30 POINTS HELP PLEASE
A boat is tied to a dock using two ropes.
what is the length of rope A

Answer:

miles: 55(36/60) = 55(0.6) = 33 miles

mins: 60(14/17.5) = 60(0.8) = 48 minutes

Total amount of time, in minutes

The total distance, in miles

Step-by-step explanation:

The required distance and time are 47 miles and 84 minutes, respectively.

Speed is measured as the ratio between the distance and time, and the SI unit of speed is m/s.

We know that speed = distance / time

Finding for distance =

55(36/60) = 55(0.6) = 33 miles

Therefore, The total distance, in miles =

= 33 miles + 14 miles

= 47 miles

For Time =

60(14/17.5) = 60(0.8) = 48 minutes

Therefore, Total amount of time, in minutes =

36 minutes + 48 minutes

= 84 minutes

Hence, The required distance and time are 47 miles and 84 minutes, respectively.

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The upper control limit is 16.4 if our  desired confidence interval is 99.73%.

Given 131 population

standard deviation  = 5

sample size = 11.

mean   = 131/11 = 11.9.

determine the upper control limit if desired

confidence interval is 99.73%

What is Confidence interval?

In statistics, a confidence interval describes the likelihood that a population parameter will fall between a set of values for a given percentage of the time.

Confidence interval = sample mean ± margin of error

Upper limit  = sample mean + margin of error.

margin of error = z* * population of standard deviation/[tex]\sqrt{n}[/tex].

margin of error = 3.00 * 5/[tex]\sqrt{11}[/tex].

value of z* for 99.73% confidence interval  is 3.00.

so margin of error = 4.5.

Upper limit  = 11.9 + 4.5

Upper limit  = 16.4

The upper control limit is 16.4 if our  desired confidence interval is 99.73%.

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The arithmetic mean for this value is M=3.1.we can calculate this data from frequency distribution.

It is sum of collection of number divided by the count of numbers.Its value   can be positive or negative both.The collection is often a set of results from an experiments and observational study.

It is often used as a parameter in statistical distribution or as a result to summarize the observations of an experiment survey.It is simplest way to used to measure the average.Its also measure frequency distribution by considering all of the observations.

Now we are using formula  for arithmetic mean

 A.M= Sum of (fx)/sum of (f)

by putting values in this formula we have

A.M= 31/10

A.M= 3.1

Hence 3.1 is the arithmetic mean for given frequency data.

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You transfer $100 from your savings account to your checking account as a result, m1 will Remains unchanged and m2 will  increase by $100.

Hence, You transfer $100 from your savings account to your checking account as a result, m1 will Remains unchanged and m2 will  increase by $100.

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The angle C can be obtained rom the computation below as 16 degrees.

We know that the cosine is one of the angular measures that we have. The trigonometric ratios that we have are the sine the cosine and the tangent. We can be able to obtain the angle of the when we take the inverse of the cosine of the angle.

Now we know that the cosine of the angle can be defined as the ratio of the adjacent and the hypotenuse. The value of the cosine of the angle can be gotten from the table of the standard measure of the angles or by the use of a calculator.

We then have that;

Cos C= 0.9613

C = Cos-1( 0.9613)

By the time we make use of a good calculator we obtain the angle as;

C = 16 degrees

This is the value of the angle.

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The rate at which the energy pass through an area of 1.0 m² at 2.0 km is equal to 1.97 × 10⁹ J/s.

At a constant power, the intensity of a wave is inversely proportional to the distance from the source. Mathematically, the intensity of a wave with respect to the distance from a source can be modeled (represented) by this mathematical expression;

I ∝ 1/r²

Where:

Next, we would re-write the mathematical expression and then determine the intensity of a wave from source as follows;

I₁/I₂ = r₂²/r₁²

I₁ = I₂(r₂²/r₁²)

Note: We know that its intensity when it passed a point from the source is 2.0 km.

Substituting the given parameters into the formula, we have;

I₁ = 2.8 × 10⁶ × (53²/2²)

I₁ = 1.97 × 10⁹ J/m²s.

Now, we can calculate the rate of the energy by using this formula;

Power = intensity × area

Power = 1.97 × 10⁹ × 1.0

Power = 1.97 × 10⁹ J/s.

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a) The thrust of the propeller is  23,834 lbf and b)  The induced velocity is 8.44 mph c)  The velocity in the downstream far field away from the propeller disc is 161.56 mph

a)The thrust of the propeller can be calculated using the equation,

Thrust = 2πρR^2V^2, where ρ is the air density, R is the propeller radius, and V is the average velocity of the propeller disc. For sea level at a speed of 150 mph, the air density is about 0.002377 slugs/ft^3.

the thrust of the propeller can be calculated as: Thrust = 2π x 0.002377 x (6 ft)^2 x (170 mph)^2 = 23,834 lbf

b)The induced velocity can be calculated using the equation v_ind = (1/2) V ∞ [1–(V_∞/V_tip)^2]^(1/2), where V_∞ is the free stream velocity and V_tip is the tip velocity of the propeller. For the given problem, the induced velocity can be calculated as: v_ind = (1/2) x 150 mph x [1–(150 mph/170 mph)^2]^(1/2) = 8.44 mph

c) The velocity in the downstream far field can be calculated using the equation V_∞ = V_tip – v_ind, where V_tip is the tip velocity of the propeller and v_ind is the induced velocity. For the given problem, the velocity in the downstream far field can be calculated as: V_∞ = 170 mph – 8.44 mph = 161.56 mph

d)The power absorbed by the fluid can be calculated using the equation P_fluid = (1/2) ρ V_ind^3 A_disc, where ρ is the air density, V_ind is the induced velocity, and A_disc is the area of the propeller disc. For the given problem, the power absorbed by the fluid can be calculated as P_fluid = (1/2) x 0.002377 x (8.44 mph)^3 x (π x (6 ft)^2) = 42.7 hp

e)The power absorbed by the propeller can be calculated using the equation P_prop = T x V, where T is the thrust of the propeller and V is the flight speed of the aircraft. For the given problem, the power absorbed by the propeller can be calculated as: P_prop = 23,834 lbf x 150 mph = 3,575,500 ft-lbf/s = 4,844.08 hp

f)The efficiency of the propeller can be calculated using the equation η = P_prop/P_fluid, where P_prop is the power absorbed by the propeller and P_fluid is the power absorbed by the fluid. For the given problem, the efficiency of the propeller can be calculated as: η = 4,844.08 hp/42.7 hp = 113.6%

Hence, d) The power absorbed by the fluid is  42.7 hp e)  the propeller power (thrust flight speed) is  4,844.08 hp f)  The propeller efficiency is 113.6%

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Answer: you need to have at least $312,500 in your account at the beginning.

Step-by-step explanation:

The total amount of money you will need to withdraw over the 25-year period is $30,000 * 25 years = $750,000. To find the total amount of interest you will earn, we need to use a compound interest formula. The formula for compound interest is:

A = P(1 + r/n)^nt

where A is the total amount of money you will have in your account after 25 years, P is the initial amount of money in your account, r is the annual interest rate, n is the number of times the interest is compounded per year, and t is the number of years.

In our case, we have A = $750,000, P = ?, r = 8%, n = 1 (since the interest is compounded annually), and t = 25. Plugging these values into the formula, we get:

$750,000 = P * (1 + 0.08/1)^1 * 25

We can simplify this equation to:

$750,000 = P * 1.08^25

To find the value of P, we can divide both sides of the equation by 1.08^25:

$750,000 / 1.08^25 = P

We can use a calculator to compute the value of 1.08^25, which is approximately 2.4. This means that the initial amount of money you need in your account is $750,000 / 2.4 = $312,500.

Therefore, to be able to withdraw $30,000 each year for 25 years and earn 8% interest on your account, you need to have at least $312,500 in your account at the beginning.

The population standard deviation of {5, 8, 8, 5} is 3

The given population is

{5, 8, 8, 5}

The mean of the population = Sum of the terms /  Number of Terms

Find the values and substitute the values in the equation

Sum of terms = 5 + 8 + 8 +5

= 26

Number of terms = 4

The mean of the population= 26 / 4

= 6.5

The variance of the population = (5 - 6.5)^2 + (8 - 6.5)^2 + (8 - 6.5)^2 + (5 - 6.5)^2

= (-1.5)^2 + (1.5)^2 + 1.5^2 + (-1.5)^2

= 2.25 + 2.25 + 2.25 + 2.25

= 9

The standard deviation of the population  = [tex]\sqrt{9}[/tex]

= 3

Therefore, the standard deviation is 3

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Answer:

------------------------------

Given

To factor it completely, factor out the common factor x + 3:

Answer:

39960

Step-by-step explanation:

first you have to divide how much money they made by the products to find the base price of each product so 13,000 / 325 which has a quotient of $40 per product then you multiply 40 by 999, so 40 x 999 has a product of 39960

The rate of change in sales volume when the price is $22 is -0.107 and When the price increases $1, the sales volume will decrease by -48

The rate of change formula gives the relationship describing how one quantity changes in relation to the change in another quantity

According to the question,

y denotes the weekly sales volume and p denotes the price per unit

Equation is [tex]y = \frac{32}{3p + 1^{\frac{-2}{5}}}[/tex]

(a) We have to find the rate of change in sales volume when price is $22

Differentiating the equation w.r.t p,

[tex]\frac{dy}{dp} = \frac{-32(3)}{(3p + 1^\frac{-2}{5})^2}[/tex]

Putting value of p = 22

=> [tex]\frac{dy}{dp} = \frac{-32(3)}{(3(22) + 1^\frac{-2}{5})^2}[/tex]

=> -96 / (66 + 1 - 2(22)(1))²

=> -96 / 897

=> -0.107

(b) To find If the price increases $1, the sales volume will decrease by

Replacing p = 1

=> dy/dp = -96/2

=> -48

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Answer:

K = 4

Step-by-step explanation:

The x-y point  ( K, -5 ) means that ...

x = K and y = -5

Let's plug in K and -5 for y in the equation to find the value of K (which is the same as x).

3(K) + (-5) = 7

3K - 5 = 7

3K = 7 + 5

3K = 12

K = 4

To use upper and lower sums to approximate the area of the region under the curve y = √6x, we need to divide the interval of integration into a certain number of subintervals of equal width.

Let's say that we want to divide the interval [a, b] into n subintervals of equal width. We can then define the points x0, x1, ..., xn as follows:

x0 = a

x1 = a + (b - a)/n

x2 = a + 2(b - a)/n

...

xn = b

The width of each subinterval is (b - a)/n.

We can then use these points to define the upper sum and lower sum as follows:

Upper sum = ∑ (b - a)/n * max(f(x))

Lower sum = ∑ (b - a)/n * min(f(x))

where the sum is taken over all subintervals, and max(f(x)) and min(f(x)) represent the maximum and minimum values of the function f(x) on each subinterval, respectively.

To calculate the upper and lower sums, we need to evaluate the function f(x) at each of the points x0, x1, ..., xn. For example, if we want to calculate the upper sum using 4 subintervals, we would evaluate the function at the points x0, x1, x2, and x3, and then use these values to calculate the upper sum using the formula above.

Once we have calculated the upper and lower sums, we can use them to approximate the area of the region under the curve. The area of the region is approximately equal to the average of the upper and lower sums.

For example, if the upper sum is 1.5 and the lower sum is 0.5, then the area of the region is approximately (1.5 + 0.5)/2 = 1.

In general, as we increase the number of subintervals, the upper and lower sums will get closer and closer to the actual area of the region, and the approximation will become more accurate.

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The standard deviation of Alex's new probability distribution is given as follows:

0.775.

The standard deviation of a discrete distribution is calculated as the square root of the sum of the differences squared between each observation and the mean, multiplied by their respective probabilities.

Hence the standard deviation of Alex's new probability distribution is calculated as follows:

S(X) = square root(0.035 x (0 - 1.471)² + 0.579 x (1 - 1.471)² + 0.286 x (2 - 1.471)² + 0.08 x (3 - 1.471)² + 0.02 x (4 - 1.471)²)

S(X) = 0.775.

Meaning that the second option is correct.

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Answer:

164

Step-by-step explanation:

Assuming that you are allowed to use graphing tools:

f(x) is below g(x) for interval [1,3]

g(x) is below f(x) for interval [3,5]

Rules of finding area between two graphs:

[tex]\int\limits^a_b {|upper - lower|} \, dx[/tex]

For interval [1,3]:

[tex]\int\limits^3_1 {g(x) - f(x)} \, dx[/tex]

[tex]\int\limits^3_1 {|(2x^{3} - 10x^{2} +29x+8)-(3x^{3}-3x^{2} -x+8) } \, dx[/tex]

[tex]\int\limits^3_1 {-x^{3} -7x^{2} +30x} \, dx[/tex]

[tex]= [-\frac{1}{4}x^{4} - \frac{7}{3}x^{3} + 15x^{2}]^3_1[/tex]

[tex]= [-\frac{1}{4}3^{4} - \frac{7}{3}3^{3} + 15*3^{2}] - [-\frac{1}{4}1^{4} - \frac{7}{3}1^{3} + 15*1^{2}][/tex]

[tex]= -\frac{81}{4} - \frac{189}{3} + 135+\frac{1}{4} + \frac{7}{3}- 15\\[/tex]

[tex]= \frac{118}{3}[/tex]

For interval [3,5]

[tex]\int\limits^5_3 {f(x)-g(x)} \, dx[/tex]

[tex]\int\limits^5_3 {|(3x^{3}-3x^{2} -x+8)-(2x^{3} - 10x^{2} +29x+8)|} \, dx[/tex]

[tex]\int\limits^5_3 {|x^{3}+7x^{2} -30x|} \, dx[/tex]

[tex]= [\frac{1}{4}x^{4} +\frac{7}{3}x^{3} - 15x^{2}]^5_3[/tex]

[tex]= [\frac{1}{4}5^{4} +\frac{7}{3}5^{3} - 15*5^{2}] -[\frac{1}{4}3^{4} +\frac{7}{3}3^{3} - 15*3^{2}][/tex]

[tex]= \frac{625}{4} +\frac{875}{3} - 375 -\frac{81}{4}} -\frac{189}{3} + 135[/tex]

[tex]=\frac{374}{3}[/tex]

Total area

[tex]= \frac{118}{3} + \frac{374}{3}\\[/tex]

[tex]= 164[/tex]

The perimeter of the right triangle is 26 units.

From the given graph, the measure of side AB= 8 units and the measure of side BC= 7 units.

The perimeter of a shape is defined as the total distance around the shape. It is the length of the outline or boundary of any two-dimensional geometric shape. The perimeter of different figures can be equal in measure depending upon the dimensions.

By Pythagoras theorem,

AC²=AB²+BC²

⇒ AC²=8²+7²

⇒ AC²=113

⇒ AC=10.63

≈ 11 units

Perimeter =AB+BC+AC

= 8+7+11

= 26 units

Therefore, the perimeter of the right triangle is 26 units.

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The temperature of the pizza that Suraj took from the freezer, after 2 minutes, given the graph, is 10 degrees Celsius.

The temperature of the pizza that Suraj took from the freezer and put in the oven, is shown on the graph. To find the temperature of this pizza after 2 minutes, given the line in the graph, look at the point where the 2 minutes on the x - axis, intercepts with the line.

This point on the y - axis is 10 degrees Celsius.

This simply means that at 2 minutes, Suraj's pizza slice had a temperature of 10 degrees Celsius.

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For this problem, it is best to consider E to be the case in which she has all of the green ones, and then apply the formula for calculating the probability of a complement. 

