364 Cal to kilowatt-hours
Express your answer using three significant figures.

Given:

displacement(x)=18.3m

time(t)=122s

Average speed(v)=x/t

=18.3/122

=0.15m/s

Therefore,the train's average speed=0.15m/s

Answer:

false

Explanation:

can carry heat, not communication

The reaction rate with mass of the tablet being 1000 mg and volume of water 0.200 L is

(i) If Reaction time is 34.5 sec – 145 mg / L / sec is the reaction rate

(ii) If Reaction time is 28.9 sec – 173 mg / L / sec is the reaction rate

(iii) If Reaction time is 23.1 sec – 216 mg / L / sec is the reaction rate

Given that, Mass of tablet = 1000 mg

                  Volume of water = 0.200 L

We need to find the reaction rate

We know that, Reaction rate =  [tex]\frac{mass of tablet / volume of water}{reaction time}[/tex]

(i) Reaction rate if reaction time is 34.5 sec = [tex]\frac{1000 / 0.200}{34.5}[/tex] = 145 mg / L / sec

(ii) Reaction rate if reaction time is 28.9 sec = [tex]\frac{1000/0.200}{28.9}[/tex] = 173 mg / L / sec

(iii) Reaction rate if reaction time is 23.1 sec = [tex]\frac{1000/0.200}{23.1}[/tex] = 216 mg / L / sec

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The pH established of the equilibrum is 7.

What is equilibrium?

equilibruim is a state in which opposing forces of influence are balanced.

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A metric prefix is a unit prefix used to denote a multiple or submultiple of a basic unit of measure. Today's metric prefixes are all decadic. Each prefix has its own distinctive sign, which is added before any unit symbol.

Since humans have been measuring things for thousands of years, the units we use to represent those measurements have changed. Numerous units are now available to describe physical amounts.

Longitude, for instance, can be expressed in terms of the foot, metre, fathom, chain, parsec, league, and so on.

In the SI, multiples and subdivisions of any unit can be designated by combining the prefixes deka, hecto, and kilo, which represent 10, 100, and 1000 respectively, and deci, centi, and milli, which represent correspondingly, with the name of the unit.

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It eats food to get energy is NOT a necessary characteristic of a living thing

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First, we have to know the rules to recognize significant numbers:

Zeros between two non-zero digits ARE significant.

are

All non-zero numbers are significant.

Trailing zeros to the right of the decimal are significant.

Leading zeros are not significant.

Trailing zeros in a whole number with the decimal shown are significant.

Trailing zeros in a whole number with no decimal shown are not significant.

After these rules, we can say that 890 has only 2 significant numbers.

Answer: 2 significant digits

Taking into account the definition of dilution, you would take 5 mL of the 0.10 M solution of HCl and you have to add 5 mL of deionized water.

When it is desired to prepare a less concentrated solution from a more concentrated one, it is called dilution. In this way, dilution is the process of reducing the concentration of solute in solution, which is accomplished by simply adding more solvent to the solution.

In a dilution the amount of solute does not change, but as more solvent is added, the concentration of the solute decreases, as the volume of the solution increases.

A dilution is mathematically expressed as:

Ci×Vi = Cf×Vf

where

In this case, you know:

Replacing in the definition of dilution:

0.10 M× Vi= 0.050 M× 10 mL

Solving:

Vi= (0.050 M× 10 mL)÷ 0.10 M

Vi= 5 mL

Finally, this means that you would take 5 mL of the 0.10 M solution of HCl. If you need to prepare 10 ml of 0.050 M, you have to add 5 mL of deionized water.

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Using ideal gas laws and the balanced reaction equation for the combustion of butane, we can calculate that the volume of produced carbon dioxide will be 25.6 L.

The balanced reaction equation for butane combustion looks like this:

[tex]2C_{4} H_{10} + 13O_{2}[/tex] → [tex]8CO_{2}+10H_{2} O[/tex]

We can see that 2 moles of butane (M = 58 g/mol) produce 8 moles of carbon dioxide. This allows us to set up a proportion that we can use to calculate the amount of carbon dioxide produced by the combustion of 14.0 g of butane:

116 g of butane : 8 moles of carbon dioxide = 14.0 g of butane : X

X = 8 moles of carbon dioxide * 14.0 g / 116 g = 0.9655 mol of carbon dioxide

Now, using the ideal gas laws, we can calculate the volume of released carbon dioxide.

PV = nRT ⇒ V = nRT/P = 0.9655 mol * 0.08206 Latm/Kmol * (25 + 273) K / 0.922 atm = 25.6 L

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By using the general gas equation, the mass of Xenon in the mixture is found to be 27.44g.

The ideal gas law, also known as the general gas equation, says that the product of the pressure and volume of one gram of an ideal gas is equal to the result of the universal gas constant and the absolute temperature of the gas.

PV = nRT denotes the general gas equation. In this equation, the letters P, V, n, R, T stand for the pressure of the ideal gas, the volume of the ideal gas, the total amount of the ideal gas given in moles, the universal gas constant and the temperature, respectively.

The general gas equation states that one mole of an ideal gas may occupy a volume of 22.414 liters under standard circumstances, which are a pressure of 101,325 Pa / 1atm and a temperature of 273.15 K or 0°C.

Given:

Pressure, P = 2.44atm

Temperature, T = 86+273 = 359K

Volume, V = 7.66L

To find:

Mass of Xe = ?

Formula:

PV = nRT

Calculations:

Let total no. of moles of Ar and Xe = y

n = PV/RT

n = 2.44 x 7.66 / (0.0821 x 359) = 0.634mol

No. of moles of Argon (yAr) = 17/40 = 0.425mol

y = yAr + yXe

0.634 = 0.425 + yXe

yXe = 0.634 - 0.425

yXe = 0.209mol

Mass of Xe = no. of moles x gram atomic mass

Mass of Xe = 0.209 x 131.293 = 27.44g

Result:

27.44g Xenon is present in the given Argon and Xenon mixture.

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Based on the mole ratio of the reaction and the volume of the reactants used;

The amount of sodium hydroxide that reacted with hydrochloric acid is calculated from the mole ratio of the reaction between hydrochloric acid and sodium hydroxide.

The equation of the reaction is given as follows:

HCl (aq) + NaOH (aq) ---> NaCl + H₂O

The mole ratio of HCl and NaOH is 1 : 1

Moles of HCl in 24.40 cm³ of 0.120 mol dm of hydrochloric acid solution will be determined as follows:

Moles of HCl = 0.120 * 24.40 / 1000

Moles of HCl = 0.002928 moles

Thus moles of NaOH reacted = 0.002928 moles

The amount of sodium hydroxide unreacted in 200 cm³ solution is determined as follows:

Moles of sodium hydroxide unreacted in 25 cm³ solution = 0.002928 moles

Moles of sodium hydroxide unreacted in 200 cm³ solution = 0.002928 moles * 250 / 25

Moles of sodium hydroxide unreacted in 200 cm³ solution = 0.0234 moles.

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The Iupac Name of given three compounds are 3,4,5-trimethylheptane, 2,2,3,3-tetramethylpentane and 2,2- dimethyl-3-ethylpentane.

For (1),

The longest straight chain have 7 carbon compound and having single bond, suffix of this compound is Heptane. Now there are three functional group of methyl there for prefix is trimethyl. Overall the name of compound is 3,4,5-trimethylheptane.

The longest straight chain have 5 carbon compound and having single bond, suffix of this compound is pentane. Now there are four functional group of methyl there for prefix is tetramethyl. Overall the name of compound is 2,2,3,3-tetramethylpentane.

The longest straight chain have 5 carbon compound and having single bond, suffix of this compound is pentane. Now there are three functional group of methyl and ethyl so they write according to alphabetic order. Overall the name of compound is 2,2- dimethyl-3-ethylpentane.

Thus, we concluded that the The Iupac Name of given three compounds are 3,4,5-trimethylheptane, 2,2,3,3-tetramethylpentane and 2,2- dimethyl-3-ethylpentane.

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A solution that is 20 mass % sugar will have highest density as density is directly proportional to mass and inversely proportional to volume. Thus option C is correct.

Density is defined as the degree to which a material is packed together

It can also be defined as substance mass per unit volume.

Density can be expressed as

Density = mass / volume

Thus, a  solution that is 20 mass % sugar will have highest density as density is directly proportional to mass and inversely proportional to volume. Thus option C is correct.

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A material with density 2.7 g/ml and volume 35.6 ml would have a mass of 96.12 g

Given that,

Density (D) = 2.7 g/ml

Volume (V) = 35.6 ml

We need to find the mass (m) of the material

We know that,

D = m / V

D = Density

m = Mass

V = Volume

Substituting,

2.7 = m / 35.6

m = 2.7 * 35.6

m = 96.12 g

Thus, mass of the material is 96.12 g

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The age of the granite given it contains 25% parent (uranium-235) and 75% daughter (lead-206) is 1408 million years

We'll begin by calculating the number of half lives that has elapsed. This can be obtained as follow:

2ⁿ = N₀ / N

2ⁿ = 100 / 25

2ⁿ = 4

2ⁿ = 2²

n = 2

The age of the granite can be obtained as follow:

n = t / t½

Cross multiply

t = n × t½

t = 2 × 704

t = 1408 million years

From the calculations made above, we can conclude that the age of the granite is 1408 million years

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A sphere surrounds the atomic nucleus called the s orbital. There are shells within the sphere where an electron is more likely to be discovered right now. 1s is the smallest sphere. Greater than the 1s orbital are the 2s and 3s orbitals.

Each p orbital has two lobes, that are located on either side of the plane of the nucleus. The three p orbitals are equal in terms of size, shape, and energy, but they differ in how the lobes are orientated. These three orbitals are referred to as 2px, 2py, and 2pz because the lobes are located along one of the x, y, or z-axis. Similar to s orbitals, p orbitals grow in size and energy as the primary quantum number rises (4p > 3p > 2p).

sp3 orbital: One of a group of hybrid orbitals that result from mathematically combining one s orbital and three p orbitals to create four new equivalent orbitals that are directed toward the corners of a regular tetrahedron.

One of the hybrid orbitals created when one s orbital and one p orbital are mathematically merged to create two new equivalent, perpendicular orbitals is the sp orbital. With the exception of being closer to the nucleus, sp orbitals resemble p orbitals in appearance.

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Trisaccharides, an oligosaccharide, are created when three monosaccharides are linked together by two glycosidic connections.

Trisaccharides, an oligosaccharide, are created when three monosaccharides are linked together by two glycosidic connections. The constituent monosaccharides can form each glycosidic bond between any hydroxyl group, just like the disaccharides can.

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Theoretical mass (O₂)= H₂O₂ Volume×  H₂O₂ density× {( 1 mol O₂)/(2 mol H2O2)}×{( mol of  H₂O₂ /g  H₂O₂ )}

H2O2 Volume= 5 ml

Known density( H₂O₂ )= 1.02 g/ml

Molar mass ( H₂O₂ )= 34.01 g/mol

Reciprocal molar mass(  H₂O₂ )= 0.0294

Theoretical mass( O₂)= 5×1.02× 0.0294× 1/2= 0.0749 moles

Actual moles of O₂ and percentage of  H₂O₂

P= 753 mm Hg×1 atm/760 mm Hg= 0.991 atm

V= 45  ml× 1L /1000 ml= 0.045 L

n= PV/RT

Actual moles ( O₂)= (0.991×0.045)/(0.0821×296 K)= 0.0445/24.3016= 1.8×10^-3 moles

Percentage ( H₂O₂ )= Theoretical moles(O₂)×100= 0.0749×100= 7.49%

Mass of  H₂O₂ (percent)= 3%

Concentration by mass( H₂O₂ )= 3 gm H2O in 100 ml of H2O

Volume ( H₂O₂ )= 100 ml

1 mol ( H₂O₂ )= 34.02 g O2

(3g  H₂O₂ /100 ml Solution)×( 1 mol  H₂O₂ /34.02 g H2O2)

No. Of moles ( H₂O₂ )= 0.088 moles

Mass ( H₂O₂ )= 0.088 moles × 34.02 = 2.99 g

%  H₂O₂ = (2.99 g  H₂O₂ /100 ml Solution)×100= 2.99%

% error= (%  H₂O₂ from the bottle-experiment %  H₂O₂ )/(% H₂O₂ from bottle)×100

=[ (3-2.99)/(3) ]× 100= 0.34% error.

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Vinegar or acetic acid(CH3COOH) has intermolecular forces  of hydrogen bonding, dipole-dipole interactions and dispersion force.

Intermolecular forces can be defined as the attractive and repulsive forces that arise between the molecules of a substance.

Intermolecular forces includes the electromagnetic forces of attraction or repulsion which act between atoms and other types of its close particles such as atoms or ions.

Vinegar or acetic acid(CH3COOH) has intermolecular forces  of hydrogen bonding, dipole-dipole interactions and dispersion force.

