45 × _____ ÷ 15 = 45

Answer:

A) 21

Step-by-step explanation:

Mean:

(23 + 18 + 24 + 15 + 25)/5

105/5

21

Answer:

21

The mean is 21. Remember to calculate the mean we add up the numbers then divide them by the number of numbers.

Answer:

e

Step-by-step explanation:

beishdhsjsvsudjdnbdhdjrjdxbxbudsndnbhhxhxbdhddbdbd

Answer:

t = 9 s

Step-by-step explanation:

A stone is thrown downward with an intitial velocity of 29.5 m/sec will travel a distance of a meters, where

[tex]s(t) = -4.9t^2 + 29.4+132.3[/tex]

We need to find when the stone will hit the ground. It means when s(t) = 0. So,

[tex]-4.9t^2 + 29.4t+132.3=0\\\\t=-3\ and\ t=9[/tex]

So, the stone will take 9 seconds to hit the ground. Hence, this is the required solution.

Answer:

320

Step-by-step explanation:

Step 1: Estimate the answer by rounding .

Step 2: If the divisor is not a whole number, then move the decimal place in places to the right to make it a whole number.

Step 3: Divide as usual.

Step 4: Put the decimal point in the quotient directly above where the decimal point now is in the dividend.

Answer:  320 is the correct answer

Step-by-step explanation:

To answer this questions is simple, you can see it as a long division question or regular division

Regular division:

16 ÷ 0.05 = 1600  

(You can transform this into a simple non-decimal question and solve easliy)

1600 ÷ 5 = 320

This is the way to solve these type of questions without straining your brain in the process.

Answer:

Area of ΔQRS = 2.3 square inches

Step-by-step explanation:

From the given information,

<S + <Q + <R = [tex]180^{o}[/tex]

51 + 44 + <R = [tex]180^{o}[/tex]

95 + <R = [tex]180^{o}[/tex]

<R = [tex]180^{o}[/tex] - 95

    = [tex]85^{o}[/tex]

<R = [tex]85^{o}[/tex]

Applying the Sine rule, we have;

[tex]\frac{q}{SinQ}[/tex] = [tex]\frac{r}{SinR}[/tex] = [tex]\frac{s}{SinS}[/tex]

Using [tex]\frac{r}{SinR}[/tex] = [tex]\frac{s}{SinS}[/tex]

[tex]\frac{r}{Sin 85}[/tex] = [tex]\frac{2.3}{Sin51}[/tex]

r = [tex]\frac{2.3*Sin85}{sin51}[/tex]

  = 2.9483

r = 2.9 inches

Also, [tex]\frac{q}{SinQ}[/tex] = [tex]\frac{s}{SinS}[/tex]

[tex]\frac{q}{Sin44}[/tex] = [tex]\frac{2.3}{Sin51}[/tex]

q = [tex]\frac{2.3*Sin44}{Sin51}[/tex]

  = 2.0559

q = 2.0 inches

From Herons formula,

Area of a triangle = [tex]\sqrt{s(s-q)(s-r)(s-s)}[/tex]

s = [tex]\frac{2.3 + 2.0 + 2.9}{2}[/tex]

  = 3.6

Area of ΔQRS = [tex]\sqrt{3.6(3.6-2.0(3.6-2.9)(3.6-2.3)}[/tex]

                        = 2.2895

Area of ΔQRS = 2.3 square inches

Answer:

2.4

Step-by-step explanation:

Answer:

negative linear relationship

Step-by-step explanation:

Step-by-step explanation:

[tex]40 - (40 \div 100 \times 65) = \\ = 40 - (0.4 \times 65) = \\ = 40 - 26 = \\ = 14[/tex]

a) 640.32 cm^3

b) 98.4 cm^3

(3.14) × 2^2 × 12 = 150.72 cm^3

We need to find the height of the base so we use the Pythagorean theorem.