. To determine the likelihood that she will receive all of the green  ones, we must first determine two values: the total number of possible outcomes, n(S), and the total number of favorable outcomes for the given event. Because she selects 8 marbles from a total of 11, n(S) = C(11, 8) = 165. To get all the green  ones, she must first select three red marbles from a set of three, and then select the remaining five marbles.

from the 8 non-red ones. There are (3,3)(8, 5) = 56 ways to do this. Thus,

() =56/165

. The probability of not occurring is then (′) = 1 −56/165=109/165

, so this is the probability that she does  get all the green one.

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Answer:

2 2/7 - 4 5/7      

= -2 3/7

Step-by-step explanation:

Answer:

A reflection of a point over the line y=−x is shown. The rule for a reflection in the origin is (x,y)→(−y,−x) .

The magnitude of the current induced in the wire is 1.2×10^{-8} and direction of the current induced in the wire is counter clockwise.

In the given question,

A rectangle (W = 20 cm, H = 30 cm) and has a resistance of(R) = 5.0 mΩ.

B(s) = 4.0 μT and B(b) = -2.5

t(s) = 2.0 s

From the question

dB(1)/dt = B(s)/t(s)

dB(1)/dt = 4 μT/2

As μ = 10^{-6}

dB(1)/dt = 2×10^{-6} T/s

dB(2)/dt = 1/2dB(1)/dt

dB(2)/dt = 2×10^{-6} /2

dB(2)/dt = 1×10^{-6} T/s

dB(3)/dt = B(b)dB(1)/dt

dB(3)/dt = -2.5×2×10^{-6} T/s

dB(3)/dt = -5×10^{-6} T/s

Now the change in magnetic field is,

dB/dt = dB(1)/dt + dB(2)/dt + dB(3)/dt

dB/dt = 2×10^{-6} + 1×10^{-6}/2 - 5×10^{-6}

dB/dt = - 2×10^{-6}

Now finding the area

Area = 1/2 wh

Firstly converting the w and h in m

So w = 0.20 m, h = 0.30 m

Area = 1/2 *0.20*0.30

Area = 0.03 square m

The induced EMF is

EMF = -AdB/dt

EMF = -(0.03)*(- 2×10^{-6})

EMF = 0.06×10^{-6}

The magnitude of the current induced in the wire is

I = EMF/R

I = 0.06×10^{-6}/5

I = 0.012×10^{-6}

I = 1.2×10^{-8}

Now, the direction of the current induced in the wire is counter clockwise.

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The right question is:

Figure (a) shows a wire that forms a rectangle (W = 20 cm, H = 30 cm) and has a resistance of 5.0 mΩ. Its interior is split into three equal areas, with magnetic fields B(1), B(2), and B(3). The fields are uniform within each region and directly out of or into the page as indicated. Figure (b) gives the change in the z components B(z) of the three fields with time t; the vertical axis scale is set by B(s) = 4.0 μT and B(b) = -2.5 B(s) and the horizontal axis scale is set by t(s) = 2.0 s. What are the magnitude and direction of the current induced in the wire?

Answer:

This is a math equation about GCD { GREATEST COMMON DIVISOR }
7 groups
Each group [ 4 red marbles / 5 blue marbles ]

Step-by-step explanation: { I will use the . as mutiply }

So first let's take a little of analysis
We take a as the groups that should be made, a ∈ N*
In the question, we can see: 28 can be divisible to a / 35 can be divisible to a

Because of that, we know that a is the smallest so a is: GCD ( 28, 30 )
Now, let's factorize numbers into prime factors:
28 = [tex]2^{2} . 7[/tex]
35 = 5.7
Choose common prime factors: 2,3,5,7
[ Because we are doing GCD, we will need to choose the common prime factors as index number the smallest. ]
GCD ( 28, 30 ) =  7
So a = 420 groups
The red marbles in each group: 28 ÷ 7 = 4 marbles
The blue marbles in each group: 35 ÷ 7 = 5 marbles

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A matrix B that has V as its nullspace. (c) Multiply A and B is [tex]I (4 by 4 ).[/tex]

[tex]\mathbb{R}^4[/tex]

What is a Nullspace vector?

The null space of A is all the vectors x for which Ax = 0, and it is denoted by null(A). This means that to check to see if a vector x is in the null space we need only to compute Ax and see if it is the zero vector.

- All vectors whose components are equal.

- All vectors whose components add to zero.

- All vectors that are perpendicular to [tex](1,1,0,0)$ and $(1,0,1,1)$.[/tex]

- The column space and the nullspace of  (4 by 4 ).

Solution. These bases are not unique.

[tex]- $(1,1,1,1)$.- $(1,-1,0,0),(1,0,-1,0)$, and $(1,0,0,-1)$.- $(1,-1,-1,0)$ and $(1,-1,0,-1)$.[/tex]

- The columns of are a basis of its column space: [tex]$(1,0,0,0),(0,1,0,0)$, $(0,0,1,0)$, and $(0,0,0,1)$.[/tex]The nullspace contains the zero vector only. By convention, the empty set is the basis of such a space.

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2.833 10 6 is the largest error as a result.

Finding a function's derivative, or rate of change, is the process of differentiation in mathematics.

The practical approach of differentiation can be performed utilizing only algebraic operations, three fundamental derivatives, four principles of operation, and an understanding of how to manipulate functions, in contrast to the theory's abstract character.

The three fundamental derivatives (D) are: (1) D(xn) = nxn 1 for algebraic functions, where n is any real number; (2) D(sin x) = cos x and D(cos x) = sin x for trigonometric functions; and (3) D(ex) = ex for exponential functions.

Hence, 2.833 10 6 is the largest error as a result.

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Answer:

x=8

Step-by-step explanation:

Simplify 2(x+1)−x.

Simplify each term.2x+2−x=10

Subtract x from 2x.x+2=10

Move all terms not containing x to the right side of the equation.

Subtract 2

from both sides of the equation.x1−2

Subtract 2 from x = 10-2

subtract 2 from 10

hope that helps!

Answer:  8

Step-by-step explanation:

First, let's write out the equation:

2(x+1) - x = 10

So, we need to find the value of x.

Let's take an estimate of what x could be.

So, we know it has to be 5-10, because that is over when we add x to one, then multiply by 2.

So, numbers 5-7 couldn't be it, because the value of x is lower than 10. So, we have to guess if it's 8 or 9

Let's use both numbers to solve if it's correct:

2(8+1) - 8 =10

18 - 8 = 10

or

2(9+1) - 8 =10

20 - 8 = 12

So, we have 8 as our answer.

So, x = 8

Answer:Each player would get 9 cards each with a reaminder of 4 cards left

Step-by-step explanation:6 times 9 is 54 + 4 is 58

Answer: 9

Step-by-step explanation:

To figure out the given problem below:

P = 6

C = 58

You have to divide the problem.

So [tex]58[/tex] ÷ [tex]6 = 9[/tex].

You can then add up the lengths of the sides to find the perimeter, and add up the areas of the faces to find the total surface area of the gift box.

What is a perimeter?

The perimeter of a shape is the total length of the outer boundary of the shape. It is the sum of all the sides of the shape.

To find the perimeter and the area of a gift box, you can use the given dimensions of the net to calculate the lengths of the sides and the areas of the faces. You can then add up the lengths of the sides to find the perimeter, and add up the areas of the faces to find the total surface area of the gift box.

Hence, you can then add up the lengths of the sides to find the perimeter, and add up the areas of the faces to find the total surface area of the gift box.

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The sum of squares of error, treatment, within and between four painters are: 330, 692, 110 and 43.25.

The data provided is for the dying time of four different types of paint.

One-way ANOVA can be used to determine whether all the four paints have the same drying time.

Use Excel to perform the one-way ANOVA.

Go to Data → Data Analysis → Anova: Single Factor

A dialog box will open. Select the data. Select "Grouping" as Columns.

Press OK.

The output is attached below.

The required values are as follows:

(1) Sum of Squares of Treatment (Between Subjects):

SST = 330

(2) Sum of Squares of Error (Within Subjects):

SSE = 692

(3) Mean Squares Treatment (Between Subjects):

MST = 110

(4) Mean Squares Error (Within Subjects):

MSE = 43.25

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