Vinegar or acetic acid(CH3COOH)  has an especially strong type of hydrogen bonding. In solid state, the molecules in the acetic acid form cyclic pairs connected by hydrogen bonds. Thus, making it to have a low volatility.

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Depending on the extraction you are performing and the way it was washed, the separatory funnel can either be dried, washed again, or just used as is.

In an ideal case, the separatory funnel was thoroughly washed and rinsed with deionized water. Because most liquid-liquid extractions include an aqueous layer, the small amount of water already present in the funnel will not have any negative impact on the results of your experiment, and the funnel can be used as it is.

If you are not sure whether the funnel was properly washed, you can quickly wash it yourself using detergent and water, rinse it thoroughly with deionized water, and then use it.

Finally, you can rinse the funnel with some ethanol (or, if possible, acetone), which will pick up water and wash away any organic impurities that might be present, and then dry it with a hair dryer. Be careful to wait for the funnel to cool after drying because many organic solvents have low boiling points and might cause a problem if poured into a hot funnel.

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Answer:

it's false the correct answer will be There are more red blood cells than white blood cells in the blood

The presence of water on the surface of the plastic sample will be indicated with a broad peak in the 2400 – 3200 [tex]cm^{-1}[/tex] range of Infra-red (IR) spectroscopy.

The term "infra-red (IR) spectroscopy" refers to a method for locating the functional groups that are present in a molecule. The electromagnetic spectrum's infrared area is located between the microwave and the visible spectrum. The typical Infra-red (IR) absorption range is 600-4000 [tex]cm^{-1}[/tex]. The IR spectra of substances that absorb in the IR range exhibits peaks. A molecule that is IR active is water. In the Infra-red region, it absorbs. Water is thus not used as a solvent in IR spectroscopy. Therefore, it is necessary that water existing on the surface of the samples be removed during cleaning before their IR is recorded. However, if cleaning does not get rid of the water that is on the surface, an expansive peak in the IR spectra will show up between 2500 and 3200 [tex]cm^{-1}[/tex].

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Dispersion forces and dipole-dipole forces are present in pure samples of both ch₃ch₂ch₂f and ch₃ch₂ch₂oh.

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Answer:

Silicone

Explanation:

Silicone matches all the things

Answer:

Acceleration

Explanation:

The reaction rate constant and activation energy are connected through the Arrhenius equation. By using the logarithmic form of that equation, we can calculate the activation energy of 0.2045 kJ/mol.

According to Arrhenius equation, activation energy and rate constant are connected in the following way:

[tex]k = Ae^{\frac{-E_{a} }{RT} }[/tex]

Ea is the activation energy, k is the rate constant, R is the universal gas constant (8.314 J/Kmol) and T is absolute temperature (in Kelvins). This expression can be transformed so that it is easier to determine Ea:

[tex]lnk = \frac{-Ea}{R}*\frac{1}{T}[/tex]

When lnk is plotted as a function of 1/T, the slope coefficient is equal to -Ea/R. This means that:

-24.6 K = -Ea/R ⇒ Ea = 24.6 K * R = 24.6 K * 8.314 J/Kmol = 204.5 J/mol = 0.2045 kJ/mol

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A single electron from the outermost shell of this element moves to the outermost shell of an atom with seven electrons.

When forming ions elements typically gain or lose the minimum number of electrons required to make a complete octet. For example, fluorine has 7 valence electrons, so it is most likely to gain an electron and form an ion of charge At the outermost energy level he states 8 electrons must be reached for an atom to be stable. Particles smaller than an atom.

Ionization is the process by which ions are formed by gaining or losing electrons from atoms or molecules. When an atom or molecule receives an electron it becomes a negatively charged anion and when it loses an electron it becomes a positively charged cation. Energy can be lost or gained in the formation of ions.

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No, this item is not made of pure silver because if it has been made from pure silver that it would have displaced only 1.16cm³ of water but due to the addition of some other low-density element it displaces 1.9cm³ of water.

For pure silver

density of pure silver is = 10.49 g/cm³

mass of silver = 12.2 gram

since, density = mass/volume

          volume = mass/density

                        = 12.2/10.49 cm³

                         = 1.16 cm³

But the actual displaced water is 1.9cm³, which means some other element of lower density has been added.

Therefore, it is clear that the given jewelry is not made of pure silver.

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Answer:

The chemical reaction 2H2+O2→2H2O 2 H 2 + O 2 → 2 H 2 O is classified as a synthesis reaction.

Explanation: