4781/32 without a decimal

Answer:

  x + y -z = 6

Step-by-step explanation:

The equation of the line can be rewritten as ...

  (x, y, z) = (2, -3, 0) +t(1, 1, -1)

The direction vector of the line tells you the coefficients of the variables in the equation of the plane. The constant in that plane equation will be the value required to make it pass through the given point.

  x + y - z = (-1) +(4) -(-3)

  x + y - z = 6 . . . . equation of the plane

Answer:

11 17/21

Step-by-step explanation:

Answer:

11 17/21

Step-by-step explanation:hope i helped

Answer:

2nd one

Step-by-step explanation:

i think(10+2)^2_4*11=100 in my opinion

The conjugate of the expression a - square root of a - 1 is given as follows:

a + square root of a - 1

The conjugate of an expression is obtained for an expression that has two terms.

For the conjugate, we have that:

The expression is given as follows:

a - square root of a - 1

The parameters are given as follows:

Inverting the - sign to a + sign, the conjugate expression is given as follows:

a + square root of a - 1

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Answer:

Multiply each side by −5, add 25 to each side.

Step-by-step explanation:

Answer: The answer is C, 4 to the 21st over 5 to the 6th power.

Answer:

190

Step-by-step explanation:

f(1)=8

f(2)=3f((2-1))-2, f(2)=22

f(3)=3f((3-1))-2, f(3)=64

f(4)=3f((4-1))-2, f(4)=190

The number of ways the yearbook chooses the winners of Most Athletic, Class Clown, Best School Spirit, and Best Looking is 330 ways.

Combination and permutation are two different ways of grouping elements of a set into subsets in mathematics. The elements of the subset can be listed in any order in a combination. The elements of the subset are listed in a specific order in a permutation.

Given that there are 11 students in a high school senior class. The number of ways will be calculated as,

The formula for arrangement,

¹¹C₄ = 11!/(7!)(4!)

¹¹C₄ = 330 ways

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Hello there

This is a simple algebra problem, that we will be solving...

First let's use [tex]PEMDAS[/tex], and [tex]DISTRIBUTIVE\:PROPERTY[/tex]

______________

[tex]{\huge{\boxed{\mathbb{PEMDAS}}}[/tex]

______________

[tex]{\huge{\boxed{\mathbb{DISTRIBUTIVE\:PROPERTY}}[/tex]

Definition- Distribute Property - The distributive property is one of the most frequently used properties in math. In general, this term refers to the distributive property of multiplication which states that the Definition: The distributive property lets you multiply a sum by multiplying each addend separately and then add the products.

______________

[tex]4(1.75y-3.5)+1.25y[/tex], first distribute...

[tex]7y-14+1.25y[/tex], combine like terms, and we get [tex]8.25y-14[/tex] as our answer

Answer:

b =146

Step-by-step explanation:

34 and b form a straight line so they add to 180

b+34 = 180

b = 180-34

b =146

Answer:

41

Step-by-step explanation:

53/106 = x/82 similar triangles

x=41

[tex]2x-3y = 7~~~....(i)\\\\y = 3x -7~~~....(ii)\\\\\\\text{Substitute}~ y = 3x -7~ \text{in equation (i):}\\\\\\2x-3(3x-7) = 7\\\\\implies 2x -9x + 21 =7\\\\\implies -7x = 7 -21\\\\\implies -7x = -14\\\\\implies x = \dfrac{-14}{-7} = 2\\\\\\\text{Substitute x = 2 in equation (ii):}\\\\y=3(2) -7 = 6 -7 = -1\\\\\\\text{Hence (x,y) =(2,-1)}[/tex]

Answer:

savind and investing money

Step-by-step explanation:

The Pythagorean theorem is:

[tex] {c}^{2} = {a}^{2} + {b}^{2} [/tex]

where c is the hypotenuse.

The two wires in the sketch are the hypotenuse so we just use the formula

let the wires=x

So:

[tex] {x}^{2} = {12}^{2} + {6}^{2} [/tex]

[tex] {x}^{2} = 144 + 36[/tex]

[tex] {x}^{2} = 180[/tex]

[tex]x = \sqrt{180} [/tex]

[tex]x = 13.42[/tex] feet

[tex]\text{a. cm}^2\\\\\text{b. cm}^3\\\\\text{c. cm}\\\\\text{d. cm}^2\\\\\text{e. cm}^3\\[/tex]

Answer:

His probability of getting a raspberry yogurt is 3/5 or 60%.

