[tex]SD = \sqrt{3.842}[/tex]
[tex]SD = 1.960[/tex]
How long would it take to fill up 480cm3 pool at 25litres a min
Answer:
the answer is 8cm i think
Chris was given 1/3 of the 84 cookies in the cookie jar. He ate 3/4 of the cookies that he was given. How many cookies did Chris eat?
Answer:
21 cookies
Step-by-step explanation:
First we know that Chris was given a third of 84 cookies so we can start working on this problem by figuring out what a third of 84 is. We can do this by multiplying 84 by 1/3 or just dividing by 3, which gives us: 84/3 = 28
So now we know that Chris was given 28 cookies, we can figure out what 3/4 of that is to work out how many cookies he ate. 28 x (3/4) = 21 cookies.
Chris ate 21 cookies.
Hope this helped!
Answer:
21 cookies
Step-by-step explanation:
1/3 × 84 = 28
3/4 × 28 = 21
use the diagram below to find all missing angles
Answer:
Step-by-step explanation:
Soooo, angle 1 is 157 degrees
That means:
Angle 2 is 23 degrees Supplementary Angles
Angle 3 is 157 degrees Vertical Angle to Angle 1
Angle 4 is 23 degrees Vertical angle to Angle 2
Answers:
angle 2 = 23 degreesangle 3 = 157 degreesangle 4 = 23 degrees=======================================================
Explanation:
Angles 1 and 2 are supplementary as they form a straight line. So the angles add to 180
(angle1)+(angle2) = 180
angle2 = 180-(angle1)
angle2 = 180-157
angle2 = 23 degrees
Angle 4 is congruent to this because angles 2 and 4 are vertical angles. Vertical angles are always congruent. Note how angles 1 and 4 are supplementary.
Since angles 1 and 3 are the other pair of vertical angles, this must mean angle 3 is 157 degrees.
PLZ HELP !!!
Solve for X
A) 6
B) 5
C) 4
D) 7
Help please, solve and explain
Answer:
Step-by-step explanation:
17.
18.
f(x)=6x^2+7x-4
(a)
f(3)=6(3)^2+7(3)-4
=54+21-4
=71
(b)
f(m)=6m^2+7m-4
(c)
f(x+1)=6(x+1)²+7(x+1)-4
=6(x²+2x+1)+7x+7-4
=12x²+12x+6+7x+7-4
=12x²+19x+9
19.
(fg)(x)=f(g(x)=f(2x²+3)=2x²+3+5=2x²+8
20.
(a)
f(x)=x²+3x+4
domain:all real values
(b)
domain:all real values≥-2
(c)f(x)=log(x+7)
Domain:x≥-7
21.
x²+6x+y²-7=0
(x²+6x+6/2)²)-(6/2)²+y²=7
(x+3)²+y²=7+9
(x+3)²+y²=4²
center=(-3,0)
radius=4
22.
(x-3)²+(y-5)²=3²
or
x²-6x+9+y²-10y+25=9
x²+y²-6x-10y+25=0
Graph is for 17th question.
A small country emits 50,000 kilotons of carbon dioxide per year. In a recent global agreement, the country agreed to cut its carbon emissions by 1.1% per year for the next 6 years. In the first year of the agreement, the country will keep its emissions at 50,000 kilotons and the emissions will decrease 1.1% in each successive year. How many total kilotons of carbon dioxide would the country emit over the course of the 6 year period, to the nearest whole number?
Answer:
291870 kilotons
Step-by-step explanation:
Since the country cuts its carbon content by 1.1% each year. The initial value at the first year is 50000. Therefore this can be represented by the exponential function:
y = a(b)ˣ ⁻ ¹
where y is the amount of carbon emission in kilotons in x years.
a = 50000, b = 100% - 1.1% = 98.9% = 0.989
y = 50000(0.989)ˣ ⁻ ¹
In the first year: y = 50000(0.989)¹ ⁻ ¹ = 50000
In the second year: y = 50000(0.989)² ⁻ ¹ = 49450
In the third year: y = 50000(0.989)³ ⁻ ¹ = 48906
In the fourth year: y = 50000(0.989)⁴ ⁻ ¹ = 48368
In the fifth year: y = 50000(0.989)⁵ ⁻ ¹ = 47836
In the sixth year: y = 50000(0.989)¹ ⁻ ¹ = 47310
The total emission in 6 years = 50000 + 49450 + 48906 + 48368 + 47836 + 47310 = 291870 kilotons
Find the value of unknown figure plz tell i will mark as brainliest
Answer:
1. [tex]2^{3}[/tex] x [tex]3^{6}[/tex]
ii. 18
b. -12
2. nth = a + (n - 1)d
ii. k = 103
3. [tex]x^{o}[/tex] = [tex]27^{o}[/tex]
4. Volume = 25.025 [tex]m^{3}[/tex]
Step-by-step explanation:
1. Prime factors of 5832 = 2 x 2 x 2 x 3 x 3 x 3 x 3 x 3 x 3
= [tex]2^{3}[/tex] x [tex]3^{6}[/tex]
ii. [tex]\sqrt[3]{5832}[/tex] = 18
b. 2[tex]a^{2}[/tex] - 3[tex]b^{2}[/tex] + 3abc
a = 3, b = 2, c = -1
Thus,
2[tex](3)^{2}[/tex] - 3[tex](2)^{2}[/tex] + 3(3 x 2 x -1)
= 18 - 12 - 18
= -12
2. The required formula is;
nth = a + (n - 1)d
where: a is the first term, n is the number of terms in the sequence and d is the common difference.
b. kth term = 304, then
304 = -2 + (k - 1) 3
= -2 + 3k -3
= 3k - 5
3k = 304 + 5
3k = 309
k = [tex]\frac{309}{3}[/tex]
= 103
k = 103
3. Comparing <DAB and < EBC;
<DAB ≅ <EBC = [tex]x^{o}[/tex]
<BEC = [tex]90^{o}[/tex] (right angle property)
<C = [tex]63^{o}[/tex]
Thus,
<B + <C + <E = [tex]180^{o}[/tex] (sum of angles in a triangle)
[tex]x^{o}[/tex] + [tex]63^{o}[/tex] + [tex]90^{o}[/tex] = [tex]180^{o}[/tex]
[tex]x^{o}[/tex] + 153 = [tex]180^{o}[/tex]
[tex]x^{o}[/tex] = 180 - 153
= 27
[tex]x^{o}[/tex] = [tex]27^{o}[/tex]
4. Volume of a cylinder = [tex]\pi[/tex][tex]r^{2}[/tex]h
where r is the radius and h is the height of the cylinder.
Diameter = 3.5 m, h = 2.6 m
r = [tex]\frac{3.5}{2}[/tex]
r = [tex]\frac{7}{4}[/tex] m
So that,
Volume = [tex]\frac{22}{7}[/tex] x [tex](\frac{7}{4}) ^{2}[/tex] x 2.6
= [tex]\frac{22}{7}[/tex] x [tex]\frac{49}{16}[/tex] x [tex]\frac{13}{5}[/tex]
= 25[tex]\frac{1}{40}[/tex]
Volume = 25.025 [tex]m^{3}[/tex]
What is the solution to the equation?
^5 / x+7= -2 (A.) -39 (B.) -17 (C.) 25 (D.) no solution
[tex]\implies {\blue {\boxed {\boxed {\purple {\sf {A. \:-39}}}}}}[/tex]
[tex]\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}[/tex]
[tex] \sqrt[5]{x + 7} = - 2[/tex]
➺[tex] \: x + 7 =( { - 2})^{5} [/tex]
➺[tex] \: x + 7 = ( - 2 \times - 2 \times - 2 \times - 2 \times - 2)[/tex]
➺[tex] \: x + 7 = - 32[/tex]
➺[tex] \: x = - 32 - 7[/tex]
➺[tex] \: x = - 39[/tex]
[tex]\large\mathfrak{{\pmb{\underline{\blue{To\:verify}}{\blue{:}}}}}[/tex]
[tex] \sqrt[5]{x + 7} = - 2 \\\\ ➼ \: \sqrt[5]{ - 39 + 7} = - 2 \\ \\➼ \: \sqrt[5]{ - 32} = - 2 \\\\ ➼ \: \sqrt[5]{ - 2 \times - 2 \times - 2 \times - 2 \times - 2} = - 2\\ \\ ➼ \: \sqrt[5]{( { - 2})^{5} } = - 2\\ \\ ➼ \: - 2 = - 2 \\\\ ➼ \: L.H.S.=R. H. S[/tex]
Hence verified.
[tex]\large\mathfrak{{\pmb{\underline{\orange{Happy\:learning. }}{\orange{❦}}}}}[/tex]
The solution of the given equation would be; x = -39.
What is the solution for an equation?The solution of an equation refers usually to the values of the variables involved in that equation which if substituted in place of those variable would give a true mathematical statement.
WE have been given an equation as,
[tex]\sqrt[5]{x+7} = -2[/tex]
WE need to find the solution of the given equation which can be calculated as;
[tex]\sqrt[5]{x+7} = -2[/tex]
First raise both sides to the power 5;
[tex](\sqrt[5]{x+7} )^5= -2^5[/tex]
Now x + 7 = - 32
subtract 7 from both sides, we get;
x = - 39
Hence, the solution of the given equation would be; x = -39.
Learn more about solving equations here:
https://brainly.com/question/13072448
#SPJ2
Write the equation of the trigonometric graph.
Answer(s):
[tex]\displaystyle y = 3sin\: (1\frac{1}{2}x + \frac{\pi}{2}) - 2 \\ y = 3cos\: 1\frac{1}{2}x - 2[/tex]
Explanation:
[tex]\displaystyle y = Asin(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow -2 \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{-\frac{\pi}{3}} \hookrightarrow \frac{-\frac{\pi}{2}}{1\frac{1}{2}} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{1\frac{1}{3}\pi} \hookrightarrow \frac{2}{1\frac{1}{2}}\pi \\ Amplitude \hookrightarrow 3[/tex]
OR
[tex]\displaystyle y = Acos(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow -2 \\ Horisontal\:[Phase]\:Shift \hookrightarrow 0 \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{1\frac{1}{3}\pi} \hookrightarrow \frac{2}{1\frac{1}{2}}\pi \\ Amplitude \hookrightarrow 3[/tex]
You will need the above information to help you interpret the graph. First off, keep in mind that although this looks EXACTLY like the cosine graph, if you plan on writing your equation as a function of sine, then there WILL be a horisontal shift, meaning that a C-term will be involved. As you can see, the photograph on the right displays the trigonometric graph of [tex]\displaystyle y = 3sin\: 1\frac{1}{2}x - 2,[/tex] in which you need to replase "cosine" with "sine", then figure out the appropriate C-term that will make the graph horisontally shift and map onto the cosine graph [photograph on the left], accourding to the horisontal shift formula above. Also keep in mind that the −C gives you the OPPOCITE TERMS OF WHAT THEY REALLY ARE, so you must be careful with your calculations. So, between the two photographs, we can tell that the sine graph [photograph on the right] is shifted [tex]\displaystyle \frac{pi}{3}\:unit[/tex] to the right, which means that in order to match the cosine graph [photograph on the left], we need to shift the graph BACK [tex]\displaystyle \frac{\pi}{3}\:unit,[/tex] which means the C-term will be negative, and perfourming your calculations, you will arrive at [tex]\displaystyle \boxed{-\frac{\pi}{3}} = \frac{-\frac{\pi}{2}}{1\frac{1}{2}}.[/tex] So, the sine graph of the cosine graph, accourding to the horisontal shift, is [tex]\displaystyle y = 3sin\: (1\frac{1}{2}x + \frac{\pi}{2}) - 2.[/tex] Now, with all that being said, in this case, sinse you ONLY have a graph to wourk with, you MUST figure the period out by using wavelengths. So, looking at where the graph hits [tex]\displaystyle [0, 1],[/tex] from there to [tex]\displaystyle [1\frac{1}{3}\pi, 1],[/tex] they are obviously [tex]\displaystyle 1\frac{1}{3}\pi\:unit[/tex] apart, telling you that the period of the graph is [tex]\displaystyle 1\frac{1}{3}\pi.[/tex] Now, the amplitude is obvious to figure out because it is the A-term, but of cource, if you want to be certain it is the amplitude, look at the graph to see how low and high each crest extends beyond the midline. The midline is the centre of your graph, also known as the vertical shift, which in this case the centre is at [tex]\displaystyle y = -2,[/tex] in which each crest is extended three units beyond the midline, hence, your amplitude. So, no matter how far the graph shifts horisontally, the midline will ALWAYS follow.
I am delighted to assist you at any time.