3plss help, it times;;;;;;;;;;;;;;;;;;;;;;;;;

Answer:

I'm not sure you mean 2-(b/3) = -5/2 or (2-b)/3 = -5/2

Step-by-step explanation:

if

2-(b/3) = -5/2

12-2b = -15

12+15 = 2b

27 = 2b

27/2 = b

else

(2-b)/3 = -5/2

2(2-b) = -5×3

4-2b = -15

4+15 = 2b

19 = 2b

19/2 = b

Answer:

2.8

Step-by-step explanation:

Answer:

Step-by-step explanation:

2.8 units

Graphs attached

Done!

Hopw it helps

Answer:

b

Step-by-step explanation:

took the test a bit ago

Answer:

A-b because radius is the line segments from its center to its perimeter

Step-by-step explanation:

Answer:

  x + y -z = 6

Step-by-step explanation:

The equation of the line can be rewritten as ...

  (x, y, z) = (2, -3, 0) +t(1, 1, -1)

The direction vector of the line tells you the coefficients of the variables in the equation of the plane. The constant in that plane equation will be the value required to make it pass through the given point.

  x + y - z = (-1) +(4) -(-3)

  x + y - z = 6 . . . . equation of the plane

Answer:

x=14

y=27

z=43

Step-by-step explanation:

hope it helps!

Answer: The answer is C, 4 to the 21st over 5 to the 6th power.

Answer:easy it’s 8

Step-by-step explanation:I just did that same ixl/quiz!

[tex]2x-3y = 7~~~....(i)\\\\y = 3x -7~~~....(ii)\\\\\\\text{Substitute}~ y = 3x -7~ \text{in equation (i):}\\\\\\2x-3(3x-7) = 7\\\\\implies 2x -9x + 21 =7\\\\\implies -7x = 7 -21\\\\\implies -7x = -14\\\\\implies x = \dfrac{-14}{-7} = 2\\\\\\\text{Substitute x = 2 in equation (ii):}\\\\y=3(2) -7 = 6 -7 = -1\\\\\\\text{Hence (x,y) =(2,-1)}[/tex]

Answer:

12 multiple choice and 8 True/False

Step-by-step explanation:

To do this we set up a system of equations. Let x represent the True/Fale questions and y represent the multiple-choice questions. Here is a system we can use:

x + y = 20

2x + 7y = 100

We can solve this by using elimination. To do this we multiply one equation by a number, and add them together. If we multiply the first equation by -2, the "x"s will, when added together, cancel out so we can solve for y.

-2(x + y = 20)

-2x - 2y = -40

Now add them together

5y = 60

Solve for y.

y = 12

This means there are 12 multiple choice questions. 20 - 12 is 8 True/False questions.

Hope this helps and have a great day! :D

Answer:

8 True/False and 12 Multiple Choice

Step-by-step explanation:

x+y=20  ...1

2x+7y=100   ...2

Now you can multiply 2 on 1

2x+2y=40

2x+7y=100

Subtract:

-5y=-60

Divide -5 on both sides:

y=12

Substitute y with 12

x+12=20

Subtract 12 on both sides:

x=8

So there are 8 True/False and 12 Multiple Choice

Hope this Helps!

Answer helped by: azailiaskoglund

Answer:

[tex]b=-a^2-c[/tex]

Step-by-step explanation:

Answer:

[tex]3^{30}[/tex]

Step-by-step explanation:

      When you are raising an exponent to another power, you multiply the exponents together:

[tex]3^{30}[/tex]

-> Hopefully this is correct, unfortunately the picture is quite blurry

Have a nice day!

     I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

- Heather

Answer: 2.78

Step-by-step explanation:

long division

Answer:

Step-by-step explanation:

1 + 3 = 4

so find the point 1/4 of the way from (-1, 2) to (7, 8)

x coordinate

Δx = ¼(7 - (-1)) = 2

x = x₀ + Δx

x = -1 + 2 = 1

y coordinate

Δy =  ¼(8 - 2) = 1½

y = y₀ + Δy

y = 2 + 1½ = 3½

(1, 3½)

Answer:

$23.80

Step-by-step explanation:

30% off means we take 30% off of the original price, or we calculate

(1-30%)=70% of the shirt's price

34*70%=23.8

Answer:

2nd one

Step-by-step explanation:

i think(10+2)^2_4*11=100 in my opinion

Considering the definition of equation, for a value of n of 10 the cost and revenue are equal.

A first degree equation is a mathematical equality with one or more unknowns.

Solving an equation consists of finding the value that the unknown must take so that equality is fulfilled.

The steps to solve an equation are as follows:

The cost C in dollars of producing a certain item is represented by the equation C = [tex]\frac{n}{2}[/tex]+ 20, where n represents the number of items produced.

The revenue R, in dollars, from selling n items is represented by the equation R=2n+ 5.

The cost and revenue are equal. Then:

[tex]\frac{n}{2}[/tex]+ 20= 2n+ 5

Solving:

When a term passes to the other side of equality, its sign changes (if it is positive it becomes negative and vice versa):

20 -5= 2n - [tex]\frac{n}{2}[/tex]

15= [tex]\frac{3}{2}n[/tex]

The X is cleared. Since the term in front of it is multiplying, it goes to the other side of the equation by dividing.