Step-by-step explanation:

Pls mark brainliest.

Answer: A. (4/8)

Step-by-step explanation: If there is 4 black swans and 8 swans in total you could see it's 4 black swan out of 8 total swans. You could do

8/8 - 4/8 = 4/8 to find out the answer too.

Answer:

Step-by-step explanation:

Let the number of quarters be x and nickels be y.

Given:

We have equations:

Solve the system by elimination, subtract 5 times the first equation from the second one:

Find the value of y:

Verify:

Answer:

2.8

Step-by-step explanation:

Answer:

Step-by-step explanation:

2.8 units

Answer:

0.75p=c

Step-by-step explanation:

Answer:

  (c)  (12th root of 8)^x

Step-by-step explanation:

The applicable rules of exponents are ...

  [tex](a^b)^c=a^{bc}\\\\\sqrt[n]{a}=a^{1 \! /n}[/tex]

In this case, we have ...

  [tex](\sqrt[3]{8})^{x/4}=8^{1/3\cdot x/4}=8^{x/12}=\boxed{\left(\!\sqrt[12]{8}\right)^x}[/tex]

Answer:

2.0015305e+15 is the answer

Answer:

Copy an angle is the best solution with compass and straight edge.

Answer:

[tex]b=-a^2-c[/tex]

Step-by-step explanation:

Answer:

D şıkkı iyi dersler hadi

Answer:

C: [tex](2x+5)(4x^2-10x+25)[/tex]

Step-by-step explanation:

First of all, you need to be able to recognize the two terms as cubes, and what they are cubes of. In this case, [tex]8x^3 = (2x)^3[/tex] and [tex]125=5^3[/tex].

Then you have to find a way you like to remember the formula for how to factorize. The way I do it is by saying "the binomial has the same zero as the original, so [tex]x^3+a^3=(x+a)(...)[/tex] and [tex]x^3-a^3 = (x-a)(...)[/tex] and the whole expression has one minus sign attached to the second term of either factor. In the sum of cubes first parenthesis has a plus, so the second term of the other parentesis has to take that minus: [tex]x^3+a^3=(x+a)(x^2-ax+a^2)[/tex] while in the difference of cubes you already used a minus, so everything else goes plus: [tex]x^3-a^3=(x-a)(x^2+ax+a^2)[/tex]

Or you commit the two formulas to memory.

Answer:

I'm not sure you mean 2-(b/3) = -5/2 or (2-b)/3 = -5/2

Step-by-step explanation:

if

2-(b/3) = -5/2

12-2b = -15

12+15 = 2b

27 = 2b

27/2 = b

else

(2-b)/3 = -5/2

2(2-b) = -5×3

4-2b = -15

4+15 = 2b

19 = 2b

19/2 = b

Answer:

[tex]\begin{bmatrix}y>2+x\\ y>\frac{2-x}{2}\end{bmatrix}[/tex]

Step-by-step explanation:

Step 1: Solve the system of equations

[tex]\begin{bmatrix}-x+y>2\\ x+2y>2\end{bmatrix}[/tex]

Isolate [tex]y[/tex] for [tex]-x+y>2[/tex]

[tex]\mathrm{Add\:}x\mathrm{\:to\:both\:sides}[/tex]

[tex]-x+y+x>2+x[/tex]

[tex]y>2+x[/tex]

Isolate [tex]y[/tex] for [tex]x+2y>2[/tex]

[tex]\mathrm{Subtract\:}x\mathrm{\:from\:both\:sides}[/tex]

[tex]2y>2-x[/tex]

[tex]\mathrm{Divide\:both\:sides\:by\:}2[/tex]

[tex]\frac{2y}{2}>\frac{2}{2}-\frac{x}{2}[/tex]

[tex]y>\frac{2-x}{2}[/tex]

[tex]\bold{=\begin{bmatrix}y>2+x\\ y>\frac{2-x}{2}\end{bmatrix}}[/tex]

Step 2: Graph

Instructions for graphing:

[tex]\mathrm{1.\:Graph\:each\:inequality\:separately.}[/tex]

[tex]\mathrm{2.\:Choose\:a\:test\:point\:to\:determine\:which\:side\:of\:the\:line\:needs\:to\:be\:shaded.}[/tex]

[tex]3. \mathrm{The\:solution\:to\:the\:system\:will\:be\:the\:area\:where\:the\:shadings\:}\\\mathrm{from\:each\:inequality\:overlap\:one\:another.}[/tex]

When done, it should look like this: