Answer:
8 meters
Explanation:
40/ 5 = 8
What is the average speed of the object? What is the average velocity?
Answer:
Avg speed
[tex] \frac{dp}{dt } = \frac{5 - 4}{12 - 0} = \frac{1}{12} m \: per \: s[/tex]
avg velocity
[tex] \frac{5}{4} m \: per \: s[/tex]
Hi there!
Average speed = Distance / time
From the previous question, distance = 17m, so:
Speed = 17/12 ≈ 1.417 m/s
Average velocity = DISPLACEMENT/ time
Displacement = 1m, so:
Average velocity = 1/12 ≈ 0.083 m/s
I need the right answer ASAP NO LINKS!!!
Answer:
Water and power come from external sources.
Explanation:
Imagine everyone in the United States exhibited the character traits we have been discussing. In what ways would America be different?
Now imagine no one in American exhibited any of those character traits. In what ways would America be different?
Answer:
Characterization is the process by which the writer reveals the personality of a character. Characterization is revealed through direct characterization and indirect characterization. Direct Characterization tells the audience what the personality of the character is.
The ______ describes the height or the wave measured from the central axis
Answer:
Amplitude
Explanation:
Answer:
the wave trough.
Explanation:
As is shown on the figure, wave height is defined as the height of the wave from the wave top, called the wave crest to the bottom of the wave, called the wave trough. The wave length is defined as the horizontal distance between two successive crests or troughs.
A teacher asks a group of students to use a ruler to measure the amplitude of the wave shown below. Between which of the following points should the amplitude be measured?
A. Points U and Z
B. Points V and X
C. Points W and Y
D. Points X and Z
Answer:
c for me
Explanation:
I don't think so
if I'm correct if I'm wrong
Answer:
a. points u and z
Explanation:
amplitude, in physics, the maximum displacement or distance moved by a point on a vibrating body or wave measured from its equilibrium position
A car's speed 3 seconds after accelerating from rest at 2 m/s^2 is?
Answer:
After 3 seconds, the velocity is 4.5+3×1.5=9 m/s.
Equations for work
W=
F=
D=
Answer:
W= work
F= force
D= Displacement
Explanation:
Work can be calculated with the equation: Work = Force × Distance.
At the end of the Giant Drop free fall ride, riders experience a large experience a large upward normal force to bring their falling bodies to a stop. Determine the normal force value required to accelerate a 52.1-kg physics student with an upward acceleration of 27.4 m/s/s.
Newton's second law allows us to find the force applied to the student so that it has an upward acceleration of 27.4 m / s² is:
F = 1.94 10³ N
Newton's second law says that the force is proportional to the product of the mass and the acceleration of the body.
∑ F = m a
Where F is the force, m the mass and the acceleration of the body.
A free body diagram is a diagram of the forces without the details of the bodies, in the attachment we have a free body diagram of the system.
They indicate that the student's mass is 52.1 kg and his acceleration is 27.4 m / s², let's write Newton's second law.
F - W = ma
F = m a + W
Body weight is.
W = mg
F = m (a + g)
We calculate.
F = 52.1 (27.4+ 9.8)
F = 1.94 10³ N
In conclusion using Newton's second law we can find the force applied to the student is:
F = 1.94 10³ N
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in which state of matter would you expect to find water on earth surface if the tempature is 25\
Answer:
Water is a liquid at standard temperature and pressure (25 degrees Celsius and 1 atm, for liquids). Water is is tasteless and odorless.
Explanation:
Use the diagram below to answer the Question.
Which convection zone region is shown at point 3?
Question 6 options:
polar region
temperate region
tropical region
Answer:
Tropical region
Explanation:
because the regions near the equator are called tropical regions
Safety engineers estimate that an elevator can hold 20 persons of 75kg average mass. The elevator itself has a mass of 500kg. Tensile strength test how the cable supporting the elevator can tolerate a maximum force of 2.96X10^4N. What is the greatest acceleration that the elevators motor can produce without breaking the cable? (show work)
The greatest acceleration that the elevators motor can produce without breaking the cable is 5 m/s².
The given parameters;
average mass of the 20 persons = 75 kgmass of the elevator, m = 500 kgtensile strength of the elevator, T = 2.96 x 10⁴ NThe total mass the elevator can support;
M = 500 kg + 20(75 kg)
M = 2000 kg
The greatest acceleration that the elevators motor can produce without breaking the cable occurs when the elevator is moving upwards;
T = M(a + g)
[tex]2.96 \times 10^4 = 2000 (a + 9.8)\\\\2.96 \times 10^4 = 2000a + 19600\\\\29600 - 19600 = 2000a\\\\10,000 = 2000a\\\\a = \frac{10,000}{2000} \\\\a = 5 \ m/s^2[/tex]
Thus, the greatest acceleration that the elevators motor can produce without breaking the cable is 5 m/s².
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would be equal to 0 miles.
If you travel from home, to school and back home, the measure of
distance
velocity
displacement
speed
Answer:
as we know Speed=Distance÷Time
Distance=Speed×Time
Velocity=Displacement÷Time
Displacement=Velocity×Time
u haven't given the speed and all give it and I will tell the answer
Investigators studying the effect of hitting a soccer ball with the head are using a force plate to look at the forces in ball collisions; the force when the ball hits a player's head will be similar. A 0.43 kg ball is launched at a force plate at 16 m/s. Smoothed data for the force versus time for the collision are shown in (Figure 1).
The integral of the function of the force applied to the time of application
of the force gives the impulse of the force.
The speed with which the ball rebounds from the plate is approximately
34.23 m/s.
Reasons:
Force = Rate of change of momentum
F × t = m·(v₂ - v₁)
Where;
Speed of the ball, v₁ = 16 m/s
v₂ = The speed with which the ball rebounds from the plate
The impulse, I, of the force is given by the area under the curve.
The height of the triangular curve, h = 2,500 N
The base length of the triangular curve = 7 ms.
Area of a triangle = [tex]\frac{1}{2}[/tex] × Base length × Height
Therefore, we have;
[tex]Area \ under \ the \ curve, \, I = \dfrac{0.007 \times 2500}{2} = 8.75[/tex]
8.75 = 0.48 × (v₂ - 16)
v₂ ≈ 34.23 m/s
Therefore, the speed with which the ball rebounds, v₂ ≈ 34.23 m/s.
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https://brainly.com/question/20595307
https://brainly.com/question/13769802
between a smooth and a rough surface, which of the two surfaces is easier to slide and why?
Answer:
When two surfaces slide against each other, a force called friction makes them stick very slightly together. Smooth surfaces, like ice and glass, are easy to slide over
Explanation:
They create very little friction. Rough surfaces like rock and sand create much more friction, and are easy to grip on to.
Hello There!
Smooth Surfaces are easier to slide over. That's true.
Take an object and slide it across a rough surface. Now, slide the same object across a smooth surface.
What do you see?
I expect you wil find out that smooth surfaces are easier to slide over.
Reason:
Smooth surfaces have less friction than rough ones.
Hope it helps!
An object of mass 300 kg is observed to accelerate at the rate of 4 m/s 2 . Calculate the force required to produce this acceleration
Answer:
F = 1200 N
General Formulas and Concepts:
Forces
Newton's Second Law of Motion: F = ma
F is force (in N)m is mass (in kg)a is acceleration (in m/s²)Explanation:
Step 1: Define
Identify variables
m = 300 kg
a = 4 m/s²
Step 2: Find Force
Substitute in variables [Newton's Second Law of Motion]: F = (300 kg)(4 m/s²)Multiply: F = 1200 NTopic: AP Physics 1 - Algebra Based
Unit: Forces
what type of telescope can be used routinely on the surface of the earth during the day?
Answer:
Radio telescopes .
Explanation:
They have a modest size that can't make out as much detail (have a lower resolution) than visible light telescopes
The acceleration of an object in uniform circular motion always points toward the center of the circle. Question 2 options: True False
Answer:
The answer is true. Hope this helps!
true or false
your weight would be the same on the moon as it is on the earth
Answer:
False
Explanation:
You could weigh less on the moon then on Earth because the moon has a smaller gravitational force compared to Earth.
The wave speed is 3 x 10^8 m/s, and the frequency is 4 x 10^8 Hz. Calculate its wavelength.
Answer:
0.75m
Explanation:
V=FX
3×10^8=4×10^8×X
X= 3×10^8/4×10^8= 0.75m
Match the labels to the correct
location on the roller coaster.
At the bottom left,
Increasing potential energy.
At ascending,
Increasing kinetic energy.
At the peak,
Greatest potential energy.
At the descending,
Greatest kinetic energy.
Which describes refraction?
the reflection of light as it passes through a substance
the focusing of light as it passes through a substance
the emission of light as it passes through a substance
the bending of light as it passes through a substance
Answer:
A
Explanation:
Image result for Which describes refraction? the reflection of light as it passes through a substance the focusing of light as it passes through a substance the emission of light as it passes through a substance the bending of light as it passes through a substance
When electromagnetic radiation, in the form of visible light, travels from one substance or medium into another, the light waves may undergo a phenomenon known as refraction, which is manifested by a bending or change in direction of the light.
Phát biểu nào sau đây sai?
A. Hàm lượng cacbon trong thép cao hơn trong gang.
B. Sắt là kim loại màu trắng hơi xám, dẫn nhiệt tốt.
C. Quặng pirit sắt có thành phần chính là FeS2.
D. Sắt (III) hiđroxit là chất rắn, màu nâu đỏ, không tan trong nước.
Phát biểu nào sau đây sai?
A. Hàm lượng cacbon trong thép cao hơn trong gang.
B. Sắt là kim loại màu trắng hơi xám, dẫn nhiệt tốt.
C. Quặng pirit sắt có thành phần chính là FeS2.
D. Sắt (III) hiđroxit là chất rắn, màu nâu đỏ, không tan trong nước.
ANSWER:D. Sắt (III) hiđroxit là chất rắn, màu nâu đỏ, không tan trong nước.
___________________CARRY ON LEARNING
CAN YOU BRAINLEST ME
A non-uniform rod XY of mass 40 kg and length 5.0 m lies on the horizontal ground. Its centre of gravity is 2.0 m from the end X. Calculate the vertical force P, that will just be sufficient to lift the end Y from the ground. Why would the force P, if applied at the end X not be sufficient to lift the end X from the ground? (8 = 10.0 (SC/GCE) ms-2)
The vertical force P, that will just be sufficient to lift the end Y from the ground is 600 N.
If the force P is applied at end X, it will not be sufficient to lift end X from the ground because the force P is acting downwards.
The sketch of the rod is presented as follows;
|---- 2 ----------|---------------------- 3 ----------------------|
X-----------------------------------------------------------------Y
P ↓
40 kg
Take moment about the center of gravity;
P(2) = 40 x g (3)
2P = 40 x 10 (3)
2P = 1200
P = 600 N
Thus, the vertical force P, that will just be sufficient to lift the end Y from the ground is 600 N.
If the force P is applied at end X, it will not be sufficient to lift end X from the ground because the force P is acting downwards.
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Help me with this please
If a car accelerates from 0 to 10 m/s in 4 seconds, and the mass of the car is 1500 kg. What force is created by the car?
Answer:
PLS MARK BRAINLIEST
Explanation:
f=m (v- u)/t
u=0m/s
v=10m/s
t=4 secs
m=1500kg
f=1500(10-0)/4
f=3750N
This car started from rest at a
position of 4 km from the reference
point. It accelerated at 2.2 m/s^2
for a period of 0.5 minutes. How far
from the reference point is the car
located after the acceleration ends?
2 km
5 km
1 km
6 km
Answer:4.99km
Explanation:
We'll use s for distance, and t for time in seconds.
s = (1/2)at²
t = 0.5 minute*(60sec/1min)=30 sec
s = (1/2)*(2.2m/s²)(30sec)²
s = 990m
Reference point is 4km at start. Distance from reference point is 9km + 0.990km = 4.99km
que es el potencial motor?
Explanation:
Motor evoked potentials (MEPs) are the electrical signals recorded from the descending motor pathways or from muscles following stimulation of motor pathways within the brain.
Espero eso ayude. Marque como más inteligente.
What's a real-life example where you have pushed or pulled on different objects and you noticed a difference in how they moved.
Easy pts! Will give Brainliest too!
Answer:
Explanation:
Think about hockey for little to no friction if you push on the puck it moves fast and far.
Now imagine taking the same puck and pushing it on gravel or grass it will not have the same motion.
A car with mass 1750 kg travels on a flat circular track with radius
80.0 m at constant
speed 35.0 m/s. What is the force of friction between the tires and the road enabling the turn?
Hi there!
On a horizontal circular track with friction, the net force acting in the horizontal direction is:
∑F = Fκ, or the force of kinetic friction.
We know that ΣF = Mv²/r, so:
Mv²/r = Fκ
Plug in the given values to solve:
(1750)(35²)/80 = Fκ
Thus:
Fκ = 26796.875 N
frequence = ?
lambda = 0.5m
Vacocity = 340m/s
Talking about physic waves things.
Answer:
Below
Explanation:
To find the frequency of a wave you can use this formula :
f = v / λ
f = 340m/s / 0.5m
f = 680 Hz
Hope this helps!