5^2 + x^2 = 14.1^2

25 + x^2 = 198.81

x^2 = 173.81

x = 13.184

After finding height, we can use the equation for a normal triangular prism:

[tex]\frac{1}{2}[/tex] × Base × Height × Length

[tex]\frac{1}{2}[/tex] × 13.184 × 10 × 12= 791.04cm^3

Total Volume: 791.04 - 150.72 = 640.32 cm^3

[tex]\frac{4}3[/tex] × 3.14 × 1^3 = [tex]\frac{314}{75}[/tex]cm^3

0.5([tex]\frac{4}3[/tex]× 3.14 × 3^3) = 56.52cm^3

5^2 = 3^2 + h^2

25 = 9 + h^2

16 = h^2

h = 4

(3.14) × 3^2 × [tex]\frac{4}{3}[/tex] = 37.68 cm^3

Total Volume = 98.4 after rounding

Step-by-step explanation:

[tex] \frac{5}{3} = 1 \frac{2}{3} = 1.67[/tex]

Since

[tex]1.67 > 1.6 \: and \: > 1.5[/tex]

C is the answer

Answer:

Step-by-step explanation:

hello : solve     (x+1)(x+4)=40

x²+5x+4 =40

x²+5x-36 =0      continu  us  delta

Answer:

1/6

Step-by-step explanation:

convert ti decimal then compare the two

Answer:

Hello There!!

Step-by-step explanation:

1/6 is less.You can check this by 2÷5=0.4 and 1÷6=0.1666666667 so 1/6 is less.

hope this helps,have a great day!!

~Pinky~

Answer:

[tex]P(50 < x < 150) =0.3834[/tex]

[tex]P(x = 100) =0.0074[/tex]

Step-by-step explanation:

Given

[tex]f(x) = \left \{ {{\frac{1}{100}e^{-x/100}\ x\ge 0} \atop {0\ x<0}} \right.[/tex]

Solving (a): Probability that it will function between 50 and 150 hr before it breaks down

This is represented as:

[tex]P(50 < x < 150) = \int\limits^{150}_{50} {f(x)} \, dx[/tex]

So, we have:

[tex]P(50 < x < 150) = \int\limits^{150}_{50} {\frac{1}{100}e^{-x/100}} \, dx[/tex]

Integrate:

[tex]P(50 < x < 150) =- e^{-x/100}|\limits^{150}_{50}[/tex]

This gives:

[tex]P(50 < x < 150) =- e^{-150/100} - - e^{-50/100}[/tex]

[tex]P(50 < x < 150) =- e^{-150/100} + e^{-50/100}[/tex]

[tex]P(50 < x < 150) =- e^{-1.5} + e^{-0.5}[/tex]

[tex]P(50 < x < 150) =- 0.2231 + 0.6065[/tex]

[tex]P(50 < x < 150) =0.3834[/tex]

Solving (a): Probability that it will function exactly 100 hr before it breaks down

This is represented as:

[tex]P(x= 100)[/tex]

This can be rewritten as:

[tex]P(x= 100) = P(99<x<101)[/tex]

So, we have:

[tex]P(99 < x < 101) = \int\limits^{101}_{99} {f(x)} \, dx[/tex]

So, we have:

[tex]P(99 < x < 101) = \int\limits^{101}_{99} {\frac{1}{100}e^{-x/100}} \, dx[/tex]

Integrate:

[tex]P(99 < x < 101) =- e^{-x/100}|\limits^{101}_{99}[/tex]

This gives:

[tex]P(99 < x < 101) =- e^{-101/100} - - e^{-99/100}[/tex]

[tex]P(99 < x < 101) =- e^{-101/100} + e^{-99/100}[/tex]

[tex]P(99 < x < 101) =- e^{-1.01} + e^{-0.99}[/tex]

[tex]P(99 < x < 101) =- 0.3642 + 0.3716[/tex]

[tex]P(99 < x < 101) =0.0074[/tex]

Hence:

[tex]P(x = 100) =P(99 < x < 101) =0.0074[/tex]

the varsity tutors ap statisyics app (app)

Answer:

The answer is false. 2 is not congruent to 5.

Honestly, someone has a different answer but they have a whole paragraph so I think you should listen to what they say.

Answer:

True

Step-by-step explanation:

Same-side exterior angle converse theorem states that if two lines are intersected by a transversal and the same-side exterior angle are congruent, then the two lines are parallel. One can apply this theorem to the given case, and thus lines A and B are parallel.

Answer: x > 4

x > 4 would look like that on the graph. If it was x is greater than or equal to 4, then the circle would be completely filled in. Hope this helped!

Let x be the weight of the candy in pounds, then 0.9x is the weight of the milk chocolate in pounds

The weight of the caramels in the candy is 3 pounds, so

An equation that can be used find the total number of pounds of milk chocolate and caramels in the candy is

0.9x + 3 = x ⇒ x = 30

So there are 0.9(30) = 27 pounds of milk chocolate in the candy.

hope this helps

Area of square = (2x-3)^2

Area = 2x-3 x 2x-3

Area = 4x^2 -6x -6x +9

Area = 4x^2 -12x + 9

Area of ovals = x-5 + x-5 = 2x-10

Area of square - area of ovals:

4x^2  - 12x +9 - 2x -10

4x^2 -14x +19 square units

Answer:

Answer:

27n³+125n³ = 152n³

5.337n)(5.337n)(5.337n)

Answer:

Step-by-step explanation: use math-way a chegg service

As per the given details, the value of ff.ds over the region V bounded by the planes x = 0, y = 0, z = 0, z = 4, and the surface of the cylinder x² + y² = 9 in the first octant, where F = xî + xyj + 2k, is 81π.

The divergence theorem relates a flux fundamental across a closed floor S to a triple crucial over strong E enclosed by way of the surface.

It states that for a vector field F and a closed floor S that encloses a solid area E, the outward flux of F across S is equal to the triple necessary of the divergence of F over E.

Mathematically, the divergence theorem can be written as:

∫∫ F · dS = ∭ div(F) dV

To examine ff.Ds over the vicinity V bounded by using the planes x = zero, y = zero, z = zero, z = 4, and the floor of the cylinder x² + y² = 9 within the first octant, in which F = xî + xyj + 2k, we can use the divergence theorem. The first step is to locate the divergence of F:

div(F) = ∂Fx/∂x + ∂Fy/∂y + ∂Fz/∂z

= 1 + x

Next, we want to discover the volume enclosed via the surface. The cylinder x² + y² = 9 inside the first octant is a round cylinder with radius 3 and top 4. Therefore, the volume enclosed with the aid of the floor is:

V = ∫∫R (4 - z) dA

= ∫0^3 ∫0^(2π) (4 - z) r dr dθ

= 18π

So,

∫∫S F · dS = ∭V div(F) dV

= ∭V (1 + x) dV

= ∫0^4 ∫0^3 ∫0^(2π) (1 + x) r dθ dz dr

= 81π

Therefore, the value of ff.Ds over the place V bounded through the planes x = 0, y = 0, z = zero, z = four, and the surface of the cylinder x² + y² = 9 inside the first octant, where F = xî + xyj + 2k, is 81π.

For more details regarding divergence theorem, visit:

https://brainly.com/question/31272239

#SPJ1

Answer:

I think your answer would be 5.6

Step-by-step explanation:

56% of 10 = 5.6

Step-by-step explanation:

[tex] \frac{2}{4} + \frac{3}{8} = \\ = \frac{4 + 3}{8} = \\ = \frac{7}{8} [/tex]

Answer:

The answer is 0.875 in decimal form but is 7/8 in fraction form

Step-by-step explanation:

Answer:

I would believe 90* clockwise.

Step-by-step explanation:

It rotated 90* to be located on its side.

Answer:

11/12

Step-by-step explanation:

Answer:

8>_x>4

>_ this is greater than equal to symbol eight is greater than or equal to x is greater than 4

Mark my answer brilliant if it helps you.