15 ÷[tex]\frac{3}{2}[/tex]= n

10= n

Finally, for a value of n of 10 the cost and revenue are equal.

Learn more with this similar problems:

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Answer:

Step-by-step explanation:

Let the number of quarters be x and nickels be y.

Given:

We have equations:

Solve the system by elimination, subtract 5 times the first equation from the second one:

Find the value of y:

Verify:

Answer:

B: 15 quarters

Step-by-step explanation:

Step 1: Setup Coin Value and Coin Total Equation:

Coin Value Equation → 0.1d + 0.25q = $7.25 where d = dimes and q = quarters

Coin Total Equation → d + q = 50

Step 2: Rearrange Coin Total Equation in terms of dimes (d)

d = 50 - q ← Revised Coin Total Equation

Step 3: Plug in our Revised Coin Total Equation for d into our Coin Value Equation:

0.1(50 - q) + 0.25q = $7.25

0.1(50) - 0.1(q) + 0.25q = $7.25

5 - 0.1q + 0.25q = $7.25

5 + (0.25 - 0.1)q = $7.25

5 + 0.15q = $7.25

Step 4: Subtract 5 from each side of the equation to isolate q

5 - 5 + 0.15q = $7.25 - 5

0.15q = 2.25

Step 5: Divide each side of the equation by 0.15 to isolate q

0.15q

0.15

=

2.25

0.15

q = 15

Step 6: Using our value for q, Solve for d using our Coin Total Equation:

d + 15 = 50

Subtracting 15 from both sides, we get d + 15 - 15 = 50 - 15

d = 35

Summarizing our word problem, we see that 15 quarters and 35 dimes adds up to $7.25

The number of ways the yearbook chooses the winners of Most Athletic, Class Clown, Best School Spirit, and Best Looking is 330 ways.

Combination and permutation are two different ways of grouping elements of a set into subsets in mathematics. The elements of the subset can be listed in any order in a combination. The elements of the subset are listed in a specific order in a permutation.

Given that there are 11 students in a high school senior class. The number of ways will be calculated as,

The formula for arrangement,

¹¹C₄ = 11!/(7!)(4!)

¹¹C₄ = 330 ways

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Answer: 29

Step-by-step explanation:

29 ÷ 8 = 3 remainder: 5

I solved using long division.

Answer:

29

Step-by-step explanation:

30

24

5

8x3=24

24+5= 29

Beacuase it had to be smaller than 30

Answer:

20m+60

Step-by-step explanation:

given,

mark=m

june=m+6(6 years older that mark)

so,

after 10 years,

10(m+(m+6)

=10(2m+6)

=20m+60

[tex]\text{a. cm}^2\\\\\text{b. cm}^3\\\\\text{c. cm}\\\\\text{d. cm}^2\\\\\text{e. cm}^3\\[/tex]

Answer:

b =146

Step-by-step explanation:

34 and b form a straight line so they add to 180

b+34 = 180

b = 180-34

b =146

Answer:

x = 10

y = 6

Step-by-step explanation:

Multiply second equation with -1 and then add it up with first equation

(-1)*(6x - 7y) = 18

-6x + 7y = -18

6x - 6y - 6x + 7y = 24 - 18 add like terms

y = 6 to find the value of x use this information

6x - 6y = 24 replace y with 6

6x - 6*6 = 24

6x - 36 = 24 add 36 to both sides

6x = 60 divide both sides by 6

x = 10

Answer:

[tex]\begin{bmatrix}y>2+x\\ y>\frac{2-x}{2}\end{bmatrix}[/tex]

Step-by-step explanation:

Step 1: Solve the system of equations

[tex]\begin{bmatrix}-x+y>2\\ x+2y>2\end{bmatrix}[/tex]

Isolate [tex]y[/tex] for [tex]-x+y>2[/tex]

[tex]\mathrm{Add\:}x\mathrm{\:to\:both\:sides}[/tex]

[tex]-x+y+x>2+x[/tex]

[tex]y>2+x[/tex]

Isolate [tex]y[/tex] for [tex]x+2y>2[/tex]

[tex]\mathrm{Subtract\:}x\mathrm{\:from\:both\:sides}[/tex]

[tex]2y>2-x[/tex]

[tex]\mathrm{Divide\:both\:sides\:by\:}2[/tex]

[tex]\frac{2y}{2}>\frac{2}{2}-\frac{x}{2}[/tex]

[tex]y>\frac{2-x}{2}[/tex]

[tex]\bold{=\begin{bmatrix}y>2+x\\ y>\frac{2-x}{2}\end{bmatrix}}[/tex]

Step 2: Graph

Instructions for graphing:

[tex]\mathrm{1.\:Graph\:each\:inequality\:separately.}[/tex]

[tex]\mathrm{2.\:Choose\:a\:test\:point\:to\:determine\:which\:side\:of\:the\:line\:needs\:to\:be\:shaded.}[/tex]

[tex]3. \mathrm{The\:solution\:to\:the\:system\:will\:be\:the\:area\:where\:the\:shadings\:}\\\mathrm{from\:each\:inequality\:overlap\:one\:another.}[/tex]

When done, it should look like this:

Answer:

0.75p=c

Step-by-step explanation: